What is the net force exerted on a 28.8 kg shopping cart that accelerates at a rate of 2.88 m/s^2?​

The component of horizontal velocity of bullet is 8m/s for 4 radians per second.

Given - Rotation rate = 4 rad per sec.

This means 4 radians for one seconds . i.e. one seconds is equivalent to 60min.

To resolve the velocity following equation can be employed-

\(\beta =vt+\frac{\alpha t^2}{2}\\ \\\beta = rotation\\\\v= velocity\\\\t= time\\\\\alpha =acceleration\)

Now substituting all values in this equation

4= 0+α/2

α=4 x 2 ⇒8m/s²

since the rotation is for one seconds so velocity = acceleration.

\(acceleration=\frac{dv}{dt}\)

dt =1

so α=v=8m/s

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Answer:

See below

Explanation:

\(\displaystyle {\textsf {Acceleration is the rate of change of velocity with time:}}\)

\(\boxed {g = \frac{dv}{dt}}\)

\(\sf {where \;dv = \;change \;in \;velocity\; and \;dt \;the \;change \;in \;time}\)

here  g is the gravitational force

When a body is thrown vertically upward, it has an initial speed. As it keeps going up, it speed keeps decreasing until it becomes zero, then the ball starts dropping down

On the upward movement, the change in velocity is negative while the change in time is always positive

So dv/dt = a negative number divided by a positive number which is a negative value for g in the equation for g

Explanation:

mass = newton ÷ g

m = 1025 ÷ 10

mass= 102.5kg

Answer:

A carton of mass 50-kg slides across an icy surface at a speed of 4 m/s. Conclusion : The momentum of a carton of given mass moving with a particular velocity is 200 kg−m/s .

The average rate at which the cable does work is 294,000 J/s.

The given parameters:

The average rate at which the cable does work is calculated as follows;

\(P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{3000 \times 9.8 \times 200}{20} \\\\P = 294,000 \ J/s\)

Thus, the average rate at which the cable does work is 294,000 J/s.

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The net force that acts on the plane's 106 kg pilot is 151.58N.

The net force acting on an object is the result of all pushing and pulling forces acting on the object collectively (the sum). If there is an imbalance in the pushing and pulling forces acting on an object, the object will accelerate in the direction of the net force.

All forces acting on an object are added together to form the "net force." If the object is not moving, then this net force must be equal to zero, according to Newton's First Law.

acceleration a = F/m

a =  38700/ 26900

a = 1.43m/s²

F = ma

F = 106×1.43

F = 151.58N.

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To solve problems involving waves, it's important to know the relationships between frequency, wavelength, and speed, which are given by the formulas v = f λ and T = 1/f, where v is the speed of the wave, f is the frequency, λ is the wavelength, and T is the period of oscillation.

The period of the tree is T=1/f= 1/58.0 Hz = 0.0172 s.

The wavelength of the wave is λ = 2 (crest to trough distance) = 2 (3.4 m)  = 6.8 m.

The speed of the sound wave is v = f λ = (285 Hz) (1.5 m) = 427.5 m/s.

The distance to the other side of the canyon is d = (speed of sound) × (time for echo to return) / 2 = (336.0 m/s) × (5.5 s) / 2 = 924 m.

The wavelength of the radio waves emitted by WKLB is λ = c / f = 3 x 10^8 m/s / 97.1 x 10^3 Hz = 3.09 m.

The speed of the water waves is v = λ / T = (7 m) / (3 s) = 2.33 m/s.

The wavelength of the water waves is λ = v T = (2.9 s) (2.33 m/s) = 6.74 m.

The frequency of the pulses is f = 1/T = 1/0.84 s = 1.19 Hz.

The speed of the wave is v = λ / T = (1.9 cm) / (0.95 s) = 2 cm/s.

The frequency of the sound wave is f = v / λ = 340 m/s / 2.3 x 10^-3 m = 1.48 x 10^5 Hz.

The speed of sound in air at 29.2°C is v = 331 m/s + (0.6 m/s/°C) × (29.2°C) = 349.5 m/s.

The wavelength of the sound wave is λ = v / f = (331 m/s + (0.6 m/s/°C) × (7.9°C)) / (40.7 Hz) = 8.06 m.

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The water budget equation for the Creek drainage basin is: Precipitation = Stream discharge + Evapotranspiration ± Change in storage.

To develop the water budget equation for this problem, we need to account for the inputs and outputs of water in the Creek drainage basin. The water budget equation can be expressed as,

P = Q + ET ± ΔS

P = Precipitation input (mm)

Q = Stream discharge (m³/s)

ET = Evapotranspiration (mm)

ΔS = Change in storage (mm)

First, let's convert the units of the given values,

Precipitation input (P) = 550 mm

Stream discharge (Q) = 1.8 m³/s

Now, let's determine the evapotranspiration (ET) and change in storage (ΔS) terms. However, the problem doesn't provide information about ET, so we cannot calculate it accurately. The problem doesn't provide information about ΔS, so we cannot calculate it accurately.

Given these limitations, we can write the simplified water budget equation for this problem,

550 mm = 1.8 m³/s + ET ± ΔS

Please note that without information about evapotranspiration and changes in storage, we cannot fully determine the water budget for the Creek drainage basin.

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Answer:

-100 kg · m/s

Explanation:

We can find the momentum of an object using the formula:

Let's start by converting the mass of the object to kilograms.

Since the left direction is the negative direction, we know that the velocity of the object is -25 m/s.

Using these variables, we can solve for p in the formula.

The momentum of the object is -100 kg · m/s.

Answer:

give brainliest please

Explanation:

T- lymphocytes or T cells

Answer:

\(A_{1}\) = 0.2 \(m^{2}\)

Explanation:

The pressure on the pistons is given as;

Pressure = \(\frac{Force}{Area}\)

So that,

Pressure on the small piston = \(\frac{F_{1} }{A_{1} }\) and Pressure on the large piston = \(\frac{F_{2} }{A_{2} }\)

Thus,

\(\frac{F_{1} }{A_{1} }\) = \(\frac{F_{2} }{A_{2} }\)

Given that: \(F_{1}\) = 100 N, \(F_{2}\) = 2000 N, \(A_{2}\) = 4 \(m^{2}\).

\(\frac{100}{A_{1} }\) = \(\frac{2000}{4}\)

\(A_{1}\) = \(\frac{100*4}{2000}\)

    = \(\frac{400}{2000}\)

    = 0.2

\(A_{1}\) = 0.2 \(m^{2}\)

The area of the small piston is 0.2 \(m^{2}\).

Answer:

D i took the test

Explanation:

Answer:

The answer is D.

Explanation:

The other ones just don't make sense. AT ALLLLLL!!!!!!!!!!!!!!!!!!!!!!!

The sound wave with more energy is the sound wave that is louder because it will have more amplitude.

Sound energy occurs when a force, either sound or pressure, makes an object or substance vibrate.

That energy moves through the substance in waves.

The energy transmitted by a sound wave depends on several factors such as;

Mathematically, the formula for energy transmitted by a sound wave is given as;

P = ¹/₂μω²A²v

where;

Thus, a sound wave more amplitude (loudness) will have more energy that a sound wave with lesser amplitude (loudness).

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Equation of motion: To find the equation of motion and the oscillation frequency of a mass-spring system, we'll use Newton's second law of motion.

Force (F) = mass (m) × acceleration

F = ma

The force acting on a spring is given by Hooke's law:

F = -k x

where k is the spring constant and x is the displacement from the equilibrium position.

Thus, combining these two equations gives us the following equation of motion for a mass-spring system:

ma = -k x

Rearranging this, we get:

m(d²x/dt²) + k x = 0

This is the differential equation of motion of the mass-spring system.

Oscillation frequency:

The oscillation frequency can be calculated using the equation:

f = (1/2π) √(k/m)

where f is the frequency, k is the spring constant, and m is the mass.

Lagrange function:

The Lagrange function for a mass-spring system can be written as:

L = T - VL

is the difference between the kinetic energy (T) and potential energy (V) of the system.

The kinetic energy of the system is given by:

T = (1/2) mv²where m is the mass and v is the velocity.

The potential energy of the system is given by:

V = (1/2) kx²

where k is the spring constant and x is the displacement from the equilibrium position.

L = (1/2) mv² - (1/2) kx²

Equation of motion:

Using the Euler-Lagrange equation, the equation of motion for a mass-spring system can be derived.

It is given by:

d/dt (∂ L/∂v) - ∂L/∂x = 0

Substituting the values from the Lagrange function:

L = (1/2) mv² - (1/2) kx²∂L/∂v = m v ∂L /∂x = -k x.

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Answer:

\(v_x=34 m/s\)

\(v_y=53.9\ m/s\)

Explanation:

Horizontal Launch

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

\(v_y=g.t\)

The horizontal component of the velocity is always the same:

\(v_x=34 m/s\)

The vertical component at t=5.5 s is:

\(v_y=9.8*5.5=53.9\)

\(v_y=53.9\ m/s\)

Answer:

?

Explanation:

Answer:

The different layers of carbon atoms present in graphite are bounded by weak van der Waals forces. ... The cleaning between the layers is done by graphite, thus, it is so slippery and soft. This is the reason why graphite is used in pencil and as lubricants in machines which operate at high temperature.

grahite is used in pencils because its so oily and it also forms quickly so it best sometimes

Answer:

Red is the longest of the visible wavelengths.

One would see red first

The visible spectrum can be characterized by "ROY G BIV".

Or

Red-Orange-Yellow-Green-Blue-Indigo-Violet

From the longest wavelength to the shortest (7000-4000 Angstroms)

This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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In the given scenario, a torsion bar with a diameter of 20 mm is being used as a suspension element for a vehicle. The torsion bar experiences a torsional moment of 450 N.m and an axial tensile force of 36.0 kN.

The torsional moment of 450 N.m indicates the torque applied to the torsion bar, causing it to twist or undergo torsion. This torque is responsible for providing the necessary suspension characteristics, such as stability and resilience.
The axial tensile force of 36.0 kN represents the tension force acting along the length of the torsion bar. This force helps to maintain the integrity and structural stability of the suspension system, ensuring proper load-bearing capacity.
The combination of the torsional moment and axial tensile force in the torsion bar allows it to effectively absorb and distribute forces encountered during vehicle operation, contributing to a smoother and more controlled ride.

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To make 4 amperes flow through a resistance of 20 ohms, 80 volts of voltage are required.

Ohm's law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. In other words, the greater the voltage, the greater the current that flows through a given resistance.

The voltage required to make 4 amperes flow through a resistance of 20 ohms can be calculated using Ohm's law:

Voltage (V) = Current (I) x Resistance (R)

Therefore, V = 4 A x 20 Ω = 80 V

So, to make 4 amps flow through a resistance of 20 ohms, 80 volts of electricity are required.

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Answer:

The ratio of the mass of planet Zeb to the mass of Earth must be 8.

Explanation:

The gravitational acceleration on the surface of a planet is determined by the mass of the planet and its radius. The equation is g = GM/r^2, where G is the gravitational constant, M is the mass of the planet, and r is the radius of the planet.

If we assume that the gravitational acceleration on the surface of both planets is the same, we can set the equation for Earth equal to the equation for planet Zeb and solve for the ratio of the mass of planet Zeb to the mass of Earth.

g(earth) = GM(earth)/r(earth)^2 = GM(zeb)/r(zeb)^2

We know that r(zeb) = 2 * r(earth)

so,

GM(earth)/r(earth)^2 = GM(zeb)/(2*r(earth))^2

GM(zeb)/GM(earth) = (2*r(earth))^2 /r(earth)^2

GM(zeb)/GM(earth) = 4*4

GM(zeb)/GM(earth) = 16

So the ratio of the mass of planet Zeb to the mass of Earth is 16/1 = 8

The tension in the string between the blocks depends on the applied force F and the ratio of the masses mB/mA.

When the frictionless system is accelerated by an applied force of magnitude F, the tension in the string between the blocks can be determined using Newton's Second Law of Motion. The equation for this law is F = m*a, where F is the force, m is the mass, and a is the acceleration.
For the block connected to the applied force, let's call it block A, the force equation would be F = mA*aA. For the other block, block B, the force equation would be T = mB*aB, where T is the tension in the string. Since both blocks are connected by the string and moving together, their acceleration (aA and aB) is the same.
We can now express the tension T in terms of the applied force F, masses mA and mB, and the acceleration a:
T = mB*(F/mA).
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The mass of the block on the frictionless horizontal surface is 5 kg.

The mass of the block is determined by applying Newton's second law of motion:

F = ma

The given parameters are

the magnitude of the first force, F₁ = 12 N

the magnitude of the second force, F₂ = 2 N

acceleration of the block, a = 2 m/s²

So, determining the mass of the block is

F = ma

∑F = ma

F₁ - F₂ = ma

12 - 2 = 2m

10 = 2m

m = 5 kg

Thus, the mass of the block on the frictionless horizontal surface is 5 kg.

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The calculated mass is 5.5*10⁴ g.

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

K.E = 1/2 mv²

1 MJ= 10⁶ J

10⁶=1/2 m * 6*6

10⁶*2=m*36

m= 5.5 *10⁴ g

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Recall, Newton's gravitational law states that any particle of matter in the universe attracts any other particle with a force varying directly as the product of their masses and inversely as the square of the distance between them. It is expressed as

F = Gm1m2/r^2

where

F is the force in Newton

G is gravitational constant = 6.673 x 10^-11 Nm^2/kg^2

m1 and m2 are the masses in kg

r is the distance in meters

From the information given,

r = 1.5

acceleration = 2cm^2/s

Recall, 100 cm = 1m

2 cm = 2/100 = 0.02m

Thus,

acceleration = 0.02m/s^2

Since the masses are identical, then m1 = m2

Each of them is accelerating at 0.02m/s^2

Recall,

Force = mass x acceleration

Force = m1 x 0.02 = 0.02m1 N

By substituting the given values into the formula, we have

0.02m1 = (6.673 x 10^-11 x m1 x m1)/1.5^2

m1 on the left cancels out one m1 on the right. It becomes

0.02 = (6.673 x 10^-11 x m1)/1.5^2

By crossmultiplying,

0.02 x 1.5^2 = 6.673 x 10^-11 x m1

0.045 = 6.673 x 10^-11 x m1

m1 = 0.045/6.673 x 10^-11

m1 = 6.74 x 10^8 kg

The mass of each ball is 6.74 x 10^8 kg

Explanation:

Distance= speed × time

= 6 × 12 m

= 72 m

Answer:

72 meters

Explanation:

Breaking distance is directly proportional to the speed squared.

d = k v²

When v = 12 m/s, d = 32 m.

32 = k (12)²

k = 2/9

d = 2/9 v²

When v = 18 m/s:

d = 2/9 (18)²

d = 72

The magnitude of the average acceleration during landing is approximately 31.22 m/s², directed southward. It can be calculated by determining the change in velocity and dividing it by the time taken.

The initial velocity is 70.5 m/s, and the final velocity is 6.97 m/s. The time taken to achieve this change in velocity is not given directly but can be obtained by using the formula for distance travelled during uniform acceleration: distance = (initial velocity + final velocity) / 2 * time.

The distance travelled is 747 m. By rearranging the formula, we can solve for time: time = 2 * distance / (initial velocity + final velocity). Plugging in the values, we find that the time taken is approximately 21.45 seconds.

Finally, the average acceleration can be calculated by dividing the change in velocity by the time taken. The magnitude of the average acceleration is given by: magnitude = (final velocity - initial velocity) / time. Substituting the values, we get a magnitude of approximately -31.22 m/s². Since the direction of the plane's motion is considered positive, the negative sign indicates that the acceleration is directed opposite to the motion of the plane, i.e., southward.

During landing, the jetliner needs to reduce its speed from an initial velocity of 70.5 m/s to a final velocity of 6.97 m/s over a distance of 747 m. To calculate the average acceleration, we need to determine the time taken to achieve this change in velocity. Using the formula for distance traveled during uniform acceleration, we find that time = 2 * distance / (initial velocity + final velocity) = 2 * 747 m / (70.5 m/s + 6.97 m/s) ≈ 21.45 s.

With the time known, we can calculate the magnitude of the average acceleration using the formula magnitude = (final velocity - initial velocity) / time = (6.97 m/s - 70.5 m/s) / 21.45 s ≈ -31.22 m/s². The negative sign indicates that the acceleration is in the opposite direction of the plane's motion, which in this case is southward. Therefore, the magnitude of the average acceleration during landing is approximately 31.22 m/s², directed southward.

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Answer:

2hr 21 min

Explanation:

0 days 2 hours 20 minutes 0 seconds

+ 0 days 0 hours 0 minutes 60 seconds

= 0 days 2 hours 21 minutes 0 seconds