An elephant pushes with 2000 N on a load of trees. If it takes the elephant 45 seconds to move trees 15 meters, how much power did the elephant generate?
Answer:
Power generate by elephant = 666.67 W
Explanation:
Given:
Force = 2,000 N
Change in time = 45 Seconds
Distance = 15 meter
Find:
Power generate by elephant ?
Computation:
⇒ Work Done = Force × Distance
⇒ Work Done = 2,000 × 15
⇒ Work Done = 30,000
⇒ Power = Work Done / Time taken
⇒ Power generate by elephant = 30,000 / 45 seconds
⇒ Power generate by elephant = 666.67 W
Identify safety preparations that are common when exercising in extreme cold or extreme hot.
For extreme cold wear appropriate clothing: Dress in layers to keep warm, with a base layer that wicks away moisture, a middle layer for insulation, and an outer layer that protects against wind and moisture.
What is hypothermia?Hypothermia is a medical emergency that occurs when the body's core temperature drops below the normal range (around 98.6°F or 37°C). It is typically caused by prolonged exposure to cold temperatures, especially when the body is wet or windy conditions are present.
For extreme heat:
Wear appropriate clothing.
Stay hydrated
Avoid the hottest times of day.
Use sunscreen.
Be aware of signs of heat exhaustion and heat stroke.
Exercise caution.
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The orbital motion of a deep water wave extends to a depth equal to.
Light waves are
A.rotating waves.
B.longitudinal waves.
C.circular waves.
D.transverse waves
SHOCKING
Explanation:
Answer:
D i promises.
Explanation:
light waves can go 2 direction
ApplyStreets A and L run parallel to each other. BoulevardN forms a 75° angle with Street L south of (below) theirintersection. What angle does Boulevard N make withStreet L north of (above) their intersection? Justifyyour answer.
The angle that Boulevard N makes with Street L north of their intersection is also 75°.
What is intersection?Intersection is a point where two or more lines, curves, surfaces, or objects meet or cross each other. It is a common concept in mathematics, engineering, and everyday life. In mathematics, an intersection is a point where two or more sets of objects meet. In engineering, an intersection is a point where two or more roads, railways, or other transportation routes meet. In everyday life, an intersection is a point where two or more paths, streets, or other routes meet. Intersections are important in transportation, as they are the points where vehicles can change direction or turn around. Intersections are also important in mathematics, as they are the points where two or more lines, curves, or surfaces meet.
This is because the angle formed by two parallel lines is always equal. Since A and L run parallel to each other, the angle formed by Boulevard N and Street L south of their intersection is equal to the angle formed by Boulevard N and Street L north of their intersection. Therefore, the angle that Boulevard N makes with Street L north of their intersection is also 75°.
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what of the average speed from 4s from 8s
A.0.5m/s
B.1m/s
C.2m/s
D.3m/s
E.9m
=====================================================
Explanation:
At 4 seconds, the distance is 8 meters. Note the point (4,8)
At 8 seconds, the distance is 10 meters. The point here is (8,10)
Find the slope of the line through (4,8) and (8,10)
m = (y2-y1)/(x2-x1)
m = (10-8)/(8-4)
m = 2/4
m = 1/2
m = 0.5
The average speed on this interval is 0.5 m/s
-----------------
Another way to look at it:
We've gone from 8 meters to 10 meters, so that's a change of y = 2 meters.
During this, the time has changed from 4 seconds to 8 seconds, which is a difference of x = 4 seconds.
The velocity is the rate of change of distance over time
velocity = (change in distance)/(change in time) = y/x = 2/4 = 0.5 m/s
show how three identical 6 resistors must be connected tho have the following effective resistance values 9 and 4 ohms
Answer:
connect two 9 ohms resistance in series now it becomes 18 ohm
What is the magnitude of the magnetic field at the point the center of a long, straight solenoid; the solenoid carries current 0.300 A and has 4.00 * 103 windings per meter
The magnitude of the magnetic field at the point at the center of a long, straight solenoid if the solenoid carries a current of 0.300 A and has 4.00 ×10³ windings per meter would be 1.512 ×10⁻³ N/Amps m
What is a magnetic field?A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted. The SI unit of the magnetic field is tesla.
The magnetic field at the point at the center of a long, straight solenoid can be calculated by using the formula
B = μnI
where B is the magnetic field
μ is the Permeability constant having a value of 1.26 × 10⁻⁶ T/m
n is the number of winding per meter
I represent the current
By substituting the respective value in the formula
B=( 1.26 × 10⁻⁶ )× (4.00 ×10³)×0.300
B =1.512 ×10⁻³ N/Amps m
Thus, the magnitude of the magnetic field at the point at the center of a long, straight solenoid would be 1.512 ×10⁻³ N/Amps m.
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You toss an apple across the room to a friend. Which of the following
statements is true about the apple at the top of its trajectory?
Your question is incomplete. Please find below the complete question.
B. Its acceleration is 9.8 m/s^2 down.
What does acceleration mean?Acceleration, is the rate at which speed adjustments with time, in phrases of pace and path. A point or an item moving in a line is expanded if it hurries up or slows down.
We always have a vertical (downward ) acceleration of 9,8 m/s^2. The horizontal acceleration is zero in case you overlook friction forces. The vertical issue of speed is zero on the top of the trajectory whilst the horizontal component isn't like zero in any other case the apple will no longer arrive at your buddy.
You toss an apple across the room to a friend. Which of the following statements is true about the apple at the top of its trajectory?
A. Its acceleration is zero.
B. Its acceleration is 9.8 m/s2 down.
C. The horizontal component of its velocity is zero.
D. The vertical component of its velocity is 9.8 m/s down.
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help asap please!
calculate the answer to the correct number of significant digits.
-3.22 x 5.1
Calculate the time for a tiger to run 14.00 m when it maintains a constant velocity of 37.50 m/s to the north.
Answer:
.37 of a second
Explanation:
because the tiger only traveled 14 meters/of the 37.5 it can travel in just 1 second. so you treat it like a divisitory fraction. 14/37.50. you divide the 14 by 37.5 to find what fraction of the second it took to travel only 14 m. you can also use the same formula for distances that would require more than the 1 second to travel.
A 75-kg man stands on his toes by exerting an upward force through the Achilles tendon, as in Figure 9.43. (a) What is the force in the Achilles tendon if he stands on one foot? (b) Calculate the force at the pivot of the simplified lever system shown—that force is representative of forces in the ankle joint.
A person's weight multiplied by two to equal 72 kilos produces an Achilles tendon force of 1400 newtons, or two times their weight.
How much Achilles tendon force is there?Because of the repetitive overload it experiences during walking or running, the Achilles tendon is extremely prone to overuse problems. The Achilles tendon, particularly when running, is subjected to forces that are roughly 6–8 times that of a person's weight, which is almost the maximum load that the tendon can withstand [9, 45].A person's weight multiplied by two to equal 72 kilos produces an Achilles tendon force of 1400 newtons, or two times their weight.The Achilles tendon, despite its incredible strength, is commonly injured even though it can support loads of more than 3500 N2,3 during physical activity.To learn more about Achilles tendon force refer to:
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I need the answer for both questions plzZz
Answer:
Im not really sure lemme ask my friend he knows about this subject and when he gives me answer ill edit this
Explanation:
Answer:
i dont even know
Explanation:
I just dont know
24.1 In a two slit interference pattern projected on a screen, are the fringes equally spaced on the screen (a) everywhere, (b) only for large angles, or (c) only for small angles
In a two-slit interference pattern projected on a screen, the fringes are equally spaced on the screen (c) only for small angles.
In a two-slit interference pattern, the fringes observed on the screen are a result of the constructive and destructive interference of light waves passing through the slits. The spacing of these fringes depends on the angle of incidence.
(a) This is because the path difference between the light waves from the two slits increases as the angle of incidence increases.
(b) At large angles, the path difference between the interfering waves becomes significantly different, resulting in a noticeable variation in fringe spacing.
(c) In this case, the path difference between the interfering waves is relatively small, which leads to a more uniform spacing of the fringes. This can be explained using the small angle approximation, where sin(θ) ≈ θ for small angles (in radians).
In summary, the fringes in a two-slit interference pattern are more equally spaced for small angles due to the smaller path difference between the interfering waves. As the angle of incidence increases, the path difference becomes more significant, leading to a variation in fringe spacing.The correct answer is c.
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Using the Left Hand Rule, if current points up and
the field is toward you, which way does the motion
point?
A. Left
B. Down
c. Up
D. Right
Using the left hand rule, if current points up and the field is toward you, the motion points up.
What is the left hand rule?The left hand rule states that if the thumb, the fore finger and the middle finger are held mutually perpendicular to each other, the thumb points in the direction motion, the middle finger points in the direction of current while the fore finger points in the direction of the magnetic field.
Thus using the left hand rule, if current points up and the field is toward you, the motion points up.
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a cylinder with , and a diameter is being pulled by a string with a force . the cylinder rolls on a surface with a coefficient of friction of horizontally: a cable reel on a flat surface is pulled by a force at its center. friction exists between the reel and the surface. determine r, and the acceleration. is the cylinder slipping?
The radius of the cylinder is approximately 2.19 m, and the cylinder is experiencing a deceleration of approximately 1.86 m/s². Since the cylinder is decelerating and the force applied is less than the friction force, it is not slipping.
From the given information:
Mass of the cylinder, m = 5 kg
Moment of inertia of the cylinder, I = 12 kg·m²
Diameter of the cylinder, D = 0.5 m
Force applied, F = 25 N
Coefficient of friction, μ = 0.7
Radius of the cylinder, r = ?
To determine the radius (r) of the cylinder, we can use the relationship between moment of inertia (I) and mass (m) for a solid cylinder:
I = (1/2) * m * r²
Given I = 12 kg·m² and m = 5 kg, we can solve for r:
12 = (1/2) * 5 * r²
r² = 12 / (1/2) * 5
r² = 12 / 2.5
r² = 4.8
r ≈ √4.8
r ≈ 2.19 m
So, the radius of the cylinder is approximately 2.19 m.
Now, let's determine the acceleration of the cylinder. The force applied is given as F = 25 N. The friction force can be calculated using the equation:
Friction force = μ * Normal force
Since the cylinder is being pulled by the string, the normal force is equal to the weight of the cylinder, which is given by:
Weight = mass * acceleration due to gravity
Weight = m * g
Assuming a standard acceleration due to gravity of 9.8 m/s²:
Weight = 5 kg * 9.8 m/s² = 49 N
Friction force = μ * Normal force = μ * Weight = 0.7 * 49 N = 34.3 N
Now, we can calculate the net force acting on the cylinder:
Net force = Force applied - Friction force
Net force = 25 N - 34.3 N
Net force = -9.3 N
Since the net force is negative, indicating that the force applied is less than the friction force, the cylinder will experience a deceleration rather than acceleration. The magnitude of the deceleration can be calculated using Newton's second law:
Net force = mass * acceleration
-9.3 N = 5 kg * acceleration
acceleration = -9.3 N / 5 kg
acceleration = -1.86 m/s²
The negative sign indicates that the deceleration is in the opposite direction to the force applied, which means the cylinder is moving in the direction opposite to the applied force.
Hence, the radius of the cylinder is approximately 2.19 m, and the cylinder is experiencing a deceleration of approximately 1.86 m/s². Since the cylinder is decelerating and the force applied is less than the friction force, it is not slipping.
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Stopping Distance Activity
Background: This activity involves observing the effect of original car speed upon the
skid distance. The simulation involves a toy car rolling down a hill, hitting a box, and
skidding to a stop. The height from which the car is released can be modified. The
speed of the car at the bottom of the hill (prior to contact with the box) is reported. The
distance that the car (and box) skid before stopping can be measured. Before answering
the questions, it would be useful to first run the simulation for each of the provided
heights and to record the corresponding pre-collision car speed and the stopping
distance. The background grid on the simulation screen can be used to determine the
stopping distance. Each square on the grid is 10 cm in length along its edge.
Data:
Initial Height Pre-Collision Speed Skid Distance
(m/s)
(cm)
(cm)
10. 0
20. 0
30. 0
40. 0
50. 0
60. 0
70. 0
80. 0
By using the formula:- \(mgh= \frac{1}{2} mv^{2} , v = \sqrt{2gh}\), as the release height of the car increase the speed of the car increases.
As the release height of the car increases, the skid distance of the car increaseincrease due to increased velocity.
The directional speed of an object in motion, as measured by a specific unit of time and witnessed from a specific point of reference, is what is referred to as velocity.
Velocity can be defined as the rate at which something travels in a specific direction. Like the speed of a vehicle travelling north on a highway or the speed of a rocket after launch, for instance.
Less momentum with increased height. Less height, more speed. The rate at which it is exchanging height for velocity at any given moment in the fall is therefore equal to the velocity divided by the gravitational constant. As a result, at the top when its velocity is low, it loses only a tiny amount of height with each increase in velocity.
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complete question:-
A 38.5 kg man is in an elevator
accelerating downward. A normal
force of 343 N pushes up on him.
What is his acceleration?
Answer:
F = m*(g - a) →
a = g - F/m = 0.891 m/s² downward
Explanation:
If elevator was stationary, the normal force of elevator floor on man* would be = mg
mg = (38.5)(9.81) ≈ 378 N.
If elevator is accelerating downward the floor is accelerating away from man and so the normal force will be less than man's weight by: 378 - 343 = 35 N.
Hope this helps.
Answer:
-0.891
Explanation:
negative because downward
find the weight of an astronaut whose mass is 75 kg on the moon
What is the weight of a 5-kg object on Earth and on the moon?
Answer:
It would remain the same on Earth (5-kg) but on the moon, it would be 1-kg
Explanation:
To discover the weight on the moon, we partition the weight on earth by the world's power of gravity, which is 9.81m/s2. This ascertains the mass of the article. When we have the article's mass, we can discover the weight by increasing it by the gravitational power, which it is dependent upon.
A baseball of mass 0.3 kg and a tennis ball of mass 0.5 kg possess equal momentum. What is the velocity of tennis ball if the baseball is moving at 21 ms ¹?
definition of gametes?
EXPLAIN WITH STEPS PLZ!
* A boat moves towards the east with velocity of 20 m/s, then it is affected by acceleration towards the west of 4 m/s^2?, so its displacement after 15 s from the moment at which the boat starts to acquire the acceleration equals ........
a 350 m towards the east
b 300 m towards the west
c) 750 m towards the east
d) 150 m towards the west
\(\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2\)
\(\\ \sf\longmapsto s=20(15)+\dfrac{1}{2}(4)(15)^2\)
\(\\ \sf\longmapsto s=300+2(225)\)
\(\\ \sf\longmapsto s=300+450\)
\(\\ \sf\longmapsto s=750m\)
____________________ (is/are) one type of tectonic event captured in geologic maps.
Mountain building
Gravity shifts
Mammal evolution
Seismic activity
Answer:
Seismic activityis/are) one type of tectonic event captured in geologic maps.
Are moons 1-4 waxing are waning ?
Answer:
I want to help you but i cant.
Explanation:
please provide a screenshot or photos of moons 1-4
Two microwave frequencies are authorized for use in microwave ovens, 910 and 2555 MHz. Calculate the wavelength (in cm) of each.
The wavelengths for frequencies 910 and 2555 MHz are 32.9 and 11.7 cm respectively.
What is frequency:
Frequency describes the number of waves that pass a fixed place in a given amount of time.
What is wavelength:
It is defined as the distance in meter required to complete one circle.
here, two microwave frequencies are given
f1 = 910 MHz = 910* 10^6 Hz
f2 = 2555 MHz = 2555* 10^6 Hz
According to formula of frequency:
λ = v / fwhere
v is speed of wave.
f is frequency of wave.
All electromagnetic wave moves with same speed v = 3×10⁸ m/s.
for f1:
substituting the values in equation,
λ1 = v / f1
λ1 = 3×10⁸ / 910* 10^6
λ1 = 0.329 m
λ1 = 32.9 cm
for f2:
λ2 = v / f2
λ2 = 3×10⁸ / 2555* 10^6
λ2 = 0.117 m
λ2 = 11.7 cm
Hence,
the wavelengths for frequencies 910 and 2555 MHz are 32.9 and 11.7 cm respectively.
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An object with a mass of 20 kg has a net force of 80 N acting on it. What is the acceleration of the object?
Answer:
the answer is 4m/ s²
hope this helps love!! <3
If a current of 2.4 A is flowing in a cylindrical wire of diameter 2.0 mm, what is the average current density in this wire?Answera.3.6 b. 3.4c. 2.5
The current density in a cylindrical wire can be calculated using the formula J = I/A, where I is the current and A is the cross-sectional area of the wire. Given a current of 2.4 A and a wire diameter of 2.0 mm, the average current density in the wire is approximately 3.05 x 10⁶ A/m².
We can use the formula for current density, which is given by J = I/A, where J is the current density, I is the current, and A is the cross-sectional area of the wire. The cross-sectional area of a cylindrical wire is given by A = πr², where r is the radius of the wire.
Given that the current I is 2.4 A and the diameter of the wire is 2.0 mm, we can find the radius as r = d/2 = 1.0 mm = 0.001 m.
Using the formula for the area of a circle, A = πr², we get A = π(0.001 m)² = 7.854 x 10⁻⁷ m².
Substituting the values into the formula for current density, we get:
J = I/A = 2.4 A / 7.854 x 10⁻⁷ m² = 3.05 x 10⁶ A/m²
Therefore, the average current density in the wire is 3.05 x 10⁶ A/m², which is closest to option (a) 3.6.
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Two parallel wires are separated by 6.00 cm , each carrying 3.00 A of current in the same direction.(a) What is the magnitude of the force per unit length between the wires?
The magnitude of the force per unit length between two parallel wires can be calculated using Ampere's Law. Ampere's Law states that the magnetic field around a current-carrying wire is directly proportional to the current and inversely proportional to the distance between the wires.
In this case, the wires are separated by 6.00 cm and each wire carries a current of 3.00 A in the same direction. To find the magnitude of the force per unit length between the wires, we can use the formula:
Force per unit length = (μ₀ * I₁ * I₂) / (2 * π * d)
where μ₀ is the permeability of free space, I₁ and I₂ are the currents in the wires, and d is the distance between the wires.
Plugging in the given values:
Force per unit length = (4π * 10^(-7) T * m/A * 3.00 A * 3.00 A) / (2 * π * 0.06 m)
Simplifying:
Force per unit length = (4 * 3.00 * 3.00 * 10^(-7)) / (2 * 0.06) N/m
Force per unit length = (36 * 10^(-7)) / 0.12 N/m
Force per unit length = 300 * 10^(-7) N/m
Force per unit length = 3.00 * 10^(-5) N/m
Therefore, the magnitude of the force per unit length between the wires is 3.00 * 10^(-5) N/m.
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Predict the proportion of hydrogen to helium in the red giant.
The proportion of hydrogen to helium in the red giant is infinitesimally small.
A red giant is a stage in the star life where hydrogen gets fused with helium. Stars are on the zero main sequences when they initially begin to fuse hydrogen to helium. The length of time a star remains in the main-sequence stage is proportional to its mass.
Higher-mass stars finish each stage of development faster compared to lower-mass stars. When a star(e.g. sun) dies, it becomes a red giant composed of majorly helium. The synthesis of hydrogen to produce helium alters the inner composition of a star, causing variations in its temperature, brightness, and width.
Therefore, we can conclude that the proportion of hydrogen to helium in the red giant is infinitesimally small.
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