what is the lateral area of the cone? 10 yd and 12.1 yd

The value of x to the nearest hundredth of a foot as required to be determined in the task content is; Choice A; 7.51.

It follows from the task content that the value of x as indicated is to be determined.

As the given triangle is a right triangle whose hypothenuse and side x is opposite the angle whose measure is 28°.

It follows from trigonometric ratios that;

sin 28° = x / 16

x = 16 sin 28°

x = 7.51.

Ultimately, the value of x to the nearest hundredth is; Choice A; 7.51.

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Step-by-step explanation:

set notebooks as x, set pens as y

1. 5x + 7y = 11

2. 4x + 2y = 7

1.  times by 2

10x + 14y = 22

2. times by 7

28x + 14y = 49

2. minus 1.

18x = 27

x = 1.5

sub 1.5 into 2.

4(1.5) +2y = 7

6+2y = 7

2y = 1

y = 0.5

Therefore, x = 1.5, y = 0.5

The range from the given table is 9, the population variance is 18.56, and the population standard deviation is 4.30.

Given the value:

xi         10     20      11        17       15     8     7     16       19    15     Total = 138

xi^2    100   400    121   289    225   64   49   256   361   225  Total = 2090

From the above, we get

n =10, ∑xi = 138, ∑xi^2 = 2090

(a) For the range:

Here, the smallest value = 10, and largest value = 19

Therefore, Range = Largest value - Smallest value

Range = 19 - 10 = 9

(b) For population variance:

For mean:

Mean of x = ∑xi/n = 138/10 = 13.8

V (X) = ∑(xi^2)/n - Mean of x^2

= 2090/10 - 13.8^2

= 209 - 190.44

V (X) = 18.56

(c) For population standard deviation:

\(SD (X) = \sqrt{VAR(X)}\)

SD(X) = \(\sqrt{18.56}\)

SD(X) = 4.30

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Step-by-step explanation:

The range from the given table is 9, the population variance is 18.56, and the population standard deviation is 4.30.

Given the value:

xi 10 20 11 17 15 8 7 16 19 15 Total = 138

xi^2 100 400 121 289 225 64 49 256 361 225 Total = 2090

From the above, we get

n =10, ∑xi = 138, ∑xi^2 = 2090

(a) For the range:

Here, the smallest value = 10, and largest value = 19

Therefore, Range = Largest value - Smallest value

Range = 19 - 10 = 9

(b) For population variance:

For mean:

Mean of x = ∑xi/n = 138/10 = 13.8

V (X) = ∑(xi^2)/n - Mean of x^2

= 2090/10 - 13.8^2

= 209 - 190.44

V (X) = 18.56

(c) For population standard deviation:

SD (X) = \sqrt{VAR(X)}SD(X)=

VAR(X)

SD(X) = \sqrt{18.56}

18.56

SD(X) = 4.30

The amount of money she will have to pay for booking of the holidays would be = £220

The total amount of money that will cost Merrisa for booking of holidays = £660

The fraction of the total cost that she needs to deposit = 1/3

Therefore, the actual amount that she needs to deposit = 1/3 of £660

= 1/3× 660

= £220

Therefore, in conclusion, Merrisa would have to pay a total of £220 for booking of the holidays. This total amount is ⅓ of total cost of booking.

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Answer:

All of the above, except for 'What is the name of the doctor at Healthy Kids Pediatrics?'

Step-by-step explanation:

What is your favorite television show that you watched this week? - If we define your favourite show as that which you watched most, you could gather data here on time spent watching each show to determine the answer

What store in the mall are you most likely to purchase apparel from? - Similar to before, data on your previous trips to the mall could be gathered to determine which stores you have been to the most often, and using this make a prediction of the most likely you are to purchase apparel from

How many students at your school have a skateboard? - Here data could be gathered by asking which students have a skateboard and which do not

What is the name of the doctor at Healthy Kids Pediatrics? - This question only has an answer, and it would be the name of the doctor

Answer:

How many students at your school have a skateboard?

Step-by-step explanation:

Since it is asking multiple people it can result in data. It can't result in data if it asks just one question to someone

The probability that either event will occur is P ( C ) = 0.89

Given data ,

Let the probability that either event will occur  be P ( C )

P ( A ) = 20/36

P ( B ) = 12/36

where P ( A or B ) = P ( C )

P ( C ) = P ( A ) + P ( B )

P ( C ) = 32/36

P ( C ) = 0.88888

Hence , the probability is P ( C ) = 0.89

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Point C is located at (6,3).

Point Locations:

A: (1, 5)

B: (1, 3)

C: (6, 3)

D: (6, 5)

Answer:

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

^

Answer: 77.28

Step-by-step explanation:

To solve this problem, we can use the formula:

P(G) = P(G ∩ NG') + P(G ∩ NG)

where P(G) is the probability that a resident has green eyes, P(G ∩ NG') is the probability that a resident has green eyes and does not wear glasses, and P(G ∩ NG) is the probability that a resident has green eyes and wears glasses. NG' represents the complement of wearing glasses, i.e. not wearing glasses.

We are given that 32% of the residents wear glasses, so the probability of not wearing glasses (NG) is:

NG = 1 - 0.32 = 0.68

We are also given that 11% have green eyes and wear glasses:

P(G ∩ NG) = 0.11

We can use this information to find the probability of having green eyes and not wearing glasses:

P(G ∩ NG') = P(G) - P(G ∩ NG) = 0.11 - P(G ∩ NG')

We are also given that 45% of the residents have neither green eyes nor wear glasses:

P(NG' ∩ NG) = 0.45

We can use this information to find the probability of not having green eyes and wearing glasses:

P(NG ∩ G') = P(G' ∩ NG) = 0.45

We can now set up a system of equations to solve for P(G) and P(G ∩ NG'):

P(G ∩ NG') = P(G) - P(G ∩ NG)

P(G' ∩ NG) = P(NG) - P(NG' ∩ NG)

Substituting the values we have:

P(G ∩ NG') = P(G) - 0.11

0.45 = 0.68P(G' ∩ NG)

Solving for P(G' ∩ NG), we get:

P(G' ∩ NG) = 0.45/0.68 = 0.6628

Substituting this value into the first equation, we get:

P(G ∩ NG') = P(G) - 0.11

P(G) = P(G ∩ NG') + 0.11

P(G) = 0.6628 + 0.11

P(G) = 0.7728

Therefore, the probability that a randomly selected resident of Toronto has green eyes is approximately 0.7728 or 77.28%.

After answering the presented question, standard deviation t Lower bound = X - \((t * (s/\sqrt(n))) = 1271.89 - (1.860 * (34.753/\sqrt(9))) = 1238.94\)

A statistic that expresses the variability or variation of a bunch of values is the standard deviation. A high standard deviation indicates that the values are more distributed, whereas a low standard deviation indicates that the numbers are closer to the set mean. The standard deviation is a measure of how far the data are from the mean (or ). When the standard deviation is small, the data tends to cluster around the mean; when it is great, the data is more spread. The standard deviation represents the average variability of the data collection. It displays the average deviation from the mean of each score.

Next, we need to find the t-value for a 90% confidence interval with 8 degrees of freedom (n-1):

t = t(0.05, 8) = 1.860

Now we can calculate the lower and upper bounds of the confidence interval:

Lower bound = X - \((t * (s/\sqrt(n))) = 1271.89 - (1.860 * (34.753/\sqrt(9))) = 1238.94\)

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Answer:

Doc Tour

Step-by-step explanation:

Answer:

Doc-Tour

Step-by-step explanation:

Answer:

please complete your question. where is figure.

Answer:

Option (1).

Step-by-step explanation:

Amount of water hold by both the pitchers (Large + small) = 12 cups

Let the small pitcher holds the water = S cups

If the water hold by the large pitcher is twice the size of the small pitcher, then the amount of water hold by large pitcher = 2S

Total amount water hold by both = S + 2S

Equation for this situation will be,

S + 2S = 12

Therefore, Option (1) will be the answer.

a. In interval notation, Increasing intervals: (12pm, 1pm) U (1pm, 2pm) U (2pm, 3pm). Decreasing intervals: (8am, 9am) U (11am, 12pm). Constant intervals: (9am, 10am) U (10am, 11am)

b. The increase in cost between 12 noon and 3 pm is $2.

c. Yellow Cab has a lower price per 1km than Swift ride at (8am, 9am) (9am, 10am) (2pm 3pm)

Interval notation is used to represent continuous intervals of numbers or values, like ranges on a number line.

The graph shows that from 8-9am, and 11-12pm, the cost from Swift Ride decreases.

We can represent it as (8am, 9am) U (11am, 12pm).

It increases at these times (12pm, 1pm) U (1pm, 2pm) U (2pm, 3pm).

And stays constant at : (9am, 10am) U (10am, 11am)

We simply deduct the 12pm's cost from 3pm's cost.

So, we have

Cost increase = $3.5 - $1.5

Evaluate the difference

Cost increase = $2

Hence, the cost increase is $2

When you plot the points provided for Yellow cab, you'll notice that Yellow Cab has a lower price per 1km than Swift ride at (8am, 9am) (9am, 10am) (2pm 3pm)

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There will be 12 slices of pizza left over, which can be expressed as 3/2 or 1 1/2 slices in fraction form.

To find out how much pizza will be left over, we need to calculate the total number of slices available and subtract the number of slices consumed by the players.

Given that there are six pizzas and each pizza has eight slices, the total number of slices available is 6 pizzas * 8 slices/pizza = 48 slices.

Since there are 36 players on the team, and each player has one slice, the total number of slices consumed is 36 slices.

To determine the remaining slices, we subtract the consumed slices from the total available slices: 48 slices - 36 slices = 12 slices.

Therefore, there will be 12 slices of pizza left over.

To express this as a fraction, we can write it as 12/1, which simplifies to 12. This means there will be 12 whole slices of pizza left over.

If you would like to express it as a fraction in its simplest form, you can write it as 12/8. By dividing both the numerator and denominator by their greatest common divisor, which is 4, we get 3/2. So, in fraction form, there will be 3/2 or 1 1/2 slices of pizza left over.

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Answer:

The rate of change is $21.5 per hour

Step-by-step explanation:

The rate of change can be found using the formula: (y^2 - y^1)/(x^2 - x^1).

(the exponents refer to which number. Y^2 refers to the y-axis number of the second number given)

So fill in the blanks:

(430 - 215)/(20– 10)

Now do the math:

430 - 215 = 215, 20 - 10 = 10

(215)/10

Divide:

215/10 = 21.5

Therefore, 21.5 is the rate of change!

your question is incorrect dear!

please tell the figure

if its triangle then either of the angle is wrong

Answer:

hello

Step-by-step explanation:

what is the shape thing so i at least have something to work with

Answer:

27

Step-by-step explanation:

I done the test

Answer:

27 ;)

Step-by-step explanation:

Answer:

The number of Zeros (roots) is

-3 and -10

Step-by-step explanation:

x^2 + 19x = 6x - 30

The negations of the given statements with the application of De Morgan's law and/or conditional law.

a) ∃x (¬P(x) ∨ ¬R(x))

De Morgan's law:

∃y ∀z(¬P(y) ∧ ¬Q(z))

b) ∃y ∀z(¬P(y) ∧ ¬Q(z))

The double negation:

∃y ¬∃z(P(y) ∨ Q(z))

c) ¬∃x (P(x) ∨ (∀z (¬R(z)) → (∀z ¬Q(z))))

The conditional law:

¬∃x (P(x) ∨ (∀z (¬R(z)) → (∀z ¬Q(z))))

Let's form the negation of the given statements and apply De Morgan's law and/or conditional law, when applicable:

a) ∀x (P(x) ∧ R(x))

The negation of this statement is:

∃x ¬(P(x) ∧ R(x))

Now let's apply De Morgan's law:

∃x (¬P(x) ∨ ¬R(x))

b) ∀y∃z(¬P(y) → Q(z))

The negation of this statement is:

∃y ¬∃z(¬P(y) → Q(z))

Using the conditional law, we can rewrite the negation as:

∃y ¬∃z(¬¬P(y) ∨ Q(z))

c) ∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))

The negation of this statement is:

¬∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))

Using the conditional law, we can rewrite the negation as:

¬∃x (P(x) ∨ (∀z (R(z) ∨ ¬Q(z))))

Applying De Morgan's law:

¬∃x (P(x) ∨ (∀z ¬(¬R(z) ∧ Q(z))))

Simplifying the double negation:

¬∃x (P(x) ∨ (∀z ¬(R(z) ∧ Q(z))))

Using De Morgan's law again:

¬∃x (P(x) ∨ (∀z (¬R(z) ∨ ¬Q(z))))

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The equation 2-3cos(x) = 5+3cos(x) has no solution in the range of 0° to 180°.

1. Start with the given equation: 2-3cos(x) = 5+3cos(x).

2. Subtract 3cos(x) from both sides to isolate the constant term: 2-3cos(x) - 3cos(x) = 5.

3. Combine like terms: 2-6cos(x) = 5.

4. Subtract 2 from both sides: -6cos(x) = 3.

5. Divide both sides by -6: cos(x) = -1/2.

6. To find the solutions for cos(x) = -1/2 in the range of 0° to 180°, we need to determine the angles where cos(x) equals -1/2.

7. These angles are 120° and 240°, as cos(120°) = cos(240°) = -1/2.

8. However, the given equation states that 2-3cos(x) equals 5+3cos(x), which is not satisfied by cos(x) = -1/2.

9. Therefore, the equation 2-3cos(x) = 5+3cos(x) has no solution in the range of 0° to 180°.

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a) The best location is the Baptist Church, with a weighted score of 69.5.

b) The best location will be the Baptist Church, with a weighted score of 70.5.

The best location is obtained considering the location that has the highest score.

The scores are computed using the weighted mean, which is the sum of each score by it's weight.

The score for Maitland is given as follows:

Maitland = 0.30 x 60 + 0.25 x 40 + 0.20 x 50 + 0.15 x 50 + 0.10 x 80 = 53.5.

The score for Baptist Church is given as follows:

Baptist Church = 0.30 x 70 + 0.25 x 80 + 0.20 x 80 + 0.15 x 70 + 0.1 x 20 = 69.5. (highest score).

The score for Northside Mall is given as follows:

Northside Mall = 0.30 x 80 + 0.25 x 30 + 0.20 x 60 + 0.15 x 40 + 0.10 x 90 = 58.5.

Then for item b, the weights for Space and Traffic Density are reversed, and thus the scores are given as follows:

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Answer: (6,-6)

Step-by-step explanation:

To find the coordinates of point B, we can use the midpoint formula:

Midpoint formula: The midpoint M of a line segment with endpoints (x1, y1) and (x2, y2) is given by:

M = ((x1+x2)/2, (y1+y2)/2)

Here, we know that the midpoint M is (4, -2), and one endpoint A is (2, 2). Let B be the other endpoint, so we can use the midpoint formula to find B:

4 = (2+x2)/2 --> 8 = 2+x2 --> x2 = 6

-2 = (2+y2)/2 --> -4 = 2+y2 --> y2 = -6

Therefore, point B has coordinates (6, -6).

As for the second question, without a graph or information about the equation of line t and point P, it is not possible to determine which points lie on the line passing through P and perpendicular to t.

Answer:

\(q=45\)

Step-by-step explanation:

Notice that \((q+2)^{\circ}\) and \((3q-2)^{\circ}\) form a linear pair, that is, they sum to \(180^{\circ}\) as follows:

\((q+2)^{\circ}+(3q-2)^{\circ}=180^{\circ}\\(q+2+3q-2)^{\circ}=180^{\circ}\\(4q)^{\circ}=180^{\circ}\\4q=180\\q=\frac{180}{4}\\q=45\)