Answer:
This is opinion, but i'll share some stuff, and reasons.
Explanation:
Push-ups- Muscular Strength. When we get older, it's good to do this exercise because it provides improved muscle and bone health with aging.
Burpees- Body composition. It's important do do this exercise because it can decrease the risk of type 2 diabetes, hypertension, and heart disease, and a lean and toned body.
What is the strength of the electric field at the position indicated by the dot in the figure?
E = _____ N/C
What is the direction of the electric field at the position indicated by the dot in the figure? Specify the direction as an angle above the horizontal line.
θ = ____ ⁰
The electric field has an angle of 0 degrees and a magnitude of 2546.35 N/C.
What is electric field?An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. It can also refer to a system of charged particles' physical field. Each location in space where a charge exists in any form can be considered to have an electric field attached to it. The electric force per unit charge is another name for an electric field. E = F/Q is the formula for the electric field. Volts per meter is the SI unit for the electric field. The Newton's per coulomb unit is the same as this one. Newton is a unit of force and Coulomb is a unit of energy in these derived units.
Here,
E=kq/r^2
r= 5 x r^2 = 7.07 cm or .0707 m
E=(9 x 10^9)(1 x 10^-9)/(.0707)^2
= 1800.5 N/C
Now to find the x component,
cos 45 = x/1800.5
x= 1273.18 N/C
Now just multiply by 2 to accommodate both charges,
E=2546.35 N/C in direction of 0 degrees
The electric field has a magnitude of 2546.35 N/C and an angle of 0 degrees.
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Describe an object's velocity when an acceleration-time graph is zero?
how much does it cost to charge an electric car at a public charging station
Answer:
Rs 16.5 lakh is a charge of an electric car at a public charging station
What is Justice according to philosophy
Answer:
justice. just in nature.
Explanation:
the concept of a proper proportion between a person's deserts (what is merited) and the good and bad things that befall or are allotted to him or her. ... Aristotle's discussion of the virtue of justice has been the starting point for almost all Western accounts.
Calculate the gravitational force between two 112 kg objects located 100 m from each other
The gravitational force between the two objects is 8.37×10^-11 N
What is Newton Law of universal gravitation?Newton Law of universal gravitation states that the force of attraction or repulsion between two object is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. From the law
This means that F = G×(mass1 × mass2)/(radius)²
Where G is the gravitational constant ,which is given as 6.67×10^-11 Nm²/kg² and r is the distance between them
the force between two objects with masses 112kg is F= 6.67×10^-11×112²/100²
F= 8.37×10^-11/10000
F= 8.37×10^-11 N
therefore the force of gravity between the two objects is 8.37×10^-11 N
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9. A speedboat engine exerts 90000 W of power in moving the boat through the water. The velocity of the boat is 1P = 5 m/s. What force does the engine apply to do this?
P = F x V
Answer:
it g hope it helps you out
What is the total energy of a proton moving with a speed of 0.83c, (in MeV)? You Answered A. 2,049.8843 B. 1,682.2043 margin of error +/- 1%
The total energy of a proton moving with a speed of 0.83c is approximately 1,682.2043 MeV.
To calculate the total energy of a particle in the context of special relativity, we need to consider the relativistic energy equation.
We can calculate the Lorentz factor using the formula γ = 1 / sqrt(1 - (v/c)²), where v is the velocity of the particle and c is the speed of light.
Substituting the values into the equation, we get γ = 1 / sqrt(1 - (0.83c/c)²) = 1 / sqrt(1 - 0.6889) ≈ 1 / sqrt(0.3111) ≈ 1 / 0.5577 ≈ 1.7927.
Next, we multiply the Lorentz factor by the rest mass of the proton. The rest mass of a proton is approximately 938.27 MeV/c². Multiplying the Lorentz factor by the rest mass, we get E = 1.7927 * 938.27 MeV/c² ≈ 1,682.2043 MeV.
Therefore, the total energy of the proton moving at 0.83c is approximately 1,682.2043 MeV.
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Deanna placed a 14 kg box on top of a shelf. Assuming the height of the shelf was 3. 2 meters, what was the potential energy of the box?
According to given information, the potential energy of the box is 439.04 kg m²/s². The potential energy of an object is given by the formula PE = mgh
The potential energy of an object is given by the formula PE = mgh, where PE represents potential energy, m represents mass, g represents the acceleration due to gravity, and h represents the height.
In this case, the mass of the box is 14 kg and the height of the shelf is 3.2 meters. The acceleration due to gravity is approximately 9.8 m/s².
To find the potential energy of the box, we can substitute the given values into the formula:
PE = (14 kg)(9.8 m/s²)(3.2 m)
Multiplying these values together, we find:
PE = 439.04 kg x m²/s²
Simplifying, we can conclude that the potential energy of the box is 439.04 kg x m²/s².
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At a drag race, a jet car travels 1/4 mile in 5.2 seconds. What is the final speed of the
car and its acceleration?
Answer:
1609.3
Explanation:
A student pushes against a wall with 20N of force and the wall does not move. In this situation, the wall exerts -
F 0N of force.
G 20N of force.
H less than 20N of force.
J more than 20N of force.
Answer:
G 20N of force
Explanation:
Every action has an equal and opposite reaction. The wall exterts as much force as you push on it.
Answer:
It is g
Explanation:
The wall is not moving nor is the kid therefore the force is equal
SOLVE PLS EZ FOR POINTS
The substance with meting point of 240 °C and boiling point of 300 °C is hard plastics. Any volume of alcohol has an 78 °C. Candle wax have higher melting point than water.
What is boiling point ?Boiling point of a substance is the temperature at which the substance is converts from liquid state to vapor state at which the the vapor pressure equal to the atmospheric pressure.
It is clear from the table that, substance with meting point of 240 °C and boiling point of 300 °C is hard plastics. Boiling point of a substance does not change with change in volume.
Hence, any volume of alcohol has an 78 °C. Candle wax have higher melting point than water.
Oxygen and nitrogen can be differentiated based on their densities and mass.
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4.
An "extreme" pogo stick utilizes a spring whose uncompressed length is 46 cm and whose force constant is 1.4 x 104 N/m. A 60-kg person is jumping on the pogo stick,
compressing the spring to a length of only 5.0 cm at the bottom of their jump. Which is the upward acceleration of the person at the moment the spring reaches its greatest
compression at the bottom of their jump?
6 m 2
Answer:
a = 85.9 m / s²
Explanation:
For this exercise we can use Newton's second law in the most compressed part
F - W = m a
force is the spring elastic force
F = - k Δx
k Δx - m g = m a
a = k/m Δx - g
Δx = x₀ -\(x_{f}\)
ΔX = 46 - 5 = 41cm (1m / 100cm) = 0.41 m
let's calculate
a = 1.4 10⁴/60 0.41 - 9.8
a = 85.9 m / s²
A No. _____ THHN conductor is required for a 19.7 ampere load if the ambient temperature is 75F and there are nine current-carrying conductors in the raceway.
A No. 12 THHN conductor is required for a 19.7-ampere load if the ambient temperature is 75F and there are nine current-carrying conductors in the raceway.
To determine the size of the THHN conductor required for a 19.7-ampere load, we will need to use the ampacity tables from the National Electric Code (NEC).
The ampacity tables provide the maximum current-carrying capacity of various types and sizes of conductors based on factors such as ambient temperature and the number of current-carrying conductors in the raceway or cable.
Assuming a copper conductor, we can use NEC Table 310.15(B)(16) to find the ampacity of a No. 12 THHN conductor at an ambient temperature of 75F with nine current-carrying conductors. According to the table, the ampacity of a No. 12 THHN conductor with nine current-carrying conductors at 75F is 20 amperes.
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the water pressure at the mid-ocean ridges exceeds times greater than atmospheric pressure at sea level.question 44 options:1000 or more500-700100-300300-500700-900
The mid-ocean ridges are underwater mountain ranges that run through the center of the Earth's oceans. They are formed by the movement of tectonic plates, which causes volcanic activity and the creation of new oceanic crust. The water pressure at the mid-ocean ridges is extremely high due to the depth of the ocean and the weight of the water above it.
At sea level, the atmospheric pressure is around 1013 millibars or 14.7 pounds per square inch (psi). In contrast, the water pressure at the depths of the mid-ocean ridges can reach up to 11,000 pounds per square inch (psi), which is more than 1000 times greater than atmospheric pressure at sea level. This extreme pressure makes it difficult for humans and equipment to explore and study the deep ocean environments found at the mid-ocean ridges.
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Pls Help Thx!! I’d Really Appreciate It
The charge on the moving particle is -5.38 x 10^-21 C and the potential difference between the two locations is 1300 V.
How do we calculate?
The formula for the electrical potential energy of a charge in an electric field is shown below:
ΔPE = qΔV
The given values are: :
distance moved, d = 4.0 m
magnitude of electric field, E = 325 N/C
change in potential energy, ΔPE = -6.9 x 10^-19 J
The work done by the electric field on a charge q as it moves a distance d in the direction of the field is:
W = -ΔPE = qEd
solving for the charge q as:
q = -ΔPE/Ed = -(6.9 x 10^-19 J)/(325 N/C × 4.0 m) = -5.38 x 10^-21 C
we can use the formula shown below to find the potential difference between the two locations, :
ΔV = Ed
ΔV = E × d = 325 N/C × 4.0 m = 1300 V
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A ball of mass 0.440 kg moving with a speed of 3.70 [m / s] collides head-on with a 0.220 [kg] ball at rest. If the 0.440 [kg] ball moves at 1.23 [m / s] in its original direction, what is the speed of the 0.220 [kg] ball after the collision?
Answer: 3.0 m/s
Explanation:
Conservation of momentum: total momentum before collision = total momentum after collision
momentum = p = mv
(0.440 kg)(3.70 m/s) + (0.220 kg)(0.0 m/s) = (0.440 kg)(1.23 m/s) + (0.220 kg)(x)
Solve for x, speed of the 0.220 kg ball after the collision:
1.628 + 0 = 0.54x
x = 1.628/.54 = 3.0 m/s
What is the energy density inside of a 1 m long coil with 2000 turns that carries 25 a?
The energy density inside a coil can be calculated using the formula:
Energy density (u) = (1/2) * (μ₀ * B^2)
Where u is the energy density, μ₀ is the permeability of free space, and B is the magnetic field strength.
The magnetic field strength (B) inside a solenoid (coil) is given by:
B = μ₀ * n * I
Where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current flowing through the coil.
Given:
Length of the coil (l) = 1 m
Number of turns (n) = 2000
Current (I) = 25 A
First, we need to calculate the magnetic field strength (B) inside the coil:
B = μ₀ * n * I
Next, we can calculate the energy density (u) using the magnetic field strength:
u = (1/2) * (μ₀ * \(B^2\))
Let's substitute the given values into the formulas:
B = μ₀ * n * I
B = (4π × \(10^{-7}\)) T·m/A) * (2000 turns/m) * 25 A
Calculate the value of B.
Once we have the value of B, we can calculate the energy density (u):
u = (1/2) * (μ₀ * \(B^2\))
Substitute the value of B and evaluate the expression to find the energy density inside the coil.
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2. Two vectors with magnitudes of 1 meters and 3 meters cannot have a resultant of (5.0 points)
3 meters
4 meters
O meters
2 meters
Answer:
the correct answer is 3 meters
which two actions would strengthen an electromagnet?
A. Add and ammeter into the circuit.
B. Decrease the size of the permanent magnet in the circuit.
C. increase the number of wraps of wire around the core.
D. Replace the magnetic core with aluminum nails.
E. Connect a second battery in the circuit.
please help!!!!, ONLY ANSWER IF YOU KNOW IT
Answer:
C. increase the number of wraps of wire around the core.
E. Connect a second battery in the circuit.
Explanation:
got the question current on a p e x
increase the number of wraps of wire around the core and Connect a second battery in the circuit are the two actions would strengthen an electromagnet.
what are the types of wiring ?
The distribution electrical power through wires in a perfect manner inside a building or a room with better load control is known as electrical wiring.
Different types of wiring such as Tee system or Joint box system where the connection of appliances is done with this wiring, which does not consume too much cable size.
Loop-in system means the system is used in lamps and other appliances are parallelly connected so that each appliance is controlled individually.
Cleat Wiring consists of ordinary VIR or PVC insulated wires is compounded on walls and ceilings by means of porcelain cleats, wood, or plastic, temporary system and is not suitable for domestic usage. For example, used in an under-construction building.
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Which of these abundance patterns is an unrealistic
chemical composition for a star?
A. 70% H, 28% He, 2% other
B. 95% H, 5% He, less than 0.02% other
C. 75% H, 25% He, less than 0.02% other
D. 72% H, 27% He, 1% othe
The unrealistic chemical composition for a star is 95% H, 5% He, less than 0.02% other. The correct option is B).
The reason is that stars primarily consist of hydrogen (H) and helium (He), with trace amounts of other elements. Hydrogen is the most abundant element in the universe, and helium is the second most abundant. Hence, it is reasonable to have a high percentage of hydrogen and a significant portion of helium in a star's composition.
Option B deviates from this pattern by having an excessively high percentage of hydrogen (95%) and an unusually low percentage of helium (5%).
It is highly unlikely to find a star with such a high hydrogen content because the fusion processes in stellar cores convert hydrogen into helium, leading to a lower proportion of hydrogen as compared to helium.
Furthermore, the extremely low concentration of other elements (less than 0.02%) in option B suggests an improbable absence of heavier elements typically found in stars. Therefore, the correct option is B).
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Let ϕ=e x
cosy. Let ϕ represent either temperature or electrostatic potential. Refer to Problem 11 for definitions and find: (a) The direction in which the temperature is increasing most rapidly at (1,−π/4) and the magnitude of the rate of increase. (b) The rate of change of temperature with distance at (0,π/3) in the direction i+j 3
. (c) The direction and magnitude of the electric field at (0,π). (d) The magnitude of the electric field at x=−1, any y. 14. (a) Suppose that a hill (as in Fig. 5.1) has the equation z=32−x 2
−4y 2
, where z= height measured from some reference level (in hundreds of feet). Sketch a contour map (that is, draw on one graph a set of curves z= const.); use the contours z=32,19,12,7,0. (b) If you start at the point (3,2) and in the direction i+j, are you going uphill or downhill, and how fast? 15. Repeat Problem 14b for the following points and directions. (a) (4,−2),i+j (b) (−3,1),4i+3j (c) (2,2),−3i+j (d) (−4,−1),4i−3j Determine whether the fol ∑ n=1
[infinity]
(−1) n+1
n 2
+16
10n
a) The direction in which the temperature is increasing most rapidly is the direction of the gradient vector ∇ϕ, which is ((1/√2) * e)i + ((1/√2) * e)j.
b) The rate of change of temperature with distance at (0, π/3) in the direction i + j√3 is (√2 + √3)/(2√2) * e.
c) The direction of the electric field is opposite to the gradient vector ∇ϕ
Let ϕ = e^x * cos(y), where ϕ represents either temperature or electrostatic potential.
I'll address each part of the problem separately:
(a) To find the direction in which the temperature is increasing most rapidly at (1, -π/4), we need to calculate the gradient of ϕ and evaluate it at that point.
The gradient of ϕ is given by ∇ϕ = (∂ϕ/∂x)i + (∂ϕ/∂y)j, where i and j are unit vectors in the x and y directions, respectively.
Taking partial derivatives of ϕ with respect to x and y, we have:
∂ϕ/∂x = e^x * cos(y)
∂ϕ/∂y = -e^x * sin(y)
Evaluating the partial derivatives at (1, -π/4), we get:
∂ϕ/∂x = e * cos(-π/4) = (1/√2) * e
∂ϕ/∂y = -e * sin(-π/4) = (1/√2) * e
Therefore, the gradient of ϕ at (1, -π/4) is:
∇ϕ = ((1/√2) * e)i + ((1/√2) * e)j
The direction in which the temperature is increasing most rapidly is the direction of the gradient vector ∇ϕ, which is ((1/√2) * e)i + ((1/√2) * e)j. The magnitude of the rate of increase is given by the magnitude of the gradient vector, which is √2 * e.
(b) To find the rate of change of temperature with distance at (0, π/3) in the direction i + j√3, we need to calculate the directional derivative of ϕ in that direction.
The directional derivative is given by the dot product of the gradient vector ∇ϕ and the unit vector in the given direction.
The unit vector in the direction i + j√3 is (1/2)i + (√3/2)j.
Calculating the dot product, we have:
∇ϕ · (1/2)i + (√3/2)j = ((1/2) * (1/√2) * e) + ((√3/2) * (1/√2) * e) = (1/2√2 + √3/2√2) * e = (√2 + √3)/(2√2) * e
So, the rate of change of temperature with distance at (0, π/3) in the direction i + j√3 is (√2 + √3)/(2√2) * e.
(c) To determine the direction and magnitude of the electric field at (0, π), we can use the relationship between the electric field and the gradient of the electrostatic potential.
The electric field E is given by E = -∇ϕ, where ∇ϕ is the gradient of the electrostatic potential.
Using the gradient formula from part (a), we have:
∇ϕ = ((1/√2) * e)i + ((1/√2) * e)j
Therefore, the electric field at (0, π) is:
E = -((1/√2) * e)i - ((1/√2) * e)j
The direction of the electric field is opposite to the gradient vector ∇ϕ,
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This response addresses various math problems related to temperature, electric fields, and contour maps. It explains how to find the direction and magnitude of the temperature change, the rate of change of temperature with distance, the direction and magnitude of the electric field, and whether you are going uphill or downhill on a hill. It also mentions that the given series cannot be evaluated without more information.
Explanation:(a) To find the direction in which the temperature is increasing most rapidly at (1, -π/4), we need to find the gradient of ϕ at that point. The gradient is a vector that points in the direction of the steepest slope of a function. So, we take the partial derivatives of ϕ with respect to x and y and evaluate them at (1, -π/4). The direction of the gradient vector gives us the direction of the fastest increase in temperature. The magnitude of the rate of increase is the length of the gradient vector.
(b) To find the rate of change of temperature with distance at (0, π/3) in the direction i+j√3, we need to find the directional derivative of ϕ in that direction. The directional derivative measures the rate at which a function changes in the direction of a given vector. It can be found by taking the dot product of the gradient vector and the unit vector in the given direction.
(c) To find the direction and magnitude of the electric field at (0, π), we need to find the gradient of ϕ at that point. The gradient gives us the direction of the electric field, and its magnitude gives us the strength of the field.
(d) To find the magnitude of the electric field at x = -1, any y, we need to find the gradient of ϕ at (x, y) and then evaluate it at x = -1. The magnitude of the gradient vector gives us the magnitude of the electric field.
(a) The contour map for z = 32 - x^2 - 4y^2 with contours z = 32, 19, 12, 7, and 0 is a set of curves that represent points on the surface of the hill with the same height. Each contour corresponds to a different height level.
(b) To determine if you are going uphill or downhill and how fast from the point (3, 2) in the direction i+j, you need to find the gradient of the hill function at (3, 2) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.
(a) To determine if you are going uphill or downhill and how fast from the point (4, -2) in the direction i+j, you need to find the gradient of the hill function at (4, -2) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.
(b) To determine if you are going uphill or downhill and how fast from the point (-3, 1) in the direction 4i+3j, you need to find the gradient of the hill function at (-3, 1) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.
(c) To determine if you are going uphill or downhill and how fast from the point (2, 2) in the direction -3i+j, you need to find the gradient of the hill function at (2, 2) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.
(d) To determine if you are going uphill or downhill and how fast from the point (-4, -1) in the direction 4i-3j, you need to find the gradient of the hill function at (-4, -1) and take the dot product of the gradient vector and the unit vector in the given direction. The sign of the dot product tells us the direction of the slope (uphill or downhill) and the magnitude tells us how fast you are going.
The given series, ∑[infinity](−1)^(n+1)/(n^2+16)/(10n), can be simplified into a summation series. However, it is incomplete and may contain typos or irrelevant parts, so it cannot be evaluated further without additional information or corrections.
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The battleship and enemy ships A and B lie along a straight line. Neglect air friction. A battleship simultaneously fires two shells with the same initial velocity at these two enemy ships. If the shells follow the parabolic trajectories shown in the figure, which ship gets hit first?
1. need more information
2. both hit at the same time
3. A
4. B
Answer: A
Explanation:
it is closer
Device A has a current of 0.4 A and a resistance of 3 Ω. Device B has a current of 0.6 A and a resistance of 3Ω. Which device would be more energy efficient?
Your answer would be Device A.
Answer:
Device A because it would use more voltage :D
Explanation:
How far is the sun, alpha centauri A, Sirius B, Bernard's Star, Sirius A, and Proxima Centauri from the earth in light years
The distance of sun, alpha centauri A, Sirius B, Bernard's Star, Sirius A, and Proxima Centauri from the earth is 1.578 * \(10^{-5}\), 4.367, 8.611, 5.978, 8.611 and 4.264 light years.
The distance of the planet Earth from other celestial bodies are as mentioned below:
Sun = 1.578 * \(10^{-5}\) Light yearsAlpha Centauri A = 4.376 Light yearsSirius B = 8.611 Light yearsBernard's Star = 5.978 Light yearsSirius A = 8.611 Light yearsProxima Centauri = 4.264 Light yearsA light year is measure of distance. It is distance covered by a light particle in a period of one year. Light travels at the speed of 3 * \(10^{8}\) m / s. So one light year will be equal to a distance of 9.46 trillion kilometers.
Therefore, the distance from Earth to
Sun = 1.578 * \(10^{-5}\) Light yearsAlpha Centauri A = 4.376 Light yearsSirius B = 8.611 Light yearsBernard's Star = 5.978 Light yearsSirius A = 8.611 Light yearsProxima Centauri = 4.264 Light yearsTo know more about light years
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According to current FDA rules on "cola" drinks, ________.
Answer:
6 Mg caffeine per ounce
Explanation:
According to current FDA rules on "cola" drinks,
✓ They cannot contain more than 6 mg caffeine per ounce.
ball is thrown upward from a window that is 12 m above the ground. The ball reaches a maximum height of 4 m above the window before falling all the way down to the ground. What distance did the ball travel?
Answer:
20 m
Explanation:
The ball travels 4 m up, then 16 m down. It travels a total distance of 20 m.
Question 1
What is a Static Load
A. is a load at rest like the weight of an object the structure is supporting or the weight of the structure itself.
B. in between radio stations
C. Aload in Motion
D. A force that is equal
12 A car travels in a straight line at speed v along a horizontal road. The car moves
against a resistive force F given by the equation
F = 400+kv²
where F is in newtons, v in ms-1 and k is a constant.
At speed v = 15ms-1, the resistive force F is 1100 N.
a
Calculate, for this car:
i the power necessary to maintain the speed of 15ms-¹,
ii the total resistive force at a speed of 30 ms-¹,
iii the power required to maintain the speed of 30ms-¹.
Answer:
i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii) Find the value of k first: F = 400 + k(15^2) k = 28/9 F = 400 +(28/9)(30^2) = 320
Explanation:
A ball is thrown vertically upward. As it rises, what happens to its potential energy?
Answer:
Explanation:
As the ball rises, its PE increases because the potential energy is equal to the mass of the ball times gravity times the height of the ball. The higher the height, the higher the PE.
Answer:
According to the law of conservation of energy its kinetic energy is getting converted in to potential energy because of gain in height. So, if the velocity of a ball goes on decreasing when it is thrown vertically upwards. When its velocity becomes zero, its potential energy becomes maximum.
we divide the electromagnetic spectrum into six major categories of light, listed below. rank these forms of light in order of increasing wavelength
- ultraviolet
- gamma rays
- radio waves
- visible light
- infrared
- X rays
Ranking the forms of light in order of increasing wavelength:
1. Gamma rays, 2. X-rays, 3. Ultraviolet, 4. Visible light, 5. Infrared, 6. Radio waves.
In this order, the wavelengths increase from shorter to longer as we move from gamma rays to radio waves. The electromagnetic spectrum is a continuum of electromagnetic waves arranged in order of increasing wavelength. Gamma rays have the shortest wavelength and the highest energy, followed by X-rays, ultraviolet, visible light, infrared, and radio waves with progressively longer wavelengths. This ranking represents the arrangement of these forms of light from shortest to longest wavelengths.
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