Need answer ASAP!!

Which of the following elements has the greatest atomic radius? *

A) Mg
B) Sr
C) Ca
D) Ba

Answer:

density = (mass) divided by (volume)

or just D = M/V

Answer:

Zirconium, Zr, 40

Explanation:

Protons can be found by looking at the atomic number. Neon's atomic number is 10, so just multiply 10 by 4 and you get 40.

The balanced for the reaction is:

2KI + Pb(NO₃)₂ → Pbl₂ + 2KNO₃

When the equation is balanced, the number of atoms for each element on both the reactant and product sides of the equation are equal. This can be seen below:

      Reactant   Product

K         2                 2

I          2                  2

Pb      1                    1

N       2                   2

O       6                  6

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

Put the given values into the formula and calculate for n:

The number of moles of the gas sample is 1.0 mol.

Explanation:

According to Charles law : V/T=k (constant).

the volume temperature relationship will be

V/T = 117.5/25 = 4.7

hope this helps you.

The claim that vinyl gloves have a higher leak rate than latex gloves is supported by the study at a significance level of 0.005.

To determine if vinyl gloves have a higher leak rate than latex gloves, we can conduct a hypothesis test.

The z-value is calculated as:

z = (p₁ - p₂) / √((p₁(1 - p₁) / n₁) + (p₂(1 - p₂) / n₂))

where p₁ and p₂ are the sample proportions, and n₁ and n₂ are the sample sizes.

Certainly! Let's calculate the z-value to determine if vinyl gloves have a higher leak rate than latex gloves.

For vinyl gloves:

Sample size (n₁) = 240

Leaking gloves (x₁) = 0.63 * 240 = 151.2 (approximated to 151)

For latex gloves:

Sample size (n₂) = 240

Leaking gloves (x₂) = 0.07 * 240 = 16.8 (approximated to 17)

We will calculate the z-value using the formula:

z = (p₁ - p₂) / √((p₁(1 - p₁) / n₁) + (p₂(1 - p₂) / n₂))

where p₁ and p₂ are the sample proportions.

p₁ = x₁ / n₁ = 151 / 240 ≈ 0.629

p₂ = x₂ / n₂ = 17 / 240 ≈ 0.071

Calculating the z-value:

z = (0.629 - 0.071) / √((0.629 * (1 - 0.629) / 240) + (0.071 * (1 - 0.071) / 240))

z ≈ 13.239

The calculated z-value is approximately 13.239. To determine if the claim is supported, we compare this value to the critical z-value for a one-tailed test at a significance level of 0.005.

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The denaturation and extension steps in PCR thermocycling are the hottest in temperature. The three stages are as follows: Denaturation, Annealing, Extension, This reaction typically occurs at 72°C.

PCR thermocycling temperatures:Temperature changes that occur during PCR thermocycling are highly specific. The exact temperature required for each stage of PCR depends on the DNA molecule being amplified and the specific primers being used. In general, the denaturation and extension steps in PCR thermocycling are the hottest in temperature. During the denaturation stage, the DNA strands are separated by heating the reaction mixture to around 95°C. During the extension stage, Taq polymerase adds nucleotides to the 3' end of the primers to synthesize the complementary DNA strand. This reaction typically occurs at 72°C.

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The theoretical yield is obtained from the limiting reactant in the reaction.

The question is incomplete but I will do my best to help. In a reaction, the theoretical yield is calculated from the limiting reactant in the reaction. Therefore, in order to obtain the limiting reactant, we must first obtain which of the reactants is the limiting reactant.

When that is done, the stoichiometry of the reaction can now be used to calculate the value of the theoretical yield from the number of moles of the limiting reactant.

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Answer:

360

Explanation:

2.23 moles of propane react when 294 g of CO₂ is formed .

Moles is a unit which is equal to the molar mass of an element.

A reaction is given

C₃H₈ +50₂ → 3CO₂ + 4H₂O

Grams of CO₂ formed = 294 gm

In moles = 294 /44 = 6.68 moles.

Let x be the moles of C₃H₈ is x

Mole ratio of CO₂ to C₃H₈ = 3 : 1

so

6.68 /x = 3/1

x = 6.68 /3 = 2.23 moles

Therefore 2.23 moles of propane react when 294 g of CO₂ is formed .

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Answer:

Explanation:

As weathered products are carried away, fresh rocks are exposed to further weathering.

Answer:

melting

Explanation:

I think think helpful it is or not

When 400.0 mL of a 0.100 M solution of barium chloride is mixed with 400.0 mL of a 0.100 M solution of iron(III) sulfate, mass of approximately 9.336 grams of barium sulfate can be produced.

The mass of barium sulfate that can be produced when the two solutions are mixed,

For barium chloride solution:

Volume = 400.0 mL = 0.4000 L (converted to liters)

Molarity = 0.100 mol/L

Number of moles of barium chloride = Molarity * Volume = 0.100 mol/L * 0.4000 L = 0.040 mol

For iron(III) sulfate solution:

Volume = 400.0 mL = 0.4000 L (converted to liters)

Molarity = 0.100 mol/L

Number of moles of iron(III) sulfate = Molarity * Volume = 0.100 mol/L * 0.4000 L = 0.040 mol

Both solutions have the same number of moles of their respective compounds, which means that they are in a 1:1 ratio according to the balanced chemical equation.

The balanced chemical equation for the reaction between barium chloride and iron(III) sulfate is:

BaCl2 + Fe2(SO4)3 -> BaSO4 + 2FeCl3

Therefore, the limiting reactant is the one that produces fewer moles of the product, which in this case is barium chloride and iron(III) sulfate.

Now, let's calculate the mass of barium sulfate produced:

Molar mass of BaSO4 = 137.33 g/mol + 32.06 g/mol + 4*(16.00 g/mol) = 233.39 g/mol

Number of moles of barium sulfate = Number of moles of limiting reactant (BaCl2 or Fe2(SO4)3)

Mass of barium sulfate = Number of moles of barium sulfate * Molar mass of BaSO4

Mass of barium sulfate = 0.040 mol * 233.39 g/mol

Mass of barium sulfate = 9.3356 g

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The rate of change in concentrations of H2O2 and I3- are 2.8 x 10^-3M/s when the concentration of I− drops from 1. 000 M to 0. 871 M in 15s.

We know that the reaction rate is equal to change in concentration of reactant or product/ time taken.

The change in concentration of I− = 1.000 M - 0.871 M = 0.129M

The time taken to drop the concentration of I- (t) = 15s

Then the required reaction rate for I- = 0.129/15 = 0.0086M/s

The rate of change of concentration of H2O2 is

From the reaction: H2O2(aq)+3I−(aq)+2H+(aq)→I3−(aq)+2H2O(l)

(a) 3 moles of I⁻ are used up for every 1 mole of H2O2

Hence, the rate of change in concentration of H2O2 is:

Δ[H2O2]/Δt = 0.0086 M/sec * 1/3 = 0.00286 = 2.8 x 10^-3M/s

(b) Similarly for every 3 moles of I- 1 mole of I3- is used up. So,

The rate of change in concentration of I3- is:

Δ[I3−]/Δt = 0.0086 M/sec * 1/3 = 0.00286 = 2.8 x 10^-3M/s

Hence the rate of change in concentrations of H2O2 and I3- are same.

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Answer:

1.64 moles O₂

Explanation:

Part A:

Remember 1 mole of particles = 6.02 x 10²³ particles

So, the question becomes, how many  '6.02 x 10²³'s are there in 9.88 x 10²³ molecules of O₂?

This implies a division of given number of particles by 6.02 x 10²³ particles/mole.

∴moles O₂ = 9.88 x 10²³ molecules O₂ / 6.02 x 10²³ molecules O₂ · mole⁻¹ = 1.64 mole O₂

_______________

Part B needs an equation (usually a combustion of a hydrocarbon).

the answer is cold front

Answer:

19.6 mole

Explanation:

because Fe molar mass is 56

Answer:

pls snap the question well

Answer:

NO2 (nitrogen dioxide)

Explanation:

The empirical formula is the formula of the compound with its proportions of each element being in the simplest mole ratio.

That being said, first, we find the number of moles of each element.

n(N) = mass present/molar mass (m/M) = 42.05/14.01 (use a periodic table to locate the molar mass)

n(N) = 3.00143 mol

n(O) = m/M = 95.95/16.00 = 5.99688 mol

∴ the ratio of nitrogen to oxygen = 3.00143 : 5.99688

divide both sides by 3.00143, and we get 1 : 1.998,

which we can then round up to 1 : 2.

Hence, the empirical formula of the compound is \(NO_{2}\)

Answer:

Explanation:

The false statement about methane degrades the ozone layer. Methane is a greenhouse gas that contributes to global warming. It is produced through natural processes, as well as human activities. Therefore, option A is correct.

Methane is a greenhouse gas and is known to contribute to global warming. It is produced through natural processes, as well as human activities. Methane is the primary component of natural gas, making statement C true.

It is released from various sources, including the decomposition of organic matter, such as sewage and manure, making statement B true. However, it does not degrade the ozone layer, which is primarily affected by substances such as chlorofluorocarbons (CFCs) and halons.

Methane has a much higher global warming potential compared to carbon dioxide over a shorter time frame, which makes it a significant contributor to climate change.

Its presence in the atmosphere traps heat, leading to an increase in temperatures on Earth. Reducing methane emissions is crucial for mitigating climate change.

In conclusion, while methane is a greenhouse gas and is produced from sewage and manure, it does not degrade the ozone layer. Therefore, option A is correct.

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Answer:

This should help you with your problem

The symbol that is used to indicate  “produces” or “yields” is "→"

Forward arrow is used to indicate the reaction moving towards products.

H₂SO₄ (aq) + 2NaOH(aq) →  Na₂SO₄(s) + 2H₂O (l)

This reaction yields or produces sodium sulphate and water when sulphuric acid and sodium hydroxide reacts.

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Dideoxynucleotides differ from deoxynucleotides by the absence of the 3' -OH group, which stops further DNA chain elongation. This property is exploited in Sanger sequencing.

Dideoxynucleotides (ddNTPs) are modified forms of deoxynucleotides (dNTPs) that lack a hydroxyl (-OH) group at the 3' position of the sugar moiety. This modification prevents the formation of phosphodiester bonds between adjacent nucleotides, which is crucial for DNA chain elongation during DNA replication and sequencing. The four dideoxynucleotides commonly used are labeled as A*, C*, G*, and T*, where the asterisk (*) denotes the absence of the 3' -OH group. By incorporating dideoxynucleotides into a DNA sequencing reaction, a technique known as Sanger sequencing or chain termination sequencing can be performed. This method relies on the random termination of DNA synthesis at specific nucleotide positions, resulting in the production of a set of DNA fragments of varying lengths. These fragments are then separated by size using gel electrophoresis, revealing the sequence of the original DNA template. Since dideoxynucleotides lack the 3' -OH group, they cannot form phosphodiester bonds with the next incoming nucleotide. Consequently, once a dideoxynucleotide is incorporated into the growing DNA chain, further elongation is prevented. The presence of the dideoxynucleotide at different positions along the DNA template produces a series of terminated fragments, each corresponding to the position of the respective dideoxynucleotide.

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A) In precipitation reaction when the solution is saturated, the expected concentration of both calcium ions and oxalate ions would be approximately 0.0192 mol/L.

B) After equilibrium is reestablished, the expected concentrations of calcium ions and oxalate ions are approximately 2.498 × 10⁻⁴ mol/L and 0.0192 mol/L, respectively.

To answer the given questions about the precipitation reaction of calcium oxalate, let's break it down into two parts:

A) The concentration of calcium ions and oxalate ions in the saturated solution can be determined when an excess amount of calcium oxalate is added to 100.0 mL of pure water.

Since excess calcium oxalate is added, it means that the solution will contain more calcium oxalate than what can dissolve. At saturation, the solution is in equilibrium with the solid calcium oxalate.

Let's assume the concentration of calcium ions and oxalate ions in the saturated solution is represented by "x" (in mol/L).

The equilibrium expression for the reaction is:

Ks = [Ca²⁺][C₂O₄²⁻]

Given that the equilibrium constant Ks = 3.7 × 10⁻⁴, we can set up the equation:

3.7 × 10⁻⁴ = x * x

Solving for "x," we find:

x = √(3.7 × 10⁻⁴) ≈ 0.0192 mol/L

Therefore, when the solution is saturated, the expected concentration of both calcium ions and oxalate ions would be approximately 0.0192 mol/L.

B) If 1.00 mg of calcium chloride (CaCl2) were added to the mixture, what would be the expected concentrations of calcium ions and oxalate ions once equilibrium is reestablished?

Since calcium chloride (CaCl₂) dissociates completely into calcium ions (Ca²⁺) and chloride ions (Cl⁻) in solution, the addition of 1.00 mg of CaCl₂ will result in the addition of 1.00 mg of calcium ions.

First, we need to convert the mass of calcium ions from mg to mol:

1.00 mg = 0.001 g

0.001 g / (molar mass of Ca²⁺) = 0.001 g / 40.08 g/mol ≈ 2.498 × 10⁻⁵ mol

Since the solution volume is assumed to be unchanged, the concentrations of calcium ions and oxalate ions will change but not the molar amounts.

The concentration of calcium ions is the molar amount (2.498 × 10^(-5) mol) divided by the total solution volume (100.0 mL or 0.100 L):

Concentration of calcium ions = (2.498 × 10⁻⁵ mol) / 0.100 L ≈ 2.498 × 10⁻⁴ mol/L

The concentration of oxalate ions remains the same as in part A since the addition of calcium chloride does not affect the concentration of oxalate ions.

Therefore, after equilibrium is reestablished, the expected concentrations of calcium ions and oxalate ions are approximately 2.498 × 10⁻⁴ mol/L and 0.0192 mol/L, respectively.

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Answer:

Explanation:

The correct answer is B. isotopes.

Isotopes are atoms of the same element that have the same number of protons but different numbers of neutrons. This difference in the number of neutrons leads to variations in their atomic mass but does not affect their chemical properties or reactivity. Isotopes of an element have similar chemical behaviors but may have slightly different physical properties due to the difference in atomic mass.

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Answer:299,800,000

Explain: The speed of light is 3.00x108m/s and in mph is 6.708 x 108.

Answer:

electrons is the answer to your question

Answer:

what are negatively charged particles called?

ELECTRONS

T/F lightning is a strong electrical current moving through air

TRUE