What is the velocity of an object whose kinetic energy is 100j and mass is 8kg?

The female skater moves backward at a speed of 3 m/s. The post-impulse speed of the male skater is 2.08m/s.

Momentum (linear) along, say, the x-axis is:

p=mv

so we have for the 2 skaters system:

\(p_before = p_after\)

(45.0)+(65.0)= (45*3)+(65*v)

v= - 135/65= -2.08m/s

Speed in physics refers to how fast an object is moving. It is a scalar quantity that only takes into account the magnitude of the velocity of the object, not its direction. The speed of an object can be calculated by dividing the distance it travels by the time it takes to travel that distance. The SI unit of speed is meters per second (m/s), but other units such as miles per hour (mph) or kilometers per hour (km/h) can also be used.

Speed can be constant, meaning the object is moving at a steady rate, or it can be changing, meaning the object is accelerating or decelerating. Acceleration is the rate at which an object's speed changes over time, and it is typically measured in meters per second squared (m/s^2).

The concept of speed is fundamental to many areas of physics, including mechanics, thermodynamics, and electromagnetism. It is also a critical component of everyday life, influencing how we travel, communicate, and interact with the world around us.

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Kinetic molecular theory states that gas particles are in constant motion and exhibit perfectly elastic collisions.

The assumption that matter is made up of microscopic particles that are always in motion is the foundation of the kinetic-molecular theory, a theory that describes the states of matter.

However, the theory is most simply understood when it is applied to gases, therefore this is where our in-depth study will start. The theory especially pertains to the ideal gas model of a gas. An ideal gas is a hypothetical gas whose behaviour exactly matches all of the kinetic-molecular theory's presumptions. Although they are not perfect in actuality, gases come extremely close to being perfect in most real-world situations.

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The time taken by photoelectrons with maximum kinetic energy to travel 2.1 cm to a detection device is approximately 6.4 x 10^-10 seconds.


Firstly, we need to find the energy of the photon using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Substituting the given values, we get E = 3.07 eV.  

Next, we subtract the work function from the energy of the photon to find the maximum kinetic energy of the photoelectrons. Max kinetic energy = E - work function = 0.53 eV.  

Now, we can use the formula v = √(2KE/m) to find the velocity of the photoelectrons, where KE is the maximum kinetic energy and m is the mass of the electron. Substituting the values, we get v = 1.6 x 10^6 m/s.  

Finally, we can calculate the time taken to travel 2.1 cm using the formula t = d/v, where d is the distance and v is the velocity. Substituting the values, we get t = 6.4 x 10^-10 seconds. Therefore, the answer is approximately 6.4 x 10^-10 seconds.

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The statement that street crime costs society more than twice as much as white-collar crime when measured in dollars is false. While both street crime and white-collar crime can have significant economic impacts, it is challenging to make a direct comparison between the costs of these two types of crimes.

Street crime typically refers to offenses such as theft, robbery, assault, and drug-related crimes that occur in public spaces. These crimes can result in immediate financial losses for individuals and businesses, as well as increased costs related to law enforcement, criminal justice proceedings, and victim support services.

On the other hand, white-collar crime involves non-violent offenses committed by individuals in business or professional settings, such as fraud, embezzlement, insider trading, and tax evasion. The economic consequences of white-collar crime can be substantial, including financial losses for individuals, companies, and even entire economies. Additionally, white-collar crime can erode public trust and confidence in financial systems.

However, quantifying the exact costs of street crime and white-collar crime is complex and depends on various factors. The costs of street crime are often more visible and immediate, as they involve direct losses and immediate responses from law enforcement agencies.

In contrast, white-collar crime may involve intricate investigations, legal proceedings, and long-term financial impacts, making it challenging to estimate the exact economic costs.

It's important to note that comparing the costs of street crime and white-collar crime solely based on dollar figures may not capture the full extent of their societal impact. Both types of crime have wide-ranging consequences, including physical harm, emotional distress, social disruption, and erosion of trust. Therefore, it is essential to consider multiple dimensions when assessing the costs and impacts of different types of crime in society.

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The time it will take do the hiker to climb the 1200m high wall is 1,411.2 seconds.

Power refers to the measure of the rate of doing work or transferring energy.

Power = Work done/time

Since work = force × distance the body is moved

Power = (m × g × h) / t

Where;

According to this question, a 60kg hiker wishes to climb 1200m high. If he can generate a sustained average power of 500 watts, the time it will take to climb is as follows;

500 = 60 × 9.81 × 1200/t

500t = 705,600

t = 1,411.2 seconds

Therefore, 1,411.2 seconds is the time it will take the hiker.

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The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.

(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:

\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)

Simplifying this expression yields:

\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)

(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).

(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.

Using the circulation form of Green's Theorem, the line integral becomes:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)

The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)

Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.

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The Doppler method can measure the eccentricity of orbit, semimajor axis of orbit, lower limit mass, and orbital period of exoplanets.

Eccentricity of orbit: The Doppler method can provide information about the eccentricity of a planet's orbit by detecting the periodic variations in the star's radial velocity caused by the planet's gravitational pull.

Semimajor axis of orbit: The Doppler method allows for the determination of the semimajor axis of a planet's orbit. By measuring the periodic changes in the star's radial velocity, scientists can infer the distance between the star and the planet, which corresponds to the semimajor axis.

Lower limit mass: The Doppler method can provide a lower limit estimate of a planet's mass. By observing the periodic variations in the star's radial velocity, scientists can calculate the minimum mass of the planet based on the gravitational influence it exerts on the star.

Orbital period: The Doppler method is particularly effective in determining the orbital period of a planet. By measuring the time it takes for the periodic changes in the star's radial velocity to repeat, scientists can accurately determine the planet's orbital period.

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Let p be the total linear momentum of the system before the collision and p' the total linear momentum of the system after the collision. Let p₁₁ and p₁₄ be the linear momentum of the 11.0kg ball and the 14.0kg ball before the collision, and let p₁₁' and p₁₄' be their linear momenta after the collision.

According to the Law of Conservation of Linear Momentum, the total linear momentum of the system before and after the collision remains the same. Then:

Let v be the unknown speed of the 11.0kg ball after the collision. Find the value of p₁₁, p₁₄, and p₁₄'. Find an expression for p₁₁' in terms of v and replace all the values into the above equation. Solve for v.

The linear momentum of a particle with mass m and velocity v is:

Then:

Then:

Therefore, the velocity of the first ball after the collision is 20.4m/s.

The normal frequencies of the system are ω₁ = √2 and ω₂ = √3, and the corresponding normal modes are (1, 1, 1) and (1, -2, 1) respectively.

To find the normal frequencies and normal modes of the system, we start by writing the equations of motion for the three particles connected by the springs. By rearranging the equations, we obtain a set of coupled differential equations in terms of the displacements x₁, x₂, and x₃.

Next, we solve these differential equations by assuming harmonic solutions of the form xᵢ(t) = Aᵢsin(ωt + φᵢ), where Aᵢ is the amplitude, ω is the angular frequency, and φᵢ is the phase constant for particle i.

By substituting the harmonic solutions into the equations of motion and solving for the angular frequency ω, we obtain the normal frequencies of the system. The normal frequencies represent the natural frequencies at which the system oscillates.

To find the corresponding normal modes, we substitute the normal frequencies back into the equations of motion and solve for the amplitudes Aᵢ. The normal modes represent the patterns of motion exhibited by the system at the respective normal frequencies.

In this case, after solving the equations of motion, we find that the normal frequencies are ω₁ = √2 and ω₂ = √3. The corresponding normal modes are (1, 1, 1) and (1, -2, 1) respectively. These modes describe the relative displacements of the particles in the system when oscillating at their respective normal frequencies.

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The volume of the air that we have from the question is 829 L

The ideal gas equation, also known as the ideal gas law, is a fundamental equation in thermodynamics that describes the relationship between the pressure (P), volume (V), temperature (T), and number of moles (n) of an ideal gas.

We know that;

PV = nRT

P = pressure

V = volume

n = Number pf moles

R = gas constant

T = Temperature

Then;

Number of moles of the air = 1000 g/29 g/mol

= 34.5 moles

Then;

V = nRT/P

V = 34.5 * 0.082 * 293/1

V = 829 L

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Regular wires and cables always have some resistance.  So when electric current flows through regular wires and cables, it always loses some energy,  It's only a little bit, so we don't usually worry about it.  

But if you're the power company, your business is selling electrical energy.  If you generate electrical energy at the power plant, and some of it is lost on its way to your customers, then you can't sell the energy that's lost.  If you're the power company, then you're shipping ginormous amounts of energy over ginormous distances, and you DO worry about losing any of it.

Strange as it may seem, it turns out that if you ship the electrical energy through the cables at HIGHER voltage, LESS of it gets lost.  So the power company wants to send the energy through the cables at the highest-possible voltage.  Real power companies use as much as 765 THOUSAND volts to send energy between cities, and 4,800 or 7,200 volts to move it between neighborhoods.  (And there's a new long-distance power line in China using 1.1 MILLION volts to move energy a couple thousand miles.)  

But this could be a big problem !  You only use 120 volts for most of the things in your house, (or 240 volts for big things like the air conditioner, the stove, or the clothes dryer).

So the power company needs a way to "step down" the voltage from the "transmission line" before they connect the wires into your house.

They use a "step down transformer" to make the electricity suable in houses.

The step-down transformers are the giant square boxes you see on the ground inside the neighborhood power-distribution substation.

And they're the round black cans you see up on the electric poles around the neighborhood.

Charging the droplets helps ensure that most of the paint ends up on the car for several reasons. First, charged droplets experience less drag force from the air, which means they lose less speed and hit the surface of the car with a larger momentum. This results in better adhesion and a smoother finish. Additionally, charged droplets do not bead up together into larger droplets, which means the weight forces exerted on each droplet are smaller.

This allows for more uniform coverage and less dripping. Charged droplets also experience acceleration in the Earth's electric field, which means they hit the surface of the car at larger speeds, further improving their ability to stick to the surface. Finally, charged droplets polarize the surface of the car, creating an additional attraction force between the droplets and the surface. This helps ensure that the paint stays in place and doesn't run or drip off the car.

Charging the droplets helps ensure that most of the paint ends up on the car because charged droplets experience less drag force from the air, allowing them to maintain their speed and hit the surface with larger momentum. Additionally, charged droplets do not bead up into larger droplets, resulting in smaller weight forces exerted on each droplet. Moreover, charged droplets experience acceleration in the earth's electric field, enabling them to hit the car's surface at higher speeds. Lastly, charged droplets polarize the car's surface, creating an additional attraction force that ensures better adherence of the paint to the surface.

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Charging the droplets in paint helps ensure that most of it ends up on the car because of several factors. Firstly, charged droplets experience less drag force from the air, meaning they lose less speed and hit the surface of the car with larger momentum.

Secondly, charged droplets do not bead up together into larger droplets, resulting in smaller weight forces exerted on each droplet. Thirdly, charged droplets experience acceleration in the Earth's electric field, allowing them to hit the surface of the car at larger speeds. Lastly, charged droplets polarize the surface of the car, resulting in an additional attraction force of the droplets to the surface. All these factors contribute to a higher probability of the paint sticking to the car's surface, resulting in a smoother and more even paint job.

Charging paint droplets ensures that most paint ends up on the car due to several factors. Firstly, charged droplets experience less drag force from the air, maintaining their speed and hitting the car's surface with greater momentum. Secondly, these droplets don't bead up into larger ones, resulting in smaller weight forces exerted on each droplet. Thirdly, charged droplets experience acceleration in the earth's electric field, increasing their impact speed on the car's surface. Finally, charged droplets polarize the car's surface, creating an additional attraction force, ensuring more efficient paint application.

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To increase the efficiency of the Carnot engine by 10% of the original efficiency, the temperature of the heat source should be increased by 0.067 times its original value

The efficiency of a Carnot engine is given by:

Efficiency = 1 - (Tc/Th)

Where

In this case, the efficiency of the engine is 40%, which can be expressed as 0.4 in decimal form. Therefore:

0.4 = 1 - (Tc/Th)

Rearranging this equation, we get:

Tc/Th = 0.6

We want to increase the efficiency by 10% of the original efficiency. This means that the new efficiency will be :

0.4 + 0.1(0.4) = 0.44

We can use this new efficiency to find the new ratio of Tc/Th:

0.44 = 1 - (Tc_new/Th_new)

Tc_new/Th_new = 0.56

Now we need to find by how many degrees the temperature of the heat source should change to achieve this new ratio of temperatures. We can set up an equation using the two ratios of temperatures:

(Tc/Th) / (Tc_new/Th_new) = 0.6 / 0.56

Substituting the first ratio we found earlier and simplifying, we get:

0.6 / (Th_new/Th) = 0.6 / 0.56

Th_new/Th = 0.56/0.6

Th_new/Th = 0.933

Multiplying both sides by Th, we get:

Th_new = 0.933 Th

So the temperature of the heat source should be increased by:

ΔT = Th_new - Th = 0.933 Th - Th = 0.067 Th

Where ΔT is the change in temperature and Th is the original temperature of the heat source.

Therefore, to increase the efficiency of the Carnot engine by 10% of the original efficiency, the temperature of the heat source should be increased by 0.067 times its original value.

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(a) A = B × r is a vector potential for B, where r = {x, y, 0}.

(b) The flux through a surface S can be calculated as Φ = ∫B·dA, where B is the magnetic field and dA is an infinitesimal area vector perpendicular to the surface.

(a) To verify that A = B × r is a vector potential for B, we need to show that ∇ × A = B.

Using the cross product property, we have ∇ × A = ∇ × (B × r). Applying the vector identity (A × B) × C = B(A · C) - C(A · B), we get ∇ × (B × r) = B(∇ · r) - r(∇ · B).

Since ∇ · r = 0 (as r = {x, y, 0}), and ∇ · B = 0 (as B has a constant magnitude in the z-direction), we find that ∇ × A = B, verifying A = B × r as the vector potential for B.

(b) The flux through a surface S can be calculated as Φ = ∫B·dA, where B is the magnetic field and dA is an infinitesimal area vector perpendicular to the surface.

Given that B has a constant strength b teslas in the z-direction, the flux through surface S will be Φ = ∫B·dA = ∫(0, 0, b) · (dxdy) = b∫dxdy = bA, where A is the area of the surface S.

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M = mass of the ball A = 5.0 kg

m = mass of the ball B = ?

V = initial velocity of the ball A before collision = 20 m/s

v = initial velocity of the ball B  before collision = 10 m/s

V' = final velocity of the ball A after collision = 10 m/s

v' = final velocity of the ball B after collision = 15 m/s

using conservation of momentum

M V + m v = M V' + m v'

(5.0) (20) + m (10) = (5.0) (10) + m (15)

100 + 10 m= 50 + 15 m

5 m = 50

m= 10 m/s

Answer: 5

Explanation:

The apparent breaking in two of a pencil that is placed diagonally part way into water is caused by the phenomenon of refraction.

When light travels through different mediums, such as air and water, it bends due to the change in density. This bending of light causes objects to appear differently than they actually are. In the case of the pencil, the part of the pencil that is submerged in water appears to be in a different position than the part that is in the air. This creates an optical illusion that makes it seem as though the pencil is breaking in two. However, in reality, the pencil is still one piece. This effect is more pronounced when the angle at which the pencil is placed in the water is closer to 45 degrees. This fascinating optical illusion has been studied by scientists and is a great example of how light can play tricks on our eyes.

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48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.

To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.

1 km (kilometer) = 1000 meter

1 h (hour) = 3600 seconds

1 minutes = 60 seconds

To convert m/s into km/h,

48 m/s * 3600/1000 =  172.8 km/h

To convert m/s into m/min,

48 m/s * 60 = 2880 m/min

To convert m/s into km/s,

48 m/s ÷ 1000 = 0.048 km/s

To convert m/s into km/minutes,

48 m/s * 60 / 1000 = 2.88 km/min

Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.

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48 m/s is equivalent to  172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

To express 48 m/s in different units of velocity:

km/h (kilometers per hour):

To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.

48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h

Therefore, 48 m/s is equivalent to 172.8 km/h.

m/min (meters per minute):

To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.

48 m/s * (60 m/min / 1 s) = 2880 m/min

Therefore, 48 m/s is equivalent to 2880 m/min.

km/s (kilometers per second):

Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.

48 m/s / 1000 = 0.048 km/s

Therefore, 48 m/s is equivalent to 0.048 km/s.

km/minute (kilometers per minute):

To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.

0.048 km/s * 60 = 2.88 km/minute

So, 48 m/s is equivalent to 2.88 km/minute.

Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

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The DC resistance in ohms per kilometer for an aluminum conductor with a 3 cm diameter is 0.00402 Ω/km. The correct option is b.

The cross-sectional area of the conductor is given by:

A = πr² = π(0.015 m)² = 7.07 × 10⁻⁴ m²

The resistance R of a conductor is given by:

R = ρL/A

where ρ is the resistivity of the material, L is the length of the conductor, and A is the cross-sectional area.

To find the resistance per unit length or the DC resistance in ohms per kilometer, we need to divide both sides of the above equation by the length of the conductor and then multiply by 1000 to convert the result to ohms per kilometer. Thus:

R/1000 = ρL/(1000A)

R/1000 = (2.83 × 10⁻⁸ Ω-m) L/(1000 × 7.07 × 10⁻⁴ m²)

R/1000 = 0.00402 L

Therefore, the DC resistance in ohms per kilometer for an aluminum conductor with a 3 cm diameter is 0.00402 Ω/km. Answer choice (b) is the closest to this value, rounded to three significant figures.

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Answer:

\(\boxed {\boxed {\sf 100 \ Newtons}}\)

Explanation:

We are asked to calculate the force you are applying to a car. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, we can use the following formula to calculate force.

\(F= m \times a\)

The mass of the car is 2000 kilograms and the acceleration is 0.5 meters per second squared.

Substitute the values into the formula.

\(F= 2000 \ kg \times 0.05 \ m/s^2\)

Multiply.

\(F= 100 \ kg *m/s^2\)

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 100 kilogram meters per second square is equal to 100 Newtons.

\(F= 100 \ N\)

You apply 100 Newtons of force to the car.

Answer:

c

Explanation:

the final momentum of the toy car is 64.0 kg m/s.

Given parameters:

Mass of the toy car, m = 2.0 kg

Velocity of the toy car, v = 20.0 m/s

Net force, F = 6.00 N

Time for which force is applied, t = 4.00 s

We can find the change in momentum of the toy car using the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse applied on it.

The impulse is given by the product of force and time. Therefore,

Δp = Ft

The final momentum of the toy car will be the sum of its initial momentum and the change in momentum. Since the toy car is initially moving with a constant velocity, its initial momentum is given by p = mv.

Therefore,

Final momentum of the toy car, p' = p + Δp

= mv + Ft

Substituting the given values, we get:

p' = (2.0 kg) (20.0 m/s) + (6.00 N) (4.00 s)p'

= 40.0 kg m/s + 24.0 kg m/sp'

= 64.0 kg m/s

Therefore, the final momentum of the toy car is 64.0 kg m/s.

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The wavelength of the sound wave is equal to 0.333 m. Therefore, option (c) is correct.

The frequency of the wave can be defined as the number of oscillations that occur in one second and can be expressed in hertz. The wavelength can be defined as the distance between the two adjacent points of a wave such as two crests or troughs.

The relationship between frequency (ν), speed of sound waves (V), and  wavelength (λ):

V = νλ

Given, the frequency of the sound wave, ν = 10 Hz

The speed of the sound wave,\(V = 340 m/s\)

The wavelength of the sound waves can determine as follows

λ = V/ν = 340/1020 = 0.333 m.

Therefore, the wavelength of the sound wave is 0.333 m

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Answer:

v = 9341.19 [m/s]

Explanation:

Linear momentum is defined as the product of mass by Velocity. In this way by means of the following equation, we can calculate the momentum.

\(P=m*v\)

where:

P = momentum [kg*m/s]

m = mass = 10.2[kg]

v = velocity = 3.03 [m/s]

Now replacing, we have:

\(P=10.2*3.03\\P = 30.91 [kg*m/s]\)

Now the ping-pong mass is 3.309 [g] or 0.003309 [kg]

We can clear the value for v from the equation above.

\(v = P/m\\v = 30.91/0.003309\\v = 9341.19 [m/s]\)

Answer:

A

Explanation:

since its the tip, you will feel it the most there.

Answer:

a total of four nodes and three antinodes

Explanation:

please tell me if im incorrect i will fix it asap.

Answer: A) Had twice as much mass

Explanation:

Given that the force of gravity pulling down on school = 400,000 N

The force of force of gravity is the product of mass of the body and the acceleration due to gravity. The acceleration due to gravity is constant on the earth surface with a constant value of 9.8m/s²

Hence,

F = mg = 800N

F = force of gravity, m = mass of body, g =! acceleration due to gravity.

since g is constant, to have 2F, then mass has to be doubled, that is 2m(2 * mass)

13.The color with the longest wavelength is option A. Red.

14.The sky appears blue due to option D. Scattering of light.

Red light has a longer wavelength compared to yellow and blue light.The color that has the longest wavelength is red. The color of the sky appears blue due to scattering of light. The distance between one peak and the next in a series of waves, particularly electromagnetic waves traveling through space or along a wire is referred to as wavelength.

The wavelength of light, for example, determines its color. Red light has the longest wavelength, followed by orange, yellow, green, blue, and purple, with violet light having the shortest wavelength. When light is reflected off a surface or passes through a medium, it can be deflected in various directions, a phenomenon known as scattering of light.

The Earth's atmosphere scatters sunlight in all directions, but the shorter blue wavelengths are scattered more than the longer wavelengths. As a result, we perceive the sky as blue during the day.  The light becomes scattered when it interacts with particles in the atmosphere, causing the sky to appear blue during the day and red during sunset or sunrise. The scattering of light is the process that causes the sky to appear blue.

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Answer:

the reflection of the candle in the concave mirror formed upside down real image that is diminished

A projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰. The correct option is (B) 57⁰.

In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at an angle of 57⁰.

The range of a projectile can be determined by using the range formula.

R = ((v^2 * sin(2θ))/g) Where

R is the range of the projectile,

v is the velocity of the projectile,

θ is the angle at which the projectile is launched, and

g is the acceleration due to gravity.

In the absence of air resistance,

the horizontal component of velocity of a projectile remains constant throughout the flight.

So, the range of a projectile depends only on its initial velocity and the angle at which it is launched.

If a projectile is launched at an angle θ,

the time of flight of the projectile can be calculated by using the following formula:

T = (2v * sin(θ))/g

The maximum height reached by the projectile is given by the formula:

H = (v^2 * sin^2(θ))/2gIf a projectile is launched at an angle θ, then the range of the projectile will be the same as the range of the projectile launched at an angle of (90 - θ).

So, if a projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰.

Therefore, the correct option is (B) 57⁰.

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Answer:15 cm

Explanation: u had 10cm. them u had another 5cm