Answer:
9 times as great
Explanation:
KE = 1/2mv²
1/2(1200)(2)² = 2,400 J1/2(1200)(6)² = 21,600 J21,600 / 2,400 = 9
A race car makes one lap around a track of radius 50 m in 9.0 s. What was the car's centripetal acceleration?
The velocity of the car is 5.5 m/s. Then the centripetal acceleration of the car will be 0.6 m/s².
What is centripetal acceleration?Acceleration is a physical quantity measuring the rate of change in velocity. It has both magnitude and direction.
Centripetal acceleration is the acceleration of an object moving through a circular path. Thus its measures the rate of change in velocity of the body moving in the curvature path.
The centripetal acceleration = V²/R.
Where R is the radius of the curvature path.
The car moves 50 m in 9 seconds. Its velocity is 50/9 = 5.5 m/s.
Thus, centripetal acceleration = (5.5 × 5.5) m/s/ 50 m = 0.6 m/s².
Therefore, the centripetal acceleration of the car moving at a speed of 9 m/s through curvature path is 0.6 m/s².
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PLEASE HELP ME ANSWER THIS QUESTION.
When the segment is shrunk to one-third of its original length, the ratio of the final linear charge density (?f) to the initial linear charge density (?i) is f/?i = 3
This is because the charge is the same, but the length of the segment has decreased to one-third of its original length. Therefore, the charge density has increased by a factor of 3.
The ratio of the electric force on the proton after the segment is shrunk (Ff) to the force before the segment was shrunk (Fi) is also 3. This is because the electric force is directly proportional to the charge density, so if the charge density increases by a factor of 3, the electric force will also increase by a factor of 3.
If the original segment of wire is stretched to 15 times its original length, the charge density will decrease by a factor of 15. To keep the linear charge density unchanged, we need to add 14 times the original charge to the wire. This is because the original charge will be spread out over 15 times the original length, so we need to add 14 times the original charge to make up for the decrease in charge density.
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Rotators motion example
Answer:
the motion of a spinning top, rotation of the earth and other planets, movement of hands of a clock, etc.
Answer:
the motion of a spinning top, rotation of the earth and other planets, movement of hand of a clock, etc.
A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and 272.0 N (54.4 lbs) stand on the board so that the board is balanced.
What is the upward force exerted on the board by the support?
The upward force exerted on the board by the support is 530.8 N.
Upward force exerted on the board by the supportThe upward force exerted on the board by the support is calculated as follows;
F(up) = 52.8 N + 206.0 N + 272.0 N
F(up) = 530.8 N
Thus, the upward force exerted on the board by the support is 530.8 N.
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what is reaction force?
original answers please
40 pointsss
According to Newton's third law
Every action in the world has an equal and opposite reaction.Or
\(\\ \tt\longmapsto F_x=-F_x\)
Answer:
When an object exerts a force on another force, there will be a force in the opposite direction exerted by the second object. This force is called reaction force.
For example, when an object is sliding, the reaction force is the friction that acts against the movement.
Hope this Helps!
Have a wonderful day!
los deportesfill in the blanks activity 5 attempts left due march 24th 8:30 am name the sport associated with each object. include the definite article. follow the model. questions modelo you see: a soccer ball
The sports fill-in-the-blanks activity requires participants to identify the sport associated with different objects and include the definite article while following the given model.
Objective of activity is to test participants' knowledge of sports and related equipment while improving their proficiency in Spanish language. The activity helps participants to practice their grammar, vocabulary, and sentence structure skills while also promoting memory and comprehension skills. Here are a few sample questions for sports fill-in-the-blank activity:
You see a tennis racket. -Answer: Ves una raqueta de tenis.You see a hockey stick.-Answer: Ves un palo de hockey.You see a baseball bat.-Answer: Ves un bate de béisbol.You see a volleyball.-Answer: Ves un balón de voleibol.You see a swimming cap.-Answer: Ves una gorra de natación.To know more about sports, here
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No no no no. no no no no
Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge
Question 3 of 10
Which option lists a form of potential energy followed by a form of kinetic
energy?
A. Gravitational energy | elastic energy
B. Sound energy | nuclear energy
C. Magnetic energy | electromagnetic energy
D. Electromagnetic energy | electrical energy
Answer: Option C
Magnetic energy | Electromagnetic energy
Hi im really confused and need an explanation on this question:
How much energy would be needed to raise the temperature of the air in a room by 5.0°C if the room measures 4.0m x 4.0m x 3.0m? (Density of air = 1.0kg/m³)
Assume that the room has no furniture and that the walls gain no thermal energy.
The energy required to raise the temperature of the air in a room by 5.0°C is 428.4 kJ
U = \(c_{p}\) m ΔT
U = Energy
\(c_{p}\) = Specific heat
m = Mass
ΔT = Change in temperature
ρ = Density
V = Volume
ρ\(_{air}\) = 1275 g / m³ (Dry air )
\(c_{p}\) = 1 J / g K
ΔT = 5 °C
V = 4 * 4 * 3
V = 48 m³
m = ρ V
m = 1275 * 48
m = 61200 g
U = 1 * 61200 * 7
U = 428400 J
U = 428.4 kJ
Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 428.4 kJ
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b) A child looking into a small, polished hemispherical metal bowl sees an erect image of himself 21cm from the bowl. He turns the bowl over and sees a further erect image of himself 7cm from the bowl. What is the radius of curvature of the bowl?
The radius of curvature of the bowl is 42 cm. It should be noted that this is a negative value, indicating that the mirror is concave (curved inward) rather than convex (curved outward).
The situation described can be modeled using the thin lens equation, which relates the object distance, image distance, and focal length of a lens or curved mirror. In this case, we can assume that the bowl acts as a concave mirror, with its reflecting surface forming a portion of a sphere.
We can also assume that the mirror is thin, meaning that the distance between the reflecting surface and the center of curvature is much greater than the radius of curvature.
Let us denote the radius of curvature of the mirror as R. When the child looks into the bowl, an erect image of himself is formed at a distance of 21 cm from the bowl. Using the thin lens equation, we can write:
\(1/f = 1/d_o + 1/d_i\)
where f is the focal length of the mirror, \(d_o\) is the object distance (i.e., the distance between the child and the mirror), and \(d_i\)is the image distance (i.e., the distance between the mirror and the image).
In this case, the object distance is negative (since the child is looking into the bowl from the same side as the object), and the image distance is positive (since the image is erect). Substituting the given values, we obtain:
\(1/f = -1/21 + 1/d_i\)
Next, when the child turns the bowl over, another erect image of himself is formed at a distance of 7 cm from the bowl. Using the same equation, we can write:
\(1/f = -1/d_o + 1/d_i'\)
where d_i' is the image distance for this case. In this case, the object distance is positive (since the child is looking at the bowl from the opposite side of the object), and the image distance is also positive (since the image is erect). Substituting the given values, we obtain:
\(1/f = 1/7 + 1/d_i'\)
Now we have two equations for f in terms of \(d_i\) and \(d_i\)', respectively. We can solve for \(d_i\)and \(d_i\)' by setting these two equations equal to each other and simplifying:
\(-1/21 + 1/d_i = 1/7 + 1/d_i'\\d_i' = 1/(1/7 - 1/21 + 1/d_i) = 28 cm\)
Now that we know both image distances, we can solve for the radius of curvature R using the mirror formula, which relates the focal length to the radius of curvature:
1/f = 2/R
Substituting the values of f and \(d_i\), we obtain:
\(1/R = 2/f = -1/21 + 1/d_i\)
Solving for R, we obtain:
R = -42 cm
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a ball of mass 100g moving at a velocity of 100m/s collides with another ball of mass 400g moving at 50m/s in same direction, if they stick together calculate the velocity and loss of energy
Answer:
Velocity of the two balls after collision: \(60\; \rm m \cdot s^{-1}\).
\(100\; \rm J\) of kinetic energy would be lost.
Explanation:
VelocityBecause the question asked about energy, convert all units to standard units to keep the calculation simple:
Mass of the first ball: \(100\; \rm g = 0.1\; \rm kg\).Mass of the second ball: \(400\; \rm g = 0.4 \; \rm kg\).The two balls stick to each other after the collision. In other words, this collision is a perfectly inelastic collision. Kinetic energy will not be conserved. The velocity of the two balls after the collision can only be found using the conservation of momentum.
Assume that the system of the two balls is isolated. Thus, the sum of the momentum of the two balls will stay the same before and after the collision.
The momentum of an object of mass \(m\) and velocity \(v\) is: \(p = m \cdot v\).
Momentum of the two balls before collision:
First ball: \(p = m \cdot v = 0.1\; \rm kg \times 100\; \rm m \cdot s^{-1} = 10\; \rm kg \cdot m \cdot s^{-1}\).Second ball: \(p = m \cdot v = 0.4\; \rm kg \times 50\; \rm m \cdot s^{-1} = 20\; \rm kg \cdot m \cdot s^{-1}\).Sum: \(10\; \rm kg \cdot m \cdot s^{-1} + 20 \; \rm kg \cdot m \cdot s^{-1} = 30 \; \rm kg \cdot m \cdot s^{-1}\) given that the two balls are moving in the same direction.Based on the assumptions, the sum of the momentum of the two balls after collision should also be \(30\; \rm kg \cdot m \cdot s^{-1}\). The mass of the two balls, combined, is \(0.1\; \rm kg + 0.4\; \rm kg = 0.5\; \rm kg\). Let the velocity of the two balls after the collision \(v\; \rm m \cdot s^{-1}\). (There's only one velocity because the collision had sticked the two balls to each other.)
Momentum after the collision from \(p = m \cdot v\): \((0.5\, v)\; \rm kg \cdot m \cdot s^{-1\).Momentum after the collision from the conservation of momentum: \(30\; \rm kg \cdot m \cdot s^{-1}\).These two values are supposed to describe the same quantity: the sum of the momentum of the two balls after the collision. They should be equal to each other. That gives the equation about \(v\):
\(0.5\, v = 30\).
\(v = 60\).
In other words, the velocity of the two balls right after the collision should be \(60\; \rm m \cdot s^{-1}\).
Kinetic EnergyThe kinetic energy of an object of mass \(m\) and velocity \(v\) is \(\displaystyle \frac{1}{2}\, m \cdot v^{2}\).
Kinetic energy before the collision:
First ball: \(\displaystyle \frac{1}{2} \, m \cdot v^2 = \frac{1}{2}\times 0.1\; \rm kg \times \left(100\; \rm m \cdot s^{-1}\right)^{2} = 500\; \rm J\).Second ball: \(\displaystyle \frac{1}{2} \, m \cdot v^2 = \frac{1}{2}\times 0.4\; \rm kg \times \left(50\; \rm m \cdot s^{-1}\right)^{2} = 500\; \rm J\).Sum: \(500\; \rm J + 500\; \rm J = 1000\; \rm J\).The two balls stick to each other after the collision. Therefore, consider them as a single object when calculating the sum of their kinetic energies.
Mass of the two balls, combined: \(0.5\; \rm kg\).Velocity of the two balls right after the collision: \(60\; \rm m\cdot s^{-1}\).Sum of the kinetic energies of the two balls right after the collision:
\(\displaystyle \frac{1}{2} \, m \cdot v^{2} = \frac{1}{2}\times 0.5\; \rm kg \times \left(60\; \rm m \cdot s^{-1}\right)^2 = 900\; \rm J\).
Therefore, \(1000\; \rm J - 900\; \rm J = 100\; \rm J\) of kinetic energy would be lost during this collision.
What is generally TRUE about diagnosing psychological disorders?
A.
High levels of neurotransmitters have been linked to depression.
B.
Diagnoses are not based on opinion or personal assessment.
C.
Doctors agree about what behaviors make up each disorder.
D.
Psychological disorders can be very difficult to diagnose.
The statement that says "Psychological disorders can be very difficult to diagnose" is true about diagnosing psychological disorders.
What are psychological disorders?Psychological disorders are those mental, behavioral, emotional and thinking conditions that interfere with the normal performance of the individual in society.
Mental disorders are psychiatric conditions that are expressed in a syndrome, verifiable from different diagnostic criteria.The steps to obtain a diagnosis include a medical history, physical examination, and possibly laboratory tests and a psychological evaluation.Therefore, we can conclude that a psychological disorder is an alteration in the mental balance of a person that requires specialized attention adapted to the characteristics of the dysfunction.
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HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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A ball is projected at an angle of 53°. If the initial velocity is 48 meters/second, what is the vertical component of the velocity with which it was launched?
A.) 31 meters/second
B.) 38 meters/second
C.) 44 meters/second
D.) 55 meters/second
Answer:
The vertical component of the velocity can be found using the formula:
V₀y = V₀ * sin(θ)
where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.
Substituting the given values, we have:
V₀y = 48 * sin(53°)
Using a calculator, we can evaluate sin(53°) to be approximately 0.799:
V₀y = 48 * 0.799
V₀y ≈ 38.352
Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.
Answer:
B.) 38 meters/second
Explanation:
A parallel-plate capacitor with plate area 2.6 cm^2 and air-gap separation 0.25 mm is connected to a 30 V battery, and fully charged. The battery is then disconnected.
I Solved most of the parts of this q's but not this one:
The plates are now pulled to a separation of 0.55 mm. What is the charge on the capacitor now?
note:
I found 125.5pC and the answer unit is pC
Answer:
276.12 pC
Explanation:
We are given that
Area,A=\(2.6 cm^2=2.6\times 10^{-4}m^2\)
Where \(1 cm^2=10^{-4} m^2\)
\(d=0.25 mm=0.25\times 10^{-3} m\)
\(1mm=10^{-3} m\)
Potential difference, V=30 V
We have to find the charge on the capacitor when the plates are pulled to a separation of 0.55 mm.
We know that
Charge ,\(Q=\frac{\epsilon_0 A V}{d}\)
Where \(\epsilon_0=8.85\times 10^{-12}\)
Using the formula
\(Q=\frac{8.85\times 10^{-12}\times 2.6\times 10^{-4}\times 30}{0.25\times 10^{-3}}\)
\(Q=2.7612\times 10^{-10} C\)
\(Q=276.12p C\)
\(1 pC=10^{-12} C\)
When the plates are now pulled to a separation of 0.55 mm.Then, the charge on the plates remain same because the battery has been disconnected.
Therefore, charge on the capacitor=276.12 pC
Question 3
A craned moved a 200 kg hot tub from the ground to the top of the hotel, 10 stories above the ground, in 80 seconds. If the crane used 200,000 J of energy, how
much power did the crane need?
Answer:
\(Power = 2.5kW\)
Explanation:
Given
\(Mass = 200kg\) -- mass of tub
\(Energy = 200,000J\)
\(Time = 80s\)
Required
Determine the amount of power needed
Power is calculated as thus:
\(Power = \frac{Energy}{Time}\)
Substitute values for Energy and Time
\(Power = \frac{200,000J}{80s}\)
\(Power = 2500W\)
Divide by 1000 to convert to kW (kilowatt)
\(Power = 2.5kW\)
Xander reached a final velocity of 4.5 m/s for 3.5 seconds. Finley reached a final velocity of 3.6 m/s for 4.2 seconds. Max reached a final velocity of 7.3 m/s for 1.2 seconds. They all started at the same location from rest.
Which lists them from least to most acceleration?
Max Finley Xander
Max Xander Finley
Xander Finley Max
Finley Xander Max
Arranging the acceleration of Xander, Finley and Max from least to most, we have: Finley, Xander, Max
The correct answer to the question is the last option. Finley, Xander, Max
To know which option is correct, we shall determine the acceleration of each person. This can be obtained as follow:
For Xander:Initial velocity (u) = 0 m/s
Final velocity (v) = 4.5 m/s
Time (t) = 3.5 s
Acceleration (a) =?\(a = \frac{v - u}{t} \\\\a = \frac{4.5 - 0}{3.5} \\\\a = \frac{4.5}{3.5}\\\\\)
a = 1.29 m/s²For Finley:Initial velocity (u) = 0 m/s
Final velocity (v) = 3.6 m/s
Time (t) = 4.2 s
Acceleration (a) =?\(a = \frac{v - u}{t} \\\\a = \frac{3.6 - 0}{4.2} \\\\a = \frac{3.6}{4.2}\\\\\)
a = 0.86 m/s²For Max:Initial velocity (u) = 0 m/s
Final velocity (v) = 7.3 m/s
Time (t) = 1.2 s
Acceleration (a) =?\(a = \frac{v - u}{t} \\\\a = \frac{7.3 - 0}{1.2} \\\\a = \frac{7.3}{1.2}\\\\\)
a = 6.08 m/s²SUMMARY:Xander's acceleration = 1.29 m/s²
Finley's acceleration = 0.86 m/s²
Max's acceleration = 6.08 m/s²
Arranging the acceleration of Xander, Finley and Max from least to most, we have: Finley, Xander, Max
The correct answer to the question is the last option. Finley, Xander, Max
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Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.83 ✕ 105 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 3.04 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.
Answer:
\(F=2.84*10^{-26}N\) & -y direction
\(F=2.84*10^{-26}N\) & +y direction
Explanation:
From the question we are told that:
Speed of electron \(V_e=3.83 * 10^5 m/s\) +x direction
Earths magnetic field \(B_e=3.04 * 10^-^8\) +z direction
a)
Generally the equation for magnetic force \(F_m\) is mathematically given by
\(F=q(V_e*B_e)\)
where
\(q=1.6*10^{-19}c\\\=i*\=z=-\=j\)
\(F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)\)
\(F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)\)
\(F=-2.84*10^{-26}N \=j\)
Magnitude & Direction
\(F=2.84*10^{-26}N\) -y direction
b)
Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by
\(\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)\)
\(\=F'=-2.84*10^{-26}N \=j\)
Magnitude & Direction
\(F=2.84*10^{-26}N\) & +y direction
A bird flew to catch a prey and went from 12 m/s to 22 m/s in 2 seconds. What was the magnitude of the bird's acceleration?
Answer: Peregrine falcons are famed for their high-speed, high-altitude stoops. Hunting prey at perhaps the highest speed of any animal places a stooping falcon under extraordinary physical, physiological, and cognitive demands, yet it remains unknown how this behavioural strategy promotes catch success. Because the behavioral aspects of stooping are intimately related to its biomechanical constraints, we address this question through an embodied cognition approach. We model the falcon’s cognition using guidance laws inspired by theory and experiment, and embody this in a physics-based simulation of predator and prey flight. Stooping maximizes catch success against agile prey by minimizing roll inertia and maximizing the aerodynamic forces available for maneuvering but requires a tightly tuned guidance law, and exquisitely precise vision and control.
Explanation:
Through which of the following mediums is the velocity of a sound wave the greatest?A) AirB) LeadC) SteelD) Water
The speed of sound depends on the density of the medium in which the sound travels. We know that solids are denser than liquids, liquids are denser than gases. This means that the speed of sound will be greater in solids than in liquids and similarly, the speed of sound is greater in liquids than in gases.
Now that we know this, we just need to remember that the speed of sound in a solid is given by:
\(v=\sqrt{\frac{Y}{\rho}}\)where Y is Young's module and rho is the density. From this equation we notice that the velocity of sound in solids decreases as the density increase.
The density of steel is approximately 7.85 g/cm^3 and the density of lead is 11.35 g/cm^3; from this we conclude that the speed of sound is greater in steel than in lead.
Therefore, the answer is C
Lenore is on an inclined plane next to her truck. Holding her hands steady, she pushes a box up the plane and into her truck. Where can energy be
lost? (1 point)
O Friction between Lenore and the ground.
O Friction between the truck and the inclined plane.
O Friction between the box and the inclined plane.
O Friction between Lenore's hands and the box.
The energy is lost in friction between the box and the inclined plane while pushing the box up the plane and into her truck.
What is friction and where is the energy getting lost?Friction is the resistance of an object on the surface to move forward and is denoted by u.Here in this question Lenore is standing on an inclined plane along with her truck next to her.She is pushing the boxes up to her truck , so there comes a friction between the heavy boxes and ground.To keep it little weight the box could have been slided to avoid the friction.Hence the energy is getting lost in friction between box and the inclined plane.To know more about friction visit:
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in physics what is moment of couples?
The moment of a couple is significant in various applications, such as analyzing the equilibrium and rotational motion of objects, understanding the behavior of rotating systems, and studying the effects of torques in mechanics and engineering.
In physics, the moment of a couple, also known as torque, refers to the rotational effect produced by two equal and opposite forces acting on an object but not along the same line of action.
A couple consists of two forces that have the same magnitude, act in parallel lines, and are opposite in direction. These forces create a rotational moment or torque around a particular point, known as the pivot or axis of rotation. The moment of a couple is a measure of the tendency of the couple to rotate an object.
The magnitude of the moment of a couple is given by the product of one of the forces and the perpendicular distance between the lines of action of the two forces. Mathematically, it can be expressed as:
Moment of couple = Force × Perpendicular distance
The SI unit of moment of a couple is the newton-meter (Nm). It is also important to note that the moment of a couple is a vector quantity and follows the right-hand rule for determining its direction.
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Please solve and answer please
Answer: 60 m
Explanation:
v = s/t
vt = s
20 x 3 = 60
7. Particle A (mass = m, charge = Q) and B (mass = m, charge = 5 Q) are released from rest with the distance between them equal to 1.0 m. If Q = 12 C, what is the kinetic energy of particle B at the instant when the particles are 3.0 m apart?
Ans: 4.32J
The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.
How to determine kinetic energy?The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:
U = k × (Q₁ × Q₂) / r
where:
U = potential energy in joules
k = Coulomb's constant (8.988 x 10⁹ N m²/C²)
Q₁ and Q₂ = charges in coulombs
r = distance between the charges in meters
In this case:
U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J
The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:
KE = 1/2 × m × v²
where:
KE = kinetic energy in joules
m = mass in kilograms
v = velocity in meters per second
Solve for the velocity of particle B using the conservation of energy equation:
KE = U
Substituting the expressions for KE and U gives:
1/2 × m × v² = 5.375 x 10⁻⁷ J
Solving for v gives:
v = √(2 × 5.375 x 10⁻⁷ J / m)
= 1.53 m/s
The kinetic energy of particle B is then:
KE = 1/2 × m × v²
= 1/2 × m × (1.53 m/s)²
= 4.32 J
Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.
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One disadvantage to experimental research is that experimental conditions do not always reflect reality.
Please select the best answer from the choices provided
T
F
Answer:
It's true I took the test on Edge.
Explanation:
Answer:
True
Explanation:
Got it right on edg
an election of mass 9.1 × 10^31kg moves with a velocity of 4.2 × 10^7mJs between the cathode and anode of an X-ray tube. Calculate the wavelength.( take Planck's constant, h= 6.6 × 10^ 34 J's)
The wavelength of the electron is 1.724 × 10^-12 m.
How do we calculate?The wavelength of the electron is found using the de Broglie wavelength formula:
λ = h / p
where λ = wavelength,
h= Planck's constant, a
p = momentum of the electron.
we find the momentum of the electron,
p = m * v
p = (9.1 × 10^-31 kg) * (4.2 × 10^7 m/s)
p = 3.822 × 10^-22 kg m/s
Therefore, wavelength ;
λ = h / p
λ = (6.6 × 10^-34 J s) / (3.822 × 10^-22 kg m/s)
λ = 1.724 × 10^-12 m
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The form of energy that can move from place to place across the universe is
Answer:kinetic energy
Explanation:
5.1 5.2 5.3 QUESTION 5 (Start on a new page.) A skier of mass 60 kg skies from rest down a slope inclined at an angle of 15°. The length of the incline is 75 in. He reaches the end of the clined at a velocity of 15 m-s¹. A constant frictional force acts on the skier on his way down. 15:... 75 m Write down an expression for the magnitude of the normal force acting on the skier and then calculate its magnitude. Draw a labelled free-body diagram showing ALL the forces acting on the skier as he skies down the slope. Calculate the average frictional force acting on the skier during his motion down the incline. (2) (3) (7) [12]
The frictional force that is acting on the object is 91N
What is a free body diagram?The normal force can be obtained from the equation mgcosθ. The magnitude of the normal force is;
F = 60 * 9.8 * cos 15
F = 568 N
To obtain the moving force, we must get the acceleration from;
v^2 = u^2 - 2as
Since v = 0
u^2 = 2as
a = u^2/as
a = (15)^2/2 * 75
a = 1.5 m/s^2
Then F = ma
F = 60 * 1.5 = 90 N
The coefficient of friction is 90 N/568N
= 0.16
Frictional force = μmgcosθ
Frictional force = 0.16 * 568
= 91 N
Learn more about frictional force:https://brainly.com/question/30280752
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How does the image make the message in the "Mummy, what happens to us if the bomb drops?" poster more clear?
A. The poster shows a clear picture of a girl having a serious talk with her parents.
B. The poster shows all the supplies needed to survive in picture format.
C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.
D. The poster shows the actual bomb attack.
Answer:
C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.
Explanation:
The girl looks quite worried in the poster. Attached is the image: