What is the importance of Transpiration? (EXPLAIN)

Answer:

tu heaven es una de esas 3personas de 3363 horas 66 horas y te la tengo a ver si no te

Answer:

Radio waves are used by radars to determine the distance and speed of moving objects.

There are two types of cell division: mitosis and meiosis. Most of the time when people refer to “cell division,” they mean mitosis, the process of making new body cells. Meiosis is the type of cell division that creates egg and sperm cells. Mitosis is a fundamental process for life.

The process by which a parent cell divides into two daughter cells is known as cell division. Cell expansion and chromosome replication come before cell division, which usually happens as part of a prolonged cell cycle. Meiosis produces haploid gametes for sexual reproduction by reducing the number of chromosomes from two of each kind in the diploid parent cell to one of each kind in the daughter cells. Cell division occurs through the process of mitosis, which results in daughter cells that are genetically identical to their parent cells. In cell biology, the cell cycle includes the process of mitosis, in which duplicated chromosomes are split into two new nuclei.

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Answer:

B. are identical to the chromosomes of the other daughter

Explanation:

placozoans eat through phagocytosis

the process of endocytosis, which is a process by which necessary substances are brought into the cell.

The term was coined by  De Duve in 1963, endocytosis can be up two types such as pinocytosis and phagocytosis.

Pinocytosis is referred as "cell drinking," while phagocytosis is known as "cell eating." These two processes are a form of active transport.

Phagocytosis is defined as a process of ingestion of bacteria or other infectious agent by phagocytosis.

In human beings, the major and phagocytes are White Blood cells. These cells are specialized in attacking infectious agents that enters the body and kill them by engulfing them.

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Derived characters are those that emerge at some point during evolution, and are expressed by all the subsequent groups. Derived characters shared by protist, plants, fungi, and animals are: eukaryotic organisms, autotroph or heterotroph, cell membrane, nuclei with DNA, mitochondria.

The derived character is any trait that a group passes to the descendants.

Through evolution, the characters change, and new changes are added.

When referring to a derived character, we mean that all the subsequent species in the cladogram, after the character emerged, carry the trait.

In the exposed example, we need to describe characters expressed by protists, plants, fungi, and animals.

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The two atria are thin-walled chambers that receive blood from the veins. The two ventricles are thick-walled chambers that forcefully pump blood out of the heart. The right atrium receives deoxygenated blood from systemic veins; the left atrium receives oxygenated blood from the pulmonary veins.

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Gibberellic acid (GA) plays a crucial role in a-amylase production and germination. GA stimulates the synthesis and release of a-amylase enzymes, which hydrolyze starch into sugars during germination. Experimental studies have demonstrated that the application of GA accelerates a-amylase production and enhances germination in various plant species

In terms of a-amylase production, GA stimulates the synthesis and release of this enzyme. a-amylase is responsible for breaking down starch into simpler sugars, which are then utilized by the plant for growth and development.

Studies have shown that applying GA to plant tissues or seeds results in an increased production of a-amylase, facilitating the conversion of stored starch into energy-rich sugars.

Regarding germination, GA is involved in breaking seed dormancy and promoting the growth of the embryonic plant.

It stimulates the production of hydrolytic enzymes like a-amylase, which enable the hydrolysis of starch reserves in the endosperm, providing the energy needed for germination and seedling establishment.

Additionally, GA helps in cell elongation and division, promoting the growth of the embryo and the emergence of the radicle.

Evidence for GA's role in both processes includes studies where the exogenous application of GA to seeds or plant tissues has been shown to enhance a-amylase production and promote germination.

Conversely, inhibiting GA synthesis or action results in reduced a-amylase activity and impaired germination. These findings support the critical involvement of GA in both a-amylase production and germination processes in plants.

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Populations in Hardy-Weinberg equilibrium express the same allelic and genotypic frequencies through generations. Number of individuals expressing each phenotype: 63 sheep S^AS^A, 84 sheep S^AS^B, 28 sheep S^BS^B.

The Hardy-Weinberg equilibrium theory states that allelic and genotypic frequencies in populations that is in equilibrium remain the same through generations. No evolutive forces are acting on these populations, so no evolution occurs.

Assuming a diallelic gene,

Allelic frequencies

Genotypic frequencies

The addition of the allelic frequencies equals 1

p + q = 1.

The sum of genotypic frequencies equals 1

p² + 2pq + q² = 1

In the exposed example,

Alleles          Frequencies

Genotypes

We need to get the number of animals expressing each genotype and phenotype. To do it, we just need to use allelic frequencies and calculate  genotypic frequencies (p², 2pq, and q²), and then multiply these values by the total number of animals (N = 175).

Genotypic and Phenotypic frequencies

F(S^AS^A) = p² = 0.6² = 0.36

F(S^AS^B) = 2pq = 2 x 0.6 x 0.4 = 0.48

F(S^BS^B) = q² = 0.4² = 0.16

Number of individuals expressing each phenotype

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Complete question

A single gene with two alleles control variation in haemoglobin type in sheep. There are three different phenotypes corresponding to genotypes

In a flock of 175 sheep the frequency of allele S^A was found to be 0.6 and frequency of allele S^B WAS found to be 0.4.

Using the hardy weinberg equation calculate the number of sheep with each phenotypes in the flock show your working

When the carbohydrate cellobiose is digested into two glucose monosaccharide sugars (by cellulase in certain fungal species), the resulting glucose monomers are properly defined as the products

The correct answer is option E.

When the carbohydrate cellobiose is digested into two glucose monosaccharide sugars by cellulase in certain fungal species, the resulting glucose monomers are properly defined as the products.

In a chemical reaction, reactants are the starting materials or substances that undergo a change, while products are the resulting substances formed after the reaction. In this case, cellobiose is the substrate, which is the molecule that undergoes the enzymatic reaction. Cellulase is the enzyme responsible for catalyzing the digestion of cellobiose into glucose monomers.

The enzyme cellulase acts as a catalyst in the reaction, facilitating the breakdown of cellobiose into glucose. Catalysts are substances that increase the rate of a chemical reaction without being consumed or permanently changed themselves. However, in the context of the given question, the glucose monomers produced are the final result or product of the enzymatic digestion process.

Therefore, in the digestion of cellobiose, the resulting glucose monomers are correctly identified as the products (option E).

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The organism that is most likely to carry out the process shown in the diagram is Calla lily (option D).

Cellular respiration is the process by which cells obtain chemical energy by the consumption of oxygen and the release of carbon dioxide.

According to this question, a diagrammatic representation of cellular respiration is given in the above chart. Based on the chart, chloroplast is included to release oxygen gas needed for respiration.

Only green plants possess chloroplast used for photosynthesis, hence, Cana lily is the most likely organism to carry out the above process.

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Lionfish co-promotes the eradication of invasive and invasive lionfish through lionfish hunter education outreach and direct hunting campaigns.

Invasive lionfish are a threat to native fish and the environment in the Atlantic waters of the United States. Invasive species can lead to the extinction of native flora and fauna, reduce biodiversity, compete with native species for limited resources, and alter habitats.

Participating in the Lionfish Derby helps reduce populations in certain areas and dive sites. Ordering something like a lionfish on your menu when you go out for lunch or dinner can also be very helpful as it creates an incentive and economic reason for more divers to catch more of this particular species. Lionfish colonies are edible and considered a delicacy so control methods should include harvesting lionfish colonies.

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The two steps of the Krebs cycle are:

1. The conversion of acetyl-CoA, a molecule produced during glycolysis, into citric acid, a complex molecule that contains three carboxyl groups. This step is catalyzed by the enzyme citrate synthase.

2. The breakdown of citric acid into smaller molecules, releasing energy in the form of ATP and generating byproducts such as carbon dioxide and water. This step involves a series of reactions that are catalyzed by a series of enzymes, including isocitrate dehydrogenase, alpha-ketoglutarate dehydrogenase, succinyl-CoA synthetase, and others. These reactions also produce NADH and FADH2, which are used in the electron transport chain to generate additional ATP.

Answer:

Both are used for breathing.

Explanation:

When rib muscles and the diaphragm contract they increase the volume of the chest cavity, increasing the air pressure outside the body, causing air to rush into the lungs to fill the vacuum created by the increase in volume.

Answer:

the cells forming and dividing into more

Explanation:

Body tissues grow by increasing the number of cells that make them up. Cells in many tissues in the body divide and grow very quickly between conception and adulthood.

Answer:cells forming and dividing into more cells

Explanation:

Answer:

Cultivator.

Explanation:

Instruments such as cultivator replaced the animal drawn farm implements​ because these instruments works quickly and more efficiently. This cultivator has long teeth which soften the soil for better root penetration and aeration of the soil. This instrument works with high speed and finished its work in hours not days which make it more preferable in agriculture than animals.

Answer:

The surface layer of the ocean is known as the epipelagic zone and extends from the surface to 200 meters (656 feet). It is also known as the sunlight zone because this is where most of the visible light exists. With the light come heat.

Grooves created from glacier movement travel in opposite directions on each continent. This is the proof or evidence of the theory of plate tectonics.

It is the solid and massive irregular shaped slab of  solid rock, generally composed of continental and oceanic lithosphere.

Glacial grooves on the rocks shows that the various proofs for moving glaciers towards the Atlantic ocean and from the Atlantic oceans onto the South America.

When oceanic or continental plates slide past each other in opposite directions or even in the same direction but with a different speeds and at that time a transform boundary is formed.

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Answer:

Explanation:

A higher percentage of compact bone portion typically results in a heavier bone, as compact bone is denser than spongy bone and contains more mineralized tissue.The marrow from a chicken bone is usually soft and gelatinous, with a slightly yellowish-white color.The marrow from a beef bone is typically firmer and more solid than chicken marrow, with a reddish-brown color.I apologize, but there seems to be a question missing from the sequence.The denser marrow was not specified, so I cannot answer this question.The overall density of the bone would be impacted by the density of the marrow, as well as the density of the compact and spongy bone portions.The density of the bone is related to the activities and environment of each animal. For example, birds that fly and need to be lightweight tend to have bones with a higher percentage of air spaces and spongy bone, which reduces weight. Cattle, on the other hand, have denser bones to support their larger bodies and movements on land.

The two pieces of evidence that support the theory of the expanding universe are the red shift of light from distant stars and the existence of cosmic background radiation.

The correct answer is option B.

1. Red shift of light from distant stars: The observation of redshift in the light coming from distant galaxies provides evidence for the expansion of the universe. Redshift occurs when the light waves from an object moving away from an observer are stretched, causing a shift towards longer wavelengths. This phenomenon is consistent with the Doppler effect, where the wavelength of light appears to stretch as the source moves away. The redshift of light from distant stars indicates that galaxies are moving away from us and from each other, supporting the idea that the universe is expanding.

2. Existence of cosmic background radiation: The discovery of cosmic background radiation further supports the theory of the expanding universe. Cosmic background radiation is a faint, uniform microwave radiation that permeates the entire universe. It is believed to be residual radiation from the Big Bang, the initial event that is thought to have initiated the expansion of the universe. The presence of cosmic background radiation provides strong evidence for the hot, dense early stages of the universe and its subsequent expansion.

Based on the information provided in the diagram, it is not possible to determine the identity or nature of the celestial objects labeled X. The diagram only represents the expansion of the universe over time and does not provide specific details about individual celestial objects.

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Answer:

According to a mind-bending new theory, a black hole is actually a tunnel between universes—a type of wormhole. The matter the black hole attracts doesn't collapse into a single point, as has been predicted, but rather gushes out a "white hole" at the other end of the black one, the theory goes.

In the cloning lab, one processed two tubes, one with the plasmid (+pGLO) and one without the plasmid (-pGLO), and the (+pGLO) on LB/amp served as the experimental plate where the gene glows ,so the option c is correct.

The +pGLO tube contains bacteria transformed with the pGLO plasmid that have a gene for antibiotic resistance and a gene for fluorescence, so the bacteria on the LB/amp/ara plate serve as a control, and based on the control, sensitive and resistant bacteria are differentiated.

Hence, in  the cloning lab, one processed two tubes, one with the plasmid (+pGLO) and one without the plasmid (-pGLO), and the (+pGLO) on LB/amp served as the experimental plate where the gene glows ,so the option c is correct.

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The question is incomplete, the complete question is the below,

For the cloning lab, you processed two tubes, one with the plasmid (+pGLO), one without the plasmid (-pGLO). The solutions were then plated on the LB, LB/amp and LB/amp/ara plates. The (+pGLO) on LB/amp/ara served as a(an) ________________________

Group of answer choices

a) control to see if transformation worked and bacteria are now antibiotic-resistant

b) control to see if bacteria survived the process of transformation

c) the experimental plate where the gene glows

d) the experimental plate where the gene of interest is expressed

Corn kernels' color and shape are coded by diallelic genes expressing complete dominance. The genotype of individuals carrying Yellow kernels and a smooth shape phenotype can be either ppSS or ppSs.

Complete dominance refers to the inheritance pattern in which the dominant allele of a gene completely masks the expression of the recessive allele.

The presence of at least one dominant allele is enough to express the dominant trait. This becomes evident in heterozygous individuals.

In the exposed example, two traits are involved. One of them is the kernel color and the other one is the kernel shape.

Genes coding for each of the traits express complete dominance,

If a corn plant had Yellow kernels and a smooth seed shape, it is expressing the recessive phenotype for color (pp) and the dominant phenotype for shape (SS or Ss), so the possible genotypes are,

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Complete question

In corn, purple kernels are dominant to yellow kernels, and smooth kernels are dominant to wrinkled kernels.

The following letters were selected to represent each of the possible alleles:

Color

Kernel shape

If a corn plant had Yellow kernels and a smooth seed shape, what could it's possible genotype be? Choose all that apply.

Group of answer choices

Answer:

the answer has to be C

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Peter and Rosemary Grant spent years on the Galápagos Islands studying changes in finch populations.

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Answer:

East

Explanation:

East is the correct answer...

Answer:

chemotropism

Explanation:

There are three hypotheses that explain the movement of water up a plant against gravity. These hypotheses are not mutually exclusive, and each contribute to movement of water in a plant, but only one can explain the height of tall trees: Root pressure pushes water up; Capillary action draws water up within the xylem

When recording euthanasia be sure to note the date, animal identification information, confirmed or tentative diagnosis, euthanasia method and final disposition.

The euthanasia record is an important document for veterinary practices and should be maintained according to state and federal regulations and the policies and procedures of your practice.

When recording euthanasia, be sure to note the date, animal identification information, confirmed or tentative diagnosis, euthanasia method, and final disposition.

Another important thing to note is that euthanasia should be considered only when alternative management options are not available or have been exhausted, when quality of life is poor, and when euthanasia is in the best interest of the animal.

All reasonable steps should be taken to minimize pain and distress during the process.

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Answer:

One

Explanation:

Sodium (Na) has one valence electron so it gets one dot.

Answer:

Explanation:

Alright, buckle up, since this isn't your average "the answer is C" explanation. Sorry beforehand for this upcoming essay. To make this easier, I'll give out the answers to start and then leave a "Why?" portion in case you want an in-depth explanation. I recommend getting the answers first since I can tell you're in a hurry, but if you get the chance look over a thing or two I said. Now:

To start, the 4 genotypes for the Dark Gray Rabbit are DD, Dd\(^{ch}\), Dd\(^h\), and Dd.

Why? Well, we know Dark Gray is dominant to all other alleles, so a Dark Gray allele with any other allele will produce a Dark Gray Rabbit.

The same concept above applies to the other rabbits:

The Chinchilla rabbit is d\(^{ch}\)d\(^{ch}\), d\(^{ch}\)d\(^h\), and d\(^{ch}\)d.

The Himalayan rabbit is d\(^h\)d\(^h\) and d\(^h\)d.

The Albino rabbit is dd.

Part 2:

Chinchilla Rabbit

Why? Because you have 2 Chinchilla alleles, and since they don't dominate and aren't dominated by any other allele, the rabbit will be a Chinchilla Rabbit.

Dark Gray Rabbit

Why? Same rule of dominance, and plus, it was one of the phenotypes listed in the first question.

For the table, look at the help image.

And finally, for the plan, the first set of rabbits with have a 50% chance of producing a dd\(^h\) rabbit, which is a Himalayan rabbit. Then, breeding two of these will ALWAYS give you a Himalayan rabbit.

Why? Because the only alleles are d and d\(^h\), and since d\(^h\) is always dominant of d, there will never be a case where that rabbit is albino (thus always Himalayan)

Hope you got it all down, and glad I could be of any service.