What is the freezing point of a solution made from 22.0 g of octane (c8h18) dissolved in 148.0 g of benzene? (for benzene, freezing point = 5.50°c; kf = 5.12°c/m)

Electrons are shared in covalent bonds.

What is a covalent bond?
The exchange of one or more pairs of electrons between two atoms forms a covalent connection. The two atomic nuclei are drawing these electrons in unison. When there is insufficient space between two atoms' electronegativities for an electron transfer to take place and create ions, a covalent bond is formed. Bonding electrons are shared electrons that are present in the region between the two nuclei. The bound pair serves as the "glue" that binds the atoms in molecular structures.

The only covalently bound substance that is the simplest is a hydrogen molecule. Two hydrogen atoms with one electron in each's 1s orbital make up the compound. The covalent link between the two hydrogen atoms allows them to share their two electrons and give each of them a helium-like electron configuration.

Hence, electrons are shared in covalent bonds.

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Answer:

\(2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}\)

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

\(2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}\)

Best regards!

Group IA are metals and all react vigorously because they have 1 valence electron in their outer most shell and the reactivity increases as you go down the group. Group VIIIA are non reactive because of their complete valence shell.

Molecule is defined as number of atoms combined together, that shows the most smaller chemical compound's fundamental unit that participate in chemical reaction. In the combination of atoms attractive forces play a vital role and it helps to bound the atoms by a chemical bond.

Liquid consist of small range of order and the reason behind this is intermolecular attractive force which is very strong and due to this reason molecules are packed together tightly. Due to presence of high kinetic energy the molecules present in the liquid move rapidly and fastly  with one another.

Water is considered to be the simpler molecule and it consist of hydrogen and oxygen atom bounded together and due to the reason of high electronegativity of the oxygen's atom the bonds present are polar as well as covalent.  Due to presence of high kinetic energy the molecules present in the liquid move rapidly and fastly  with one another.

Therefore,Group IA are metals and all react vigorously because they have 1 valence electron in their outer most shell and the reactivity increases as you go down the group. Group VIIIA are non reactive because of their complete valence shell.

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a. Decreasing alpha from 0.05 to 0.01 makes the significance level more stringent. You will be less likely to reject the null hypothesis, even when it's false. This increases the probability of a Type II error, thus potentially reducing the power of the test. The power curve will shift to the left.

b. If the sample size is reduced from 90 to 50, the effect on the power curve is that it will also shift towards the left.

The power curve is a graph that shows the probability of rejecting the null hypothesis as a function of the true value of the mean.

In the given scenarios of this study, Reducing the significance level and reducing the sample size will shift the power curve to the left, indicating a decrease in the statistical power of the test.

The power of a statistical test is the probability that it correctly rejects the null hypothesis when the alternative hypothesis is true.

a) Reducing alpha from 0.05 to 0.01 means that we are more stringent in our assessment of whether the new treatment is effective.

This will result in a decrease in the power of the test, meaning that it is less likely that we will be able to detect a difference between the new treatment and the previous treatment.

b) If the sample size is reduced from 90 to 50, the effect on the power curve is that it will also shift towards the left.

This is because a smaller sample size decreases the power of the test. A larger sample size provides more information and thus makes it more likely to correctly reject the null hypothesis when the alternative hypothesis is true.

Therefore, by reducing the sample size, you are decreasing the likelihood of detecting a true effect if one exists, thus reducing the power of the test.

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The statement "Syrah, Shiraz, and Petite Syrah are related because they are essentially the same varietal" is False. Syrah, Shiraz, and Petite Syrah are not the same varietal, but they are related to each other. The varietal known as Syrah is an Old World grape that is grown in France's Rhône Valley.

The statement "Syrah, Shiraz, and Petite Syrah are related because they are essentially the same varietal" is False. Syrah, Shiraz, and Petite Syrah are not the same varietal, but they are related to each other. The varietal known as Syrah is an Old World grape that is grown in France's Rhône Valley. Shiraz, on the other hand, is a New World grape that is grown primarily in Australia, but also in other parts of the world, including South Africa, New Zealand, and the United States. Both Syrah and Shiraz produce full-bodied wines that are known for their deep color, spicy notes, and high tannin content.

However, Shiraz wines tend to be fruitier and more jammy than Syrah wines. Petite Sirah is another grape varietal that is related to both Syrah and Shiraz. Petite Sirah is a cross between Syrah and Pelours in, another grape varietal that is grown in France. Petite Sirah is grown primarily in California and produces wines that are known for their dark color, high tannin content, and bold, jammy flavors. So while Syrah, Shiraz, and Petite Sirah are related to each other, they are not the same varietal.

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Answer:

Translated < what is the maximum number of electrons in the sublevel 4s?

answer 32 electrons

Answer:

I think C But I can't really see it well

Answer:

any push or pull that causes an object to move, stop, or change speed or direction

Description:

zayn your my enemy

Answer:

less metallic

Explanation:

Answer:

D; Decrease in atomic mass.

Explanation:

I looked at the periodic table.

Answer:

Explanation:

Some substances are poor conductors because they do not possess freely moving ions but they conduct electricity in their aqeous solution beacuse their ions become free to move when dissolved in water. Common example of such substances is NaCl which is commnly called table salt

Yes, the carbons in glucose are ultimately used to make additional Krebs cycle intermediates.

Glucose is one of the primary sources of energy that our body uses to fuel daily activities. Carbons in glucose are ultimately used to make additional Krebs cycle intermediates.

The Krebs cycle or Citric acid cycle (CAC) is a part of cellular respiration where it breaks down the molecules of glucose and other fuel to produce energy. It is an important metabolic pathway that is present in all living cells.

The carbon in glucose undergoes the breakdown process in the Krebs cycle which produces ATP, carbon dioxide, and water. The citric acid cycle is responsible for completing the breakdown of glucose.

The carbons in glucose ultimately produce two CO₂ molecules, which enter into the Krebs cycle and converted to Acetyl CoA and water in the mitochondria to produce ATP. The two CO₂ molecules come from the two-carbon acetyl CoA molecules that enter the Krebs cycle.

So, from the above explanation, we can conclude that the carbons in glucose are ultimately used to make additional Krebs cycle intermediates. Hence, glucose is one of the important sources that can be used to generate the energy required by the body.

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There are five molecules of the water of crystallization.

Mass of hydrated copper(II) sulfate CuSO4 · xH2O = 0.755 g

Mass of anhydrous copper(II) sulfate CuSO4 = 0.483 g

Molar mass of hydrated copper(II) sulfate CuSO4 · xH2O = (160 + 18x) g/mol

Molar mass of anhydrous copper(II) sulfate CuSO4 =160 g/mol

Number of moles of hydrated copper(II) sulfate CuSO4 · xH2O = Number of moles of anhydrous copper(II) sulfate CuSO4

Therefore;

0.755 g/(160 + 18x) g/mol  = 0.483 g/160 g/mol

0.755 * 160 = 0.483 (160 + 18x)

120.8 = 77.28 * 8.694x

120.8 - 77.28 = 8.694x

x = (120.8 - 77.28)/8.694

x = 5

The formula of the hydrated salt is CuSO4 · 5H2O.

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Answer:

Cellular Respiration:

C6H12O6 + 6O2 → 6CO2 + 6H20 + energy (Glucose + Oxygen yields Carbon Dioxide + Water + Energy) 

Photosynthesis is important to living organisms because it is the number one source of oxygen in the atmosphere. Without photosynthesis, the carbon cycle wouldn't occur/exist, oxygen-requiring life would not survive and plants would die. Without photosynthesis there would be little to no oxygen on the planet and Earth would be impossible to live on.

Answer:

1 Zn + 2 HCl ⇒ 1 H₂ + 1 ZnCl₂

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The free energy required to synthesize ATP in a rat hepatocyte is 24,365.6364 J/mol

To calculate the free energy required to synthesize ATP in a rat hepatocyte, we can use the formula:

ΔG'º = -RTln(Q)

where:

ΔG'º is the standard free energy change,

R is the gas constant (8.314 J/(mol·K)),

T is the temperature in Kelvin,

ln(Q) is the natural logarithm of the mass-action ratio.

Given:

ΔG'º = -30.5 kJ/mol

T = 37°C = 37 + 273.15 = 310.15 K

Q = 5.33 x \(10^{(-10)\) M

First, we need to convert ΔG'º from kJ/mol to J/mol:

ΔG'º = -30.5 kJ/mol = -30.5 x \(10^3\) J/mol

Next, we can calculate the free energy required to synthesize ATP using the formula:

ΔG = ΔG'º - RTln(Q)

ΔG = \((-30.5 * 10^3 J/mol) - (8.314 J/(molK) * 310.15 K) * ln(5.33 x 10^{(-10))\)

≈ -30,500 J/mol - 2576.1911 J × (-21.3364)

≈ -30,500 J/mol + 54,865.6364 J

≈ 24,365.6364 J/mol

Calculating this expression will give us the value of ΔG, which represents the free energy required to synthesize ATP in a rat hepatocyte.

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The photoelectrons' kinetic energy increased with an increase in light frequency, and the current increased with a rise in light amplitude.

What is demonstrated by the photoelectric effect?

The current increased with a rise in light amplitude, and the kinetic energy of the photoelectrons increased with a rise in light frequency.

What does the photoelectric effect prove?

Light can be categorised as a wave because it demonstrates all three of the essential features of a wave—interference, diffraction, and polarisation.

The photoelectric effect, however, only makes sense if we consider light to be made up of tiny energy packets (particles) known as photons; in other words, the photoelectric effect proves that light is a particle.

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To calculate the old selling price, we need to first find the markup value using the original cost of $136 and the markup percentage of 25%.

Markup value = original cost x markup percentage/100
Markup value = $136 x 25/100
Markup value = $34

Therefore, the old selling price is:
Selling price = original cost + markup value
Selling price = $136 + $34
Selling price = $170

Now, let's calculate the new selling price using the decreased markup percentage of 17%.
Markup value = original cost x markup percentage/100
Markup value = $136 x 17/100
Markup value = $23.12

Therefore, the new selling price is:
Selling price = original cost + markup value
Selling price = $136 + $23.12
Selling price = $159.12

In summary, the old selling price of the cell phone was $170 and the new selling price is $159.12.

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The old selling price was $170 and the new selling price is $159.12.

To answer this question, we first need to calculate the original markup value when the sellers marked up the cost by 25 percent.
Markup value = original cost x markup percentage
Markup value = $136 x 0.25
Markup value = $34

Therefore, the original selling price of the cell phone was:
Selling price = original cost + markup value
Selling price = $136 + $34
Selling price = $170

However, due to poor sales, the sellers decided to decrease the markup to 17 percent. So, we need to calculate the new markup value:
New markup value = original cost x new markup percentage
New markup value = $136 x 0.17
New markup value = $23.12

Now, we can calculate the new selling price of the cell phone:
New selling price = original cost + new markup value
New selling price = $136 + $23.12
New selling price = $159.12


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Answer:

a) [H₃O⁺] = 1.8x10⁻⁵ M

b) pH = 4.75

c) % rxn = 3.5x10⁻³ %

Explanation:

a) The dissociation reaction of HCN is:

HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)

0.5 M - x                       x               x

The dissociation constant from the above reactions is given by:

\(Ka = \frac{[H_{3}O^{+}][CN^{-}]}{[HCN]} = 6.17 \cdot 10^{-10}\)

\( 6.17 \cdot 10^{-10} = \frac{x*x}{(0.5 - x)} \)

\( 6.17 \cdot 10^{-10}*(0.5 - x) - x^{2} = 0 \)

By solving the above quadratic equation we have:

x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]

Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.

b) The pH is equal to:

\(pH = -log[H_{3}O^{+}] = -log(1.75 \cdot 10^{-5} M) = 4.75\)    

Then, the pH of the HCN solution is 4.75.

c) The % reaction is the % ionization:

\( \% = \frac{x}{[HCN]} \times 100 \)

\( \% = \frac{1.75 \cdot 10^{-5} M}{0.5 M} \times 100 \)

\( \% = 3.5 \cdot 10^{-3} \% \)          

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.

I hope it helps you!      

Answer:

Move

Explanation:

Answer:

not goin to be rude but I don't even get the question??

The Tris-HCl buffer and the specific experimental conditions (incubation time, temperature, etc.) may vary depending on the protocol used.

To determine the organophosphate concentration, alkaline phosphatase is used as it can hydrolyze the organophosphate compounds into phosphate ions. The reaction can be monitored by measuring the amount of phosphate released, which is directly proportional to the concentration of organophosphates in the sample.

Here is a step-by-step process for conducting the experiment:

1. Prepare a horn sample by extracting the organophosphates of interest.
2. Prepare the enzyme solution by diluting alkaline phosphatase in 50mM Tris-HCl buffer at the specified pH.
3. Mix the horn sample with the enzyme solution and incubate at an appropriate temperature.
4. After incubation, measure the released phosphate ions using a spectrophotometer or a colorimetric assay.
5. Compare the phosphate concentration with a standard curve generated using known concentrations of organophosphate standards.
6. Calculate the concentration of organophosphates in the horn sample based on the standard curve.

It's important to note that the pH of the Tris-HCl buffer and the specific experimental conditions (incubation time, temperature, etc.) may vary depending on the protocol used.

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Answer:

Evaporation. The water Condenses in the clouds then fall. So the answer is False.

Answer:

A small positively charged nucleus surrounded by revolving negatively charged electrons in fixed orbits

Answer:

C is the answer..

The equation is showing how it is formed, so the answer is on the other side of the equal sign.

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, diagram C shows the final compound.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

The diagram below shows what happens during the formation of a compound. The diagram shows two substances joining together to form a third substance. Diagram C shows the final compound.

Therefore, diagram C shows the final compound.

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Answer: I believe you are talking about the world's first recorded nuclear explosion that took place on the plains of the Jornada del Muerto Dessert.

Explanation: It is to be noted that the Trinity site is still considered to be radioactive, and Trinitite which is a green glass-like substance is found abundantly in the area. Trinity was an atmospheric test conducted by the U.S. Army on July 16th of 1945. The site was chosen because of its isolated, flat grounded, non-windy lands. This experiment was so tightly gatekept that not even the military policemen whom rode with it knew of its contents.

The first step is to lessen the number of the organism which consumes clawcats. The second is to enhance the resources Clawncat requires to live.

Population is the total number of people living in a region (such as a nation or the planet), which is always changing due to births, immigration, and natural mortality.

There are two ways to boost the Clawcat population. The first step is to lessen the number of the organism which consumes clawcats. The second is to enhance the resources Clawncat requires to live, namely by expanding the plantation of Clawncat, providing enough irrigation, giving full access to sunshine, and increasing the richness of the soil through proper and effective fertilization.

Therefore, in the above given ways we can increase the population of Clawncat.

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