what is the minimum work needed to push a 850 kg car 840 m up along a 8.0 ∘ incline ignore friction

When comparing the motions of a baseball thrown from a height of 10 ft and a ball that is simply dropped from the same height, there are distinct differences.

The thrown baseball exhibits a combination of vertical and horizontal motion. It follows a curved path due to the initial throwing velocity and the force of gravity, resulting in a parabolic trajectory. In contrast, the dropped ball experiences only vertical motion, falling straight down toward the ground in a vertical line. While both objects are affected by gravity, the thrown baseball's additional horizontal velocity allows it to cover a longer distance and follow a more complex path compared to the vertically descending dropped the ball.

Therefore, the thrown baseball exhibits both vertical and horizontal motion, following a curved trajectory due to the combination of the initial throwing velocity and the force of gravity. The dropped ball, on the other hand, experiences only vertical motion, falling straight down toward the ground along a vertical line.

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Answer:

The not alligator side.

Obviously the middle, both sides will be shallow, so the middle will most likely  be the deepest part.

Explanation:

The magnitude of the change in momentum is therefore 6.12 kg*m/s, and the direction is downward and the floor exerts an average net force of 51 N upward on the ball during the collision.

(a) To find the magnitude and direction of the ball's change in momentum, we need to first find the initial and final momenta of the ball. The initial momentum is given by:

\(p_i = m*v_i\)

where m is the mass of the ball, and \(v_i\) is the initial velocity of the ball before it hits the floor. Substituting the given values, we get:

\(p_i\) = (0.60 kg)(6.0 m/s) = 3.6 kg*m/s

The final momentum is given by:

\(p_f = m*v_f\)

where \(v_f\) is the velocity of the ball after it rebounds from the floor. Substituting the given values, we get:

\(p_f\)= (0.60 kg)(-4.2 m/s) = -2.52 kg*m/s

Note that the negative sign indicates that the direction of the final momentum is opposite to that of the initial momentum.

The change in momentum is given by:

Δp = \(p_f - p_i\)

Substituting the calculated values, we get:

Δp = -2.52 kgm/s - 3.6 kgm/s = -6.12 kg*m/s

The magnitude of the change in momentum is therefore 6.12 kg*m/s, and the direction is downward.

(b) To find the average net force that the floor exerts on the ball, we can use the impulse-momentum theorem:

Δp = \(F_avg\) * Δt

where Δt is the time duration of the collision. Substituting the calculated value of Δp and the given value of Δt, we get:

-6.12 kg*m/s = \(F_avg\) * 0.12 s

Solving for \(F_avg\), we get:

\(F_avg\) = -6.12 kg*m/s / 0.12 s = -51 N

Note that the negative sign indicates that the direction of the average net force is opposite to that of the change in momentum, i.e., upward. Therefore, the floor exerts an average net force of 51 N upward on the ball during the collision.

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Answer:

For a closed organ pipe, the point at the closed end is always a node, 'N' while the open end is always an antinode, 'A'

Therefore, for a closed organ pipe, we only have;

NA = N↔A = First harmonics = f₁

NANA = NA↔AN↔ NA = Third harmonics, = f₃ = 3·f₁

NANANA = NA↔AN ↔ NA ↔ AN ↔ NA = f₅ = 5·f₁

It can also be shown that for a closed organ pipe, only f₇, f₉, f₁₁, ... are present

Therefore, a closed organ pipe has only odd harmonics present

For an open organ pipe, we have;

ANA = First harmonics = f₁

ANANA = ANA ↔ ANA = Second harmonics = f₂ = 2·f₁

ANANANA = ANA ↔ ANA ↔ ANA = Third harmonics = f₃ = 3·f₁

Similar relationship exist for f₄, f₅, f₆...

Therefore, for an open organ pipe, all harmonics, (multiples of the fundamental, f₁) are present

Explanation:

Answer:

V=u + at

V= final velocity

U= Initial velocity

a= acceleration

t= time taken

V= 5 + 30*2

V=5+60

V=65m/s

Explanation:

The answer is that the electrical force on 3q is three times greater than the electrical force on q.

The electrical force between two charges is not directly proportional to the product of the charges alone. The electrical force between two charges is not only determined by the product of the charges but also by the inverse square of the distance between them.

To determine the electrical force on 3q, we need to consider Coulomb's law, which states that the electrical force between two charges is given by the equation:

The force (F) between two charges can be expressed as the product of the electrostatic constant (k) and the absolute value of the product of the charges (|q1 * q2|), divided by the square of the distance (r) between the charges.

The force between two charges, denoted by F, is governed by the electrostatic constant (k), the charges of the particles (q1 and q2), and the distance separating the charges (r).

Given that the electrical force on q is f, we can write the equation as:

f = k * |q * 3q| / r²

Simplifying the equation:

f = 3 * (k * |q²| / r²)

So, the electrical force on 3q is three times the electrical force on q, assuming the distance and other factors remain the same.

In conclusion, the answer is that the electrical force on 3q is three times greater than the electrical force on q.

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Answer:

When the both the forces are acting in the same direction

Explanation:

Answer:

The resultant of these two forces will be the greatest when the two forces are in the same direction.

Explanation:

Let \(F_1\) and \(F_2\) denote these two forces. The resultant of these two force would be the vector sum \((F_1 + F_2)\).

Refer to the diagram attached. Join the head of \(F_1\) to the tail of \(F_2\). Under this construction, the vector connecting the tail of \(F_1\!\) to the head of \(F_2\!\) (the vector shown with a lighter color) would represent the resultant vector \((F_1 + F_2)\).

Consider the triangle inequality: as long as \(F_1\) and \(F_2\) (the first two sides of the triangle in the diagram) are not parallel to one another, the magnitude of the resultant vector would always be smaller than the sum of the magnitude of \(F_1\!\) and that of \(F_2\!\).

In other words: \(\| F_1 + F_2 \| < \| F_1 \| + \| F_2 \|\).

However, notice that when \(F_1\) and \(F_2\) are in the same direction, the three sides \(F_1\!\), \(F_2\!\), and \((F_1 + F_2)\) are in the same line and no longer form a triangle.

On the other hand, if \(F_1\) and \(F_2\) are opposite to one another, \(\| F_1 + F_2 \| = \| F_1 \| - \| F_2 \|\).

The magnitudes of the two forces, \(\| F_1 \| = 5\; \rm N\) and \(\| F_2 \|= 3\; \rm N\), are fixed. Hence, when the two forces are in the same direction, \(\| F_1 + F_2 \| = \| F_1 \| + \| F_2 \| =8\; \rm N\).

As long as \(F_1\) and \(F_2\) are not in the same line, the triangle inequality ensures that \(\| F_1 + F_2 \| < \| F_1 \| + \| F_2 \| =8\; \rm N\).

Hence, \(8 \rm \; N\) would be the greatest magnitude that the resultant force could achieve. That value is reached when the two forces are in the same direction.

If the silver liquid sinks to the bottom, the red liquid settles on top of the silver one, and the pink liquid stays on the surface, then the liquid with the smallest density is the pink liquid. The correct option is A.

This is because density is defined as the mass of a substance per unit volume, which means that a substance with a lower mass per unit volume will have a lower density. In this case, the pink liquid stays at the surface, which suggests that it has the lowest density compared to the other liquids.

A common way to determine the density of a liquid is to measure the mass of a certain volume of the liquid. The unit of density is typically grams per cubic centimeter (g/cm³) or kilograms per liter (kg/L).

The formula for density is: Density = Mass/Volume

Since the pink liquid is floating at the top of the bottle, it suggests that it is less dense than the other liquids in the bottle. Therefore, the pink liquid has the smallest density out of all the liquids.

Find the complete question below-

A scientist has four different liquids and pours them all into a bottle. The silver liquid sinks to the bottom, the red liquid settles on top of the silver one, and the pink liquid stays at the surface. Which liquid has the smallest density?

A. the pink liquid

B. the silver liquid

C. the red liquid

D. the water

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The effect that this will have on the amplitude of your oscillation.is b.) The amplitude of oscillation will decrease.

The amplitude of an oscillating system is the magnitude of change in the oscillating variable with each oscillation. Sound waves in air, for example, are oscillations in atmospheric pressure, and their amplitudes are proportional to the pressure change during one oscillation.

When a wave travels through a medium, it loses energy as it moves. As the distance between the wave and its source grows, it spreads out over a larger and larger area. As the wave spreads through the medium, it loses energy and its amplitude decreases.

In this case, at the point of equilibrium, the cart and the skater will have maximum kinetic energy. By dropping the same bag, the energy is reduced. The amplitude of an oscillating pendulum decreases with time because of friction due to air

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On a whim, you are trying to stand in a cart attached to a strong spring. The spring is compressed and then released, and you oscillate back and forth, trying to maintain your balance. There is a sand bag in the cart.

At the instant you pass through the equilibrium (x=0) location of the spring, you drop the sandbag onto the ground, out of the cart.

Question: If you drop the sand bag out of the cart right at the equibrium location, what effect will that have on the amplitude of your oscillation? (choose correct choice):

a.) The amplitude of oscillation will increase.

b.) The amplitude of oscillation will decrease.

c.) There will be no effect on the amplitude.

Answer:

Thrust

Explanation:

Thrust is the force that causes a car to move in the direction that it wants to.

The mass transfer rate of iodine in this flow is approximately 0.0052 kg/s.

Assuming that the concentration of iodine in the air is constant and uniform, we can use Fick's law of diffusion to calculate the mass flux:

J = -D (dC/dx)

where J is the mass flux in kg/(m²·s), D is the diffusion coefficient in m²/s, C is the concentration of iodine in kg/m³, and x is the distance in meters.

The diffusion coefficient for iodine in air at room temperature is approximately 1.16 × 10^-5 m²/s.

Assuming that the flow is fully developed and laminar, we can use the Hagen-Poiseuille equation to calculate the volumetric flow rate:

Q = (π/4)D²v

where Q is the volumetric flow rate in m³/s, D is the diameter of the pipe in meters, and v is the velocity of the flow in m/s.

Substituting the given values,

Q = (π/4)(0.03 m)²(5.25 m/s) ≈ 0.0043 m³/s

To convert the volumetric flow rate to a mass flow rate, we need to multiply by the density of the air. Assuming that the air is at room temperature and atmospheric pressure, we can use the ideal gas law to calculate the density:

ρ = P/(RT)

where ρ is the density in kg/m³, P is the pressure in Pa, R is the gas constant, and T is the temperature in Kelvin.

Substituting the values for room temperature and atmospheric pressure, we get:

ρ = (101325 Pa)/[(8.314 J/(mol·K))(293 K)] ≈ 1.20 kg/m³

Multiplying the volumetric flow rate by the density, we get:

ṁ = Qρ ≈ 0.0052 kg/s

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When lee pushes horizontally with a force of 87 n on a 20 kg mass for 13 m across a floor the amount of work lee did is 1,131 J.

Work is defined as the product of force and displacement in the direction of the force. In this case, Lee pushes horizontally with a force of 87 N on a 20 kg mass for a distance of 13 m across a floor.

To calculate the amount of work, we can use the formula:

Work = Force × Displacement × cos(θ)

where θ is the angle between the force vector and the displacement vector. In this case, the force and displacement are in the same direction, so cos(θ) is equal to 1.

Substituting the given values into the formula, we have:

Work = 87 N × 13 m × cos(0°)

Since cos(0°) is equal to 1, the equation simplifies to:

Work = 87 N × 13 m

Calculating the value, we find:

Work = 1,131 J

Therefore, Lee did 1,131 J of work.

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Answer:

can you be more specific? The answer is in the question. The bunny weighs 4.3 kg lol.

Explanation:

If you're looking for kg to lbs, then 4.3 kg is about 9.4lbs

The kind of energy stored within a chemical substance is potential energy.

Chemical substances store potential energy within their molecular bonds. This potential energy arises from the arrangement of atoms and the interactions between their electrons. In a chemical reaction, this potential energy can be released or transformed into other forms of energy such as heat, light, or kinetic energy.

The potential energy stored in chemical substances is a result of the forces holding the atoms together within molecules or ions. These forces include covalent bonds, ionic bonds, hydrogen bonds, and van der Waals forces. Breaking these bonds requires an input of energy, and when new bonds are formed, energy is released.

Chemical potential energy plays a crucial role in various natural processes and human activities. It fuels biological reactions, powers engines, generates electricity, and is harnessed in various industrial applications. Understanding and manipulating the potential energy stored in chemical substances is essential for advancements in fields such as chemistry, materials science, and energy production.

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The number of poles in the right half-plane is 1, the number of poles in the left half-plane is 2, and the number of poles on the j omega-axis is 1.

To construct the Routh table, we first need to write the characteristic equation of the transfer function T(s) in the following form:

s^5 - s^4 + 3s^3 - 3s^2 + 3s - 2 + 8/s = 0

The Routh table has the following form:

s^5 coefficient: 1 3 3

s^4 coefficient: -1 -3 8/3

s^3 coefficient: 2 2

s^2 coefficient: -2 -8/3

s^1 coefficient: 1

s^0 coefficient: -2/3

To determine the number of poles in the right half-plane, we need to count the number of sign changes in the first column of the Routh table. In this case, there is only one sign change, so there is only one pole in the right half-plane.

To determine the number of poles in the left half-plane, we need to count the number of sign changes in the first column of the Routh table, starting from the top row and moving downwards. In this case, there are two sign changes, so there are two poles in the left half-plane.

To determine the number of poles on the j omega-axis, we need to count the number of rows in the Routh table that has a zero in the first column. In this case, there is one row with a zero in the first column, so there is one pole on the j omega-axis.

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Answer:

The magnitude and direction of the centripetal acceleration will be:

\(a_c=5\) m/s²   (towards the center of the circle).

Explanation:

Given

Using the formula to determine the centripetal acceleration

\(a_c=\frac{v^2}{r}\)

\(a_c=\frac{\left(10\right)^2}{20}\)

\(\:a_c=\frac{100}{20}\)

\(a_c=5\) m/s²

As the truck is moving in a circle, therefore the direction is towards the center of the circle.

Hence, the magnitude and direction of the centripetal acceleration will be:

\(a_c=5\) m/s²   (towards the center of the circle).

Answer:

Bacteria

Explanation:

UV kills bacteria and its 8 letters

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

Both caesium-137 and iodine-131 emit ionizing radiation, which can damage living tissue and increase the risk of cancer.

Isotopes are members of the same element's family but have variable numbers of neutrons despite having the same number of protons.

Iodine-131 and caesium-137 both produce ionizing radiation, which can harm living things and raise the risk of cancer.

Due to their varied half-lives and processes of decay, each isotope's danger has changed between 1986 and 2018 despite this.

Caesium-137 degrades gradually over time since it has a longer half-life of roughly 30 years. Iodine-131, on the other hand, degrades swiftly because of its significantly lower half-life of only around 8 days.

Thus, the risk has diminished over time as a result of radioactive decay.

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The charged paint has been spread in a very thin uniform layer over the surface of a plastic sphere with a diameter of 11.0 cm, resulting in a charge of -11.0 μC. The charge of the paint indicates that there is an excess of negative charge on the sphere.

When a charge is spread over a conductive object, such as a metal sphere, it distributes itself uniformly on the surface. However, in this case, the sphere is made of plastic, which is an insulator. Due to the insulating nature of plastic, the charge will not be able to move freely across the surface.

The charge on the plastic sphere creates an electric field around it. This electric field affects other charged objects in its vicinity. For example, if a positively charged object is brought close to the negatively charged sphere, it will experience an attractive force due to the electric field.

The magnitude of the charge (-11.0 μC) does not depend on the size or diameter of the sphere. It solely represents the amount of excess negative charge on the surface.

To summarize, spreading the charged paint over the plastic sphere creates a negatively charged surface. This charge distribution creates an electric field around the sphere, influencing the behavior of other charged objects in its vicinity. The magnitude of the charge (-11.0 μC) indicates the amount of excess negative charge on the sphere.

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The phenomena addressed is pertinent to physics, especially the concept of electrostatics. They reiterate how excess negative charge quickly moves to the outer surface of spheres due to electrostatic repulsion, creating an electric field outside similar to that of a central point charge. This is crucial for achieving a uniform electric potential over the sphere surface.

The subject of your question pertains to physics, specifically, electrostatics. Here, a plastic sphere is coated with a thin layer of charged paint, with the given charge being -11.0 μC. You are dealing with the phenomena of distribution of charge on the surface of objects. When an object is charged, the excess charge tends to move to the surface of the object due to electrostatic repulsion.

The radius of the given sphere would be half the diameter, which equates to 5.5 cm or 0.055 m. Now, to summarize the behavior of the sphere: the electric field inside a charged sphere is zero, and the electric field outside can be considered the same as the electric field of a point charge located at the center of the sphere. Meanwhile, the charge on the sphere is at the surface.

The fact that the charge is uniformly distributed on the sphere's surface and does not remain inside can be linked to the concept of electric potential, which is the same at every point on the surface of a sphere. This phenomenon occurs because the excess charge quickly moves to the outer surface due to the repelling effect amongst themselves.

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Use Hooke's law to find the spring constant, k :

F = kx   ⇒   2.5 N = k (0.040 m)   ⇒   k = 62.5 N/m

Then use the law again to find the force needed to extend the spring by 12 cm = 0.12 m :

F = (62.5 N/m) (0.12 m) = 7.5 N

Answer:

A) so the conditions for the expirament don’t affect the outcome

b) to make sure the results are conclusive and accurate

Explanation:

In the northern hemisphere, gyres rotate in the clockwise direction.

Therefore, the statement on question number 4 is false.

The film sensor and the long axis of the tooth must be aligned perpendicular to the central ray of the x-ray beam when using the paralleling approach.

To find the answer, we need to know above the paralleling technique in the dental x-ray.

Thus, we can conclude that, the film sensor and the long axis of the tooth must be aligned perpendicular to the central ray of the x-ray beam when using the paralleling approach.

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Answer:

The acceleration of freely falling bodies due the force of attraction of the other body is called Acceleration due to gravity. It is a constant quantity for a given attracting body at a given place. Like for earth on or near its surface, the average value of acceleration due to gravity is 9.8 m/s2.

Answer: The acceleration de to gravity on eon the moon it has earth has a pull and on the moon it is mass        <3

The friction between a vehicle's brakes and the wheel is worked on when a force is applied to the brakes. The vehicle's kinetic energy is decreased, which slows it down and raises the temperature of the brakes.

The electric motor starts functioning as a generator as soon as your foot leaves the accelerator pedal. It begins to recharge the battery by utilizing the kinetic energy that is released while the automobile is going ahead. Depending on the setting chosen, this results in a stronger than typical slowdown of the vehicle.

Braking has to adhere to the energy conservation concept, just like any other system. Energy can only be changed from one form to another; it cannot be generated or destroyed.

Chemical energy (fuel, air, and spark plugs) is converted inside the engine to mechanical energy known as kinetic energy.

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Answer: .28 meters

Explanation:

The correct position that the fuse should be to ensure safety from the image is b.

A fuse is a type of electrical safety device used to guard against excessive current flow in electrical circuits. When there is a surge or overload of power, its main purpose is to interrupt the electrical current and break the circuit.

The fuse wire or element inside the fuse warms up due to resistance when the current flowing through a circuit exceeds the rated limit of the fuse. This opens the circuit and destroys the electrical connection by causing the fuse wire to melt or burst. The fuse does this to stop an excessive amount of current from passing through the circuit, which may cause overheating, harm to electrical equipment, or even provide a fire risk.

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An effective display of trend and magnitude is achieved by using a combination of a C)heat map and sparklines.

While the standard chart is designed to expose as a great deal fact as possible and is set off from the float of text, sparklines are meant to be succinct, memorable, and located in which they are mentioned.

A heatmap (or warmness map) is a graphical illustration of facts wherein values are depicted through color. They are crucial in detecting what does or does not paintings on a website or product page.

A warmth map visualization is a mixture of nested, colored rectangles, each representing an attribute detail. Heat Maps are regularly used inside the monetary services industry to review the reputation of a portfolio.

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Answer:

C.

Explanation:

The Sumerians were very inventive people. It is believed that they invented the sailboat, the chariot, the wheel, the plow, and metallurgy.

Answer: p = mv

Explanation:  momentum(p) is equal to mass(m) and velocity(v).