Which action could a student take to produce a longitudinal wave with a large amplitude?


A. Stand still as possible

B. Light a candle

C. Bang on a drum

D. Drop a pebble in a pond

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\( \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \)

Where ,

Therefore , by Substituting the given values in the above Formula :-

\( \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \)

\( \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \)

\( \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \)

\( \longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }} \)

Hence :-

\( \underline {\rule {210pt} {4pt}} \)

Note :-

Answer:

Question :-

If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\begin{gathered} \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \end{gathered}

★

Acceleration=

t

v−u

Where ,

V denotes to Final Velocity .

U denotes to Initial Velocity .

T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

\begin{gathered} \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \end{gathered}

†Acceleration=

Time

FinalVelocity−InitialVelocity

\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \end{gathered}

⟼Acceleration=

85

0−60

\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \end{gathered}

⟼Acceleration=

85

60

\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }}⟼Acceleration = 0.70

Hence :-

Acceleration = 0.70 m/s² .

\underline {\rule {210pt} {4pt}}

Note :-

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The true statement among the given options is that "The law of conservation and the first law of thermodynamics are not exactly the same." Although these laws are related, they have some fundamental differences. The law of conservation states that energy cannot be created or destroyed, only transferred or converted from one form to another.

On the other hand, the first law of thermodynamics is an extension of this law and states that the total energy of a system is constant, and energy can only be transferred between the system and its surroundings.
The statement "A thermometer transfers thermal energy to an object" is not entirely accurate. A thermometer measures the temperature of an object by detecting the thermal energy of the object. It does not transfer any significant amount of thermal energy to the object.

The statement "Objects may either spontaneously heat up or cool down, depending on the system (entropy)" is also true. Objects tend to move towards a state of maximum entropy or disorder. Therefore, they may either heat up or cool down depending on the system's conditions.

Finally, the statement "Temperature is the same thing as thermal energy" is not entirely correct. Temperature is a measure of the average kinetic energy of the particles in an object, whereas thermal energy is the total energy of the particles in an object. Temperature and thermal energy are related but not the same.

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The planet that moves the fastest in a solar system is the planet nearest the Sun.

The correct option is C. The Planet Nearest The Sun.

What is a Solar System?

A solar system is a collection of planets, moons, comets, asteroids, and other objects that revolve around a single star. The sun is the center of our solar system, and it includes all of the matter and energy that orbits around it, including Earth and all the other planets.

Sun, the star around which Earth and the other planets of the solar system revolve, has a huge gravitational field. Planets move around the sun in a fixed orbit at varying speeds, depending on their distance from the sun. Because planets are closer to the sun, their gravitational pull is greater, resulting in a faster orbital speed for them.

The planet nearest the sun in the solar system is Mercury. Due to its proximity to the sun, it orbits at a speed of around 48 km/s, making it the fastest planet in the solar system, with an orbital period of 88 Earth days.

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Answer:

Astronauts who are orbiting the Earth often experience sensations of weightlessness. These sensations experienced by orbiting astronauts are the same sensations experienced by anyone who has been temporarily suspended above the seat on an amusement park ride. Not only are the sensations the same (for astronauts and roller coaster riders), but the causes of those sensations of weightlessness are also the same. Unfortunately however, many people have difficulty understanding the causes of weightlessness.

The force that the Sun exerts on a 50 kg person standing on Earth's surface is approximately 3.55 × 10^22 Newtons.  The ratio of the Sun's gravitational force to Earth's gravitational force on the same 50 kg person is approximately 7.23 × 10^19.

(a) To calculate the force that the Sun exerts on a 50 kg person standing on Earth's surface, we can use Newton's law of universal gravitation:

F = G * (m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant (approximately 6.67430 × 10^-11 m^3⋅kg^−1⋅s^−2), m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two objects.

In this case, the mass of the person (m1) is 50 kg, the mass of the Sun (m2) is 2.0 × 10^30 kg, and the distance between them (r) is 1.5 × 10^11 m.

Substituting the values, we have:

F = (6.67430 × 10^-11) * (50 kg) * (2.0 × 10^30 kg) / (1.5 × 10^11 m)^2

F ≈ 3.55 × 10^22 N

Therefore, the force that the Sun exerts on a 50 kg person standing on Earth's surface is approximately 3.55 × 10^22 Newtons.

(b) To determine the ratio of the Sun's gravitational force to Earth's gravitational force on the same 50 kg person, we can use the formula:

Ratio = F_sun / F_earth

The gravitational force exerted by Earth on the person can be calculated using the same formula as in part (a), but with the mass of the Earth (m2) and the average distance from the person to the center of the Earth (r_earth).

The mass of the Earth (m2) is approximately 5.97 × 10^24 kg, and the average distance from the person to the center of the Earth (r_earth) is approximately 6.37 × 10^6 m.

Substituting the values, we have:

F_earth = (6.67430 × 10^-11) * (50 kg) * (5.97 × 10^24 kg) / (6.37 × 10^6 m)^2

F_earth ≈ 4.91 × 10^2 N

Now we can calculate the ratio:

Ratio = (3.55 × 10^22 N) / (4.91 × 10^2 N)

Ratio ≈ 7.23 × 10^19

Therefore, the ratio of the Sun's gravitational force to Earth's gravitational force on the same 50 kg person is approximately 7.23 × 10^19.

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Answer:

D

Explanation:

Water has a high surface tension because the water molecules on the surface are pulled together by strong hydrogen bonds. That means a drop of water will "want" to have the smallest possible surface area.

Acceleration

Now

Apply Newtons second law

To find frictional force we need coefficient of friction which is not given .

generally for car case the value of coefficient is 0.6-0.8 .

Putting max 0.8

Note:

Last part is assumption not accurate

The force acting on the sports car is the product of its mass and acceleration. The force on the car is 3300 N.

Force is an external agent acting on a body to deform it or to change it from the state of rest or motion. There are different kinds of forces such as frictional force, gravitational force, nuclear force, magnetic force etc.

Frictional force is acting as a hindrance to the motion of an object. The frictional force is the product of normal force and coefficient of friction.

According to second law of motion, force is the product of mass and acceleration.

Given mass m = 1000 Kg

change in velocity = 20 - 0 m/s

Acceleration = 20 m/s / 6.6 s

= 3.3 m/s².

Force = m a

= 3.3 m/s² × 1000 Kg

= 3300 N.

Now, product of this normal force and coefficient of static friction.

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The time taken for the mass to reach the bottom of the inclined plane after it is released from rest is 0.78 s.

The height of the inclined plane is calculated as follows;

h = L(sin 37)

where;

h = 5 x sin(37)

h = 3.01 m

t = √(2h/g)

t = √(2 x 3.01 / 9.8)

t = 0.78 s

Thus, the time taken for the mass to reach the bottom of the inclined plane after it is released from rest is 0.78 s.

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Answer:

All the spheres interact with other spheres.

Explanation:

Rain (hydrosphere) falls from the clouds in the atmosphere to the lithosphere and then forms streams and and rivers that provide drinking water for wildlife and humans and water for plants and crops to grow.

Answer:The first is the magnitude of the force applied on the body and the second is the perpendicular distance from the line of action of force and the axis of rotation of the body.

Explanation:

If the lovers both walk toward each other and meet at the center of the boat, at 0.725m and since romeo has greatest mass of the boat moves towards him away from the shore.

Calculating the system's center of mass should come first

X_{CM}=\sum_{n=1}^{n}\frac{X_n*M_n}{M_n}

Romeo, Juliet, and the boat's masses are multiplied by each coordinate's x value, and the result is then divided by the sum of all the masses.referring to Juliet's position as an example.

X_{CM}=\frac{57Kg\times0m+75Kg\times 2.7m+75kg\times1.35m}{57kg+75kg+75kg}

X_{CM}=\frac{307.395kg.m}{207kg}=1.485m

When internal forces are in play, the center of mass remains constant.

After the maneuver, the center of mass shifts in relation to the back of the boat, but it stays at the same distance from the shore.

X_{CM}=\frac{75\times1.35m+(75kg+57kg)\times2.70m}{207kg}=

X_{CM}=\frac{457.65}{207kg}=2.210m

The boat moves toward the shore with this displacement.

0.725m

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An example of physical weathering is the wind that is blowing off bits of a rock over time. This results into breaking down of large rocks. Thus, the correct option is C.

Physical weathering is also called as mechanical weathering. It is a process which causes the disintegration of large rocks, minerals, and large soil particles without any chemical change. The primary process in physical weathering is the abrasion, it is the process by which clasts and other particles are reduced in size and mix up with soil.

Physical weathering occurs when large rocks are broken down through mechanical processes such as wind blowing, water, gravitational force, freeze-thaw cycles, or the growth of roots into the rocks.

Therefore, the correct option is C.

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Answer:

A wave in which the medium vibrates at right angles to the direction of the propagation is called transverse wave.

Answer:

distance=10km=10*1000=10000m

time=5min=5*60=300sec

average speed=distance/time

= 10000/300=33.33m/s

Explanation:

Answer:

0.99kgm/s

Explanation:

Given parameters:

Initial momentum  = 5.8kgm/s

Final momentum  = 6.79kgm/s

Unknown:

Magnitude of the impulse applied to the baseball  = ?

Solution:

To solve this problem;

 The impulse applied to the baseball can be found by using the expression below:

 Impulse  = Final momentum   -   Initial momentum

Impulse  = 6.79kgm/s - 5.8kgm/s  = 0.99kgm/s

Answer:

The small car and the truck experience the same average force.

Explanation:

Here we need to remember two of Newton's laws.

The second one says that:

F = m*a

force equals mass times acceleration.

And the third one says that;

"If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A"

From the third law, if the car experiences a force F due to the impact with the truck, then the truck experiences the same force F due to the impact.

But this seems odd, because we would expect to see the car being more affected by the impact, right?

Well, this is explained by the second law.

Suppose that the mass of the car is m, and the mass of the truck is M.

such that M > m

Then for the small car we have:

F = m*a

And for the truck:

F = M*a'

Because the force is the same for both of them, we can write:

m*a = M*a'

a = (M/m)*a'

because M > m, then M/m > 1.

This means that the acceleration that the car experiences is larger than the acceleration for the truck, and this is why we would see that the car seems more affected by the impact, regardless of the fact that both vehicles experience the same force in the impact.

Answer:

Distance

Explanation:

trust me

Answer:

The distance "r" must be squared

Explanation:

In the equation F=GMm/r^2, the distance "r" is squared, which represents the distance between masses M and m and G is the gravitational constant.

Answer:

no

Explanation:

the equation can't be balanced because it doesn't have the same elements on each side of the equal sign.

The given equation is not a balanced chemical equation because it does not contain the same elements on both sides of the equation.

A chemical equation can be explained as the representation of a chemical reaction in terms of symbols of the substances. A balanced equation containing the same number of atoms of each element on either side of the equation.

The law of mass conservation is followed by every balanced chemical equation. By obeying this law, the total mass on the reactant side should be equal to the total mass on the product side in a balanced equation.

On both sides of the chemical equation, the same elements as well as an equal number of elements are present as the chemical reaction does not alter the identity of the elements. Therefore, the given equation is not a balanced chemical equation.

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A perfect machine is not possible because perfect machines mean that the system will always perform at a 100% efficiency, and that's not possible in real life because the systems of the real world will always lose some energy in the form of heat, resulting in a lower efficiency percentage.

Answer:

Explanation:

Pooh Shiesty, that's my dawg

But Pooh, you know I'm really shiesty

You told all them O.T. ni  ggas that you really slide

Tell the truth about your gang, they really dyin'

I got my own fire, don't need security in the club

All that woofin' on the net , I thought you was a thug

They ain't got nowhere to go, I sh0t up everywhere they was

Yeah, you know who took that - from you

Come get it back in blood

Come get it back in blood

Answer:

An electron is a component of the broader term, electricity. Generally electricity refers to the control, manipulation, and use of the movement of electrons to perform some kind of work (motion/rotation, light, heat, etc…).

Explanation:

Or

put this

The study of electrons as it relates to their use in electric devices is electricity.

But I will go with the first one

Answer:

please help

Explanation:

Answer:

hydrogen bonding between H atoms.

Explanation:

Answer:

6m/s

Explanation:

The magnitude of the average acceleration is 2.5 m/s²

Acceleration refers to the ratio of  velocity changes with to time. if it speeds up or slows down, the object moving in a straight line is accelerated . Motion along a circle is accelerated even if the speed is constant, due the constantly changing direction. Both effects contribute to the acceleration for all other kinds of motion, .

It is a vector quantity because it have both a magnitude and a direction, . Velocity is also a vector quantity. Acceleration is defined as the change in velocity vector over the time interval divided by the time interval.

a =  \(\frac{v-u}{t}\) m/s²

a = acceleration

v = final velocity of object

u = initial velocity of object

For the given question:

a = \(\frac{25-15}{4}\)  m/s²

a = \(\frac{10}{4}\)  m/s²

a =  2.5 m/s²

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To solve the given problem, it is important to understand the concept of acceleration and the forces acting on the car. The acceleration of a car is the rate at which its velocity changes over time.

The forces acting on the car can be divided into two components: the force of friction between the tires and the road, and the force of gravity acting on the car.

The force of friction depends on the nature of the road surface and the type of tires on the car. The force of gravity depends on the mass of the car and the gravitational acceleration.

Therefore, a = (μ - g)/m is the expression for the acceleration of the car.

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Answer:

Las estrellas se forman debido a la unión de pequeños elementos y partículas como el hidrógeno y el helio que experimentan una fusión nuclear en el núcleo debido a la intensa presión para formar un nuevo átomo (como dos hidrógeno que se combinan para formar un átomo de helio) que es un proceso. que requiere una gran cantidad de energía para comenzar, por lo que cada reacción de fusión produce una gran cantidad de energía que puede mantener la reacción y equilibra la fuerza gravitacional que atrae las masas de las partículas hacia el centro de la estrella

A medida que la energía de la estrella se irradia, la superficie de la estrella cede la energía en forma de calor y luz de manera que debido a la alta temperatura de las partículas de los átomos de los elementos se mueven muy rápida y energéticamente para emitir fotones rápidamente. (alta frecuencia) que se ve como el alto brillo de la estrella

Explanation:

The potential energy of the car when it let go is 20,000 J.

The speed of the car at the bottom of the ramp is 20 m/s.

The given parameters;

The potential energy of the car is calculated as follows;

P.E = mgh

P.E = 100 x 10 x 20

P.E = 20,000 J

The speed of the car at the bottom of the ramp is calculated as follows;

\(K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 10 \times 20} \\\\v = 20 \ m/s\)

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When a comet comes near the Sun, its volatile ice sublimates and changes directly from the solid to the gas phase.

Comets are cosmic snowballs of frozen gases, dust, and rocks, orbiting the Sun. When frozen, comets are the size of a small town. As the comet's orbit approaches the Sun, it heats up, spewing gases and dust onto its giant glowing head, larger than most planets.

Comets vaporize when their orbits come to close to the Sun. Comets do not melt in the strict sense of chinging to liquid. However, since they are made up partly of ice and other volatile compounds, comets vaporize (turn directly to gas) when warmed in the vacuum of space by orbiting near the sun.

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