Using Ohm's law, what is the current passing through a wire when the 10 V is placed across a wire with 50 Ohms? (3pts) If voltage is slowly increased, what will happen to current flow? What will the current be if that initial voltage (10 V) is used but now a longer the wire is 10x longer?

An unmagnetized piece of iron differs from a magnetized piece of iron primarily in their internal structure and magnetic properties. In an unmagnetized iron, the individual magnetic domains are randomly oriented, which means that their magnetic fields cancel each other out, resulting in no net magnetic field.

On the other hand, when the iron becomes magnetized, the magnetic domains align in the same direction, thereby creating a net magnetic field. This process is typically achieved through the application of an external magnetic field or by placing the iron piece in close proximity to a strong magnet. The alignment of the magnetic domains causes the magnetized iron to exhibit magnetic properties, such as attracting or repelling other magnetic materials and generating a magnetic field.

In terms of practical applications, magnetized iron can be used in a variety of devices, such as electromagnets, transformers, and magnetic storage media. Unmagnetized iron, while not possessing these magnetic properties, still retains its inherent characteristics, like strength and ductility, making it suitable for structural and engineering purposes.

In summary, the main difference between an unmagnetized and magnetized piece of iron lies in the orientation of their magnetic domains and the resulting presence or absence of a net magnetic field. This difference gives rise to distinct magnetic properties, which ultimately determine their specific applications in various industries.

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Explanation:

Why are high tides found simultaneously on opposite sides of Earth? The tidal bulges occur on both sides of Earth that are aligned with the tide-generating body. The ocean water experiencing high tide rotates around Earth on a 12-hour cycle.

        Tides are the steady rise and fall of the ocean's waters. The water steadily rises over the beach along shores before falling back again. It is high tide when the water has risen to its highest point and is mostly covering the shore. Low tide is when the water is at its lowest point. There may be tides in some rivers and lakes.

        In the ocean, tides cause various fascinating features. Additionally, traits unrelated to tidal activity are linked to them.

        When a river empties into the ocean or sea, it causes a tidal bore along the coast. A powerful tide that pushes upstream against the river's current is called a tidal bore. This really is a tidal wave. The Amazon River's massive tidal bore is known as the pororoca. The pororoca is a wave that can reach heights of up to 4 meters (13 feet) and travels at 15 kph (9 mph). The pororoca ascends the Amazon for 10 kilometers (6 miles).

      Also unrelated to actual tides are so-called "red tides." Algal blooms are sometimes known as crimson tides. Sea critters known as algae are very small. In the water, red tides and waves appear when billions of red algae develop.

      Rip tides are not a tidal feature, to sum up. Strong ocean currents known as rip tides flow over the water's surface. From the shore to the wide ocean, a rip tide flows. Surfers can benefit from rip tides since they can use them to avoid having to paddle out to sea. Swimmers can be swept out to sea during rip tides, which makes them extremely dangerous.

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Answer:

Answer in below and plz mark me as brainlist plz

Explanation:

The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum

The rate of change of momentum =tm(v−u) Rate of change of momentum = force applied. Force∝tm(v−u) Velocity is the rate of change of displacement and acceleration is the rate of change of velocity. Impulse is a change in momentum

Spring tides are extremely wide ranges of tidal highs and lows that occur during full moon or new moon phases when the gravitational forces of the Sun and Moon are at their strongest.

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To explain the tangent plane to the surface, `z = 53 − x² − 2y²` at the point `(3, 2, 6)`, let us first determine the partial derivatives of `z` with respect to `x` and `y`.

Partial derivative of `z` with respect to `x`, `∂z/∂x = -2x`Partial derivative of `z` with respect to `y`, `∂z/∂y = -4y`Now, let's find the gradient vector `grad z` at `(3, 2, 6)` and the value of `z` at `(3, 2)`.gradient vector `grad z = (-2x, -4y, 1)`gradient vector `grad z = (-6, -8, 1)` at `(3, 2, 6)`.Value of `z` at `(3, 2)` is given by `z = 53 - 3² - 2(2)² = 39`.

Therefore, the equation of the tangent plane to the surface `

z = 53 − x² − 2y²` at `(3, 2, 6)` is:

`z - 6 = -6(x - 3) - 8(y - 2)`

which can be written as:`6x + 8y + z = 50`Thus, the equation of the tangent plane to the surface `z = 53 − x² − 2y²` at the point `(3, 2, 6)` is `6x + 8y + z = 50`.

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Answer:

1. Solid- rock, shoe

2. Liquid- water, dish soap

3. Gas- oxygen, carbon dioxide

4. Plasma- lightning, stars

The correct option is B: The tension on the aluminum wire is approximately 65 N.

To find the tension on the aluminum wire, we can use the formula for the speed of transverse waves in a string:

v = √(T/μ)

where:

v = speed of transverse waves

T = tension in the wire

μ = linear mass density (mass per unit length) = density * area

First, let's calculate the area of the aluminum wire:

Given diameter = 4.6 mm

Radius = diameter/2 = 4.6 mm / 2 = 2.3 mm = 2.3 x \(10^(^-^3^)\) m

Area = π * \(r^2\)

      = π * (2.3 x 10⁽⁻³⁾)²

      = π * (5.29 x 10⁽⁻⁶⁾)

      ≈ 1.658 x 10⁽⁻⁵⁾ m²

Now, let's calculate the linear mass density (μ):

Density of aluminum = 2700 kg/m³

Linear mass density (μ) = density * area

                       = 2700 kg/m³ * 1.658 x 10⁽⁻⁵⁾ m²

                       ≈ 0.0447 kg/m

Now, we can rearrange the formula for the speed of transverse waves to solve for tension (T):

T = μ * v²

Given v = 38 m/s and μ = 0.0447 kg/m, we can calculate T:

T = 0.0447 kg/m * (38 m/s)²

 ≈ 63.9906 N

Rounding to the nearest whole number, the tension on the wire is approximately 64 N.

Therefore, the closest option from the given choices is: b) 65 N

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Answer: thermal energy

Answer:

Osteologists are trained to read and translate a bone's story.

Explanation:

This rare skill provides information that helps us better understand ancient cultures, solve mysteries, and learn about animals. Being an Osteologist means you have a variety of job opportunities.

Answer:

avoid verbal argument and walk away

Energy released ,

\( = 3.789 \times {10}^{ - 12} \) J

Answer:

C

Explanation:

When an x-ray photon with a wavelength of 0.0500 nm loses 4% of its energy in a collision with an electron that is initially at rest, the angle of deflection (from its initial path) is 0.0527 radians.

The energy of a photon is proportional to its frequency and inversely proportional to its wavelength (E = hν = hc/λ, where h is Planck's constant and c is the speed of light).

The momentum of a photon is p = h/λ. The photon's initial energy and momentum are E1 = hc/λ1 and p1 = h/λ1, respectively. After the collision, the photon's energy and momentum are E2 = hc/λ2 and p2 = h/λ2, respectively.

Conservation of energy states that E1 = E2 + Ee, where Ee is the kinetic energy of the electron. Conservation of momentum states that p1 = p2 + pe, where pe is the momentum of the electron. Since the electron is initially at rest, pe = 0.λ2 = λ1 + Δλ, where Δλ is the change in wavelength.

Δλ/λ1 = -Ee/E1

Rearranging, Ee/E1 = -Δλ/λ1

This equation states that the energy of the photon is inversely proportional to the fraction of its energy lost to the electron. When 4% of the energy of a 0.0500-nm x-ray photon is lost to an electron, the final wavelength is

λ2 = λ1 + Δλ = λ1 + (Ee/E1)λ1 = (1 - Ee/E1) λ1 = (1 - 0.04) λ1 = 0.960λ1

The final angle of the photon can be found using the formula for the scattering of a photon by a free electron.

θ = arctan(h/λ1)(1 - cosθ)/p1θ = arctan(h/λ1)(1 - cosθ)/(h/λ1)θ = arctan(1 - cosθ)λ1/p1

Plugging in the values,

θ = arctan(1 - cos 0.0527)0.0500 nm/h(2π/0.0500 nm)

θ = arctan(0.0000176) = 0.0527 rad

Thus, the photon is deflected at an angle of 0.0527 radians from its initial trajectory.

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The proof that can be used to show the mass energy equivalence os given below.

According to Einstein, mass energy equivalence is represented by

E=mC²

As Einstein's theory of relativity tells us, the equation that relates mass and energy is given by:E = mc²

in which E stands for energy, m refers to mass, while c denotes the speed of light in a vacuum.

In order to switch mass from kg units to electronvolts (eV), we can use this conversion factor:

1 kg = 5.610 × 10^35 eV/c^2

As IMEV = 1.6 × 10^-13J

E = 1.49 × 10^-10 / 1.6 × 10^-13

E = 931.25MeV

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A wet bar of soap (m=150 grams) starts at rest and slides without friction down a ramp 2.0 N meters long inclined at 7.3°. It take 1.792 second time to reach the bottom.

Friction is a force that resists the relative motion of two contact points. Friction happens when two bodies come into touch with each other.

Given that,

A wet bar soap mass = 150 gm

Length (l) = 2m

angle (θ) = 7.3°

As we know, F = m × g × Sinθ

Acceleration (a) = \(\frac{F}{m}\) = g × Sinθ

a = (9.8) × Sin 7.3°

a = 1.2452 m/s²

Next,

S = ut + 1/2 at²

2 = 0 + 1/2 × (1.2452) × (t)²  [ As, u = 0 m/s]

t² = 3.212335

t = 1.792 seconds

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The element belonging to principal quantum number 5 that is radioactive is e. Tc.

The principal quantum number, denoted by the symbol n, is used to determine the energy level of an electron in an atom. Each energy level is associated with a specific principal quantum number, with the first energy level corresponding to n=1, the second energy level corresponding to n=2, and so on.

The element Tc, or technetium, is the only element in the list that is radioactive. It belongs to the fifth energy level, which corresponds to principal quantum number 5. Technetium is an unstable element and does not occur naturally on Earth. It is produced artificially through the bombardment of other elements with neutrons. Therefore, the correct answer is e. Tc.

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Answer:

Option B.

Explanation:

The bending of a wave when it reaches the interface separating two media is called refraction of light.

In figure B, the wave initially in medium 1. Then it reaches the interface. After that it bends. It means the bending of light occurs in this case.

Hence, the correct option is (B).

Answer:

The range of the projectile can be calculated using the formula:

R = (v^2/g) * sin(2θ)

where v is the initial velocity, g is the gravitational acceleration, θ is the launch angle.

Substituting the given values:

R = (30^2/32.2) * sin(2*52)

R = 72.7 ft

Therefore, the answer is B. 72.7 ft.

38 degrees Celsius is equal to 100.4 degrees Fahrenheit.

To convert Celsius to Fahrenheit, you can use the following formula:

F = (9/5)C + 32

where F is the temperature in Fahrenheit and C is the temperature in Celsius.

So if we plug in 38 for C, we get:

F = (9/5) * 38 + 32 = 100.4

Therefore, 38 degrees Celsius is equal to 100.4 degrees Fahrenheit.

Temperature is a measure of the thermal energy of a substance or system. The most commonly used units of temperature are Celsius (°C), Fahrenheit (°F) and Kelvin (K).

To convert a temperature from Celsius to Fahrenheit, you can use the following formula:

°F = (9/5) x °C + 32

To convert a temperature from Fahrenheit to Celsius, you can use the following formula:

°C = (5/9) x (°F - 32)

To convert from Celsius to Kelvin you can use the following formula:

K = °C + 273.15

To convert from Fahrenheit to Kelvin you can use the following formula:

K = (5/9) x (°F - 32) + 273.15

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Answer:

Explanation:

The Earth's Moon has considerably less mass than the Earth itself. Not only is the Moon smaller than the Earth, but it is only about 60 percent as dense as Earth. Thus, the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.

Answer:

The volume of an object is a measure of the amount of space occupied by that object

Explanation:

Answer: A student might use a graduated cylinder to measure volume of a chemical solution in milliliters

Explanation:

Volume is the quantity of three-dimensional space enclosed by a closed surface,an often quantified numerically using the SI derived unit, the cubic metre.

Answer:

3,033,276 J

Explanation:

The work can be calculated as

W = Fd

Where F is the force and d is the distance.

Replacing F by 29,738 N and d by 102 m, we get:

W = (29,738 N)(102 m)

W = 3,033,276 J

Then, it has done 3,033,276 J

When two surfaces touch, they exert a force that prevents the two surfaces from sliding past one another. Static friction is the name of this force.

The body's net force's strength and direction. All of the forces acting on a moving object are depicted in the free-bod diagram. Every force, in particular, is represented by an arrow, the direction of which corresponds to the force's direction and whose length corresponds to the force's magnitude. Therefore, the net force can be estimated from a free body diagram. In reality, one may calculate the net force acting in each of the two directions by examining the forces acting along the horizontal and vertical axes independently. These two forces then stand in for the constituent parts of the final force (net force) acting on the item.

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The minimum coefficient of static friction needed for the ball to roll without slipping is `tan β.

Given that the maximum friction force is given by `f = μN. The normal force that the ramp exerts on the ball is given by `N = mg cos β. The force of gravity acting on the ball is given by `mg`. The angle of inclination of the ramp is given by β. To derive the expression for the minimum coefficient of static friction needed for the ball to roll without slipping, we will take the following steps:

Let the minimum coefficient of static friction be represented by μsThe force of gravity acting on the ball is given by `mg`The normal force that the ramp exerts on the ball is given by `N = mg cos β.

Therefore, we have the maximum friction force as;

`f = μsN``f

= μs mg cos β`

Since the ball is to roll without slipping, the frictional force will provide torque. The torque due to friction is given by `τ = fR`. The torque due to the force of gravity is given by `τ = mgR sin β`.

Since the ball is to roll without slipping, we have the condition that the friction force should be equal to the force of gravity multiplied by the sine of the angle of inclination of the ramp.

Therefore, we have:`f = mg sin β``μs mg cos β

= mg sin β``μs

= sin β / cos β``μs

= tan β`

Therefore, the minimum coefficient of static friction needed for the ball to roll without slipping is `tan β`.The answer is expressed in terms of β.

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Answer:

Parallel Circuits

Explanation:

Loads can be operated on their own. If you had a series circuit, adding another light would dim the rest!

The initial maxima speed for light with a 500 nm wavelength is 5 mm/s.

Hence, given the distance to a screen, the breadth of the slit, and the wavelength of the light, we can apply the equation y = L l / a to pinpoint the location of the initial diffraction minimum with in single slit diffraction pattern.

Its Type III dispersion is intended for applications such general carparks and streets where a larger illumination area is required. Type III lighting must be placed to one side of the area in order for it to illuminate the entire area. As a result, there's a filling light flow.

Distance between slits and screenD=3m

Distance between slits d=10 mm

Speed v=4 m/s

v β =5×10 −3 m/s

= 5 mm/s

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The object has the greatest total work done on it by all the forces during its motion, when it is in Free Fall. The correct answer A.

The object that has the biggest total work done on it by all forces during its motion is the one that falls straight down, as it experiences the force of gravity over its entire path.

The object that slides down the frictionless inclined plane experiences the force of gravity over only part of its path, while the object that swings on the end of a string only experiences the force of gravity for a very short period of time.

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