A vendor bought 10 kg of goods for ₹ 350. He sold them at ₹42 per kg. How much profit

did he make for 1 kg?

Profit and loss chap

The area of triangle ABC is approximately 90.37 square units.

To determine the area of triangle ABC, we can use the formula for the magnitude of the cross product of two vectors. Let's denote the vectors AB and AC as vectors u and v, respectively.

Vector u = B - A = (7, 8, -4) - (-2, 1, 3) = (9, 7, -7)

Vector v = C - A = (5, 0, 2) - (-2, 1, 3) = (7, -1, -1)

Now, we can calculate the cross product of u and v:

u x v = (9, 7, -7) x (7, -1, -1)

= [(7*(-7) - (-1)(-7)), (-1(-7) - (-7)7), (9(-1) - 7*7)]

= (-42, -48, -64)

The magnitude of the cross product u x v gives us the area of triangle ABC:

Area = |u x v| = sqrt((-42)^2 + (-48)^2 + (-64)^2)

= sqrt(1764 + 2304 + 4096)

= sqrt(8164)

≈ 90.37

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The segment AB is a radius and the notation is ↔ AB

From the question, we have the following parameters that can be used in our computation:

The circle

On the circle, we can see that

The segment AB goes from the center of the circle to a point on the circle

A line that goes from the center of the circle to a point on the circle is the radius of the circle

This means that the segment AB is a radius and the notation is ↔ AB

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Answer:

Overtime hours = [h - 40] hours

Step-by-step explanation:

Given:

Weekly hour work = 40 hours per week

Total hour work = h hours

Find:

Overtime hours

Computation:

Overtime hours = Total hour work - Weekly hour work

Overtime hours = [h - 40] hours

Using it's concept, the range of the function is given by:

y ≥ 1

The range of a function is composed by the set that contains all output values for the function. Considering the graph of the function, the range is given by all the values of y, which compose the vertical axis of the graph.

Looking at this graph, the function assumes values of 1 and greater, hence the range of the function is given by:

y ≥ 1.

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In polar coordinates, the radial distance "r" is defined as the distance from the origin to a point in the plane. Since distance cannot be negative, we only consider the positive square root of 3 in the range for this problem. So, the correct range for "r" is 0 ≤ r ≤ √3, and negative square root of 3 is not included because it doesn't represent a valid distance in polar coordinates.

To find the volume of the given solid enclosed by the hyperboloid −x2 − y2 + z2 = 6 and the plane z = 3 using polar coordinates, we need to express the equation of the hyperboloid in terms of polar coordinates.

Substituting x = rcosθ and y = rsinθ, we get:

−r2cos2θ − r2sin2θ + z2 = 6

Simplifying, we get:

z2 = 6 - r2

Since the plane z = 3 intersects the hyperboloid, we have:

3 = √(6 - r2)

Solving for r, we get:

r = √3

Hence, the range for r is 0 ≤ r ≤ √3.

In summary, the negative square root of 3 is not included in the range of r because r represents a distance and cannot be negative. The volume of the solid can be found by integrating the function f(r,θ) = √(6 - r2) over the range 0 ≤ r ≤ √3 and 0 ≤ θ ≤ 2π using polar coordinates. The result will be in cubic units and can be obtained by evaluating the integral.

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Yes, the ratios form a proportion.

Given that, Steve plants 64 bulbs in which 48 are tulips.

So the ratio of tulips to total bulbs of Steve is = 48:64 = 3:4

Again, Dawn plants 96 bulbs in which 72 are tulips.

So the ratio of tulips to total bulbs of Dawn is = 72:96 = 3:4

Since the ratio are same so the ratios form a proportion.

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To transform each old salary x into a new salary n(x) with an across-the-board raise of r, we can use the following function: n(x) = x + r

In this case, since each teacher at C.F. Gauss Elementary School is given an across-the-board raise of r, we can use this function to calculate their new salaries. For example, if a teacher's old salary is x, their new salary would be:

n(x) = x + r

So if the across-the-board raise is 10%, or r = 0.1, then a teacher with an old salary of $50,000 would have a new salary of:

n($50,000) = $50,000 + 0.1($50,000) = $55,000

Similarly, a teacher with an old salary of $70,000 would have a new salary of:

n($70,000) = $70,000 + 0.1($70,000) = $77,000

And so on for each teacher at C.F. Gauss Elementary School.

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The required probability is 0.4408.

The operating characteristics of the loading gate problem are:

L = λ/ (μ - λ)

W = 1/ (μ - λ)

Lq = λ^2 / μ (μ - λ)

Wq = λ / μ (μ - λ)

ρ = λ / μ

P0 = 1 - λ / μ

Where, L represents the average number of cars either being loaded or waiting.

W represents the average time a car spends either being loaded or waiting.

Lq represents the average number of cars waiting.

Wq represents the average waiting time of a car.

ρ represents the utilization factor.

ρ = λ / μ represents the ratio of time the worker spends loading cars to the total time the system is busy.

P0 represents the probability that the system is empty.

The probability that there will be more than six cars either being loaded or waiting is to be determined. That is,

P (n > 6) = 1 - P (n ≤ 6)

Now, the probability of having less than or equal to six cars in the system at a given time,

P (n ≤ 6) = Σn = 0^6 [λ^n / n! * (μ - λ)^n]

Putting the values of λ and μ, we get,

P (n ≤ 6) = Σn = 0^6 [(6/ 48)^n / n! * (8/ 48)^n]

P (n ≤ 6) = [(6/ 48)^0 / 0! * (8/ 48)^0] + [(6/ 48)^1 / 1! * (8/ 48)^1] + [(6/ 48)^2 / 2! * (8/ 48)^2] + [(6/ 48)^3 / 3! * (8/ 48)^3] + [(6/ 48)^4 / 4! * (8/ 48)^4] + [(6/ 48)^5 / 5! * (8/ 48)^5] + [(6/ 48)^6 / 6! * (8/ 48)^6]P (n ≤ 6) = 0.5592

Now, P (n > 6) = 1 - P (n ≤ 6) = 1 - 0.5592 = 0.4408

Therefore, the required probability is 0.4408.

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Answer:

I'm leaning mostly towards C Because there is a solution, None of them are real numbers and if they were, S would = 5 Especially positive S

~ Zachary

The angle, a, between the Vectors u and W is  2.0 radians (rounded to the nearest tenth).

The angle, a, between the vectors u = <-4, -3> and W = <-1, 5>, we can use the dot product formula:

u · W = |u| |W| cos(a)

Where u · W is the dot product of u and W, |u| is the magnitude of u, |W| is the magnitude of W, and a is the angle between the vectors.

First, let's calculate the dot product:

u · W = (-4)(-1) + (-3)(5)

      = 4 - 15

      = -11

Next, let's calculate the magnitudes of the vectors:

\(|u| = \sqrt{((-4)^2 + (-3)^2)}\\= \sqrt{(16 + 9)}\\= \sqrt{(25)}\\= 5\)

\(|W| = \sqrt{((-1)^2 + 5^2)}\\= \sqrt{(1 + 25)}\\= \sqrt{(26)\)

Now, we can substitute the values into the dot product formula:

\(-11 = (5)(\sqrt{(26)}) cos(a)\)

To find cos(a), we can rearrange the equation:

cos(a) = \(-11 / (5 \times \sqrt{(26))\)

Now, let's calculate the value of cos(a):

cos(a) ≈ -11 / (5 * 5.099)

      ≈ -11 / 25.495

      ≈ -0.431

To find the angle a, we can take the inverse cosine (arccos) of cos(a):

a ≈ arccos(-0.431)

 ≈ 1.994 radians (rounded to the nearest tenth)

Therefore, the angle, a, between the vectors u and W is approximately 2.0 radians (rounded to the nearest tenth).

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Answer:

its -6

hopefully this will help you

A. m∠1 = 45° because m∠1 and the angle measuring 135° are supplementary angles

B. m∠2 = 95° because m∠2 and the angle measuring 95° are vertical angles

C. m∠3 = 40° because m∠1, m∠2, and m∠3 form a triangle.

When a transversal line intersects a pair of parallel lines, several angles are formed which includes: Corresponding angles, vertical angles, alternate angles, complementary and supplementary angles.

m∠1 + 135° = 180° {supplementary angles}

m∠1 = 180° - 135°

m∠1 = 45°

m∠2 and 95° are vertical angles thus they are equal so;

m∠2 = 95°

m∠1 + m∠2 + m∠3 = 180° {sum of interior angles of a triangle}

45° + 95° + m∠3 = 180°

140° + m∠3 = 180°

m∠3 = 180° - 140°

m∠3 = 40°

In conclusion:

A. m∠1 = 45° because m∠1 and the angle measuring 135° are supplementary angles.

B. m∠2 = 95° because m∠2 and the angle measuring 95° are vertical angles

C. m∠3 = 40° because m∠1, m∠2, and m∠3 form a triangle.

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The image has two(2) hexagons as the top and base of the figure, and six(6) rectangular blocks by the sides.

For six(6) rectangular blocks, the area becomes:

Hence, sum of their areas is 83.2 + 216 = 299.2 square centimeter.

The answer choice which represents the solution to the inequality as given in the task content is; x>-2 or x≤ 1.

On this note, it follows that the inequalities can be solved individually as follows;

-4 < 3x +2

-6 < 3x

x > -2

Also, 3x +2 ≤ 5

3x ≤ 3

x ≤ 1.

Ultimately, the correct answer choice is; Choice C; x>-2 or x≤ 1.

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Answer:

the answer would be c=81x^28-n I hope it helps!

Answer:

c=81x^28-n

Step-by-step explanation:

\(c=81x^{28-n}\)

Answer:

i think its c

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

i think i helped successfully

Answer:

y= 1

Step-by-step explanation:

In the equation, the 1 means that it's the y-intercept

And whenever x is 0, then the y value is the y-intercept

So since x=0, then y=1

Answer:

Proper Subsets = 1023

Step-by-step explanation:

Given\(W= \{Hampton\ Hotels, Anytime\ Fitness, Subway, Jack\ in\ the\ Box, Supercuts, \\Jimmy\ Johns, Servpro, Denny's, Pizza\ Hut, 7-Eleven\}\)

Required

Determine the proper subsets

Proper Subset (P) is calculated using;

\(P = 2^n - 1\)

Where

\(n = number\ of\ elements\)

In this case;

\(n = 10\)

So:

\(P = 2^n - 1\)

\(P = 2^{10} - 1\)

\(P = 1024 - 1\)

\(P = 1023\)

Hence;

Proper Subsets = 1023

Answer:

1024

Step-by-step explanation:

There are 720 possible horse combinations for the first 3 places in the race.

To solve this problem, let us break this down one by one.

There are 10 possible horses that could win in first place.

Therefore, this means that for each of these possibilities, there are now 9 horses that could come in second.

So there are 10 x 9 possible combinations for the first 2 places.

10 x 9 = 90.

And for each of those combinations, there are also 8 possible horses that could come in the third place. So

10 x 9 x 8 = 720

There are 720 possible horse combinations for the first 3 places in the race.

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The volume of the cylinder with the same radius and height as the cone is thus 157 cm³.

Volume is the quantity of space in a 3D object in arithmetic. A fish tank, for example, is 3 feet long, 1 foot wide, and 2 feet tall. To calculate the volume, multiply the length by the breadth by the height, which is 3x1x2, which is six. As a result, the fish tank has a volume of 6 cubic feet. Volume is defined as the space occupied by an item inside the confines of three-dimensional space. It is also known as the object's capacity.

Here,

The volume of a cone with radius "r" and height "h" can be calculated using the formula:

V = (π * r³ * h) / 3

Since we know the volume of the cone, we can solve for "r" using the formula and then find the volume of a cylinder with the same radius and height:

V = (π * r² * h) / 3

525 = (π * r² * h) / 3

1575 = π * r² * h

r² = 1575 / (π * h)

The volume of a cylinder with radius "r" and height "h" can be calculated using the formula:

V = π * r²* h

Using the value of r² from above:

V = π * (1575 / (π * h)) * h

So, the volume of the cylinder with the same radius and height as the cone is 157.5 cm³, which is approximately 157 cm³ (rounded to the nearest whole number).

Therefore, the volume of the cylinder with the same radius and height as the cone is 157 cm³.

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Answer:

your answer is going to be B: Obtuse

The key here is to know place values

We can move from right to left and understand the place values.

• Right most "4" is place value of ones

• Moving left, "4" has place values tens

• Moving left, "2" has place value hundreds

• Again left, "8" has place value thousands

• Left, "4" has place value ten thousands

• Lastly (leftmost digit, 4), "4" has place value hundred thousands

Now,

The left-most pair of 4s have place value of:

hundred thousands and ten thousands, that means:

Also, now, let's look at right-most pair of 4s, they have place value of:

ones and tens, that means:

We have to figure out the relationship between 400,000 and 40,000 and also between 4 and 40.

We can simply see that 40 is 10 times the number 4.

Also, 400,000 is 10 times the number 40,000.

Hence, the value of one of the 4's is 10 times the value of the other 4's (IN BOTH THE PAIRS, leftmost pair and rightmost pair).

When using Beer's law type measurements, the expected error bars for data points taken at low and high analyte concentrations are typically larger than the measurements in the mid-range of the concentration curve. This is because the relationship between absorbance and concentration is not linear throughout the entire range.

In the mid-range of the concentration curve, the absorbance and concentration exhibit a linear relationship according to Beer's law, which states that absorbance is directly proportional to the concentration of the analyte. This linear relationship leads to more accurate and precise measurements, resulting in smaller error bars.

However, at low and high analyte concentrations, the relationship between absorbance and concentration becomes nonlinear. At low concentrations, the absorbance may be close to zero, leading to a larger relative error as even a small fluctuation in the measured value can have a significant impact on the calculated concentration. Similarly, at high concentrations, the absorbance may approach a maximum value, causing deviations from linearity and larger errors.

These nonlinearities can arise due to factors such as instrument limitations, deviations from ideal chemical behavior, or limitations of the Beer's law itself. As a result, measurements taken at extreme concentration values tend to have larger error bars compared to those in the mid-range of the concentration curve.

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Answer:

Step-by-step explanation:

27/ 77  (Decimal: 0.350649)

Step-by-step explanation:

slop -3

(x ,y) point that throgh the x,y axis

(0,2), (1,-1), (2, -4),( -1, 5), ( -2, 8) etc you can make the graph by connect the co ordinat point

Answer: I beleive that the systems of transformation are that

Figure JKLM to Figure J' K' L' M' is a Rotation

Figure J' K' L' M' to Figure J" K" L" M" is a Dilation

Step-by-step explanation:

Answer:

im confusedddddddd.................