Just double checking answers. Please helppp

Option D) 180K is the correct answer.

Hence, the temperature of the gas before the pressure changed is 180K

Gay-Lussac's law states that "the pressure exerted by a given mass of gas at constant volume varies directly with its absolute temperature".

It is expressed as;

\(\frac{P_1}{T_1} = \frac{P_2}{T_2}\)

Given the data in the question;

Initial pressure of gas; \(P_1 = 0.5atm\)

Final pressure of gas; \(p_2 = 2.5atm\)

Final temperature; \(T_2 = 900K\)

Initial temperature before pressure change; \(T_1 = \ ?\)

We substitute our given values into the expression above.

\(\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\\frac{0.5atm}{T_1} = \frac{2.5atm}{900K}\\\\T_1 = \frac{0.5atm\ *\ 900K}{2.5atm}\\ \\T_1 = \frac{450K}{2.5}\\\\T_1 = 180K\)

Option D) 180K is the correct answer.

Hence, the temperature of the gas before the pressure changed is 180K.

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On the basis of oxidation number considerations, the oxide that would not react with molecular oxygen is SO3. This is because sulfur already has the maximum oxidation number of +6 in this compound.

Oxidation number is a measure of the number of electrons that an atom has lost or gained in a compound. In the case of NO, nitrogen has an oxidation number of +2, so it can still react with oxygen to form NO2, where nitrogen has an oxidation number of +4. Similarly, in N2O, nitrogen has an oxidation number of +1, so it can also react with oxygen to form a compound with a higher oxidation number, such as N2O3 or N2O5. In P4O6, phosphorus has an oxidation number of +3, so it can also react with oxygen to form P4O10, where phosphorus has an oxidation number of +5.

However, in SO3, sulfur already has the maximum oxidation number of +6, so it cannot react with oxygen to form a compound with a higher oxidation number. Therefore, SO3 is the oxide that would not react with molecular oxygen.

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Answer:

MP hippopotamus

Explanation: I'm in the fifth grade so yeah I really don't know this so I'm just going to say some random stuff and white cheddar mac and cheese warm TV perfect back MD 11443 to 2885 eleven 12:20 to 11 132 0.24 answer

The order for reactant A is 2 and the order for reactant B is 1. For the first reaction, the overall order of the reaction is 3 and for the second reaction, the overall order of the reaction is 5.

The order of a reaction is the sum of the exponents in the rate law expression that relates the rate of a chemical reaction to the concentrations of the reactants.

To determine the order of each reactant, we need to compare the initial rates of reaction at different concentrations while keeping the concentration of the other reactant constant.

For reactant A:

Exp#1 (0.100 M A, 0.100 M B): initial rate = k(0.100)^2(0.100) = 0.001 k

Exp#2 (0.200 M A, 0.100 M B): initial rate = k(0.200)^2(0.100) = 0.004 k

Exp#3 (0.100 M A, 0.200 M B): initial rate = k(0.100)^2(0.200) = 0.002 k

We can see that when the concentration of A doubles (Exp#1 to Exp#2), the initial rate quadruples, which indicates that A is second order. When the concentration of B doubles (Exp#1 to Exp#3), the initial rate doubles, which indicates that B is first order.

Therefore, the order for reactant A is 2 and the order for reactant B is 1.

To determine the overall order of the reaction, we add the orders of the reactants:

Overall order = 2 (order of A) + 1 (order of B) = 3

Therefore, the overall order of the reaction is 3.

For the second reaction, we can see that the rate depends on the concentration of both reactants, and we cannot determine their individual orders without further information or experiments. However, we can determine the overall order of the reaction by adding the exponents of the concentration terms in the rate law:

Overall order = 1 + 4 = 5

Therefore, the overall order of the reaction is 5.

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Answer:

7. A. ee

8. Genotypes in which the dominant gene must show: Both A & B

9. Genotypes in which the recessive genes must show: A. aa

Answer:

31.Microbial

32.Coke is a grey, hard, and porous fuel with a high carbon content and few impurities, made by heating coal or oil in the absence of air—a destructive distillation process. It is an important industrial product, used mainly in iron ore smelting, but also as a fuel in stoves and forges when air pollution is a concern.

33.examples to show that plastics are non corrosive in nature: Iron nails get rusted when exposed to moisture and air but plastic do not react with water and air. Plastic does not react with strong chemicals. Hence,cleansing chemicals are stored in plastic bottles and not in metal containers.

34.rainfall made sufficiently acidic by atmospheric pollution that it causes environmental harm, typically to forests and lakes. The main cause is the industrial burning of coal and other fossil fuels, the waste gases from which contain sulfur and nitrogen oxides, which combine with atmospheric water to form acids.

35.in an insect or amphibian) the process of transformation from an immature form to an adult form in two or more distinct stages.

38.a medical condition in which the lens of the eye becomes progressively opaque, resulting in blurred vision.

Explanation:

Hope it helps!

The lattice energy of MX is 459.2 kJ/mol.

The lattice energy (ΔH° lattice) of an ionic compound is the energy released when one mole of the solid is formed from its constituent gaseous ions under standard conditions. The lattice energy is calculated using the Born-Haber cycle, which involves several steps including atomization, ionization, dissociation, and sublimation energies.

The lattice energy is related to the Coulombic attraction between the oppositely charged ions in the solid. To calculate the lattice energy for MX, we can use the following equation:

ΔH° lattice = ΔH° sub + ΔH° ion + ΔH° diss + ΔH° formation

where ΔH° sub is the sublimation energy of M(s), ΔH° ion is the first ionization energy of M(g), ΔH° diss is the dissociation energy of X2(g), and ΔH° formation is the enthalpy of formation of MX(s).

Using the given data, we can calculate each of these values and substitute them into the equation to obtain the lattice energy. The final answer should be in units of kJ/mol.

ΔH° sub (M) = 107.3 kJ/mol

ΔH° ion (M) = 577.5 kJ/mol

ΔH° diss (X2) = 242 kJ/mol

ΔH° formation (MX) = -467.6 kJ/mol

ΔH° lattice = 107.3 + 577.5 + 242 + (-467.6) = 459.2 kJ/mol

As a result, MX has a lattice energy of 459.2 kJ/mol.

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Answer:

Language

Explanation:

this is very obvious not to be mean

Considering the definition of molar mass, the correct answer is option c): the mass of 1.85 moles H₂O₂ is 62.9 grams.

The molar mass of substance is a property defined as the amount of mass that a substance contains in one mole.

The molar mass of a compound is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

In this case, you know the molar mass of the elements is:

So, the molar mass of the compound H₂O₂ is calculated as:

H₂O₂= 2× 1 g/mole + 2× 16 g/mole

Solving:

H₂O₂= 34 g/mole

You can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 34 grams, 1.85 moles of the compound contains how much mass?

mass= (1.85 moles× 34 grams)÷ 1 mole

mass= 62.9 grams

Finally, the mass of 1.85 moles H₂O₂ is 62.9 grams.

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The answer is  21.5 L ,So, start with the balanced chemical equation for the decomposition of hydrochloric acid.

An liquid solution of hydrogen chloride is what is known as hydrochloric acid, also referred to as muriatic acid. It has an unmistakably strong odour and is translucent. It is categorised as a powerful acid. In the digestive processes of the majority of mammal species, including humans, it is a part of the gastric acid. A crucial commercial substance and reagent for laboratories is hydrochloric acid.

Chemical burns from hydrochloric acid can be extremely painful if they come into touch with skin or other organs. Ingestion of hydrochloric acid can result in blindness. The concentration of the acid and how long it remains in touch with the organs determine how severe the burns are.

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Answer:

Differences between Orbit and Orbitals

Orbit

An orbit is the simple planar representation of an electron.

It can be simply defined as the path that gets established in a circular motion by revolving the electron around the nucleus

The shape of molecules cannot be explained by an orbit as they are non-directional by nature.

An orbit that is well-defined goes against the Heisenberg principle.

Orbital

An orbital refers to the dimensional motion of an electron around the nucleus in a three-dimensional motion.

An orbital can simply be defined as the space or the region where the electron is likely to be found the most.

The shapes of the molecules can be found out as they are directional by nature.

An ideal orbital agrees with the theory of Heisenberg’s Principles.

Answer:

The hypothetical van't Hoff factor of magnesium nitrate,\(Mg(NO_3)_2\) is 3 .

Explanation:

Lets calculate -

\(Mg(NO_3)_2\rightarrow Mg^2^+ +2NO_3^-\)

We know that ,

\(i=\alpha n+(1-\alpha )\)

Dissociation should be 100% for the hypothetical vant hoff factor , that is

\(\alpha =1\) and \(n=3\) for  \(Mg(NO_3)_2\)

Therefore , putting the given values ,

\(i=1\times3+(1-1 )\)

\(i=3+0\)

\(i=3\)

Hence , the answer is 3.

The hypothetical van't Hoff factor of magnesium nitrate is 3.

Van't Hoff factor is a measure of the deviation of a solution from ideal behavior. It depends on the number of particles in the solution. The more the particles in solution, the greater the Van't Hoff factor and the greater the deviation from ideal behavior.

For Mg(NO3)2, the hypothetical van't Hoff factor is 3 since there are three particles in solution when magnesium nitrate is dissolved in water.

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Answer:

bulb or pump, meniscus, outside

Explanation:

In order to use a pipet, place a BULB OR PUMP at the top of the pipet. Use this object to fill the pipet such that the MENISCUS of the liquid is even with the volume line. Release the liquid, touching the tip of the pipet to the side of the container if necessary to release the last drop OUTSIDE the pipet tip.

To dissolve sugar cubes quickly in a cup of tea, here are two effective methods you can try:Stirring and Crushing, Hot Water Pre-Dissolution.

Stirring and Crushing:

a. Start by placing the sugar cube(s) into the cup of tea. The larger the sugar cubes, the longer they will take to dissolve.

b. Use a spoon or a stirring rod to vigorously stir the tea. The stirring action increases the contact between the sugar cubes and the hot liquid, helping to speed up the dissolution process.

c. While stirring, apply some pressure to the sugar cubes against the walls or base of the cup. This helps to break down the cubes into smaller pieces, exposing more surface area to the tea. Crush the cubes with the back of the spoon or the stirring rod.

d. Continue stirring until all the sugar is dissolved. You can test by observing whether any sugar crystals are visible on the spoon or at the bottom of the cup. If needed, stir a bit longer or crush any remaining sugar crystals.

Hot Water Pre-Dissolution:

a. Fill a separate cup with hot water, ensuring it is hot enough to dissolve the sugar cubes completely.

b. Place the sugar cubes in the hot water and stir until they are fully dissolved. This pre-dissolves the sugar cubes, making it easier and quicker for them to dissolve in the tea.

c. Once the sugar cubes are dissolved in the hot water, pour the sugar solution into your cup of tea.

d. Stir the tea briefly to ensure any remaining undissolved sugar is incorporated.

e. The pre-dissolved sugar solution will mix more readily with the tea, accelerating the overall dissolution process.

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The reaction becomes spontaneous at approximately 2667 Kelvin.

To determine the temperature at which a nonspontaneous reaction becomes spontaneous, we can use the equation ΔG = ΔH - TΔS, where ΔG is the change in Gibbs free energy, ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy.

In this case, we are given ΔH = 144 kJ/mol and ΔS = 54 J/K mol. To convert ΔH to J/mol, we multiply by 1000, giving us ΔH = 144,000 J/mol.

To find the temperature at which the reaction becomes spontaneous, we set ΔG to zero, as this is the condition for equilibrium. Thus, we have 0 = ΔH - TΔS.

Rearranging the equation, we have TΔS = ΔH, and substituting the given values, we get T * 54 J/K mol = 144,000 J/mol.

Dividing both sides by 54 J/K mol, we find that T = 144,000 J/mol / 54 J/K mol = 2667 K.

Therefore, the reaction becomes spontaneous at approximately 2667 Kelvin.

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Answer:

It is not 100% silver, but it contains a high percentage (more than the 98% for sure) of silver.

Explanation:

Hello,

In this case, since the density of silver is 10.49 g/cm³, we can substantiate if the given sample is silver by computing is density as shown below:

\(\rho =\frac{m}{V}=\frac{1.7kg}{0.164L}*\frac{1000g}{1kg} *\frac{1L}{1000cm^3}\\ \\\rho=10.37g/cm^3\)

In such a way, since we find a slight difference in the computed density, we can say it is not 100% silver, but it contains a high percentage (more than the 98% for sure) of silver.

Regards.

Explanation:

The chemical symbol of an element X is written as:\(^A_ZX^C\)

Where : Charge on ion = C

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The statement that is true of a Lewis base is that a Lewis base donates electron pairs (option A).

A Lewis base is any nucleophylic compound that can donate a pair of electrons and form a coordinate covalent bond.

On the other hand, a Lewis acid is any electrophylic compound that can accept a pair of electrons and form a coordinate covalent bond.

This means that a Lewis base can donate a pair of electrons to a Lewis acid to form a product containing a coordinate covalent bond. This product is also referred to as a Lewis adduct.

Therefore, option A is correct about Lewis base

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Answer:

ANSWER: 0.331 moles of tin

Explanation: in my working * means multiply and ^ means to the power of.

Ok BASICALLY if you have 6.02*10^23 of something you have yourself 1 mole of things. The atomic weight in the left hand corner of each element in the periodic table gives you the MOLAR MASS, which is the mass of 1 mole of that element. For example, Carbon has a molar mass of 12.011, this means it has 12.011 grams every 1 mole of carbon [C] (12.011 g/mol)

So now, how many moles are in 39.3 grams of tin? Very easy. You will find that in chemistry classes students are taught a basic formula to find the number of moles, which is:

---

Number of moles = Mass given / Molar mass

---

So in order to answer this question and find out the NUMBER OF MOLES, we need to find the MASS GIVEN - this is simply the mass given to you in the question, which is 39.3 grams of tin. We also need to know the MOLAR MASS, which is found in the left hand corner of the element. For tin [Sn] the molar mass is 118.710.

Sub both these into the formula to get:

Number of moles = 39.3 / 118.710

Number of moles = 0.331058883

We are not finished - remember to round of the lowest amount of significant figures found in the working of the question. In the working out, which was (39.3 / 118.71) the 39.3 has 3 significant figures and the 118.70 has 5 significant figures. ALWAYS TAKE THE LOWEST AMOUNT FOUND. The lowest amount is 3, so we must round this answer to 3 significant figures.

It will be: 0.331

Therefore, 0.331 moles of tin atoms are in a pure tin cup with a mass of 39.3.

Hope i helped and good luck!

Answer:

When science educators teach nurses, their primary aim should be to help them to develop understanding of their world of nursing. From a study of registered nurses' conceptions of the physical science underlying their clinical practice, we assert that nurses' understanding of the physical sciences is inadequate in terms of the competencies required of them as nurses.

Explanation: Hopes this helps You A lot :-D

When the reaction of  Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.

Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.

An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.

The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.

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Answer:

you need to multiply your number of half-lives by how many years are in one half-life. This gives you an age of 2 x 5730 = 11,460 years. Your fossil is of an organism (maybe human) that died 11,460 years ago

Explanation:

Answer:

Less than 7

Explanation:

during the titration of strong acid and weak base, the weak base is usually kept in the flask and strong acid is kept in the burette. So when we add strong acid slowly drop by drop, slowly the pH level of solution starts to decrease and at equivalence point the acid overpowers the base as a strong acid was taken over a weak base.

Answer:

b) warm

Explanation:

A warm weather front forms when a warm air mass pushes into a cooler air mass. Therefore, the answer is b) warm.

I'm sorry to bother you but can you please mark me BRAINLEIST if this ans is helpfull

Given what we know, we can confirm that in order to heat the contents in the most rapid fashion, the bottom of the beaker should be just barely touching the tip of the flame.

Therefore, due to the fact that the heat generated by the flame will rise, placing the beaker just above the tip of the flame will ensure that all of the heat generated by the flame will be deposited onto the contents of the beaker, heating it rapidly.

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Answer:

I can't see any picture?????

Answer:

antimony

Explanation:

Since the p sublevel is partially filled, it is in the p-block. There are five electrons in the outermost energy level, so it has 5 valence electrons. The element is antimony, a metalloid. The element is in Period 7.

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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Answer

All the options apply

Procedure

Generally speaking, metals have the following characteristics:

• high melting points.

• good conductors of electricity.

• good conductors of heat.

• high density.

• malleable.

• ductile

• bright luster.