Which parts of atoms can interact (react) to form chemical bonds?

a) valence electrons

b) protons

c) the nucleus of each atom

d) the orbitals

Answers

Answer 1

Atoms interact and form chemical bonds through its various components: valence electrons, protons, the nucleus of each atom, and the orbitals.

Here, all the options are correct.

These components are essential for atoms to interact and form bonds, as they provide the crucial energy and direction for the reaction. Valence electrons contain the most energy and are most available for reacting. These electrons are the outer shell and provide the electrons needed to form a bond with another atom.

This process creates a stable bond between atoms, and can be observed when an atom has an incomplete outer shell of electrons (an incomplete electron valence shell).Protons and the nucleus of each atom provide the matter for a bond between two atoms.

The nucleus of an atom has a “charge”, either a positive or neutral, and the protons within the nucleus contribute to the overall charge of the atom. Finally, the orbitals are important for allowing two atoms to interact and form a bond. Orbitals are the “region” in space around an atom where electrons have the highest probability of being found.

Here, all the options are correct.

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Related Questions

81.3% completeQuestionYou supervise a team of seven workers. You record the number of team members who reach their production goal each day. For the past week, you record the following data: Monday 5 team members reached their goal; Tuesday 4 team members reached their goal; Wednesday 2 team members reached their goal; Thursday 7 team members reach their goal; Friday 3 team members reached their goal. What was the average number of team members who reached their goal per day?A.4.2B.5.0C.6.6D.14.7E.21.0

81.3% completeQuestionYou supervise a team of seven workers. You record the number of team members who

Answers

Answer:

Average number of team members who reached their goal per day = 4.2

Explanation:

Number of team members that reached their goals on Monday = 5

Number of team members that reached their goals on Tuesday = 4

Number of team members that reached their goals on Wednesday = 2

Number of team members that reached their goals on Thursday = 7

Number of team members that reached their goals on Friday = 3

Total number of team members that reached their goals = 5 + 4 + 2 + 7 + 3

Total number of team members that reached their goals = 21

Average number of team members who reached their goal per day = 21/5

Average number of team members who reached their goal per day = 4.2

Round the following off to required number of significant figures.


137 (2 significant figures)

Answers

Answer:

140

hope this helps

have a good day :)

Explanation:

140 but I’m not sure. Have a great day

a spider hangs by a strand of silk at an eye level 40 cm in front of a plane mirror. you are behind the spider, 68 cm from the mirror.

Answers

Your eye as well as the spider's image in the mirror are 1.28 meters apart.

What is mirror, in a brief?

A mirrors is a luminance that reflects light and creates an actual or fictitious picture. An device that returns an image is a reflector or looking glass, which reflects the image of the object when it is positioned in front of it. When focused through an eye or camera lens, light that reflects off a mirror will reveal an image of everything that was in front of it. Mirrors reflect light at an equal but opposite angle, reversing the orientation of the image.

Briefing:

The image distance is equal to the object distance:

Distance between the spider and mirror = 40cm

So, the image is formed 40cm inside the mirror

Distance between the person and mirror = 68cm

Distance between the image and person = 68+40= 128cm

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How many seconds are in a day?

Answers

Answer:86,400

Explanation:

A force of 30 Newtons is used to push a basket along the floor a total distance of 3 meters. How much work is done on the basket?

Answers

Answer:

the total work done is 90J

Explanation:

the reason why is because you are the force (30 newtons) and the metere (3) so you will be multiplying those two numbers together.

W= FD 30(3)= 90J

A metal conducting sphere of radius R holds a total charge Q. What is the surface charge density, sigma, on the outer surface of the conducting sphere?

Answers

\(O = Q/4PiR^{2}\) is the surface charge density, sigma, on the outer surface of the conducting sphere.

The load per group of a double surface area is defined as surface charge density. It is a measurement of how much electric charge accumulates on a surface. It is represented by the symbol, and the SI unit is Coulombs for each square meter, abbreviated  \(Cm^{2}\).

A surface charge is a non-zero electric charge on a two-dimensional surface. These electric fields are constrained here on the 2-D surface, and the bias voltage on the surface is described by surface charge density, which is measured even in coulombs per square meter.

Surface charge density is defined in electromagnetism also as the quantity of electric charge per unit length, volume, or surface area. surface charge is inverse to the conductor radius of curvature.

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Eating soda is used while cooking rice in the hotels ? why?​

Answers

Answer:

because it helps to neutralize acid in our body.

An electrical spark, such as lightning, generates electromagnetic radiation over a wide range of wavelengths. How much longer will a pulse of radio energy take to travel between two detector stations 100 m apart than a pulse of ultraviolet radiation from the same spark

Answers

Answer:

The time is identical, since both pulses travel at the speed of light.

Explanation:

6. What is not an example of mechanical energy?
A a hammer
B a bowling ball
C a moon in orbit around its planet
D a drawn bow

Answers

Answer:

the answer to your question is c

Plzz Help easy quesion for 20 points Why does someone get burned if they touch an old filament bulb that has been on for a few hours? Plzz Help

Answers

incandescent lights get hot very quickly and therefore can easily burn u or catch fire

Answer:

In reality, the filament gets so hot it in a real sense bubbles off molecules and electrons. Now and again this material gathers as a dull spot at the highest point of the bulb. Eventually, the filament falls apart, gets frail, and breaks, subsequently finishing the life of the light. Lights radiate light by siphoning an electric flow through a dainty tungsten fiber. The filament warms and emits light. Over the long haul, the filament oxidizes and turns out to be increasingly fragile, until it splits up and the bulb goes out. ... Tungsten picks up obstruction as it warms.

Hope this helped :)

A trebuchet at ground levels throws a boulder with an initial velocity of 25 m/s at 30 degrees.
What was the magnitude of the final velocity of the boulder before it hit the ground?
a
30 m/s
b
10 m/s
C С
25 m/s
ОООООО
d
20 m/s
e
27.5 m/s
12.5 m/s

Answers

Answer:

The correct option is;

C. 25 m/s

Explanation:

The initial velocity with which the boulder was thrown = 25 m/s

The path in which the boulder projectile moves = 30°

For projectile motion, we have;

The time it takes the boulder to hit the ground is given by the following equation;

y = y₀ + v₀·sin(θ₀)t -¹/₂·g·t²

Where;

y = The height of the boulder

y₀ = The initial height of the boulder = 0

g = The acceleration due to gravity = 9.81 m/s²

When the boulder touches the ground again, the value  of y = 0. therefore, we have;

0 = 0 + 25 × sin(30)t -¹/₂ × 9.81 × t²= 12.5·t - 4.905·t²

From which we have, t = 0 or t ≈ 2.55 s

At t = 2.55 s The vertical velocity = v₀sin(θ₀) - g·t = 25 × 0.5 - 9.81×2.55 =  -12.5 m/s

The vertical velocity, \(v_y\) =  -12.5 m/s

The horizontal velocity, vₓ = v₀·cos(θ₀) = 25×cos(30) ≈ 21.65 m/s

The magnitude of the resultant velocity before, the boulder hits the ground is given as follows

\(\left | v \right |\) = √((vₓ)² + (\(v_y\))²) = √(12.5² + 21.65²) = √625 = 25

The magnitude of the resultant velocity before, the boulder hits the ground is 25 m/c

Galaxies are made of millions of stars, interstellar gas, and dust that stay relatively close together due to magnetic attraction.

True or False?
if its false please explain why

Answers

Answer:

True

Explanation:

Its true

The statement "Galaxies are made of millions of stars, interstellar gas, and dust that stay relatively close together due to magnetic attraction." is false.

What is Gravitation?

Gravitation, also known as gravity, is a fundamental force of nature that attracts objects with mass or energy toward each other. It is the force that keeps planets in orbit around stars, stars in orbit around the centers of their galaxies, and all objects on the surface of the Earth.

According to Newton's law of gravitation, every mass in the universe attracts every other mass with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This means that the larger the masses of the objects and the closer they are to each other, the greater the gravitational force between them.

In this question,

Galaxies are made up of millions, or even billions, of stars along with interstellar gas and dust. However, the gravitational force, not magnetic attraction, is what holds the stars and other components of a galaxy together. The gravitational attraction between the stars and other matter in the galaxy is what allows them to orbit around the center of mass of the galaxy. In fact, the vast majority of matter in a galaxy is dark matter, which is an invisible and unknown form of matter that interacts gravitationally with other matter in the galaxy.

While magnetic fields do exist in galaxies, they are generally much weaker than gravitational forces and play a secondary role in the structure and dynamics of galaxies.

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A car is moving along a straight line op is shown below it moves from O to P in 8sec and return to p to q in 6sec. What is the average velocity and the speed of the car

Answers

Answer:

The answer would be A

Explanation:

Write the cautions which are taken to keep the magnetic properties of magnetsa) Don’t hammer it b) don’t drop it c) don’t heat it d) all of these


PLS HELP GUYS ITS URGENTTT!! I AM IN CLASS ...PLEASE!!

Answers

Answer:

D

Explanation:

These all can impact the magnetic properties

which of the following is an example of thermal energy being transferred directly from one substance to another via conduction?

which of the following is an example of thermal energy being transferred directly from one substance

Answers

Answer:I think it’s D

Explanation:

Conduction needs direct touch to transfer

when an apple falls towards the earth the earth moves up to meet the apple. Is it true? If yes, why is the earth motion not noticeable ?

Answers

Answer:

Explanation:

The apple also exerts an equal and opposite force on the earth but earth does not move because the mass of apple is very small,due to which the gravitational force produces a large acceleration in it (a=F/m) and we can see the apple falling towards the earth but the mass of earth is very large,the same gravitational .

Las ruedas de una locomotora de 500 toneladas tiene un coeficiente de friccion estatico con las vias de 0.15 ¿Cual es la fuerza de traccion tangencial maxima ejercida entre las vias y las ruedas?

Answers

Answer:

Ff = 7.35*10^5 N

Explanation:

To find the maximum transverse pulling force you use the following formula, for the friction force:

\(F_f=\mu N=\mu Mg\) (1)

μ: friction coefficient = 0.15

N: normal force, which is equal to the weight over the wheel

M: mass of th train = 500 ton = 500 000 kg

g: gravitational acceleration = 9.8 m/s^2

You replace the values of the variables in the equation (1):

\(F_f=(0.15)(500000kg)(9.8m/s^2)=735000 N=7.35*10^5N\)

hence, the maximum transverse pulling force is 7.35*10^5 N

Three people are pulling on a crate , but the crate isn’t moving (it’s at rest ) :Robert and Rachel are pulling to the Right , while Larry is pulling to the Left. If Robert is pulling with force of 74 N, and Larry is pulling with a force of 106 N , how much is Rachel’s force ?

Answers

Answer:32

(im not sure if this is right but im just gonna try and explain.)

Explanation: If Larry and the two other people are both pulling at the same force, it wouldn't be able to move.

Xp (cm) The following data is given for a cantilever beam. The experiment is set up the same way as in our Displacement and Strain Lab, where a strain gage located at xg is used to measure the strain and a proximity probe located at xp is used to measure deflection of the beam. beam dimensions gage location probe location Length (cm) width (mm) thickness (mm) X, (cm) 30 24 8 4 26 For a load with 300 g of total mass at the free end, the strain indicator reads 165 micro- strain and the proximity probe reads 4.02V (this reading has already adjusted 0 when unloaded) (a) What is the fiber stress at the gage location, in kPa? What is the Young's modulus of the beam material using the Hook's law, in GPa? (b) A calibration equation for the probe was previously obtained with a slope of 0.25 mm/V. What is the deflection of the beam at the probe location, in mm? What is the Young's modulus of the beam using Euler-Bernoulli beam theory, in GPa?

Answers

(a)The Young's modulus of the beam material using Hooke's law is 200 GPa.(b)The Young's modulus of the beam using Euler-Bernoulli beam theory is 200 GPa.

(a) The fiber stress at the gage location is calculated using the following equation:

σ = Eε

where σ is the stress in kPa, E is the Young's modulus in GPa, and ε is the strain in micro-strain.

The Young's modulus for steel is 200 GPa. The strain is 165 micro-strain.

Substituting these values into the equation, we get:

σ = (200 GPa)(165 micro-strain) = 33 kPa

Therefore, the fiber stress at the gage location is 33 kPa.

The Young's modulus of the beam material using Hooke's law is calculated using the following equation:

E = σ/ε

where E is the Young's modulus in GPa, σ is the stress in kPa, and ε is the strain in micro-strain.

The stress is 33 kPa. The strain is 165 micro-strain.

Substituting these values into the equation, we get:

E = (33 kPa)/(165 micro-strain) = 200 GPa

Therefore, the Young's modulus of the beam material using Hooke's law is 200 GPa.

(b) The deflection of the beam at the probe location is calculated using the following equation:

δ = sL3/4EI

where δ is the deflection in mm, s is the slope of the calibration equation in mm/V, L is the length of the beam in cm, E is the Young's modulus in GPa, and I is the moment of inertia in cm4.

The slope of the calibration equation is 0.25 mm/V. The length of the beam is 30 cm. The Young's modulus is 200 GPa. The moment of inertia is (24 mm)(8 mm)^3 / 12 = 15360 mm^4.

Substituting these values into the equation, we get:

δ = (0.25 mm/V)(30 cm)^3 / 4(200 GPa)(15360 mm^4) = 0.15 mm

Therefore, the deflection of the beam at the probe location is 0.15 mm.

The Young's modulus of the beam using Euler-Bernoulli beam theory is calculated using the following equation:

E = 3(FL/δ^2)

where E is the Young's modulus in GPa, F is the force in N, L is the length of the beam in cm, and δ is the deflection in mm.

The force is (300 g)(9.81 m/s^2) = 294 N. The length of the beam is 30 cm. The deflection is 0.15 mm.

Substituting these values into the equation, we get:

E = 3(294 N)(30 cm)/(0.15 mm)^2 = 200 GPa

Therefore, the Young's modulus of the beam using Euler-Bernoulli beam theory is 200 GPa.

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An object is moving to the west at a constant speed. Three forces are exerted on the object. One force is 10 N directed due North, and another is 10N directed due West. What is the magnitude and direction of the third force if the object is to continue moving West at a constant speed?

Answers

Answer:

10 N south

Explanation:

It cancels out the north allowing the object to keep going west :)

i think this might be wrong so like don't trust me-

a uniform cylinder of diameter .20 m and mass 12 kg rolls without slipping down a 37 degree inclined plane. the gain in translational kinetic energy of the cylinder when it has rolled 5 m down the incline of the plane is approximately

Answers

The gain in translational kinetic energy of the cylinder when it has rolled 5m down the incline of the plane is approximately 345.6 J.

Given data:

Diameter, d = 0.20 mRadius,

r = 0.10 mMass of cylinder,

m = 12 kgInclined angle, θ = 37°

Distance traveled by cylinder, s = 5m

We know that work done by the gravitational force is the change in potential energy.

W=Fhsinθ... (1)

The kinetic energy of rolling objects is equal to its rotational kinetic energy plus its translational kinetic energy.

K = 1/2Iω² + 1/2mv²... (2)

The moment of inertia of a solid cylinder I=mr²/2.

Using conservation of energy principle:

Gain in translational kinetic energy of the cylinder is equal to the loss in potential energy.

Thus,

½mv²=mgH-mgSins....(3)

When the cylinder rolls without slipping, its velocity is equal to its angular velocity multiplied by its radius

v=ωr

Therefore, the rotational kinetic energy can be expressed as

1/2Iω²=1/2mr²ω²/2.... (4)

Using equations (1), (2), (3), and (4),

we can find the gain in translational kinetic energy of the cylinder while it rolls 5m down the incline of the plane.

K=1/2mv²=1/2m(v=ωr)²=1/2mr²ω²/2=1/2Iω²=1/2(12)(0.10)²(2/2)=0.12J... (5)

Potential energy, P=mgh=mgSins=12(9.8)(5)sin37°=294.2 J... (6)

So, using equations (5) and (6), we can get the gain in translational kinetic energy of the cylinder to be approximately:

K = 294.2 J – 0.12 J = 294.08 J

Therefore, the gain in translational kinetic energy of the cylinder when it has rolled 5 m down the incline of the plane is approximately 345.6 J.

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The greatest number of thunderstorms occur in the?
mountains

tropics

high latitudes

middle latitudes

Answers

Answer:

On the other hand, Florida's Gulf Coast experiences the greatest number of thunderstorms out of any U.S. location. These types of storms occur on average 130 days per year in Florida.

The answer is the first one ☝️

An element of atomic number 88 decays radioactively to an element of atomic number 82.
Part A
Which of the following emissions achieve this result?
Check all that apply.
a.) one alpha particle and one beta-minus particle
b.) three alpha particles
c.) one alpha particle
d.) six beta-minus particles
An element of atomic number 82 and mass number 214 decays radioactively to an element of atomic number 82 and mass number 210.
Part B
Which of the following emissions achieve this result?
Check all that apply.
a.) four beta-minus particles
b.) two beta-minus particles and one alpha particle
c.) two alpha particles
d.) one alpha particle

Answers

An element of atomic number 88 decays radioactively to an element of atomic number 82. The emissions that achieve this result is one alpha particle. The correct option is D. The emission that achieves this result is one alpha particle. The correct option is C.

To determine the emissions that achieve the radioactive decay from an element with atomic number 88 to an element with atomic number 82, we need to consider the changes in atomic number and mass number during the decay process.

In a radioactive decay, the atomic number decreases by the emission of a particle, and the mass number decreases by a specific amount as well.

Atomic number of initial element = 88

Atomic number of final element = 82

From this information, we can conclude that the decay process involves the emission of an alpha particle.

The emission of an alpha particle corresponds to the emission of a helium nucleus, which consists of two protons and two neutrons. This emission reduces the atomic number by 2 and the mass number by 4.

Therefore, the emission that achieves this result is C, one alpha particle.

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Two 31-m long parallel wires are 0.155 m apart. Each carries 168 A of current. What is the magnitude of the force between the wires? Please give your answer in Newtons.

Answers

Answer:

The magnitude of magnetic force between the two parallel wires is 1.13 N.

Explanation:

Given;

length of each wire, l = 31 m

distance between the two parallel wires, r = 0.155 m

current on each wire, I = 168 A

The magnitude of magnetic force between the two parallel wires is calculated as;

\(F = \frac{\mu _oI_1I_2 L}{2\pi r} \\\\F = \frac{(4\pi \times 10^{-7}) \times (168)^2 \times (31)}{2\pi \times 0.155} \\\\F = 1.13 \ N\)

Therefore, the magnitude of magnetic force between the two parallel wires is 1.13 N.

Anna doe a handtand. 1 hand ha an area of 0. 020m. Anna ha a ma of 70kg. What i the preure on the floor when Anna doe a handtand with both of her hand

Answers

The pressure on the floor when Anna does a handstand with both of her hands is 17.15 KPa

F = m g

F = Force

m = Mass

g = Acceleration due to gravity

m = 70 kg

g = 9.8 m / s²

F = 70 * 9.8

F = 686 N

Area of one hand = 0.02 kg

Since she does a handstand with both hands, the total area,

A = 0.02 * 2

A = 0.04 m²

P = F / A

P = Pressure

A = Area

P = 686 / 0.04

P = 17150 Pa

P = 17.15 KPa

Therefore, the pressure on the floor is 17.15 KPa

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At the gym, a man pulls a bar on a machine that works the muscles of the upper back. It takes him 0. 5 seconds to raise 30


kilograms of weights a vertical distance of 0. 5 meters.


Which of these exerts the same power output? (Estimate g as 10 m/s2. )



A) lifting 25 kilograms a distance of 2. 4 meters in 2. 0 seconds



B) lifting 45 kilograms a distance of 2. 4 meters in 3. 0 seconds


C) leg pressing 45 kilograms a distance of 0. 5 meters in 0. 5 seconds.


D) bench pressing 30 ligrograms a distance of 0. 5 meter in 1. 5 seconds.


Pleaseeeeeee help me

Answers

The power output of the man pulling the bar can be calculated as follows:

Power = Work / Time

The work done by the man is equal to the force he exerts multiplied by the distance he moves the weights:

Work = Force x Distance

The force he exerts is equal to the weight of the weights he is lifting:

Force = Weight x g

where g is the acceleration due to gravity, which is approximately 10 m/s^2.

Plugging in the given values, we get:

Force = 30 kg x 10 m/s^2 = 300 N

Work = Force x Distance = 300 N x 0.5 m = 150 J

Power = Work / Time = 150 J / 0.5 s = 300 W

Now we can check which of the other options exerts the same power output:

Option A:

Force = 25 kg x 10 m/s^2 = 250 N

Work = Force x Distance = 250 N x 2.4 m = 600 J

Power = Work / Time = 600 J / 2.0 s = 300 W

Option B:

Force = 45 kg x 10 m/s^2 = 450 N

Work = Force x Distance = 450 N x 2.4 m = 1080 J

Power = Work / Time = 1080 J / 3.0 s = 360 W

Option C:

Force = 45 kg x 10 m/s^2 = 450 N

Work = Force x Distance = 450 N x 0.5 m = 225 J

Power = Work / Time = 225 J / 0.5 s = 450 W

Option D:

Force = 30 kg x 10 m/s^2 = 300 N

Work = Force x Distance = 300 N x 0.5 m = 150 J

Power = Work / Time = 150 J / 1.5 s = 100 W

Therefore, options A and B exert the same power output as the man pulling the bar, while options C and D do not.

NACA 0012 produces what kind of pitching moments with increases in Angle of Attack?Large nose-up moments.Negative nose-down moments.No pitching moments.Small positive nose-up moments.

Answers

NACA 0012 produces large nose-up moments with increases in Angle of Attack.

When the Angle of Attack is increased, the flow over the top of the airfoil is disturbed and separates from the surface, creating a low-pressure region above the airfoil. This creates a lift force perpendicular to the direction of airflow. However, this also creates a moment that rotates the airfoil nose-up around its center of gravity. This nose-up moment is more pronounced in airfoils with a relatively flat upper surface like the NACA 0012. Thus, the NACA 0012 produces large nose-up pitching moments with increases in Angle of Attack.

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1) An object is dropped from the top of tower of hight 156.8m and at the same time another object is thrown vertically upward with the velocity of 77.1 m/s from the feetof tower,when and where the object meet​

Answers

Answer:

The objects meet after 2.033722438s, at a height 136.5334679m from the ground.

Explanation:

Call the object being dropped A and the object being thrown B.

When the objects meet, the time ('t') for both objects will be equal, and the sum of their distances will be equal to 156.8m.

Figure out the distance for A in terms of time, t:

s = ut + (1/2)at²

= 0t +(1/2)(9.8)t²

=4.9t²

Figure out the distance for B in terms of time, t:

s = ut + (1/2)at²

=(77.1)t + (1/2)(-9.8)t²

=77.1t - 4.9t²

We now adding the distances gives us 156.8, so can write:

(4.9t²) + (77.1t - 4.9t²) = 156.8

77.1t = 156.8

∴ t = 2.033722438s

To find the distances, plug in this value for t:

For A: 4.9t² → 20.26653209m

For B: 77.1t - 4.9t² → 136.5334679m

The objects will meet 155.2 meters below the top of the tower after 15.7 seconds.

What is the height?

The formula to calculate the time it takes for the object thrown upwards to return to the ground:

Time = 2 * Initial velocity / gravitational acceleration

Plugging in the values given in the question, you can calculate the time as follows:

Time = 2 * 77.1 m/s / 9.8 m/s^2 = 15.7 seconds

To determine when and where the objects meet, you can use the following formula to calculate the height of the object thrown upwards at any given time:

\(Height = Initial velocity * time - (1/2) * gravitational acceleration * time^2\)

Plugging in the time calculated above and the initial velocity and gravitational acceleration given in the question, you can calculate the height of the object at the time it returns to the ground as follows:

Height = 77.1 m/s * 15.7 s - (1/2) * 9.8 m/s^2 * (15.7 s)^2 = -1.6 meters

This means that the object thrown upwards returns to the ground 1.6 meters below the point where it was launched. The object dropped from the top of the tower will also have fallen a distance of 156.8 meters in the same amount of time, so the two objects will meet at a point 156.8 meters - 1.6 meters = 155.2 meters below the top of the tower

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The amount of friction depends on the weight of the objects pressing together.

Answers

Answer:

The amount of friction depends on the force pushing the surfaces together. If this force increases, the hills and valleys of the surfaces can come into closer contact. The close contact increases the friction between the surfaces. Objects that weigh less exert less downward force than objects that weigh more.

Explanation:

Friction depends partly on the smoothness of the contacting surfaces, a greater force being needed to move two surfaces past one another if they are rough than if they are smooth.

a hypothetical planet has a mass of twice that of the earth and a radius of four times that of the earth. what is the acceleration due to gravity on the planet in terms of g, the acceleration due to gravity at the earth?

Answers

The acceleration due to gravity on the planet will be 8g.

What is gravity?

Gravity is the force of attraction between objects that is exerted by the masses of those objects. It is the weakest of the four fundamental forces in nature and is most noticeable when two objects of significant mass interact. On Earth, gravity is what keeps us firmly rooted to the ground and is what causes objects to fall when we drop them. It is also what causes the moon to orbit around the Earth and the planets to orbit around the sun.

This is because the acceleration due to gravity is directly proportional to the mass of a body and inversely proportional to the square of its radius. This means that if the mass of a body is doubled and its radius is quadrupled, the acceleration due to gravity will be 8 times the acceleration due to gravity at the Earth.

Therefore, the acceleration due to gravity on the planet will be 8g.

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The acceleration due to gravity on the planet will be g/8

What is gravity?

Gravity is the force of attraction between objects that is exerted by the masses of those objects. It is the weakest of the four fundamental forces in nature and is most noticeable when two objects of significant mass interact. On Earth, gravity is what keeps us firmly rooted to the ground and is what causes objects to fall when we drop them. It is also what causes the moon to orbit around the Earth and the planets to orbit around the sun.

This is because the acceleration due to gravity is directly proportional to the mass of a body and inversely proportional to the square of its radius.

As we know,

Charge (q) = GM/R²

Here, R = radius of the planet

M = mass of the planet

G = Gravitational constant

Now, after putting the values we get:

q = (G × 2me) / (4ve)²

or, q = 1/8 (Gme/ve²)

or, q = 1/8 × g

Therefore, the acceleration due to gravity on the planet will be g/8

To learn more about gravity refer to:

brainly.com/question/88039

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