Answer:
The blood circulatory system (cardiovascular system) delivers nutrients and oxygen to all cells in the body. It consists of the heart and the blood vessels running through the entire body. The arteries carry blood away from the heart; the veins carry it back to the heart. The system of blood vessels resembles a tree: The “trunk” – the main artery (aorta) – branches into large arteries, which lead to smaller and smaller vessels. The smallest arteries end in a network of tiny vessels known as the capillary network. There isn't only one blood circulatory system in the human body, but two, which are connected: The systemic circulation provides organs, tissues and cells with blood so that they get oxygen and other vital substances. The pulmonary circulation is where the fresh oxygen we breathe in enters the blood. At the same time, carbon dioxide is released from the blood. Blood circulation starts when the heart relaxes between two heartbeats: The blood flows from both atria (the upper two chambers of the heart) into the ventricles (the lower two chambers), which then expand. The following phase is called the ejection period, which is when both ventricles pump the blood into the large arteries. In the systemic circulation, the left ventricle pumps oxygen-rich blood into the main artery (aorta). The blood travels from the main artery to larger and smaller arteries and into the capillary network. There the blood drops off oxygen, nutrients and other important substances and picks up carbon dioxide and waste products. The blood, which is now low in oxygen, is collected in veins and travels to the right atrium and into the right ventricle. This is where pulmonary circulation begins: The right ventricle pumps low-oxygen blood into the pulmonary artery, which branches off into smaller and smaller arteries and capillaries. The capillaries form a fine network around the pulmonary vesicles (grape-like air sacs at the end of the airways). This is where carbon dioxide is released from the blood into the air inside the pulmonary vesicles, and fresh oxygen enters the bloodstream. When we breathe out, carbon dioxide leaves our body. Oxygen-rich blood travels through the pulmonary veins and the left atrium into the left ventricle. The next heartbeat starts a new cycle of systemic circulation.
Explanation:
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what is the difference between a chemical bond formed in a molecule of cl2 and a chemical bond formed in a molecule of hcl?
The difference between a chemical bond formed in a molecule of Cl2 and a chemical bond formed in a molecule of HCl is that the bond formed in Cl2 is:
A covalent bond, which involves the sharing of electrons between the two chlorine atoms, while the bond formed in HCl is an ionic bond, which involves the transfer of electrons from the hydrogen atom to the chlorine atom.In a covalent bond, the electrons are shared equally between the two atoms, while in an ionic bond, the electrons are transferred completely from one atom to the other.
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The half-life of a radioactive isotope is 1,000 million years. Scientists testing a rock sample discover that the ratio of parent and daughter isotopes indicates that the rock is 3,000 million years old. What percentage of parent isotopes remains in the sample
Approximately 12.5% of the parent isotopes remain in the rock sample.
The half-life of a radioactive isotope is the time it takes for half of the parent isotopes to decay into daughter isotopes. In this case, the half-life of the isotope is 1,000 million years.
To determine the age of the rock sample, scientists analyze the ratio of parent and daughter isotopes present. If the rock is 3,000 million years old, it means that three half-lives have occurred since its formation (3,000 million years / 1,000 million years per half-life = 3 half-lives).
With each half-life, half of the remaining parent isotopes decay, while the other half remains. Therefore, after one half-life, 50% of the parent isotopes remain. After two half-lives, 25% (50% of 50%) remain. And after three half-lives, 12.5% (50% of 25%) of the parent isotopes remain.
Hence, approximately 12.5% of the parent isotopes remain in the rock sample.
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18 points Which identifies an oxidation-reduction reaction?
a double replacement reaction
a neutralization reaction
a reaction in which oxidation numbers change
a reaction in which no electrons are transferred
Answer:
a reaction in which oxidation numbers change
Explanation:
here you go happy to help
A sample of vegetable oil with density 913 kg/m” is found to have a mass of 35.1 g. Find the volume of this sample.
volume:
D = m/v
D = 921 kg/m3
m = 44.1 g = 0.0441 kg
Solve for v by rearranging the equation.D = m/v
vD = m
v = m/D = 0.0441 kg / 921 kg/m3 = 4.79 x 10-5 m3
The process of water migrating from areas of low electrolyte concentration to area of high electrolyte concentration is called ———————. ——————— is the medicine term for the swelling of the brain
Answer:1-Diffusion
2-Cerebral edema
Explanation:
The process of water migrating from areas of low electrolyte concentration to areas of high electrolyte concentration is called diffusion.
Cerebral edema is the medical term for the swelling of the brain.
What is diffusion?Diffusion is a process where the substance or ions of from a low concentration to a high concentration. It occurs against the concentration gradient, so it needs energy.
Cerebral edema is a condition where fluid gets filled in the brain and the brain swells and make pressure on the skull called intracranial pressure.
Thus, Diffusion is the mechanism by which water moves from regions with low electrolyte concentrations to regions with high electrolyte concentrations.
The medical term for brain swelling is cerebral edema.
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QUESTION 1 Before there was evidence from rocks and fossils, many scientists theorized that the continents were once joined together. Using only maps, these scientists observed that -
Using only maps, scientists observed several lines of evidence that led them to theorize that the continents were once joined together before there was evidence from rocks and fossils.
One key observation was the remarkable fit between the coastlines of different continents, such as South America and Africa. They noticed that the shapes of these continents seemed to match like puzzle pieces, suggesting they were once connected.
Additionally, scientists observed similar geological features across continents, such as mountain ranges and rock formations, that extended across apparent continental boundaries. They also noticed the distribution of certain plant and animal species that were found on different continents but had no means of natural dispersal.
These observations, made solely through maps, led scientists to propose the concept of continental drift, which was later supported by geological and paleontological evidence found in rocks and fossils.
Therefore, using only maps, scientists observed several lines of evidence that led them to theorize that the continents were once joined together before there was evidence from rocks and fossils.
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a 1) How would you make 1 liter of a 10% NaCl solution from a solid stock? Provide details of what kind of containers you would use.
To make 1 liter of a 10% NaCl solution from a solid stock, you will require the following materials and containers.MaterialsSolid NaClDistilled water1-Liter volumetric flask250-mL volumetric flask 2-beakersProcedureTo prepare 1 liter of a 10% NaCl solution, the following procedure should be followed:Measure out 100g of NaCl using a balance.
Measure the weight of an empty 250-mL volumetric flask.Add the NaCl to a 250-mL beaker and add a small amount of distilled water to it to dissolve the NaCl.Carefully pour the dissolved NaCl solution into the 250-mL volumetric flask. Add distilled water to the mark on the flask to make up the volume. Stopper the flask and invert it several times to mix the solution.Measure the weight of the 1-Liter volumetric flask.Add the 250-mL volumetric flask solution to a 1-Liter volumetric flask.Add distilled water to the mark on the flask to make up the volume.
Stopper the flask and invert it several times to mix the solution.The final volume of the solution will be 1 liter of a 10% NaCl solution.PrecautionsEnsure the NaCl has completely dissolved before adding more water to avoid making a less concentrated solution.Measure the weight of the volumetric flask before and after adding the solution to calculate the volume of solution that was added.Use distilled water to prepare the solution.
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to which of the 20 amino acids that make up proteins does citrulline have structural similarity?
Citrulline has structural similarity to arginine among the 20 amino acids that make up proteins.
Citrulline, an amino acid, has structural similarity to arginine among the 20 amino acids that make up proteins. Citrulline and arginine share similar chemical structures and contain a guanidino group. Citrulline is a non-standard amino acid, meaning it is not directly encoded by the genetic code and is typically produced in the urea cycle in the body. Structurally, citrulline differs from arginine by the absence of a terminal guanidino group, as it has been deaminated.
However, citrulline can be converted back to arginine through enzymatic reactions. Functionally, citrulline plays a role in the urea cycle and is involved in the synthesis of nitric oxide. Arginine, on the other hand, is essential for protein synthesis and is a precursor for the production of various molecules, including nitric oxide, creatine, and polyamines. Despite their structural similarity, citrulline and arginine have distinct roles and functions in biological systems.
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When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq) , 3.14 kJ of heat are produced. Determine the enthalpy change per two moles of zinc reacting for the reaction:
Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g)
Select one:
a.
-98 kJ
b.
-103 kJ
c.
-222 kJ
d.
-306 kJ
When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq) , 3.14 kJ of heat are produced.the answer is not one of the choices given.
To solve for the enthalpy change per two moles of zinc reacting, we need to first calculate the moles of zinc reacted and the amount of heat produced.
The moles of zinc reacted can be found using its molar mass:
1.34 g Zn ÷ 65.38 g/mol Zn = 0.0205 mol Zn
The amount of heat produced can be found using q = mCΔT, where q is the heat produced, m is the mass of the solution (which we assume to be 60.0 g since 1 mL of water is approximately 1 g), C is the specific heat capacity of the solution (which we assume to be 4.18 J/g°C, the value for water), and ΔT is the change in temperature (which we assume to be negligible since the reaction is done at constant pressure).
q = (60.0 g)(4.18 J/g°C)(0°C) = 0 J
However, we are given that 3.14 kJ of heat are produced, which is equivalent to 3140 J. Therefore, we need to adjust the moles of zinc reacted to account for this amount of heat:
3140 J ÷ (-2 mol HCl)(-46.1 J/mol°C) = 0.0345 mol Zn
Now we can calculate the enthalpy change per two moles of zinc reacted:
ΔH = q ÷ n = (3140 J) ÷ (0.0345 mol Zn ÷ 2) = -181609 J/mol
Converting to kJ/mol and rounding to the nearest whole number, we get:
ΔH = -182 kJ/mol
Therefore, the answer is not one of the choices given.
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(08.05 M)
A solution has a [H30) of 1 x 10-3 M. What is the [OH-] of the solution?
11M
14 M
1x 10-14 M
1* 10-11M
The [OH⁻] of the solution : 1 x 10⁻¹¹ M
Further explanationGiven
[H30) : 1 x 10-3 M.
Required
the [OH]
Solution
The water equilibrium constant is a product of the concentrations of [H3O +] and [OH-]
Kw = [H₃O⁺] [OH⁻]
Input the value of [H₃O⁺]
1 x 10⁻¹⁴ = 1 x 10⁻³ x [OH⁻]
[OH⁻] = 1 x 10⁻¹⁴ : 1 x 10⁻³
[OH⁻] = 1 x 10⁻¹¹ M
A thermometer is taken from a room where the temperature is 24
∘
C to the outdoors, where the temperature is −11
∘
C. After one minute the thermometer reads 7
∘
C. (a) What will the reading on the thermometer be after 4 more minutes? (b) When will the thermometer read −10
∘
C ? minutes after it was taken to the outdoors.
The thermometer will read -10°C after about 2.43 minutes.
(a) After four more minutes, the thermometer will read -1°C.
This is because the temperature difference between the room and outdoors is (24 - (-11)) = 35°C.
The thermometer then rises 7°C in one minute, so the thermometer is heated at 7°C/minute, i.e. 35°C in five minutes.
So the temperature of the thermometer after 4 more minutes is 7°C + 7°C + 7°C + 7°C = 28°C, 28°C - 35°C = -7°C, -7°C - 3°C = -10°C.
Thus the reading on the thermometer will be -1°C after four more minutes.
(b) To find out when the thermometer will read -10°C, use the formula:
time = (temperature difference ÷ heating rate) + time to start
= (-10°C - 7°C) ÷ 7°C/minute + 1 minute
= -17°C ÷ 7°C/minute + 1 minute≈ -2.43 minutes
Thus, the thermometer will read -10°C after about 2.43 minutes.
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Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produced 36.86 g CO, and 10.06 g H,. The molar mass of estriol is 288.38 g/mol. Part A Find the molecular formula of the unknown compound Express your answer as a chemical formula AE" Om ?
Combustion analysis of a 13.42 g sample of an unknown organic compound (which contains only carbon, hydrogen, and oxygen) produced 36.86 g CO2, and 10.06 g H2O. The molar mass of estriol is 288.38 g/mol. The molecular formula of the compound is C9H10O4.
To find the molecular formula of the unknown compound:
1. To find the molecular formula, we should calculate the compound's empirical formula first and then divide the molar mass by the empirical formula. The combustion reaction of a compound containing carbon, hydrogen, and oxygen produces CO2 and H2O in proportion to the moles of carbon and hydrogen in the compound:
CxHyOz + (x + y/4 - z/2) O2 -> x CO2 + y/2 H2O
The ratio of CO2 produced to the moles of C in the original sample can be used to calculate the compound's empirical formula. Mass of CO2 produced = 36.86 g, 44.01 g/mol (molar mass of CO2). Therefore, the number of moles of CO2 produced = 36.86 g/44.01 g/mol = 0.837 moles.
From the balanced combustion equation, the mole ratio of CO2 to carbon is 1:1. So the number of moles of carbon in the compound is 0.837 moles. Number of grams of carbon in the compound = 0.837 moles x 12.01 g/mol = 10.05 g. Number of grams of hydrogen in the compound = 10.06 g.
Therefore, the number of moles of hydrogen in the compound = 10.06 g/2.02 g/mol = 4.98 moles.
From the balanced combustion equation, the mole ratio of H2O to hydrogen is 1:2. So, the number of moles of hydrogen in the compound is 2 x 4.98 moles = 9.96 moles.
Number of grams of oxygen in the compound = mass of sample - mass of carbon - mass of hydrogen= 13.42 g - 10.05 g - 10.06 g = 2.31 g.
Number of moles of oxygen in the compound = 2.31 g/16.00 g/mol = 0.144 moles.
The empirical formula of the unknown compound is CH2O. The empirical formula mass is 12.01 + 2 x 1.01 + 16.00 = 30.03 g/mol.
Dividing the molar mass of the compound by the empirical formula mass gives the factor by which we need to multiply the empirical formula to get the molecular formula:
Molecular formula = Empirical formula × n, where n = molecular weight/empirical weight
Molecular formula = CH2O × (288.38 g/mol/30.03 g/mol)Molecular formula = C9H10O4
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Global seawater chemical composition changed over geological time. "Aragonite-calcite sea" was supported by analyzing Mg/Ca ratio in A. fossil materials B. ancient salt crystals C. fluid inclusions in ancient salt crystals D. modern semwater
The correct answer is A. fossil materials. The Mg/Ca ratio in fossil materials, such as shells or skeletons of marine organisms, can provide insights into the chemical composition of seawater in the past.
By analyzing the Mg/Ca ratio in these fossils, scientists can infer whether the seawater at the time favored the precipitation of aragonite or calcite minerals.
Aragonite and calcite are two different forms of calcium carbonate minerals, and their formation is influenced by the chemical composition of seawater. In an aragonite-calcite sea, the relative abundance of aragonite and calcite minerals in the fossil record can indicate the prevailing chemical conditions in the ancient oceans.
On the other hand, ancient salt crystals (option B) and fluid inclusions in ancient salt crystals (option C) are not directly related to the Mg/Ca ratio or the aragonite-calcite sea concept. Modern seawater (option D) may provide some insights into the current chemical composition but does not directly inform us about past geological changes in seawater chemistry.
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write the correct balanced equation of Lead 2 Oxide and hydrogen
The balanced equation of the reaction between hydrogen and lead (ii) oxide is given is:
PbO + H₂ ----> Pb + H₂O
Balanced chemical equationA chemical equation is balanced if the number of atoms of each element on the reactants side of the equation is equal to the number of atoms of each element on the product side.
A balanced chemical equation follows the law of conservation of mass that matter is neither created nor destroyedReaction between hydrogen and lead (ii) oxideHydrogen reacts with lead(ii) oxide to produce lead and water
The balanced equation of the reaction between hydrogen and lead (ii) oxide is given is:
PbO + H₂ ----> Pb + H₂O
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The solubility of water is 0.13g/L at 90kPa. What is the solubility when the pressure of the gas is increased to 150 kPa? Assume the temperature remains constant.
Answer:
Explanation:
The solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. This relationship is known as Henry's Law. According to Henry's Law, the solubility of the gas in the liquid is given by:
C = k * P
where C is the concentration of the gas in the liquid (in g/L), P is the partial pressure of the gas (in kPa), and k is a constant that depends on the gas and the temperature.
To find the solubility of water at a pressure of 150 kPa, we can use the following equation:
C2 = (P2/P1) * C1
where C1 is the solubility of water at a pressure of 90 kPa (0.13 g/L), P1 is the initial pressure (90 kPa), P2 is the final pressure (150 kPa), and C2 is the solubility of water at a pressure of 150 kPa (which we want to find).
Substituting the values into the equation, we get:
C2 = (150/90) * 0.13 g/L
C2 = 0.217 g/L
Therefore, the solubility of water is 0.217 g/L at a pressure of 150 kPa, assuming the temperature remains constant.
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2. (10 Points) If something has a high heat capacity will it take a little energy or a
lot of energy to change its temperature? Defend your answer.
I uploaded the answer to a file hosting. Here's link:
tinyurl.com/wtjfavyw
Why is water able to easily dissolve ionic compounds?
A. The bonds between water molecules are easily broken by the strong ions of ionic compounds.
B. The opposite charges of ionic compounds repel each others, so water molecules can separate the ions.
C. The electron transfer in ionic compounds results in ions that are attracted to water's poles.
D. The poles of water molecules share electrons with the ions in ionic compounds.
why are we always at the center of a rainbow? and why can we see a rainbow?
Answer:
the sun is directly behind your head
Explanation:
The reason why we can see a rainbow is caused by sunlight and atmospheric conditions
Help help please help help!!
Answer:
I believe the answer is numbers
if you add 0.5312 g of benzoic acid to a 100 ml volumetric flask and then add enough water to bring the total volume to 100.00 ml, how many ml of 0.2514 m naoh solution will be required to completely neutralize the benzoic acid (pka
In the 100 ml volumetric flask, 17.3 mL of a 0.2514 M NaOH solution will be needed to fully neutralise the benzoic acid.
The first step in calculating the volume of NaOH required to neutralize the benzoic acid is to determine how many moles of benzoic acid are present in the 100 ml volumetric flask.
We can do this by dividing the mass of benzoic acid by its molar mass:
0.5312 g / 122.12 g/mol = 0.004346 mol benzoic acid
Since benzoic acid is a weak acid, we can use the Henderson-Hasselbalch equation to calculate the pH of its solution:
pH = pKa + log([A-⁻]/[HA])
The pKa of benzoic acid is 4.20. At the equivalence point of the titration, [A-] = [HA], so we can simplify the equation to:
pH = pKa + log(1) = pKa = 4.20
This means that the benzoic acid will be fully ionized at pH 4.20, and the volume of NaOH required to neutralize it can be calculated by using the balanced equation:
C₆H₅COOH + NaOH → NaC₆H₅COO + H₂O
The stoichiometric ratio of benzoic acid to NaOH is 1:1, so the moles of NaOH required to neutralize the benzoic acid is also 0.004346 mol.
To calculate the volume of 0.2514 M NaOH required to provide this number of moles, we can use the following equation:
moles = concentration x volume
0.004346 mol = 0.2514 mol/L x volume
volume = 0.0173 L = 17.3 mL
Therefore, 17.3 mL of 0.2514 M NaOH solution will be required to completely neutralize the benzoic acid in the 100 ml volumetric flask.
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The state of matter which has no definite shape or volume is calledAsolidBliquidCgasDwater
Answer: C. Gas
Explanation:
A gas is a state of matter that has no definite shape or volume, and its particles are usually far apart and moving quickly in random directions.
carbon is able to form a wide variety of stable chain, ring, and branched compounds. which factors contribute to this behavior? select all that apply.
Due to catenation property of carbon
What is catenation property ?
Carbon has the capacity to join together to form lengthy chains. In actuality, among all the other atoms present in nature, carbon atoms are distinct due to catenation. Tetravalent connections between carbon atoms are what cause carbon chains to develop today.
They create tetravalent bonds, in which one carbon atom joins forces with four additional carbon atoms. They have a repeating structure because this structure can be repeated indefinitely without affecting the stability of the bonds or the compounds created.
In actuality, chains can create branches, which in turn, create sub-branches, which create rings, and so on. Now, there are two categories of carbon compounds, the first of which is open-chain or aliphatic molecules.
C forms covalent bonds almost exclusively.
C-C bonds are relatively short and therefore strong.
C-C multiple bonds form readily and are stable.
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What happens to particles in a sample of liquid when the liquid is heated and cooled?
How much percent of the earth is water?
Answer:70%
Explanation:
Answer:
71%
Explanation:
71% of the earth is covered by water and oceans hold about 96 percent of the water
What volume of 1.0 M sodium phosphate, to the nearest tenth of a liter, must be used to make 4.0 L of 0.80 M sodium phosphate?
Pilihan jawaban
0.2 L
1.2 L
2.2 L
3.2 L
Sodium phosphate is a generic term for a variety of salts of sodium (Na +) and phosphate\((PO _{4 }^{3-} .\))
To make 4.0 L of 0.80 M sodium phosphate, we need to find the volume of 1.0 M sodium phosphate required.
If one gram of solute is able to be dissolved in one liter of solution, then the molarity of the solution is equal to one mole. In a solution, the most crucial thing that happens is that the solute and the solvent mix together to produce the solution.
As a result, the volume of the whole solution is measured out.
The coherent unit for molarity or molar concentration, as defined by the International System of Units (SI), is
We can use the following formula to find the volume of the solution:
M1V1 = M2V2,
where M1 and V1 are the initial molarity and volume of the solution, respectively, and M2 and V2 are the final molarity and volume of the solution, respectively.
Using the above formula:
M1V1 = M2V24.0 L × 0.80 M = M2V2V2 = (4.0 L × 0.80 M) / 1.0 MV2 = 3.2 L
Therefore, the volume of 1.0 M sodium phosphate, to the nearest tenth of a liter, that must be used to make 4.0 L of 0.80 M sodium phosphate is 3.2 L.
The correct option is option D.
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an equimolar mixture of n2(g)n2(g) and ar(g)ar(g) is kept inside a rigid container at a constant temperature of 300 kk. the initial partial pressure of arar in the mixture is 0.75atm0.75atm. an additional amount of arar was added to the container, enough to double the number of moles of arar gas in the mixture. assuming ideal behavior, what is the final pressure of the gas mixture after the addition of the arar gas?
The new pressure of the gas is 2.25 atm.
We know that the pressure of a given mass of gas is directly proportional to the number of moles of the gas.
Mathematically;
P ∝ n
For two masses of an ideal gas;
P1/n1 = P2/n2
Where
P1 = initial pressure
P2 = Final pressure
n1 = number of moles of gas initially present
n2 = Final moles of gas present
Let the number of moles of the Ar gas be n
Given that;
P1 = 0.75atm
n1 = n
P2 = ?
n2 = 2n
Substituting into the given equation and making P2 the subject of the formula;
P2 = P1n2/n1
P2 = 0.75atm ×2n/n
P2 = 1.5 atm
Since the original mixture was equimolar, the new total pressure of the gas is partial pressure of N2 + new partial pressure of Ar = 0.75 atm + 1.5 atm = 2.25 atm
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Separate the molecule you just formed back into two individual amino acid molecules (reverse the reaction). Add any atoms necessary. 14. What type of chemical reaction did you just simulate? 15. What atoms did you use to make this happen? What molecule do those atoms combine to create? Triglyceride Molecule: 16. Is this molecule polar? 17. Is it soluble in water? 18. Is there a significant amount of energy stored in this molecule? 19. How does the energy stored in a triglyceride molecule compare with the energy stored in an amino acid or glucose molecule? Explain your answer.
The type of chemical reaction that typically forms peptide bonds between amino acids to create a protein is a condensation or dehydration synthesis reaction.
The atoms involved in the formation of a peptide bond are carbon, hydrogen, oxygen, and nitrogen. These atoms combine to create a peptide bond, which links the carboxyl group (-COOH) of one amino acid with the amino group (-NH₂) of another amino acid.
A triglyceride molecule is generally non-polar because it consists of three fatty acid chains attached to a glycerol molecule, and both fatty acids and glycerol are hydrophobic (non-polar) in nature.
Triglycerides are insoluble in water due to their non-polar nature. They do not form hydrogen bonds with water molecules, making them hydrophobic.
Triglycerides store a significant amount of energy. They are the primary storage form of energy in adipose tissue, providing high-energy density due to the long carbon chains in fatty acids.
The energy stored in a triglyceride molecule is higher compared to an amino acid or glucose molecule. Triglycerides have more carbon-hydrogen bonds, which store a higher amount of energy per unit mass than the shorter carbon chains in amino acids or glucose molecules. This is why triglycerides are an efficient energy storage molecule in organisms, as they can be broken down through hydrolysis to release energy when needed.
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Need help please!
The image below shows particles flowing by each other.
A square is shown with the title State of Matter. It has three groups of three circles each. Each group is touching the other and are all close to one another. Double arcs are shown around some circles
Which state of matter is most likely represented in the image? (5 points)
Gas
Solid
Liquid
Plasma
Answer:
The answer would be solid
Explanation:
The molecular mass of nicotine is 162.1 grams. Nicotine contains 74.0% carbon, 8.7% hydrogen, and 17.3% nitrogen. Determine it's molecular formula.
A). C10H14N2
B). C6H8N4
C). C5H7N
D). C3H6N
I give Brainliest! Please no links
Answer:D). C3H6N
Explanation:applesause
When an aqueous solution of NaBr is electrolyzed, what forms at the electrodes?
The answer is Cathode: H2; anode: Br2
Would anyone mind explaining this to me?
During the electrolysis of an aqueous solution of NaBr, water is also present in the solution along with NaBr.
Therefore, the products formed at the electrodes depend on the reduction and oxidation potentials of both the ions present in the solution as well as water.At the cathode (negative electrode), water can be reduced to hydrogen gas (H2) or sodium ions (Na+) can be reduced to sodium metal, depending on their reduction potentials. In this case, the reduction potential of water (-0.83 V) is less than that of Na+ ions (-2.71 V), so water is reduced to hydrogen gas 2H2O + 2e- → H2 + 2OH-At the anode (positive electrode), the Br- ions present in the solution can be oxidized to form Br2 molecules or water can be oxidized to form oxygen gas (O2) and hydrogen ions (H+), depending on their oxidation potentials. In this case, the oxidation potential of Br- (-1.07 V) is greater than that of water (-1.23 V), so Br- ions are oxidized to form Br2 molecules:
2Br- → Br2 + 2e-Therefore, the final products of the electrolysis of NaBr solution are hydrogen gas (H2) at the cathode and bromine gas (Br2) at the anode.
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