what will you use to measure the length of a copper wire of 50cm long?​

We are given that a force of 24N is exerted on an object to lift it a distance of 2.24m. To determine the work done we will use the following formula:

Where:

Substituting the values we get:

Solving the operations:

Therefore, the work done is 53.76 Joules.

Answer:

5

Explanation:

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Bluetooth works through radio waves in the ISM band, that is, they work by radio frequency. For that use the wireless networks of personal area (WPAN).

Bluetooth is a form of communication that works through radio waves by which there can be a transfer of data such as music, documents, images, etc. It works at a short distance so the devices must be close for the data transfer to occur correctly

Therefore, we can confirm that Bluetooth works through radio waves in the ISM band, that is, they work by radio frequency. For that use the wireless networks of personal area (WPAN).

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Answer:

Explanation:

To find the direction of the displacement vector, we have to solve for the ratio of both displacements, and furthermore the inverse tangent of the ratio.

Given data

200km east represents the x axis

70 km north represents y axis

the direction of the resultant is given as

∅= tan-1x/y

∅=tan-1 200/70

∅= tan-120/7

∅= tan-12.85

∅= 70.66°

hence the direction of the resultant is 70.66°

Answer:

Explanation:

No 1 is linked to the option provided at no 5.

A direct object is the noun that follows the verb and answers the question.

No 2 is linked to the option provided at no 8.

A verb is a word that expresses action.

No 3 is linked to the option provided at no 5.

The subject is what or whom the sentence is about.

No 5 is linked to the option provided at no 3.

A predicate noun follows a linking verb, and renames the subject.

No 6 is linked to the option provided at no 4.

A predicate adjective follows a linking verb, and describes a subject.

No 7 is linked to the option provided at no 1.

A linking verb joins a subject and a predicate.

No 8 is linked to the option provided at no 2.

A sentence expresses a complete thought....

Answer:

predicate noun: follows a linking verb and describes a subject

verb: a word that expresses action

direct object: a noun that indicates to or for whom or what something is done

sentence: expresses a complete thought

predicate adjective: verb that joins a subject and a predicate noun or predicate adjective

subject: who or what the sentence is about

indirect object: follows a linking verb and renames the subject

linking verb: the noun that follows the verb and answers the questions whom or what

Hope this helps!

Correct me if I'm wrong:)

Answer:

75 kg

Explanation:

Net Force

\(\sf \longmapsto F_{net} = 225N\)

Acceleration produced

\(\sf \longmapsto \: a = 3 .0 m / {s}^{2}\)

According to Newton's 2nd Law –

F = m•a

\(\sf \longmapsto \: M = \frac{F}{a} \)

\(\sf \longmapsto \: M = \frac{225N}{300m/s ^{2} } \)

\(\sf \longmapsto \: M = \: 75 \: kg\)

Hence, the mass of an object is 75 kg.

Answer:

70-100 BPM

Explanation:

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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(a) The linear momentum of the system is conserved due to the absence of external forces. (b) The kinetic energy of the system is generally not conserved in an explosion due to energy transfers and losses associated with the process.

(a)  According to the principle of conservation of momentum, the total momentum of an isolated system remains constant if no external forces act upon it. In the given scenario, the bomb is initially at rest, which means the total momentum of the system is zero before the explosion. After the explosion, the bomb fragments move in different directions, but their individual momenta add up to zero. Thus, the total momentum of the system remains conserved.

(b) In an explosion, a significant amount of potential energy stored in the bomb is rapidly converted into kinetic energy of the fragments. As the bomb explodes, the fragments gain kinetic energy, resulting in an increase in the total kinetic energy of the system. Additionally, the explosion may cause the fragments to collide with other objects or experience air resistance, leading to energy losses in the form of heat, sound, or work done against external forces. These energy losses further prevent the conservation of kinetic energy.

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The amount of work done by the gas is proportional to the pressure and the change in volume, as well as the efficiency of the process. If the pressure and volume are known, the work done by the gas can be calculated by multiplying these values by the efficiency of the process.

The amount of work done by a gas when it expands is proportional to the change in volume, pressure, and temperature. According to the first law of thermodynamics, the energy of a closed system is conserved, so the work done by the expanding gas is equal to the energy transferred from the gas to the environment in the form of work. Therefore, the work done by the gas is equal to the change in energy of the system. Assume that the process is 10% efficient. Then, only 10% of the energy available to the system is converted into work. This means that the remaining 90% of the energy is lost to the environment in the form of heat. As a result, the amount of work done by the gas expanding into the atmosphere is given by the formula

W = E x η, where W is the work done by the gas, E is the energy available to the system, and η is the efficiency of the process. The energy available to the system is determined by the difference between the internal energy of the gas before and after the expansion. The internal energy of a gas is determined by its temperature, pressure, and volume.

Assuming that the temperature and pressure are constant, the change in internal energy is proportional to the change in volume. Therefore, the energy available to the system is equal to the product of the pressure and the change in volume: E = P x ΔV, where P is the pressure of the gas and ΔV is the change in volume during the expansion. Substituting this equation into the formula for work, we get W = P x ΔV x η.

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Aproximately 1.09 m/s was the locust's first speed.

In engineering mechanics, vectors are used to express values with both a magnitude and a direction. For analysis, vector representations of a variety of engineering quantities—including forces, displacements, velocities, and accelerations—are required.

Δy = vsin(θ)t - 0.5gt²

0 = v*sin(55°)t - 0.5(-9.81 m/s²)*t²

t = 2vsin(55°)/g

Now, we can use the horizontal motion of the locust to find the initial velocity v. The horizontal distance traveled by the locust is given by:

Δx = v*cos(55°)*t

Substituting the expression for t that we just found:

0.750 m = vcos(55°)2vsin(55°)/g

Solving for v:

v = √(0.750 mg/(2sin(55°)*cos(55°)))

v ≈ 1.09 m/s

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n unit vector notation, -22j is the torque about the origin on a particle located at coordinate (o, -4.0m, 3.0m)


Torque is defined as the force that can cause an object to rotate along an axis is measured as torque. Estimate the angle between the vector connecting the force's application point and the pivot point and the direction of the applied force. You may calculate the torque by multiplying r by F and sin.

T=R (distance) x F (Force)

R=-4j+3k

F=2J

Hence, t=  R x F vector product

=(-4j+3k)x2j

=-4x2x(y x J)

=+3x2y(k x r)

=-8x(-k)+6j

=(6j+8k) nm

b) F^2=2J+4K

Hence, t=r x f^2

=(-4j+3k)x(2j+4k)

=0-16( J x k)+6(K x J)+0

=-16j-6j

=-22j  

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He employs kinematic equations to address this issue. The main equations we'll employ are Time-dependent positions: y = y0 + v0t + 1/2at2. The ball has a downward velocity of 0.175 m/s at 1.50 seconds.

These equations allow us to determine the location and speed of the ball 1.50 seconds after it is thrown:

Position:

y = y0 + v0t + 1/2at^2

y = 0 + 15.0 m/s * 1.50 s + 1/2 * (-9.81 m/s^2) * (1.50 s)^2

y = 11.0 m

The ball is thus 11.0 m above the point of throw at 1.50 seconds after being thrown.

Velocity:

v = v0 + at

v = 15.0 m/s + (-9.81 m/s^2) * 1.50 s

v = 0.175 m/s

The acceleration of an item in free fall is -9.8 m/s/s. (The minus symbol represents a downward acceleration.) For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.

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Answer:

two of the same instrument playing notes at slightly different frequencies

Explanation:

The correct answer is two of the same instrument playing notes at slightly different frequencies.

Frequency is the number of occurrences of a periodic event per unit of time. In the context of sound waves, frequency refers to the number of complete cycles of a sound wave that occur in one second and is measured in units of Hertz (Hz).

In this question,

A beat frequency occurs when two sound waves with slightly different frequencies interfere with each other, resulting in a periodic variation in the amplitude of the resulting wave. The beat frequency is equal to the difference in frequency between the two original sound waves.

When two of the same instrument play notes at slightly different frequencies, the sound waves produced by each instrument will have slightly different frequencies due to differences in tuning or other factors. When the two sound waves interfere with each other, they will produce a beat frequency equal to the difference between their frequencies. This beat frequency will be audible as a periodic variation in the loudness or intensity of the sound.

In the other statements, There will not be any beat frequency because the sound waves being produced have either the same frequency or very different frequencies, which do not interfere with each other in a way that produces beats.

Therefore, The statement two of the same instrument playing notes at slightly different frequencies is correct.

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Given data

*The given velocity of the car is v(t)= 10 + 3t + 512

The acceleration of the car is calculated as

Thus, the acceleration of the car at t = 2 s is 3 m/s^2

Answer:

A. The long, medium, and short straws all mixed together and placed

in the box

The correct statement is Molecular collisions transfer thermal energy between the system and its surroundings. Thus, option D is correct.

The energy moves between a system of reacting substances and the surroundings by the collision of molecules. The transfer of heat or thermal energy between the system and its surroundings by the process of Conduction. Conduction is the process of transmitting the heat to the neighboring atoms or collisions by the process of collisions.

The conduction takes place more steadily in solids and liquids where the molecules are closer together. When the molecules are collided with the nearby molecules, the potential energy is converted into kinetic energy and hence the heat energy is transferred between the system and its surroundings.

Hence, Molecular collisions transfer thermal energy between the system and its surroundings. Thus, the correct option is D.

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The new distance of the 3.78 nC particle when the electrostatic force is doubled is 0.049 m.

The magnitude of the electrostatic force experienced by the 3.78 n C particle when it is 0.069 m from the 2.15 nC particle is calculated as follows;

F = kq₁q₂ / r²

where;

F = ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 0.069² )

F = 1.536  x 10⁻⁵ N

When this electrostatic force is doubled, the new distance of 3.78 nC particle from the 2.15 nC is calculated as;

r² = kq₁q₂ / 2F

r = √ ( kq₁q₂ / 2F )

r = √ [ ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 2 x 1.536  x 10⁻⁵ ) ]

r = 0.049 m

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Answer:

speed

Explanation:

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The ball that correctly relates the kinetic energy of a ball is;  Ball C

The kinetic energy of an object is the energy generated by an object in motion ( i.e. object whose speed is greater than zero )

and the formula for Kinetic energy = 1/2 mv^2 .

Ball B :

mass = 4kg , speed = 8 m/s . kinetic energy = 130 J

K.E = 1/2 ( 4 * 8^2 )

      = 128 J   ( 130 J ≠ 128 J ) ( does not correctly relate the kinetic energy

Ball C :

mass = 5 kg, speed = 8 m/s , kinetic energy = 160 J

K.E = \(1/2*\) \(( 5 * 8^2 )\)

      = 160 J  ( 160 J = 160 J )  ( correctly relates the kinetic energy )

Hence we can conclude that The ball that correctly relates the kinetic energy of a ball is;  Ball C.

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Answer:

b=c or b,c

Explanation:

the order of average normal stress developed on cross section through B, C and D c) B>C>D.

When examined at constant levels of the applied shear stress s, the initial stress distribution differences N1 (cv) show a decreasing trend as the solid fraction cv increases.In other words, the shear stress increases more quickly than the usual stress differential does with filler volume fraction.

How is the typical soil stress determined?

EF is the area, and is the stress, hence F1 = EF.EF = EF = θ θ θ θ θ θ = θ θ θ θregular stress on the plane's EF.We can select the value of from this equation in a way that it equals zero.The primary plane is the one that forms this angle with block, which only experiences normal stress.

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Answer:

The answer is 1.35m.

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Answer:

61.33 Kg

Explanation:

From the question given above, the following data were obtained:

Distance = 1×10² m

Time = 9.5 s

Kinetic energy (KE) = 3.40×10³ J

Mass (m) =?

Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:

Distance = 1×10² m

Time = 9.5 s

Velocity =?

Velocity = Distance / time

Velocity = 1×10² / 9.5

Velocity = 10.53 m/s

Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:

Kinetic energy (KE) = 3.40×10³ J

Velocity (v) = 10.53 m/s

Mass (m) =?

KE = ½mv²

3.40×10³ = ½ × m × 10.53²

3.40×10³ = ½ × m × 110.8809

3.40×10³ = m × 55.44045

Divide both side by 55.44045

m = 3.40×10³ / 55.44045

m = 61.33 Kg

Thus, the mass of Leroy Burrell is 61.33 Kg

The average speed of the whole journey is 54 mph.

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Answer:

FALSE

Explanation:

Answer:

Participant 1 wins

Explanation:

Coefficient of static, μ = F/N, where F is the frictional force and N is the normal force.

The force exerted by each participant is the sum of the frictional force acting on each of them and the maximum force with which each participant pulls on the rope.

Frictional force, F =  μ * N

Normal force, N = mass * acceleration due to gravity, g

For Participant 1; μ = 2.0, mass = 60 kg, g = 9.8 m/s²

Frictional force = 2.0 * 60 * 9.8 = 1176 N

Total force = (1176 + 1000) = 2176 N

For Participant 2; μ = 1.2, mass = 80 kg, g = 9.8 m/s²

Frictional force = 1.2 * 80 * 9.8 = 940.8N

Total force = (940.8 + 1200) N = 2140.8 N

From the values obtained above, Participant 1 exerts more force than Participant 2, therefore, Participant 1 wins

The exploded star is called a black hole.

The time horizon of the black hole is an area of spacetime where gravitational pull is so intense that nothing, not even light or other electromagnetic waves, have the energy to pass through it.

It is believed that the first black holes appeared shortly after the big bang, in the beginning of the cosmos. When the core of an extremely massive star is collapsed on itself, stellar black holes are created.

A supernova, also known as an exploding star, is also brought on by this collapse and sends a portion of the star into space.

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To calculate the weight of the block, we can use the formula:

Weight = Mass x Gravity

Where gravity is approximately 9.8 m/s^2.

First, we need to find the mass of the block. We can use the formula:

Density = Mass / Volume

The volume of the block is:

Volume = Length x Width x Height

Volume = 10 cm x 3 cm x 2 cm

Volume = 60 cm^3

We don't know the density of the metal, so we can't calculate the mass directly. However, we can use the spring balance reading to find the weight of the block.

The spring balance has a maximum reading of 10 Newtons, which corresponds to a length of 20 cm. When the block is hung on the balance, it stretches the string by 15 cm. The extension of the spring is proportional to the weight of the block, so we can use the following proportion:

Extension of spring / Total length of spring = Weight of block / Maximum weight of spring balance

Substituting the values we have:

15 cm / 20 cm = Weight of block / 10 N

Solving for the weight of the block:

Weight of block = 7.5 N

Now we can find the mass of the block:

Mass = Weight / Gravity

Mass = 7.5 N / 9.8 m/s^2

Mass = 0.765 kg

Finally, we can calculate the density of the metal:

Density = Mass / Volume

Density = 0.765 kg / 60 cm^3

Density = 0.01275 kg/cm^3

So the weight of the block is 7.5 N, the mass of the block is 0.765 kg, and the density of the metal is 0.01275 kg/cm^3.

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Answer:

Explanation is given

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