Lines L and M are parallel. 3/4 5 - L -M 2 1/6 38 7 Find : m​

Answer:

The range is −5≤y≤−1 - 5 ≤ y ≤ - 1 .

Answer:

1.19 if its not that its 0.19 but i believe its 1.19.

Step-by-step explanation:

Answer:  1.19 Is 1 19/100 as a decimal

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

the answer would be (x-2)(x+2)

One solution for the given linear equation is the poiont (1, 1)

We want to find a solution for the linear equation:

y = 2x - 1

A solution will be any pair (x, y), such that when we replace these values in the equation, it becomes true.

To find a solution we can evaluate the equation in some value of x, for example, if x = 1

y = 2*1 - 1

y = 2 - 1

y = 1

(1, 1) is a solution for the line.

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The seepage quantity is approximately 0.0036 ft³/s/ft of dam.

To find the seepage quantity, we can use Darcy's law,

Q = KiA

where Q is the seepage quantity (ft³/s), K is the hydraulic conductivity (ft/s), i is the hydraulic gradient, and A is the cross-sectional area perpendicular to the flow direction (ft²).

First, we need to calculate the hydraulic gradient at point C:

i = Δh / ΔL

where Δh is the head difference between point C and the downstream toe, and ΔL is the horizontal distance between these two points. From the flow net, we can estimate Δh to be about 4.5 inches and ΔL to be about 15 feet. Therefore,

i = 4.5 / (15 x 12) = 0.025 ft/ft

Next, we can calculate the seepage velocity:

v = Ki

where v is the seepage velocity (ft/s). From the given soil parameters, K = 0.0003 ft/s. Therefore,

v = 0.0003 x 0.025 = 0.0000075 ft/s

Finally, we can calculate the seepage quantity:

Q = Av

where A is the cross-sectional area of the dam at point C. From the given dimensions, we can estimate A to be about 480 ft². Therefore,

Q = 480 x 0.0000075 = 0.0036 ft³/s

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--The complete question is, The soil parameters provided in the problem statement are,

k = 0.0003 in/sec

G = 2.65

θ = 0.72

Find the seepage quantity.--

True, free bilirubin is transported by the blood to the liver.

Macrophages begin the disposal of hemoglobin by separating the heme from the globin. They hydrolyze the globin into free amino acids, which can be used for energy-releasing catabolism or recycled for protein synthesis.

Bilirubin

Bilirubin is a red-orange compound that occurs in the normal catabolic pathway that breaks down heme in vertebrates. This catabolism is a necessary process in the body's clearance of waste products that arise from the destruction of aged or abnormal red blood cells.

Hemoglobin

Hemoglobin is a protein in your red blood cells that carries oxygen to your body's organs and tissues and transports carbon dioxide from your organs and tissues back to your lungs.

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Answer: The answer is 1 and 2/3

Hope this helps you bye

Solving a linear equation, we will see that after 9 days he cuts the last section.

We know that the initial length of the piece of cloth is 20m, and the taylor each day cuts a piece of 2 meters of it.

So, the length as a function on the number of days, is:

L(x) = 20m - 2m*x

Here we just need to solve:

L(x) = 2m

Because the last cut is when the long piece measures 4 meters (in that case he does one cut and has the two final pieces of 2 meters).

Solving that, we get:

20m - 2m*x = 2m

20m - 2m = 2m*x

18m/2m = x = 9

After 9 days he cuts the last section.

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Answer:2

Step-by-step explanation:

Answer:

i think the 3rd one i have not done that in a while

Step-by-step explanation:

sorry if its not right

Answer:

radius of mars= 3,397km

The path straight to the end of the hike is 6 km farther than past the scenic lookout.

The map is not given, but the question can still be answered

From the question, the positions are given as::

Maria = (4, -4)

Scenic = (2, 3)

End = (-5, 5)

The distance between Maria and the end point is calculated using:

\(d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2\)

So, we have:

\(Route\ 1 = \sqrt{(4 + 5)^2 + (-4 -5)^2}\)

\(Route\ 1 = 13\)

The distance between Maria and the scenic lookout is calculated using:

\(d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2\)

So, we have:

\(Route\ 2 = \sqrt{(4 - 2)^2 + (-4 -3)^2}\)

\(Route\ 2 = 7\)

The distance between both routes is:

Distance = 13 - 7

Evaluate

Distance = 6

Hence, the path straight to the end of the hike is 6 km farther than past the scenic lookout.

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Dont cheat Answer:

Step-by-step explanation:

Dont cheat, you got this!

Answer:

I think this is how....

Step-by-step explanation:

4x + y = 12

4x + y -y = 12 - y

4x = 12

*divide by 4 on each side*

x = 3

What's the question?

The parent square root function  \(f(x)=\sqrt{x}\) has its graph on the first quadrant since both x and y are positive or zero.

The function \(f(x)=\sqrt{x+3} -4\) is the translation of the parent 3 units left and 4 units down, hence its start point moves to the third quadrant.

Said that, none of the attached graphs represent the given function.

The first graph is \(f(x)=\sqrt{x+3} +4\) , the middle one is not closer to the given function and the last one is  \(f(x)=\sqrt{x-3} -4\).

Answer:

\(6i \sqrt{3}\)

Step-by-step explanation:

To simplify a negative square root, you can rewrite the \(\sqrt{-27}\):

\(\sqrt{-27}\) == \(\sqrt{-1 * 27}\)

Which can then be rewritten itself as:

\(\sqrt{-1} * \sqrt{27}\)

Now, you need to factor the 27, traditionally you will get to remember these but:

\(\sqrt{3 * 9} * i == \sqrt{3 * 3^{2} }* i\)

As you are square rooting, the \(3^{2}\) can be cancelled and simplified:

\(3 \sqrt{3} * i\)

Now, as there is already a 2 before the square root, you can simply multiply the 3i by 2:

\((3i * 2) \sqrt{3} = 6i \sqrt{3}\)

Hope this helps!

To calculate the maximum (M V/M 01), we can use the following formula:
(M V/M 01) = (1 - ε 1) / (1 - ε 1 * ε 2 * ε 3)

Given that ε 1 = ε 2 = ε 3 = 0.15, we can substitute these values into the formula:
(M V/M 01) = (1 - 0.15) / (1 - 0.15 * 0.15 * 0.15)

Simplifying the equation gives us:
(M V/M 01) = 0.85 / 0.9827

Calculating this division, we find:
(M V/M 01) ≈ 0.8656

The value of (M V/M 01) is approximately 0.8656.

Now, let's address why an explicit optimization is not required in this case. In the problem statement, it is mentioned that I sp1 = I sp2 = I sp3 = 370 s. This means that the specific impulse of each stage is the same. Additionally, ε 1 = ε 2 = ε 3 = 0.15. This indicates that each stage has the same exhaust velocity ratio.

When the specific impulse and exhaust velocity ratios are the same for each stage, an explicit optimization is not necessary. This is because the rocket stages are already optimized to achieve the desired characteristics. Therefore, we can directly calculate the maximum (M V/M 01) without the need for additional optimization.

Moving on to the next part of the question, we are given the payload mass (M L) as 20000 kg. To compute the structural mass of the first stage (M s1), we can use the following formula:

M s1 = M V * M L / (M V/M 01 - M L)

Substituting the given values, we have:
M s1 = 0.8656 * 20000 / (0.8656 - 20000)

Simplifying the equation gives us:
M s1 ≈ 0.0175 * 20000 / (-19983.49)

Calculating this division, we find:
M s1 ≈ 0.0175 * -0.0010002
M s1 ≈ -0.0000175

The structural mass of the first stage (M s1) is approximately -0.0000175 kg. However, this negative value doesn't make physical sense. Therefore, there might be an error or inconsistency in the given values or calculations. It's recommended to double-check the given information and calculations to ensure accuracy.

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Answer:

The point of intersection between 2x+3y=12 and 2x-y=4 is (3,2)

Step-by-step explanation:

Given a set of elements U = {a, b, c, d, e, f}, and two subsets of U:

X = {a, b, c, d}, and Y = {b, c, d, e, f}, we need to show that (X ∩ Y)′ = X′ ∪ Y′.

Firstly, we find the intersection of X and Y, i.e., X ∩ Y.

Hence, X ∩ Y = {b, c, d}.

Next, we need to find the complement of the intersection (X ∩ Y)′.

The complement of a set A is defined as the set of all elements of U that do not belong to A.

Therefore, the complement of the intersection of X and Y is:(X ∩ Y)′ = {a, e, f}

Now, we need to find the union of X′ and Y.

We know that the complement of a set A can be defined as the set of all elements of U that do not belong to A, i.e., U - A.

Therefore, we have:

X′ = U - X

= {e, f}

Y′ = U - Y

= {a}

Thus, X′ ∪ Y′ = {e, f, a}.

Therefore, we have (X ∩ Y)′ = {a, e, f} and X′ ∪ Y′ = {e, f, a}.

So, we can say that (X ∩ Y)′ = X′ ∪ Y′.

Hence, the given statement is proved.

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We require a degree of freedom of 14 to create a 95% confidence interval for the population mean from a sample size of 15.

Given that,

Assume that a sample size of 15 will be used to calculate a 95% confidence interval for the population mean.

We have to find how many degrees of freedom should we utilize.

We know that,

The answer to the problem is

A 95% confidence interval is being created.

The sample size is 15 (<30). Therefore, in order to account for the decreased sample size and use the sample SD, we must adapt and use a t-value rather than a Z score.

As a reflection of sample size, it should be noted that the t-value is dependent on the degrees of freedom (df). df = n-1 is the formula used to calculate a confidence interval using the t-distribution.

Therefore, we require a degree of freedom of 14 to create a 95% confidence interval for the population mean from a sample size of 15.

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Answer:

19.545

Step-by-step explanation:

Answer:

Answer:

80 lemons

Step-by-step explanation:

Let x represent the amount of lemons that were on the tree.

We can use this to set up an equation:

\(40\%x=32\)

Note that percentages can also be written as that number over 100.

\(\frac{40}{100}x=32\)

Simplify the fraction.

\(\frac{2}{5}x=32\)

Multiply both sides by 5

\(2x=160\)

Divide both sides by 2

\(x=80\)

There were 80 lemons on the tree before he picked the lemons.

As per the functions given, (f+g)(x) = f(x) + g(x) adding the two functions (f+g)(x) = 3x^2 - 5x + 9.

Adding the two functions, we get:

(f+g)(x) = (2x^2 - 5x + 5) + (x^2 + 4)

(f+g)(x) = 3x^2 - 5x + 9

Therefore, (f+g)(x) = 3x^2 - 5x + 9.

b) (f-g)(x) = f(x) - g(x)

Subtracting the two functions, we get:

(f-g)(x) = (2x^2 - 5x + 5) - (x^2 + 4)

(f-g)(x) = x^2 - 5x + 1

Therefore, (f-g)(x) = x^2 - 5x + 1.

c) (f x g)(x) = f(x) * g(x)

Multiplying the two functions, we get:

(f x g)(x) = (2x^2 - 5x + 5) * (x^2 + 4)

(f x g)(x) = 2x^4 - 5x^3 + 5x^2 + 8x^2 - 20x + 20

(f  x g)(x) = 2x^4 - 5x^3 + 13x^2 - 20x + 20

Therefore, (f x g)(x) = 2x^4 - 5x^3 + 13x^2 - 20x + 20.

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The probability of NOT drawing a face card from a standard deck of 52 cards is 10 over 13.

First determine the total number of face cards and non-face cards in a standard deck of 52 cards.                                   In a standard deck, there are 12 face cards (3 face cards per suit: Jack, Queen, and King, and 4 suits: Hearts, Diamonds, Clubs, and Spades). This means there are 52 - 12 = 40 non-face cards.

Now, we'll calculate the probability of NOT drawing a face card:
Probability = (Number of favorable outcomes) / (Total number of outcomes)
Probability of NOT drawing a face card = (Number of non-face cards) / (Total number of cards)
Probability = 40 / 52

Simplify the fraction by dividing the numerator and denominator by their greatest common divisor (4):
Probability = (40/4) / (52/4)
Probability = 10 / 13

So, the probability of NOT drawing a face card from a standard deck of 52 cards is 10/13. Your answer: 10 over 13.

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With the informations given by the question, we have the following diagram:

To calculate the height, we have the following trigonometric relation(since it is a right triangle):

Just solving for 'h':

With this, we have our height. The height of the kite is 363.7 ft

The next step that Ian needs in bisecting the line segment CD is; keep the compass the same width, and place it on the other point D.

Bisecting a line segment simply means we are trying to divide the line segment into two equal parts. The steps to use to bisect a line segment is as follows;

Step 1: Place a compass at the center of line CD and make an arc at both ends of line CD.

Step 2: Place the compass at each of the arcs you made at both ends of CD and make a mark above and below line CD.

Step 3: Join the points of intersection of both arcs above and both arcs below line AB. That is the perpendicular bisector of line AB.

Looking at Ians' procedure, his last step was what is step 1 of the above i have listed and as such his next step would be to keep the compass the same width, and place it on the other point D.

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Answer: Place the compass on a point that is not on segment CD

Step-by-step explanation: option d is correct

H0 says that the population means are equal.

In the context of a hypothesis test for the difference of means between two independent populations (x1 and x2), the null hypothesis (H0) states the following about the relationship between the two population means:
H0 says that the population means are equal.
In other words, the null hypothesis assumes that there is no significant difference between the means of the two populations. The alternative hypothesis would then state that the population means are different. Remember that hypothesis testing is a process to determine whether there is enough evidence to reject the null hypothesis in favor of the alternative hypothesis.

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The critical value for a t-test with a 0.05 level of significance in the lower tail only and 24 degrees of freedom is approximately -1.711.

In a t-test, the critical value is the value at which the test statistic must surpass in order to reject the null hypothesis. The critical value depends on the level of significance and the degrees of freedom.

For a lower-tailed t-test with a 0.05 level of significance and 24 degrees of freedom, we consult a t-distribution table or use statistical software to determine the critical value. Looking up the value for 24 degrees of freedom at a significance level of 0.05 in the lower tail, we find the critical value to be approximately -1.711. This means that the test statistic must be less than -1.711 to reject the null hypothesis at the 0.05 level of significance.

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