what is the speed of a 38-g bold eagle if it has a momentum magnitude of 0.45 kg•m/s ?

Answers

Answer 1

The speed of a 38-gram bald eagle with a momentum magnitude of 0.45 kg m/s is approximately 11.84 m/s. This can be calculated using the momentum formula.

The momentum formula is given by:
momentum = mass × speed

First, we need to convert the mass of the bald eagle from grams to kilograms since the momentum is given in kg•m/s. To do this, we divide the mass in grams by 1000:
mass (kg) = 38 grams ÷ 1000 = 0.038 kg

Now, we can rearrange the momentum formula to solve for the speed:
speed = momentum ÷ mass

Substitute the given values:
speed = 0.45 kg•m/s ÷ 0.038 kg
speed ≈ 11.84 m/s

Therefore, the speed of a 38-gram bald eagle with a momentum magnitude of 0.45 kg•m/s is approximately 11.84 m/s.

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Related Questions

Calculate the volume of water in gallons that 4.1 mL of water takes up. Express your answer in scientific notation,

Answers

Explanation:

The unit of volume derived from SI units(1) is the cubic meter, m3.

Chemists in a laboratory usually deal with much smaller volumes than cubic meters and the metric but non-SI units of liter or litre (L) and milliliter or millilitre (mL or ml) are in common use.

In 1964 the litre was redefined as being equal to exactly 1 cubic decimetre:

1 L = 1 dm3

So 1 milliltre = 1 cubic centimetre

1 mL = 1 cm3 (= 1cc)

Other metric units of measuring volume are given in the table below:

large volume → → → → → → → → → → small volume

name teralitre gigalitre megalitre kilolitre hectolitre decalitre decilitre centilitre millilitre microlitre nanolitre picolitre femtolitre attolitre

symbol TL GL ML kL hL daL dL cL mL µL nL pL fL aL

volume (L) 1012 L 109 L 106 L 103 L 102 L 101 L 10-1 L 10-2 L 10-3 L 10-6 L 10-9 L 10-12 L

How long will it take to travel 200.000 m [N] traveling 10 m/s [N]?

Answers

Answer: here are 1,000m in a km, so 200km is 200,000m

200,000m/10m/s = 20,000s

Explanation:

Answer:

15.9k

Explanation:

Identify which of the cyclists ended their trip closest to home. Which cyclists did not end their trip closest to home? Be sure to use evidence to support your claim and explain your reasoning. Answer in complete sentences.

Use CER, claim, evidence, and reasoning. The claim is your answer, the evidence is from the pictures, and the reasoning is your explanation.

Identify which of the cyclists ended their trip closest to home. Which cyclists did not end their trip

Answers

The cyclists S and U did not end their trip closest to home.

What is displacement?

A displacement is a vector in geometry and mechanics whose length is the shortest distance from the starting point to the position after motion.

It calculates the length and angle of the net motion, or total motion, in a straight line from the starting point to the destination of the point trajectory. The translation that links the starting point and the ending point can be used to spot a displacement.

In the give graphs, the cyclists S and U  have the highest displacement. Hence, they did not end their trip closest to home.

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What is a metallic bond?
Explain in like a simple way please

Answers

Metallic bond, force that holds atoms together in a metallic substance. ... The atoms that the electrons leave behind become positive ions, and the interaction between such ions and valence electrons gives rise to the cohesive or binding force that holds the metallic crystal together.
Metallic bond, force that holds atoms together in a metallic substance. ... The atoms that the electrons leave behind become positive ions, and the interaction between such ions and valence electrons gives rise to the cohesive or binding force that holds the metallic crystal together.

A metallic bond is the sharing of many detached electrons between many positive ions, where the electrons act as a "glue" giving the substance a definite structure. It is unlike covalent or ionic bonding. ... The electrons and the positive ions in the metal have a strong attractive force between them.

how do i multiply 9.6 by 3/2

Answers

Solve the given problem as

\(\begin{gathered} x=9.6\times\frac{3}{2} \\ =9.6\times1.5 \\ =14.4 \end{gathered}\)

When the mass of the cylinder increased from 3.0 kg to 6.0 kg, what happened to the amount of heat generated in the system? it decreased by a factor of 3. it decreased by a factor of 2. it increased by a factor of 2. it increased by a factor of 3.

Answers

Option c. It is increased by 2.

Heat generation that is thermal capacity of an object is dependent on mass. So if the mass of an object increases, the heat generation also increases.

How thermal capacity is related to mass?

Thermal capacity= mass × specific heat

As we can see by the formula, that the thermal capacity is directly proportional to mass. So if the mass of the object increases, so does the thermal capacity.

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The answer is C:

It increased by a factor of 2.

a) What is the y component of the vector given in the diagram? (120 N, 50 °) 120 N 50⁰ (C) 60 N (B) 92 N (D) 120 N (A) 77N

Answers

Answer: B

Explanation:

The y component of the vector is given by the formula:

y component = magnitude of the vector x sin(angle between the vector and the y-axis)

In this case, the magnitude of the vector is 120 N and the angle between the vector and the y-axis is 50 degrees. So we have:

y component = 120 N x sin(50°) ≈ 92 N

Therefore, the answer is (B) 92 N.

How does LIGO detect gravitational waves?
a. It looks for changes in the distance between sets of mirrors located at right angles to each other.
b. It uses lasers in an interferometer.
c. It measures variations in the Earth's gravitational acceleration.
d. It looks for the same signal nearly simultaneously in two different detectors located a few miles apart.

Answers

LIGO detect gravitational waves by: looks for changes in the distance between sets of mirrors located at right angles to each other, uses lasers in an interferometer, and looks for the same signal nearly simultaneously in two different detectors located a few miles apart.

So, the correct answer is A, B and D.

LIGO, or the Laser Interferometer Gravitational-Wave Observatory, detects gravitational waves using lasers in an interferometer.

It does this by looking for changes in the distance between sets of mirrors located at right angles to each other.

When a gravitational wave passes through, it causes the mirrors to move slightly, which can be detected by the interference pattern of the laser beams. LIGO also looks for the same signal nearly simultaneously in two different detectors located a few miles apart to confirm the detection.

By detecting gravitational waves, LIGO allows us to study the universe in a new way, opening up opportunities for new discoveries and insights into the nature of space and time.

Hence, the answer of the question is A, B and D.

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What is your wheel and axle

Answers

Explanation:

The wheel and axle is a type of simple machine used to make tasks easier in terms of manipulating force by applying the concept of mechanical advantage.

You are moving a chair by sliding it across the ground. The maximum force you can give the chair before it slides is 150 N. If you push the chair with 250 N of force and the chair begins to slide, what will the frictional force be?

Answers

Answer:

Frictional force will be 150N

No I need a ride home from school lol I just don’t need you too lol bye mama bye love

Write a paragraph on the nervous system.

Answers

Answer:

The basic building block of the nervous system is a nerve cell, or neurone. Neurones are shaped differently depending on where they are in the body and what role they play. All neurones have finger-like projections called dendrites and a long fibre called an axon.  In many cases, the axon is coated by a specialised membrane called a myelin sheath. The axon feathers out and has a number of bumps on it. Each bump sits near to a dendrite from another neurone. The space between the bump and the dendrite is called a synapse. Messages jump the synapse from one neurone to the next, using special chemicals called neurotransmitters.

Unlike other cells in the body, neurones aren’t easily replaced if they die or are damaged by infection or injury

Explanation: I hope this helped :)

1. If a plane flying at 230 m/s drops a package to the ground 75m below.
a. How much time before the package hits the ground?
b. How far in the x-direction does the package travel before it hits the ground?
c. What is the speed and direction of the package before it hits the ground?

2. A diver runs with a speed of 1.2 m/s straight off a diving board 10m above the water.
a. How much time is he in the air?
b. How far from the board does he land?
c. What is his speed right before he strikes the water?

3. A car leaves the edge of a cliff 55m high and hits 130 m from the base.
a. How much time is the car in the air?
b. What is the initial velocity of the car?
c. What is the speed and direction it hits the ground?

Answers

Answer:

What class is this for, I think I have done this before.

Electricity is converted into other forms of _________ such as heat, sound, or light.

Answers

Answer:

chemical i think

I hope this helped

What is the name of a hypothesis that has passed the test of many experiments and has support of other scientists

Answers

Answer: Scientific Hypothesis

Explanation: A scientific hypothesis is something supported or approved by a line of scientists through experiments and close observations.

a car traveling at 27 m/s hits a tree. if the front end of the car is 1.2 meters, what is the acceleration rate of the car.

Answers

The acceleration rate of the car travelling at 27m/s in 1.2metres is 303.8m/s².

How to calculate acceleration?

Acceleration of a body refers to the amount by which a speed or velocity increases. The acceleration of a moving body can be calculated using one of the equation of motion as follows:

v² = u² + 2as

Where;

v = final velocityu = initial velocitya = accelerations = distance

According to this question, a car traveling at 27 m/s hits a tree. if the front end of the car is 1.2 meters, the acceleration rate of the car can be calculated as follows:

27² = 0² + 2(a)(1.2)

729 = 2.4a

a = 303.8m/s²

Therefore, 303.8m/s² is the acceleration of the car.

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At a given temperature, 3.00 m of carbon dioxide has a mass of 5.94 kg. What is the density of carbon dioxide at this temperature​

Answers

Answer:

1.98 kg/m

Explanation:

5.94 divided by 3.00

What is the ratio of the orbital velocity of a terrestrial planet orbiting at 5.00 AU from its star to that of a giant planet orbiting at 19.00 AU? NOTE: You may assume circular orbits.

Answers

The ratio of the velocities of the two planets is 0.482

The velocity v of the planet in its circular orbit can be calculated using the following formula: v = 2πr/T

So, v = 2πr/ T

Where T is the time period of revolution of the planet around the star, r is the radius of the circular orbit, and v is the velocity of the planet in its orbit.

Since we can assume circular orbits, we have v ∝ r^-1/2.

Therefore, the ratio of velocities of the two planets is given as follows:

V1 / V2 = (r1 / r2)^(1/2)

Where, V1 is the velocity of the terrestrial planet orbiting at 5.00 AU, r1 is the radius of the orbit of the terrestrial planet around the star, V2 is the velocity of the giant planet orbiting at 19.00 AU, and r2 is the radius of the orbit of the giant planet around the star.

Therefore, substituting r1 = 5.00 AU, r2 = 19.00 AU, we get the ratio of the velocities of the two planets as:

V1 / V2 = (5/19)^(1/2)

V1 / V2 = 0.482

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The total mass of the reactants before a chemical reaction is the same as the total mass of the products after the chemical reaction.

Answers

Answer:

If it is a True or False question then the answer would be TRUE

Explanation:

simple machines are in a mousetrap

Answers

Answer:

A mousetrap makes use of a simple machine called a lever.

Explanation:

In a second-class lever the effort force is at the other end, with the load in the middle. In a third-class lever, the load is at the end and the effort force is between the fulcrum and the load. When you set the mousetrap, you are using a second-class lever. Sorry if I get this wrong. I am in 5th grade! ♥

how does 1 horsepower compare to 1 watt power​

Answers

Answer:

they both use power how much it has

Explanation:

i think

Answer:

1 horsepower is a unit of power equal to 746 watts 1 watt is a unit of power equal to 1 joule per second.

Explanation: Working on it for homework right now and using my textbook

Whispering Gallery: A hall 100 feet in length is to be designed as a whispering gallery. If the foci are located 25 feet from the center, how high will the ceiling be at the center?

Answers

The height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.

In an ellipse, the sum of the distances from any point on the ellipse to its two foci is constant. In this case, the two foci are located 25 feet from the center of the hall.

Given that the hall is 100 feet in length, the distance from one end to the center is 50 feet. We can consider this as the semi-major axis (a) of the ellipse.

The sum of the distances from any point on the ellipse to its two foci is equal to 2a. Thus, the sum of the distances from the ceiling at the center of the hall to the two foci is also 2a.

Since the foci are located 25 feet from the center, the sum of the distances is 2a = 50 feet.

To find the height of the ceiling at the center, we need to determine the semi-minor axis (b) of the ellipse. The semi-minor axis can be calculated using the formula:

b = √(a² - c²)

where c represents the distance from the center to each focus. In this case, c = 25 feet.

Substituting the values into the formula:

b = √(50² - 25²)

b = √(2500 - 625)

b = √(1875)

b = 43.3 feet

Therefore, the height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.

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A coal train in Montana starts from rest and accelerates at 2.5m/s^2 for 15 s.

Answers

Complete Question

A coal train in Montana starts from rest and accelerates at 2.5m/s^2 for 15 Find the trains maximum velocity

Answer:

The maximum velocity is   \(v =  37.5 \ m/s \)  

Explanation:

From the question we are told that

   The acceleration is \(a =2.5\ m/s^2\)

   The time for the acceleration is \(t = 15 \  s\)

Generally from the kinematics equation

   \(v =  u  +  at\)  

here u  is the initial  velocity and the value  is  0 m/s  given that it started rom rest

     \(v =  0  +  2.5  *  15\)  

     \(v =  37.5 \ m/s \)  

One side of a triangle is 4.0 m and another side is 3.0 m. The angle between the two sides is 142°. The length of the third side is

Answers

If one side of a triangle is 4.0 m and another side is 3.0 m. The angle between the two sides is 142°. The length of the third side is 2.7m.

How to find the length?

We can use the Law of Cosines to find the length of the third side:

c^2 = a^2 + b^2 - 2ab*cos(C)

where c is the length of the third side, a and b are the lengths of the other two sides, and C is the angle between those sides.

Substituting the given values:

c^2 = 4.0^2 + 3.0^2 - 24.03.0cos(142°)

c^2 = 16.0 + 9.0 - 24.0cos(142°)

c^2 = 25.0 + 24.0*(-0.766)

c^2 = 6.6

c = sqrt(6.6)

c ≈ 2.57 m

Therefore, the length of the third side is approximately 2.57 m.

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select the intermolecular forces present in water. group of answer choices h-bonding ion-dipole london dispersion dipole-dipole

Answers

The intermolecular forces present in water include hydrogen bonding and dipole-dipole interactions.

Water is a polar molecule, meaning it has a positive and a negative end due to an uneven distribution of electron density. This polarity gives rise to intermolecular forces that hold water molecules together.

One of the intermolecular forces present in water is hydrogen bonding. Hydrogen bonding occurs when a hydrogen atom, which is covalently bonded to an electronegative atom (in this case, oxygen), is attracted to another electronegative atom (such as oxygen or nitrogen) in a different molecule. In water, the oxygen atom of one water molecule forms a hydrogen bond with a hydrogen atom of a neighboring water molecule. Hydrogen bonding is a strong intermolecular force and contributes to many of the unique properties of water, such as its high boiling point and surface tension.

In addition to hydrogen bonding, water also exhibits dipole-dipole interactions. Dipole-dipole interactions occur between the positive end of one polar molecule and the negative end of another polar molecule. In water, the positive hydrogen end of one water molecule is attracted to the negative oxygen end of a neighboring water molecule. These dipole-dipole interactions are weaker than hydrogen bonds but still contribute to the overall intermolecular forces present in water.

Other intermolecular forces, such as ion-dipole interactions and London dispersion forces, are not as significant in water compared to hydrogen bonding and dipole-dipole interactions. Ion-dipole interactions occur between an ion and the charged end of a polar molecule, while London dispersion forces arise from temporary fluctuations in electron distribution. While these forces may exist in other substances, they play a relatively minor role in the intermolecular forces of water.

In conclusion, the intermolecular forces present in water are primarily hydrogen bonding and dipole-dipole interactions. These forces contribute to the unique properties and behavior of water as a liquid.

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A spacecraft is drifting at a constant speed of 500m/s. If a 20N Force is applied to the front of the craft and a 20N force is applied to the back of the craft, what will be the result

Answers

When a 20N force is applied to the front of the spacecraft and a 20N force is applied to the back of the spacecraft, the net force acting on the spacecraft will be zero.

This is because the forces applied to the front and back of the spacecraft are equal in magnitude and opposite in direction, thereby canceling each other out. As a result, the spacecraft will continue drifting at its constant speed of 500m/s.

A spacecraft is a vehicle designed to operate in outer space. It can be manned or unmanned, and can travel to different parts of the solar system and beyond. Spacecraft use a combination of rocket propulsion, gravity assist, and other techniques to reach their destinations.

They are used for scientific exploration, military purposes, and commercial activities such as satellite deployment and space tourism. Spacecraft have played a crucial role in advancing our understanding of the universe and expanding our capabilities in space.

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Which of the following is NOT a type of electromagnetic wave?

Which of the following is NOT a type of electromagnetic wave?

Answers

Answer:

Sound waves

Explanation:

You should let someone else answer too though because I'm not 100% sure that's the correct answer.

what type of energy are the water molecules gaining during a phase change​

Answers

Answer:

Potential energy.

Explanation for yall who dont get:

Basically, the energy that is changing during a phase change is potential energy. Why? Cuz, during a phase change, the heat added (Potential Energy INCREASES) or released (Potential Energy DECREASES) allow the molecules to move apart or be together.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Leme know if im wrong.  

GL.

problem 6: a car, starting from rest, accelerates at 1.72m/s 2 m/s2 on a circular track with a 225mm diameter.
What is the elapsed time, in seconds, at which the centripetal acceleration of the car has the same magnitude as its tangential acceleration?

Answers

A car, starting from rest, accelerates at 1.72m/s 2 m/s2 on a circular track with a 225mm diameter. The elapsed time at which the centripetal acceleration of the car has the same magnitude as its tangential acceleration is approximately 0.244 seconds.

We can start by finding the centripetal acceleration and the tangential acceleration of the car.

The centripetal acceleration is given by

ac = \(v^{2}\) / r

Where v is the speed of the car and r is the radius of the circular track. Since the diameter is given as 225 mm, the radius is

r = 225 mm / 2 = 0.1125 m

The tangential acceleration is simply the rate of change of the speed, given by

at = d v / d t

Where t is time.

Since the car starts from rest, its initial speed is zero. We can integrate the acceleration to find the speed as a function of time

at = d v / d t = 1.72 m/\(s^{2}\)

Integrating both sides with respect to time, we get

v = at t

Now we can substitute this into the expression for the centripetal acceleration to get

ac =  \(v^{2}\) / r = \(( at t)^{2}\) / r

We want to find the time at which the magnitudes of the centripetal and tangential accelerations are equal, so we set them equal and solve for t

ac = at

\(( at t)^{2}\) / r = at

\(t^{2}\) = r / at

\(t^{2}\) = (r / at) = (0.1125 m / 1.72  m/\(s^{2}\))

t = 0.244 seconds.

Therefore, the elapsed time at which the centripetal acceleration of the car has the same magnitude as its tangential acceleration is approximately 0.244 seconds.

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The voltage across two points in an electric circuit is
876 mV. A power source does 1 901 kJ of work
when moving a certain amount of charge between
these two points.
Determine the amount of charge that moved between
between the two points.

Answers

Answer:

V=w/q V= 1.2/0.4* 10 ^-3 V = 3 * 10 ^ 3 V = 3000 v

if its not correct let me know so I can figure it out

The following images show five planets in our solar system. Rank these planets from left to right based on their average surface (or cloud-top) temperature, from highest to lowest. (Not to scale.)
Highest -- Mercury, Earth, Mars, Jupiter, Neptune -- Lowest
Notice that, for these five planets, temperature correlates with distance from the Sun: the closer to the Sun, the hotter the planet. Remember, however, that this is not always the case, because a planet’s temperature also depends on its reflectivity and on the strength of its greenhouse effect (if any). For example, the greenhouse effect gives Venus a higher average temperature than Mercury, even though Venus is nearly twice as far from the Sun.

Answers

Loftiest to smallest temperature

Mercury

Earth

Mars

Jupiter

Neptune

What's the average face temperature?

Planetary face temperatures range from over 400 °C on Mercury and Venus to below-200 °C on distant globes. The factors that determine temperature are the complex balance of heat entered and lost.

Thus, for these five globes, temperature correlates with distance from the Sun. The near to the sun, the hotter the earth. Note, still, that this isn't always the case, as the earth's temperature also depends on its reflectance and the strength of the greenhouse effect( if present). For illustration, although Venus is nearly doubly as far from the Sun, the average temperature on Venus is advanced than on Mercury due to the greenhouse effect.

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