Writing the chemical formula only in its simplest form (empirical formula) helps to represent the relative proportions of atoms in a compound. It is useful for identifying the identity of an unknown compound and for predicting its properties.
How does the empirical formula differ from the molecular formula?The empirical formula represents the simplest whole-number ratio of atoms in a compound, whereas the molecular formula specifies the actual number of each type of atom in a molecule.
The empirical formula is useful for identifying the identity of an unknown compound and for predicting its properties.
Can the empirical formula be used to determine the molecular formula of a compound?Yes, the empirical formula can be used to determine the molecular formula of a compound, but additional information is needed, such as the molar mass of the compound.
Once the molar mass is known, the empirical formula can be used to calculate the molecular formula by determining the number of empirical formula units that would be needed to reach the molar mass.
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To describe the relative proportions of atoms in a compound, the chemical formula should only be written in its simplest form (empirical formula). It is helpful for figuring out a compound's identification and foretelling its properties.
What distinguishes the molecular formula from the empirical formula?The empirical formula defines the precise number of each type of atom in a molecule, whereas the empirical formula represents the simplest whole-number ratio of atoms in a compound.
The empirical formula can be used to determine a compound's identity and forecast its properties.
Can the molecular formula of a substance be determined using the empirical formula?The empirical formula can be used to ascertain the molecular formula of a combination, but other details, such as the compound's molar mass, are required.
The empirical formula can be used to determine the molecular formula once the molar mass is known by counting the number of empirical formula units required to get there.
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Which of the following units are commonly used in chemistry? A Kelvin b ampere c fluid ounce d kilogram
Explanation:
your answer is Kelvin because it is the SI unit of temperature
How many grams are in 4. 5 moles of sodium fluoride naf.
Draw plausible electron dot structures for the following substances. Each substance contains only single covalent bonds. A. I2 B. OF2 C.H2S D.NI3.
The plausible electron dot structures of I₂, OF₂, H₂S, NI₃ substances are attached below.
How is an electron dot structured?Lewis dot structures, also known as electron dot structures, are diagrams that show how atoms in a molecule are chemically bonded to one another. They also show how many lone pairs there are in total among all the atoms that make up the molecule.
An electron configuration writing guide. The shell number (n) comes first in the symbols used to represent the electron configuration, followed by the type of orbital and, finally, a superscript that represents the number of electrons in the orbital. Examples include As you can see from the periodic table, oxygen has 8 electrons.
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How many moles of gas are in a 30 liter scuba canister if the temperature
of the canister is 300 K and the pressure is 200 atmospheres?
Answer: the answer is n= 0.487 mol
Explanation: i took the test and got it right
If a bag of chips cost $4.50 and contains 6 servings, how much are you paying per serving?
Answer:
.75
Explanation:
Answer:
0.75 cents
Explanation:
Calculate the amount of heat (in kJ) that must be absorbed to convert 108 g of ice at 0oC to water at 70oC.
"The amount of heat that must be absorbed to convert 108 g of ice at 0°C to water at 70°C is approximately 68.12 kJ."
To calculate the amount of heat required to convert ice at 0°C to water at 70°C, we need to consider two steps:
Heat required to raise the temperature of ice from 0°C to its melting point (0°C).
Heat required to melt the ice at its melting point (0°C) and raise the temperature of water from 0°C to 70°C.
Let's calculate the heat for each step:
Step 1: Heating ice from 0°C to its melting point (0°C)
The specific heat capacity of ice is 2.09 J/g°C.
Heat = mass × specific heat capacity × change in temperature
Heat = 108 g × 2.09 J/g°C × (0°C - 0°C)
Heat = 0 kJ (No heat is absorbed as there is no change in temperature)
Step 2: Melting ice and heating water from 0°C to 70°C
The enthalpy of fusion (heat of fusion) for ice is 334 J/g, which represents the amount of heat required to melt ice at 0°C.
Heat for melting ice = mass × enthalpy of fusion
Heat for melting ice = 108 g × 334 J/g
Heat for melting ice = 36,072 J
Next, we need to calculate the heat required to raise the temperature of the water from 0°C to 70°C.
The specific heat capacity of water is 4.18 J/g°C.
Heat = mass × specific heat capacity × change in temperature
Heat = 108 g × 4.18 J/g°C × (70°C - 0°C)
Heat = 32,043.6 J = 32.04 kJ
Now, we can sum up the heat required for both steps:
Total heat = Heat for melting ice + Heat for raising water temperature
Total heat = 36,072 J + 32,043.6 J
Total heat = 68,115.6 J = 68.12 kJ
Therefore, the amount of heat that must be absorbed to convert 108 g of ice at 0°C to water at 70°C is approximately 68.12 kJ.
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What is the difference between a divide and a drainage basin?
Answer:
Drainage basin, also called catchment area, or (in North America) watershed, area from which all precipitation flows to a single stream or set of streams. ... The boundary between drainage basins is a drainage divide: all the precipitation on opposite sides of a drainage divide will flow into different drainage basins.
Explanation:
just looked it up
Which salt is the most common found in ocean water?
magnesium
calcium carbonate
potassium
sodium chloride
Answer:
Sodium chloride
Explanation:
There are several salts in seawater, but the most abundant is ordinary table salt or sodium chloride (NaCl). Sodium chloride, like other salts, dissolves in water into its ions, so this is really a question about which ions are present in the greatest concentration. Sodium chloride dissociates into Na+ and Cl- ions.
2. True or false. The body does not digest cellulose.
True
False
A gas in a cylinder with a movable piston occupies 1.38 liters. The piston is moved and the gas now occupies 4.77 liters and exerts a pressure of 803 kPa. Assuming temperature is constant, what was the initial pressure (in atm) of the gas in the cylinder?
The initial pressure of the gas in the cylinder is 31.6 atm.
Gas law problemUsing the combined gas law:
\(P_1V_1/T_1 = P_2V_2/T_2\)
where:
\(P_1\) and \(V_1\) are the initial pressure and volume of the gas\(T_1\) and \(T_2\) are the initial and final temperature\(P_2\) and \(V_2\) are the final pressure and volume of the gasRearranging:
\(P_1 = (P_2V_2/T_2) * (T_1/V_1)\)
We are given that \(V_1\) = 1.38 L, \(V_2\) = 4.77 L, \(P_2\) = 803 kPa, and \(T_1\) = \(T_2\)
\(P_1\) = (803 kPa x 4.77 L / T) x (T / 1.38) / 101.325
\(P_1\) = 31.6 atm
Therefore, the initial pressure of the gas in the cylinder was approximately 31.6 atm.
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Analyzing Chemical Reactions
Student Guide
Assignment Summary
In this assignment, you will predict the products of a chemical reaction and explain why you made this prediction. You will use what you have learned about atoms, bonding, and the organization of the periodic table in your explanation. You will then review and revise your prediction and explanation based on some additional information.
Background Information
Atoms combine with other atoms to form chemical bonds. When atoms bond, electrons can be either shared, donated, or gained. The likelihood that an atom of one element will bond with an atom of another element is related to the number of valence electrons in each atom. For example, elements in Group 1A contain one valence electron, and elements in Group 7A contain seven valence electrons. Elements from these two groups are likely to bond with one another, as the one valence electron from the Group 1A element can be donated to the Group 7A element to complete its outer valence shell.
In general, metals, which have only a few valence electrons, form ionic bonds with nonmetals that have nearly full outer valence shells. In an ionic bond, one or more electrons are donated from the metal element to the nonmetal element. Nonmetals tend to form covalent bonds with other nonmetals by sharing one or more pairs of electrons.
Materials
1–2 sheets of paper
Colored pencils or markers
Assignment Instructions
Step 1: Prepare for the project.
a) Read the entire Student Guide before you begin this project.
b) Gather the materials you will need to complete this project.
Step 2: Predict the products of a chemical reaction.
a) Use your knowledge of atoms, bonding, and the periodic table to complete the chemical equation and predict the products of the chemical reaction on your paper. Label this equation “Initial Prediction.”
CH4 + O2 =
Step 3: Explain your prediction.
a) Write a few paragraphs predicting the products of the chemical reaction and explaining why you made this prediction. Your document should:
i. identify the products of the chemical reaction.
ii. explain why these are the products based on trends in the periodic table (the number of valence electrons, electronegativity, etc.).
iii. identify the types of bonds in the reactants and products.
iv. identify the number of each type of bond in the reactants and products.
v. identify the type of reaction.
b) Label these paragraphs “Initial Explanation.”
Step 4: Create Lewis dot diagrams.
a) Draw Lewis dot diagrams of the reactants and products on the paper with your chemical equation.
b) Select a different color to use for each element in the chemical reaction. Use your chosen color for the element’s symbol and for its valence electrons.
c) Label these diagrams “Lewis Dot Diagrams.”
Step 5: Review and revise your prediction and explanation.
a) First, review your initial prediction and explanation by comparing it to your Lewis dot diagrams. If the results of your Lewis dot diagrams are different from your initial prediction, you will need to revise your prediction and explanation. See Step 5d.
b) Next, review your prediction and explanation to determine whether they adhere to the law of conservation of mass. If they do not, you will need to revise your prediction and explanation so that mass is conserved. See Step 5d.
c) Finally, determine whether your explanation addresses trends in the periodic table and how they can be used to predict outcomes of chemical reactions. If it does not, you will need to revise your explanation to include a discussion of periodic trends and how they help predict the outcomes of chemical reactions. See Step 5d.
d) Write your revised chemical reaction on the same paper as your initial chemical reaction and your Lewis dot diagrams. Label the equation “Revised Prediction.” Write your revised explanation below your initial explanation in the same document. Label it “Revised Explanation.” Be sure that your revised explanation includes all of the information necessary to address Step 3b and
Steps 5a–c.
Answer:
Explanation:
Answer :
Reaction 1 : Add Zinc to Copper Sulfate.
Observations of Reactants : Zinc is in solid state and copper sulfate in aqueous state.
Predicted Type(s) of Reaction : Single-displacement reaction
Observations of Products : Copper is in solid state and zinc sulfate in aqueous state.
The balanced chemical reaction :
Types of reaction : Single-displacement reaction : It is a type of reaction in which a single element displaces another element in a compound.
Reaction 2 : Mix Potassium Iodide and Lead (II) Nitrate.
Observations of Reactants : Potassium iodide is in solid state and lead nitrate in aqueous state.
Predicted Type(s) of Reaction : Double-displacement reaction
Observations of Products : Lead iodide is in solid state and potassium nitrate in aqueous state.
The balanced chemical reaction :
Types of reaction : Double-displacement reaction : It is a type of reaction in which two reactants exchange their ions to form two new compounds.
Reaction 3 : Burn Copper Wire.
Observations of Reactants : Copper is in solid state and oxygen in gas state.
Predicted Type(s) of Reaction : Oxidation reaction
Observations of Products : Copper oxide is in solid state.
The balanced chemical reaction :
Types of reaction : Oxidation reaction : In a oxidation reaction, a substance gains oxygen.
Reaction 4 : Heat Sodium Carbonate.
Observations of Reactants : Sodium carbonate is in solid state.
Predicted Type(s) of Reaction : Thermal decomposition reaction
Observations of Products : Sodium oxide is in solid state and carbon dioxide in gas state.
The balanced chemical reaction :
Types of reaction : Thermal decomposition reaction : It is defined as the breaking down of a chemical compound due to heating.
Reaction 1: Single-displacement reaction.
Reaction 2: Double-displacement reaction.
Reaction 3: Oxidation reaction.
Reaction 4: Thermal decomposition reaction.
What is a chemical equation?A representation of a chemical reaction using symbols of the elements to indicate the amount of substance, usually in moles, of each reactant and product.
Reaction 1: Add Zinc to Copper Sulfate.
Observations of Reactants: Zinc is in a solid state and copper sulfate is in an aqueous state.
Predicted Type(s) of Reaction : Single-displacement reaction
Observations of Products: Copper is in a solid state and zinc sulfate is in an aqueous state.
The balanced chemical reaction :
Types of reaction: Single-displacement reaction.
It is a type of reaction in which a single element displaces another element in a compound.
Reaction 2: Mix Potassium Iodide and Lead (II) Nitrate.
Observations of Reactants: Potassium iodide is in a solid state and lead nitrate is in an aqueous state.
Predicted Type(s) of Reaction : Double-displacement reaction
Observations of Products: Lead iodide is in a solid state and potassium nitrate is in an aqueous state.
The balanced chemical reaction :
Types of reaction: Double-displacement reaction
It is a type of reaction in which two reactants exchange their ions to form two new compounds.
Reaction 3: Burn Copper Wire.
Observations of Reactants: Copper is in a solid state and oxygen is in the gas state.
Predicted Type(s) of Reaction : Oxidation reaction
Observations of Products: Copper oxide is in the solid state.
The balanced chemical reaction :
Types of reaction: Oxidation reaction
In an oxidation reaction, a substance gains oxygen.
Reaction 4: Heat Sodium Carbonate.
Observations of Reactants: Sodium carbonate is in a solid state.
Predicted Type(s) of Reaction : Thermal decomposition reaction
Observations of Products: Sodium oxide is in a solid state and carbon dioxide is in a gas state.
The balanced chemical reaction :
Types of reaction: Thermal decomposition reaction
It is defined as the breaking down of a chemical compound due to heating.
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Determine the total energy needed to change 25 grams of 75 degree water to 125 degree water vapor.
The total energy needed to change 25 grams of water at 75 degrees to water vapor at 125 degrees is 60333.75 J
How do i determine the total energy required?
First, we shall determine the heat needed to change the water from 75 °C to 100°C. Details below:o
Mass of water (M) = 25 gInitial temperature of water (T₁) = 75 °CFinal temperature of water (T₂) = 100 °CChange in temperature of water (ΔT) = 100 - 75 = 55 °CSpecific heat capacity of water (C) = 4.184 J/gºC Heat (H₁) =?H₁ = MCΔT
H₁ = 25 × 4.184 × 25
H₁ = 2615 J
Next, we shall determine the heat needed to vaporize the water. Details below:
Mass of water (M) = 25 g Heat of Vaporization (ΔHv) = 2259 J/gHeat (H₂) =?H₂ = m × ΔHv
H₂ = 25 × 2259
H₂ = 56475 J
Next, we shall determine the heat needed to change the steam from 100 °C to 125°C. Details below:
Mass of steam (M) = 25 gInitial temperature of steam (T₁) = 100 °CFinal temperature of steam (T₂) = 125 °CChange in temperature of steam (ΔT) = 125 - 100 = 25 °CSpecific heat capacity of steam (C) = 1.99 J/gºC Heat (H₃) =?H₃ = MCΔT
H₃ = 25 × 1.99 × 25
H₃ = 1243.75 J
Finally, we shall determine the total heat needed to change the water from 75 °C to 120°C. Details below:
Heat required to change the water from 75 °C to 100°C (H₁) = 2615 JHeat required to vaporize the water (H₂) = 56475 JHeat required to change the steam from 100 °C to 125°C (H₃) = 1243.75 JTotal heat needed (Q) =?Q = H₁ + H₂ + H₃
Q = 2615 + 56475 + 1243.75
Total heat needed = 60333.75 J
Thus, we scan conclude that the total heat needed is 60333.75 J
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In chemical reactions, what does the principle of conservation of mass mean?
Which of the following ions could exist in either the high-spin or low-spin state in an octahedral complex?
A. Sc3+
B. Ni2+
C. Mn2+
D. Ti4+
E. Zn2+
Ni²⁺ is the only ion on the list that can exist as both a high-spin and a low-spin octahedral complex. The correct option is B.
An electrostatic model called the crystal field theory (CFT) assumes that the metal-ligand connection is ionic and results only from electrostatic interactions between the metal ion and the ligand. When dealing with anions, ligands are viewed as point charges, and when dealing with neutral molecules, as dipoles.
The crystal field splitting theory predicts that some transition metal ions can exist as either high-spin or low-spin octahedral complexes, depending on the magnitude of the crystal field splitting parameter (Δ) relative to the pairing energy (P).
Of the ions listed, the only one that could exist as either a high-spin or a low-spin octahedral complex is Ni²⁺ (B).
Mn²⁺ (A) is a d⁵ ion and will always form a high-spin octahedral complex due to its large number of unpaired electrons.
Sc³⁺ (C) is a d⁰ ion and does not form octahedral complexes with ligands.
Cu²⁺ (D) is a d⁹ ion and typically forms a low-spin octahedral complex due to the stability of the half-filled d⁹ configuration.
Zn²⁺ (E) is a d¹⁰ ion and does not have any unpaired electrons to undergo spin pairing, so it will always form a low-spin octahedral complex.
Therefore, the correct answer is B) Ni²⁺.
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what is the bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals?
The bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5
Bond order is defined as the number of electrons in bonding molecular orbitals minus the number of electrons in antibonding molecular orbitals divided by two. As a result, we may determine the bond order of this diatomic particle by the formula: Bond order = (number of bonding electrons - number of antibonding electrons) / 2
Bond order = (8 - 5) / 2
Bond order = 1.5.
This diatomic molecule, according to the bond order, is a stable molecule since the bond order is greater than 1, indicating that it is a double bond. The molecule has an overall bond strength that is greater than a single bond, but not as strong as a triple bond. So therefore he bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5
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fill in the blank the amount of water vapor in the atmosphere is measured as blank ____ , whereas blank ___is the ratio of the amount of water vapor to the maximum amount of water vapor that can be held by an air mass.
The amount of water vapor in the atmosphere is measured as absolute humidity, whereas relative humidity is the ratio of the amount of water vapor to the maximum amount of water vapor that can be held by an air mass.
What is the unit used to measure the amount of water vapor in the atmosphere?The amount of water vapor in the atmosphere is measured as specific humidity, whereas relative humidity is the ratio of the amount of water vapor to the maximum amount of water vapor that can be held by an air mass.
Therefore, the unit used to measure specific humidity is grams of water vapor per kilogram of air (g/kg), while the unit used to measure relative humidity is a percentage (%).
Specific humidity is an absolute measure of the amount of water vapor present in the air, while relative humidity is a relative measure that compares the actual amount of water vapor to the maximum amount that can be held at a given temperature.
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what is a spectorscope?
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Study of the absorption and emission of light and other radiation by matter, as related to the dependence of these processes on the wavelength of the radiation.
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Which of the following do not contribute to weathering?
A. Rain
2.earthquakes
3. ice
4. wind
Answer:
Earthquakes
Explanation:
a 25.0 ml sample of a saturated c a ( o h ) 2 ca(oh)x2 solution is titrated with 0.023 m h c l hcl , and the equivalence point is reached after 38.0 ml of titrant are dispensed. based on this data, what is the concentration (m) of the hydroxide ion? type answer:
The concentration of hydroxide ion is 0.0035 M when a 25.0 ml sample of a saturated Ca(OH)₂ solution is titrated with 0.023 m HCl , and the equivalence point is reached after 38.0 ml of titrant are dispensed.
Concentration of hydroxide ion can be calculate as follow:
First we should determine The concentration of the Ca(OH)₂ by write the balanced chemical equation for the reaction
2 HCl + Ca(OH)₂ ⇒ CaCl₂ +2H₂O
This means,
2 moles of HCl are required to neutralized 1 mole Ca(OH)2 completely
so we can use this formula:
\(\frac{C_A V_A}{C_B V_B} = \frac{n_A}{n_B}\)
Substituting the value we get from question into the formula, we get:
\(\frac{0.023 X38}{C_B X 25} = \frac{2}{1}\)
so,
\(C_B X 50 - 0.23 X 8\\C_B = \frac{0.23 x 38}{50} \\C_B = \frac{0.874}{50}\\ C_B = 0.0175 M\)
The concentration of Ca(OH)₂ solution is 0.0175 M.
To calculate the concentration of hydroxide ion we should write the balanced chemical equation for the ionize reaction
Ca(OH)₂⇒ Ca²⁺ +2OH⁻
with coefficient comparison we got
[OH] = 2 x 0.0175 M
[OH] = 0.035 M
Hence, the concentration of the hydroxide ion is 0.035 M
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Choose the answers below that are functions of the Embden-Meyerhof, Entner-Doudoroff, and pentose phosphate pathways.
a. Production of NADH
b. Catabolize glucose to pyruvate
c. Production of ATP
d. Production of precursor metabolites
a. Production of NADH: Embden-Meyerhof pathway and Entner-Doudoroff pathway.
b. Catabolize glucose to pyruvate: Embden-Meyerhof pathway and Entner-Doudoroff pathway.
c. Production of ATP: Embden-Meyerhof pathway.
d. Production of precursor metabolites: Pentose phosphate pathway.
The Embden-Meyerhof pathway (glycolysis) and the Entner-Doudoroff pathway are both involved in the catabolism of glucose to pyruvate. They convert glucose into pyruvate through a series of enzymatic reactions, generating energy and producing NADH as a byproduct. The NADH molecules can then participate in further energy production processes.
The Embden-Meyerhof pathway also plays a major role in ATP production. Through substrate-level phosphorylation, it generates ATP directly from the breakdown of glucose. This pathway is especially important in anaerobic conditions when oxygen is not available as an electron acceptor in cellular respiration.
On the other hand, the pentose phosphate pathway is primarily responsible for the production of precursor metabolites, such as ribose-5-phosphate and erythrose-4-phosphate. These metabolites serve as building blocks for the synthesis of nucleotides, amino acids, and other essential cellular components.
Overall, the Embden-Meyerhof pathway and the Entner-Doudoroff pathway are involved in glucose catabolism and NADH production, while the Embden-Meyerhof pathway is responsible for ATP production. The pentose phosphate pathway, on the other hand, produces precursor metabolites needed for biosynthetic processes in the cell.
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how many moles of na2s2o3 are needed to dissolve 0.35 mol of agbr in a 1.0 l solution if ksp for agbr is 3.3×10−13 and kf for the complex ion [ag(s2o3)2]3− is 4.7×1013?
There are 4.48 × 10-3 moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution if Ksp for AgBr is 3.3 × 10-13 and Kf for the complex ion \([Ag(S_{2}O_{3})_{2}]^{3-}\).
AgBr dissociates in water, and we can write the reaction as shown below:
\(AgBr = Ag^{+} + Br{-}\)
Since \(Ksp = [Ag^{+}][Br^{-}]\), we can obtain the equilibrium concentrations of \(Ag^{+}\) and \(Br^{-}\) from the Ksp value, using the stoichiometry of the balanced equation. Here, the concentration of \(Br^{-}\) is equal to that of \(Ag^{+}\).
Therefore, \(Ag^{+}\) = \(Br^{-}\) = √Ksp = √3.3 × 10-13 M\(\sqrt{Ksp} = \sqrt{3.3 * 10^{-13}} M\) \(5.74 * 10^{-7}\) M. To determine the number of moles of \(Na_{2}S_{2}O_{3}\) required to dissolve 0.35 mol of AgBr in a 1.0 L solution, we must calculate the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) ion first.
Kf = \([Ag(S_{2}O_{3})_{2}]^{3-}\)./(\(Ag^{+}\)\([S_{2}O_{3}^{-2}]\))
For \(Ag^{+}\), we use the concentration obtained from Ksp:
\(Ag^{+}\)= \(5.74 * 10^{-7}\) M
Kf = \(4.7 * 10^{13}\) mol-1L-3
\([Ag(S_{2}O_{3})_{2}]^{3-}\)= Kf × \([Ag(S_{2}O_{3})_{2}]^{3-}\)
= \(Ag^{+}\)/Kf
\([Ag(S_{2}O_{3})_{2}]^{3-}\)
= (\(5.74 * 10^{-7}\) M)/(\(4.7 * 10^{13}\) mol-1L-3 × (\(5.74 * 10^{-7}\) M)2)
= \(4.48 * 10^{-3}\) M
To find the number of moles of \(Na_{2}S_{2}O_{3}\) required to dissolve AgBr in 1 L of solution, multiply the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) by the volume of the solution:
\(4.48 * 10^{-3}\) M × 1 L = \(4.48 * 10^{-3}\) moles \(Na_{2}S_{2}O_{3}\).
\(4.48 * 10^{-3}\) moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution.
We used the stoichiometry of the balanced equation and the Ksp value to determine the concentration of [Ag+] and [Br-]. Then, we calculated the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\). from the Kf value and the [Ag+] value obtained from Ksp.
Finally, we multiplied the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) by the volume of the solution to obtain the number of moles of \(Na_{2}S_{2}O_{3}\) needed to dissolve 0.35 mol of AgBr in a 1.0 L solution.
4.48 × 10-3 moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution if Ksp for AgBr is \(3.3 * 10^{-13}\) and Kf for the complex ion \([Ag(S_{2}O_{3})_{2}]^{3-}\) is \(4.7 * 10^{13}\) mol-1L-3.
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A 2.65 g sample of a salmon colored powder contains 0.70 g of chromium, 0.65 g of sulfur, and 1.30 g of oxygen. The molar mass is 392.2. What is the formula of the compound
The molecular formula of the compound is \(Cr_{2}S_{3}O_{12}\).
Given:Mass of Cr = 0.70 g
Mass of S = 0.65 g
Mass of O = 1.30 g
Molecular mass = 392.2 g
Moles of Cr = \(\frac{0.70}{52.0}\)
= 0.01346 mol
Moles of S = \(\frac{0.65}{32.06}\)
= 0.02025 mol
Moles of O = \(\frac{1.30}{16.0}\)
= 0.08125 mol
Dividing both sides with lower quantity ;
\(Cr_{\frac{0.01346}{0.01346} } S_{\frac{0.2025}{0.01346} } O _{\frac{0.08125}{0.01346} }\)≅ \(CS_{1.5} O_{6}\)
And \((empirical formula )_{n} = molecular formula\)
392.2 = n (52.0 + 6 × 16.0)
n = 2
Therefore, the molecular formula of the compound is \(Cr_{2}S_{3}O_{12}\).
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which of the following can serve as a good source of zn for the body? (you want a water soluble salt. ingestion of zn ions has been shown to have some effect in reducing the length of a cold).
Zinc sulfate (ZnSO4) can serve as a good source of zinc for the body. It is a water-soluble salt that can provide zinc ions for absorption in the gastrointestinal tract.
Ingesting zinc ions has been shown to have some effect in reducing the length of a cold. Therefore, zinc sulfate can be an effective option for boosting zinc levels in the body and potentially supporting immune function during a cold.
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at what temperature will the mass of 198g of carbon dioxide gas at 2 atmospheric pressure take up to a volume of 35l? (gas constant= 0.0821L atm.
Answer:
The temperature will be 189.70 K.
Explanation:
Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P*V = n*R*T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.
In this case:
P= 2 atmV= 35 Ln= 198 g* \(\frac{1 mole}{44 g}\) = 4.5 moles (where 44 g/mole is the molar mass of carbon dioxide)R= 0.082 \(\frac{atm*L}{mol*K}\)T= ?Replacing:
2 atm* 35 L= 4.5 moles* 0.082 \(\frac{atm*L}{mol*K}\) * T
Solving:
\(T=\frac{2 atm* 35 L}{4.5 moles* 0.082\frac{atm*L}{mol*K} }\)
T= 189.70 K
The temperature will be 189.70 K.
The molar heat capacity of tungsten is 24.2 J/K•mol. Calculate the energy as heat needed to increase the temperature of 0.40 mol of tungsten by 10.0 K.
The energy as heat needed to increase the temperature of 0.40 mol of tungsten by 10.0 K is 96.8J.
How to calculate energy?The energy of a substance can be calculated using the following formula;
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = massc = molar heat capacity ∆T = change in temperatureAccording to this question, the molar heat capacity of tungsten is 24.2 J/K•mol. The energy as heat needed to increase the temperature of 0.40 mol of tungsten by 10.0 K is as follows:
Q = 0.40 × 24.2 × 10
Q = 96.8J
Therefore, 96.8J is the energy of the tungsten metal.
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How many molecules does 1 mole of O2 gas have?
A. 3.01 x 1023 molecules
B. 12.04 x 1023 molecules
C. 15.99 x 1023 molecules
D. 6.02 x 1023 molecules
SUBMIT
Answer:
d.6.02×1023 molcules
Answer:
D
Explanation:
6.02 x 1023 molecules
The chemical equation below shows the decomposition of nitrogen triiodide (NI3) into nitrogen (N2) and iodine (I2). 2NI3 Right arrow. N2 3I2 The molar mass of NI3 is 394. 71 g/mol. How many moles of I2 will form 3. 58 g of NI3? 0. 00907 moles 0. 00940 moles 0. 0136 moles 0. 0212 moles.
The moles of I₂ will form from the decomposition of 3.58g of NI₃ is 0.0136 moles.
How we calculate moles?Moles of any substance will be calculated as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is:
2NI₃ → N₂ + 3I₂
Moles of 3.58g of NI₃ will be calculated as:
n = 3.58g / 394. 71 g/mol = 0.009 moles
From the stoichiometry of the solution, it is clear that:
2 moles of NI₃ = produce 3 moles of I₂
0.009 moles of NI₃ = produce 3/2×0.009=0.0136 moles of I₂
Hence, option (3) is correct i.e. 0.0136 moles.
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What is the answers?
the numbers are going to be small so like a power but its at the bottom
NH3, H2O2, NHO2
Is an electronegativity difference of 0. 4 polar or nonpolar?.
A bond is considered nonpolar if the electronegativity difference is less than about 0.4.
A bond is considered polar if the electronegativity difference of the atoms in the bond is greater than 0.4. If the electronegativity difference is less than 0.4, the bond is essentially nonpolar. If there are no polar bonds, the molecule is non-polar. To determine whether a molecule is polar or nonpolar, it is often useful to look at the Lewis structure.
Nonpolar compounds are symmetrical. That is all sides around the central atom are identical. That is, they have no unshared pair of electrons and are bonded to the same element. Bonds with an electronegativity difference between atoms of 0.5 to 2.1 are called polar covalent bonds. A polar covalent bond is a covalent bond whose shares are unequal because atoms have unequal attractive forces on electrons.
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How many grams are in 1,000 Lutheran of C2H4
Answer:
28.05316 grams
Explanation: