What type of continuous distribution (normal, positively or negatively skewed, bimodal, exponential) would best represent the following situations? a) The age of people who have retired. b) The number of red Smarties in boxes of Smarties. c) The shoe sizes of Stouffvillians. d) The wait time between calls to Pizza Pizza.

Answer:

SRM, MRS

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

the range is the largest number take away the smallest number

56-41=15

The future amount is equal to $17,605.4.

Mathematically, compound interest can be calculated by using this mathematical expression:

A(n) = P(1 + r)^{n}

Where:

Substituting the given parameters into the compound interest formula, we have;

A(12) = 1000(1 + 0.27)^{12}

A(12) = 1000(1.27)^{12}

A(12) = 1000 × 17.6054

A(12) = $17,605.4

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We have to put the triangular side as the base.

So, the height of the tent is signified by the red line, h.

Shown below:

The volume of the triangular prism is area of triangle x height

Let's find the area of the triangle, A_T:

The height is 10.

The volume is 280.

Substituting into the formula, let's sovle for "h". Shown below:

The dishonest shopkeeper marks his goods with a 40% markup and offers a 25% discount to customers. The profit earned by the shopkeeper on this particular item is $105 - $100 = $5.

Let's consider the cost price of an item to be $100. The shopkeeper marks it up by 40%, which results in a selling price of $140. However, the shopkeeper then offers a 25% discount on this inflated price, bringing the price down to $105.

Now, regarding the weight manipulation, the shopkeeper falsely claims that the weight of the item is 1kg. However, in reality, it weighs only 800g. Since the selling price is determined based on weight, the customer is paying the price of 1kg while receiving only 800g of the item.

To calculate the profit, we need to subtract the cost price from the selling price. The selling price, taking into account the discount and weight manipulation, is $105. The cost price is $100. Hence, the profit earned by the shopkeeper on this particular item is $105 - $100 = $5.

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The probability that the person participates in at least one school-sponsored activity given that the student works part-time is 0.58.

The possibility of an event or outcome occurring based on the existence of a prior event or outcome is known as conditional probability.

Assume that events A and B are two independent occurrences with probabilities P(A) and P(B), respectively, such that the probability that event B will occur given that event A is given by: P(B|A) = P(A∩B)/P (A)

Given:

Percentage of the students who have part-time jobs, P(A) = 73%

Percentage of the students who participate in at least one school-sponsored activity, P(B)= 65%

Percentage of the students who work part-time and participate in at least one school-sponsored activity, P(A∩B) = 42%

The probability that the person participates in at least one school-sponsored activity given that the student works part-time is:

P(B|A) = P(A∩B)/P(A)

          = 42/73

          = 0.58

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Answer:

0.575

Step-by-step explanation:

nice job

Answer:

87.5% loss

Step-by-step explanation:

6 • 250 = 1500

4.5 • 35 = 157.5

6 - 4.5 = 1.5

1.5 • 20 = 30

157.5 + 30 = 187.5

1500x = 187.5

x = 0.125

12.5% is an 87.5% decrease

Answer:

no images are available here

The trough's dimensions are base 1 = 0.53 m, base 2 = 1.47 m, height = 0.62 m and depth = 0.77 m. The formula for the volume of a trapezoidal prism is used to solve this problem.

Given, the trough has the capacity to hold 100 liters of water.

The formula for the volume of a trapezoidal prism is given as follows:

V = (a+b)/2 × h × d

where,a and b are the lengths of the bases,h is the height of the trapezoidal cross-section,and d is the depth of the prism.

Therefore,

V = (a+b)/2 × h × d100 L = (a+b)/2 × 0.62 m × 0.77 mLHS = 100000 mL (converting from L to mL)

100000 = (a+b)/2 × 0.62 × 0.77100000 = (a+b) × 0.2405

(a+b) = 416.1806a + b = 416.1806

We can obtain the value of b by solving the linear equation 1.47a - b = 0 and a + b = 416.1806.

Therefore, b = 168.8965 m

We can now substitute the value of b in equation 1.47a - b = 0 to find the value of a.1.47a - 168.8965 = 0a = 114.9481 m

Therefore, the trough's dimensions are base 1 = 0.53 m, base 2 = 1.47 m, height = 0.62 m and depth = 0.77 m.

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Answer: x - 1.5

4x – 97 + 12 – x = -80.5

3 x - 85 = -80.5

3 x - 85 +85 = -80.5 + 85

3x = -80.5 + 85

3x = 4.5

x = 1.5

Step-by-step explanation: hope this helps

Answer:

x=1.5

Step-by-step explanation:

4x-97+12-x=-80.5

Combine like terms

-97+12=-85

4x-x=3x

now you have 3x-85=-80.5

add 85 to both sides and now you have

3x=4.5

Now divide 3 to both sides and you get x=1.5

Answer:

\(a - 10 = \frac{a}{5 } - 2 \\ \\ \implies \: a - 10 = \frac{a - 10}{5} \\ \\ \implies \: 5a - 50 = a - 10 \\ \\ \implies \: 5a - a = - 10 + 50 \\ \\ \implies \: 4a = 40 \\ \\ \implies \: a = \cancel\frac{40}{4} \\ \\ \implies \: a = 10\)

hope helpful ~

Answer:

a-10=a/5-2

a-10=a/3

3(a-10=a/3)

3a-30=a

3a-a=30

2a=30

a=15

The slope of a function is defined as the change in y-coordinate with respect to the change in x-coordinate of the line.

m = Δy/Δx

∆y --> net change in the y coordinate

∆x ---> net change in x coordinate

m ---> slope of fution

The y-intercept of both functions 'f' and 'g' are equal and slope of f(x) is less than the slope of g(x). So, the correct option is option (A).

We have given a function, g (x) = 2x + 1

comparing the g(x) with standard equation

y = mx + b

where m is slope of this line

b --> y-intercept

Thus we get m = 2 , b= 1 . So, the slope of g(x) is 2 and y-intersecpt is 1 .

Now, we have a table for function f(x) that is function f(x) passing through all points as given in table. The slope of function passing through (h,k) and (a,b) is expressed as (k-b)/(h-a)

Thus, slope of function 'f' passing through (0,1) and (2,4) = (1-4)/(0-2) = -3/-2

= 3/2

=> f (x) = (3/2)x + b

where , b --> y-intercept

plug the value x= 4 and corresponding to it

f(x) = 7 we get , 7 = 3/2× 4 + b

=> b = 7-6 = 1

Therefore, slope of function g(x) is greater than slope of function f(x) and y-intercept of f(x) is equal to y-intercept g(x) .

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Complete question:

The Table represents the linear function f(x), and the equation represents the linear function g(x). Compare the y-intercepts and the slopes of the linear functions f(x) and g(x) and choose the answer that best describes them.

x / f(x)

0/1

2/4

4/7

g(x)= 2x+1

A. The slope of f(x) is less than the slope of g(x). The y-intercept of f(x) is equal to the y-intercept of g(x).

B. The slope of f(x) is less than the slope of g(x). The y-intercept of f(x) is greater than the y-intercept of g(x).

C. The slope of f(x) is greater than the slope of g(x). The y-intercept of f(x) is equal to the y-intercept of g(x).

D. The slope of f(x) is less than the slope of g(x). The y-intercept of f(x) is greater than the y-intercept of g(x).

Answer:

C. Yes, there is an outlier at 110. This means that one person's age was 110, which is 25 years older than the next closest age.

Step-by-step explanation:

An outlier is a data point that sticks out like a sore thumb. It's so different from the rest of the data that it makes you wonder if it's a mistake or a miracle. One way to spot an outlier is to use the 1.5IQR rule, where IQR stands for interquartile range. The interquartile range is the gap between the third quartile (Q3) and the first quartile (Q1) of the data. The 1.5IQR rule says that any data point that is more than 1.5*IQR above Q3 or below Q1 is an outlier.

In this case, the first quartile (Q1) is 75, the third quartile (Q3) is 85, and the interquartile range (IQR) is 10. So, any data point that is more than 1.5*10 = 15 above 85 or below 75 is an outlier. The only data point that does this is 110, which is 25 above 85. That means 110 is an outlier.

What does this outlier mean in this situation? It means that one person who came to the senior center that afternoon was way older than the rest of the folks. The average age of the visitors was not changed by this outlier, since it was just one out of 12 data points. But, the outlier does mess up the range and the standard deviation of the data, making them bigger than they would be without the outlier.

Answer:The answer is C

Step-by-step explanation:I did the test.

Answer:

53×3= 159

1908-159(0)= 318

53×6= 318

318-318=0

Answer- 36

first blank-

(1) 5 9

______

Second blank-

(3) 1 8

-

3 1 8

______

third blank-

0

_____

Answer-

3 6

On average, 10.2 times would a gaming app be launched over a six-month period.

The percentage change in the total number of app launches in feb 2014 compared to feb 2015 is 29.78%.  

1.75 times a gaming app is launched, a retail app is launched.

The average number of times a gaming app would be launched over a six-month period is 13, this is based on the given data of January to June, the total number of launches was 72, and the number of gaming app launches was 42.

Therefore,

Average = Total number of launches / Number of gaming app launches

Average = 72/42 ≈ 1.7

per month, so for a six-month period, the average would be

1.7 × 6 = 10.2 (approx) launches.

We are given the data for February 2014 and February 2015:

February 2014 - 47 launches

February 2015 - 61 launches

The percentage change can be calculated using the following formula:

Percentage change = ((New value - Old value) / Old value) × 100

Substituting the values,

Percentage change = ((61 - 47) / 47) × 100

Percentage change = (14 / 47) × 100 ≈ 29.78%

Based on the given data, for the year 2014, the number of gaming app launches was 182 and the number of retail app launches was 318.

Therefore,

Each time a gaming app is launched, the retail app is launched

318 / 182 ≈ 1.75 times.

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Answer:

\( - 26 \sqrt{10} \)

Step-by-step explanation:

Simplify.

\( \rightarrow \sqrt{40} \: \: \: \: \: \: \: \: \\ = \sqrt{4 \times 10} \: \: \: \\ = \sqrt{4} \times \sqrt{10} \\ = 2 \times \sqrt{10} \: \: \: \: \\ = 2 \sqrt{10} \: \: \: \: \: \: \: \: \: \)

\( \rightarrow \sqrt{160} \\ = \sqrt{16 \times 10} \: \: \: \\ = \sqrt{16} \times \sqrt{10} \\ = 4 \sqrt{10} \: \: \: \: \: \: \: \: \: \: \: \: \)

Let us solve the given expression now.

\( - \sqrt{40} - 6 \sqrt{160} \\ - 2 \sqrt{10} - 6 \times 4 \sqrt{10} \\ - 2 \sqrt{10} - 24 \sqrt{10} \\ - 26 \sqrt{10} \)

Answer: The box under 1000 is 1, because there are 1000 milliliters in 1 liter. your next box would be 6000, the box above 8 is 8000, and above 9 is 9000. Does this make sense? I hope so.

Answer:

ML: 1,000 | 6,000 | 8,000 | 9,000

L: 1 | 6 | 8 | 9

I hope this helps :)

According to ASC 420 Exit or Disposal Cost Obligations, exit or disposal cost obligations are liabilities that arise from one-time termination benefits provided to employees, costs associated with closing a facility, and other expenses incurred as a result of an exit or disposal activity.

These obligations are recognized and measured based on the principles of other applicable GAAP.

The relevant topic number for exit or disposal cost obligations is Topic 420. The specific eight-digit codification citation (XXX-XXXXX) that addresses the initial measurement of these obligations is 420-10-25-1. This paragraph notes that the fair value of the liability at the initial recognition date is the amount for which these obligations and related costs are measured.

The amount for which these obligations and related costs are measured is determined based on the fair value of the liability at the initial recognition date. This amount includes the estimated costs associated with employee severance arrangements, lease termination fees, and other direct costs associated with the exit or disposal activity.

The specific eight-digit codification citation (XXX-XX-XX-X) that describes the disclosure requirements in the notes to the financial statements for exit or disposal obligations is 420-10-50-2. This paragraph requires entities to disclose information about the nature and scope of the exit or disposal activity, including its timing, the expected completion date, the associated costs, and any significant uncertainties or risks that could affect the outcome or timing of the activity.

In summary, under ASC 420, exit or disposal cost obligations are recognized and measured based on their fair value at the initial recognition date. Entities are required to disclose information about the nature and scope of the exit or disposal activity, as well as any significant uncertainties or risks that could affect the outcome or timing of the activity.

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Answer:

8 to 1

Step-by-step explanation:

Answer:

8:1

Step-by-step explanation:

32:4

divid both sides by 4

8:1

To complete an order of 90 omelets in 15 minutes, the diner would need 6 cooks.

Given that four cooks can make 24 omelets in 10 minutes, we can calculate the rate of omelet production per cook per minute.

The rate per cook per minute can be calculated as:

Rate = Number of Omelets / Number of Cooks / Time

Rate = 24 omelets / 4 cooks / 10 minutes = 0.6 omelets per cook per minute

To determine the number of cooks needed to make 90 omelets in 15 minutes, we can use the following equation:

Number of Cooks = Number of Omelets / Rate / Time

Number of Cooks = 90 omelets / 0.6 omelets per cook per minute / 15 minutes = 6 cooks

Therefore, the diner would need 6 cooks to complete the order of 90 omelets in 15 minutes.

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Answer:

Step-by-step explanation:

The first thing they did was factor the denominators

so

x²-3x+2= (x-1)(x-2)

and

x²-1= (x-1)(x+1)

To add two fractions their denominators need to be the same

to accomplish this they mulitpied both sides of the fraction

after that they mulitplied what was in the numerator and combined like terms

Because the denominator cannot equal 0 x≠ -1, 1, 2

The approximate value of f(1) using Euler's method with two steps of equal size is 6.636. The range of f for t > 0 is 0 < f(t) < 6.

a. The limiting factor in this logistic differential equation is the carrying capacity, which is 6 in this case. As y approaches 6, the growth rate of y slows down, until it eventually levels off at the carrying capacity.

b. To use Euler's method, we first need to calculate the slope of the solution at t=0. Using the given differential equation, we can find that the slope at t=0 is y(0)/8(6-y(0)) = 8/8(6-8) = -1/6.

Using Euler's method with two steps of equal size, we can approximate f(1) as follows:

f(0.5) = f(0) + (1/2)dy/dx|t=0

= 8 - (1/2)(1/6)*8

= 7.333...

f(1) = f(0.5) + (1/2)dy/dx|t=0.5

= 7.333... - (1/2)(7.333.../8)*(6-7.333...)

= 6.636...

Therefore, the approximate value of f(1) using Euler's method with two steps of equal size is 6.636.

c. The range of f for t > 0 is 0 < f(t) < 6, since the carrying capacity of the logistic equation is 6. As t approaches infinity, f(t) will approach 6, but never exceed it. Additionally, f(t) will never be negative, since it represents a population size. Therefore, the range of f for t > 0 is 0 < f(t) < 6.

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The measure of the segment AC = 26.51 units in the given figure.

The relationship between the three sides of a right-angled triangle is explained by the Pythagoras theorem, commonly known as the Pythagorean theorem. The Pythagorean theorem states that the square of a triangle's hypotenuse is equal to the sum of its other two sides' squares. The Greek mathematician Pythagoras of Samos is credited with developing the Pythagoras theorem. He was a Greek philosopher who organised a community of mathematicians who practised rigorous number theory and had monastic lifestyles. Despite Pythagoras' invention of the theorem, there is evidence that suggests it was also used by other cultures.

From the given figure we observe that the triangle ABS and triangle ASC are similar using the SAS criteria.

Thus, segment AB = AC using CPCT.

Now, using the Pythagorean theorem we have:

AS² = BS² + AB²

Substitute the given values:

(28)² = (9)² + AB²

AB² = 703

AB = 26.51 units.

Since, AB = AC the value of the segment AC = 26.51 units in the given figure.

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The value of f(2) in the function f(x) = 2x is (c) 4

From the question, we have the following parameters that can be used in our computation:

f(x) = 2x

In f(2), we have

x = 2

To calculate f(2), we set x = 2 in f(x) = 2x

using the above as a guide, we have the following:

f(2) = 2 * 2

Evaluate

f(2) = 4

Hence, the value of f(2) in the function is (c) 4

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Question

Use the function below to find f2).

f(x) = 2x

A. 2

B. 6/4

c. 4

D. 15/3

The HDD for the month of January in State College, PA is 930.

To calculate the HDD (Heating Degree Days) for the month of January in State College, PA, we need to subtract the average daily temperature from 65 degrees Fahrenheit, which is considered the standard temperature for indoor heating.

HDD = 65°F - 35°F
HDD = 30°F

Therefore, the HDD for the month of January in State College, PA is 30 degrees Fahrenheit.
Hi! To calculate the Heating Degree Days (HDD) for the month of January in State College, PA with an average outside temperature of 35 degrees F, follow these steps:

1. Determine the base temperature: In the US, the base temperature is commonly 65 degrees F.
2. Subtract the average temperature from the base temperature: 65 - 35 = 30 degrees.
3. Multiply the difference by the number of days in the month: January has 31 days, so 30 * 31 = 930.

So, the HDD for the month of January in State College, PA is 930.

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To calculate the HDD for the month of January in State College, PA, we need to first determine the base temperature. The base temperature is the temperature below which a building needs to be heated in order to maintain a comfortable indoor temperature. In this case, we will use a base temperature of 65 degrees F.

To calculate the HDD, we need to subtract the average daily temperature from the base temperature and sum up the values for each day of the month. If we assume that January has 31 days, we can calculate the HDD as follows:

HDD = (65 - 35) x 31
HDD = 930

So the HDD for the month of January in State College, PA is 930. This means that during the month of January, there were 930 heating degree days, which indicates the amount of heating required to maintain a comfortable indoor temperature. It is important to note that the HDD can vary depending on the base temperature used, so it is important to choose a base temperature that is appropriate for the climate and the building being heated.

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The exact value of the logarithmic expression 12 · ㏒₃ [z⁷ / (y⁵ · t²)] is equivalent by logarithm properties to -711 / 5.

In this question we must determine the exact value of a logarithmic expression by means of logarithm properties, which are described below:

Logarithm of a product

㏒ (a · b) = ㏒ a + ㏒ b

Logarithm of a division

㏒ (a / b) = ㏒ a - ㏒ b

Logarithm of a power

㏒ aⁿ = n · ㏒ a

Now we proceed to determine the exact value of the expression:

12 · ㏒₃ [z⁷ / (y⁵ · t²)]

12 · [㏒₃ z⁷ - ㏒₃ (y⁵ · t²)]

12 · (㏒₃ z⁷ - ㏒₃ y⁵ - ㏒₃ t²)

12 · (7 · ㏒₃ z - 5 · ㏒₃ y - 2 · ㏒₃ t)

12 · (7 · 7.74 - 5 · 11.03 - 2 · 5.44)

-711 / 5

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To find the exponential function that describes the exponential growth or decline of customers coming to a restaurant.

We can use the general form of an exponential function, which is f(x) = ab^x, where a represents the initial value and b represents the base of the exponential function.

a) Given the initial point (0, 1) and the point (2, 16), we can substitute these values into the exponential function equation. Plugging in x = 0 and f(x) = 1, we get 1 = ab^0, which simplifies to a = 1. Plugging in x = 2 and f(x) = 16, we get 16 = b^2. Taking the square root of both sides, we find b = 4. Therefore, the exponential function is f(x) = 4^x.

b) Given the initial point (0, 1) and the point (-7, 2187), we can follow a similar process. Plugging in x = 0 and f(x) = 1, we have 1 = ab^0, which gives us a = 1. Plugging in x = -7 and f(x) = 2187, we get 2187 = b^(-7). Taking the seventh root of both sides, we find b = 3. Therefore, the exponential function is f(x) = 3^x.

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