what type of hybridization is exhibited by the central atom in chclo? group of answer choices a. sp b. sp2 c. sp3 d. sp3d e. sp3d2

Answer:

1+

Explanation:

Sodium has one valence electron. When it bonds with a nonmetal like sulfur, it gives up that electron to become a positively charged ion (cation) with a charge of 1+.

HCl>H2S>PH3

Explanation:

Acidity is directly proportional to non metallic character. as we move in period (i.e. from left to right) non metallic character increases hence acidic strength increases.

The order of the acidic strength from strongest to weakest: HCl > H₂S > PH₃. Therefore, option (a) is correct.

The acidic strength measures the ability of the acid to lose its H⁺ ion. In general dissociation of acid can be shown as:

HA  →  H⁺ + A⁻

Some examples of strong acids are hydrochloric acid, perchloric acid  (HClO4), sulfuric acid (H2SO4), etc.

For the given acids, with the increase in the electronegativity from phosphorous to chlorine in the period. The bond pair of electrons attract more strongly by the electronegative atom.

Due to this, the weaker bond can easily donate the proton. Hence, HCl has a greater tendency to liberate proton (H⁺) than phosphine (PH₃). After dissociation,  the anion can be easily stabilized by a more electronegative Chlorine atom.  

Therefore, the order of acidic strength for the given acids is HCl> H₂S > PH₃.

Learn more about acidic strength, here:

https://brainly.com/question/3223615

#SPJ2

Among the given options, there is only one chemical property, which is flammability. This property measures the capability of substance to burn or ignite when exposed to a flame.

It means that in chemical properties you should put the flammability of ethyl alcohol.

In physical properties you should put the rest of the options.

Trisaccharides, an oligosaccharide, are created when three monosaccharides are linked together by two glycosidic connections.

Trisaccharides, an oligosaccharide, are created when three monosaccharides are linked together by two glycosidic connections. The constituent monosaccharides can form each glycosidic bond between any hydroxyl group, just like the disaccharides can.

To know more about Trisaccharides visit:

https://brainly.com/question/1333943

#SPJ9

Answer:

22.4/3.8=5.89

Explanation:

Answer:

Explanation: I don’t even know what you said

Answer:

so basically

Explanation:

bsuxnssu hhusnn ji

All proteins have the ability to act as buffers. Proteins are made up of amino acids. It contains both positively and negatively charged amino and carboxyl groups. The charged regions of these molecules can bind hydrogen and hydroxyl ions. So they act as buffers.

A general rule of thumb for choosing a suitable buffer for a chosen pH is to choose a buffer whose pKa is within one pH unit of the test. This ensures that the experimental pH stays within the desired range and prevents unwanted changes in protein behavior while maintaining protein safety and health.

A general rule for keeping proteins stable is that the pH of the buffer should be within 1.0 pH unit of the pI or isoelectric point of the protein. The pI is the pH at which a protein has no net charge and is determined by the aggregate pKa of each amino acid in the protein. The kidneys help control acid-base balance by excreting hydrogen ions and producing bicarbonate, which helps maintain plasma pH within the normal range.

Learn more about The protein here:-https://brainly.com/question/2054570

#SPJ4

Extrapolation method for determining the titration end point is more accurate than finding the minimum conductivity because there is no human error when calculating as there could be with doing the actual experiment

Extrapolation is the estimating an unknown value based on extending a known sequence of values and to extrapolate is the infer something not explicitly stated from existing information and the point at which the indicator changes color is called as endpoint and so the addition of an indicator to the analyte solution help us to visually spot the equivalence point in an acid base titration and the endpoint refer to the point at which the indicator changes color in and acid base titration

Know more about titration

https://brainly.com/question/1886350

#SPJ4

The solutions will be ranked as follows from lowest to highest vapor pressure:

20 g. of glucose C6H12O6 in 100ml h2o

20 g. of sucrose C12H22O11 in 100ml h2o

10 g. of potassium acetate KC2H3O2 in 100ml h2o

The vapor pressure depends on the concentration and nature of the solute. A nonvolatile solute like sugar will decrease the vapor pressure of the solvent, while a volatile solute such as acetate salt , will increase it

Both glucose and sucrose are non-volatile solutes, so they will decrease the vapor pressure of the solvent and thus will have lower vapor pressure than the pure solvent. However, sucrose has a lower molecular weight than glucose which means that it will have a greater effect on the vapor pressure of the solution and thus have a slightly lower vapor pressure.

To know more about sucrose, visit:

brainly.com/question/29186350

#SPJ1

Answer:

i cant help you, if you'd like you can re-post this with a photo of the bacterial shapes or explain them.

Explanation:

:)

Answer:

Explanation:

Here, we want to get which of the compounds have the highest percentage by mass of nitrogen

What we have to do here is to divide the mass of nitrogen atoms in the compound by the molecular mass of the compound

a) NH3

The atomic mass of nitrogen is 14 amu, the atomic mass of hydrogen is 1 amu

The molar mass is thus 14 + 3(1) = 17 g/mol

The percentage by mass of nitrogen will be

14/17 * 100 = 82.35 %

b) HCN

The atomic mass of carbon is 12 amu

Thus, we have the molar mass as

1 + 12 + 14 = 27 g/mol

Percentage of nitrogen by mass will be : 14/27 * 100 = 51.85 %

c) For N2O

The atomic mass of oxygen is 16 amu

The molar mass of the compound will be 14(2) + 16 = 44 g/mol

Percentage of nitrogen by mass will be = 28/44 * 100 = 63.64 %

d) NI3

The atomic mass of iodine is 127 g/mol

So the molar mass of the compound will be:

14 + 3(127) = 395 g/mol

Percentage by mass of nutrogen will be

14/395 * 100 = 3.54 %

From what we have, the highest percentage by mass of nitrogen is 82.35 % and that belongs to ammonia (NH3)

The size of micropipette that you would select to deliver 215 microliters would be a micropipette with a volume range of 200-1000 microliters.

What is a micropipette?

A micropipette is a laboratory instrument used to measure and dispense small volumes of liquid, typically in the range of microliters (µL) or nanoliters (nL). They are commonly used in chemistry, biology, and biochemistry experiments, as well as in clinical and industrial settings.

Micropipettes consist of a handle, a digital or manual volume adjustment mechanism, and a tip that is placed into the liquid to be dispensed. They work by creating a vacuum or positive pressure inside the tip, which draws or pushes the liquid out of the tip.

Micropipettes come in different volume ranges and it is important to select the right one to ensure accurate delivery of the desired volume. For example, a micropipette with a volume range of 2-10 microliters would not be suitable for delivering 215 microliters, while a micropipette with a volume range of 200-1000 microliters would be more appropriate.

It's also important to note that, even if the micropipette is able to deliver 215 microliters, you should always check the calibration of the micropipette before use, to make sure that it's delivering the correct volume.

Hence, a micropipette with a volume range of 200-1000 microliters is suitable to deliver 215 microliters.

To learn more about a micropipette from the given link:

brainly.com/question/28425080

#SPJ4

Answer:

Closed-toe shoes, long pants, a lab coat, safety glasses with side shields or splash goggles, and gloves.

Explanation:

Answer: the answer is ch3ch2ch3 would have the fewest intermolecular forces with only dispersion forces

Explanation:

Answer: 51 g

Explanation:

The specific heat of the metal is 0.387 J/g°C.

To find the specific heat of the metal, we can use the formula:

q = m × c × ΔT

where q is the heat transferred, m is the mass of the metal, c is its specific heat, and ΔT is the change in temperature. We can assume that there is no heat lost to the surroundings, so the heat gained by the water is equal to the heat lost by the metal:

qwater = -qmetal

We can also use the formula for the heat gained or lost by the water:

qwater = mwater × cwater × ΔT

where mwater is the mass of the water and cwater is its specific heat. We can plug in the values given in the problem:

qwater = (102.0 g) × (4.184 J/g°C) × (48.1°C - 23.2°C)
qwater = 10771.46 J

Now we can solve for the heat lost by the metal:

qmetal = -10771.46 J

We can use the formula for the heat gained or lost by the metal:

qmetal = mm × cm × ΔT

where mm is the mass of the metal and cm is its specific heat. We can rearrange the formula to solve for the specific heat:

cm = qmetal / (mm × ΔT)

We can plug in the values given in the problem:

cm = (-10771.46 J) / (225 g × (48.1°C - 100.0°C))
cm = 0.387 J/g°C

Therefore, the specific heat of the metal is 0.387 J/g°C.

learn more about specific heat

https://brainly.com/question/27991746

#SPJ11

It is important to use the same solvent for the rinse as for the recrystallization process to ensure the maximum recovery and purity of the solid product.

When isolating the solid after recrystallization using vacuum filtration, the solvent used to aid in the rinse from the Erlenmeyer flask to the vacuum filter funnel should be the same solvent used in the recrystallization process. This is because the solvent should be a good solvent for the solid being purified, so it can dissolve the impurities and allow them to be removed from the solid during the recrystallization process. Using a different solvent for the rinse could dissolve some of the solid product, reducing the yield and purity of the final product.

To know more about recrystallization

brainly.com/question/14918321

#SPJ4

KOH is a strong base, so [OH-] = 0.10 M = 1.0 x 10^-1 M

[H+][OH-] = Kw

Kw = 1.0 x 10^-14

[H+] = 1.0 x 10^-14 / 1.0 x 10^-1 = 1.0 x 10^-13 M

Answer:

Explanation:

1 mole of iron is 56 grams (rounded)

x mole of iron is 38 grams (given

1/x = 56/38                Cross multiply

56x = 38*1                Divide by 56

x = 38/56

x = 0.679 mols of iron

1 mol of anything = 6.02 * 10^23

0.678 mols of iron = x

1/0.679 = 6.02 *10^23 /x

x = 0.679 * 6.02*10^23

x = 4.09 * 10 ^23

So there are 4.09 * 10^23 atoms of Fe in 38 grams of iron

Answer:

Commensalism is a symbiotic relationship in which one species benefits while the other species is not affected. One species typically uses the other for a purpose other than food.

Explanation:

let's have a look at bohrs postulates to answer the question, (bohrs model was applicable only for hydrogen like species)

Now coming to your question,

Electrons can only orbit the nucleus in a fixed circular orbit.

Electrons prefer fo orbit in the shell which are close to nucleus or having less energy.

Each shell can only hold a specific number of electrons given by formula 2n² where n is the number of shell,

the 1st shell can hold 2n² = 2×1² = 2 electrons

the 2nd shell can hold 2×2² = 8 electrons

the 3rd shell can hold 2×3² = 18 electrons

An atom can gain or lose electrons to form an ion.

\(\sf \small \pink{Thanks }\: \green{for} \: \blue{joining} \: \orange{brainly } \: \red{community}!\)

Answer:

Al avanzar hacia la derecha por el período 5, el tamaño atómico, la energía de ionización y los electrones de valencia: A. disminuye, aumenta y aumentan, respectivamente.

Explanation:

El radio atómico representa la distancia que existe entre el núcleo y la capa de valencia, es decir la más externa. Por medio del radio atómico es posible determinar el tamaño del átomo.  En un período el tamaño atómico disminuye de izquierda a derecha pues en este sentido aumenta el  número atómico aumentando la carga nuclear mientras que el efecto pantalla y el número de  niveles permanecen constantes. En otras palabras, disminuye de izquierda a derecha debido a la atracción que ejerce el núcleo sobre los electrones de los orbitales más externos, disminuyendo así la distancia núcleo-electrón.

Al avanzar hacia la derecha por el período 5, el tamaño atómico disminuye.

La energía de ionización es la necesaria para remover un electrón a un átomo en estado  gaseoso. Mientras más lejos del núcleo esté el electrón, es más fácil removerlo porque se necesita  menos energía. Al aumentar el número atómico de los elementos de un  mismo período, se incrementa la atracción nuclear sobre el  electrón más externo, ya que disminuye el radio atómico y  aumenta la carga nuclear efectiva sobre él. Entonces en un período, al aumentar el número atómico, la energía de ionización aumenta.

Entonces, al avanzar hacia la derecha por el período 5, la energía de ionización y los electrones de valencia aumenta.

Los electrones de valencia  son los electrones que están en la última capa electrónica (llamados orbitales de valencia) y tienen una alta posibilidad de participar en una reacción química.

En cada período aparecen los elementos cuyo último nivel de su configuración electrónica coincide con el número del período, ordenados por orden creciente de número atómico. Por ejemplo, el período 3 incluye los elementos cuyos electrones más externos están en el nivel 3.

Los electrones de valencia aumentan en número a medida que se avanza en un período.

Entonces, al avanzar hacia la derecha por el período 5, los electrones de valencia aumentan.

Answer:

solid(particles are rightly packed)

liquid(particles are losely packed)

gas(particles move freely)

Explanation:

there u go, hope it helps

Answer:he period of a simple pendulum is T=2π√Lg T = 2 π L g , where L is the length of the string and g is the acceleration due to gravity.

Explanation:

Answer:

Stem

Explanation:

Answer:

option-(d) stem

Explanation:

Stems have four main functions which are: Support for and the elevation of leaves, flowers and fruits. The stems keep the leaves in the light and provide a place for the plant to keep its flowers and fruits. Transport of fluids between the roots and the shoots in the xylem and phloem...

I hope it help you

The given question requires us to calculate the pH of a solution formed by mixing 100.0 mL of 0.100 M NaF and 100.0 mL of 0.060 M HCl. The Ka of HF is given as 7.24 × 10-4. The following is the step-by-step explanation of how to calculate the pH of the given solution.

Mixing 100.0 mL of 0.100 M NaF and 100.0 mL of 0.060 M HCl we get:0.100 M × 100.0 mL = 10.0 mmol NaF0.060 M × 100.0 mL = 6.00 mmol HCl. We need to find the final concentration of NaF and HCl and determine if a buffer is formed or not. Initially, we have: NaF → Na+ + F-HCl → H+ + Cl-Therefore, in the final solution, we have: Na+ + H+ + F- + Cl- → Na+ + Cl- + HF. The final concentration of NaF is given by: Concentration = moles/volume= (10.0 mmol)/(200.0 mL)= 0.050 M. Similarly, the final concentration of HCl can be determined to be 0.030 M.

Consequently, the final concentration of HF is:6.00 mmol – 10.0 mmol = –4.00 mmol The negative value implies that all of the NaF has reacted with the HCl and that there is no NaF left over to react with water. This indicates that there is no buffer formed, and the solution will be acidic. We can write the following equilibrium equation for HF:HF (aq) + H2O (l) ⇌ H3O+ (aq) + F- (aq). The Ka for HF is 7.24 × 10-4.Ka = [H3O+][F-]/[HF]We can assume that [H3O+] ≈ [F-]. Hence, we can write the expression as follows: Ka = [H3O+]2/[HF]= (7.24 × 10-4) = [H3O+]2/(0.050)Therefore,[H3O+] = √(7.24 × 10-4 × 0.050) = 1.08 × 10-3 pH = –log[H3O+]= –log(1.08 × 10-3) = 2.97Hence, the pH of the given solution is 2.97.

To know more about equilibrium equation visit

https://brainly.com/question/32209502

#SPJ11

Answer:

Metals have high densities, high melting points, are malleable and ductile, and can conduct heat and electricity.

Option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

The long-run equilibrium condition for perfect competition is that price (P) is equal to average total cost (ATC), which is also equal to marginal cost (MC), and marginal revenue (MR).

Option (d), P=ATC=MR=MC, best represents the long-run equilibrium condition for perfect competition. In perfect competition, firms operate at the minimum point of their average total cost curve, where price equals both average total cost and marginal cost. This condition ensures that firms are earning zero economic profit and are producing at an efficient level.

In the long run, if firms are earning economic profit, new firms will enter the market, increasing competition and driving prices down. Conversely, if firms are experiencing losses, some firms may exit the market, reducing competition and causing prices to rise. This process continues until firms reach a state where price equals average total cost, marginal cost, and marginal revenue, ensuring a long-run equilibrium.

Therefore, option (d), P=ATC=MR=MC, accurately represents the long-run equilibrium condition for perfect competition, reflecting the balance between price and cost for firms operating in a competitive market.

Know more about Equilibrium here:

https://brainly.com/question/30694482

#SPJ11