Which of the following is NOT an interaction among body systems?
A. The circulatory system works with the digestive system to deliver digested nutrients to cells.
B. The nervous system send signals to the musculoskeletal system to cause movement.
C. The excretory system works with the circulatory system to remove toxic carbon dioxide from cells.
D. The immune system gathers information for the respiratory system to aid in white blood cell production.

it would be the 3rd one. so C

Answer:

B-C

D-E

Explanation:

Trust

Answer:

B-C and D-E are correct

Explanation:

Answer:

xxxxx

Explanation:

Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a Volume (the same volume as 1 milliliter).

Answer:

rocks are vertical.

Explanation:

I'm so sorry if I'm wrong this is what I think

Newton's second law allows finding the result for the comparison of the rise and fall times of the block on the ramp is:

Newton's second law establishes a relationship between the net force, the masses and the acceleration of the bodies.  

         ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

The reference system is a coordinate system with respect to which the forces are drawn, in the attached we can see a free body diagram of the block going up and down the ramp, in this case the x axis is parallel to the ramp and the y axis it is perpendicular.

Let's use trigonometry to find the components of weight.

         sin θ = \(\frac{W_x}{W}\)  

         cos θ = \(\frac{W_y}{W}\)  

         Wₓ = W sin θ

          \(W_y\) = W cos θ

Let's write Newton's second law for each axis.

Case 1. block slides down.

x- axis

         Wₓ = ma

         mg sin θ = ma

         a = g sin θ

Case 2. block rises

X axis

         - Wₓ = m a

         - m gsin θ = a

          a = - g sin θ

We can see that the acceleration is the same in two two cases, if the block has the same initial speed, the rise and fall time is the same.

           y = v₀ t - ½ a t²

            y = ½ a t²

In conclusion using Newton's second law we can find the result for the comparison of the rise and fall times of the block on the ramp is:

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According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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Since speed is 0 when at rest. Only while moving does an object have kinetic energy.

The power behind motion is called kinetic energy.

KE = (0.5) m v2 is the equation for kinetic energy.

m denotes the object's mass, and v its speed.

An object at rest has no kinetic energy because it is at rest because its speed is zero, whereas an object moving at some speed and mass will have kinetic energy.

since speed is 0 when at rest. Only while moving does an object have kinetic energy.

An object at rest has no kinetic energy because it is at rest because its speed is zero, whereas an object moving at some speed and mass will have kinetic energy.

Since speed is 0 when at rest. Only while moving does an object have kinetic energy.

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Answer:

Hopefully, this is right.

Explanation:

Answer is 5.43.

Answer:

Just like a solid ,the density of a liquid equals the mass of the liquid by its volume;D=m/v. The density of the water is 1 gram per cubic centimeter. The density of a substance is the same regardless of the size of the sample.

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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After pushing the pumpkin hard, you find yourself reversing direction at a speed of 4.0 m/s. 3.0 seconds after being pushed, the pumpkin will slide 12 m. Assume you weigh 60.0 kg.

We can use the conservation of momentum to solve this problem. After the push, the momentum of the system is given by:

p = (449 kg + 60 kg) * v

where v is the speed of the pumpkin and you after the push. Since you end up sliding backward at 4.0 m/s, we have:

v = -4.0 m/s

Substituting this into the expression for momentum, we find:

p = (449 kg + 60 kg) * (-4.0 m/s) = -2036 kg·m/s

The negative sign indicates that the momentum of the system is in the opposite direction of your motion.

During the sliding motion, the net force on the system is given by:

Fnet = (449 kg + 60 kg) * g * sin(θ)

where g is the acceleration due to gravity (9.81 m/s^2) and θ is the angle of the ramp. Since the ramp is smooth and horizontal, θ = 0 and Fnet = 0. Therefore, there is no net force to change the momentum of the system.

Using the equation for motion with constant acceleration, we can find the distance the pumpkin slides in 3.0 seconds:

x = x0 + v0t + (1/2)at²

Since the initial speed of the pumpkin is -4.0 m/s and there is no net force acting on it, its speed remains constant during the slide. Therefore, v0 = -4.0 m/s and a = 0. Substituting these values, we find:

x = x0 + v0t = (-4.0 m/s) * (3.0 s) = -12 m

The negative sign indicates that the pumpkin slides in the opposite direction to your motion. Therefore, the pumpkin slides 12 meters backward (i.e., towards you) in 3.0 seconds after the push.

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Answer: d

Explanation:

The magnitude of the resulting angular acceleration about the pivot point is approximately 0.0021 rad/s^2.

To solve this problem, we need to use the equation for the torque on a rigid body:

τ = Iα

where τ is the torque, I is the moment of inertia, and α is the angular acceleration. We can also use the fact that the torque is given by:

τ = r × F

where r is the vector from the pivot point to the point of application of the force, and F is the force. The vector cross product r × F gives the torque about the pivot point.

First, we need to find the vector r. Since the force is acting at an angle of 95° to the horizontal, the vertical component of the force is given by:

Fy = F sin(95°) = 1.5 sin(95°) ≈ 0.15 N

The horizontal component of the force is given by:

Fx = F cos(95°) = 1.5 cos(95°) ≈ 0.04 N

The vector r points vertically downward from the pivot point and has a magnitude equal to half the length of the rod:

|r| = 0.5(1.9 m) = 0.95 m

Therefore, the vector r is given by:

r = -0.95j

where j is the unit vector in the vertical direction.

The torque about the pivot point is given by:

τ = r × F = (-0.95j) × (0.04i + 0.15j) = -0.15k

where i is the unit vector in the horizontal direction and k is the unit vector in the direction perpendicular to the plane of the rod and pointing out of the page.

Substituting the moment of inertia and torque into the equation for angular acceleration, we have:

α = τ/I = (-0.15k)/(930.02/12) ≈ -0.0021 rad/s^2

Therefore, the magnitude of the resulting angular acceleration about the pivot point is approximately 0.0021 rad/s^2.

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Answer:

false.

Explanation:

Since temperature and kinetic energy of molecules are proportional, the more we increase the temperature of the solvent, the faster the solute will dissolve.

This increase of kinetic energy allows the solvent molecules to more effective break apart the solvent molecules that are held together by intermolecular forces.

A C and D

C because ofc when electric charge flow electric field is produced

Answer:

A & D

Explanation:

Given data:

* The potential energy of the pendulum at the swing is U = 15 J.

Solution:

(a). At the top of the swing, the pendulum is in the rest state, thus, the kinetic energy of the pendulum at the top of the swing is,

The net energy of the system at the top of the swing is,

According to the law of conservation of energy, the net energy at the bottom of the swing is the same as the net energy at the top of the swing.

As the value of height at the bottom of the swing is zero, thus, the potential energy of the pendulum at the bottom of the swing is,

Thus, the kinetic energy at the bottom of the swing is,

Thus, the kinetic energy at the bottom of the swing is 15 J.

(b). If the potential energy of the pendulum is,

The kinetic energy of the pendulum is,

Thus, the kinetic energy of the pendulum in the given case is 7 J.

(c). If the loss of 2 J energy takes place, then the kinetic energy in the case b is,

Thus, the kinetic energy of the pendulum in the given case is 5 J.

Part A

The angular separation of the two stars is 0.03 degrees

Part B

The angular separation of the two stars is 108 arcseconds.

Part C

Yes, the Hubble Space Telescope can resolve the two stars.

Angular separation is the angular distance between two objects as seen from a particular point in space. This is usually expressed in degrees, arcminutes, or arcseconds. It is a measure of the angular separation between two objects, such as stars, planets, galaxies, or other celestial objects, as seen from Earth. The angular separation of two objects is the angle between them as seen from the observer's point of view.

For example, the Moon and the Sun have an angular separation of 0.5 degrees when they are in opposition.

Part A:

To find the angular separation of the two stars, we can use the formula:

θ = arctan(d/D)

where θ is the angular separation, d is the physical distance between the two stars, and D is the distance to the stars from Earth.

Substituting the given values, we get:

θ = arctan(100,000,000 km / (200 x 9.461 trillion km))

θ = arctan(100,000,000 km / 1.8922 x 10^15 km)

θ = 0.03 degrees

Therefore, the angular separation of the two stars is 0.03 degrees.

Part B:

To convert degrees to arcseconds, we can use the formula:

1 degree = 3600 arcseconds

Substituting the value we found in part A, we get:

θ = 0.03 degrees x 3600 arcseconds/degree

θ = 108 arcseconds

Therefore, the angular separation of the two stars is 108 arcseconds.

Part C:

To determine if the Hubble Space Telescope (HST) can resolve the two stars, we need to compare the angular separation of the stars to the angular resolution of the HST. The angular resolution of a telescope is the smallest angle between two point sources that the telescope can distinguish.

The angular resolution of the HST is about 0.05 arcseconds. Since the angular separation of the two stars is 108 arcseconds, the HST can easily resolve the two stars as separate objects.

Therefore, the HST can resolve the two stars in the binary star system.

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Answer:

Explanation:

1. First draw a free body diagram of the scenerio (a block sliding down a a slant surface).
2. Then we analyze the forces and write equations that satisfy Fnet = ma. This will give us the acceleration as the block slides down the surface.

3. Last, we can use the kinematic equation (vf^2 = vi^2 + 2as) and to solve the final speed of the block.

Answer:

True

Explanation:

Answer:

your answer is true hope this helps

Answer:

it keeps it growing because if it stays warm and yuh put it by a plant that needs sun yk

Explanation:

A flower of a plant that can stay warm at night as it keeps it growing.

The roots are the underground part of the plant which plays a major role in pulling the water and minerals,  expands within the ground  for better water absorption, anchors which helps in creating better stability.

A stem present above the ground bears leaves, fruits plus flowers.  as it distributes the nutrients and minerals to the leaves, shields the plant and assists in asexual dissemination.

leaf is one of the most major parts of a plant as it contain chlorophyll pigment which assists the plants in preparation for food, the veins allow the flowing of nutrients plus water, it has the parts like petiole, leaf base and lamina help in photosynthesis.

Flower is the most bright and beautiful part of the plant show an important role in making food, used in fertilization process , the basic parts are petals, sepals, stamens, and pistil.

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Answer:

Explanation:

work done=force*displacement

=350N*15m

=5250 joule

Answer:

she rode for 166.66 seconds , which is about 2 minutes and 47 seconds

Explanation:

We use the kinematic equation that relates initial and final velocities with time and distance travelled that is shown below:

\(distance=\frac{(v_i+v_f)*t}{2}\)

which in our case gives:

\(distance=\frac{(v_i+v_f)*t}{2}\\500=\frac{(0+6)*t}{2}\\500=3*t\\t=\frac{500}{3} \,s\\t\approx 166.66\,sec\)

which reduced to minutes gives 2 minutes and approximately 47 seconds

Answer:

1) t = 3.45 s, 2)  x = 138 m, 3) v_{y} = -33.81 m /s, 4) v = 52.37 m / s ,

5) θ = -40.2º

Explanation:

This is a projectile exercise, as they indicate that the projectile rolls down the cliff, it goes with a horizontal speed when leaving the cliff, therefore the speed is v₀ₓ = 40 m / s.

1) Let's calculate the time that Taardaen reaches the bottom, we place the reference system at the bottom of the cliff

      y = y₀ + \(v_{oy}\) t - ½ g t²

When leaving the cliff the speed is horizontal  v_{oy}= 0 and at the bottom of the cliff y = 0

      0 = y₀ - ½ g t2

      t = √ 2y₀ / g

      t = √ (2 60 / 9.8)

      t = 3.45 s

2) The horizontal distance traveled

     x = v₀ₓ t

     x = 40 3.45

     x = 138 m

3) The vertical velocity at the point of impact

     v_{y} = I go - g t

     v_{y} = 0 - 9.8 3.45

     v_{y} = -33.81 m /s

the negative sign indicates that the speed is down

4) the resulting velocity at this point

   v = √ (vₓ² + v_{y}²)

   v = √ (40² + 33.8²)

   v = 52.37 m / s

5) angle of impact

    tan θ = v_{y} / vx

    θ = tan⁻¹ v_{y} / vx

    θ = tan⁻¹ (-33.81 / 40)

    θ = -40.2º

6) sin (-40.2) = -0.6455

7) tan (-40.2) = -0.845

8) when the projectile falls down the cliff, the horizontal speed remains constant and the vertical speed increases, therefore the resulting speed has a direction given by the angle that is measured clockwise from the x axis

The change in momentum of Kara's car is -1.43 × 10⁴ kg.m/s, the magnitude of force is -1.021 × 10⁵ N.

Force is the external agent which causes the motion of an object or it is the resistant which makes the object come at rest from motion. It is a vector quantity, because it has both the magnitude and direction.

Mass of Kara's car = 1300 Kg

moving with speed = 11 m/s

time taken to stop = 0.14 s

final velocity = 0 m/s

distance between Lisa ford and Kara's car = 30 m

a) change in momentum of Kara's car

Δ P = m Δ v          

Δ P = m(vf - vi)

Δ P = 1300 (0 - 11)

Δ P = -1.43 × 10⁴ kg.m/s

The impulse is equal to the change in momentum of the car

I = -1.43 × 10⁴ kg.m/s

Magnitude of the force experienced by Kara

I = F × t

where, I is impulse acting on the car

t is time

- 1.43 × 10⁴ = F × 0.14

F = -1.021 × 10⁵ N

Negative sign represents the direction of the force.

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Your question is incomplete, most probably the complete question is:

Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was stopped in her lane 30 feet ahead, Kara rear-ended Lisa's rented Taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds.

a. Determine the momentum change of Kara's car.

b. Determine the impulse experienced by Kara's car.

c. Determine the magnitude of the force experienced by Kara's car.

\(\bold{\huge{\red{\underline{ Solution }}}}\)

Here, We have to,

We know that,

Change in internal energy = heat required + Work done

That is,

\(\bold{\pink{ ΔU = Q + W }}\)

Here, we have,

[ Here, + sign of Q denotes that heat is absorbed in the given chemical reaction and - sign of W denotes work done by the system ]

Subsitute the required values in the given formula :-

\(\sf{ ΔU = + 53 + ( -15) }\)

\(\sf{ ΔU = 53 - 15 }\)

\(\sf{ ΔU = 38kJ }\)

Hence, The change in internal energy is 38kJ and work done is by the system on the surroundings

We know that,

\(\bold{\pink{ ΔU = Q + W }}\)

Here, we have

[ Here, + sign of Q denotes that heat is absorbed in the given chemical reaction and - sign of W denotes work done by the system ]

Subsitute the required values in the above formula :-

\(\sf{ ΔU = + 100 + ( -62) }\)

\(\sf{ ΔU = 100 - 62 }\)

\(\sf{ ΔU = 38kJ }\)

Hence, The change in internal energy is 38kJ and work done is by the system on the surroundings .

We know that,

\(\bold{\pink{ ΔU = Q + W }}\)

Here, we have

[ Here, - sign of Q denotes that heat is evolved in the given chemical reaction and - sign of W denotes work done by the system ]

Subsitute the required values in the above formula :-

\(\sf{ ΔU = - 65 +(-30) }\)

\(\sf{ ΔU = -65 - 30 }\)

\(\sf{ ΔU = - 95kJ }\)

Hence, The change in internal energy is -95 kJ and work done is by the system on the surroundings .

In all the three cases the work done is done by the system that is work is done on the surroundings by the system because work done is negative in all the three cases

Whereas, If work done is positive then work is done on the system not by the system.

The change in internal energy for Q = + 53 kJ, W = - 15 kJ is 38 kJ, for Q = 100 kJ, W = - 62 kJ is 38 kJ, and for Q = - 65 kJ, W = - 30 kJ is -95 kJ.

The energy connected to the disorderly, random motion of molecules is known as internal energy. It refers to the intangible microscopic energy at the atomic and molecular scales, which is distinct in scale from the macroscopic organized energy associated with moving objects. For instance, a glass of water on a table appears to have no apparent energy, either potential or kinetic, at room temperature.

Given:

The energy, Q = \(53 \ kJ\)

The work done, W = \(-15 \ kJ\)

Change in internal energy = heat required + Work done

Δ\(U = Q +W\)

Substitute the values

ΔU = 53-15

ΔU = 38 kJ

Similarly for

Q = + 100. kJ, W = - 62 kJ

ΔU = 38 kJ

Q = - 65 kJ, W = - 30 kJ

ΔU = -95 kJ

Therefore, the changes in internal energy for Q = + 53 kJ, W = - 15 kJ is 38 kJ, for Q = + 100. kJ, W = - 62 kJ is 38 kJ, and for Q = - 65 kJ, W = - 30 kJ is -95 kJ.

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Answer:

100

Explanation:

F = m * a

Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):

F = 0.02 kg * 5 m/s^2 = 0.1 N

So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.

Answer:

50µs

Explanation:

The conversion is that 1 second equals 1,000,000 micro seconds. Since we have 0.00005 seconds, we will multiply that to a million.

0.00005 * 1,000,000 = 50µs

Keep in mind that 50 only has 1 significant figure because any trailing zeroes before the decimal point do NOT count.

Best of Luck!

0.00005 seconds = 50 μs

Thank you

The approximate value of the magnitude of the displacement vector 2D - E is roughly  16.88.

In order to find out the magnitude of the displacement vector 2D - E, you can use these steps:

multiplying  D by 2. this would result to

12i + 6j - 2k

subtracting  E from 2D. this would result to

8i + 11j - 10k

The calculation of Step three entails computing the magnitude of 2D - E where   |V| = sqrt(Vi^2 + Vj^2 + Vk^2)

|2D - E| = sqrt((8^2) + (11^2) + (-10^2))

|2D - E| = sqrt(64 + 121 + 100)

|2D - E| = sqrt(285),

|2D - E| = 16.88 when rounded off to two decimal places.

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