The equations
\(x = r*\cos(\theta)\\\\y = r*\sin(\theta)\)
are useful to convert from polar to Cartesian
So,
\(x = r*\cos(\theta)\\\\x = r*\cos\left(\frac{\pi}{3}\right)\\\\x = r*\frac{1}{2} \ \text{ use unit circle} \\\\x = \frac{1}{2}r\)
Answer: Choice AIf the composite functions f(g(x)) and g(f(x)) both equal x, then the function g is the____function of f.
If the composite functions f(g(x)) and g(f(x)) both equal to x, then the function g is the Inverse function of f.
What is the inverse of a function?A function that can reverse into another function is known as an inverse function or anti-function. In other words, the inverse of a function "f" will take y to x if any function "f" takes x to y.
Let us take the Example.
Suppose f(x)= x/4 and g(x)=4x.
Let x=1
then f(g(x))= f(g(1))=f(4)=1
and g(f(x))=g(f(1))=g(1/4)=1
Here, f(g(x))=g(f(x))=1
Therefore , we can say that f(g(x)) and g(f(x)) are inverse of each other.
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Solve the system using elimination. x − 4y = 4 and -3x − 4y = 12
x - 4y = 4
-3x - 4y = 12
Subtract the first equation from the second
x - 4y = 4
-4x = 12
Divide the second equation by (-4)
x - 4y = 4
x = -3
Subtract the second equation from the first
- 4y = 7
x = -3
Divide the first equation by (-4)
y = -7/4
x = -3
So, the solution is x = -3 and y = - 7/4a cardboard box without a lid is to have a volume of 23,328 cm3. find the dimensions that minimize the amount of cardboard used. (let x, y, and z be the dimensions of the cardboard box.) (x, y, z) =
The dimensions (x, y, z) that minimize the amount of cardboard used for a box with a volume of 23,328 cm³ are (28, 28, 30).
1. Given the volume, V = x*y*z = 23,328 cm³.
2. The surface area, which represents the amount of cardboard used, is S = x*y + x*z + y*z.
3. To minimize S, we need to use calculus. First, express z in terms of x and y using the volume equation: z = 23,328 / (x*y).
4. Substitute z into the surface area equation: S = x*y + x*(23,328 / (x*y)) + y*(23,328 / (x*y)).
5. Now find the partial derivatives dS/dx and dS/dy, and set them equal to zero.
6. Solve the system of equations to get x = 28 and y = 28.
7. Plug x and y back into the equation for z: z = 23,328 / (28 * 28) = 30.
So the dimensions that minimize the amount of cardboard used are (28, 28, 30).
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Walter used the iterative process to determine that √13 is between 3.61 and 3.62. Analyze Walter's estimation. Is he correct? If not, what was his mistake?
Question options:
A. Yes, Walter is correct.
B. No 3.612 is less than 13.
C. No, both 3.612 and 3.622 are greater than
D. No, both 3.612 and 3.622 are less than 13
Answer:
C. No, both 3.612 and 3.622 are greater than the square root of 13
Explanation:
13 is a prime number and must have a decimal number as its square root and so the square root should be between √9 and √16
Using the Newton Raphson method to estimate the square root of 13 with the formula: ai +1= ai²+n/2ai
We get square root of 13 = 3.6055512
This is the same result we get using a calculator to calculate square root of 13= 3.6055512
So yes Walter is not correct
The pic is here , just the question wouldn’t show up right. Any help ?
Answer:
its 4√2i i think
Step-by-step explanation:
Answer:
Answer:B
Step-by-step explanation:
Please review the toy description below. Answer the following questions:
Jenga is a game played with 54 rectangular blocks. Blocks are stacked into a tower of 13 levels - 3 blocks on each level. Once the tower is built, players take turns removing one block from one of the levels and placing in on the top of the tower. Players can only use one hand to take remove a block from the tower and then place it on the top. The game ends when the tower falls over.
A) What developmental age group(s) is/are this toy appropriate for (e.g., infant & toddler, early childhood, middle childhood, adolescence, young adult)?
B)Why (e.g., what aspects of cognitive, physical, and socioemotional development do you think needs to have already occurred?)? Explain how this toy could promote cognitive, physical, and socioemotional development. Use specific concepts in this explanation.
Clearly define concepts (in your own words!) and be explicit in how you link the toy to each concept. Stronger responses will synthesize a variety of concepts and ideas (e.g., your discussion should not be limited to discussing one theoretical framework). Highlight or bold all concepts used in your explanation.
Answer:
A) The Jenga game is appropriate for the middle childhood age group, typically ranging from around 6 to 12 years old.
B) Jenga promotes cognitive, physical, and socioemotional development in middle childhood through enhancing spatial reasoning and problem-solving skills, improving fine motor skills and proprioceptive input, and fostering social interaction, cooperation, and risk assessment.
Step-by-step explanation:
Jenga, a game played with rectangular blocks, can promote cognitive, physical, and socioemotional development through various concepts.
Cognitive Development: Jenga enhances spatial reasoning as players analyze the tower's structure, evaluate block stability, and strategize their moves. They mentally manipulate objects in space, building an understanding of spatial relationships and balance. Problem-solving skills are fostered as players make decisions about which block to remove, considering the consequences of their actions. They must anticipate the tower's reaction to their moves, think critically, and adjust their strategies accordingly.
Physical Development: Jenga improves fine motor skills as players carefully remove and stack blocks using only one hand. Precise finger movements, hand-eye coordination, and grip strength are required for successful manipulation of the blocks. The game also provides proprioceptive input as players gauge the weight and balance of each block, refining their sense of touch and motor control.
Socioemotional Development: Jenga promotes social interaction and cooperation when played with multiple players. Taking turns, discussing strategies, and supporting each other's successes and challenges enhance communication, collaboration, and empathy skills. Players learn to respect and consider others' perspectives, negotiate and compromise, and work together towards a common goal. Sportsmanship is nurtured as players accept both victory and defeat gracefully, fostering resilience and emotional regulation.
Furthermore, Jenga offers opportunities for developing patience and perseverance. As the tower becomes increasingly unstable, players must exercise self-control, focus, and delayed gratification. They learn to take their time, plan their moves carefully, and tolerate the suspense of potential collapse. The game also presents a low-risk environment for risk assessment, allowing children to assess the consequences of their decisions and make calculated judgments.
By engaging in Jenga, children actively participate in a multi-dimensional activity that combines physical manipulation, cognitive analysis, and social interaction. Through the concepts of spatial reasoning, problem-solving, fine motor skills, proprioceptive input, social interaction, cooperation, sportsmanship, patience, perseverance, and risk assessment, Jenga supports holistic development in cognitive, physical, and socioemotional domains.
what is the domain and range of the following? (1,5) (-2,4) (-3,0) (-6,2)
Domain: {1, -2, -3, -6}
Range: {5, 4, 0, 2}
im not 100% sure but Im pretty sure it’s that
let n be a positive number such that 72!/n is a multiple of 2^n, but not a multiple of 2^(n 1). what is the sum of all possible values of n?
The sum of all possible values of n is 448.
Let n be a positive number.
We are given that 72!/n is a multiple of 2^n, but not a multiple of 2^(n-1).
We can start by finding all values of n that fit this criteria:
n = 1: 72!/1 = 479001600 is not a multiple of 2^1, but is a multiple of 2^0.
n = 2: 72!/2 = 1197500400 is not a multiple of 2^2, but is a multiple of 2^1.
n = 3: 72!/3 = 59875200 is a multiple of 2^3, but not a multiple of 2^2.
n = 4: 72!/4 = 29937600 is a multiple of 2^4, but not a multiple of 2^3.
n = 5: 72!/5 = 14968800 is a multiple of 2^5, but not a multiple of 2^4.
n = 6: 72!/6 = 7484400 is a multiple of 2^6, but not a multiple of 2^5.
n = 7: 72!/7 = 3742200 is a multiple of 2^7, but not a multiple of 2^6.
n = 8: 72!/8 = 1871100 is a multiple of 2^8, but not a multiple of 2^7.
n = 9: 72!/9 = 935550 is a multiple of 2^9, but not a multiple of 2^8.
n = 10: 72!/10 = 467775 is a multiple of 2^10, but not a multiple of 2^9.
Therefore, the sum of all possible values of n is 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 = 448.
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What is the range of the function graphed below? PLEASE ANSWER ASAP
This is a more complicated way to write \(y < 2\)
The range is the set of all possible y outputs of a function. So we use the graph to see what y values are possible. The graph shows that y can be anything smaller than y = 2. We can't actually reach y = 2 itself due to a horizontal asymptote here.
In interval notation, the answer would be \((-\infty, 2)\) with the curved parenthesis to indicate "do not include y = 2 as part of the range".
2t + 9 + 7
Idk what this isss
Answer:
2t+16
Step-by-step explanation:
this should 2t+16
because 2t contains a variable and there are no available numbers/figits that match up
and 9 +7 is 16
hope i could help
Answer:
2t +16
Step-by-step explanation:
2t + 9 + 7
Combine like terms
2t +16
A PLEASE HELP ASAP
Lira Massimi has just opened a retirement savings account with an initial investment of $2000. She hopes that the account will be worth 310000 when she retires in twenty years. Lira will not make any further
investments in the
withdrawals from the account until it is worth $10000. The interest is compounded continuously at
8.0% annually. You need a calculator for the next three questions.)
17. Suppose that the interest rate for the account is 8.0% , compounded continuously.
How much will be in the account in exactly twenty years? (Nearest cent)
18. How long will it take for Lira's investment to double if the interest rate is
8.0% , compounded continuously? Write answer correct to the nearest hundredth
year.
The amount in the account after 20 years is $49530.32.
What is continuous compounding?
There is no cap on how frequently interest can compound thanks to continuous compounding. A balance can compound continuously an infinite number of times, which means interest is earned on it constantly.
Given:
Lira will not make any further investments in the withdrawals from the account until it is worth $10000.
Suppose that the interest rate for the account is 8.0% , compounded continuously.
We have to find the amount in the account after 20 years.
Consider, the compounded continuously formula
\(P(t)= P_0e^r^t\)
Where
P(t) = Value at time t.
\(P_0\) = Original principle sum = $10,000
r = Interest rate = 8.0% = 0.08
t = time in years = 20
Plug the values in the above formula
\(P(t) = 10000e^0^.^0^8^*^2^0\\P(t) = 49530.32\)
Hence, the amount in the account after 20 years is $49530.32.
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convertir 4.7 nanometros a milímetros??
Answer:
4.7e-6 millimeters
Step-by-step explanation:
A dilation has center (0,0). Find the image of the point L(−8,0) for the scale factor 9.
Given:
Center of dilation: (0, 0)
Scale factor = 9
Let's find the image of point L(-8, 0) after the dilation with the given scale factor.
To find the image of a point after dilation, multiply the coordinates of point by the scale factor of dilation.
We have:
L(-8, 0) ==> (-8 x 9, 0 x 9) ==> L'(-72, 0)
Therefore, the image of the point after a dilation with a scale factor of 9 is:
(-72, 0)
ANSWER:
(-72, 0)
Maddie is making pineapple punch for her birthday party. The recipe says you need 3 cups of pineapple juice for every 4 cups of ginger ale. If she uses 16 cups of ginger ale, how much pineapple juice will she need?
Answer:
12 cups of pineapple juice for 16 cups of ginger ale.
Step-by-step explanation:
4+4+4+4= 16
3+3+3+3= 12
What is the probability that in the next six 18- to 29-year-olds surveyed, all six will own a tablet?
C. What is the probability that in the next six 18- to 29-year-olds surveyed, at least four will own a tablet?
D. What are the mean and standard deviation of the number of 18- to 29-year-olds who will own a tablet in a survey of six?
In the given scenario, we can calculate the probability of all six individuals surveyed owning a tablet using the binomial probability formula. Additionally, we can determine the mean and standard deviation of the number of individuals who own a tablet using the formulas: mean (μ) = n * p and standard deviation (σ) = √(n * p * (1-p)). C.
The probability that of the next six 18- to 29-year-olds surveyed, all six will own a tablet can be calculated using the binomial probability formula. Since each individual has a certain probability of owning a tablet, we can calculate the probability of success (p) for each trial and use the formula to find the probability of all six trials being successful.
D. The mean and standard deviation of the number of 18- to 29-year-olds who will own a tablet in a survey of six can also be determined using the binomial distribution. The mean (μ) of a binomial distribution is calculated by multiplying the number of trials (n) by the probability of success (p). The standard deviation (σ) is found using the formula √(n * p * (1-p)).
C. To find the probability that all six 18- to 29-year-olds surveyed will own a tablet, we can use the binomial probability formula. Each individual has a certain probability of owning a tablet, and we want to find the probability of all six trials being successful. The formula for calculating the probability of exactly k successes in n trials is given by P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where (n choose k) represents the binomial coefficient. In this case, k=6, and p represents the probability of owning a tablet for an individual in this age group.
D. The mean (μ) of a binomial distribution is the expected number of successes in a given number of trials. For this scenario, we multiply the number of trials (n) by the probability of success (p) to find the mean. In this case, n=6 represents the number of individuals surveyed, and p is the probability of owning a tablet for an individual.
The standard deviation (σ) of a binomial distribution measures the spread or variability of the distribution. It is determined using the formula √(n * p * (1-p)). The standard deviation indicates how much the individual values in the distribution deviate from the mean.
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The perimeter P of a rectangle is P = 21 + 2w, where I and w are the rectangle's length and
width, respectively.
(A) Rewrite the formula to find the length given perimeter and width. Justify each step in your solution with the property used. (B) compite the length of a rectangle with a perimeter 40.2in and width of 6.7in.
Answer:
see below
Step-by-step explanation:
P = 2l + 2w
Subtract 2w using the subtraction property of equality
P -2w = 2l+2w-2w
P -2w = 2l
Divide each side by 2, using the division property of equality
P/2 -2w/2 = 2l/2
1/2 P -w = l
Now we have P =40.2 and w = 6.7
l =1/2 (40.2) - 6.7
l =20.1-6.7
=13.4
2 ( 3x + 4) + 3
( ) + __( ) +
+
+
-
+
Answer:
\(2(3x + 4) + 3 \\ 2(3x) \: + 2(4) \: + \: 3 \\ 6x + 8 + 3 \\ 6x + 11\)
I hope I helped you^_^
Solve the following inequality for p. Write your answer in simplest form.
6p+5≤-2p-5
Answer:
p≤-5/4
Step-by-step explanation:
Move variable to the left hand side and change its sign, move the constant tp the right hand side and change its sign
6p+2p+5≤-5
Collect like terms
8p≤-5-5
8p≤-10
Divide both sides of the inequality by 8
p≤-5/4
there is a boxplot. the left whisker ends at 2. the right whicker ends at 43. the box is between 5 and 15. do we know the percentage of people below 2? if so, what is this percentage?
Yes, we can determine the percentage of people below 2 from the box plot. The answer is 0%
A boxplot is a graph that stretches along the minimum and maximum values of any frequency distribution. The left whisker marks the minimum value of the box plot.The right whisker marks the maximum value of the plot.The box is drawn from the first Quartile to the third quartile of the frequency distribution.From the given data we can sketch out a box plot given as follows. Here since the left whisker ends at 2 and the right whisker ends at 43, there are no people less than 2 and no people more than 43.
5 and 15 are the 1st and the 3rd Quartile respectively.
Since the minimum value of this data is 2, there are no people who could be below 2. Therefore, the percentage of people below 2 is 0%
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Exercise 10
You randomly choose one of the tiles. Without replacing the first tile, you choose a second tile. What is the probability of the compound event? Write your answer as a fraction or percent rounded to the nearest tenth.
The probability of choosing a 5 and then a 6 is 1/49
Finding the probability of the compound eventFrom the question, we have the following parameters that can be used in our computation:
The tiles
Where we have
Total = 7
The probability of choosing a 5 and then a 6 is
P = P(5) * P(6)
So, we have
P = 1/7 * 1/7
Evaluate
P = 1/49
Hence, the probability of choosing a 5 and then a 6 is 1/49
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Question
You randomly choose one of the tiles. Without replacing the first tile, you choose a second tile. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth. The probability of choosing a 5 and then a 6
#1: Find the value of X. (GEOMETRY)
I will give brainliest to BEST answer! fake answers will be reported.
refer to attachment!
Answer:
x = 14
Step-by-step explanation:
1. We know that all angle measures in a triangle sum to 180 degrees.
This means that 7x - 11 + 5x - 2 + 2x - 3 = 180.2. (Solving)
Step 1: Combine like terms.
\((7x+5x+2x)+(-11-2-3)=180\) \(14x -16 = 180\)Step 2: Add 16 to both sides.
\(14x - 16 + 16 = 180 + 16\) \(14x = 196\)Step 3: Divide both sides by 14.
\(\frac{14x}{14}=\frac{196}{14}\) \(x = 14\)Step 2: Check if solution is correct.
\(7(14)-11+5(14)-2+2(14)-3=180\) \(98-11+70-2+28-3=180\) \(180=180\)Therefore, the answer is x = 14.
A line has a slope of -3 and a y-intercept of 3.
3
2
1
4
2
-1
1
2.
3
4
6
What is the x-intercept of the line?
-9
ОО
Answer: the answer is B
Step-by-step explanation:
If all are equally likely, find the number of possible outcomes
4 play dates, 3 show times
There are 12 possible outcomes when considering all combinations of 4 play dates and 3 show times.
For each play date, you have 3 options for the show time.
Since the events are independent and all options are equally likely, you can multiply the number of options together to find the total number of possible outcomes.
Number of possible outcomes
= Number of play dates × Number of show times
= 4 × 3
= 12
Therefore, there are 12 possible outcomes when considering all combinations of 4 play dates and 3 show times.
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Please help me solve this
Answer:
x=61
2x+3 = 125
x-6 = 55
Step-by-step explanation:
The two angles shown form a straight line so they add to 180
2x+3 + x-6 = 180
Combine line terms
3x-3 =180
Add 3 to each side
3x-3+3 =180+3
3x=183
Divide each side by 3
3x/3 =183/3
x =61
The angle on the left is 2x+3
2x+3 = 2*61+3 = 122+3 = 125
The angle on the right is x-6 = 61-6 = 55
Find an equation of the line passing through (-3, 2) and parallel to the graph of x - 2y = 7. Write the equation in slope-intercept form.
Answer:
y = \(\frac{1}{2}\) x + \(\frac{7}{2}\)
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given
x - 2y = 7 ( subtract x from both sides )
- 2y = - x + 7 ( multiply through by - 1 )
2y = x - 7 ( divide through by 2 )
y = \(\frac{1}{2}\) x - \(\frac{7}{2}\) ← in slope- intercept form
with slope m = \(\frac{1}{2}\)
• Parallel lines have equal slopes , then
y = \(\frac{1}{2}\) x + c ← is the partial equation
to find c substitute (- 3, 2 ) into the partial equation
2 = \(\frac{1}{2}\) (- 3) + c = - \(\frac{3}{2}\) + c ( add \(\frac{3}{2}\) to both sides )
2 + \(\frac{3}{2}\) = c , that is
c = \(\frac{7}{2}\)
y = \(\frac{1}{2}\) x + \(\frac{7}{2}\) ← equation of parallel line
If southland is producing at point x, it can produce _____ more schools without giving up any movies. (note: enter your answer as a numeral.)
If Southland is producing at point X, to determine the number of additional schools it can produce without giving up any movies, we need to refer to the concept of production possibilities frontier (PPF).
The PPF represents the maximum output combination of two goods that an economy can produce with its available resources and technology.
In this case, movies and schools are the two goods being produced. If Southland is operating at point X on the PPF, it means it is efficiently allocating its resources to produce a certain quantity of movies and schools. To find out how many more schools can be produced without sacrificing any movies, we need to identify a point on the PPF that lies on the same movie production level as point X.
Let's assume that at point X, Southland is producing 10 movies. To determine the number of additional schools, we need to find a point on the PPF where the movie production level is also 10. Let's say at this point, Southland can produce 20 schools.
Therefore, the answer is 20 more schools.
If Southland is producing at point X and is currently producing 10 movies, it can produce an additional 20 schools without giving up any movies. This calculation is based on the assumption that the PPF remains constant and there are no changes in resource availability or technology.
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Which equation represents the graphed function?
5
10,3)
O y = -2x + 3
O y = 2x + 3
O y = 2/x + 3
O y=-x+3
--
1
4
5
X
977
y = -2x + 3
in the equation y = mx + b, the m represents the slope and b represents the y-intercept
remember that slope is rise over run:
starting from the point (1, 1) you rise 2 up and go over left 1 to reach the second point shown (0, 3).
add a negative sign to show the negative downward slope, and the m in the equation would be -2
the y-intercept is just where the line hits the y-axis, or when the x in the ordered pair is 0. In this graph, one of the points given is (0, 3) so 3 is the y intercept
just plug all that into y = mx + b
m, the slope, is -2 and b, the y- intercept, is 3.
y = -2x + 3 is your answer
(b) estimate the errors in the approximations t8 and m8 in part (a). (use the fact that the range of the sine and cosine functions is bounded by ±1 to estimate the maximum error. round your answer to seven decimal places.) |et| ≤ |em| ≤
To estimate errors in the approximations t8 and m8, we can use the fact that the range of the sine and cosine functions is bounded by ±1.
In part (a), we have approximations t8 and m8.
To estimate the error in t8, we can compare it to the actual value of the function. Let's denote the actual value of the function at t8 as T8. Since the range of the sine function is bounded by ±1, the maximum error in the approximation t8 would be |t8 - T8| ≤ 1.
Similarly, to estimate the error in m8, we can compare it to the actual value of the function. Let's denote the actual value of the function at m8 as M8. Since the range of the cosine function is also bounded by ±1, the maximum error in the approximation m8 would be |m8 - M8| ≤ 1.
Therefore, the estimated errors in the approximations t8 and m8 are |et| ≤ 1 and |em| ≤ 1, respectively.
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I need help pls its really hard for me rn and teach me how to do it
The sequence that contains all the given terms is:
aₙ = -18 + 6*n
Then the correct option is C.
Which sequence can be used to find the n-th term?
Here we have the elements:
a₃ = 0
a₄ = 6
a₅ = 12
a₆ = 18
a₇ = 24
So each term adds 6 to the previous one, so trivially the relation is of the form:
aₙ = aₙ₋₁ + 6
Now we need to find the first term.
We can rewrite the above equation as:
aₙ₋₁ = aₙ - 6
Then we willget:
a₂ = a₃ - 6 = 0 - 6 = -6
a₁ = a₂ - 6 = -6 - 6 = -12
a₀ = a₁ - 6 = -18
Then the sequence is:
aₙ = -18 + 6*n
Then the correct option is C.
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Given: f(n) = 2n – 2 and g(n) = 2n+5
Find:
(f•g)(t-1)
Answer:
(f · g)(t - 1) = 4t² - 2t - 13
Step-by-step explanation:
First, find (f · g)(n). You can do this by multiplying f(n) by g(n).
f(n) = 2n - 2
g(n) = 2n + 5
(f · g)(n) = (2n - 2)(2n + 5)
(f · g)(n) = 4n² + 6n - 10
Now, plug (t - 1) into (f · g)(n) and simplify.
(f · g)(n) = 4n² + 6n - 10
(f · g)(t - 1) = 4(t - 1)² + 6(t - 1) - 10
(f · g)(t - 1) = 4(t² - 2t + 1) + 6(t - 1) - 10
(f · g)(t - 1) = 4t² - 8t + 4 + 6t - 1 - 10
(f · g)(t - 1) = 4t² - 8t + 4 + 6t - 1 - 10
(f · g)(t - 1) = 4t² - 2t + 4 - 1 - 10
(f · g)(t - 1) = 4t² - 2t - 13