a sequence that has a subsequence that is bounded but contains no subsequence that converges.

Answer:

Less than

Step-by-step explanation:

To see how 3/4 compares to 3/8, give em the same denominator. The simplest way is to multiply 3/4 by 2. Multiply each the numerator and denominator by 2. That gives you 6/8. She needs 6/8 but only has 3/8, so less than a pizza.

Answer:

The area of a shape that has a length of 5 and a width of 16 is 80.

Step-by-step explanation:

Just multiply 5 by 16.

Answer:

The answer is -107

Step-by-step explanation:

Answer:

The boat traveled at 10 miles per hour for 2 hours and at 30 miles per hour for 4 hours.

Step-by-step explanation:

Let x be the time (in hours) that the boat traveled at 10 miles per hour, and let y be the time (in hours) that it traveled at 30 miles per hour.

We know that:

x + y = 6 (the total time the boat traveled)

We also know that the boat traveled a total distance of 140 miles, which can be expressed as:

10x + 30y = 140

We can use the first equation to solve for one of the variables in terms of the other:

y = 6 - x

Substituting this expression for y into the second equation, we get:

10x + 30(6 - x) = 140

Simplifying and solving for x, we get:

10x + 180 - 30x = 140

-20x = -40

x = 2

Therefore, the boat traveled at 10 miles per hour for 2 hours and at 30 miles per hour for 4 hours.

When Solver is unable to find a solution to a problem, it can be an indication of various issues. One possible cause is that the problem may be too complex for Solver to solve within the given constraints.

In such cases, it may be necessary to adjust the problem parameters or seek alternative solutions. Another possible cause of Solver's inability to find a solution could be due to incorrect input data. This can lead to inconsistent or contradictory constraints, making it impossible for Solver to arrive at a feasible solution. Lastly, Solver may fail to find a solution due to numerical errors or limitations in the algorithm used. These issues can arise when dealing with large datasets or highly non-linear problems. In any case, when Solver is unable to find a solution, it is important to carefully examine the problem and its parameters, and consider alternative approaches. Sometimes, a small adjustment to the input data or constraints can make all the difference in arriving at a successful solution.  In such cases, Solver may struggle to find an accurate or optimal solution. Ill-conditioned problems typically involve numerical instability or poor scaling, while infeasible problems occur when the given constraints cannot be satisfied simultaneously. It is crucial to analyze and refine the problem to enable Solver to find a viable solution effectively. When there is a problem with Solver being unable to find a solution, it often indicates the presence of a(n) ill-conditioned or infeasible problem.

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Answer:

The points where E' and F' are located after dilation and how the lines g and g' are related are;

The locations E' and F' are E'(-8, 0) and F'(0, 4), and lines g and g' are parallel

Please see attached plot of lines g and g' created with MS Excel

Step-by-step explanation:

When an object is dilated by a scale factor, the length of the sides of the image formed is given as follows;

The length of the image = The length of the figure × The scale factor

The given parameters are;

The center of dilation = (0, 0) Dilated from the origin

The coordinates of the endpoint of the line 'g' = E(-4, 0), F(0, 2)

Therefore, we have;

The 'x', and 'y' coordinates of the point E' on the image from the center of dilation  (0, 0) = (-4 × 2, 0 × 2) = (-8, 0)

The 'x', and 'y' coordinates of the point F' on the image from the center of dilation  (0, 0) = (0 × 2, 2 × 2) = (0, 4)

Therefore, the coordinates of the point E' and F' on line g' = E'(-8, 0) and F'(0, 4)

Given that the proportion of the distances of E and E' to center of dilation (to the origin) and F and F' center of dilation are equal by the triangle proportionality theorem, EF is parallel to E'F' and the lines g and g' are said to be parallel

Therefore;

The coordinate of point E' = (-8, 0) and The coordinate of point F' = (0, 4)

Ling g is parallel to line g'

Answer:

The locations of E' and F' are E' (−8, 0) and F' (0, 4), and lines g and g' are parallel.

Step-by-step explanation:

Now give the other guy the brainliest. xoxo

Answer:

iam sorry

i don't know the answer

The value of the money supply (m) is 2818

The given parameters are:

velocity (v) equals 4,

the price level (p) equals 98,

real gdp (q) equals 115

The equation is given as:

mv= pq

So, we have

m * 4 = 98 * 115

Evaluate the product

m * 4 = 11270

Divide by 4

m = 2818

Hence, the value of the money supply (m) is 2818

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Answer:

C = 7.72 ~ 7.7

Step-by-step explanation:

So when you solve this equetion you must 1st find x then c

we can find x by using cos(60)

cos(60) = x/14

x = cos(60) × 14

x = 1/2 ×14

x = 7

so after we find x we are going to solve c by using cos (25)

cos (25) = X/C = 7/c

cos(25) × C = 7

C = 7/cos (25)

C = 7.72 ~ 7.7

so the solution is 7.7

Answer: 166,400,000 1000 bills

$166,400,000,000

Answer:

166,400,000

sry for answering late!

The Figure that can be transformed into Figure K by a reflection across the x-axis, and a dilation of 1/2 is given as follows:

A. Figure J.

The first transformation is a reflection across the x-axis, which has the rule defined as follows:

(x,y) -> (x, -y).

Meaning that the orientation of the rotated figure is rotated upside down compared to the original figure.

Then the second transformation is a dilation by a scale factor of 1/2, meaning that each vertex of the figure is multiplied by 1/2, and thus the image size is half the original image.

Figure K is in the third quadrant, hence:

Hence Figure J is the original figure, meaning that option A is correct.

The options are given by the image shown at the end of the answer.

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Answer:

158km²

Step-by-step explanation:

2· (3·5 + 8·5 + 8·3)

=

158

The initial value problem y' = y + cos(y), y(0) = 1 has a unique solution on any interval of the form [-M, M], where M > 0.

To show that the initial value problem has a unique solution on any interval of the form [-M, M], where M > 0, we can apply the existence and uniqueness theorem for first-order ordinary differential equations. The theorem guarantees the existence and uniqueness of a solution if certain conditions are met.

First, we check if the function f(y) = y + cos(y) satisfies the Lipschitz condition on the interval [-M, M]. The Lipschitz condition states that there exists a constant L such that |f(y₁) - f(y₂)| ≤ L|y₁ - y₂| for all y₁, y₂ in the interval.

Taking the derivative of f(y) with respect to y, we have f'(y) = 1 - sin(y), which is bounded on the interval [-M, M] since sin(y) is bounded between -1 and 1. Therefore, we can choose L = 2 as a Lipschitz constant.

Since f(y) satisfies the Lipschitz condition on the interval [-M, M], the existence and uniqueness theorem guarantees the existence of a unique solution to the initial value problem on that interval.

Hence, we can conclude that the initial value problem y' = y + cos(y), y(0) = 1 has a unique solution on any interval of the form [-M, M], where M > 0.

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Answer:

see explanation

Step-by-step explanation:

the shape given is half a cylinder

the volume of a cylinder = πr²h , then volume of half a cylinder is

V = \(\frac{1}{2}\) πr²h

here r = 5 and h = 18

V = 0.5 × 3.14 × 5² × 18

  = 0.5 × 3.14 × 25 × 18

  = 706.5

  ≈ 707 cm³ ( to the nearest whole number )

Answer:

55 + .45m

Step-by-step explanation:

The total cost of renting the car is the fixed cost plus the cost per mile

55 + .45m where m is the number of miles

y = 0.45m + 55 [equation]

m [number of miles] = 100

Step-by-step explanation:

Equation:

y = mx + b

y = 0.45m (# of miles) + 55 (daily fee)

To solve for m, the number of miles:

100 = 0.45m + 55

Subtract 55 from each side.

45 = 0.45m

Answer:

21 Books in total

Step-by-step explanation:

If you just want the total number of books, here:

If each student has 3 books, and there are 7 students, we can create the equation: 7 * 3 :because this is showing that 7 people each have 3 books

7 * 3 = 21 so There are 21 books in total

Another we could write it is 3 + 3 + 3 + 3 + 3 + 3 + 3 because there are 7 students with 3 books each. Adding this up would equal 21.

Answer:

21 books in total

Step-by-step explanation:

If there is 7 students who have 3 books each, and want to find the total. The easiest way is multiply 7 with 3 to give you an answer of 21

Or draw a picture if it helps

Draw 7 stick figure and under it draw 3 books for them and count the books, still gives you 21

I think this is what you want

The series is absolutely convergent. In this code, the always block is used to implement the loop. The initial block is used to initialize the values of x, y, and i.

We can use the Comparison Test to determine whether the series is absolutely convergent, conditionally convergent, or divergent. We can compare the given series with the series [infinity] n = 1 1/n^2, which is a known convergent p-series with p = 2.

To use the Comparison Test, we need to find a positive constant M such that |sin(n)/(n^2)| <= M/n^2 for all n greater than some fixed value N.

Since -1 <= sin(n) <= 1 for all n, we have:

|sin(n)/(n^2)| <= 1/n^2

So we can choose M = 1 and use the Comparison Test as follows:

sum(sin(n)/(n^2)) <= sum(1/n^2)

Since the series on the right-hand side is convergent, the series on the left-hand side is absolutely convergent by the Comparison Test. Therefore, the series is absolutely convergent. In this code, the always block is used to implement the loop. The initial block is used to initialize the values of x, y, and i. The assign statements are used to assign the values of x and y to the output ports.

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Answer:

11.39

Step-by-step explanation:

Have a great day! :)

The equation of a plane in vector form is r. (n * a) = d, where a is a point on the plane, n is the normal, r is the position vector, and d is the distance from the origin. The line passes through (0,-5,-4) and has a direction vector of d = (1,0,0).

Given:Point through which the line passes (0,−5,−4)Normal to the surface at (0,−5,−4)The equation of a plane in vector form is given byr. (n * a) = dwhere, a is a point on the plane, n is the normal to the plane, r is the position vector and d is the distance of the plane from the origin.For the given point and normal vector,n = (0,-1,0)and a = (0,-5,-4)respectively.

So, the plane equation can be written as

r.(0,-1,0) = - 5

So, the equation of the plane can be given by y = - 5 It is given that the line passes through the point (0,-5,-4) which is normal to the surface at (0,-5,-4).As the given normal vector is in y-direction, the line will be parallel to x-z plane and perpendicular to the y-axis.

So, the direction vector of the line can be given byd = (1,0,0)Now, as the line passes through (0,-5,-4), we can get the vector equation of the line as

r = a + td

where, t is the parameter.So, the vector equation of the line can be givend = (0,-5,-4) + t(1,0,0)Thus, the vector equation of the line through point (0,−5,−4) which is normal to the surface at (0,−5,−4) isr = (t, - 5, - 4) where t is any real number.

Note: In the given question, it was not mentioned about the surface. But it is given that the line is normal to the surface. So, the equation of the surface is taken as the plane equation.

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Answer:

The interest is $5.80

Step-by-step explanation:

Here, we want to

calculate the interest on $580 for 6 months at a rate of 2%

Mathematically, we use the formula;

I = PRT/100

As T is not up to a year, we did use by 12 which is 6/12 = 0.5

P = 580

R = 2%

Substituting these values in the interest formula, we have;

I = (580 * 2 * 0.5)/100 = $5.80

Answer:

The inequality can be written as 10 - 3x ≤ 61. Solving for x, we have:

3x ≥ -51

x ≥ -17

The slope of the tangent line to the polar curve r = 8 cos(θ) at θ = 3 is -4.

To find the slope of the tangent line to a polar curve, we need to first find the derivative of r with respect to θ using the chain rule:

dr/dθ = -8 sin(θ)

Next, we can find the slope of the tangent line by using the polar slope formula:

dy/dx = (dy/dθ) / (dx/dθ) = (r sin(θ)) / (r cos(θ)) = tan(θ)

So at θ = 3, the slope of the tangent line is tan(3). Using a calculator, we can approximate this value to be about -1.43. However, we want the slope in terms of the x- and y-coordinates, so we can use the relationships x = r cos(θ) and y = r sin(θ) to find that at θ = 3, x = -4 and y = 6. So the slope of the tangent line is

dy/dx = tan(3) ≈ -1.43

≈ -4

Therefore, the slope of the tangent line to the polar curve r = 8 cos(θ) at θ = 3 is -4.

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Answer:

  6

Step-by-step explanation:

You want to know the number of uphill integers divisible by 15, where an uphill integer is one that has its digits strictly increasing.

An integer will be divisible by 15 if and only if it is divisible by 3 and 5. An integer is divisible by 5 if it ends in 5 or 0. An uphill integer cannot end in 0, so must end in 5.

An integer is divisible by 3 if the sum of its digits is divisible by 3

An uphill integer will have differences between successive digits that are positive integers. In order for the final digit to be 5, the sum of these differences must be 5. Hence we can find uphill integers by considering the "integer partitions" of 5: the sets of positive integers whose total is 5. Those sets would be ...

  {5}, {4, 1}, {3, 1, 1}, {2, 2, 1}, {2, 1, 1, 1}, {1, 1, 1, 1, 1}

Uphill integers will also have digit differences that are some permutation of each of these sets. For example, the digit differences may be {4, 1} or {1, 4}, corresponding to the numbers 45 or 15.

The uphill integers that end in 5 are ...

  5, 45, 15, 35, 25, 345, 145, 125, 245, 235, 135, 2345, 1345, 1245, 1235, 12345

We already know each of these is divisible by 5. The ones that have a digit total that is a multiple of 3 are ...

  15, 45, 135, 345, 1245, 12345

There are 6 uphill integers divisible by 15.

The best way to remedy Ask customers throughout the day on both weekdays and weekends.

The cause of the bias in the survey is likely sampling bias. This means that the sample of 110 customers may not be representative of the entire population of food court shoppers. The bias can arise if the sample is not selected randomly or if certain groups of shoppers are overrepresented or underrepresented in the sample.

To remedy the sampling bias, the best way would be to  Ask customers throughout the day on both weekdays and weekends.

By surveying customers at different times, including both weekdays and weekends, a more diverse and representative sample can be obtained. This will help to capture the preferences of a wider range of food court shoppers and reduce the bias introduced by sampling only weekday mornings.

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The manager of a shopping mall wishes to expand the number of shops available in the food court. He has a market researcher survey the first 110 customers who come into the food court during weekday mamings in distin what types of food the shoppers would like to see added to the food court,

Which of the following is the best way to remedy this problem?

OA cisne the sample size so that more people respond to the question OB Ask customers throughout the day on both weekdays and hands

OC Reward the question so that it is balanced

Answer:

p(blue) = 0.2

Step-by-step explanation:

A: "Pick 1 blue marble"

\(n(A)=C^{1}_3\) = 3

n(Ω) = \(C^{1}_{15}\) = 15

p(blue) = n(A)/n(Ω) = 3/15 = 0.2

The probability of selecting a blue marble is 0.20 expressed as a decimal.


To determine the theoretical probability of choosing a blue marble, follow these steps:
 
1. Count the total number of marbles in the bag: 3 blue + 5 red + 7 yellow = 15 marbles.
2. Identify the number of blue marbles: 3 blue marbles.
3. Calculate the probability of choosing a blue marble by dividing the number of blue marbles by the total number of marbles: 3 blue marbles / 15 total marbles.
4. Express this probability as a decimal by dividing 3 by 15: 3 ÷ 15 = 0.2.
5. Round the decimal to the nearest hundredth: 0.2 already falls at the hundredth place.
       
The theoretical probability of choosing a blue marble, expressed as a decimal rounded to the nearest hundredth, is 0.20 or simply 0.2.

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This does not imply that there is a one-to-one correspondence between dorm rooms and students.

A one-to-one correspondence between sets A and B if pairing of each object in A with one and only one object in B, and also another statement is when we counting one- to - one or like counting, one, two, three and so on.

In the question says that : Each and Every student assigned per room then we would be able to guarantee that there is a one-to-one correspondence between dorm rooms and students.

However, the possibility that two students could be assigned per one room, there is no way to imply that there is a guaranteed one-to-one correspondence between dorm rooms and students. It is follows only one student assign one room it is able to guarantee a one-to-one correspondence between dorm rooms and students.

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Answer:

Number of donuts each student get = 144 / x

Step-by-step explanation:

Given:

Number of donuts = 12 dozen

Number of students = x

Find:

How many donuts each student get

Computation:

Total number of donuts = 12 × 12 = 144

Number of donuts each student get = Total number of donuts / Number of students

Number of donuts each student get = 144 / x

The length of segment BD is given as follows:

BD = 6.

The geometric mean theorem states that the length of the altitude drawn from the right angle of a triangle to its hypotenuse is equal to the geometric mean of the lengths of the segments formed on the hypotenuse.

The altitude segment for this problem is given as follows:

BD.

The bases for this problem are given as follows:

3 and 12.

Hence the length of segment BD is obtained as follows:

(BD)² = 3 x 12

(BD)² = 36

BD = 6 -> taking the square root.

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Answer:

See below.

Step-by-step explanation:

<2 is congr <3                               Vertical angles are congruent

<1 is congr <4                                Congruence of angles is transitive

k || l                                                If two lines are cut by a transversal

                                                     such that alternate interior angles are

                                                      congruent, then the lines are parallel.