Answer:
(9,-3)
Step-by-step explanation:
Create ABC by drawing AC. AC represents the foreman’s line of sight to the top of the landfill. What is m
Where the above is given, the required angle m∠BAC = 45°.
In triangle ABC. AC represents the foreman’s line of sight to the top of the landfill. Landfill height is BC
What is triangle?The triangle is geometric shape which includes 3 sides and sum of interior angle should not grater than 180°
According to conditions angle b = 90°
The sum of angles of a triangle= 180°
That is a + b + c = 180
Therefore, c = a
a = (180 - b)/2
= (180 - 90) / 2
= 90 / 2
= 45°
Hence, the required angle m∠BAC = 45°
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Question 1 Create Triangle ABC by drawing AC. Segment AC represents the foreman’s line of sight to the top of the landfill. What is Angle m BAC?
Three figures exist such that abcd ≅ ghij and bcda ≅ rstu. if gh = 6 cm, hi = 8 cm, ij = 10 cm, and gj = 9 cm, what is ts? 6 cm 8 cm 9 cm 10 cm
The figures abcd, ghij and rstu are congruent figures, and the value of length ts is 8 cm
How to determine the length ts?The congruent statement is given as:
abcd ≅ ghij and bcda ≅ rstu
The above statement means that:
ts = dc = ij
From the question, we have:
ij = 10 cm
This means that
ts = 10 cm
Hence, the value of length ts is 8 cm
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Answer:
D: 10 cm
Worked for me on the "Congruent Figures" quiz on edge
i need help answer it correctly
Answer:
(1) when x is 0 y=5/2 and when y is 0 x=5
(2)Graph the points : (0 , 5/2) and (5 , 0)
(3)the slope is -1/2
Step-by-step explanation:
show that if g and h are consistent cuts of a distributed computation (e, →), then so are g ∪ h and g ∩ h.
The distributed computation (e, →) is said to be consistent if all computations lead to the same result, regardless of the order in which the steps are performed.
Let g and h be consistent cuts of a distributed computation (e, →).
We must demonstrate that g ∪ h and g ∩ h are also consistent cuts of (e, →).
Let R be the set of events that are in both g and h. If we remove R from either g or h, we get a consistent cut since the removed events cannot cause a change in the outcome.
By removing R from both g and h, we obtain two new consistent cuts: g − R and h − R.
Thus, we can write:g = (g − R) ∪ R and h = (h − R) ∪ R. Since (g − R) and (h − R) are consistent cuts, it follows that their union, g ∪ h, is also a consistent cut. I
f we let S be the set of events that are in both g and h, then we can write:g = (g ∩ h) ∪ (g − S) and h = (g ∩ h) ∪ (h − S).
Again, (g − S) and (h − S) are consistent cuts, so their intersection, g ∩ h, is also a consistent cut.
Therefore, if g and h are consistent cuts of a distributed computation (e, →), then so are g ∪ h and g ∩ h.
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Pleaseeeee help urgent!
The values of the trigonometric ratios sec θ and cot θ are:
sec θ = -13/12
cot θ = 12/5
How to use Trigonometric ratios?There are three main trigonometric ratios which are:
sin x = opposite/hypotenuse
cos x = adjacent/hypotenuse
tan x = opposite/adjacent
We are told that sin θ = -5/13
Using Pythagoras theorem, we have that:
Adjacent side = √(13² - 5²)
Adjacent side = √144 = 12
Thus:
cos θ = -12/13
sec θ = 1/cos θ
Thus:
sec θ = 1/(-12/13)
sec θ = -13/12
1/ tan θ = cot θ
tan θ = sin θ/cos θ
tan θ = (-5/13)/(-12/13) = 5/12
cot θ = 1/(5/12) = 12/5
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4 A piece of wire is 30 cm long.
It is cut into two unequal pieces.
One piece is bent into a circle.
The other is bent into a square enclosing the circle, as
shown in the diagram.
Find the length of each piece of wire in cm to 3 s.f.
Step-by-step explanation:
When an iron rod is cut into equal pieces of 30 cm each, a piece of 4 cm is left out. When cut into equal pieces of 29 cm, a piece of 13 cm is left out. The minimum length of rod is
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A 5 metre long piece of cloth is cut into three smaller pieces. How long is the longest of the three pieces? Given that:
I. One piece is 2.90 metre long.
II. One piece is 90 cm longer than another piece and the remaining piece is 20 cm long
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A piece of wire 12 m long is cut into two pieces, one piece is 4.29 m long. What is the length of the other piece?
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A rope 5 m 75 cm long is cut into two pieces. If one piece is 2.25 m long find out the length of the other piece.
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A piece of wire. 2
4
3
metres long, broke into two pieces. One piece is
8
5
metre long. How long is the other piece?
Sin(x+4)=cos(4x-9)
How do you solve this?
1.) Graph the function y = x + 1 for the domain of 2,-1,0,1
Answer:
(2,3) (-1,0) (0,1) (1,2)
Step-by-step explanation:
ez
vicente is eating at a restaurant. his total bill comes to $24.90. if vicente decides to leave a tip that is approximately 15% of the total bill, how much should he leave for the tip?
The tip will be $3.735 based on the amount of bill and percentage decided to give tip.
Vicente decides to give 15% of the total bill, hence, the calculation will be to find out the 15% of the bill. The formula to be used is -
Tip amount = total bill × percentage
Keep the values in formula to find the value of tip
Tip = 24.90 × 15%
Tip = 24.90 × 15/100
Performing division and multiplication on Right Hand Side of the equation
Tip = 3.735
Thus, the tip amount is $3.735, according to the 15% calculation on total bill amount.
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Factor the expression.
x^2+ 8x - 20
A number squared subtracted from 3 times the number is equal to negative 70.Set up and solve a quadratic equation, then solve by factoring.
Given
Number squared subtracted fom 3 times the number is equal to negative 70.
Find
Set up quadratic equation and solve by factoring
Explanation
Let the number be x.
according to the question,
\(3x-x^2=-70\)then,
\(x^2-3x-70=0\)by solving , we get
\(\begin{gathered} x^2-3x-70=0 \\ (x+7)(x-10)=0 \\ x=-7,x=10 \end{gathered}\)Final Answer
quadratic equation =
\(x^2-3x-70=0\)and factors are -7 and 10
What is the equation for g, which is f(x) = 2x2 + 3x − 1 reflected across the y-axis?
A. G(x) = 2x2 + 3x − 1
B. G(x) = −2x2 − 3x + 1
C. G(x) = 2x2 − 3x − 1
D. G(x) = −2x2 − 3x − 1
\(G(x)=f(-x)\\\\G(x)=2(-x)^2+3(-x)-1\\\\G(x)=\boxed{2x^2-3x-1}\)
Quadrilateral GHIJ is similar to quadrilateral
KLMN. Find the measure of side MN. Round
your answer to the nearest tenth if necessary.
Based on the definition of similar quadrilaterals, the measure of side MN is: 14.1 units.
What are Similar Quadrilaterals?If two quadrilaterals are similar to each other, then the measure of their corresponding sides will have a ratio that is equal. This means they will have proportional side measures.
Since we are told that quadrilaterals GHIJ and KLMN are similar to each other, then their corresponding sides will have measures that are proportional to each other.
Therefore:
IJ/MN = GJ/KN
IJ = 35
MN = ?
GJ = 52
KN = 21
Substitute:
35/MN = 52/21
Cross multiply:
MN(52) = (35)(21)
MN(52) = 735
MN = 735/52
MN = 14.1 units
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HELP WORTH 30 POINTS
What is the value of b?
100
110
55
90
Find the tangential and normal components of the acceleration vector.
The tangential component of the acceleration vector represents the change in speed or direction along the path. The normal component of the acceleration vector represents the change in direction perpendicular to the path.
To find the tangential and normal components of the acceleration vector, we need the velocity vector and the curvature of the path. The tangential component of acceleration (at) represents the change in speed or direction along the path. It is given by the derivative of the velocity vector with respect to time. The normal component of acceleration (an) represents the change in direction perpendicular to the path. It is given by the curvature of the path multiplied by the square of the speed.
In mathematical terms:
at = dV/dt
an = (V^2) / R
where:
V is the velocity vector
t is time
R is the radius of curvature of the path.
The tangential component of the acceleration vector represents the change in speed or direction along the path. The normal component of the acceleration vector represents the change in direction perpendicular to the path.
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the histogram displays the number of 2008 births among u.s. women ages 10 to 50. each bin represents an interval with a class width of two years, and the height of each bin represents the frequency with which the data fall within that interval. use the histogram to answer parts (a), (b), and (c). (a) identify the cases and variables of this study. (b) how many births occurred among women who are at least 38 years old?
(a) Cases: US women ages 10-50. Variable: births in 2008. (b) The bin for 38-40 years old has height 40, so 40 births occurred. (c) The bin for 18-20 years old has height 160, so 160 births occurred.
(a) The cases in this study are US women ages 10-50. The variable is the number of births in 2008. (b) The bin for 38-40 years old has a height of 40, so this indicates that 40 births occurred among women who are at least 38 years old. (c) The bin for 18-20 years old has a height of 160, so this indicates that 160 births occurred among women in that age group. To further illustrate this, each bar on the histogram shows the frequency with which the data fall within a specific age range. The height of each bar indicates the frequency with which the data fall within that range. For example, the bar for 18-20 years old indicates that the data fall within this age range 160 times, which means that 160 births occurred among women in that age group.
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An apartment building owner charges $905 to each apartment for rent month if the building is currently renting 64 apartments how much money does the building owner collect in each month?
Answer: 57920 per month
Step-by-step explanation: 905 x 64 = 57920
During the rebuilding after World War II, we were short of tractors. The machine and tractor stations would lend each other equipment as needed. Three machine and tractor stations were neighbors. The first lent the second and third as many tractors as they each already had. A few months later, the second lent the first and third as many as they each had. Still later, the third lent the first and second as many as they each already had. Each station now had 24 tractors.
How many tractors did each station originally have?
The number of tractors lent by the first, second and third stations results in a system of three simultaneous equations which indicates;
The first originally station had 39 tractors, the second station had 21 tractors and the third station originally had 12 tractors
What are simultaneous equations?Simultaneous equations are a set of two or more equations that have common variables.
Let x represent the number of tractors at the first station, let y represent the number of tractors at the second tractor station, and let z, represent the number of tractors at the third tractor station
According to the details in the question, after the first transaction, we get
Number of tractors at the first station = x - y - z
Number of tractors at the second station = y + y = 2·y
Number of tractors at the third station = z + z = 2·z
After the second transaction, we get;
Number of tractors at the first station = 2·x - 2·y - 2·z
Number of tractors at the second station = 2·y - (x - y - z) - 2·z = 3·y - x - z
Number of tractors at the third station = 2·z + 2·z = 4·z
After the third transaction, we get;
Number of tractors at the first station = 2 × (2·x - 2·y - 2·z) = 4·x - 4·y - 4·z
Number of tractors at the second tractor station = 6·y - 2·x - 2·z
Number of tractors at the third tractor station = 4·z - (2·x - 2·y - 2·z) - (3·y - x - z) = 7·z - x - y
The three equations after the third transaction are therefore;
4·x - 4·y - 4·z = 24...(1)
6·y - 2·x - 2·z = 24...(2)
7·z - x - y = 24...(3)
Multiplying equation (2) by 2 and subtracting equation (1) from the result we get;
12·y - 4·x - 4·z - (4·x - 4·y - 4·z) = 16·y - 8·x = 48 - 24 = 24
16·y - 8·x = 24...(4)
Multiplying equation (3) by 2 and multiplying equation (2) by 7, then adding both results, we get;
14·z - 2·x - 2·y = 48
42·y - 14·x - 14·z = 168
42·y - 14·x - 14·z + (14·z - 2·x - 2·y) = 48 + 168
40·y - 16·x = 216...(5)
Multiplying equation (4) by 2 and then subtracting the result from equation (5), we get;
40·y - 16·x - (32·y - 16·x) = 216 - 48 = 168
8·y = 168
y = 168/8 = 21
The number of tractors initially at the second station, y = 21
16·y - 8·x = 24, therefore, 16 × 21 - 8·x = 24
8·x = 16 × 21 - 24 = 312
x = 312 ÷ 8 = 39
The number of tractors initially at the first station, x = 39
7·z - x - y = 24, therefore, 7·z - 39 - 21 = 24
7·z = 24 + 39 + 21 = 84
z = 84/7 = 12
The number of tractors initially at the third station, z = 12
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Please Please I need help ASAP you don't know how much it is to me if you answer this question. :(
Find what n is in this image:
Answer:
x = 20
Step-by-step explanation:
I'm still in algebra II, but if you need help with problems like this, you should look into the TI-nspire CXII CAS. This calculator can solve problems like this and do countless other things as well
Given f^ prime prime (x)=x+2 and f^ prime (0)=3 and f(0) = - 1. Find f(x).
The derivative function is given as
\(f^{\prime}^{\prime}(x)=x+2\)and f(0) = - 1 and f'(0) = 3
ExplanationTo determine the function,
\(\begin{gathered} \int d^2y=\int(x+2)dx^2 \\ \frac{dy}{dx}=\frac{x}{2}^2+2x+C \\ f^{\prime}(0)=\frac{0}{2}^2+2(0)+C \\ 3=C \end{gathered}\)It is also given that f(0) = - 1.
\(f^{\prime}(x)=\frac{x^2}{2}+2x+3\)Take the integral and find the function
\(\begin{gathered} \int dy=\int\frac{x^2}{2}+2x+3dx \\ y=\frac{x^3}{6}+\frac{2x^2}{2}+3x+C \\ y=\frac{x^3}{6}+x^2+3x+C \\ f(x)=\frac{x^3}{6}+x^2+3x+C \\ -1=0+C \\ C=-1 \end{gathered}\)Then the function is determined as
\(y=\frac{x^3}{6}+x^2+3x-1\)AnswerHence the function is determined as
\(f(x)=\frac{x^3}{6}+x^2+3x-1\)The sum of two numbers is 52 and the difference is 16. What are the numbers?
Answer:
18
Step-by-step explanatio:a 52 le quitas la diferencia de 16 y da 36 que lo divides entre 2 y es 18 por lo que 18+18=36+16=52
Step-by-step explanation:
\(here \: is \: your \: solution \\ \\ let \: the \: first \: number \: be \: x \\ \\ let \: the \: second \: number \: be \: y \\ \\ now \: according \: to \: question \\ \\ x + y = 52 \\ \\ and \: x - y = 16 \\ \\ now \: add \: both \: equation \\ \\ we \: will \: get \: \\ \\ 2x = 68 \\ \\ x = 68 \div 2 \\ \\ x = 34 \\ \\ now \: put \: the \: value \: of \: x \: in \: equation \\ \\ 34 + y = 52 \\ \\ y = 52 - 34 \\ \\ y = 18 \\ \\ x = 34 \: and \: y = 18 \\ \\ hope \: it \: helps\)
Find the angle between vector bold lower u equals 3 bold lower I plus start root 3 end root bold lower j and vector bold lower v equals negative 2 bold lower I minus 5 bold lower j to the nearest degree. A. 82° B. 38° C. 142° D. 98°
Answer:
C. 142°
Step-by-step explanation:
You want the angle between vectors u=3i+√3j and v=-2i-5j.
AngleThere are a number of ways the angle between the vectors can be found. For example, the dot-product relation can give you the cosine of the angle:
u•v = |u|·|v|·cos(θ) . . . . . . where θ is the angle of interest
You can find the angles of the vectors individually, and subtract those:
u = |u|∠α
v = |v|∠β
θ = α - β
When the vectors are expressed as complex numbers, the angle between them is the angle of their quotient:
\(\dfrac{\vec{u}}{\vec{v}}=\dfrac{|\vec{u}|\angle\alpha}{|\vec{v}|\angle\beta}=\dfrac{|\vec{u}|}{|\vec{v}|}\angle(\alpha-\beta)=\dfrac{|\vec{u}|}{|\vec{v}|}\angle\theta\)
This method is used in the calculation shown in the first attachment. The angle between u and v is about 142°.
A graphing program can draw the vectors and measure the angle between them. This is shown in the second attachment.
__
Additional comment
The approach using the quotient of the vectors written as complex numbers is simply computed using a calculator with appropriate complex number functions. There doesn't seem to be any 3D equivalent.
The dot-product relation will work with 3D vectors as well as 2D vectors.
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The tetrahedron enclosed by the coordinate planes and the plane 2x + y + z =4
volume= 16/3, A coordinate plane is a graphing and description system for points and lines. A vertical (y) axis and a horizontal (x) axis make up the coordinate plane. There are four quadrants in the coordinate plane. The point where these lines connect is called the origin (0, 0).
limits
z= 0 to z = 4-y-2x
y= 0 to y = 4- 2x
x= 0 to x= 2
volume
v= \(\int\limits^2_0 \int\limits^4_0 \int\limits^4_0 dzdydx\)
v= \(\int\limits^2_0 \int\limits^4_0 (4-y-2x) dydx\)
v= \(\int\limits^2_0 ( 4y- y^{2} / 2 - 2xy) ^4^-^2^x _0\)
dx= \(\int\limits^2_0 [ 16-8x - 16+ 4x^2 - 16x / 2 - 8x+ 4x^2 ] dx\)
v= \(\int\limits^2_0 [ 8+ 2x^2- 8x] dx\\\)
= [ 8x + 2x^3 / 3 - 8x^2 / 2 ] ^2_0
= [16+ 16/3- 16]
v= 16/3
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Complete Question
Question: Sketch The Tetrahedron Enclosed By The Coordinate Planes And The Plane 2x+Y+Z=4. Use A Triple Integral To Find The Volume Of The tetrahedron
Elsa, Alan, and Deon have a total of $82 in their wallets. Alan has 3 times what Deon has. Deon has $7 less than Elsa. How much do they have in their wallets?
Answer:
Alan=$45
Deon=$15
Elsa=$22
Step-by-step explanation:
Let
Elsa=x
Deon=x-7
Alan=3(x-7)
Total=$82
x+(x-7)+3(x-7)=82
x+x-7+3x-21=82
5x-28=82
5x=82+28
5x=110
x=110/5
=22
Elsa=x=$22
Deon=x-7
=22-7
=$15
Alan=3(x-7)
=3(22-7)
=3(15)
=$45
obsa has two prism shaped container. one has a volume of2 1/3 cubic feet, and the other has a volume of 4/3 cubic feet. how many smaller prisms would it take to fill the larger?
Obsa will need 2 smaller prisms to fill the larger prism, with each smaller prism having a volume of 4/3 cubic feet.
To find out how many smaller prisms it would take to fill the larger one, we need to first determine the volume of the larger prism. We know that the larger prism has a volume of 2 1/3 cubic feet, which can also be expressed as 7/3 cubic feet.
Next, we need to find out how many of the smaller prisms will fit into the larger one.
To do this, we can divide the volume of the larger prism by the volume of the smaller prism.
The smaller prism has a volume of 4/3 cubic feet, so:
(7/3 cubic feet) / (4/3 cubic feet) = 7/4
This means that it will take 7/4 smaller prisms to fill the larger prism.
However, since we can't have a fraction of a prism, we need to round up to the nearest whole number.
Therefore, it will take 2 smaller prisms to fill the larger prism. One prism will fill up 4/3 cubic feet, and the other will fill up 4/3 cubic feet, totaling to 8/3 cubic feet, which is just a bit more than the 2 1/3 cubic feet of the larger prism.
This means that it takes 1 and 3/4 smaller prisms to fill the larger container.
However, since we cannot have a fraction of a prism, we need to round up to the nearest whole number, which is 2.
Therefore, it would take 2 smaller prisms to fill the larger prism-shaped container.
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Help please. KHAN ACADEMY!!!
what is the average rate of change of y with respect to x over the interval [1, 5] for the function y = 4x 2?
The average rate of change of y with respect to x over the interval [1, 5] for function \(y=4x^{2}\) is 24.
To find the average rate, follow these steps:
The formula for the average rate of change is expressed as rate= (f (b) - f (a)) / (b - a), where the letters a and b represent two points on the interval that is being analyzed and f (a) and f (b) are the function values of those points. The interval [1, 5] is being considered here so the value of a =1 and value of b=5.So, the average rate of change of y with respect to x is given by;(f(b)−f(a))/(b−a) = [f(5)−f(1)]/(5−1). By substituting x = 5 into the function equation, we get f(5) = \(4(5)^2\) = 100. By substituting x = 1 into the function equation, we get f(1) = \(4(1)^2\) = 4. Substituting these values into the average rate of change formula;[f(5)−f(1)]/(5−1) = (100 - 4) / 4 = 96/4 = 24.Therefore, the average rate of change of y with respect to x over the interval [1, 5] for the function \(y=4x^{2}\) is 24.
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Find mZG The diagram is not to scale.
My watch loses three minutes every hour today at 6:00am it was marking the exact time what time will it actually be when my watch says 6:00pm
Your watch will be 39 minutes behind the actual time when it says 6:00 PM. Therefore, the actual time will be 5:21 PM.
If your watch loses 3 minutes every hour, then from 6:00 AM to 6:00 PM, it will lose a total of 13 hours * 3 minutes/hour = 39 minutes.
So, when your watch says 6:00 PM, the actual time will be 6:00 PM - 39 minutes = 5:21 PM.
Here is a more detailed explanation of the calculation:
* Hour 1: 6:00 AM - 6:03 PM = 3 minutes lost
* Hour 2: 7:00 AM - 7:03 PM = 3 minutes lost
* Hour 3: 8:00 AM - 8:03 PM = 3 minutes lost
* ...
* Hour 13: 5:00 PM - 5:03 PM = 3 minutes lost
* Hour 14: 6:00 PM - 5:21 PM = 39 minutes lost
Therefore, the time elapsed and actual time will be 5:21 PM.
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The range of the following numbers is 6. What could
the missing number be?
7,4,5,6,4, ?
Answer:
Range = highest number - lowest number
Let h be the highest number.
6 = h - 4, so h = 10
The missing number is 10.