Answer: D
Explanation:
As the volume of a gas increases, its pressure
(Assume all other factors are held constant).
if hydrogen is the most common element in the universe, why do we not see the lines of hydrogen in the spectra of the hottest stars?
The reason we do not see the lines of hydrogen in the spectra of the hottest stars is due to the ionization of hydrogen atoms at high temperatures.
In these stars, the temperatures are so high that the electrons in the hydrogen atoms are stripped away, leaving behind only the protons. This ionized hydrogen does not produce the same spectral lines as neutral hydrogen, which is what we typically observe in cooler stars. Instead, the spectra of hot stars are dominated by lines from ionized metals, such as helium, carbon, and oxygen. So while hydrogen is indeed the most common element in the universe, its presence in the spectra of hot stars is not as prominent due to ionization.
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If a lightning occurred exactly 1 mile from your location, how many seconds will it take for the sound waves created by the thunder to reach your ears at 343 m/s?
Answer:
5 seconds
Explanation:
sound travels 1 km in roughly 3 secs so 1 mile in roughly 5 secs.
A uniform lead sphere and a uniform aluminum sphere have the same mass. What is the ratio of the radius of the aluminum sphere to the radius of the lead sphere?
The ratio of the radius of the aluminum sphere to the radius of the lead sphere can be represented as:
\(\displaystyle \frac{r_{Al}}{r_{Pb}} =\sqrt[3]{\frac{\rho_{Pb}}{\rho_{Al}} }\)
What is the density?The density of a material can be measured as the mass per unit volume of the material. The average density equals the mass divided by its total volume.
The mathematical formula for the density can be expressed as follows:
Density = Mass/Volume
The S.I. unit of the density that is used to measure is Kg/m³. If the size increases, the mass increases as well but the density remains constant.
Given the mass of the Al = mass pf the Pb
The ratio density of the Al and Pb can be represented as:
\(\displaystyle \frac{\rho_{Al}}{\rho_{Pb}} } = \frac{m/4\pi r_{Al}^3}{m/4\pi r_{Pb}^3}\)
\(\displaystyle \frac{\rho_{Al}}{\rho_{Pb}} } = \frac{ r_{Pb}^3}{r_{Al}^3}\)
\(\displaystyle \frac{r_{Al}}{r_{Pb}} =\sqrt[3]{\frac{\rho_{Pb}}{\rho_{Al}} }\)
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a mass of 500g ball is kicked at angle of 45 degree to the horizontal the ball reaches 12m height what is the initial velocity
The initial velocity of a 500g ball kicked at a 45-degree angle to the horizontal and reaching a height of 12m can be calculated using the kinematic equation.
What is the kinematic equation?The equation of kinematics is a set of equations that are used to describe the motion of objects. They relate to displacement, velocity, acceleration, and time. Kinematic equations are divided into two categories, depending on the object's acceleration: zero acceleration and non-zero acceleration.
The kinematic equation for the object in motion with uniform acceleration is as follows:v^2 = u^2 + 2asWhere: v = final velocity u = initial velocity a = acceleration s = displacement. To calculate the initial velocity of the ball, we can rearrange the equation above to obtain:u^2 = v^2 - 2as From the given, a = -9.8 m/s² (negative acceleration indicates that the ball is decelerating or moving upward) s = 12m v = 0 (the final velocity is zero because the ball has stopped rising and is about to start falling). We'll use these values to calculate the initial velocity of the ball.u² = (0)² - 2(-9.8)(12)u² = 235.2u = sqrt(235.2)u = 15.33 m/s.
Therefore, the initial velocity of the ball is approximately 15.33 m/s.
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You have an oxygen atom that is looking to bond. How many atoms of one element from column 1 would need to bond with that oxygen to form an ionic bond? Why?
2. A cinder block is sitting on a platform 20 m high. It weighs 16kg. The block has
_ joules of potential energy.
Answer:
3136 Joules
Explanation:
Applying,
P.E = mgh.............. Equation 1
Where P.E = potential energy, m = mass of the cinder block, h = height of the platform, g = acceleration due to gravity.
From the question,
Given: m = 16 kg, h = 20 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
P.E = 16(20)(9.8)
P.E = 3136 Joules
Hence the potential energy of the cinder block is 3136 Joules
A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children swings from this rope that is 5.70 m long, his tangential speed at the bottom of the swing is 9.10 m/s.What is the centripetal acceleration, in m/s2, of the child at the bottom of the swing?
Given,
The length is r=5.70 m
The tangential speed is r=9.10 m/s
The centripetal acceleration is:
\(\begin{gathered} a=\frac{v^2}{r} \\ \Rightarrow a=\frac{9.10^2}{5.70} \\ \Rightarrow a=\frac{14.52m}{s^2} \end{gathered}\)The acceleration is:
\(a=14.52m/s^2\)What form of energy is needed to make photosynthesis happen?
A. Proton energy
B. Chemical energ
C. Electron energy
D. Solar energy
Answer:
Photosynthesis converts solar energy into chemical energy.
your answer is solar energy
hope it helps
Draw a picture showing the possible phases of the moon in this binary star
system, do they look the same or different from those we see in the sky in
reality? (You might want to think about scale and how far the suns would be
when considering your answer.)
(Help ASAP)
forces of 10 pounds and 14 pounds act on each other with an angle of 50°. the magnitude of the resultant force
The resultant force is 10.77 pounds.
We need to know about vector to solve this problem. Force is included to vector because it has magnitude and also direction. The resultant force can be determined using cosine law. It can be written as
F² = F1² + F2² - 2F1 . F2 cos(θ⁰)
From the question above, we know that:
F1 = 10 pounds
F2 = 14 pounds
θ = 50°
By substituting the parameter, we get
F² = F1² + F2² - 2F1 . F2 cos(θ⁰)
F² = 10² + 14² - 2. 10 . 14 cos(50⁰)
F² = 100 + 196 - 280 . 0.64
F² = 100 + 196 - 280 . 0.64
F² = 116.02
F = 10.77 pounds
Hence, the resultant force is 10.77 pounds.
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The space shuttle, which was first launched on April 12, 1981, is the world's
first reusable space vehicle. The shuttle is placed in orbit by three engines that
do 1.4 x 1013 J of work in 8.5 min. What is the power output of these engines?
Answer:2.7 X 10₁₀W = 27 GW
Explanation:
W=1.4 X 10₁₃ J
ΔT=8.5 mins
P=W/ΔT=
1.4 x 10₁₃J/(8.5 mins)(60s/min)=2.7 x10₁₀W=27GW
Since all stars begin their lives with the same basic composition what characteristics most determines how they will differ
Answer:
Mass they are formed with
Explanation:
All stars are born with the same composition such as one quarter of helium, three quarter of hydrogen, and heavier element does not found more than two except their mass. Mass that differ all stars from other stars they born with. How much the mass of a star is large , the star would be as messy.
For example our sun is a star and have large mass four times greater than other living stars. It is found that smallest mass is around 1/12th of sun mass. The masses of a star is determined by its orbit binary. Sun is called a brown dwarf.
How much work does a supermarket checkout attendant do on a can of soup he pushes 0.560 m horizontally with a force of 4.70 n? express your answer in joules and kilocalories. (for each answer, enter a number.)
The work done by the attendant on the can of soup is 2.632 Joules or approximately 0.000629 kilocalories.
To calculate the work done by the supermarket checkout attendant on the can of soup, we can use the formula:
Work (W) = Force (F) × Distance (d)
Given the force is 4.70 N and the distance is 0.560 m, we can find the work done:
W = 4.70 N × 0.560 m = 2.632 J (joules)
Now, to convert joules to kilocalories, we'll use the conversion factor:
1 kcal = 4184 J
So, to find the work in kilocalories:
W (kcal) = 2.632 J / 4184 J/kcal ≈ 0.000629 kcal
Thus, the work done by the attendant on the can of soup is 2.632 Joules or approximately 0.000629 kilocalories.
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Nêu 2 ví dụ cho mỗi trường hợp sau: vật chuyển động,đứng yên,chuyển động do với vật này đứng yên so với vật khác,chuyển động thẳng,chuyển động cong,chuyển động tròn.
Answer:
Hai ví dụ như sau:
a) Vật thể chuyển động - Phương tiện di chuyển, Người đàn ông đi bộ
b) ở trạng thái nghỉ - Xe đứng, người ngồi
c) Chuyển động vì một vật đứng yên so với một vật khác - Một người đàn ông ngồi trên sân ga đứng yên so với đoàn tàu đang chuyển động, Một ô tô chuyển động ngang qua những ngôi nhà đang đứng yên
d) chuyển động thẳng - Đi bộ trên đường, chuyển động lên trên
e) chuyển động cong - Chạy trên đường tròn, đạn bắn ra từ súng
f) chuyển động tròn đều - Xe chuyển động trên đường cong, êlectron chuyển động vuông góc với từ trường đều
Explanation:
Hai ví dụ như sau:
a) Vật thể chuyển động - Phương tiện di chuyển, Người đàn ông đi bộ
b) ở trạng thái nghỉ - Xe đứng, người ngồi
c) Chuyển động vì một vật đứng yên so với một vật khác - Một người đàn ông ngồi trên sân ga đứng yên so với đoàn tàu đang chuyển động, Một ô tô chuyển động ngang qua những ngôi nhà đang đứng yên
d) chuyển động thẳng - Đi bộ trên đường, chuyển động lên trên
e) chuyển động cong - Chạy trên đường tròn, đạn bắn ra từ súng
f) chuyển động tròn đều - Xe chuyển động trên đường cong, êlectron chuyển động vuông góc với từ trường đều
How does the voltage V_1 across the first capacitor (C_1) compare to the voltage V_2 across the second capacitor (C_2)? Capacitors II A. V_1 = V_2 B. V_1 > V_2 C. V_1 < V_2 D. all voltages are zero
Compared to the voltage V2 across the second capacitor (C2), the voltage V1 across the first capacitor (C1) will be lower thus option C is correct
In a series circuit with two capacitors (C1 and C2), the voltage is divided between the two capacitors based on their capacitance values. The capacitor with the larger capacitance will have a greater voltage drop across it than the capacitor with the smaller capacitance.
Therefore, the voltage V1 across the first capacitor (C1) will be less than the voltage V2 across the second capacitor (C2). Thus, the correct answer is C. V1 < V2.
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Complete the following statement: The sum of the magnitudes of the currents directed into a junction Select one: a. is divided equally among the number of lines directed out of the junction. b.equals the current that is directed along one of the lines out of the junction. c. is greater than the total current directed out of the junction. d. equals the sum of the magnitudes of the currents directed out of the junction.
By kirchoff rule ,The sum of the magnitudes of the currents directed into a junction equals the sum of the magnitudes of the currents directed out of the junction. Therefore, the correct option is d, which says that the sum of the magnitudes of the currents directed into a junction equals the sum of the magnitudes of the currents directed out of the junction.
How does a junction work?A junction is a point where two or more lines meet. The current flowing into the junction must be the same as the current flowing out of it. The current will divide into various branches at the junction. The sum of the current entering the junction equals the sum of the current exiting the junction. Therefore, the current through one branch must be subtracted from the current through the other branch when calculating the current through each branch.The law of conservation of charge says that charge is neither created nor destroyed. Thus, the sum of the charges that flow into a junction must equal the sum of the charges that flow out of it, according to Kirchhoff's junction rule.The Kirchhoff's junction rule states that the sum of the currents into a junction must equal the sum of the currents leaving the junction. When two or more resistors are connected in a circuit, they share the current flowing through the circuit in the same direction, and the current is split into two or more branches.
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"Prove the above channel thickness equation.
This proves that the channel thickness is constant along the flow and does not depend on the channel width or the velocity of the fluid.
The above channel thickness equation can be proved by making use of continuity equation which states that the product of cross-sectional area and velocity remains constant along the flow.
The velocity of the fluid is directly proportional to the channel depth and inversely proportional to the channel width.
Hence, we can use the following steps to prove the above channel thickness equation: - Continuity equation: A1V1 = A2V2 - Where A is the cross-sectional area and V is the velocity of the fluid. - For a rectangular channel,
A = WD
where W is the channel width and D is the channel depth. - Rearranging the continuity equation for the ratio of channel depth to channel width,
we get: D1/W1 = D2/W2
Substitute D1/W1 = h1 and D2/W2 = h2 in the above equation. - We get the following expression: h1 = h2
The question is incomplete so this is general answer.
This proves that the channel thickness is constant along the flow and does not depend on the channel width or the velocity of the fluid.
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THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! What is the fundamental frequency of a mandolin string that is 42.0 cm long when the speed of waves of the string is 329 m/s? with working outs
Answer:
\(f_{o}\) = 391.67 Hz
Explanation:
The sound of lowest frequency which is produced by a vibrating sting is called its fundamental frequency (\(f_{o}\)).
The For a vibrating string, the fundamental frequency (\(f_{o}\)) can be determined by:
\(f_{o}\) = \(\frac{v}{2L}\)
Where v is the speed of waves of the string, and L is the length of the string.
L = 42.0 cm = 0.42 m
v = 329 m/s
\(f_{o}\) = \(\frac{329}{2*0.42}\)
= \(\frac{329}{0.84}\)
\(f_{o}\) = 391.6667 Hz
The fundamental frequency of the string is 391.67 Hz.
A car's horn produces a constant frequency of 350 Hz as it passes by Suzy. What is the best estimate of the
frequency Suzy hears after the car passes her?
330 Hz
350 Hz
360 Hz
700 Hz
Answer:
330 Hz
Explanation:
edg2020
The best estimate of the frequency Suzy hears after the car passes her is govern by doppler effect and it is 330 Hz.
What is frequency?Frequency is the number of occurrences of a repeating event per unit of time.
What is Doppler EFFECT?
The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source.
According to the Doppler Effect, the frequency observed by an observer decreases for source going away.
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What is the electrical force of two punctiform electrical charges of 3ųC and 4ųC respectively at a distance of 10 cm in a vacuum
Answer:
Electrical force, F = 10.8 N
Explanation:
We have,
Charge 1, \(q_1=3\ \mu C=3\times 10^{-6}\ C\)
Charge 2, \(q_2=4\ \mu C=4\times 10^{-6}\ C\)
Distance between charges is 10 cm or 0.1 m
It is required find the electric force between two charges. The formula used to find the electrical force is given by :
\(F=\dfrac{kq_1q_2}{r^2}\)
k is electrostatic constant
Plugging all the values we get :
\(F=\dfrac{9\times 10^{9}\times 3\times 10^{-6}\times 4\times 10^{-6}}{(0.1)^2}\\\\F=10.8\ N\)
So, the electrical force between charges is 10.8 N.
Suppose that you are standing on a cardboard carton that just barely supports you. what would happen to the cardboard box if you jumped up in the air? it will
The cardboard box will collapse when you jumped up in the air.
When they are standing over the cardboard. Cardboard is supporting our weight which results in the whole system is in equilibrium position.
In the equilibrium condition the box will not collapse. But as soon as you want to jump in the upward direction then a force has to be applied. in the upward direction there will be an acceleration according to the Newton second law.
As we know, Newton's third law states that every action has an equal and opposite reaction.
So to push the body upward, we will push the cardboard in the downward direction. With equal force by which we have to make a jump.
Due to this jump the systems equilibrium will not maintained and the box will collapse.
The cardboard box will collapse when you jumped up in the air.
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Giving a puppy a treat to encourage the behavior of sitting is an example of________________. * 5 points Gestalt Theory Reinforcement None of the above
Typically, operant conditioning is the method we employ when we are training our canines. The outcome is now determined by the dog's conduct.
Simple definition of Gestalt psychology.In order to comprehend how the human brain interprets experiences, gestalt psychology is a school of thinking. It implies that structures have unique qualities that distinguish them from the sum of their constituent pieces when taken as a whole.
An illustration of a gestalt is...The Gestalt principle of similarity describes how humans combine information by comparing the similarity of items if closeness is determined by position. For instance, we would classify them as cats and dogs if there were five dogs of various varieties and five cats of various breeds.
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5. after 58 days, a sample of a radioactive isotope contains only 6.25% of its original
material. what is the half life of the isotope?
The half-life of the isotope is approximately 157.17 days. This means that it takes around 157.17 days for the quantity of the isotope to reduce to half of its original amount.
How do we determine the half-life of a radioactive isotope?To determine the half-life of a radioactive isotope, we can use the formula:
Half-life = (Time * ln(2)) / ln(Ratio)
Given that the sample of the isotope contains only 6.25% of its original material after 58 days, we can calculate the half-life as follows:
Ratio = Final amount / Initial amount = 6.25% / 100% = 0.0625
Time = 58 days
Substituting these values into the formula, we have:
Half-life = (58 days * ln(2)) / ln(0.0625) ≈ 157.17 days
Therefore, the half-life of the isotope is approximately 157.17 days.
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Find the x-component of this
vector:
12.1 m
48.4°
The resultant distance of the vector is 12.1 m and the angle between two vectors are 48.4°. So the x-component of this vector is, Aₓ = 8.0335 m
What is vector?Vector is a product that means a parameter has two types of property one is value second is direction. If a parameter has both then it called a vector quantity. Example: Velocity.
How can we calculate x-component of this vector?To calculate the vector we know first this is a proper vector quantity or not. According to the question, this is a vector quantity. So it has two component, one along x axis another is y axis as shown in the picture.
We have to calculate the x-component, so we are using the formula is,
Aₓ = Acosθ
Here we are given,
A = The resultant distance of the vector = 12.1 m
θ= The angle between two vectors = 48.4°.
Now We have to calculate the x-component = Aₓ
Now we put the known values in the above equation, we get
Aₓ = Acosθ
Or, Aₓ = 12.1*cos(48.4°)
Or, Aₓ = 8.0335 m
According to the calculation we get, the x-component of this vector is, Aₓ = 8.0335 m
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Answer:
Explanation:
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A2.0kg arrow is fired at 10m/s into a stationary 10 kg block of ice as shown below: the arrow sticks into the block of ice and they start moving . What is the velocity of the arrow/ice combination after the collison
Answer:
the velocity is 1.67 m/s
Explanation:
The computation of the velocity of the arrow/ice combination after the collison is shown below:
Here the law of conservation is applied
\(p_i = p_f\\\\m_av_a+m_b+v_b= (m_a + m_b)v\)
Here
\(m_a = 2.0 kg\\\\v_a = 10m/s\\\\m_b = 10 kg\\\\v_b = 0\)
Now
\(v = \frac{m_av_a+ m_bv_b}{m_a + m_b} \\\\= \frac{(2.0kg) (10 m/s) + 0}{2.0kg + 10.0kg}\)
= 1.67 m/s
hence, the velocity is 1.67 m/s
PLEASE HELP!!! ILL MARK BRAINLYEST!!
How many atoms are in 5 C?
7
5
3
4
6
Answer:
Explanation:
3.011 x 10^24 atoms
Answer:
jskskskssksksksskssksksksksks
if a Ferrari, with a initial velocity of 10 m/s, accelerates at a rate of 20 m/s² for 3 seconds, what will its final velocity be?
Answer:
70 m/s
Explanation:
Vf = Vo + a t
= 10 + 20 (3) = 70 m/s
a rock hits the ground at a speed of 15 m/s and leaves a hold 50 cm deep. after it hits the ground, what is the magnitude of the rock's (assumed) uniform acceleration?
The magnitude of the rock's (assumed) uniform acceleration is v² - 225.
Initial speed, u = 15 m/s
Displacement, s = 50 cm = 0.5 m
Magnitude of acceleration, a = ?
We know, v² - u² = 2as
Let's substitute the given values into the above formula. v² - u² = 2as (v is the final velocity)
Final velocity, v = ?u = 15 m/s (Initial velocity)
s = 0.5 m (Displacement)
a = ?
v² - u² = 2as (v² - u²)/2s = a(v+u)/2(a = (v² - u²)/2s)
(a = (v² - u²)/2s)(a = (v² - (15 m/s)²)/2(0.5 m))(a = (v² - 225)/1)(a = v² - 225)
Therefore, the magnitude of the rock's uniform acceleration is v² - 225, given that a rock hits the ground at a speed of 15 m/s and leaves a hold 50 cm deep after it hits the ground.
The magnitude of the rock's uniform acceleration is v² - 225.
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Based on your observations in the prelab, did the size of the ball you chose have any affect on the observed acceleration?
o Yes, the larger the ball the greater the acceleration
o Yes, the smaller the ball the greater the acceleration
o No, thee had no effect on the acceleration, it was constant for each planet
o No, there was no observable correlation between ball size and acceleration it varied a lot
Based on the observations in the prelab, the size of the ball chosen did not have any effect on the observed acceleration.
The correct answer would be: No, there was no observable correlation between ball size and acceleration it varied a lot
The size of the ball, whether larger or smaller, did not have a significant effect on the acceleration experienced by the ball.
The acceleration observed in the prelab was likely primarily influenced by the gravitational force acting on the ball. The acceleration due to gravity is determined by factors such as the mass of the planet and the distance from its center, as described by the equation:
a =
In this equation, a represents the acceleration due to gravity, G is the gravitational constant, M is the mass of the planet, and r is the distance from the planet's center. Notably, the size of the ball, referring to its diameter or volume, does not directly impact these parameters.
It is important to note that other factors, such as air resistance, may have influenced the observed variations in acceleration. The shape, density, and surface area of the ball can affect the extent of air resistance experienced during its motion. However, these factors are separate from the size of the ball itself.
Therefore, based on the prelab observations, it can be concluded that the size of the ball chosen did not have a significant effect on the observed acceleration. The variations in acceleration were likely influenced by factors other than the size of the ball, such as air resistance.
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