pablo is standing on the beach, and the sea is choppy. he observes that the crests of distant waves appear not only smaller but also higher in his field of vision than do the crests of waves nearer the beach. this example illustrates the monocular depth cues of:

Answer:If the coefficient of kinetic friction (u) is 0.2, what ... The force of friction for a 7.5-kg object being pushed horizontally at a constant speed ... needed to start the box moving? ... An applied force of 21 N accelerates a 9.0-kg wagon at 2.0 m/s² along the ... 3N = p. 88.2 N. (u=0,034. 5. A sled of mass of 50.0 kg is pulled along a flat,

The acceleration necessary for the plane to take flight is:  0.7949 m / s 2

Initial velocity  u = 0

Final velocity  v = 203 km / h

                       = 203 x 1000 m / 3600 s

                       = 56.388 m / s

Distance  S = 2000 m

From the relation v 2 - u 2 = 2aS

Accleration a = [  v 2 - u 2 ] / 2S

                    = 0.7949 m / s 2

What is Accleration?

Compared to displacement and velocity, acceleration is like a raging fire-breathing dragon of motion variables. it can be violent. Some people fear it. And when it's big, you have to be careful. Taking off an airplane, braking a car, cornering a go-kart at high speed are all sensations of acceleration.

Acceleration is the name we give to any process that changes velocity. Velocity is speed and direction, so there are only two ways to accelerate. Either change speed, change direction, or change both.

Therefore, the acceleration is:  0.7949 m / s 2

To know more about acceleration, visit:

https://brainly.com/question/460763

#SPJ4

Answer:

\(||\vec E_A||=1.11446 \times 10^6 \ \frac{N}{C}\), where the vector arrow will point from the charge towards point A.

Conceptual:

What is an electric field?

An electric field is a physical field produced by charged particles, these electric fields have the ability to exert forces on other charged particles. The following formula can be used to find the electric field (as a vector) at a point in space. "k_e" is Coulomb's constant and "\(\hat r\)" indicates the direction vector that point from the charge towards the field you are trying to calculate.

\(\boxed{\left\begin{array}{ccc} \text{\underline{Equation for Electric Field:}} \\\\\ \vec E=\frac{k_eq}{r^2} \hat r \\k_e=8.99 \times 10^9\frac{Nm^2}{C^2} \end{array}\right }\)

Explanation:

Given:

\(q=6 \times 10 ^{-6} \ C\\\\r=0.22 \ m\)

Find:

\(\vec E_A=?? \ \frac{N}{C}\)

\(\vec E_A=\frac{k_eq}{r^2} \hat r\\\\\Longrightarrow \vec E_A=\frac{(8.99 \times 10 ^9)(6 \times 10 ^{-6})}{(0.22)^2} \cdot\frac{ < 0,-0.22 > }{\sqrt{(0)^2+(-0.22)^2} } \\\\\Longrightarrow \vec E_A= 1.11446 \times 10^6 \cdot < 0,-1 > \\\\\Longrightarrow \vec E_A= < 0,-1.11446 \times 10^6 > \frac{N}{C} \\\\\Longrightarrow||\vec E_A||=\sqrt{(0)^2+(-1.11446 \times 10^6\))^2} \\\\\therefore \boxed{\boxed{||\vec E_A||=1.11446 \times 10^6 \ \frac{N}{C}}}\)

Thus, the electric field strength at point A is found. The vector arrow will point from the charge, q, towards point A.

1) I=Q/T then Q= I ×T 10* ( 20*60) = 10 (120) therefore the answer is 1200C

2) I= Q/T that is 500/ 25 and the answer is 20A

The takeoff speed of the aircraft is approximately 41.6 m/s.

The wing loading of the aircraft is approximately 1128.6 N/m².

The required power to maintain a constant cruising speed of 300 km/h is approximately 173791.5 W.

1. Lift = Weight

1/2 * density * velocity² * wing area * lift coefficient = mass * gravity

1/2 * 1.225 * velocity² * 35 * 0.45 = 4000 * 9.81

Simplifying and solving for velocity, we get:

velocity = ✓((4000 * 9.81 * 2) / (1.225 * 35 * 0.45)) = 41.6 m/s

(b) Wing loading = Weight / wing area

Wing loading = 4000 * 9.81 / 35 = 1128.6 N/m²

Therefore, the wing loading of the aircraft is approximately 1128.6 N/m²

(c) Drag = 1/2 * density * velocity² × wing area * drag coefficient

Substituting the given values, we get:

Drag = 1/2 * 1.225 * (300/3.6)² * 35 * 0.035 = 2085.5 N

Power = force * velocity

Power = 2085.5 * 83.33 = 173791.5 W

Learn more about speed on

https://brainly.com/question/13943409

#SPJ4

Distanced travelled by a ship with a constant velocity in a day is 719712m

VELOCITY is defined as rate of change of displacement in a given interval of time.

it is a vector quantity.

its unit is m/s

to calculate the distance of a ship travelled

distance = speed x time

d = s x t   ----1.

velocity of ship = 8.33m/s

time taken = 1 day =86400 sec

now using the above values in equation 1 we get

d =8.33m/s x  86400 sec

d = 719712m

thus a ship travels 719712m in a day.

Distanced travelled by a ship with a constant velocity in a day is 719712m

To know more about velocity

https://brainly.com/question/24503842

#SPJ1

Answer:

A.Nitrogen

Explanation:

Because it is belong to non-metal group.

I don't knowwwww

Answer:

D.Beryllium (Be)

Explanation:

Trust

Answer:

259200

Explanation:

use the formula distance= speed x time

change the 2 hours to seconds (7200) and multiply that number by 36 and it'll give you 259200

Answer:

12 kilometers and hour

Explanation:

Effort is 600N, load distance is 0.75m, effort distance is 199.25m, effort MA is 0.00377, VR is 265.67 and the efficiency is 0.22%.

Effort is the force that is applied on the crowbar to move the load. Load is the object that needs to be moved. Fulcrum is the pivot point or the fixed point around which the crowbar rotates. The distance between the fulcrum and the load is known as load distance. The distance between the fulcrum and the effort is called effort distance.

Effort = 600N

Load distance = 0.75m

Effort distance = 200 - 0.75 = 199.25m

Effort MA (Mechanical Advantage) = Load distance / Effort distance

Effort MA = 0.75 / 199.25 = 0.00377VR (Velocity Ratio) = Effort distance / Load distance

VR = 199.25 / 0.75 = 265.67

Efficiency = (Load * Load distance) / (Effort * Effort distance)

Efficiency = (600 * 0.75) / (Effort * 199.25) = 0.00224 * 100% = 0.22%

To learn more about distance click here https://brainly.com/question/29552792

#SPJ11

upper body muscular strength

Answer:

Explanation:

muscular strength test

The amplitude, restoring force and speed of an object undergoing simple harmonic  motion may have maximum magnitudes at the same instant of time.

Simple harmonic motion is a regular repeating motion. The acceleration of a simple harmonic motion is always directed towards the center of the motion.

There are three  quantities related to the object that can have maximum values at the same time and these are;

Learn more about simple harmonic motion:https://brainly.com/question/17315536

When we Click Play() the motion of a transverse wave is from left to right and when we Click Reset() the motion of a wave and hand both is left to right.

Wave motion is the regular and orderly movement of disturbances, or departures from equilibrium or rest, from one location to another. The most well-known waves are surface waves on water, but waves can also be seen in sound waves, light waves, and subatomic particle movements.

When we Click Play() the motion of a transverse wave will be from left to right but the movement of particles will be up and down and in conclusion the wave moves left and right and the hands move up and down.

Now, when we Click Reset() and choose the Longitudinal wave and increase the Amplitude to 20. 0 cm. and then  Click Play the motion of the longitudinal wave and the hand both is left to right.

Learn more about transverse waves

brainly.com/question/13863548

#SPJ4

Answer:

8.829 Joules

Explanation:

The potential energy of an object, is the energy it posses (the energy stored within the object) by virtue of its relative elevation or height, position, state, or arrangement

The potential energy of an object raised to a given height, P.E. = m·g·h

Where;

m = The mass of the object

g = The acceleration due to gravity, a constant ≈ 9.81 m/s²

h = The present height of the object

For the potato sack having a mass, m = 2 kg, and raised to a height, h = 450 cm = 0.45 m, we have;

The potential energy given to the potato sack, by raising its height, P.E. is given as follows;

P.E. = 2 kg × 9.81 m/s² × 0.45 m = 8.829 Joules

The potential energy given to the potato sack, P.E. = 8.829 Joules

The wavelength of the given transverse wave is 8 cm and the amplitude is approximately 14 cm.

Wavelength of a transverse wave is the distance between two consecutive crests or troughs of the wave. Wavelength of a wave is inversely proportional to the  frequency and energy  of the wave.

The amplitude of a transverse wave is the distance from the base line to the top of the crest or to the bottom of the trough.It is directly proportional to the frequency of the wave.

For the given wave, the wavelength is 8 cm and the amplitude that is , the distance to the base line to the top of the peak is 14 cm.

To find more on wavelength, refer here:

https://brainly.com/question/13533093

#SPJ1

Answer:

a region around a magnetic material or a moving electric charge within which the force of magnetism acts.

Explanation:

The definition of a magnetic field is a place in space near a magnet or an electric current where a physical field is created from a moving electric charge that creates a force on another moving electric charge. An example of a magnetic field is the Earth's magnetic field.

True. Various heat-related disorders can be brought on by inadequate hydration combined with exposure to extreme heat and humidity.

One of three disorders brought on by excessive heat, with heat cramps being the least dangerous and heatstroke being the most serious, is heat exhaustion. High temperatures, particularly when there is also a high humidity level, and intensive physical activity are the main causes of heat illness.

According to T8 CCR Section 3395, "Heat Illness" refers to a dangerous medical illness caused by the body's incapacity to handle a specific amount of heat. Examples of this ailment include heat cramps, heat exhaustion, heat syncope, and heat stroke.

To know more about heat  visit:-

https://brainly.com/question/30603212

#SPJ1

A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) The photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).(b)option B and C are correct.

To determine the photon's energy and the energies of photons that might be emitted when the hydrogen atom returns to the ground state, we can use the energy level formula for hydrogen atoms:

E = -13.6 eV / n^2

where E is the energy of the electron in the atom, and n is the principal quantum number.

(a) To find the energy of the photon that was absorbed by the hydrogen atom to raise it from the ground state (nᵢ = 1) to the nf = 3 state, we need to calculate the energy difference between the two states:

ΔE = Ef - Ei = (-13.6 eV / 3^2) - (-13.6 eV / 1^2)

Calculating the value of ΔE:

ΔE = -13.6 eV / 9 + 13.6 eV

= -1.51 eV

Therefore, the photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).

(b) When the hydrogen atom returns to the ground state, it can emit photons with energies corresponding to the energy differences between the excited states and the ground state. We need to calculate these energy differences and check which values are present among the given options.

ΔE1 = (-13.6 eV / 1^2) - (-13.6 eV / 3^2) = 10.20 eV

ΔE2 = (-13.6 eV / 1^2) - (-13.6 eV / 4^2) = 10.20 eV

ΔE3 = (-13.6 eV / 1^2) - (-13.6 eV / 5^2) = 12.10 eV

ΔE4 = (-13.6 eV / 1^2) - (-13.6 eV / 6^2) = 12.10 eV

ΔE5 = (-13.6 eV / 1^2) - (-13.6 eV / 7^2) = 13.55 eV

ΔE6 = (-13.6 eV / 1^2) - (-13.6 eV / 8^2) = 13.55 eV

ΔE7 = (-13.6 eV / 1^2) - (-13.6 eV / 9^2) = 13.55 eV

Comparing the calculated energy differences with the given options:

(A) 1.89 eV: This energy difference does not match any of the calculated values.

(B) 12.1 eV: This energy difference matches ΔE3 and ΔE4.

(C) 10.2 eV: This energy difference matches ΔE1 and ΔE2.

(D) 13.6 eV: This energy difference does not match any of the calculated values.

Therefore option B and C are correct.

To learn more about principal quantum number visit: https://brainly.com/question/2292596

#SPJ11

Answer: The speed limit is 15 mph when you come within 100 feet of a railroad crossing and you cannot see the tracks for 400 feet in both directions. You may go faster than 15 mph if the crossing is controlled by gates, a warning signal, or a flagman.

Explanation: hope this helps

Answer:69

Explanatioits funnyn:

A driver ignores the stop sign and continues driving west at constant speed ,is true.

The complete question is A driver ignores the stop sign and continues driving west at constant speed.t/false

To learn more about constant speed refer to:

https://brainly.com/question/21071572

#SPJ4

Answer:

Explanation:

2aS=vf^2-vi^2

vf^2=2as+vi^2

vf^2=2*9.8*1.25*10^3+vi^2

vf^2=24500vi2

√vf2=√24500vi2

vf=156.5vi

The frequency observed by the observer on the left (fL) is higher than the frequency observed by the observer on the right (fR). Here option A is the correct answer.

The observed frequency, fL, of the sound heard by the observer on the left is higher than the observed frequency, fR, heard by the observer on the right. This phenomenon is known as the Doppler effect.

When a source of sound is moving towards an observer, the sound waves are compressed, resulting in a higher frequency. Conversely, when the source of sound is moving away from an observer, the sound waves are stretched, leading to a lower frequency.

In this case, as the police car is moving towards the observer on the left, the sound waves are compressed, causing an increase in frequency. Therefore, the observer on the left hears a higher frequency, fL. On the other hand, the observer on the right experiences the sound waves stretching due to the car moving away, resulting in a lower frequency, fR. Thus, the correct answer is A. fL > fR.

To learn more about frequency

https://brainly.com/question/254161

#SPJ8

The efficiency of the system of the levers is  122%.

We have to note that the efficiency is the ratio of the work out put to the work out put multiplied by 100. In this case, we are told that a lift is used to carry boxes to the top floor of a hotel 20 m high. A total weight of 100 kg of boxes was carried up in 20 seconds. and that  the useful output of the engine driving the lift mechanism is 1.2 kilowatt.

Work input = 100 Kg * 9.8 m/s^2* 20 m = 19600 J

Work output = 1.2 kilowatt * 10^3 * 20 = 24000 J

Then we have;

Efficiency = Work out put/ Work input * 100

= 24000/19600 * 100

= 122%

Learn more about efficiency:https://brainly.com/question/30333608

#SPJ1

Answer:

The fuse wire is made up of Sn (tin) and Pb (lead) alloy because of its high resistance and low melting point.

∙ The tin and lead alloy is a eutectic composition (low melting point composition) consisting of 62% tin plus 38% lead.

∙ Melting point of this alloy is 183 ^C

Explanation:

The total mechanical energy of the system change into its motion as the ball rolls down the ramp.

As the ball rolls down on the ramp, the potential energy is converted to kinetic energy. If there is no friction, all of the energy is converted into kinetic energy which leads to increase in the motion of the ball.

So we can conclude that the total mechanical energy of the system change into its motion as the ball rolls down the ramp.

Learn more about energy here: https://brainly.com/question/13881533

#SPJ1

The Andromeda Galaxy distance is approximately 2.52 million light-years away from us.

The Andromeda Galaxy (M31) is indeed similar to our own Milky Way galaxy, but slightly larger with a linear diameter of 140,000 light-years along its longest axis. To determine its distance from us, we can use the angular diameter, which is 3.18°.

We can use the small-angle formula to find the distance. This formula relates the angular diameter (in radians), the actual diameter, and the distance between the observer and the object:

angular diameter (radians) ≈ actual diameter / distance

First, we need to convert the angular diameter from degrees to radians:

3.18° * (π radians / 180°) ≈ 0.0555 radians

Now, plug in the values into the small-angle formula:

0.0555 radians ≈ 140,000 light-years / distance

To solve for the distance, divide both sides of the equation by 0.0555 radians:

distance ≈ 140,000 light-years / 0.0555 radians
distance ≈ 2,522,522 light-years

For more about distance:

https://brainly.com/question/15172156

#SPJ11

The distance in mm between these minima is 0.29 ×\(10^{-3}\) m

For first minima, m=1, Then,

\(a\sin \theta_1 = \lambda_1 \Rightarrow \sin\theta_1 = \frac{\lambda_1}{a} \Rightarrow \theta_1 = \sin^{-1}\left(\frac{589.1\times10^{-9}}{2.4\times 10^{-6}}\right) = 14.2^{\circ}\)

\(a\sin \theta_2 = \lambda_2 \Rightarrow \sin\theta_2 = \frac{\lambda_2}{a} \Rightarrow \theta_2 = \sin^{-1}\left(\frac{589.6\times10^{-9}}{2.4\times 10^{-6}}\right) = 14.22^{\circ}\)

Hence the required angle is , (14.22 - 14.2) = 0.02o

The distance between these two minima,

\(\Delta y = y_2 -y_1 = \frac{D}{a}\left( \lambda_2-\lambda_1\right) = \frac{1.4}{2.4\times 10^{-6}}\left(0.5\times 10^{-9} \right ) = 0.29\times 10^{-3} \hspace{2mm} m\)

This distance is best measured using a microscope.

The length of a particular path taken by an object between two points is its distance, such as the distance traveled through a maze. In some cases, such as when a ball is thrown straight up or the Earth completes an orbit, this can even be a closed distance along a closed curve that begins and ends at the same location. The mathematical term for this is the curve's arc length. It is also possible to signify the distance traveled: a "ahead" distance is positive and a "backward" distance is negative.

When building vehicles or mechanical gears, it can be helpful to take circular distance—the distance covered by a

Learn more about distance here:

https://brainly.com/question/13034462

#SPJ4

The other options listed (thinner bright fringes, brighter fringes, decreased distance between dark fringes, and more bright fringes) are not affected by changes in wavelength in a double-slit experiment.

If the wavelength of light were increased in a double-slit experiment, the angular separation between bright fringes would increase. This is because the distance between the slits and the screen remains the same, but the larger wavelength of light causes the interference pattern to spread out more, resulting in a wider angle between the bright fringes. The other options listed (thinner bright fringes, brighter fringes, decreased distance between dark fringes, and more bright fringes) are not affected by changes in wavelength in a double-slit experiment.
Visit here to learn more about wavelength:

https://brainly.com/question/31143857

#SPJ11

When a bow is drawn and has 40 J of potential energy, the arrow's kinetic energy when fired will be:

Your answer: d. 40 J

Explanation:

Potential energy is the energy that an object possesses due to its position, configuration, or state of being. It is stored energy that has the potential to do work in the future. The amount of potential energy that an object has depends on its position or configuration relative to other objects or systems. For example, a bow that is pulled back has potential energy that can be released as kinetic energy when it is released.

Kinetic energy, on the other hand, is the energy that an object possesses due to its motion. It is the energy that an object possesses because it is in motion and is able to do work by causing a change in another object's motion or position. The amount of kinetic energy that an object has depends on its mass and its velocity. For example, a moving car has kinetic energy that can be transferred to another object if it collides with it.

When the bow is drawn, it stores potential energy. When fired, this potential energy is converted into kinetic energy for the arrow. In an ideal situation with no energy loss, the arrow's kinetic energy will be equal to the bow's potential energy. Therefore, the arrow will have a kinetic energy of 40 J.

To learn more about Potential Energy and Kinetic Energy. Please Visit:

https://brainly.com/question/30176483

#SPJ11

The golf ball spends approximately 1.46 seconds in the air before hitting the water. Just before striking the water, its speed is approximately 18.84 m/s.

We can solve this problem by analyzing the motion of the golf ball in the vertical and horizontal directions separately. In the vertical direction, the ball falls a distance of 12.3 m due to gravity. We can use the equation of motion for vertical motion, which is given by:

\(h = (1/2)gt^2\)

where h is the vertical distance, g is the acceleration due to gravity (approximately 9.8 \(m/s^2\)), and t is the time. Rearranging the equation, we can solve for t:

\(t = \sqrt(2h / g) = \sqrt(2 * 12.3 / 9.8)\) ≈ 1.46 s

Therefore, the ball spends approximately 1.46 seconds in the air.

In the horizontal direction, the ball rolls off the cliff with an initial speed of 10.2 m/s. Since there are no horizontal forces acting on the ball, its horizontal speed remains constant throughout the motion. Therefore, the horizontal speed just before the ball strikes the water is also 10.2 m/s.

Combining the vertical and horizontal components of motion, we can find the resultant velocity just before the ball hits the water using the Pythagorean theorem:

\(v = \sqrt(v_{horizontal}^2 + v_{vertical}^2) = \sqrt(10.2^2 + 0)\) ≈ 10.2 m/s

Therefore, the speed of the ball just before it strikes the water is approximately 18.84 m/s.

Learn more about Pythagorean theorem here:

https://brainly.com/question/18372032

#SPJ11