What is the recursive formula for the geometric sequence with this explicit
formula?

Option B is true of a probability mass function but not a probability density function.

A probability mass function is used to describe the probability distribution of a discrete random variable. The function maps each possible value of the random variable to the probability of that value occurring. Therefore, a probability mass function takes on only non-negative values and sums to one over its domain.Option A and C are true of both probability mass function and probability density function.

A probability density function, on the other hand, describes the probability distribution of a continuous random variable. The function assigns probabilities to intervals of possible values rather than to specific values. For this reason, the probability that a random variable X is equal to a specific value x is always zero. Therefore, option B is true of a probability mass function but not a probability density function.Option D is true of both probability mass function and probability density function. This is because, for continuous random variables, the probability that a random variable X is between a and b is the area under the function between a and b (integral), while for discrete random variables, it is the sum of the probabilities of all values between a and b.

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Answer:

10

Step-by-step explanation:

So |7|+3=10

Answer:

g(7) = 10

Step-by-step explanation:

Hello!

The absolute value turns the value inside positive.

Find g(7) by plugging in 7 for n.

g(7) is 10.

Answer:

14005

Step-by-step explanation:

I did the math and everything checks out

\(~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{-12}x\stackrel{\stackrel{c}{\downarrow }}{-35}=y \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (-12) \pm \sqrt { (-12)^2 -4(1)(-35)}}{2(1)} \implies x = \cfrac{ 12 \pm \sqrt { 144 +140}}{ 2 } \\\\\\ x= \cfrac{ 12 \pm \sqrt { 284 }}{ 2 }\implies x= \cfrac{ 12 \pm 2\sqrt { 71 }}{ 2 }\implies x=6\pm\sqrt{71} \\\\[-0.35em] ~\dotfill\)

\(x=6+\sqrt{71}\implies x-6-\sqrt{71}=0 \\\\[-0.35em] ~\dotfill\\\\ x=6-\sqrt{71}\implies x-6+\sqrt{71}=0 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} (x-6-\sqrt{71})(x-6+\sqrt{71}) \end{array}}~\hfill\)

To calculate the 95% confidence interval for the difference in mean weekly sales for the two movie theaters, follow these steps:

Step 1: Gather the data for the random sample of 25 weeks.

Step 2: Calculate the mean and standard deviation for each movie theater's weekly sales.

Step 3: Calculate the difference in mean weekly sales for the two movie theaters (subtract the mean of theater 2 from the mean of theater 1).

Step 4: Calculate the standard error of the difference by taking the square root of [(standard deviation of theater 1^2 / number of weeks) + (standard deviation of theater 2^2 / number of weeks)].

Step 5: Determine the critical value for a 95% confidence interval using a t-table or calculator (for a two-tailed test with 24 degrees of freedom, the critical value is approximately 2.064).

Step 6: Multiply the critical value by the standard error to get the margin of error.

Step 7: Calculate the lower and upper bounds of the confidence interval by subtracting and adding the margin of error from the difference in mean weekly sales.

The result will be the 95% confidence interval for the difference in mean weekly sales for the two movie theaters.

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The rate of conversion between pounds and ounces is shown as;

16 ounces = 1 pound

Then you have a digital scale that measures weight in ounces. If you put an object that weighs "exactly 1 pound" on the digital scale, its supposed to display 16 ounces.

However the scale has been described as "not accurate," which implies that the calibration (fine tuning) has been altered either accidentally or on purpose. This also implies that the result would not be 100 percent correct, but it might be a little over or below 16 ounces. Hence the scale might display what in mathematics is termed as "plus or minus" and is denoted by the sign ±

The scale therefore might display 15 ounces or 17 ounces (that is ± 16)

±

Answer:

C

Step-by-step explanation:

\(Answer:\ f^{-1}(x)=\sqrt[3]{x} -4\)

Step-by-step explanation:

\(f(x)=(x+4)^3\)

Extract the cube root from both parts of the equations:

\(\sqrt[3]{f(x)} =x+4\\\sqrt[3]{f(x)}-4=x+4-4\\ \sqrt[3]{f(x)} -4=x\)

Redefine the variables:

\(f^{-1}(x)=\sqrt[3]{x} -4\)

Answer:

What is the question?

I can't see any question.

Answer:

72

Step-by-step explanation:

Answer: 12 animals 36 people , in total 48 its so easy just adding and multiplying :)

Step-by-step explanation:6 knights 6 squires =12,  then animals human people 6 time animals 2 is 12 animals then more humans 2 times 12 the horses is 24 in total add up humans 24+12=36 and animals is 12 so 36 people, and 12 animals in total 36+12 is 48

Answer:

the correct answer is b

Answer:

The money Emily spend is 324 dollars

Step-by-step explanation:

Given:

3 pairs of shorts= 25 dollars

5 tank tops = 23 dollars

1 pair of sandal = 54 dollars

2 bathing suits = 40 dollars

The total money spend on 3 pairs of shorts is 3 x 25=75

The total money spend on 5 tank tops is 5 x 23=115

The total money spend on 1 pairs of sandals =54

The total money spend on bathing suits is 2 x 40= 80

Adding them all= 75+115+54+80

                         = 324 dollars

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The amount Emily spent is $324

We are given that

3 pairs of shorts = $25

5 tank tops = $23

1 pair of sandals = $54

2 swimsuits = $40

Total amount spent on 3 pairs of shorts is 3 x 25 = 75

The total amount spent for 5 increased shirts is 5 x 23 = 115

Total amount spent on 1 pair of sandals = 54

Total amount spent on swimwear is 2 x 40 = 80

Add them all up = 75 + 115 + 54 + 80

= $324

The amount Emily spent is $324

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Answer: The answer is 6. Please mark BRAINLIEST!!

Answer:

the factor pairs of 12 are  1 and 12 , 2 and 6 , 3 and 4

Step-by-step explanation:

The computation of the factor pairs is shown below:

The factor pairs means the two numbers which are multiplied to get the number 12

So it is

1 and 12

2 and 6

3 and 4

Hence, the factor pairs of 12 are  1 and 12 , 2 and 6 , 3 and 4

The same would be relevant

Answer:

b = -a

Step-by-step explanation:

Since a and b are equally distant to zero but in opposite directions, a and b are opposites, or additive inverses.

The sum of additive inverses is zero.

a + b = 0

b = -a

The eighth term of the sequence -2, -1, 0, 1, 2, ... is 5.

Given is an arithmetic sequence -2, -1, 0, 1, 2.... we need to find the eighth term of the sequence,

The arithmetic sequence has a common difference of 1.

To find the eighth term, we can use the formula for the nth term of an arithmetic sequence:

nth term = first term + (n - 1) x common difference

In this case, the first term is -2 and the common difference is 1.

Plugging in the values, we have:

8th term = -2 + (8 - 1) x 1

= -2 + 7

= 5

Therefore, the eighth term of the sequence -2, -1, 0, 1, 2, ... is 5.

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Step-by-step explanation:

\( \frac{2}{3} = 2 \times \frac{1}{3} = 2 \times 0.333 = 0.666 \\ \\ \frac{7}{6} = 7 \times \frac{1}{6} = 7 \times \frac{1}{2} \times \frac{1}{3} = 7 \times 0.5 \times 0.333 = 1.1655 \\ \\ 3 \frac{1}{9} = 3 + \frac{1}{9} = 3 + ( \frac{1}{3} \times \frac{1}{ 3} ) = 3 + (0.333 \times 0.333) = 3 \times 0.11088 = 3.11088 \\ \\ 5 \frac{5}{18} = 5 + (5 \times \frac{1}{18} ) = 5 + (5 \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{2} ) = 5 +(5 \times 0.333 \times 0.333 \times 0.5) = 5 + 0.27722 = 5.27722\)

Answer:

1 slice will be left because there are 16 slices and 15 guests

Step-by-step explanation:

a. The probability that he must stop at both signals is 0.2.b. The probability that he must stop at the first signal but not at the second one is 0.2.

c. The probability that he must stop at exactly one signal is 0.5.

a. The probability that he must stop at both signals is equal to the product of the individual probabilities of stopping at each signal, which is 0.4 x 0.5 = 0.2.

b. The probability that he must stop at the first signal but not at the second one is equal to the probability of stopping at the first signal only, which is 0.4.  

c. The probability that he must stop at exactly one signal is equal to the sum of the probability of stopping at the first signal and the probability of stopping at the second signal, which is 0.4 + 0.5 = 0.5.

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The solution to the given initial value problem, obtained using Laplace transforms, is y(x) = 0. This means that the function y(x) is identically zero for all values of x.

To find the solution of the initial value problem using Laplace transforms for the equation d²y/dx² + 9y = 9sin(t)u(t - 3), where y(0) = y'(0) = 0, we can follow these steps:

Take the Laplace transform of the given differential equation.

Applying the Laplace transform to the equation d²y/dx² + 9y = 9sin(t)u(t - 3), we get:

s²Y(s) - sy(0) - y'(0) + 9Y(s) = 9 * (1/s² + 1/(s² + 1))

Since y(0) = 0 and y'(0) = 0, the Laplace transform simplifies to:

s²Y(s) + 9Y(s) = 9 * (1/s² + 1/(s² + 1))

Solve for Y(s).

Combining like terms, we have:

Y(s) * (s² + 9) = 9 * (1/s² + 1/(s² + 1))

Multiply through by (s² + 1)(s² + 9) to get rid of the denominators:

Y(s) * (s⁴ + 10s² + 9) = 9 * (s² + 1)

Simplifying further, we have:

Y(s) * (s⁴ + 10s² + 9) = 9s² + 9

Divide both sides by (s⁴ + 10s² + 9) to solve for Y(s):

Y(s) = (9s² + 9)/(s⁴ + 10s² + 9)

Partial fraction decomposition.

To proceed, we need to decompose the right side of the equation using partial fraction decomposition:

Y(s) = (9s² + 9)/(s⁴ + 10s² + 9) = A/(s² + 1) + B/(s² + 9)

Multiplying through by (s⁴ + 10s² + 9), we have:

9s² + 9 = A(s² + 9) + B(s² + 1)

Equating the coefficients of like powers of s, we get:

9 = 9A + B

0 = A + B

Solving these equations, we find:

A = 0

B = 0

Therefore, the decomposition becomes:

Y(s) = 0/(s² + 1) + 0/(s² + 9)

Inverse Laplace transform.

Taking the inverse Laplace transform of the decomposed terms, we find:

L^(-1){Y(s)} = L^(-1){0/(s² + 1)} + L^(-1){0/(s² + 9)}

The inverse Laplace transform of 0/(s² + 1) is 0.

The inverse Laplace transform of 0/(s² + 9) is 0.

Combining these terms, we have:

Y(x) = 0 + 0

Therefore, the solution to the initial value problem is:

y(x) = 0

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The sum of length of the parallel sides of a trapezium exists 300 cm.

A trapezoid, which is often referred to as a trapezium, is a flat, closed object with four straight sides and one set of parallel sides. A trapezium's parallel bases and non-parallel legs are referred to as its bases and legs, respectively. Also possible are parallel legs on a trapezium.

Four sides, four corners/vertices, and four angles make up a trapezium, which is a closed shape or polygon. A trapezium has parallel sides on each of its opposing angles.

One set of the sides of a trapezium is parallel only. Since no trapezium is a rectangle, they are not all the same.

Area of trapezium = (a + b)/2 × h

where h is the perpendicular height, and a and b are parallel sides.

So, (a + b) exists sum of length of bases of a trapezium.

Let the equation be

Area of trapezium = (a + b)/2 × h

substitute the values in the above equation, we get

⇒  4.2 × 100² = (a + b) / 2 × 280 {1 m = 100 cm}

simplifying the equation, we get

⇒ (84/280) × 10000 = a + b

⇒ a + b = 300 cm

Therefore, the sum of length of the parallel sides of a trapezium exists 300 cm.

The complete question is:

Find the sum of length of the parallel sides of a trapezium whose area is 4.2 m² and whose height is 280 cm.

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The sum of length of the parallel sides of a trapezium exists 300 cm.

A trapezoid, also known as a trapezium, is a closed, flat object with one pair of parallel sides and four straight sides. The parallel bases and the non-parallel legs of a trapezium are called the bases and the legs, respectively. A trapezium with parallel legs is another option.

A trapezium is a closed shape or polygon with four sides, four corners, and four angles. Each of the opposing sides of a trapezium has parallel sides.

A trapezium has only one set of parallel sides. They are not all the same since no trapezium is a rectangle.

Area of trapezium = (a + b)/2 × h

where h is the perpendicular height, and a and b are parallel sides.

So, (a + b) exists sum of length of bases of a trapezium.

Let the equation be

Area of trapezium = (a + b)/2 × h

substitute the values in the above equation, we get

⇒  4.2 × 100² = (a + b) / 2 × 280 {1 m = 100 cm}

simplifying the equation, we get

⇒ (84/280) × 10000 = a + b

⇒ a + b = 300 cm

Therefore, the sum of length of the parallel sides of a trapezium exists 300 cm.

The complete question is:

Find the sum of length of the parallel sides of a trapezium whose area is 4.2 m² and whose height is 280 cm.

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Answer:

7/2

Step-by-step explanation:

rewrite the equation

7 / 6 / 3

7 /2

simplest doesn't mean answer fully just get to the simplest form where there are only absolute numbers

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a. When evaluating a model, we use R2 as a parameter for performance assessment.

b. If model A has a higher MAPE but model B has a higher R2, we choose the model with the higher R2 for better overall performance.

c. For accuracy measures, we typically use MAPE (Mean Absolute Percentage Error) due to its interpretability and ability to capture relative errors.

When evaluating a model's performance, it is crucial to choose the appropriate parameters to assess its accuracy and reliability. In the case of MAPE (Mean Absolute Percentage Error) and R2 (Coefficient of Determination), the choice between them depends on the specific evaluation goals.

The R2 parameter is commonly used for evaluating models because it measures the proportion of the dependent variable's variance that can be explained by the independent variables. R2 provides insights into how well the model fits the data and captures the relationship between the input features and the target variable. Therefore, R2 is a suitable parameter to use when evaluating a model.

When comparing two models, if model A has a higher MAPE but model B has a higher R2, it is advisable to choose the model with the higher R2 value. This is because R2 indicates the proportion of variance explained, suggesting that model B performs better in capturing the underlying patterns and predicting the target variable.

Although model A may have a lower relative error (MAPE), it is crucial to prioritize the model's ability to explain and predict the target variable accurately.

Among MAPE, MAD (Mean Absolute Deviation), and MSD (Mean Squared Deviation), MAPE is commonly preferred as a parameter for accuracy measures. MAPE calculates the average percentage difference between the predicted and actual values, making it interpretable and easily understandable.

It captures relative errors and enables comparisons across different scales and datasets. MAD and MSD, on the other hand, measure absolute and squared errors, respectively, but they do not account for the relative magnitude of the errors. Hence, MAPE is a more suitable parameter for accuracy measures.

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Our calculated t-value of -5.88 is less than the critical t-value of 2.201, we have sufficient evidence to reject the null hypothesis that there is no difference in the mean time until remission between the two treatments.

To determine whether there is a significant difference in the mean time until remission for the two treatments, we can use an independent t-test.

First, we need to calculate the mean difference between the two groups:

Mean difference = mean time until remission for treatment 1 - mean time until remission for treatment 2

= 154 days - 162 days

= -8 days

Next, we need to calculate the standard deviation of the difference:

Standard deviation of difference = √((standard deviation for treatment 1²/sample size for treatment 1) + (standard deviation for treatment 2²/sample size for treatment 2))

= √(7²/13 + 6²/9)

= √(49/13 + 36/9)

= √(3.77 + 4)

= 2.86

Now that we have the mean difference and standard deviation of the difference, we can calculate the t-value:

t-value = (mean difference)/(standard deviation of difference/√(sample size for treatment 1 + sample size for treatment 2))

= (-8)/(2.86/√(13 + 9))

= (-8)/(1.36)

= -5.88

Finally, we need to find the critical t-value from a t-table using the appropriate degrees of freedom (13-1=12 for treatment 1 and 9-1=8 for treatment 2) and alpha level (typically 0.05). For a two-tailed test (assuming we are interested in whether there is any difference in mean time until remission between the two treatments), the critical t-value at an alpha level of 0.05 is 2.201.

Since our calculated t-value of -5.88 is less than the critical t-value of 2.201, we have sufficient evidence to reject the null hypothesis that there is no difference in mean time until remission between the two treatments. This means that we can conclude that there is a significant difference in mean time until remission between the two treatments. However, we cannot determine which treatment is more effective based on this test alone. Additional analysis would be needed to determine the direction of the difference and whether one treatment is more effective than the other.

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Answer:

$0.18

Step-by-step explanation:

we need to set up two simultaneous equations

using variables, pencils = p and erasers = e

3 pencils and 2 erasers, the cost is $0.76

3p + 2e = $0.76

2 pencils and 4 erasers, the cost is $1.04.

2p + 4e = $1.04

we now have

3p + 2e = $0.76

2p + 4e = $1.04

to make the number of erasers the same, multiply the first equation by 2 to give 4e

2(3p + 2e = $0.76)

6p + 4e = $1.52

now we have the same number of erasers for both equations

6p + 4e = $1.52

2p + 4e = $1.04

subtract across: 6p - 2p = 4p, 4e - 4e = 0, $1.52 - $1.04 = $0.48

we are left with 4p = $0.48

divide both sides by 4

p = $0.12

1 pencil = $0.12

go back to the start of both equations and use one of them to find 1 eraser. I'll use 3p + 2e = $0.76

input $0.12 in p

3($0.12) + 2e = $0.76

$0.36 + 2e = $0.76

subtract $0.36 on both sides

2e = $0.76 - $0.36

2e = $0.40

divide 2 on both sides

e = $0.20

1 eraser = $0.20

How much more does 1 eraser cost than 1 pencil?

we now know 1 pencil = $0.12 and 1 eraser = $0.20

find the difference between them

$0.20 - $0.12 = $0.18

final answer= $0.18

Answer:

About 12 peanuts.  This is 20% of 60 (nuts and peanuts together)

Step-by-step explanation:

Let  there be a total of n pieces in the mixture.  Then, focusing on raisins, 0.80n = 48, so that n = 60.  Then the number of peanuts is 0.20(60) = 12.

Answer:

the y intercept is 105. the n is like X.

hope that helped!!!!

Step-by-step explanation:

C=105+5n

y=mx+b

y=5x+105