You are creating a model showing the distances between colored balls which represent the Earth, the Moon, and the Sun. The Earth is about 240 thousand miles from the Moon and about 93 million miles from the Sun. In your model, represent one million miles with one step. Which of the following statements are correct? Select the two that apply.
A. The ‘Moon’ should be 240 steps away from the ‘Earth’.
B. The ‘Earth’ should be 93 steps away from the ‘Sun’.
C. The ‘Moon’ should be less than one step away from the ‘Earth’.
D. The ‘Earth’ should be 5 steps away from the ‘Sun’.

Given

Object 1

m = 1kg

Object 2

m = 2 kg

Gravitational force

Fg = 1.33 x 10^-10 N

Procedure

Newton's law of universal gravitation is usually stated as that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers

As the distance is tripled the gravitational force would change by a factor of 1/9

Answer:

(a) J = 10560  kg-m/s (b) 251.42 N

Explanation:

Given that,

Mass, m = 4400 kg

Initial speed, u = 5.2 m/s

Final speed, v = 7.6 m/s

Time, t = 42 s

(a) Let J be the impulse exerted on the vehicle. Impuse is equal to the change in momentum such as :

J = m(v-u)

J = 4400 (7.6-5.2)

J = 10560  kg-m/s

(b) Impulse = Force × t

\(F=\dfrac{J}{t}\\\\F=\dfrac{10560}{42}\\F=251.42\ N\)

Hence, this is the required solution.

Answer:

I HOPE THIS IS CORRECT

Explanation:

Power of water =2 kw=2000w

Mass of water =200kg

difference in temperature ΔT=70−10=60oC

Concept

energy required to heat the water = energy given by water in time t=pt

energy required to increase tempeature of water by 60oC,Q=msΔT

S= specific heat =4200J/kgoC

              pt=msΔT

   2000×t=200×4200×60

      t=25200  

or   t=25.2×103sec.

The quantity of heat generated is 720,000 Joules or 720 kiloJoules.

Given the following data:

To find the quantity of heat generated when the electrical coil is used:

Note: the quantity of heat generated is energy.

First of all, we would convert the time in hour to seconds.

Conversion:

1 hour = 3600 seconds

Mathematically, the energy of a device is given by the formula;

\(Energy = power\) × \(time\)

Substituting the values into the formula, we have;

\(Energy = 200\) × \(3600\)

Energy = 720,000 Joules or 720 kiloJoules.

Therefore, the quantity of heat generated is 720,000 Joules or 720 kiloJoules.

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Answer:

The speed stays constant after the force stops pushing.

Explanation:

Speed always stays constant when the force stops pushing it.

The current (in amperes) the frying pan draws from the 500 volt circuit, given that it has a resistance of 25 ohms is 60 amperes

From the question given above, the following data were obtained:

The current drawn by the frying pan can be obtained as follow:

Voltage (V) = Current (I) × resistance (R)

Inputting the given parameters, we have:

1500 = Current × 25

Divide both sides by 25

Current = 1500 / 25

Current = 60 amperes

Thus, from the above calculation we can conclude that the current drawn by the frying pan is 60 amperes

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Answer:

0.667 cm

Explanation:

|F_1on3| = |F_2on3|

k×q1×q3/x^2 = k×q2×q3/(d-x)^2

q1/x^2 = q2/(d-x)^2

(d-x)^2/x^2 = q2/q1

(d-x)/x = sqrt(q2/q1)

(2 - x)/x = sqrt(4×q/q)

(2 - x)/x = 2

2 - x = 2x

2 = 3x

x = 2/3

x= 0.667 cm

Emission current = 0.035 A

This question falls under the topic of thermionic emission.

We are given;

Surface Area; a = 0.157 cm² = 0.157 × 10⁻⁴ m²

Temperature; T = 110 K

Area; A = 100 A/m²/k²

Work function; Φ = 1.04 eV

Formula for emission current density is;

J = AT²\(e^{\frac{b}{T}}\)

where b is a constant = 665Φ

Plugging in the relevant values to get;

J = 100 × 110² × \(e^-{\frac{665 * 1.04}{110}}\)

J = 2250.3886 amp/m²

Formula for emission current is;

Emission Current = J × a

Emission current = 2250.3886 × 0.157 × 10⁻⁴

Emission current = 0.035 A

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Answer:

See explanation

Explanation:

Plankton refers to the small and microscopic organisms drifting or floating in the sea or fresh water, consisting chiefly of diatoms, protozoans, small crustaceans, and the eggs and larval stages of larger animals(Oxford dictionary).

The spring bloom is a sudden growth or increase in plankton abundance. It begins around the early spring and continues until late in the spring or sometimes even early in the summer.

One organism that is a consumer of plankton are the snails. One of the commonest snails that eat plankton are the Nerite Snails.

(1/2)mv^2 = (1/2) * 100 * (2*3)^2 = 1800 [J]

Answer:

Second Option

Explanation:

The "hard drive" or the second option is one of the main components of storing information on a computer. You already have a hard drive built into your computer, or laptop when you buy it, and you can buy additional hard drives in the form of plugins that can store even more data if your original hard drive becomes full of data.

Hope this helps.

Answer:

B

Explanation:

Whereas memory refers to the location of short-term data, storage is the component of your computer that allows you to store and access data on a long-term basis. Usually, storage comes in the form of a solid-state drive or a hard drive.

Answer:

am pretty sure the answer is d

Answer: either 3.20s or 1.18s

Explanation:

Answer:

D

Explanation:

A and C are balanced, B has a resultant force of 5N right, and D has a resultant force of 20N right.

Explanation:

All living organisms metabolize. That is the definition of life. So jr answer is no animal or organism that does not consume food.

The statement that is true about height and strength is that In boys, the strength spurt occurs about a year after their height spurt

Puberty is the transformational change that occur between childhood and adulthood. It is a stage of maturity

Height of a person is the distance from the feet of a person to the peak or his head.

Strength is the ability of a person to be very strong and can do vigorous things.

Therefore, The statement that is true about height and strength is that In boys, the strength spurt occurs about a year after their height spurt.

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The electric field at the y-axis position is -10.0 N/C and is oriented towards the negative charge and electric potential at the point on the y-axis is -0.5 V..

To calculate the electric potential and electric field at the point on the y-axis, use equations for electric potential and electric field due to an electric dipole:

Electric potential V = kq/(r_+) - kq/(r_-)

Electric field E = kq/(r_+)² - kq/(r_-)²

where k = Coulomb constant,

q = charge of each point charge,

r_+ = distance from the positive charge to the point on the y-axis, and

r_- = distance from the negative charge to the same point on the y-axis.

Using the given values:

r_+ = √((0.01 m)² + (0.1 m)²) = 0.1005 m

r_- = √((0.008 m)² + (0.1 m)²) = 0.1002 m

q = 3.0 μC

Electric potential:

V = (9.0 x 10⁹ N·m²/C²)(3.0 x 10⁻⁶ C)/(0.1005 m) - (9.0 x 10⁹ N·m²/C²)(3.0 x 10⁻⁶ C)/(0.1002 m)

V = 215.6 V - 216.1 V

V = -0.5 V

The electric potential at the point on the y-axis is -0.5 V.

Electric field:

E = (9.0 x 10⁹ N·m²/C²)(3.0 x 10⁻⁶ C)/(0.1005 m)² - (9.0 x 10⁹ N·m²/C²)(3.0 x 10⁶ C)/(0.1002 m)²

E = 2705.6 N/C - 2715.6 N/C

E = -10.0 N/C

The electric field at the point on the y-axis is -10.0 N/C, directed towards the negative charge.

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The height of the balloon is 1.3 miles above the ground.

Height is the measure of vertical distance, either how "tall" something or someone is, or how "high" the point is. For example, a person's height is typically measured using a stadiometer and is recorded in centimeters or feet and inches. The height of a mountain is usually measured in meters or feet. In aviation, height is measured from the surface of the earth, either above ground level (AGL) or above mean sea level (AMSL).

The answer to this question can be found by using the trigonometric formula of Tangent. To calculate the height of the balloon, we must find the length of the hypotenuse in the triangle formed by the two towns and the balloonist.

Using the formula for tangent, we can calculate the length of the hypotenuse. The formula is:

tan (angle) = opposite side/adjacent side

In this case, the opposite sides are the two towns, and the adjacent side is the height of the balloon.

For the first town, the formula is:

tan 36° = 1.6/x

Solving for x, we can calculate the length of the hypotenuse for the first town to be 2.8 miles.

For the second town, the formula is:

tan 32° = 1.6/x

Solving for x, we can calculate the length of the hypotenuse for the second town to be 2.9 miles.

Since the hypotenuse is the total distance between the two towns and the balloonist, the height of the balloon can be calculated by subtracting the total length of the two towns (1.6 miles) from the hypotenuse of the second town (2.9 miles).

The height of the balloon is 1.3 miles above the ground.

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Answer:

ke=648J

Explanation:

ke=1/2mv²

m=9kg

v=12m/s

1/2(9)(12)²

=648J

Answer:

e

Explanation:

Option B is correct.Increasing the distance between the particles by a factor of 3 decrease the force between two charged particles by a factor of 9.

The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.

The electric force is found as;

\(\rm F = \frac{K q_1q_2}{r^2}\)

The electric force between the two charges is directly proportional to the product of the charge.

The electric force is inversely proportional to the square of the distance between them.

Increasing the distance between the particles by a factor of 3 decreases the force between two charged particles by a factor of 9

Hence, option B is correct.

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mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.

An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.

De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.

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Answer: C, D, and E are incorrect.

Explanation: You seem to have forgotten to square the spring displacement. 0.5*2340*0.75^2 = 658.125 J. Everything else seems correct :)

The horizontal component of the vector is determined as 6i.

The horizontal component of the vector is calculated as follows;

V = (0 i, 0 j) + (6i, 8j)

V = (6i, 8j)

where;

Thus, the horizontal component of the vector is determined as 6i.

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The volume density of atoms in a simple cubic crystal is 2.92 × 1021 atoms per cubic centimeter.

The lattice constant (a) of a simple cubic (SC) crystal is 0.7 nm. One atom is present at each lattice point. We have to compute the volume density of atoms (i.e. the number of atoms per unit volume) in terms of atoms per cubic centimeter.1 nm = 10-7 cm ⇒ 0.7 nm = 0.7 × 10-7 cm = 7 × 10-8 cm.

Volume of the unit cell of a SC crystal is given byV = a3= (0.7 × 10-7 cm)3= 3.43 × 10-22 cm3The unit cell has one atom, so the volume density of atoms is the same as the number of atoms per unit cell, which is1/ V = 1 / (3.43 × 10-22 cm3)= 2.92 × 1021 atoms per cubic centimeter.= 2.92 × 1023 atoms per cubic meter= 2.92 × 10-4 atoms per cubic angstrom.

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The tension in the swing's chain at the bottom of the swing is 178.35 N.

The given parameters:

The tension in the swing's chain at the bottom of the swing is calculated as follows;

\(T = mg + ma_c\\\\ T= mg + \frac{mv^2}{r} \\\\T = (12 \times 9.8) + (\frac{27 \times 3^2}{4} )\\\\T = 117.6 \ N \ + \ 60.75 \ N\\\\T = 178.35 \ N\)

Thus, the tension in the swing's chain at the bottom of the swing is 178.35 N.

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Answer:

The correct answer is 325.35

Explanation:

Replace the 12 with 27

The distance between two objects of radius 6 cm and 2 cm is zero

To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.

Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.

The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.

Substituting the values, we have d = 6 cm + 2 cm = 8 cm.

Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:

Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.

The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.

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Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

Answer: EASY BROOOOOOOOOOOOOOOOOOOOOOOOO

Take a look inside your heart

Is there any room for me?

I would have to hold my breath

'Til you get down on one knee

Because you only want to hold me

When I'm looking good enough

Did you ever fault me?

Would you ever picture us?

Every time I pull my hair out

Was only out of fear

That'd you find me ugly

And one day you'll disappear

Because what's the point of crying?

It was never even love

Did you ever want me?

Was I ever good enough?

The total distance traveled by the block in a one full or complete cycle is  2A.

option C.

If a block on the end of a spring is pulled to position x = A and released. In one full cycle of its motion, it will travel the following distance as shown below;

x = A cos (ωt)

where;

During a half cycle the block will travel a total distance of A.

During another half cycle the block will travel a total distance of A.

The total distance traveled by the block in a one full or complete cycle is calculated as follows;

distance = A + A

distance = 2A

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