What percentage of a DC signal passes through a high pass filter? What percentage would pass through a low pass filter?

Answers

Answer 1

In a high-pass filter, the percentage of a DC signal that passes through is effectively zero. Conversely, in a low pass filter, the percentage of a DC signal that passes through is 100%.

A high-pass filter allows high-frequency components of a signal to pass through while attenuating low-frequency components. Since a DC signal has a frequency of zero, it is considered a low-frequency component. Therefore, in a high pass filter, the capacitors and/or inductors used in the circuit effectively block the DC signal, allowing close to zero percent of the DC signal to pass through.

On the other hand, a low-pass filter permits low-frequency components of a signal to pass through while attenuating high-frequency components. As a DC signal has no frequency beyond zero, it is considered a low-frequency component. Consequently, in a low-pass filter, the capacitors and/or inductors in the circuit have a negligible effect on the DC signal, enabling close to 100% of the DC signal to pass through the filter unaffected.

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Related Questions

a car moving on a road passes by kilometer 218 at 10:15 am and milestone 236 at 10:30 am. determine an average scalar speed in km / h over this stretch.

Answers

Answer:

v?

Explanation:

v = ∆s / ∆t

v =?

∆s = 236 - 218 = 18km

=t = 10: 30 - 10:15 = 15 minutes to hour 15/60 = 0.25h

v = 18 / 0.25

v = 72km / h

speed of 72km / h

A gun is fired with muzzle velocity 1099 feet per second at a target 4750 feet away. Find the minimum angle of elevation necessary to hit the target. Assume the initial height of the bullet is 0 feet, neglect air resistance, and give your answer in degrees.

Answers

A gun is fired with muzzle velocity 1099 feet per second at a target 4750 feet away. The minimum angle of elevation necessary to hit the target is approximately 15.2 degrees.

To find the minimum angle of elevation, we can use the equation for the horizontal range of a projectile. The horizontal range is the distance traveled by the bullet in the horizontal direction, which in this case is 4750 feet. The equation for the horizontal range is: R = (v^2 * sin(2θ)) / g

where R is the range, v is the muzzle velocity, θ is the angle of elevation, and g is the acceleration due to gravity.

Rearranging the equation to solve for θ, we have: θ = 0.5 * arcsin((R * g) / v^2). Plugging in the given values, we have: θ = 0.5 * arcsin((4750 * 32.2) / (1099^2))

Evaluating this expression, we find that the minimum angle of elevation necessary to hit the target is approximately 15.2 degrees. This means that the gun should be elevated at an angle of approximately 15.2 degrees above the horizontal in order to hit the target 4750 feet away.

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GENTE ME AJUDEM NESTA QUESTÃO POR FAVOR, TENHO PROVA ONLINE AMANHÃ! "Um sonar de um navio de pesca localizou um cardume de sardinhas a 300 m de profundidade. Sabendo que a velocidade de propagação do som na água tem o valor de 1500 m/s, calcula o tempo que decorre desde a emissão dos ultra-sons e a sua receção no navio." Por favor!

Answers

Answer:

The time between the emission of the wave and it's reception was 0.4 seconds.

Explanation:

The sound wave emitted by the sonar traveled from the boat to the fishes and came back, therefore the distance of it's total route is twice the distance from the boat to the fishes. We can apply the average speed formula in order to solve this problem, this is done below:

\(\text{speed} = \frac{\text{distance}}{\text{time}}\)

We were given the distance traveled by the wave and it's speed, therefore we can solve for the time:

\(\text{time} = \frac{\text{distance}}{\text{speed}}\\\\\text{time} = \frac{(2*300)}{1500}\\\\\text{time} = \frac{600}{1500} = 0.4 \text{ s}\)

The time between the emission of the wave and it's reception was 0.4 seconds.

A truck with an overall mass of 6,500 kg is accelerating at 0.3 m/s2. What force does the engine need to apply in order to do this? (Round to the nearest tenth of a decimal.)

Answers

Answer:

1950 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6500 × 0.3

We have the final answer as

1950 N

Hope this helps you

Which one of the following energy sources is most likely to lead to thermal pollution?A) a coal-fired power plantB) a large field of windmillsC) a hydroelectric plantD) a large field of solar cells

Answers

The energy sources that is most likely to lead to thermal pollution is option C) a hydroelectric plant

Energy production is essential for the modern world, but it often comes at a cost, with various forms of pollution resulting from different energy sources.

Out of the energy sources listed, a coal-fired power plant is most likely to lead to thermal pollution. This is because coal-fired power plants generate electricity by burning coal to heat water and produce steam, which drives a turbine to generate electricity.

Hydroelectric plants generate electricity by using the kinetic energy of falling water to turn a turbine, but the water used for generating electricity is not heated, so there is no thermal pollution.

In conclusion, thermal pollution is a form of pollution caused by energy production that can have harmful effects on aquatic life and the overall ecosystem of a body of water.

Hence the option (c) is correct.

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the drawing shows an exaggerated view of a rifle that has been"sighted in" for a 91.4-meter target. If the muzzle speed of thebullet is v0 = 427 m/s, what are the two possible anglesθ1 and θ2 between the rifle barreland the horizontal such that the bullet will hit the target? One ofthese angles is so large that it is never used in target shooting.(HInt: the following trigonometric identity may be useful: 2 sinθ cos θ = sin 2 θ.)

Answers

The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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5 points
A car, of mass 1600 kg, is travelling at a speed of 20 m/s when the driver
applies the brakes. The car decelerates at a constant rate and stops. The
braking force used to stop the car and driver was 8000 N. Calculate the
braking distance of the car in m. This is a two step problem, you must
calculate a value and use it to find the final answer.

Answers

Answer:

The braking distance of the car is 40 m

Explanation:

The two steps are;

1) Calculation (finding) of the initial kinetic energy , K.E., of the car

2) Calculation (finding) of the braking distance from the calculated K.E., of the car

The initial Kinetic energy of the car, K.E. = 1/2×m×v²

Where;

m = The mass of the car = 1,600 kg

v = The velocity of the car = 20 m/s

∴ K.E. = 1/2 × 1,600 kg × (20 m/s)² = 320,000 joules

2) The work done in stopping the car, W = The braking force, 'F' × The braking distance, 'd'

∴ W = F × d

Where;

F = The braking force = 8,000 N

d = The braking distance of the car

By energy conservation principle, the work, 'W', that is required to stop the car = The initial kinetic energy of the car, K.E.

∴ W = K.E. = 320,000 joules

Therefore, by substituting the known values for the variables, we have;

320,000 J = 8,000 N × d

∴ d = 320,000 J/(8,000 N) = 40 m

The braking distance of the car, 'd' = 40 m.

Sitting on the table is a red book and a blue book. Which one is hotter?
A. Books are not blackbodies, so they do not emit radiation.
B. The red book
C. They are probably the same temperature
D. The blue book

Answers

C. They are probably the same temperature. it is likely that both the red book and the blue book are at the same temperature.

The color of an object does not inherently determine its temperature. The perceived color of an object is based on the wavelengths of light it reflects or absorbs. While different colors may have different abilities to reflect or absorb light, this does not necessarily indicate differences in temperature. Without additional information about the books or their exposure to external heat sources, it is reasonable to assume that both books sitting on the table would be at the same ambient temperature. In the absence of any specific heating or cooling mechanisms acting on the books, they would equilibrate with the surrounding environment and reach the same temperature over time.

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Compared to its average speed in air, the average speed of a beam of light in glass is Select one:
a. the same.
b. more.
c. less.

Answers

Answer:

C is the correct answer.

Explanation:

we have given about light and we have to compare the speed of light in air as well as in glass. So let's take the expression of refractive index of glass. Suppose we are representing a refractive index of glass with respect to air. So this will be equal to the fraction or the ratio of the speed of light in air divided by the speed of light in glass. Hence we get the expression in the modified form as speed of light in glass is equal to speed of light in air, divided by the refractive index of glass with respect to air. So obviously when we consider the refractive index of class with respect to air, it is a number which is more than one. Hence from equation number A we get that the speed of light in glass will be less than that speed of light in air. Hence we can get it the correct answer. As the choice number C means the answer is less. This is our final answer.

Thank you.

Green light has a wavelength of about 510 nm and travels at a speed of 3. 00 × 108 m/s. The frequency of green light, rounded to the nearest tenth and written in scientific notation, is × 1014 hz.

Answers

Green light has a wavelength of about 510 nm and travels at a speed of 3. 00 × 108 m/s. The frequency of green light, rounded to the nearest tenth and written in scientific notation, is 5.9 × 10¹⁴ Hz.

Light is the name given to the type of electromagnetic radiation that can be detected by the human eye. It's visible light that we can see. When all of the different colors that make up visible light are combined, white light is formed. These colors are red, orange, yellow, green, blue, indigo, and violet.

Light travels at a speed of 299,792 kilometers per second, or 186,282 miles per second. This speed is also referred to as the "speed of light." In a vacuum, the speed of light is constant.How is the frequency of light calculated?The frequency of light is the number of wave cycles that pass a fixed point in space per second. This number is expressed in units of hertz (Hz).

To calculate frequency, divide the speed of light by the wavelength of the light: c = λνWhere,ν is the frequency of lightλ is the wavelength of lightc is the speed of light

Putting the given values in the above formula we get,ν = c/λν = (3.00 × 10⁸ m/s) / (510 nm)Convert 510 nm to meters,1 nm = 1 × 10⁻⁹m510 nm = 510 × 10⁻⁹m = 5.10 × 10⁻⁷mSubstitute the given values,ν = (3.00 × 10⁸ m/s) / (5.10 × 10⁻⁷m)ν = 5.9 × 10¹⁴ HzTherefore, the frequency of green light, rounded to the nearest tenth and written in scientific notation, is 5.9 × 10¹⁴ Hz.

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A 9.0-V battery is connected to a resistor so that there is a 0.50-A current through the resistor.For how long should the battery be connected in order to do 160 J of work while separating charges?

Answers

The battery should be connected to the circuit for 35.6 seconds in order to do 160 J of work while separating charges.

According to the conservation of energy principle, the electrical energy supplied by the battery equals the work done on the charges in the circuit.

The expression that relates electrical energy and work done is W = VIt,

where W is the work done,

V is the voltage of the battery,

I is the current,

and t is the time that the battery is connected to the circuit.

In this particular case, the voltage of the battery is 9.0 V, the current is 0.50 A, and the work done is 160 J.

Using the expression above, we can solve for the time that the battery should be connected to the circuit.

t = W/VI

= (160 J)/(9.0 V x 0.50 A)

= 35.6 s.

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how does a particle differ from its anti-particle? it has opposite mass. it has opposite charge. its wave-function is the opposite sign. all of the above none of the above

Answers

An antiparticle is a subatomic particle that, by definition, has the same mass as its normal particle counterpart but the opposite magnetic moment and electric charge. An electron's antiparticle, for instance, is the positron.

The mass of an antiparticle is equal to that of the particle version, but it has the opposite charge. Antiparticles have opposite charges, baryon numbers, lepton numbers, and strangeness. A subatomic particle known as an antiparticle has the same mass as a particle of regular matter but the opposite electric charge and magnetic moment. Thus, the positron (a positively charged electron) is the opposite of the negatively charged electron.

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is this kinetic or potential energy: A baseball has reached its highest point after being hit toward the top of the stadium

Answers

Answer: Kinetic because it’s in motion.


Potential is when it’s not in motion but has the potential. For example, if you were going to drop a pencil, it would have potential energy while in your hand but kinetic when it’s falling.

URGENT: If there is a 2 kg ball and a 5 kg ball with the same kinetic
energy, which one will be moving faster?
a. the 5 kg ball
b. the 2 kg ball
C. They will move with the same speed
d. None of the above. Explain.

Answers

Answer:

there is less mass to move so the 2kg ball will move faster. the kinetic energy of the 5kg ball will move slower due to the fact that it needs more energy to move if it has more mass.

Answer:

the 2kg ball

Explanation:

there is less mass to move so the 2kg ball will move faster. the kinetic energy of the 5kg ball will move slower due to the fact that it needs more energy to move if it has more mass.

What is thermal energy.

Answers

Explanation:

thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat the flow of thermal energy

The term 'thermal energy' is used differently, and often loosely, in different contexts. It refers to several distinct physical concepts, such as the internal energy, or as the enthalpy, of a body of matter and radiation; or as heat, defined as a type of energy transfer (as is thermodynamic work); or as the characteristic energy of a degree of freedom,
k
B
T
{\displaystyle k_{\mathrm {B} }T}, in a system that is described in terms of its microscopic particulate constituents, where
T
T denotes temperature and
k
B
k_{\mathrm{B}} denotes the Boltzmann constant.

I learned this last week in my Sci-tech class!

2
Select the correct answer.
A force of 15 newtons is applied to both Object A with a mass of 25 kilograms and object with a mass of 50 kilograrns. What is true about the
acceleration of Object A and Object B?
OA Acceleration of Object Als four times that of the acceleration of Object B.
OB Acceleration of Object A is the same as the acceleration of Object B.
OC. Acceleration of Object A is half the acceleration of Object B.
OD. Acceleration of Object A is twice that of the acceleration of Object B.
Reset
Next

Answers

Answer:

D. The Acceleration of object A is twice that of Object B.

This is because a force pushing on something light will move faster than an equally strong force pushing on something heavier.

If it took Mrs. Coleman 1.4 s to go from the 10 m mark to the 15 m mark, what was Mrs. Coleman's average speed?​

Answers

Answer:

1m every 0.28 seconds

Explanation:

she travelled 5 m in 1.4 s, so divide it by itself, 1.4s divided by 5 m gets you 0.28s for 1m

constriction is made in a clinical thermometer why​
subject :science (energy)

Answers

Answer:

The constriction in the thermometer is to prevent the mercury from dropping back to the bulb when the reading is being taken. It is easier for us to take reading. It prevents the thermometric substance (Mercury or Alcohol) from running back into the bulb.

Explanation:

Hope it is helpful....

Answer:

constriction is made in a clinical thermometer because it prevents the thermometric liquid from running back into the bulb.

Introduction to Physical Science: Tutorial and Asking Questions
This activity will help you meet these educational goals:
. You will ask questions to identify and clarify evidence for an argument.
. You will apply scientific principles to design a process.
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end
of the activity, write a brief evaluation of your work.
Activity
Spend time observing or thinking about events that involve matter and energy. Which events can you explain? Which
events can't you explain? Now answer the following questions.
Part A
Describe three events that you cannot explain.
BIUX X₂ 15px
AVA
Space used (includes formatting): 0/15000
26 of 40
行 ≡ ≡ V 田
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Answers

Energy and matter are both conserved within natural processes. It follows that while energy and matter can adopt different forms, they cannot be produced or extinguished. Different types of matter and energy can combine, and energy and matter frequently cycle within a system.

Explain energy.

Energy is the ability to perform tasks. It could appear in numerous different forms, such as potential, kinetic, thermal, electrical, chemical, nuclear, etc. Additionally, there is heat and work, which is energy being transferred from one entity to another.

The most important source of chemical energy for sustaining life is found in food. The three states of matter—liquid, solid, and gas—are essential because matter and energy move in concert along food networks.

An ice cube composed of water, for instance, changes into liquid water when you add energy, and when you add even more energy, it turns into steam. The type of matter and the quantity of matter are the same as in the original cube, but the level of energy may be higher or lower.

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I need help please and thank you

I need help please and thank you

Answers

Answer: magnitude= 2 m/s/s

Explanation: I goes up 2 every second

The angular acceleration of a rotating body is given in radians and seconds byα(t)=7+5t+8t2.What are the units of the three numbers in the expression? Use the abbreviations rad and s.

Answers

The angular acceleration is a measure of how quickly the rotational speed of the body is changing.

The expression \(\alpha (t) = 7 + 5t + 8t^2\) represents the angular acceleration of a rotating body as a function of time t.

The constant term of 7 represents the initial angular acceleration of the body, measured in radians per second squared (\(rad/s^2\)). The coefficient of t, 5, represents the rate at which the angular acceleration is increasing with time, measured in radians per second cubed (\(rad/s^3\)). The coefficient of \(t^2\), 8, represents the rate at which the rate of increase in angular acceleration is changing with time, measured in radians per second to the fourth power (\(rad/s^4\)).

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Explain at least 3 different ways that you can motivate yourself past any distractions to reach your goals. (The subject is Physical Education)
Help!
Due today

Answers

Answer:

Explanation:

Set specific, achievable goals: Break down your larger goal into smaller, more manageable targets that you can work towards each day. When you accomplish these smaller goals, it will give you a sense of accomplishment and motivation to continue working towards your larger goal.

Visualize your success: Imagine yourself successfully achieving your goal and all of the positive feelings that come along with it. This visualization can help keep you focused and motivated when distractions arise.

Find an accountability partner: Find someone who shares your goals and who can help you stay focused and motivated. This could be a friend, family member, or a coach. Having someone to share your progress with and to hold you accountable can be a powerful motivator.

Reward yourself: Set up a system of rewards for yourself when you reach certain milestones on the way to your goal. These rewards could be something as simple as a treat or a movie, or something more substantial like a new piece of workout equipment.

Get organized: Plan out your workouts and stick to a routine. Having a clear plan and structure can help you stay focused and motivated, as you can see how each workout is helping you to reach your goal.

Surround yourself with positive influences: Surround yourself with people who support and encourage your goals. Having positive influences in your life can help you stay motivated and inspired to reach your goals.

when you increase magnification is it necessary to increase the amount of light

Answers

According to my research on how microscopes work, I can say that based on the information provided within the question as you move to a higher level of magnification on a microscope the following terms have the following effects

Resolution increases

Working Distance decreases

Amount of Light needed increases

Depth of Field decreases

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Two identical resistors are connected in parallel across a 26-V battery, which supplies them with a total power of 7.1 W. While the battery is still connected, one of the resistors is heated so that its resistance doubles. The resistance of the other resistor remains unchanged. Find (a) the initial resistance of each resistor, and (b) the total power delivered to the resistors after one resistor has been heated.

Answers

Answer:

A) R = 190.42 Ω

B) P = 5.325 W

Explanation:

We are given;

Total power;P_tot = 7.1 W

Voltage;V = 26 V

A)We are told that while the battery is still connected, one of the resistors is heated, so that its resistance doubles.

Thus, the power is doubled.

Now, formula for power is;

P = IV

Thus, since power is doubled, we have;

P = 2(IV)

Now, formula for current is; I = V/R

So, P = 2V²/R

Making R the subject, we have;

R = 2V²/P

In this question, P is p_total = 7.1 W

Thus;

R = (2 × 26²)/7.1

R = 190.42 Ω

B) Now, the resistance of the resistors are R and 2R.

Formula for power in this context is;

P = V²/R

Thus,

Total power delivered to the resistors is;

P = V²/R + V²/2R

P = 3V²/2R

P = (3 × 26²)/(2 × 190.42)

P = 5.325 W

Using the graph below answer the following questions about the Photo-electric effect.
a) What is the work function of the experimental photo-missive material?
b) What the threshold frequency of the experimental photo-missive material?
c) If the incoming frequency is 8.0 E14 Hz what would be the maximum kinetic energy of the most energetic electron?
d) If the incoming photon had a wavelength of 500.0 nm would you have a photo-electron ejected?
e) If you use a different experimental photo-missive material what would be the same on the graph?

f) What is the slope of the graph?

Answers

(a) The work function  is 1.98 x 10⁻¹⁹ J.

(b) The threshold frequency is 3 x 10¹⁴ Hz.

(c) The maximum kinetic energy of the most energetic electron is 3.32 x 10⁻¹⁹ J.

(d) Photo-electron would be ejected.

(e) The only constant parameter would be speed of the photon.

(f) The slope of the graph is 6.67 x 10⁻³⁴ J.s

What is the work function of the experimental photo-missive material?

(a) The work function of the experimental photo-missive material is calculated as follows;

Ф = hf₀

where;

h is the Planck's constantf₀ is the threshold frequency = 3 x 10¹⁴ Hz (from the graph)

Ф = hf₀

Ф = 6.626 x 10⁻³⁴ x 3 x 10¹⁴

Ф = 1.98 x 10⁻¹⁹ J

(b) The threshold frequency of the experimental photo-missive material is the frequency at which the kinetic energy is zero = 3 x 10¹⁴ Hz.

(c) The maximum kinetic energy of the most energetic electron is calculated as;

K.E = E - Φ

K.E = ( 6.626 x 10⁻³⁴ x 8 x 10¹⁴) -  1.98 x 10⁻¹⁹ J

K.E =  3.32 x 10⁻¹⁹ J

(d) The frequency of the photon with a wavelength of 500 nm is calculated as;

f = c/λ

where;

c is the speed of light = 3 x 10⁸ m/sλ is the wavelength of the photon

f = ( 3 x 10⁸ ) / ( 500 x 10⁻⁹ )

f = 6 x 10¹⁴

Since the frequency of the incoming photon is greater than  the threshold frequency, photo-electron would be ejected.

(e) If you use a different experimental photo-missive material the only parameter that would be the same on the graph is speed of photon.

(f) The slope of the graph is calculated as;

m = (2.5 eV - 0 eV) / [(9 - 3) x 10¹⁴]

m = (2.5 ev) / (6 x 10¹⁴)

m = (2.5 x 1.6 x 10⁻¹⁹ ) / (6 x 10¹⁴ )

m = 6.67 x 10⁻³⁴ J.s

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Using the graph below answer the following questions about the Photo-electric effect.a) What is the work

Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52

Answers

The solution to the equation is; x =4 and x = 10

How do you solve an equation?

In most cases, the goal is to isolate the variable (usually represented by x) on one side of the equation. To do this, you can use inverse operations (e.g., adding, subtracting, multiplying, or dividing both sides of the equation by the same value) to cancel out any other terms.

If the equation contains more than one variable, you will need to repeat the above steps to solve for the other variables.

Now we have that;

(x – 3)^2 = 49

x^2 - 6x + 9 = 49

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when a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied: group of answer choices (b) there is a large increase in the magnetic induction (b) (a) the magnetic induction (b) is decreased both a

Answers

When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, the magnetic induction (B) is increased.

Ferromagnetic materials, such as iron, nickel, and cobalt, have unique properties that make them highly responsive to magnetic fields. When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, several factors contribute to the increase in magnetic induction (B):Alignment of Magnetic Domains: In the absence of an external magnetic field, the magnetic domains within a ferromagnetic material are randomly oriented, resulting in a net magnetic moment of zero. However, when a magnetic field is applied, the domains align themselves in the direction of the field, leading to an increase in the overall magnetic induction.Magnetic Saturation: Ferromagnetic materials have a saturation point, beyond which further increase in the magnetic field does not significantly increase the magnetic induction. This saturation point is typically higher than that of other magnetic materials, allowing ferromagnetic materials to exhibit a larger increase in magnetic induction.Amplification of Magnetic Field: The presence of a ferromagnetic material within an electromagnetic coil enhances the magnetic field generated by the coil. This phenomenon is known as magnetic amplification or magnetic flux concentration. The ferromagnetic material acts as a magnetic conductor, guiding and intensifying the magnetic field lines, resulting in a larger magnetic induction.In contrast, option (a) stating that the magnetic induction (B) is decreased is incorrect. When a ferromagnetic material is subjected to an external magnetic field, the magnetic induction increases due to the alignment of magnetic domains and the amplification of the magnetic field.

Therefore, the correct answer is:

(a) There is a large increase in the magnetic induction (B)

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If the area of A1=0.005m^2 and the area A2=0.10m^2, external input force F1=100N. Calculate the output force F2.​

Answers

Answer:

\(F_2 = 2000N\)

Explanation:

Given

\(A_1 = 0.005m^2\)

\(A_2 = 0.010m^2\)

\(F_1 = 100N\)

Required

Calculate \(F_2\)

The solution to this question is Pascal's principle of pressure

Pressure is calculated using:

\(Pressure (P) = \frac{Force(F)}{Area(A)}\)

For the input force:

\(P_1 = \frac{F_1}{A_1}\)

Substitute values for F1 and A1

\(P_1 = \frac{100}{0.005}\)

\(P_1 = 20000\)

For the input force:

\(P_2 = \frac{F_2}{A_2}\)

Substitute value for A2

\(P_2 = \frac{F_2}{0.10}\)

The pressure in the system is constant.

So:

\(P_1 = P_2 = 20000\)

Substitute 20000 for P2

\(20000 = \frac{F_2}{0.10}\)

Make F2 the subject

\(F_2 = 20000 * 0.10\)

\(F_2 = 2000N\)

Hence, the output force is 2000N

5- A 2500g object is pushed with 55N for 12m in 11s, there was a force of friction of 30N.
a) Calculate the work done.
b) Calculate the acceleration
c) Calculate the average speed

Answers

Answer:

1kg =1000g

2.5kg

D=12m

t=11s

F=2.5KG

Explanation:

work done =f.d

=2.5×12

=30Nm

55-30

average speed

final - initial

divide by time t(s)

How much force must a 40,000 W engine exert to get a car up to 75 m/s?​
Edit: Answer - 533N

Answers

Answer:

Force = 533.33N

Explanation:

Given the following data;

Power = 40000watt

Velocity = 75m/s

To find the force;

\( Power = force * velocity \)

Making force the subject of formula, we have;

\( Force = \frac {Power}{velocity}\)

\( Force = \frac {40000}{75} \)

Force = 533.33N

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