What must be the normal force acting on a crate as it slides across a horizontal floor if the friction acting on the box is 0.490N and the coefficient of friction is 0.250?

Answer:

Which feature is created when a block of rock dropped down in relation to the block of rock beside it?

Explanation:

Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.

S = (v-u)t/2

s = (14)1.4/2

s = 9.8m

The range of the shot will be "19.6 m". A complete solution is provided below.

The given values in the question are:

Horizontal velocity,

v = 14 m/s

Time,

t = 1.4 sec

Now,

The Range will be:

= \(Velocity\times Time\)

By putting the given values, we get

= \(14\times 1.4\)

= \(19.6 \ m\)

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What happens when a negatively charged object A is brought near a neutral object B is that: B. Object B gets a positive charge.

According to the law of electrostatic forces, unlike charges attract each other while like charges repel one another.

This ultimately implies that, objects that are having the same charges (like charges) would repel one another, and this causes a transfer of electrons (charges) to any differently charged object which comes in contact with it, through a process known as conduction.

In this context, we can reasonably and logically deduce that the negative charge of object A would induce an opposite charge (positive) on object B when a negatively charged object A is brought near a neutral object B.

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Explanation:

(a) To find the work done by the frictional force on the block, we can use the work-energy principle which states that the work done on an object is equal to the change in its kinetic energy. Therefore,

Work done by frictional force = Change in kinetic energy

The initial kinetic energy of the block is given by:

K1 = (1/2)mv1^2 = (1/2)(5 kg)(7 m/s)^2 = 122.5 J

The final kinetic energy of the block is given by:

K2 = (1/2)mv2^2 = (1/2)(5 kg)(4 m/s)^2 = 40 J

Therefore, the change in kinetic energy is:

ΔK = K2 - K1 = 40 J - 122.5 J = -82.5 J

Since the work done by the frictional force is negative, we have:

Work done by frictional force = -|-82.5 J| = 82.5 J

Therefore, the magnitude of the work done by the frictional force on the block is 82.5 J.

(b) To find the magnitude of the average frictional force on the block, we can use the equation:

Average frictional force = Work done by frictional force / Distance traveled

The distance traveled by the block during the 6 seconds is given by:

d = vit + (1/2)at^2

where vi is the initial velocity, t is the time, a is the acceleration, and d is the distance.

Since the surface is smooth before the rough patch, the block moves with constant velocity and the acceleration is zero. Therefore,

d = vit = (7 m/s)(6 s) = 42 m

After the rough patch, the block slows down from 7 m/s to 4 m/s in 6 seconds. Therefore, the acceleration of the block is given by:

a = (v2 - v1) / t = (4 m/s - 7 m/s) / 6 s = -0.5 m/s^2

Using this acceleration, we can find the distance traveled by the block after the rough patch:

d' = vit + (1/2)at^2 = (4 m/s)(6 s) + (1/2)(-0.5 m/s^2)(6 s)^2 = 12 m

Therefore, the total distance traveled by the block is:

d_total = d + d' = 42 m + 12 m = 54 m

Now, we can find the average frictional force on the block:

Average frictional force = Work done by frictional force / Distance traveled

= 82.5 J / 54 m

≈ 1.53 N

Therefore, the magnitude of the average frictional force on the block is approximately 1.53 N.

(a) The magnitude and direction of the acceleration of the object is 200 m/s².

(b) The force acting upon the object causing this acceleration is 1000 N.

The given parameters:

The magnitude and direction of the acceleration of the object is calculated as follows;

\(a_c = \frac{v^2}{r} \\\\a_c = \frac{6^2}{0.18} \\\\a_c = 200 \ m/s^2\)

The force acting upon the object causing this acceleration is calculated as follows;

\(F = ma_c\\\\F = 5 \times 200\\\\F = 1000 \ N\)

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Answer:

Nnamdi Benjamin Azikiwe,

Explanation:

Water adheres to the surface of a freshly waxed automobile with minimal adhesive forces due to its cohesiveness and surface tension.

The correct answer is :A.

With respect to water, a sticky surface has weak adhesive properties. As a result, due of surface tension, water droplets up on the surface. The cohesion, or propensity of hydroxyl groups to attract one another, is what causes surface tension.

Water just beads up and rolls off your car's surface, a phenomenon known more technically as hydrophobicity. Technically speaking, molecules enjoy sticking with one another like electromagnet, but they also enjoy sticking to other objects like dirt, particular if it has a static charge on it.

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Answer:

Objects that are closer together have a stronger force of gravity between them.

Explanation:

For example, the moon is closer to Earth than it is to the more massive sun, so the force of gravity is greater between the moon and Earth than between the moon and the sun.

The net work done per cycle for 1.00 mol of gas initially at 0°C is 4.88 kJ.

An isothermal process is a thermodynamic process in which the temperature of the system remains constant, while other state variables such as pressure and volume may change. An adiabatic process is a thermodynamic process in which there is no exchange of heat between the system and its surroundings, while other state variables such as pressure and volume may change.

a) The net work done by the gas per cycle is equal to the area enclosed by the cycle on the PV diagram. From the given figure, the cycle can be divided into two parts: the first part is an isothermal expansion from volume V0 to volume 5V0 and the second part is an adiabatic compression from volume 5V0 to volume V0.

For the isothermal expansion, the pressure decreases from P0 to P0/4. Using the equation for the work done during an isothermal process, the work done by the gas during this part of the cycle is:

W1 = nRT0 ln(5) = 4RT0 ln(5)

For the adiabatic compression, the pressure increases from P0/4 to P0. Using the equation for the work done during an adiabatic process, the work done by the gas during this part of the cycle is:

W2 = (P0V0^m/P0/4*(5V0)^m)^(1 - m)/1-m - (P0/4*(5V0)^m/P0/4)^(1 - m)/1-m = 4P0V0/3(1 - 1/5^(4/5))

The net work done by the gas per cycle is the sum of the work done in each part of the cycle:

W = W1 + W2 = 4RT0 ln(5) + 4P0V0/3(1 - 1/5^(4/5))

b) Since the cycle is closed, the net energy added to the system per cycle must be equal to the net work done by the gas per cycle:

Q = W = 4RT0 ln(5) + 4P0V0/3(1 - 1/5^(4/5))

c) To obtain a numerical value for the net work done per cycle for 1.00 mol of gas initially at 0°C, we need to substitute the appropriate values for R, T0, P0, V0, n, and m. Assuming the gas is an ideal gas, R = 8.314 J/mol K. At 0°C (273 K), the pressure of 1.00 mol of gas in a volume of V0 = 22.4 L (molar volume of ideal gas at STP) is P0 = 1 atm. Therefore,

W = 4(8.314 J/mol K)(273 K) ln(5) + 4(1 atm)(22.4 L)/3(1 - 1/5^(4/5))) = 4.88 kJ

Therefore, the net work done per cycle for 1.00 mol of gas initially at 0°C is 4.88 kJ.

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Given data

*The distance between the centers of two successive rarefaction area of a sound wave is 4.5 cm

The wavelength of the sound wave is 4.5 cm as the vertical distance between the adjacent peaks (crests or troughs of the wave)

Hence, the correct answer is (C)

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Steps to formulate a logical, reasonable perspective to any situation are: gather information, identify problem, analyze the situation, consider assumptions, generate solutions, evaluate options, consider your values, make decision and monitor and adjust

Here are the six questions that you can apply to formulating a logical, reasonable perspective to any situation:

What are the issues that should be addressed?

What are the relevant facts and data related to this problem or issue?

What assumptions am I making about the problem or issue?

What are the possible solutions or outcomes, and what are the pros and cons of each?

What are my values and priorities related to this problem or issue?

What additional information do I need to make an informed decision or come to a reasonable conclusion?

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- The resistance of the first resistor (R₁) is 12 Ω.

- The electromotive force (EMF) of the battery is 18 V.

- The internal resistance of the battery is 12 Ω.

To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.

Let's start by calculating the resistance of the first resistor (R₁):

1. Apply Ohm's law to find the voltage drop across the external circuit:

  V = I * R

  V = 1 A * 6 Ω

  V = 6 V

2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:

  V = E - Ir

  6 V = E - (1 A * r)   (where r is the internal resistance of the battery)

3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:

  E = 6 cells * 3 V/cell

  E = 18 V

4. Substitute the value of E in the equation from step 2:

  6 V = 18 V - r

  r = 12 Ω

Therefore, the resistance of the first resistor (R₁) is 12 Ω.

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(a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

Acceleration owing to gravity is the term used to describe the rate at which a body's velocity changes as a result of the earth's gravitational pull. In general, it is assumed that the acceleration caused by gravity is in the downward direction.

The acceleration caused by gravity has been calculated as, however as it changes from location to location, it may have an impact on the estimation.

You may have thought that the wind has no impact, but it can actually generate drag and even cause the ball to shift course.

Therefore, (a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

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Answer:

m = 2.4

Explanation:

Given that,

Input force, \(F_i=5\ N\)

Output force, \(F_o=12\ N\)

We need to find the mechanical advantage of the ramp. The ratio of output force to the input force is equal to mechanical advantage. So,

\(m=\dfrac{12}{5}\\\\m=2.4\)

So, the mechanical advantage of his ramp is 2.4.

The wavelength of light that should be used to obtain fringes that are 0.0045 m wide after reducing the distance between the screen and the slit by half is 2.25 * 10^7 Å.

Huygens's Principle states that every point on a wavefront can be considered as a source of secondary spherical wavelets that spread out in all directions with the same speed as the original wave. The new wavefront is formed by the envelope of these secondary wavelets at a later time.

Now, let's consider a Young's double-slit experiment. In this experiment, when light passes through two narrow slits, it creates an interference pattern on a screen behind the slits. The fringe width is the distance between two consecutive bright or dark fringes in the pattern.

Given that the fringe width obtained is 0.6 cm and the wavelength of light used is 4500 Å (Angstroms), we can calculate the wavelength of light required to obtain fringes that are 0.0045 m wide.

We can use the formula for fringe width in Young's double-slit experiment:

w = (λ * D) / d

Where:

w is the fringe width,

λ is the wavelength of light,

D is the distance between the screen and the double slits, and

d is the distance between the two slits.

Let's calculate the value of D/d using the given information:

D/d = w / λ

= 0.006 m / 4500 Å (1 m = 10^10 Å)

= 0.006 * 10^10 / 4500 m^-1

Now, if the distance between the screen and the slit is reduced by half, the new value of D/d would be:

(D'/d) = (0.006/2) * 10^10 / 4500 m^-1

Now, we can rearrange the equation to solve for the new wavelength (λ'):

(λ' * D') / d = (D/d)

λ' = (D/d) * d / D

= [(0.006/2) * 10^10 / 4500] * (4500 / 0.006) Å

= 0.0045 m * 10^10 / 2 Å

= \(0.00225 * 10^{10\) Å

=\(2.25 * 10^7\)Å

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Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.

The correct answer is option D.

The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :

Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).

When Mark climbs the stairs with the cello, he is doing work against the force of gravity.

The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.

Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.

Therefore, mark's work decreases.

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The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.

To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.

The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.

Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).

To calculate the area, we can break it down into two separate integrals:

1. The area above the x-axis (forward motion):

Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:

Area1 = velocity * time = 20 m/s * 4 s = 80 m

2. The area below the x-axis (backward motion):

The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:

Area2 = velocity * time = -10 m/s * 1 s = -10 m

To find the total distance traveled, we add the absolute values of the areas:

Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m

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The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.

The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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Answer:

What are the best flowers? (My opinion)

Explanation:

You're welcome.

Answer:

Tulips,

Lilies,

Lotuses on my opinion...

The work done by gravity on the sliding crate is 176.6 J.

The work done by gravity on the sliding crate is calculated by applying the following formula.

W = Fd cosθ

W = mg x d cosθ

where;

W = ( 14 kg x 9.8 m/s² ) x ( 1.61 m ) x cos ( 36.9 )

W = 176.6 J

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The magnitude of the force on the tooth is approximately 0.022 N.

To find the magnitude and direction of the force on the tooth, we can use Hooke's Law, which states that the force exerted on an object is directly proportional to the change in length of a material when it is stretched or compressed.

First, we need to calculate the strain (ε) of the stainless-steel wire.

Strain is defined as the change in length divided by the original length:

ε = ΔL / L₀

Given that the change in length (ΔL) is 0.10 mm \((0.10 \times 10^{-3} m)\) and the unstretched length (L₀) is 3.1 cm \((3.1 \times 10^{-2} m)\), we can calculate the strain:

\(\epsilon=(0.10 \times 10^{-3} m)/(3.1 \times 10^{-2} m)=0.003225\)

Next, we can use Young's modulus (E) to calculate the stress (σ) in the wire.

Stress is defined as the force per unit area:

σ = E * ε

Given that Young's modulus (E) for stainless-steel is 18 × 10¹⁰ N/m², we can calculate the stress:

σ = (18 × 10¹⁰ N/m²) * 0.003225 = 5.805 × 10⁸ N/m²

Now, we can find the force (F) on the tooth by multiplying the stress by the cross-sectional area (A) of the wire:

F = σ * A

The cross-sectional area (A) can be calculated using the formula for the area of a circle:

A = π * (d/2)²

Given that the diameter (d) of the wire is 0.22 mm\((0.22 \times 10^{-3} m)\), we can calculate the cross-sectional area:

\(A = \pi * (0.22 \times 10^-3 m / 2)^{2} = 3.802 \times 10^{-8} m^2\)

Finally, we can calculate the force:

\(F = (5.805 \times 10^{8} N/m^{2}) * (3.802 \times 10^-8 m^{2}) \approx 2.206 \times 10^{-2} N\)

Therefore, the magnitude of the force on the tooth is approximately 0.022 N.

Since the wire is stretched, the force is pulling the tooth in the direction opposite to the stretching.

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Answer:

2 m/s

Explanation:

The momentum of the colliding system is conserved . Therefore, the velocity of the ball B with the same mass as A is 0.52 m/s.

Momentum of a body is the ability to bring the applied force makes maximum displacement. it is the product of mass and velocity. For a collision, the sum of initial momentum of the two bodies is equal to the sum of their final momentum.

Thus, u be the initial velocity and v be the final velocity.

Then, m1 u1+ m2 u2 = m1 v1 + m1 v2

m1 =  0.17 kg

u1 = 4 m/s

m2 = 0.17 kg

u2 = 0

Then initial momentum = 0.17 × 4 m/s + 0 = 0.68 kg m/s

v1 = 3.5 m/s

0.68 kg m/s = (0.17 × 3.5 m/s ) +  (0.17 × v2)

then v2 = 0.52 m/s.

Therefore, the velocity of ball B after collision will be 0.52 m/s.

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The Santa Ana winds can exacerbate forest fires in southern California, but the Sierra Nevada mountains does not blocks and redirect these winds north and south.

The Santa Ana winds (sometimes the Devil's Winds) are strong, extremely dry downwind winds that originate inland and affect coastal Southern California and northern Baja California.

hence they does not have any contact with the Sierra Nevada mountains, the statement "the Sierra Nevada mountains block and redirect the winds north and south" is not true for the Santa Ana winds.

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Answer:

65 Newtons

Explanation:

A book is kept on the table. The book is applying 65 N of force down on the table. So the table will also apply 65 N force to the book.

According to physics, a force is an effect that has the power to change an object's motion. A force can cause a massed item to accelerate or modify its velocity. A push or a pull is a straightforward method to explain force. Considering that a force has both a magnitude and a direction, it is a vector quantity.

The pace at which an object's direction changes when it is traveling is referred to as its velocity, and is measured by a particular unit of time and from a particular point of view.

When the book is applying force on the table that is mg, and it is 65 N the table will also generate a normal reaction force which will be equal to the force applied by the book which is 65 N.

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The efficiency of the leaf blow is 48%.

         Here, E = Energy transferred

                   m = Mass

                   Ф = Temperature change

            Here, E = Energy transferred

                      P = Power

                      t = time

        Here, v = speed

                   f = frequency

                  ∧ = wavelength

       Efficiency =  (Useful power out / Total power in ) = 360/750 = 0.48

So, the efficiency of the leaf blower is 48%.

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In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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The common characteristics  of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.

Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.

The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.

Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.

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