when a substance such as ice melts, its temperature increases. desrcibe what happens to the arrangment of water molecules as the temperature increases

Answer: Weight changes with surface gravity.So in Moon mass will be same as 26 gram mes.

Explanation:

The second snowball should be thrown at an angle of approximately 48.196° with respect to the horizontal to arrive at the same point as the first snowball.

the second snowball should be thrown 4.582 seconds later in order for both to arrive at the same time.

To find the angle at which the second snowball should be thrown, we can use the fact that the horizontal displacement of both snowballs must be the same.

Let's first find the horizontal and vertical components of the velocity for the first snowball. The initial speed is 26.5 m/s, and the angle is 58.0° with respect to the horizontal.

The horizontal component of the velocity for the first snowball is given by:

V1x = V1 * cos(angle1)

    = 26.5 m/s * cos(58.0°)

    = 26.5 m/s * 0.530

    = 14.045 m/s

Now, let's find the vertical component of the velocity for the first snowball:

V1y = V1 * sin(angle1)

    = 26.5 m/s * sin(58.0°)

    = 26.5 m/s * 0.848

    = 22.472 m/s

Since the vertical acceleration is the same for both snowballs (gravity), the time it takes for both to arrive at the same point is the same. Therefore, we can use the time of flight of the first snowball to calculate the vertical displacement for the second snowball.

The time of flight for the first snowball can be calculated using the vertical component of velocity and the acceleration due to gravity:

t = (2 * V1y) / g

  = (2 * 22.472 m/s) / 9.8 m/s²

  ≈ 4.582 s

Now, let's find the vertical displacement for the second snowball:

Δy = V1y * t - (0.5 * g * t²)

    = 22.472 m/s * 4.582 s - (0.5 * 9.8 m/s² * (4.582 s)²)

    ≈ 103.049 m

To find the angle at which the second snowball should be thrown, we can use the horizontal displacement and the vertical displacement:

tan(angle2) = Δy / Δx

           = 103.049 m / (2 * 14.045 m/s * t)

           = 103.049 m / (2 * 14.045 m/s * 4.582 s)

           ≈ 1.085

Now, we can find the angle2 by taking the arctan of both sides:

angle2 ≈ arctan(1.085)

angle2 ≈ 48.196°

Therefore,

To find how many seconds later the second snowball should be thrown, we can simply use the time of flight of the first snowball, which is approximately 4.582 seconds.

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The M-file code and main function is written.

An M-file for the bisection method,

function c = bisection(f, xl, xu, tol)

% Bisection method for finding roots of a function

% Input:

%   - f: the function to find the root of

%   - xl: lower bound of the initial bracketing interval

%   - xu: upper bound of the initial bracketing interval

%   - tol: tolerance for the relative error

% Output:

%   - c: the root of the function within the given tolerance

% Compute the initial values of f at the endpoints of the interval

fl = f(xl);

fu = f(xu);

% Check if the function changes sign over the interval

if fl*fu > 0

   error('Function has the same sign at both endpoints of the interval');

end

% Initialize the iteration counter and the relative error

i = 0;

err = 100;

% Iterate until the relative error is below the tolerance

while err > tol

   % Compute the midpoint of the interval

   c = (xl + xu)/2;

   % Compute the value of the function at the midpoint

   fc = f(c);

   % Update the bracketing interval based on the sign of the function

   if fc*fl < 0

       xu = c;

       fu = fc;

   else

       xl = c;

       fl = fc;

   end

   % Update the iteration counter and the relative error

   i = i + 1;

   err = abs((xu - xl)/c);

   % Print the current values of c, fc, and the relative error

   fprintf('Iteration %d: c = %.6f, fc = %.6f, err = %.6f\n', i, c, fc, err);

end

function main()

% Parameters of the problem

m = 95; % mass of the jumper (kg)

g = 9.81; % acceleration due to gravity (m/s^2)

v = 46; % desired velocity (m/s)

t = 9; % time of free fall (s)

x_l = 0.2; % lower bound

x_u = 0.5; % upper bound

erro_r = 0.05; % relative error

% The function for the velocity of the jumper

f = (c) m*g/c*(1 - exp(-c/m*t)) - v;

% Call the bisection function to find the root of f

c = bisection(f, x_l, x_u, erro_r);

% Print the result

fprintf('The required drag coefficient is %.6f\n', c);

end

When we run the main function, it will call the bisection function with the given parameters and print out the result.

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Answer:

Explanation: Acceleration due to gravity is the acceleration acquired by an object due to the gravitational force. It is a vector quantity, denoted by g and its SI unit is m ... The mass of the earth is about 6E24 kg and the earth radius (Re) is 6371 km which gives G= 9.8m/s/s as the acceleration constant at earth's surface.  I hope this is helpful :)

Acceleration on a body that approached the earth and comes within 6 earth radii of the earth’s surface is 0.2046 m/s²

Acceleration is rate of change of velocity with respect to time.

i.e. a = dv/dt

if an object changes its velocity in short time, we can say that it has grater acceleration.

a= dv/dt =Δv/Δt =  \(\frac{v_{2}- v_{1} }{t_{2}- t_{1}}\)

where    v₂= initial velocity

             v₁= final velocity

             t₂= initial time

             t₁ = final time  

Acceleration due to gravity is nothing but acceleration produced in the body due to gravitational force. According to second newton's second law, F=ma, force is responsible for the acceleration of the body. it is denoted by g and which is equal to 9.8 m/s². Acceleration due to gravity is affected by the height at which a body is from the surface of the earth.

Acceleration due to gravity at height h is given by,

g(h) = GM ÷ (R+h)²

where

g(h) = acceleration due to gravity at height h.

G = universal gravitational constant.

M = mass of the planet(earth)

R= radius of the planet(earth)

h = height of the object from surface.

Given,

G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

M = 5.97 × 10²⁴ kg

R = 6.3 × 10⁶ m

h=  6R

g(h) = (6.67 × 10⁻¹¹)×(5.97 × 10²⁴) ÷(R+6R)²

g(h) = 3.98×10¹⁴ ÷ (7×6.3 × 10⁶)²

g(h) = 0.2046 m/s²

Hence acceleration due to gravity of body is 0.2046 m/s²

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After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.

To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:

N(t) = N0 * \((1/2)^{(t / T)\),

where:

N(t) = number of atoms remaining at time t,

N0 = initial number of atoms (812 x  \(10^{20\) atoms),

T = half-life of the substance (21 minutes), and

t = time that has passed.

Let's calculate the number of atoms remaining after a given time.

Suppose the time passed is t = 42 minutes (twice the half-life).

N(t) = 812 x  \(10^{20\) * \((1/2)^{(42 / 21)\)

N(t) = 812 x  \(10^{20\) * \((1/2)^2\)

N(t) = 812 x  \(10^{20\) * 1/4

N(t) = 203 x  \(10^{20\) atoms.

So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.

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Answer:

where u put it last time or retrace ur steps to where u last put it

Answer:

VR=2

Explanation:

driven=60

driving=30

but VR=driven/driving

VR=60/30

VR=2

hence the velocity ratio VR is 2

Explanation:

A concave lens is also known as a diverging lens because it is shaped round inwards at the centre and bulges outwards through the edges, making the light diverge. They are used to treat myopia as they make faraway objects look smaller than they are.

Answer:

Different ions are deflected by the magnetic field by different amounts. The amount of deflection depends on: the mass of the ion. Lighter ions are deflected more than heavier ones.

The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.

Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.

When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.

The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.

In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.

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Answer:

The velocity of the steel pellet relative to the ground when it leaves the sling shot is approximately 5.960 meters per second.

Explanation:

Let suppose that RC car-slingshot-steelpellet is a conservative system, that is, that non-conservative forces (i.e. friction, air viscosity) can be neglected. The velocity of the steel pellet can be found by means of the Principle of Energy Conservation and under the consideration that change in gravitational potential energy is negligible and that the RC car travels at constant velocity:

\(\frac{1}{2}\cdot (m_{C}+m_{P})\cdot v_{o}^{2} + \frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m_{C}\cdot v_{o}^{2} + \frac{1}{2}\cdot m_{P}\cdot v^{2}\)

\(\frac{1}{2}\cdot m_{P}\cdot v_{o}^{2} + \frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m_{P}\cdot v^{2}\)

\(m_{P}\cdot v_{o}^{2} + k\cdot x^{2} = m_{P}\cdot v^{2}\)

\(v^{2} = v_{o}^{2} + \frac{k}{m_{P}}\cdot x^{2}\)

\(v = \sqrt{v_{o}^{2}+\frac{k}{m_{P}}\cdot x^{2} }\) (1)

Where:

\(v_{o}\) - Initial velocity of the steel pellet, measured in meters per second.

\(v\) - Final velocity of the steel pellet, measured in meters per second.

\(k\) - Spring constant, measured in newtons per meter.

\(m_{P}\) - Mass of the steel pellet, measured in kilograms.

\(m_{C}\) - Mass of the RC car, measured in kilograms.

\(x\) - Initial deformation of the spring, measured in meters.

If we know that \(v_{o} = 5.6\,\frac{m}{s}\), \(k = 85\,\frac{N}{m}\), \(m_{P} = 0.025\,kg\) and \(x = 0.035\,m\), then the velocity of the steel pellet relative to the ground when it leaves the sling shot is:

\(v = \sqrt{\left(5.6\,\frac{m}{s} \right)^{2}+\frac{\left(85\,\frac{N}{m} \right)\cdot (0.035\,m)^{2}}{0.025\,kg} }\)

\(v \approx 5.960\,\frac{m}{s}\)

The velocity of the steel pellet relative to the ground when it leaves the sling shot is approximately 5.960 meters per second.

Answer:

upward thrust, makes the rocket go up

and kentic energy, you swing and the energy that was built up before you hit the ball was transferred

Explanation:

Answer:

Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).

Explanation:

Convert velocity to the standard units (meters per second):

\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).

Convert mass to standard units (kilograms):

\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).

When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:

\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).

Answer:

\(F=5(240t^2i+72tj)\ N\)

Explanation:

Given that,

The mass of the object, m = 5 kg

The position vector is, \(r=20t^4i+12t^3j\)

Velocity, \(v=\dfrac{dr}{dt}=80t^3i+36t^2j\)

Acceleration, \(a=\dfrac{dv}{dt}=240t^2i+72tj\)

Newton's second law of motion is given as follows:

F = ma

Put all the values,

\(F=5(240t^2i+72tj)\ N\)

Hence, this is the required solution.

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

When Gordon jumps into the pool and creates waves that travel from one end of the pool to the other, this is an example of wave transmission.

Wave transmission occurs when waves pass through a medium, such as water in this case, without being absorbed or reflected. In other words, the waves propagate through the medium and continue to travel in the same direction, potentially with some attenuation (reduction in amplitude) due to frictional losses.

In the case of Gordon jumping into the pool and creating waves that propagate through the water, the waves are not absorbed by the water or reflected back towards Gordon, but instead continue to propagate through the water in the direction in which they were generated. Therefore, this is an example of wave transmission.

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Answer:

I believe the answer is Property taxes

Explanation:

Answer: I'm pretty sure property taxes

Explanation:

Answer: This (random) thermal motion of the particles due to the temperature is also called Brownian motion. ... The higher the temperature, the faster the diffusion will be, because the stronger the molecule movement and thus the “mixing”.

Explanation:

Answer:

Enrol in our 50 studyscore masterclass. Click here! Fuel cells are a type of primary cell in that they are not recharged, However, they are unique because they never run out, if the reactants are constantly supplied.

Answer:

The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

The given parameters;

Current flowing in the wire, I = 4.00 mA

Initial diameter of the wire, d₁ = 4 mm = 0.004 m

Final diameter of the wire, d₂ = 1 mm = 0.001 m

Length of wire, L = 2.00 m

Density of electron in the copper, n = 8.5 x 10²⁸ /m³

The initial area of the copper wire;

The final area of the copper wire;

The initial drift velocity of the electrons is calculated as;

The final drift velocity of the electrons is calculated as;

The change in the mean drift velocity is calculated as;

The time of motion of electrons for the initial wire diameter is calculated as;

The time of motion of electrons for the final wire diameter is calculated as;

The average acceleration of the electrons is calculated as;

Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

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Explanation:

The changing mean drift velocity of the electrons plays out at 3.506 x 10⁻⁷ m/s along with an average acceleration nearing 4.38 x 10⁻¹⁵ m/s².

As the electrons traverse one end of the wire to another, their mean drift velocity undergoes a shift of 3.506 x 10⁻⁷ m/s with an average acceleration of 4.38 x 10⁻¹⁵ m/s² in accordance with the following parameters:

- The current flowing through the wire is at 4.00 mA.

- The original diameter of the wire, d₁, measures at 4 mm or 0.004 m.

- Conversely, the final diameter, d₂, displays a measurement of 1 mm or 0.001 m.

- The length of the entire wire is consistent, measuring at 2 meters.

- Notably, the density of electrons present within copper reaches an estimated value of 8.5 x 10²⁸ /m³.

Calculations regarding both initial and final area coverage provided by copper must be explored along with numerical data involving the two varying drift velocities for accurate results.

Thus, we arrive at the change rate of the mean drift velocity between points in the wire as well as the plenitude of electron acceleration achieved after contemplation into the corresponding motion periods.

The conclusion reflects that our measurements find the changing mean drift velocity of the electrons plays out at 3.506 x 10⁻⁷ m/s along with an average acceleration nearing 4.38 x 10⁻¹⁵ m/s².

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The net electric force on charge q2 is 28.7 N.

The net electric force on charge q2 is calculated by applying Coulomb's law of electrostatic force.

F(net) = F(12) + F(23)

The force on q2 due to charge 1 is calculated as;

F(12) = -(9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.1²)

F(12) = 25.2 N

The force on q2 due to charge 3 is calculated as;

F(23) = (9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ )/(0.15²)

F(23) = 3.5 N

The net force on q2 is calculated as;

F(net) = 25.2 N + 3.5 N = 28.7 N

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Answer:

a) DOWN direction,  b)  directed INTO THE SCREEN, c)    F = 0

Explanation:

The direction of the force is

for electric force

           F = q E

where we assume a positive test charge, for which the force has the direction of the electric field.

For a magnetic field

in this case the direction of the force is given by the right hand rule.

For a positive test charge, the thumb points in the direction of velocity, the other fingers extended in the direction of the magnetic field, and the palm gives the direction of force for a positive charge.

           F = q v x B

Let us apply these considerations to our case.

a) negative charge moving to the left

in a magnetic field points away from the screen

In this case the thumb goes to the left, the fingers extended outwards and the palm points upwards, but since the charge is negative the force has a DOWN direction.

b) negative charge moves to the left

in electric field it points off the screen.

The outside is in the direction of the electric field and since the charge is negative, the force is directed INTO THE SCREEN

c) positive charge moves down

in magnetic field points up

in this case the velocity and the field have the same direction so the vector product of them is zero

       F = q v  B sin 0

       F = 0

The kinetic energy of the roller coaster at the bottom of the hill is 12250000 J

To answer this question, we must understand that the energy of a system is always conserved as explained by the law of conservation of energy.

The kinetic energy of the roller coaster will be equivalent to the potential energy of the roller coaster.

The kinetic energy of the roller coaster can be obtained as follow:

Kinetic energy = Potential energy

KE = mgh

KE = 2500 × 9.8 × 500

KE = 12250000 J

Therefore, the kinetic energy of the roller coaster is 12250000 J

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Answer:

electromagnetic radiation moves at the speed of light

Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Answer:

Hope this helps =)

Explanation:

The current in a short circuit may be very high because the resistance in the short circuit is probably less than the resistance in the original circuit.

Answer:

Zero

Explanation:

Because using

Deta X= dsinစ x n(lambda)

But we know that for central maxima

n is zero

So after substituting

Deta x = 0

Answer:

False

Explanation:

Sievert is the unit of dose equivalent

The initial velocity of the cart.

Newton, There can be a mass is four.080, So acceleration might be equal to 2.50 m in step with cent within the rectangular. Initial is that amount that relies upon total mass. The greater mass the more inertia. So Mass is 2000 kg and acceleration is 3 ms square. So this offers us an internet pressure identical to 6000 newtons or 6.0 and 210 to the power

In case you roll a ball, it initially will keep rolling except friction or something else stops it by means of pressure. you could also think about the way that your body maintains transferring ahead when you hit the brake on your bike. Translational Inertia = ma, in which m is the mass, and a is the acceleration of the object. Calculate the rotational inertia or the instant of inertia velocity by way of multiplying the mass of the object with a square of the gap between the item and the axis, the radius of rotation.

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