Which best summarizes a concept related to the work-energy theorem?
- When work is positive, the environment does work on an object.
- When work is negative, the environment does work on an object.
- When work is positive, the kinetic energy in a system remains constant.
- When work is negative, the kinetic energy in a system remains constant.

this is times pls help!

Answer:

This difference is kept to a minimum because the resistance in transformers is a few tens of ohms and the resistance of modern voltmeters is of the order of MΩ.

Explanation:

A voltmeter is built by a galvanometer and a resistance in series, this set is connected in parallel to the resistance where the voltage is to be measured, therefore the voltage is divided between the voltmeter and the element to be measured, consequently the measured voltage It is less than the calculated one, since for them the resistance of the voltmeter is assumed infinite.

This difference is kept to a minimum because the resistance in transformers is a few tens of ohms and the resistance of modern voltmeters is of the order of MΩ.

The resulting charge on A is \(1.6 x 10^-7\) C, and the resulting charge on B is \(-3.2 x 10^-7\) C.

A charge is a property of matter that results from the presence or absence of electrons. It can be either positive or negative, and two objects with opposite charges will be attracted to each other, while two objects with the same charge will repel each other. The unit of charge is the Coulomb (C), which is defined as the amount of charge carried by 6.242 x 10^18 electrons. The concept of charge is important in many areas of physics, including electricity and magnetism, and plays a role in many natural phenomena and technological applications.

The charge on object A is \(-1.6 X10^-13\)C.

When two million electrons are removed from object A, the charge on object A becomes more negative. The charge on object A can be calculated using the formula:

Q = Q - ne,

where Q is the original charge, n is the number of electrons, and e is the charge of an electron, which is -1.6 x 10^-19 C.

Therefore, the charge on object A becomes:

\(Q = -1.6 X 10^-13 C - (2X10^6)(-1.6X 10^-19 C)\)

\(= -1.6 X 10^-13 C + 3.2X 10^-7 C\)

= 1.6 x 10^-7 C

Object B starts as electrically neutral, which means that the total charge on B is 0 C. When two million electrons are placed on object B, the charge on object B becomes more negative. The charge on object B can be calculated using the formula:

Q = Q + ne,

where Q is the original charge, n is the number of electrons, and e is the charge of an electron, which is -1.6 x 10^-19 C.

Therefore, the charge on object B becomes:

Q = 0 C + (2 x 10^6)(-1.6 x 10^-19 C)

\(= -3.2 X 10^-7 C.\)

So, the resulting charge on A is\(1.6 X 10^-7\)C, and the resulting charge on B is \(-3.2X 10^-7\) C.

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With 4.3 m/s velocity, is the cheetah running.

velocity= distance/time

distance=27.6 m

time=6.3 s

velocity=27.6 m/6.3 s

velocity=4.3 m/s

A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity. As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item.

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Answer:

All 7 Dragonballs

Explanation:

the dragonball Summon shenron which will then grant you a wish

Answer:

it is chemical energy

Explanation:

that is the energy used by our body, so it is the one that we will loose. and the energy that we gain is also chemical energy

The input AC provided to the full wave rectifier is very high. The step-down transformer in the rectifier circuit transforms the high voltage AC into low voltage AC.

The secondary winding of the transformer and the load resistor are connected by the anode of the center-tapped diodes. The top half of the secondary winding turns positive while the bottom half turns negative during the positive half cycle of the alternating current . Diode D1 is forward biassed during the positive half cycle because it is connected to the top of the secondary winding, but diode D2 is reverse biassed since it is connected to the bottom of the secondary winding.

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Given,

Voltage, V=9 V

Resistor, R=50.0 ohm

To find

The power emitted by the battery.

Explanation

The power is:

Conclusion

The power is: C.1.62W

Answer:

True

Explanation:

Answer:

True

Explanation:

The four spheres of atmosphere are

Water begins its journey from hydrosphere then goes through atmosphere, biosphere and geosphere respectively

Answer:

0.87 g per ml

Explanation:

D=M/V

43.5/50=0.87

To ensure proper airspace protection while holding at5,000 feet in a civil aircraft, the maximum indicated airspeed a pilot should use is 200 knots.

Indicated airspeed means that the speed of an aircraft as shown on pitot static airspeed indicator is calibrated to reflect standard atmosphere adiabatic compressible flow at sea level uncorrected for airspeed system errors.

Indicated airspeed is the airspeed which is read directly from the airspeed indicator on an aircraft and driven by the pitot-static system. It uses difference between total pressure and static pressure, to mechanically or electronically measure dynamic pressure.

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To find z = w/x and its uncertainty, we can use the formula for propagating uncertainties. The formula for z = w/x can be expressed as
z = w * (1/x).

The uncertainty refers to the range or interval within which the calculated value of z is expected to lie. To determine the uncertainty in z, we use the formula for propagating uncertainties, which takes into account the uncertainties in the measured values of w and x. The uncertainties in w and x are expressed as ± values, representing the range within which the true values of w and x are expected to lie.

Given that w = (4.52 ± 0.02) cm and x = (2.0 ± 0.2) cm, we can substitute these values into the formula. First, let's calculate the central value of z:

z = w * (1/x) = (4.52 cm) * (1/2.0 cm) = 2.26

Next, let's calculate the uncertainty in z using the formula for propagating uncertainties:

Δz = |z| * √((Δw/w)^2 + (Δx/x)^2)

where Δw and Δx are the uncertainties in w and x, respectively. Substituting the values into the formula:

Δz = |2.26| * √((0.02/4.52)^2 + (0.2/2.0)^2) = 0.059

Therefore, the value of z is 2.26 with an uncertainty of 0.059.

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(a) The electric field at a point 5.0 cm from the negative charge and along the line between the two charges is -2.58825 x 10⁵ N/C, directed towards the negative charge. (b) The force on an electron placed at that point is 2.58825 x 10⁻⁵ N, directed towards the positive charge.

The electric field at a point due to a point charge is given by the equation E = k * q / r², where E is the electric field, k is the electrostatic constant (k = 9 x 10⁹Nm² /C² ), q is the charge, and r is the distance between the charges.

(a) To find the electric field at a point 5.0 cm from the negative charge, we need to calculate the electric field due to both charges and then subtract the electric field due to the positive charge from the electric field due to the negative charge.

The electric field due to the negative charge (q2) is given by E2 = k * q2 / r², where q2 = -6.4 x 10⁻⁸  C and r = 5.0 cm = 0.05 m.

Plugging in the values, we get E2 = (9 x 10 Nm² /C² ) * (-6.4 x 10 C) / (0.05 m)² = -2.58825 x 10⁵ N/C.

The negative sign indicates that the electric field due to the negative charge is directed towards the negative charge.

(b) To find the force on an electron placed at that point, we need to calculate the force due to both charges and then subtract the force due to the positive charge from the force due to the negative charge.

The force between two charges is given by the equation F = k * |q1 * q2| / r², where F is the force, q1 and q2 are the charges, and r is the distance between the charges.

The force on the electron due to the negative charge (q2) is given by F2 = k * |q2 * e| / r², where q2 = -6.4 x 10⁻⁸ C, e is the charge of an electron (e = -1.6 x 10⁻¹⁹ C), and r = 5.0 cm = 0.05 m.

Plugging in the values, we get F2 = (9 x 10⁹ Nm²/C²) * |-6.4 x 10⁻⁸ C * -1.6 x 10⁻¹⁹ C| / (0.05 m)² = 2.58825 x 10⁻⁵ N.

The positive sign indicates that the force on the electron is directed away from the negative charge, which is towards the positive charge.

So, the answers to the given questions are:

(a) The electric field at a point 5.0 cm from the negative charge and along the line between the two charges is -2.58825 x 10⁵ N/C, directed towards the negative charge.

(b) The force on an electron placed at that point is 2.58825 x 10⁻⁵ N, directed towards the positive charge.

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Answer:

1 x 10 -10 whisper at 1m distance.

Explanation:

Answer:

The change in intensity is 63%.

Explanation:

intensity level = 18 db

Let the intensity is I.

Io = 10^(-12) W/m^2

Use the formula of intensity

\(dB = 10 log\left ( \frac{I}{Io} \right )\\\\18 = 10 log\left ( \frac{I}{Io} \right )\\\\1.8 = log\left ( \frac{I}{Io} \right )\\\\\left ( \frac{I}{Io} \right )=63.1\)

So, the change in intensity is 63%.

The term that fills the blank in the statement "Turn your head left and right and glance over your shoulder to view what cannot be seen in the side-view mirrors" is "left and right"

The statement "Turn your head left and right and glance over your shoulder to view what cannot be seen in the side-view mirrors" is a complete sentence that is easy to comprehend. It is usually suggested to follow the rules of safe driving and never rely solely on the car's side-view mirrors.

Drivers should always be cautious when they change lanes or merge into traffic because there might be blind spots that aren't apparent to the driver in the car's side-view mirrors.To verify whether there are any vehicles approaching, drivers must glance left and right while looking over their shoulders. It is a smart way to ensure that you are secure while driving on the road.

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Answer:

B. 24.2 m/s

Explanation:

Given;

mass of the roller coaster, m = 450 kg

height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster  due to its height is given by;

\(P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J\)

\(P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)\)

\(K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\ v_{max} = 24.2 \ m/s\)

Therefore, the maximum speed of the roller coaster is 24.2 m/s.

Answer:

1. 24.2 m/s

2. 20.4 m

3. 22.5 m/s

4. 109,375 J

5. It is easy to calculate new scenarios.

Explanation:

5/5 on the Maximum Energy Quick Check

Answer:

None of the statements are correct.

Explanation:

There is no mention of potential energy in the given information, so it is not correct to say that there are 1,900 joules of potential energy in this system.

It is not correct to say that 900 joules of energy are destroyed in this system. Energy cannot be destroyed, it can only be converted from one form to another or transferred from one place to another.

It is not correct to say that 2,500 joules of work are being done by this model engine. Work is defined as the product of force and displacement, and the given information does not include any information about force or displacement.

It is not correct to say that 1,000 joules of energy leave the system. The given information only states that the thermal energy of the engine increases by 900 joules, but does not specify whether any other forms of energy leave the system.

It is correct to say that 1,500 joules of kinetic energy are produced by this model engine for every 3,400 joules of chemical energy taken in. However, it is not correct to say that this energy can be used to move an object without any further information about the object or the conditions under which the energy would be used.

Answer:

A

Explanation:

Hopefully this helps

Answer:

A

Explanation:

The acceleration of the baseball is 97.56 m/s^2.

To find the acceleration of the baseball, we can use the formula for acceleration, which is acceleration = change in velocity / time. In this case, the change in velocity is 40 m/s (the final velocity) minus 0 m/s (the initial velocity), which is 40 m/s. The time is given as 0.41 s.

So, the acceleration of the baseball can be calculated as follows:

acceleration = 40 m/s / 0.41 s

acceleration = 97.56 m/s^2

This means that the velocity of the baseball is increasing by 97.56 m/s every second, which is a very high rate of acceleration. This acceleration is likely due to the force exerted by the pitcher's arm and the resistance of the air on the baseball as it travels through the air.

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Answer:

Explanation:

Fe has 2 Fe ions making up Fe2O3

There are 3 oxygen ions making up Fe2O3

There are 3*2 = 6 hydrogen ions making up 3H2

If you haven't been told what an ion is, you can use atoms in your answer, but it is not entirely correct.

Answer:

answer is 2, 3, and 6

Explanation:

cuz it is

The calculated root mean square (RMS) velocity of Cl₂ at -23.0°C is approximately 412 m/s.

To calculate the RMS velocity, we can use the following formula: v(rms) = √((3 * R * T) / (M))Where:- v(rms) represents the root mean square velocity - R is the ideal gas constant (8.314 J/(mol·K))- T is the temperature in Kelvin (K) - M is the molar mass of the gas in kilograms per mole (kg/mol) First, we need to convert the temperature from Celsius to Kelvin: T(K) = T(°C) + 273.15 T(K) = -23.0°C + 273.15 T(K) ≈ 250.15 K The molar mass of Cl₂ is 70.906 g/mol, which is equivalent to 0.070906 kg/mol. Now, we can substitute the values into the formula to calculate the RMS velocity: v(rms) = √((3 * 8.314 J/(mol·K) * 250.15 K) / (0.070906 kg/mol)) v (rms) ≈ 412 m/s Therefore, the root mean square velocity of Cl₂ at -23.0°C is approximately 412 m/s.

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Answer:

False

Explanation:

The softball is bigger, but it is lighter, which means it has a better chance of getting farther way faster with a lighter amount of force. On the other hand, the golfball is heavier, which would take more force to move it a certain distance.

Answer: false

Explanation:

• Defines what the “natural” states of motion are, either at rest and constant

velocity. In essence, the first law sets up the basis to define what accelerated

motion is, which we address with Newton’s 2nd law.

• Defines the type of coordinate systems so that Newton’s laws are valid. These

coordinate systems are called inertial reference frames.

All strings over the single alphabet a are accepted by M and L(M) = L.

Given a language L ⊆ Σ* recognized by a FA and |Σ|= 1, then there is a DFA M = (K, Σ, δ, s0, F) with |F|= 1 such that L = L(M).This is true for the following reasons:

If a language L ⊆ Σ* is recognized by a FA, it means there exists an FA such as N = (Q, Σ, δ, q0, F) that recognizes L.

Also, given |Σ| = 1, it means the number of symbols in the alphabet of the language is one.

Thus, Σ = {a}. Then, since |F| = 1, there's only one final state in the DFA. Thus, we can have M = (K, Σ, δ, s0, F) with |F|= 1 such that L = L(M) for some state 's'.

Therefore, all strings over the single alphabet a are accepted by M and L(M) = L. Thus, the above assertion holds.

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Answer: the theory that all matter is made up of tiny indivisible particles (atoms). According to the modern version, the atoms of each element are effectively identical, but differ from those of other elements, and unite to form compounds in fixed proportions.

Answer:

C.)

Explanation:

The theory that all matter is made up of tiny indivisible particles (atoms). According to the modern version, the atoms of each element are effectively identical, but differ from those of other elements, and unite to form compounds in fixed proportions.

Answer:

Approximately \(1.5\; {\rm s}\).

(Assumptions: \(g = 9.81\; {\rm m\cdot s^{-2}}\); air resistance on the volleyball is negligible.)

Explanation:

Under the assumptions, acceleration of the volleyball would be \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\) during the entire flight. (This value is negative since the ball is accelerating downwards- toward the ground.)

By the time the volleyball hits the ground, the volleyball would be at a position \(2.0\; {\rm m}\) below where it was launched. In other words, the (vertical) displacement of the volleyball during the entire flight would be \(x = (-2.0)\; {\rm m}\). (Negative since the ball is below where it was launched.)

Apply the SUVAT equation \((v^{2} - u^{2}) = 2\, a\, x\) to find the velocity of the volleyball right before hitting the ground. In this equation:

Rearrange this equation and solve for the velocity right before landing, \(v\). Note that because \(v\!\) is raised to the power of \(2\) in \((v^{2} - u^{2}) = 2\, a\, x\), both \(v = \sqrt{u^{2} + 2\, a\, x}\) and \(v = -\sqrt{u^{2} + 2\, a\, x}\) could satisfy this equation. However, \(v\!\!\) needs to be negative since the volleyball would be travelling downwards before reaching the ground.

Therefore, right before reaching the ground, velocity of the volleyball would be:

\(\begin{aligned} v &= -\sqrt{u^{2} + 2\, a\, x \\ &= -\sqrt{(6.0)^{2} + 2\, (-9.81)\, (-2.0)} \; {\rm m\cdot s^{-1}} \\ &\approx (-8.67)\; {\rm m\cdot s^{-1}}\end{aligned}\).

In other words, velocity of this volleyball has changed from \(u = 6.0\; {\rm m\cdot s^{-1}}\) (upwards) to \(v \approx (-8.67)\; {\rm m\cdot s^{-1}}\) (downwards) during this flight. Divide the change in the velocity \((v - u)\) by the rate of change in velocity \(a = (-9.81)\; {\rm m \cdot s^{-2}}\) to find the duration of this flight:

\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{(-8.67) - 6.0}{(-9.81)}\; {\rm s} \\ &\approx 1.5\; {\rm s}\end{aligned}\).

Answer:

A

Explanation:

Answer:

The person delivered a power of 2,558 Watt

Explanation:

Work and Power

Mechanical work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

Being  the force vector and  the displacement vector, the work is calculated as:

\(W=\vec F\cdot \vec s\)

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

Power is the amount of energy transferred per unit of time. In the SI, the unit of power is the watt, equivalent to one joule per second.

The power can be calculated as:

\(\displaystyle P=\frac {W}{t}\)

Where W is the work and t is the time.

If the person lifts a mass of m=200 Kg, then exerts a force equal to its weight:

F = m.g = 200*9.8 = 1,960

F = 1,960 N

The work done when lifting the weight 7 times by a distance of s=2.2 m is:

W = 7*1,960*2.2=30,184

W = 30,184 J

Finally, the power delivered in t=11.8 seconds is:

\(\displaystyle P=\frac {30,184}{11.8}\)

P = 2,558 Watt

The person delivered a power of 2,558 Watt

Answer:

1) Throw the ball straight in the air and time how long it takes the ball to travel out of your hand then back into your hand at the same height it was released at.

2) Use this time and divide it by two to get t1. Insert t1 into the formula y=(g(t1)^2)/2. Solve for y.

3) To find the maximum speed you take t1 and insert it into the formula Vy=G(t1) and solve for Vy.

4) Remember to ignore air resistance and that g=9.8 m/(s^2)

Explanation:

Answer:

8.79 J

Explanation:

Given that a slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the bottom of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??

Total energy = mgh

Total energy = 4.41 × 2 = 8.82 J

Elastic potential energy = 1/2 × Ke^2

Elastic potential energy = 1/2 × 0.84 × 0.25^2

Elastic potential energy = 0.02625

Also,

Total energy = P.E + K.E

Substitute them into the formula above

8.82 = 0.02625 + K.E

K.E = 8.82 - 0.02625

K.E = 8.79375

K.E = 8.79 J

Therefore, the KINETIC ENERGY of the slinky at the bottom of the stairs is 8.79 Joules approximately