Answer:
A
Explanation:
Making all the schedules
The task within an airline company that are related to operations is;
Option A: Crew scheduling.
In airline operations there are numerous tasks carried out which includes;
dispatchflight planningflight watchweather data provisionoperations controlground to air communications Integration with crewCrew schedulingMaintenance planningNow, looking at the given options, the only task that falls into the list given of airline operations tasks is Crew scheduling.
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The 13-lb weight is supported by the cord AC and roller and by the spring as shown in the figure. If the spring has an unstretched length of 8 in., and the weight is in equilibrium when d = 4 in., determine the stiffness k of the spring.
can you help me with a question
In order to break a half-normmaled pair of patch points, who row do you need to plug a cable in to?
The interconnection between that component and the ports will only be severed if a cable is placed into the bottom jack if those points are wired to be half-normal (the channel input jack). The connection will not be broken if a cable is plugged into the top jack (the module output).
a dial indicators can be used to measure which two of the following: (a) diameter, (b) length, (c) roundness, (d) straightness, (e) surface roughness, and (f) thickness?
A dial indicator can be used to measure (c) roundness and (d) straightness. These tools are useful for assessing the deviation of a surface from its ideal shape, such as determining how round a cylindrical object is or how straight a flat surface is.
A dial indicator can be used to measure the (b) length and (d) straightness of an object.A dial indicator is a precision measurement tool that uses a plunger or probe to make contact with the object being measured. It is typically used in manufacturing and engineering to ensure that parts and components are within specified tolerances.While a dial indicator can provide useful information about the surface roughness, diameter, roundness, and thickness of an object, it is not the most appropriate tool for measuring these characteristics. Other measurement tools, such as micrometers, calipers, and profilometers, are better suited for these tasks.
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Under a subsection for geological hazards the buyer is encouraged to obtain an read the booklet
Answer:
Buyer is encouraged to obtain and read the booklet entitled "The Homeowners Guide to Earthquake Safety." In most cases a questionnaire within the booklet must be completed by Seller and the entire booklet given to the Buyer if the Property was built prior to 1960.
the two main categories of home and office printers are
The two main categories of home and office printers are:
1. Inkjet Printers: Inkjet printers are commonly used for both home and office settings. They work by spraying tiny droplets of ink onto paper to create text and images. Inkjet printers are known for their versatility, affordability, and the ability to produce high-quality color prints. They are suitable for printing documents, photos, and graphics with varying levels of detail.
2. Laser Printers: Laser printers are widely used in office environments due to their speed and efficiency. These printers use a laser beam to transfer toner onto paper, producing sharp and precise prints. Laser printers are known for their fast printing speeds, high-volume capabilities, and superior text quality.
Both inkjet and laser printers have their own advantages and are designed to cater to different printing needs. Inkjet printers excel in producing high-quality color prints and are often preferred for printing photos and graphics. On the other hand, laser printers are more commonly used for printing text-heavy documents in office settings due to their speed, cost-effectiveness, and crisp text output. The choice between inkjet and laser printers depends on factors such as the intended use, required print quality, volume of printing, and budget.
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In order to be a Mechanical Engineer, you need to:
1. Have a Bachelor's Degree
2. Have a Master's Degree
3. Have a Ph.D.
Answer:
3
Explanation:
it is compulsory to have a bachelor's degree
The accompanying specific gravity values describe various wood types used in construction. 0.320.350.360.360.370.380.400.400.40 0.410.410.420.420.420.420.420.430.44 0.450.460.460.470.480.480.490.510.54 0.540.550.580.630.660.660.670.680.78 Construct a stem-and-leaf display using repeated stems. (Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
Answer:
\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)
Explanation:
Given
\(0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38,\ 0.40,\ 0.40,\ 0.40,\ 0.41,\)
\(0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.43,\ 0.44,\ 0.45,\ 0.46,\)
\(0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49,\ 0.51,\ 0.54,\ 0.54,\ 0.55,\)
\(0.58,\ 0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68,\ 0.78.\)
Required
Plot a steam and leaf display for the given data
Start by categorizing the data by their tenth values:
\(0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38.\)
\(0.40,\ 0.40,\ 0.40,\ 0.41,\ 0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\)
\(0.43,\ 0.44,\ 0.45,\ 0.46,\ 0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49.\)
\(0.51,\ 0.54,\ 0.54,\ 0.55,\ 0.58.\)
\(0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68.\)
\(0.78.\)
The 0.3's is will be plotted as thus:
\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \ \end{array}\)
The 0.4's is as follows:
\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \ \end{array}\)
The 0.5's is as follows:
\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \ \end{array}\)
The 0.6's is as thus:
\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \ \end{array}\)
Lastly, the 0.7's is as thus:
\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)
The combined steam and leaf plot is:
\(\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}\)
A series resistive circuit has two resistors. R1 is 570 ohms and R2 is 560 ohms.
The total circuit current is 17.9 milliamps.
Find the voltage drop across R1 in volts.
Answer:
10.203 Volts
Explanation:
For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.
First, we need to find the voltage in the circuit. To do this, we need to find the total resistance of the circuit. When two resistors are in series, you sum the resistance. So we can say the following:
R_Total = R1 + R2
R_Total = 570 Ω + 560 Ω
R_Total = 1130 Ω
Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.
V_Total = I_Total * R_Total
V_Total = 17.9 mA * 1130 Ω
V_Total = 20.227 V
Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more. Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).
V_Total = V_1 + V_2
V_Total = V_1 + I_2*R2
V_Total - I_2*R2 = V_1
20.227 V - (17.9 mA * 560 Ω) = V_1
20.227 V - (10.024 V) = V_1
10.203 V = V_1
Hence, the voltage drop across R1 is 10.203 Volts.
Cheers.
In the High Low Logic Index low levels are bearish and high levels are bullish, generally True False
Answer:
True
Explanation:
Logic index is selection of values based on the logical streams. The values appear on the logical array. The levels are determined on the market investment performance. If there are many buyers available in the market the index will be high and the market will be bullish. If there are few or no investors available the market index will be low which means the market is bearish.
A machine is required to produce an output force of 600 newtons. If the machine has a mechanical advantage of 6, what input force must be applied to the machine?.
The input force that must be used if the machine has a mechanical advantage of 6 is 600 N / 6 = 100 N. Output / Input = MA
When a force of 500 N is supplied to a machine, what mechanical advantage does the machine have when applying a force of 1000 N to an object?The efficiency of a machine is 80%. How much labor must be put into the machine for it to produce 50,000 J of work? The mechanical advantage of a machine is 4.5.
How is output force determined?Simply multiply the input force by the mechanical advantage ratio to determine the output force.
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A platinum resistance temperature detector has a resistance of 100.00 V at 0°C, 138.50 V at 100°C and 175.83 V at 200°C. What will be the nonlinearity error in °C at 100°C if the detector is assumed to have a linear relationship between 0 and 200°C?
Answer:
about 1.54 °C
Explanation:
The error will be the difference between the temperature interpreted from the resistance value and the actual temperature. The linear equation used to translate the resistance reading to temperature will be ...
T = (200 -0)/(175.83 -100.00)(R -100.00)
T ≈ 2.637479(R -100)
At the temperature of 100°C, the resistance value of 138.50 will be interpreted to be a temperature of ...
T = 2.637479(138.50 -100) ≈ 101.543°C
This represents an error of 1.543°C relative to the actual temperature.
what is the effect of impacts on the structure? on the structure course
Explanation:
Structure controls the major elements of a story, including plot, characters, setting, and theme. ... In this, we see the plot introduced, a crisis or complication, and a resolution. The structure affects the meaning of the story by organizing the theme of the writing.
There are several books placed in the HackerStudy library. One of those books on mathematics described an interesting problem that a mathematician wishes to solve. For an array arrofnintegers, the mathematician can perform the following move on the array: 1. Choose an indexi(0≤i
Using the knowledge of computational language in python it is possible to write a code that There are several books placed in the HackerStudy library.
Writting the code:include<iostream>
using namespace std;
long getMaximumScore(int arr[],int k,int n)
{
long count=0,sum=0;
for(int i=0;i<n-1;i++)
{
for(int j=0;j<n-i-1;j++)
{
if(arr[j+1]>arr[j])
{
arr[j+1]=arr[j+1]+arr[j];
arr[j]=arr[j+1]-arr[j];
arr[j+1]=arr[j+1]-arr[j];
}
}
}
for(int i=0;i<n;i++)
{
if(count==k)
return sum;
else
{
sum=sum+arr[i];
count++;
}
}
}
int main()
{
int n,k;
cin>>n;
int arr[n];
for(k=0;k<n;k++)
cin>>arr[k] ;
cin>>k;
cout<<getMaximumScore(arr,k,n);
return 0;
}
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what is the primary receptor used in night vision?
The primary receptor used in night vision is the rod cells in the retina. The rod cells in the retina play a crucial role in enabling night vision by capturing and amplifying available light, allowing individuals to see in dimly lit or dark conditions.
The retina of the human eye contains two types of photoreceptor cells: rods and cones. While cones are responsible for color vision and work best in bright light conditions, rods are more sensitive to low levels of light and are primarily responsible for night vision. Rod cells contain a pigment called rhodopsin, which undergoes a chemical reaction when exposed to light, allowing them to detect and transmit signals in low-light environments.
The rod cells in the retina play a crucial role in enabling night vision by capturing and amplifying available light, allowing individuals to see in dimly lit or dark conditions. Their high sensitivity makes them essential for detecting objects and perceiving shapes and movements in low-light environments.
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An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building. c. The development of the last remaining lots in an existing developed area, the new development within an area already served by existing infrastructure and services, or the reuse of already developed, but vacant properties. d. The practice of creating structures and using processes that are environmentally responsible and resource-efficient throughout a building's life-cycle from siting to design, construction, operation, maintenance, renovation and deconstruction.
Answer:
b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.
Explanation:
An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.
It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.
Cellular network towers are configured in such a way so that they avoid what type of problem?
Answer:
They are configured this way to avoid overlap issues.
Explanation:
What is polarized electrical receptacle used for
Answer:
they are used for electrical currents so that they can flow along the appropriate wires in the circuit
Explanation:
To ensure safety and reliable electrical connections, polarized electrical receptacles are employed.
It is frequently seen in both residential and commercial structures and has two slots, one of which is broader than the other.
In a polarised outlet, the neutral slot is broader than the hot slot, which is smaller. To ensure that electrical appliances or gadgets are connected correctly and consistently, this design was created.
By ensuring a steady flow of energy through the instrument, polarization lowers the chance of electric shock.
Thus, it's crucial to remember that not all electrical appliances need polarized plugs.
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stream enters a 3-cm-diameter pipe at 80 bar and 700°c with a velocity of 150 m/s. determine the mass flow rate, in kg/
The flow rate, in kilograms per second, of the stream entering the 3-cm-diameter pipe at 80 bar and 700°C with a velocity of 150 m/s is 11.3 kg/s.
How to determine the flow rate of the stream?To determine the mass flow rate of the stream, we need to use the mass conservation equation, which states that the mass flow rate is constant along a stream tube:
ρAV = constant
where ρ is the density of the stream, A is the cross-sectional area of the pipe, and V is the velocity of the stream.
First, we need to determine the density of the stream using the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.
Assuming the stream is an ideal gas and using the given values, we can solve for the density:
ρ = (P / RT)
where:
P = 80 bar = 8 x 10⁶ Pa (since 1 bar = 10⁵ Pa) R = 8.314 J/(mol K)T = 700°C + 273.15 = 973.15 K.Then the density is:
ρ = (8 x 10⁶ Pa) / (8.314 J/(mol K) x 973.15 K) = 106.2 kg/m³
Next, we can calculate the cross-sectional area of the pipe using the formula for the area of a circle:
A = πr²
where r is the radius of the pipe, which is half the diameter.
r = 1.5 cm = 0.015 m
A = π(0.015 m)² = 7.07 x 10⁻⁴ m²
Finally, we can use the mass conservation equation to solve for the mass flow rate:
ρAV = constant
flow rate = ρAV
flow rate = (106.2 kg/m³)(7.07 x 10^⁻⁴ m²)(150 m/s) = 11.3 kg/s
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The advantages of swamped amplifiers include higher input impedance, less loading effect, and higher stability against temperature change. The disadvantage of the CE swamped amplifier is the reduction of the voltage gain compared to regular CE amplifiers that are unstable against changes of time
The statement you provided contains a mix of accurate and inaccurate information. Let's break it down and clarify each point such as Advantages of Swamped Amplifiers and Reduced Loading Effect.
Swamping a transistor amplifier involves connecting a resistor in parallel with the emitter resistor. This configuration increases the input impedance of the amplifier, which can be advantageous in certain applications. A higher input impedance allows for easier coupling of signal sources with different output impedances and reduces the loading effect on the preceding stages of the amplifier.
By swamping the emitter resistor, the voltage gain of the amplifier becomes less dependent on the load connected to its output. This means that changes in the load impedance have less impact on the overall performance of the amplifier. Swamped amplifiers are thus less affected by variations in the connected load compared to non-swamped configurations.
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1. Why is the perfect elastic-plastic model adopted in steel design?
Answer:
Explained below
Explanation:
Perfect Elastic Plastic in steel design is simply a method whereby the structural members are selected using the criteria of the overall ultimate capacity of the system. However, when safety is considered, the applied loads are usually increased by factors of safety as prescribed in the relevant steel design codes. Therefore, this model of design is just based on the yield capacity of the steel.
In the simplest of terms Interior design can be broken down as the art of designing the internal shell of a building , be it commercial or residential.
What components should you inspect if the crankshaft end play is out of specifications?
Answer:
gdyc ddxtfvytg4dgtfxdwcftcd3rcby
If the crankshaft end play is out of specifications, check for:
Thrust Bearings
Main Bearings
Crankshaft
Crankshaft Thrust Washers
Engine Block
To understand the crankshaft when it is out of specifications, check for:
Thrust Bearings: Check the condition of the thrust bearings, which are located at the front and/or rear of the engine block. Excessive wear or damage to the thrust bearings can contribute to increased crankshaft end play.
Main Bearings: Inspect the main bearings, which support the crankshaft within the engine block. Worn or damaged main bearings can cause excessive movement of the crankshaft.
Crankshaft: Check the crankshaft itself for any signs of damage, such as scoring or bending. A damaged crankshaft may not sit properly within the bearings, leading to increased end play.
Crankshaft Thrust Washers: Some engines use thrust washers to control the end play of the crankshaft. Inspect these washers for wear, damage, or improper installation.
Engine Block: Check the engine block for any signs of damage or distortion that may affect the alignment and support of the crankshaft.
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*sapnap teaching you how to drive*
"Skeppy and Badboyhalo are crossing the street, what do you hit?"
"Skeppy, I would never hurt Bad."
"whA- THE BRAKES YOU HIT THE BREAKS!!"
*Dream wheezing from the back*
Answer:
yes dream
Explanation:
Answer:
Me: "i would just hit you, sapnap. In the freaking face" LOL
Elana has opened a new aerobics studio in her area. How might Elana use social media as a market to spread the word about her new studio? Make a list of hashtags that Elana might use to attract interest to her posts.
Answer:
A list of hashtags that will help Elena's aerobic studio are:
Explanation:
#aerobics #aerobicsstudio #workout #gym #fitness #exercise #burnout #dance #lifestyle #healthylifestyle #yoga #motivation #weightloss #slimfit #health #livinghealthy #cardio #cardiohealth #hearthealth #funworkout #cardiodance #fitnessdance #bodybalance #burncalories #hitworkout
A power plant operates on a regenerative vapor power cycle with one open feedwater heater. Steam enters the first turbine stage at 12 \mathrm{MPa}, 560^{\circ} \mathrm{C}12MPa,560 ∘ C and expands to 1 MPa, where some of the steam is extracted and diverted to the open feedwater heater operating at 1 MPa. The remaining steam expands through the second turbine stage to the condenser pressure of 6 kPa. Saturated liquid exits the open feedwater heater at 1 MPa. The net power output for the cycle is 330 MW. For isentropic processes in the turbines and pumps,
determine:
a. the cycle thermal efficiency.
b. the mass flow rate into the first turbine stage, in kg/s.
c. the rate of entropy production in the open feedwater heater, in kW/K.
Answer:
a. 46.15%
b. 261.73 kg/s
c. 54.79 kW/K
Explanation:
a. State 1
The parameters given are;
T₁ = 560°C
P₁ = 12 MPa = 120 bar
Therefore;
h₁ = 3507.41 kJ/kg, s₁ = 6.6864 kJ/(kg·K)
State 2
p₂ = 1 MPa = 10 bar
s₂ = s₁ = 6.6864 kJ/(kg·K)
h₂ = (6.6864 - 6.6426)÷(6.6955 - 6.6426)×(2828.27 - 2803.52) + 2803.52
= (0.0438 ÷ 0.0529) × 24.75 = 2824.01 kJ/kg
State 3
p₃ = 6 kPa = 0.06 bar
s₃ = s₁ = 6.6864 kJ/(kg·K)
sg = 8.3291 kJ/(kg·K)
sf = 0.52087 kJ/(kg·K)
x = s₃/sfg = (6.6864- 0.52087)/(8.3291 - 0.52087) = 0.7896
(h₃ - 151.494)/2415.17 = 0.7896
∴ h₃ = 2058.56 kJ/kg
State 4
Saturated liquid state
p₄ = 0.06 bar= 6000 Pa, h₄ = 151.494 kJ/kg, s₄ = 0.52087 kJ/(kg·K)
State 5
Open feed-water heater
p₅ = p₂ = 1 MPa = 10 bar = 1000000 Pa
s₄ = s₅ = 0.52087 kJ/(kg·K)
h₅ = h₄ + work done by the pump on the saturated liquid
∴ h₅ = h₄ + v₄ × (p₅ - p₄)
h₅ = 151.494 + 0.00100645 × (1000000 - 6000)/1000 = 152.4944113 kJ/kg
Step 6
Saturated liquid state
p₆ = 1 MPa = 10 bar
h₆ = 762.683 kJ/kg
s₆ = 2.1384 kJ/(kg·K)
v₆ = 0.00112723 m³/kg
Step 7
p₇ = p₁ = 12 MPa = 120 bar
s₇ = s₆ = 2.1384 kJ/(kg·K)
h₇ = h₆ + v₆ × (p₇ - p₆)
h₇ = 762.683 + 0.00112723 * (12 - 1) * 1000 = 775.08253 kJ/kg
The fraction of flow extracted at the second stage, y, is given as follows
\(y = \dfrac{762.683 - 152.4944113 }{2824.01 - 152.4944113 } = 0.2284\)
The turbine control volume is given as follows;
\(\dfrac{\dot{W_t}}{\dot{m_{1}}} = \left (h_{1} - h_{2} \right ) + \left (1 - y \right )\left (h_{2} - h_{3} \right )\)
= (3507.41 - 2824.01) + (1 - 0.22840)*(2824.01 - 2058.56) = 1274.02122 kJ/kg
For the pumps, we have;
\(\dfrac{\dot{W_p}}{\dot{m_{1}}} = \left (h_{7} - h_{6} \right ) + \left (1 - y \right )\left (h_{5} - h_{4} \right )\)
= (775.08253 - 762.683) + (1 - 0.22840)*(152.4944113 - 151.494)
= 13.17 kJ/kg
For the working fluid that flows through the steam generator, we have;
\(\dfrac{\dot{Q_{in}}}{\dot{m_{1}}} = \left (h_{1} - h_{7} \right )\)
= 3507.41 - 775.08253 = 2732.32747 kJ/kg
The thermal efficiency, η, is given as follows;
\(\eta = \dfrac{\dfrac{\dot{W_t}}{\dot{m_{1}}} -\dfrac{\dot{W_p}}{\dot{m_{1}}}}{\dfrac{\dot{Q_{in}}}{\dot{m_{1}}}}\)
η = (1274.02122 - 13.17)/2732.32747 = 0.4615 which is 46.15%
(762.683 - 152.4944113)/(2824.01 - 152.4944113)
b. The mass flow rate, \(\dot{m_{1}}\), into the first turbine stage is given as follows;
\(\dot{m_{1}} = \dfrac{\dot{W_{cycle}}}{\dfrac{\dot{W_t}}{\dot{m_{1}}} -\dfrac{\dot{W_p}}{\dot{m_{1}}}}\)
\(\dot{m_{1}}\) = 330 *1000/(1274.02122 - 13.17) = 261.73 kg/s
c. From the entropy rate balance of the steady state form, we have;
\(\dot{\sigma }_{cv} = \sum_{e}^{}\dot{m}_{e}s_{e} - \sum_{i}^{}\dot{m}_{i}s_{i} = \dot{m}_{6}s_{6} - \dot{m}_{2}s_{2} - \dot{m}_{5}s_{5}\)
\(\dot{\sigma }_{cv} = \dot{m}_{6} \left [s_{6} - ys_{2} - (1 - y)s_{5} \right ]\)
= 261.73 * (2.1384 - 0.2284*6.6864 - (1 - 0.2284)*0.52087 = 54.79 kW/K
A Field Check is an abbreviated calibration procedure
performed at a work site.
True or false?
Answer:
true
Explanation:
hope this helps!
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A car is driven over a curb twice—once very slowly and once quite rapidly. What would you need to know about the car in the second case that you did not need to know in the first case if you were required to find the tire force that resulted from going over the curb?
Answer:
You'd need to know things like the weight of the car, the spring constant of the suspension springs.
Explanation:
Driving over the curb slowly does not have much of an "impact" because of the small potential energy it has but to find the force that results from going over the curb at a much higher speed, you would need to know the weight of the car since it directly impact the force that it applies. You also would need to know about the car's suspension, the spring material, how stiff the springs are and their spring constant to calculate the force they absorb.
I hope this answer helps.
technician a says that an electrical short circuit causes excess current flow. technician b says a short causes excess resistance to develop. who is right?
Technician A is correct. A short circuit causes excess current flow due to the decreased resistance within the circuit.
What is Resistance?
Resistance is opposition to the flow of electric current. It is an electrical property of a material, measured in ohms, which is represented by the Greek letter Omega (Ω). Resistance is caused by the collisions of electrons with the atoms of the material. The higher the resistance, the more collisions occur, which means that the current is being slowed down. Resistance can be used to control the current in electrical circuits and devices, such as resistors and transistors. Resistance is also used to convert electrical energy into thermal or mechanical energy, or to create electromagnetic fields.
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True or false for the 4 questions?
Answer:
true, false, true, true
Explanation:
what are the advantages and disadvantages of dynamic programming in operations research?
Answer:
ADVANTAGES
1.for the various problems in areas such as inventory chemical engineering design and control theory dynamic programming is the only technique used to solve the problem
2. it is well suited for multi-stage or multi-point or sequential decision process
3. it is suitable for linear or nonlinear problems discrete or continuous variables and deterministic problems
DISADVANTAGE
1. no general formation of dynamic program is available; every problem has to be solving in its own way
2. dividing problem in sub problem and storing intermediate results consumes memory.
Explanation:
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