What number should be placed in front of HCl to
balance this chemical equation?
Zn + __HCI - ZnCl2 + H2

Answer: The mass of product, \(H_2O\) is, 36.0 grams.

Explanation : Given,

Mass of \(H_2\) = 4.0 g

Mass of \(O_2\) = 32.0 g

Molar mass of \(H_2\) = 2 g/mol

Molar mass of \(O_2\) = 32 g/mol

First we have to calculate the moles of \(H_2\) and \(O_2\).

\(\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}\)

\(\text{Moles of }H_2=\frac{4.0g}{2g/mol}=2.0mol\)

and,

\(\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}\)

\(\text{Moles of }O_2=\frac{32.0g}{32g/mol}=1.0mol\)

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

\(2H_2+O_2\rightarrow 2H_2O\)

From the balanced reaction we conclude that

2 mole of \(H_2\) react with 1 mole of \(O_2\)

From this we conclude that, there is no limiting and excess reagent.

Now we have to calculate the moles of \(H_2O\)

From the reaction, we conclude that

2 moles of \(H_2\) react to give 2 moles of \(H_2O\)

Now we have to calculate the mass of \(H_2O\)

\(\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O\)

Molar mass of \(H_2O\) = 18 g/mole

\(\text{ Mass of }H_2O=(2.0moles)\times (18g/mole)=36.0g\)

Therefore, the mass of product, \(H_2O\) is, 36.0 grams.

a) Al(s) + SnSO4(aq) → six electrons transferred

b) Mg(s) + Fe(NO3)2(aq) → Two electrons transferred

The activity series is a list of metals and nonmetals in order of their relative reactivity. It is a useful tool for predicting the outcome of single displacement reactions and for understanding the behavior of metals and nonmetals in various chemical reactions.

In the activity series, the most reactive metals are listed at the top, while the least reactive metals are listed at the bottom. This means that the metals at the top of the activity series are more likely to lose electrons and undergo oxidation, while the metals at the bottom are less likely to lose electrons and undergo oxidation. Similarly, nonmetals are listed in order of their relative ability to gain electrons and undergo reduction.

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The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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Answer:

[Xe]: 6s²

Explanation:

that's the noble gas config for Barium.

The electron configuration of barium (Ba) in noble gas notation is [Xe] 6s². This shorthand notation signifies that barium has chemically stable electron configuration similar to that of the noble gas xenon (Xe), plus two additional electrons in the 6s orbital.

The electron configuration of an element represents the distribution of electrons in an atom's electron shells. Barium (Ba) is a chemical element with atomic number 56 in the periodic table. Its electron configuration can be written out in full, but the noble-gas notation provides a convenient shorthand. To write the electron configuration of barium in noble gas notation, you first locate the nearest noble gas that precedes barium in the periodic table. In this case, the nearest noble gas is xenon (Xe), which has an atomic number of 54. This leaves two more electrons, which go into the 6s orbital. So, the electron configuration of barium in noble gas notation is [Xe] 6s².

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Answer:

i dont know

Explanation:

its simple i dont know

Answer:

Explanation:Red

0.5 moles of lithium chloride are dissolved in .05 liters of water. 10M  is the molarity of the solution.

The total amount of moles of solute found within a specific number of litres of the solution, or moles per litre of a solution, is known as molar concentration or molarity. Please explain the difference amongst the terms "solute" and "solvent" before we continue.

'Solution' for making it simpler to comprehend the topics that will follow. Solutes are simply substances that exist in solutions because a solution is defined as a homogenous mixture that comprises one or more solutes.

Molarity = moles/volume of solution in liter

              = 0.5/ .05

               = 10M

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Answer:

A

Explanation:

using

mC∆t

50×4.17×(91-56)

=50×4.17×35

=7297.5

~ 7298 J

A helium-filled balloon has a volume of 4.50 L at a barometric pressure of 747.3 mmHg. Given the balloon’s volume is neither increasing nor decreasing, the pressure of the helium inside the balloon is 747.3 mmHg.

A helium-filled balloon has a volume of 4.50 L when the temperature is 22.5 degrees C and the barometric pressure is 747.3 mmHg.

Barometric pressure is the measurement of air pressure in the atmosphere, specifically the measurement of the weight exerted by air molecules at a given point on Earth.

The pressure of the helium gas is the force that the gas exerts on the container boundaries, in this case, the balloon.

We know that the balloon’s volume is neither increasing nor decreasing. This means that the barometric pressure and the pressure of the helium gas are at equilibrium. That is, the pressure of the gas is 747.3 mmHg as well.

A helium-filled balloon has a volume of 4.50 L at a barometric pressure of 747.3 mmHg. Given the balloon’s volume is neither increasing nor decreasing, the pressure of the helium inside the balloon is 747.3 mmHg.

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The standard deviation of the sample is 0.579, rounded to the correct number of significant figures.

To calculate the standard deviation of the sample, we need to follow these steps:

To find the mean, we sum up all the data points and divide by the number of data points. Let's calculate it:

(3.09 + 4 + 2.775 + 2.5 + 3.80) / 5 = 16.165 / 5 = 3.233

To do this, we subtract the mean (3.233) from each data point and square the result:

(3.09 - 3.233)^2 = 0.020049

(4 - 3.233)^2 = 0.586489

(2.775 - 3.233)^2 = 0.209025

(2.5 - 3.233)^2 = 0.537289

(3.80 - 3.233)^2 = 0.323329

To find the variance, we sum up the squared differences from step 2 and divide by the number of data points:

(0.020049 + 0.586489 + 0.209025 + 0.537289 + 0.323329) / 5 = 1.676181 / 5 = 0.3352362

√0.3352362 = 0.579 (rounded to three significant figures)

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Answer:

Cl-

Explanation:

Neutral (Cl) have 7 electron, but Cl- have 8 electron due to gain of 1 electron

Answer:

Cd + ZnSO4 -----> Zn + CdSO4

Explanation:

:)

Answer:

164.04 K

Explanation:

PV = n RT       R = gas constant = .082057 L-atm/(mol-K)

                       T will be in K

102.63 (.341) = 2.60 * .082057 * K

K = 164.04 K

The molecule that is drawn in a conformation that has a proton and a leaving group anti-periplanar is H₂C, Br.

The A, B, C, and D bond angles of a molecule are referred to as anti-periplanar, or antiperiplanar, in organic chemistry. The dihedral angles of the A–B and C–D bonds in this conformer are larger than +150° or less than 150°. In textbooks, the term "anti-periplanar" is frequently used to refer to a strictly anti-coplanar structure with a 180° AB CD dihedral angle. The anti-periplanar functional groups will be 180° apart from one another and in a staggered configuration in a Newman projection of the molecule.  

Conformation is an essential factor in predicting reactivity in organic molecules. The anti-periplanar conformation of a molecule is one that occurs when two atoms in a molecule are in the same plane and are separated by 180 degrees. In this case, the proton and leaving group are placed in a perpendicular plane to the atoms directly in between them. This is the most stable conformer of the molecule. A significant factor in predicting reactivity in organic molecules is conformation. In this case, the molecule H₂C, Br is drawn in a conformation that has a proton and a leaving group anti-periplanar.

Therefore, the correct option is H₂C, Br.

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Answer:

it will fail

Explanation:

Answer:

physical projects

Journal entries

Materials

Lab reports

Artworks

Explanation:

Definition of a Portfolio:

Portfolio can be defined as a physical collection of student work that includes materials such as written assignments, completed tests, artwork, lab reports, physical projects and other material evidence of learning progress and academic accomplishment, including awards and honors,

A portfolio is a long-term form of self reflection and assessment that students do together.

Portfolios are a great way to demonstrate the competencies you would list on a resume or talk about in a science interview

a) Cl is the atom Atoms are expected to have the most negative (exothermic) electron affinities. 

Electron affinity is the amount of energy produced or released when an atom attracts an electron. Electron affinity can be used as a measure of the ease with which an atom captures electrons. The greater the energy released (electron affinity) indicates that the atom tends to attract electrons to become a negative ion.

Electron affinity can be used as a measure of the ease with which an atom captures electrons. The greater the energy released (electron affinity) indicates that the atom tends to attract electrons to become a negative ion.

The energy of an atom is defined when the atom loses or gains energy through a chemical reaction that causes the loss or gain of electrons. Chemical reactions that release energy are called exothermic reactions and chemical reactions that absorb energy are called endothermic reactions.

The energy of an exothermic reaction is negative, so the energy is given a negative sign; while the energy of the endothermic reaction is positive and the energy is given a positive sign. An example that demonstrates both processes is when someone drops a book. When he lifts the book, he gives the book potential energy (absorbed energy).

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Answer:

Discrete atoms

Argon

Molecules

Bromine

Nitrogen

Fluorine

Explanation:

The existence of substances in the elemental form depends on the nature of the substance.

Argon is a noble gas hence it seldom participates in chemical combination therefore it exists as discrete molecules in elemental form.

Bromine, fluorine and nitrogen all exist as diatomic gases because they combine readily with each other to form elemental molecules. An elemental molecule is a molecule composed of the atoms of the same element.

Answer:

Synthesis.

Explanation:

Hello!

In this case, since we can find synthesis, decomposition and single and double displacement reactions, it is possible for us to realize this reaction is synthesis because sulfur and fluorine react to produce sulfur hexafluoride according to:

\(S_8+24F_2\rightarrow 8SF_6\)

These reactions are characterized by the presence of two or more reactants and just one product.

Best regards!

The molarity of potassium hydroxide in the resulting solution is 0.129 M.

Molarity of a substance refers to the concentration of a substance in solution, expressed as the number of moles of solute per litre of solution.

According to this question, a student weighs out a 2.17g sample of KOH, transfers it to a 300. mL volumetric flask, adds enough water to dissolve it and then adds water to the 300. mL tick mark.

No of moles of KOH = 2.17g ÷ 56.11g/mol = 0.039 moles

Molarity = 0.039 moles ÷ 0.3L = 0.129 M

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N - 7 - 1s2 2s2 2p3

O - 16 - 1s2 2s2 2p6 3s2 3p4

Mn - 25 - 1s2 2s2 2p6 3s2 3p6 4s2 3d5

Ga - 31 - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1

Answer:

The hydrogen sample has a pressure of 0.957 atmospheres.

Explanation:

Let consider that the hydrogen sample behaves ideally, the equation of state for ideal gases is:

\(P\cdot V = n\cdot R_{u}\cdot T\) (1)

Where:

\(P\) - Pressure, in atmospheres.

\(V\) - Volume, in liters.

\(n\) - Molar quantity, in moles.

\(T\) - Temperature, in Kelvin.

\(R_{u}\) - Ideal gas constant, in atmosphere-liters per mole-Kelvin.

If we know that \(V = 19.1\,L\), \(n = 0.684\,mol\), \(T = 326\,K\) and \(R_{u} = 0.082\,\frac{atm\cdot L}{mol\cdot K}\), then the pressure of the hydrogen sample is:

\(P = \frac{n\cdot R_{u}\cdot T}{V}\)

\(P = \frac{(0.684\,mol)\cdot \left(0.082\,\frac{atm\cdot L}{mol\cdot K} \right)\cdot (326\,K)}{19.1\,L}\)

\(P = 0.957\,atm\)

The hydrogen sample has a pressure of 0.957 atmospheres.

Answer:

Kindly check the explanation section.

Explanation:

Without mincing words let us dive right into the solution to the question above, taking each compound at a time.

NB: Kindly Check attachment for the Lewis Structure of each of the chemical compounds.

Therefore, the number of valence electrons, electronic shape, molecular shape and whether the molecules are polar(Polarity) is given below for each chemical compound.

(1). Compound: HCN

(a). number of valence electrons = 10.

(b). electronic shape =linear.

(c). molecular shape = linear.

(d). Polarity = Y.

(2). Compound: PH3

(a). number of valence electrons = 8.

(b). electronic shape = Tetrahedral.

(c). molecular shape = Trigonal Pyramidal.

(d). Polarity = Y.

(3). Compound: CHCl3.

(a). number of valence electrons = 26.

(b). electronic shape = tetrahedral.

(c). molecular shape = tetrahedral.

(d). Polarity = Y.

(4). Compound: NH4^+

(a). number of valence electrons = 8

(b). electronic shape = tetrahedral

(c). molecular shape = tetrahedral

(d). Polarity = Y.

(5). Compound: H2CO

(a). number of valence electrons = 12.

(b). electronic shape = Trigonal planar.

(c). molecular shape = Trigonal planar

(d). Polarity = Y.

(6). Compound: SO4^2-

(a). number of valence electrons = 32.

(b). electronic shape = Tetrahedral.

(c). molecular shape = Tetrahedral.

(d). Polarity = N.

(7). Compound: SeF2.

(a). number of valence electrons = 20.

(b). electronic shape = Tetrahedral.

(c). molecular shape = bent.

(d). Polarity = Y.

(8). Compound: CO2.

(a). number of valence electrons = 16.

(b). electronic shape = linear.

(c). molecular shape = linear.

(d). Polarity = N.

(9). Compound: O2

(a). number of valence electrons = 32.

(b). electronic shape = Trigonal planar.

(c). molecular shape = Linear.

(d). Polarity = N.

(10). Compound: ClO4-.

(a). number of valence electrons = 32.

(b). electronic shape = Tetrahedral.

(c). molecular shape = Tetrahedral.

(d). Polarity = N.

(11). Compound: HBr.

(a). number of valence electrons = 8.

(b). electronic shape = Linear.

(c). molecular shape = Linear.

(d). Polarity = Y.

(12). Compound: PF5.

(a). number of valence electrons = 40.

(b). electronic shape = Trigonal Bipyramidal.

(c). molecular shape = Trigonal Bipyramidal.

(d). Polarity = N.

(13). Compound: BeH2.

(a). number of valence electrons = 4.

(b). electronic shape = Linear.

(c). molecular shape = Linear.

(d). Polarity = N.

(14). Compound: PO4^3-.

(a). number of valence electrons = 32.

(b). electronic shape = Tetrahedral.

(c). molecular shape = Tetrahedral.

(d). Polarity = N.

(15). Compound: BH3.

(a). number of valence electrons = 6.

(b). electronic shape = Trigonal planar.

(c). molecular shape = Trigonal planar.

(d). Polarity = N

(16). Compound: Br3-.

(a). number of valence electrons = 32.

(b). electronic shape = Trigonal Bipyramidal.

(c). molecular shape = Linear.

(d). Polarity = N.

Answer:

cannot be measure

Hope this helps :) !!!

Answer:

This idea helps students explain why more rain forms over West Ferris than East Ferris. ... Therefore, when students explain that water vapor condenses higher in the atmosphere, they are actually explaining that water vapor condenses high in the troposphere, which is relatively low in the atmosphere.

Explanation:

Answer:

This is your answer

Hope it helps!!!

Answer:

3.01 × 10^24 particles

Explanation:

According to Avagadro, in one mole of a substance, there are 6.02 × 10^23 atoms or particles.

Using the formula: N = n × NA

Where;

N= number of particles or atoms

n = number of moles

NA = Avagadro's constant or number

This means that for 5 moles of a substance, there will be:

5 × 6.02 × 10^23

= 30.1 × 10^23

= 3.01 × 10^24 particles

For this section:

(d) To determine which acid would be completely dissociated when dissolved in water, consider the strength of the acid and its ability to ionize completely. Strong acids are those that ionize completely in water, while weak acids only partially dissociate.

Among the given options:

(H O)₂SO is sulfuric acid (H₂SO₄), which is a strong acid and completely dissociates in water.

(H O)IO₃ is iodic acid (HIO₃), which is also a strong acid and completely dissociates in water.

(H O)₂SO₂ is not a known acid and cannot be evaluated for dissociation.

HCO₂H is formic acid (HCOOH), which is a weak acid and only partially dissociates in water.

Therefore, the acids that would be completely dissociated when dissolved in water are (H O)₂SO and (H O)IO₃.

(e) To estimate the pH of the given solutions formed by titration, compare the moles of the acid and base used in the reaction.

(i) For the titration of 25.0 mL of 0.10 M aqueous NaOH with 25.0 mL of 0.10 M aqueous HCl, the reaction between a strong acid (HCl) and a strong base (NaOH) forms a neutral salt (NaCl) and water. The resulting solution would have a pH of 7, indicating neutrality.

(ii) For the titration of 25.0 mL of 0.10 M aqueous NaOH with 25.0 mL of 0.10 M aqueous acetic acid, consider the ionization of acetic acid and the formation of its conjugate base. The pKa of acetic acid is given as 4.76.

Since the volumes and concentrations of the acid and base are equal, we have a 1:1 mole ratio between them. This means that half of the acetic acid will be neutralized, and the remaining half will be in the form of the conjugate base (acetate ion, CH₃COO-). The resulting solution will be a buffer solution with a pH close to the pKa of acetic acid, which is 4.76.

(f) To predict the products formed from mixing the given reagents, we need to consider the reactions and the possible chemical reactions that occur.

(i) 3I₂ + PBr₃: This reaction involves the combination of iodine (I₂) with phosphorus tribromide (PBr₃). The balanced equation is:

3I₂ + 2PBr₃ → 6IBr + P₂

(ii) 4LiH + GaCl₃: This reaction involves the combination of lithium hydride (LiH) with gallium trichloride (GaCl₃). The balanced equation is:

4LiH + GaCl₃ → 4LiCl + GaH₃

(iii) NH₃ + BCl₃: This reaction involves the combination of ammonia (NH₃) with boron trichloride (BCl₃). The balanced equation is:

NH₃ + BCl₃ → NH₃BCl₃

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Answer:

3

Explanation:

Increasing concentration