Which type of scientist would observe the spread of a species of red fire ants

The percent yield of \(Fe_2O_3\)  if 57.8g was collected is 75.1%.

To calculate the percent yield, we need to compare the actual yield (the amount of\(Fe_2O_3\) collected) to the theoretical yield (the amount of \(Fe_2O_3\)that would be obtained if the reaction went to completion).

First, we need to determine the molar mass of \(Fe_2O_3\) and \(Fe_2S_3\):

Molar mass of \(Fe_2O_3\):

2(55.85 g/mol) + 3(16.00 g/mol) = 159.69 g/mol

Molar mass of\(Fe_2S_3\):

2(55.85 g/mol) + 3(32.07 g/mol) = 207.67 g/mol

Next, we can calculate the theoretical yield of\(Fe_2O_3\) using stoichiometry:

2 moles of \(Fe_2S_3\) produce 2 moles of \(Fe_2O_3\)(according to the balanced equation).

So, the molar ratio of \(Fe_2O_3\)to Fe2S3 is 2:2.

The molar mass ratio of \(Fe_2O_3\) to Fe2S3 is:

159.69 g/mol : 207.67 g/mol

To calculate the theoretical yield, we can use the following equation:

Theoretical yield of\(Fe_2O_3\) = (mass of \(Fe_2S_3\)) * (molar mass of \(Fe_2O_3\) / molar mass of \(Fe_2S_3\))

Theoretical yield of \(Fe_2O_3\) = (100.0 g) * (159.69 g/mol / 207.67 g/mol)

Theoretical yield of \(Fe_2O_3\) = 76.46 g

Now we can calculate the percent yield using the formula:

Percent yield = (actual yield / theoretical yield) * 100

Percent yield = (57.8 g / 76.46 g) * 100

Percent yield = 75.1%

Therefore, the percent yield of \(Fe_2O_3\) is 75.1%.

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Answer: \(K_a\) for the acid is \(2.7\times 10^{-4}\)

Explanation:

\(C_9H_7O_4H\rightarrow H^+C_9H_7O_4^-\)

   c             0             0

\(c-c\alpha\)        \(c\alpha\)          \(c\alpha\)  

So dissociation constant will be:

\(K_a=\frac{(c\alpha)^{2}}{c-c\alpha}\)

Give c= 0.313 M and \(pH\) = 2.031

\((\alpha)=0.030\)

\([H^+]=c\times \alpha\)

\([H^+]=0.500\times 0.030=0.015\)

Also \(pH=-log[H^+]\)

\(2.031=-log[H^+]\)

\([H^+]=0.009\)

[ \([H^+]=c\alpha\)  

\(c\alpha=0.009\)

Putting in the values we get:

\(K_a=\frac{(0.009)^2}{(0.313-0.009)}\)

\(K_a=\frac{(0.009)^2}{(0.304)}=2.7\times 10^{-4}\)

\(K_a\) for the acid is \(2.7\times 10^{-4}\)

Answer:

What are the compounds

Explanation:

Answer:

Where is the picture?

Explanation:

Answer:

B.K2(OH)2 i think that is the answer

The correct equation that has been balanced is option (c): ZnS + 02 -> 2ZnO + SO2. This equation is balanced because the number of sulfur atoms (1 on each side) and the number of oxygen atoms (2 on each side) are equal.

The correct equation that has been balanced is option (c): ZnS + 02 -> 2ZnO + SO2. To determine whether an equation is balanced, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's analyze each option:

(a) 2ZnS + 302 -> 2ZnO + 2SO2: This equation is unbalanced because there are an unbalanced number of oxygen atoms (7 on the left side and 4 on the right side) compared to the amount of sulphur atoms (2 on each side).

(b) ZnS + 02 --> ZnO + SO2: This equation is unbalanced because there are an unbalanced number of oxygen atoms (2 on the left side and 3 on the right side) compared to the sulphur atoms (1 on each side).

(c) ZnS + 02 -> 2ZnO + SO2: This equation is balanced because the number of sulfur atoms (1 on each side) and the number of oxygen atoms (2 on each side) are equal. Therefore, option (c) is the only equation that has been balanced correctly.

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Answer:

protons

These particles do not vary in quality from one element to another; rather, what gives an element its distinctive identification is the quantity of its protons, called its atomic number. Protons and neutrons contribute nearly all of an atom's mass; the number of protons and neutrons is an element's mass number

Explanation:

Answer:

If n = 4, then the possible values of 1 and m depend on the equation or expression being used. Without more information, it is impossible to determine what the possible values of 1 and m might be. Can you please provide more context or information about the problem you are trying to solve?

For Test One, phenotype ratio is Short fur : Long fur = 2 : 0; For Test Two, the phenotype ratio is Short fur : Long fur = 3 : 1; For Test Three, the phenotype ratios will be Short fur : Long fur = 0 : 2

For Test One:

Parent 1: FF (homozygous dominant for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff = 1 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 2 : 0 or 100% short fur

For Test Two:

Parent 1: Ff (heterozygous for short fur)

Parent 2: Ff (heterozygous for short fur)

The Punnett square for this cross will give the following genotype ratios:

FF : Ff : ff = 1 : 2 : 1

And the corresponding phenotype ratios will be:

Short fur : Long fur = 3 : 1 or 75% short fur and 25% long fur

For Test Three:

Parent 1: ff (homozygous recessive for long fur)

Parent 2: ff (homozygous recessive for long fur)

The Punnett square for this cross will give the following genotype ratios:

ff : ff = 1 : 0

And the corresponding phenotype ratios will be:

Short fur : Long fur = 0 : 2 or 100% long fur

For this investigation, the test variable is the breed of hamster and the outcome variable is the phenotype of the hamster.

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• The engineers uses ,Hydrogen-fueled engines ,, that uses ,ammonia as the carrier ,or as the as a propellent .

• Ammonia constitutes of a ,large hydrogen weight ,, this helps in providing a ,source of hydrogen for fuel cells,.

The number of atoms :

C = 6 x 5 x 10²¹ = 3 x 10²²

H = 12 x 5 x 10²¹ = 6 x 10²²

O =  6 x 5 x 10²¹ = 3 x 10²²

Given

1.5 g glucose(C₆H₁₂O₆)

Required

The number of atoms

Solution

mol of glucose(MW=6.12+12.1+6.16=180 g/mol) :

mol = mass : MW

mol = 1.5 : 180

mol = 0.0083

Number of molecules = 0.0083 x 6.02 x 10²³ = 5 x 10²¹

There are 6 C, 12 H and 6 O, so number or atoms :

C = 6 x 5 x 10²¹ = 3 x 10²²

H = 12 x 5 x 10²¹ = 6 x 10²²

O =  6 x 5 x 10²¹ = 3 x 10²²

Diatomic: Composed of two atoms. Polar: A bond with a negative end and a positive end. Nonpolar: A bond in which neither atom takes more than its share of electrons. Metallic: A type of bond that allows valence electrons to move freely among ions. Electronegativity: Determines what type of bond will form.

The ability of an atom or functional group to draw electrons to itself is known as electronegativity in chemistry.

Diatomic molecules consist only of two atoms, whether they are from the same or distinct chemical elements.

Since charges fluctuate, a momentary dipole moment occurs in a so-called nonpolar molecule at any given time if the charge arrangement is spherically symmetric when averaged across time.

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Answer:

apply chemical models to demonstrate the organization of the elements in the periodic table

Explanation:

Answer:

The first thing you will need to do is find some information about your element. Go to the Periodic Table of Elements and click on your element. If it makes things easier, you can select your element from an alphabetical listing.

Number of Protons = Atomic Number

Number of Electrons = Number of Protons = Atomic Number

Number of Neutrons = Mass Number - Atomic Number

For krypton:

Number of Protons = Atomic Number = 36

Number of Electrons = Number of Protons = Atomic Number = 36

Number of Neutrons = Mass Number - Atomic Number = 84 - 36 = 48

Explanation:

hope this helps, have a good day :-)

Answer:

Five general properties of organic  compounds:

Answer: The amount of matter in a particle or object.

Answer:

cotton

Explanation:

which is typically spun into fine yarn for mechanical weaving or knitting into cloth.

Answer:

Explanation:

I hope it helps you.

Answer: potential energy is stored

Explanation:

Answer:

D

Explanation:

the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of an object

Answer:

gahwidsuacsgsuacayau1joagavahiq8wtw8quavakiafabajozyavqhaigavayquata

Explanation:

vahaiqgahiavavqugafayqigqvsbjsiagwyeiwvvs

Answer:

0.359 L or 359 mL of O2 gas will be produced from the given reaction at STP

Explanation:

The balanced chemical equation for the decomposition of KNO3 is:

2 KNO3 (s) → 2 KNO2 (s) + O2 (g)

From this equation, we can see that 2 moles of KNO3 produce 1 mole of O2. Therefore, we need to calculate the number of moles of KNO3 we have and use the mole ratio to find the number of moles of O2 produced.

First, we need to convert the mass of KNO3 given to moles:

moles of KNO3 = mass of KNO3 / molar mass of KNO3

The molar mass of KNO3 is 101.1 g/mol (39.1 g/mol for K, 14.0 g/mol for N, and 3 x 16.0 g/mol for 3 O atoms), so we have:

moles of KNO3 = 3.25 g / 101.1 g/mol = 0.0321 mol

Now we can use the mole ratio from the balanced equation to find the number of moles of O2 produced:

moles of O2 = 0.5 x moles of KNO3

moles of O2 = 0.5 x 0.0321 mol = 0.01605 mol

Finally, we can convert the number of moles of O2 to volume at STP using the ideal gas law:

V(O2) = n x RT/P = (0.01605 mol)(0.0821 L·atm/(mol·K) x 273.15 K)/(1 atm) = 0.359 L

Therefore, 0.359 L or 359 mL of O2 gas will be produced from the given reaction at STP.

Answer: 4 1/6

Explanation: 3/5x1 1/9=2/3. 2/3+3 1/2=4 1/6.

Answer:

Explanation:

i wish i can help

Answer:

Explanation:

Combined Gas Law

T2= T1P2V2/ (P1V1) = 348.15 X .5 X 3.4/(2 X 7.5) =39.46 K or -233.69C

Answer: The mass in grams of sodium carbonate is 34.3 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

\(Molarity=\frac{n\times 1000}{V_s}\)

where,

n = moles of solute

\(V_s\) = volume of solution in ml

moles of \(Na_2CO_3\) = \(\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{106g/mol}\)

Now put all the given values in the formula of molarity, we get

\(1.27=\frac{xg\times 1000}{106g/mol\times 255.0 ml}\)

\(x=34.3g\)

Therefore, the mass in grams of sodium carbonate is 34.3 g

Answer:

Kk I got it now but I think it to be great

Answer:

arctic glacier

Explanation:

Answer:

Explanation:

are there any choices to choose from?

if not a glacier is a type of frozen water compacted together...

if it   doesnt have choices ill word it differently...

can u also tell me what is your unit about?

The balanced chemical equation for the reaction between Fe2+ and Na3PO4 is:

\(3Fe2+ + 2Na3PO4\) → \(Fe3(PO4)2 + 6Na+\)

First, we need to determine the chemical formula of the products based on the charges of the reactants. Fe2+ has a charge of +2, while PO43- has a charge of -3. To balance the charges, we need two Fe2+ ions for every three PO43- ions. This gives us the formula Fe3(PO4)2 for the product.

Next, we need to balance the equation by making sure that the same number of atoms of each element are present on both sides of the equation. To do this, we can start by balancing the phosphorus atoms. There are two phosphorus atoms on the left side (2x PO43-), so we need two Fe3(PO4)2 molecules on the right side to balance this. This gives us:

3Fe2+ + 2Na3PO4 → 2Fe3(PO4)2 + ?

Next, we can balance the sodium atoms by adding six Na+ ions to the right side:

3Fe2+ + 2Na3PO4 → 2Fe3(PO4)2 + 6Na+

Finally, we can check that the equation is balanced by counting the number of atoms of each element on both sides of the equation. The equation is now balanced with respect to the number of atoms of Fe, P, Na, and O.

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The calculate the age of the rock sample values, the age of the rock sample can be determined.

we can use the concept of radioactive decay and the ratio of 87Sr to 87Rb. Since 87Sr is a stable product of the beta decay of 87Rb, the increase in the ratio of 87Sr to 87Rb over time reflects the decay of 87Rb.

The ratio of 87Sr to 87Rb in ancient samples is given as 0.0205. This means that for every 0.0205 moles of 87Rb, there is one mole of 87Sr.

Since the half-life of 87Rb is 4.75×10^10 years, after each half-life, half of the 87Rb would have decayed into 87Sr. Therefore, the ratio of 87Sr to 87Rb increases by a factor of 2.

To determine the age of the rock sample, we can calculate the number of half-lives that have occurred based on the change in the ratio. The ratio of 0.0205 corresponds to 1 half-life, 0.041 corresponds to 2 half-lives, 0.082 corresponds to 3 half-lives, and so on.

By taking the logarithm of the ratio change and dividing it by the logarithm of 2 (since the ratio doubles with each half-life), we can find the number of half-lives.

Using this information, the age of the rock sample can be calculated as follows:

Age (in years) = number of half-lives × half-life of 87Rb

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