What are four ways you can describe the motion of a person on a swing?

Answer:

W = F s

F = 5.2E4 J / 170 m = 301 N

The magnitude of the total momentum of the two balls after the collision is Zero.

Expecting the collision is elastic, the total momentum is conserved, so the total momentum of the two balls after the collision will be equivalent to the total momentum before the collision.

As a result, all that is required is to determine the total momentum prior to the collision. We have, assuming that north is a positive direction:

the momentum of the ball 1: p₁ = mv = 2 kg × 4 m/s = 8 kg m/s

The momentum of ball 2: p₂ = mv = 1 kg × -8 m/s = -8 kg m/s

total momentum = p₁ + p₂ = 8 kg m/s + (-8 kg m/s) = 0

So, consequently, the total momentum will be zero following the collision.

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The metal is a good conductor of heat, while the paper is a poor conductor of heat. The metal is a conductor, and the paper is an insulator.

Conductors are materials that allow the easy flow of heat or electricity through them. In the case of the metal sheet, it has high thermal conductivity, which means it efficiently transfers heat. Therefore, when exposed to sunlight, the metal sheet absorbs the heat energy and quickly becomes warmer to the touch. On the other hand, paper is an insulator, which means it has low thermal conductivity. It does not conduct heat well and acts as a barrier to the flow of heat. As a result, when exposed to sunlight, the paper sheet does not efficiently absorb or transfer heat, and therefore it remains relatively cooler compared to the metal sheet.

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No, the 2px and 2py orbitals are not eigenfunctions of the z-component of the angular momentum operator. This is because the z-component of the angular momentum operator.

No, the 2px and 2py orbitals are not eigenfunctions of the z-component of the angular momentum operator. This is because the z-component of the angular momentum operator, Lz, is given by:

Lz = -iħ(∂/∂θ)

Where ħ is the reduced Planck's constant, and θ is the polar angle. The 2px and 2py orbitals are eigenfunctions of the x-component and y-component of the angular momentum operator, respectively.

To find the eigenvalues of the z-component of the angular momentum operator for the 2px and 2py orbitals, we need to apply the Lz operator to each of them. Let's consider the 2px orbital first:

Lz(2px) = -iħ(∂/∂θ)(2px)

= -iħ(∂/∂θ)[(1/√2)(y/a0)(z/2a0 - x/2a0)]

= iħ(1/√2)(z/2a0 - x/2a0)(1/a0)

= iħ(1/√2)(-sinθ)(1/a0)

The eigenvalue of Lz for the 2px orbital is then:

Lz(2px) = iħ(1/√2)(-sinθ)(1/a0)

Similarly, for the 2py orbital, we have:

Lz(2py) = iħ(1/√2)(cosθ)(1/a0)

Therefore, the 2px and 2py orbitals are not eigenfunctions of the z-component of the angular momentum operator, and their eigenvalues for this operator are given by iħ(1/√2)(-sinθ)(1/a0) and iħ(1/√2)(cosθ)(1/a0), respectively.

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It could be caused by a clogged or dirty air filter, malfunctioning thermostat, or damaged heating elements. The air ducts may also be leaking, allowing cold air to seep in and mix with the heated air, which results in cold air coming out of the vents instead of warm air.

Another possible cause of cold air coming out of the vents when the heat is on could be a faulty fan or fan motor that is not working properly. This can cause the heated air to remain in the furnace instead of being distributed throughout the house. Finally, it could be due to a blocked or restricted airflow, which may cause the system to overheat and result in cold air coming out of the vents.

It is important to conduct regular maintenance on heating systems, including cleaning and replacing air filters, checking the thermostat settings, and ensuring that the air ducts are free of leaks and blockages. If the problem persists, it may be necessary to consult with a professional HVAC technician to identify and repair any underlying issues that are causing cold air to come out of the vents instead of warm air.

There are several reasons why cold air may be coming out of the vents when the heat is on, ranging from simple issues such as clogged air filters to more complex problems such as a damaged fan motor or air ducts. Regular maintenance and repair can help prevent these issues and ensure that heating systems function correctly, providing warm air throughout the house.

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Answer:

too much :(

Explanation:

\overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}

\overline{a} = average acceleration

v = final velocity

v_0 = starting velocity

t = elapsed time

Answer:

a = Δv⁄t.

Explanation:

Answer: A

Explanation:

Answer:

C. tiny particles called charges flowing through the wires.

Explanation:

An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.

Hope it helps!

Answer:

c

Explanation:

electric current is tiny particles called charges flowing through the wires
pls mark me brainliest :)

The statement in the question is: "the mechanical stage lower knob causes the stage to move up and down." Therefore, the correct answer to the multiple-choice question is "up and down."

While the mechanical stage lower knob may also have additional functionalities, such as moving the stage right and left or back and forth, the statement in the question only mentions the up and down movement.

A mechanical knob that moves back and forth typically refers to a control or switch that can be turned or toggled in opposite directions to activate or deactivate a function or adjust a setting.

For example, a volume control knob on a stereo system can be turned clockwise to increase the volume and counterclockwise to decrease it. A light switch can be flipped up to turn on the light and flipped down to turn it off. A thermostat might have a knob that can be turned to adjust the temperature setting higher or lower.

The back and forth motion of a mechanical knob allows for easy manipulation of a device or machine, providing a tactile way to interact with it and make adjustments to its function or settings.

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The total time the balls are in the air is 2.77 s.

The correct answer is option E.

To calculate the total time the ball is in the air, we need to analyze the vertical motion of the ball. Let's consider the given values:

Height of the taller platform (H1) = 6.0 m

Height of the shorter platform (H2) = 3.6 m

Horizontal speed of the ball (ux) = 15 m/s

We can neglect friction for this calculation. Since the ball rolls off the taller platform horizontally, the initial vertical velocity (uy) is zero. We can use the following equation to calculate the time of flight:

H = ut + (1/2)\(gt^2\)

Phase 1: Upward motion

In this phase, the ball moves vertically against the force of gravity. The acceleration due to gravity (g) is approximately 9.8 m/s^2. The initial vertical velocity (uy) is zero.

Using the equation of motion:

H1 = (1/2)\(gt^2\)

6.0 = (1/2)(\(9.8)t^2\)

12.0 =\(4.9t^2\)

\(t^2\) = 12.0 / 4.9

\(t^2\) ≈ 2.449

t ≈ \(\sqrt{2.449}\)

t ≈ 1.564 s

Phase 2: Downward motion

In this phase, the ball moves vertically downward. The final velocity in the upward phase (when it reaches the top of the shorter platform) is zero. We can calculate the time it takes to fall from the shorter platform using the same equation:

H2 = (1/2)g\(t^2\)

3.6 = (1/2)(9.8)\(t^2\)

7.2 = 4.9\(t^2\)

\(t^2\) = 7.2 / 4.9

\(t^2\) ≈ 1.469

t ≈ \(\sqrt{1.469}\)

t ≈ 1.212 s

Total time:

The total time the ball is in the air is the sum of the times for phase 1 and phase 2:

Total time = t1 + t2

Total time ≈ 1.564 + 1.212

Total time ≈ 2.776 s

Therefore, among the given options the correct one is option E.

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The question probable may be:

The diagram represents two horizontal platforms that are different height levels above ground ball rolls off the taller platform with a horizontal speed of 15 m/s in travels through the air landing on top of the short a platform. What is the total time the ball is in the air where H1 =6.0 m H2= 3.6m (NEGLECT FRICTION)

A.0.16 s

B. 0.70 s

C.0.49s

D. 1.1 s

E. 2.77 s

Answer:

Have you ever tried turning a glass of water upside down without spilling it? It seems impossible! Both kids and adults will be amazed by this experiment that appears to defy gravity.

With just a few simple household items, you can try this simple and fun science experiment where kids can get see the effects of air pressure in action. Printable instructions, a demonstration video, and an easy to understand explanation of how it works are included below.

Helpful Tip: Be sure to try this experiment over a sink or large container lest you accidentally make a BIG wet mess!

From the formula for coulomb's, the formula for k would be k = Fd²/q1q2.

Here, we are required to solve for k from the Coulomb's formula, F=kq1q2/d².

Solving the formula for k, we obtain;

k = Fd²/q1q2

To solve the formula for k, we need to make k the subject of the formula;

F = kq1q2/d²

Then, F × d² = kq1q2

Therefore, to make k the subject of the formula; we divide both sides of the equation by q1q2.

Therefore, k = Fd²/q1q2.

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Complete question

Coulomb's Law is given by the formula

F=kq1q2/d2

The force F between two charges q1 and q2 in a vacuum is proportional to the product of the charges, and is inversely proportional to the square of the distance d between the two charges. Solve the formula for k.

Answer:.

They both rely on "reflected" sound waves.

Answer:Whenever an object experiences uniform circular motion there will always be a net force acting on the object pointing towards the center of the circular path. This net force has the special form  , and because it points in to the center of the circle, at right angles to the velocity, the force will change the direction of the velocity but not the magnitude.

It's useful to look at some examples to see how we deal with situations involving uniform circular motion.

Example 1 - Twirling an object tied to a rope in a horizontal circle. (Note that the object travels in a horizontal circle, but the rope itself is not horizontal). If the tension in the rope is 100 N, the object's mass is 3.7 kg, and the rope is 1.4 m long, what is the angle of the rope with respect to the horizontal, and what is the speed of the object?

As always, the place to start is with a free-body diagram, which just has two forces, the tension and the weight. It's simplest to choose a coordinate system that is horizontal and vertical, because the centripetal acceleration will be horizontal, and there is no vertical acceleration.

The tension, T, gets split into horizontal and vertical components. We don't know the angle, but that's OK because we can solve for it. Adding forces in the y direction gives:

This can be solved to get the angle:

In the x direction there's just the one force, the horizontal component of the tension, which we'll set equal to the mass times the centripetal acceleration:

We know mass and tension and the angle, but we have to be careful with r, because it is not simply the length of the rope. It is the horizontal component of the 1.4 m (let's call this L, for length), so there's a factor of the cosine coming in to the r as well.

Rearranging this to solve for the speed gives:

which gives a speed of v = 5.73 m/s.

Example 2 - Identical objects on a turntable, different distances from the center. Let's not worry about doing a full analysis with numbers; instead, let's draw the free-body diagram, and then see if we can understand why the outer objects get thrown off the turntable at a lower rotational speed than objects closer to the center.

In this case, the free-body diagram has three forces, the force of gravity, the normal force, and a frictional force. The friction here is static friction, because even though the objects are moving, they are not moving relative to the turntable. If there is no relative motion, you have static friction. The frictional force also points towards the center; the frictional force acts to oppose any relative motion, and the object has a tendency to go in a straight line which, relative to the turntable, would carry it away from the center. So, a static frictional force points in towards the center.

Summing forces in the y-direction tells us that the normal force is equal in magnitude to the weight. In the x-direction, the only force there is is the frictional force.

The maximum possible value of the static force of friction is

As the velocity increases, the frictional force has to increase to provide the necessary force required to keep the object spinning in a circle. If we continue to increase the rotation rate of the turntable, thereby increasing the speed of an object sitting on it, at some point the frictional force won't be large enough to keep the object traveling in a circle, and the object will move towards the outside of the turntable and fall off.

Why does this happen to the outer objects first? Because the speed they're going is proportional to the radius (v = circumference / period), so the frictional force necessary to keep an object spinning on the turntable ends up also being proportional to the radius. More force is needed for the outer objects at a given rotation rate, and they'll reach the maximum frictional force limit before the inner objects will.

Explanation:

Answer:

Every rock is somewhere in the rock cycle. The story of the rock is the story of rock cycle: where the rock is now on the rock cycle, the path it took on the rock cycle to get to where it is now, and the path on the rock

Explanation:

This is the answer i put it and it worked if it didn't work for you that's because you lesson or teacher was doing it in a different way.

Answer:

The rock cycle, illustrated in Figure below, depicts how the three major rock types – igneous, sedimentary, and metamorphic - convert from one to another. Arrows connecting the rock types represent the processes that accomplish these changes.

Explanation:

Answer:

girl what- I can't answer this but I need points so I'ma just put this random lol sorry tho . ask the tutor

Answer:

The option that best describes the relationship between frequency and wavelength of electromagnetic waves is the third option

c. The frequency increases as the wavelength decreases

Explanation:

The frequency of an electromagnetic wave, 'f', is given by the following formula;

\(Frequency, \, f = \dfrac{Wave \ Speed,v }{Wavelength, \ \lambda}\)

From the above formula, the frequency of an electromagnetic wave is inversely proportional to the wavelength, and therefore, a higher frequency, ('f', to increase), requires a lower wavelength, (λ, decreases)

The correct option is that the frequency of an electromagnetic increases as the wavelength of the wave decrease.

Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

Answer: I'm sorry what's wrong with your money

Explanation:

Answer: LOL YO I HAVE 5K IN GROUP FUNDS

Explanation:

The accommodation process is essential for the eye to maintain clear vision, regardless of the distance of the objects being viewed.

Accommodation is the process by which the eye’s lens changes shape to focus on objects at varying distances. When the eye is focused on a distant object, the ciliary muscle in the eye relaxes and the lens becomes flatter, thereby increasing the distance between the lens and the retina.

This enables the eye to focus light rays from distant objects on the retina. When the eye is focused on a nearby object, the ciliary muscle contracts and the lens becomes thicker, bringing it closer to the retina and enabling it to focus light rays from the nearby object onto the retina.

Therefore, the human eye can accommodate the images of objects located at different distances from the eye. This is made possible by the ciliary muscles. The ciliary muscle adjusts the curvature of the lens in the eye to enable the eye to focus light rays on the retina, which is at the back of the eye.

The  answer to the question of what is the process of accommodation in the human eye is that the ciliary muscles of the eye adjust the lens’ shape to enable the eye to focus on objects at varying distances, resulting in clearer vision.

The conclusion is that the accommodation process is essential for the eye to maintain clear vision, regardless of the distance of the objects being viewed.

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Answer:

Air temperature and air pressure both decreases

Answer: A

Explanation:

Answer:

Work is defined as force thru a distance:   W = F * S

Power is defined as Work per unit time  P = W / t

So we an write:  P = F * S / t  = 2000 N * 50 m / 5 s = 20,000 N-m/s

Since a Joule/sec is equivalent to a Watt

The power required is 20,000 Watts or 20  Kw

Also, you can convert to Hp since 1 Hp = 746 Watts

Explanation:

\(E = \frac{BA}{t} \sin( \theta) \\ = \frac{1.23 \times 2}{1} \\ = 2.46 \: V\)

The given series, 1 + 7n Σ 57 n = 1, is divergent because the terms in the series continue to increase without bounds, the sum of the series also increases indefinitely.

To determine the convergence or divergence of the series, we can analyze its behaviour as n approaches infinity. The series can be written as Σ(1 + 7n*57) for n = 1 to infinity. By simplifying the expression, we have Σ(399n + 1) for n = 1 to infinity.

As n increases, the summand of the series grows linearly with a coefficient of 399. Since the coefficient is nonzero and positive, the series will diverge. This means that the sum of the series will not approach a finite value as n tends to infinity.

Therefore, the given series is divergent, and we cannot find its sum. It is important to note that a divergent series does not have a finite sum. Therefore, the sum of the given series is "DIVERGES."

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This is determined by dividing the overall distance traveled by the overall journey time. Consider the older automobile as an illustration. The automobile will cover 70 miles in two hours.

That is speed Equals distance time. Alternatively, you can calculate the time by dividing the distance traveled by the speed. You can figure out the third input if you knew two of the inputs. For instance, if a car drives 120 miles in 2 hours, we may calculate the speed as 120 x 2 Equals 60 mph.

Average The arithmetic mean is calculated simply adding a set of numbers, dividing by their count, and then taking the result. For instance, the result of 30 divided by 6 is 5, which is the mean for & 10. Median a collection of numbers that falls in the middle.

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The magnitude of the elevator's acceleration is 18.25 m/s².

The acceleration of the elevator is calculated as follows;

R = Fa - Fg

R = ma - mg

R = m(a - g)

where;

m = W/g

m = (545 N) / (9.8 m/s²)

m = 55.61 kg

ma = R + mg

ma = R + W

a = (R + W) /m

a = (470 + 545) / 55.61

a = 18.25 m/s²

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Answer:

1/2 m v^2 = G M m / R         speed of object at surface of earth

v^2 = 2 G M / R        escape speed needed

V = 3 v     if original speed = 3 * escape speed

v^2 / 9 = 2 G M / R

v^2 = 18 G M / R    where v is initial speed

v^2 = G M / R  * (18 - 2) = 16 G M / R     very far from earth

v = (16 G M / R)^1/2

v = (16 * 6.67E-11 * 5.98E24 / 6.37E6)^1/2

v = 31650 m/s = 19.7 mi/sec

When a particle is projected from the surface of Earth with a speed equal to 3 times the escape speed, its final speed when very far from Earth will be 2 times the escape speed.

The escape speed is the minimum speed required for an object to overcome Earth's gravitational pull and move indefinitely away from it.

When a particle is projected with a speed 3 times the escape speed, it has more than enough energy to escape Earth's gravity.

As the particle moves away from Earth, it loses some of its kinetic energy due to Earth's gravitational force. Eventually, when the particle is very far from Earth, it will have lost an amount of kinetic energy equal to the escape speed.

Summary: When a particle is projected with a speed 3 times the escape speed and reaches a point very far from Earth, its speed will be 2 times the escape speed.

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