What is the energy density at the center of a circular loop of wire carrying a 23.0 a current if the radius of the loop is 28.0 cm?
Answers
The energy density at the center of a circular loop of wire carrying a 23.0 a current if the radius of the loop is 28.0 cm will be 1.06 * \(10^{-3}\) J / \(m^{3}\)
Energy density is defined as the amount of energy accumulated in a system per unit volume. In the case of electrical energy. Electrical energy density = permittivity* Electric field squared/2 mu0
When an electric current is passed through a current-carrying circular wire loop, the magnetic field lines are generated in a circular pattern around the arms of the coil while the magnetic field lines are straight at the center of the loop
The magnetic field strength at the center of a circular loop is given by
B=(muo*I)/2R (at center of loop),
Energy density = \(B^{2}\) / 2 (mu0)
= \(\frac{1}{2 (muo)}\) * \((\frac{muo * I}{2R})^{2}\) = \(\frac{muo * I^{2} }{8 * R^{2} }\)
= \(\frac{4*3.14*10^{-7}*(23)^{2} }{8 * (0.28)^{2} }\)
= 1.06 * \(10^{-3}\) J / \(m^{3}\)
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Related Questions
What Machines that help you go faster
Answers
Answer:
If you mean for exercising then, The Treadmill. Purists may claim that treadmill running isn't "real" running. ...
The Elliptical Trainer. ...
The Stair-Climber. ...
The Cross-Country Skiing Simulator. are all machines that help you practice agility
Explanation:
which force causes the protons in an atom to be attracted to one another?
Answers
answer:
the electromagnetic force
explanation:
the electromagnetic force of attraction between negative electrons and positive protons in the nucleus keeps electrons in the area surrounding the nucleus the electromagnetic force of repulsion between positive protons in the nucleus is overcome by the strong nuclear force between protons and neutronscredits: online sourceA truck with a mass of 15,000 kg moving at 25 m/s crashes into the back of a small 1,100 kg car moving at 15 m/s. They
stick together after the collision. Calculate the momentum of the system before the collision and after the collision.
Answers
Explanation:
Given that,
Mass of a truck = 15,000 kg
Speed of the truck = 25 m/s
Mass of car = 1,100 kg
Speed of the car = 15 m/s
As they stick together after the collision. Let V be the speed after the collision.
Initial momentum of the system,
\(P_i=15000\times25+1100\times15\\\\=391500\ kg-m/s\)
Final momentum of the system,
\(P_f=(15000+1100)V\\\\=16100V\)
Hence, this is the required solution.
Describe the relationship between current, voltage difference and resistance in a circuit.
Answers
Answer:
see below
Explanation:
voltage = current * resistance
what is the image that you see through a converging lens when the lens is close to your eyeball and you look at a close object? check all that xhwgg .
Answers
The image that you see through a converging lens when the lens is close to your eyeball and you look at a close object is virtual and enlarged.
When an object is held close to the eye and seen via a converging lens, the image seems magnified and virtual. An expanded and upright virtual picture is created when the lens bends the incoming light rays so that they converge and seem to come from a point behind the lens. The distance between the lens and the item being seen as well as the focal length of the lens affect the distance of the image from the lens.
To examine a close item, it may not be the best practice to hold a lens too close to the eye as this might strain and hurt the eye. For this reason, a magnifying glass or another optical device could be better suitable.
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If I have a series circuit with 3 resistors on it and each resistor has a resistance of 500
Ohms, what is my total resistance?
Answers
Answer:
1,500 ohms is the total resistance
How do you find the image size in a concave mirror?
Answers
The concave mirror is represented by a vertical line MMl. The principal axis is represented by a horizontal line drawn on the PC. 1 mm. 12 mm (focal length: 12 cm); I Image position.
Here, u = 25 cm for the object distance (To the left of the mirror)
Also, the focal length is f = 20 cm (It is a concave mirror)
What is the size of the image in a concave mirror?
The size of image formed by a concave mirror is same as the size of object.
Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height. Where v is the image distance u is the object distance and f is the focal length.
However, if we increase the distance between the object and the mirror then the size of the image reduces and a real and inverted image is formed. The image formed by the concave mirror can be small or large and can be real or virtual.
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The concave mirror is represented by a vertical line MMl. The principal axis is represented by a horizontal line drawn on the PC. 1 mm. 12 mm (focal length: 12 cm); I Image position.
Here, u = 25 cm for the object distance (To the left of the mirror)
Also, the focal length is f = 20 cm (It is a concave mirror)
What is the size of the image in a concave mirror?
The size of image formed by a concave mirror is same as the size of object.
Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height. Where v is the image distance u is the object distance and f is the focal length.
However, if we increase the distance between the object and the mirror then the size of the image reduces and a real and inverted image is formed. The image formed by the concave mirror can be small or large and can be real or virtual.
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need help asap, thank you !
In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at which of the following angles? O 38 O 57⁰ 0:45. 07
Answers
A projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰. The correct option is (B) 57⁰.
In the absence of air resistance, a projectile launched at an angle of 33 above the horizontal will have the same range as a projectile launched at an angle of 57⁰.
The range of a projectile can be determined by using the range formula.
R = ((v^2 * sin(2θ))/g) Where
R is the range of the projectile,
v is the velocity of the projectile,
θ is the angle at which the projectile is launched, and
g is the acceleration due to gravity.
In the absence of air resistance,
the horizontal component of velocity of a projectile remains constant throughout the flight.
So, the range of a projectile depends only on its initial velocity and the angle at which it is launched.
If a projectile is launched at an angle θ,
the time of flight of the projectile can be calculated by using the following formula:
T = (2v * sin(θ))/g
The maximum height reached by the projectile is given by the formula:
H = (v^2 * sin^2(θ))/2gIf a projectile is launched at an angle θ, then the range of the projectile will be the same as the range of the projectile launched at an angle of (90 - θ).
So, if a projectile is launched at an angle of 33⁰ above the horizontal, then the projectile launched at an angle of 90 - 33 = 57⁰ will have the same range as the projectile launched at 33⁰.
Therefore, the correct option is (B) 57⁰.
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how many apples are in 29 trees if each tree has 45 apples?
Answers
Answer:
1305 I think but not sure
Please help with this, Im a little stuck!!
Answers
Answer:
Jwbsbsbdjeiskbsj3kabajj2jjj1jj2j2j3jkkkk3j3j2
____ thermal mass walls help retain captured energy and slowly transfers to the inside.
Answers
Thermal mass walls help retain captured energy and slowly transfer it to the inside by making use of the property of "thermal mass." This property refers to the ability of a material to absorb and store heat energy. Materials with high thermal mass, such as concrete, brick, and stone, can effectively store heat during the day and gradually release it at night.
In the context of building design, thermal mass walls can enhance energy efficiency and maintain comfortable indoor temperatures. When sunlight or other heat sources warm the outer surface of these walls, the heat is absorbed by the high thermal mass materials. Throughout the day, the walls capture and store the heat energy, preventing it from entering the building's interior.
As temperatures drop in the evening, the heat stored within the walls is gradually released into the building, providing a stable and consistent source of warmth. This process helps to maintain comfortable indoor temperatures with less reliance on artificial heating systems, reducing energy consumption and associated costs.
In summary, thermal mass walls contribute to energy efficiency and indoor comfort by effectively capturing, storing, and slowly releasing heat energy. Their high thermal mass properties help to moderate temperature fluctuations, providing a consistent source of warmth in colder periods and reducing the need for additional heating systems.
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How would the removal of the rabbit population affect the other populations in
the ecosystem?
A.
B.
The field mouse population will decrease.
The snake population will increase.
The lizard population will increase.
The tree population will decrease.
C.
D.
Answers
Fill in the blank.
_______________, not velocity, is used to calculate the average acceleration.
Answers
Answer:
speed
Explanation:
Change in velocity, not velocity, is used to calculate the average acceleration. Velocity is displacement over time.
Acceleration:
It is defined as the ratio of change in velocity to time. It is given by:
Acceleration= Change in velocity / time
a= u-v / t
where,
u= initial velocity
v= final velocity
t= time
Thus, we can conclude that a change in velocity is used to calculate average acceleration.
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Can anyone help me. . .
Answers
Answer:
welll
Explanation:
i honestly dk
what’s the relationship between height and potential energy?
Answers
Answer:
the higher up an object is, the more potential energy it has
Explanation:
times more energy than an earthquake with a magnituide of 2. Ori the Richter scale a magnitude 5 earthquake releases about
A. 30
B. 1000
C. 90
D. 27.000
What is the main caase of the spreading movement of the ocean crust
A. The convection current of the asthenosphere is drasging the ocean crust.
B. The riew magma forming at ocean ridges is pushing the ocean krure
C. There is a stearing motion on translorm plate boundaries
D. All of the above
consribute equally Respr Selestion
A. Increasing temperatures at the top of the asthenosphere
B. There is a greater water content in subducted oceanic crust
c. Decreasing pressure as the overlying crust thins
D. Higher viscosity as the silica content increases E. All of the above Reset Selection
Answers
The main cause of the spreading movement of the ocean crust is the new magma forming at ocean ridges, which pushes the oceanic plates apart. The other options listed do not contribute equally or directly to the spreading movement.
The spreading movement of the ocean crust is primarily driven by the formation of new magma at ocean ridges. As the mantle material beneath the Earth's surface rises and melts, it creates new magma. This molten material then pushes its way upward and fills the gap between the separating oceanic plates. As the new magma solidifies, it forms a new crust, expanding the ocean floor and causing the plates to move apart.
The other options listed do not directly contribute to the spreading movement of the ocean crust. Increasing temperatures at the top of the asthenosphere, the greater water content in subducted oceanic crust, decreasing pressure as the overlying crust thins, and higher viscosity as the silica content increases may have their own geological implications, but they are not the main causes of the spreading movement observed at ocean ridges.
Therefore, the correct answer is B. The new magma forming at ocean ridges is the main cause of the spreading movement of the ocean crust.
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The complete question is:
What is the main cause of the spreading movement of the ocean crust? A. As the ocean crust cools it becomes denser than the asthenosphere and the edge of the slab is pulled downward at subduction zones. B. The convection current of the asthenosphere is dragging the ocean crust C. The new magma forming at ocean ridges is pushing the ocean crust D. There is a shearing motion on transform plate boundaries E. All of the above contribute equally
Derive temperature distribution in a tube wall. Outer surface (at r=ra) is thermally insulated, while inner surface (n.) has constant temperature T
Answers
The temperature distribution in a tube wall refers to how the temperature varies across the thickness of the wall. in a tube wall, temperature distribution can be given as T(r, t) = R(r) Θ(t).
To derive the temperature distribution in a tube wall, we can use the heat conduction equation in cylindrical coordinates. The equation is:
∂²T/∂r² + (1/r) ∂T/∂r = (1/α) ∂T/∂t,
where T is the temperature, r is the radial coordinate, α is the thermal diffusivity, and t is the time.
Since the outer surface of the tube wall is thermally insulated, there is no heat transfer across that surface. This implies that the heat flux at r = ra is zero:
(-k) (dT/dr) |(at r=ra) = 0,
where k is the thermal conductivity.
Additionally, since the inner surface of the tube wall has a constant temperature T, we can set:
T(r=0) = \(T_{inner\).
To solve this differential equation subject to the given boundary conditions, we can assume a separation of variables solution of the form:
T(r, t) = R(r) Θ(t).
Plugging this into the heat conduction equation, we get:
(R''/R) + (1/r)(R'/R) = (1/(αΘ))(Θ'/Θ) = -λ²,
where λ is the separation constant.
Simplifying, we have:
(zR'' + R')/R = λ²,
and
(Θ'/Θ) = -λ²α,
which gives us two separate ordinary differential equations (ODEs):
rR'' + R' - λ²R = 0, (1)
Θ'/Θ = -λ²α. (2)
Solving equation (2), we have:
Θ(t) = C exp(-λ²αt),
where C is a constant determined by the initial conditions.
Next, let's solve equation (1). This is a second-order linear ODE, and its solution depends on the specific boundary conditions and geometry of the tube wall. Different boundary conditions would result in different solutions.
Once we solve equation (1) and obtain the solution R(r), we can express the general solution for the temperature distribution as:
T(r, t) = R(r) Θ(t).
In the equation T(r, t) = R(r) Θ(t):
T(r, t) represents the temperature at a specific radial position (r) and time (t) within the tube wall.
R(r) represents the radial part of the temperature distribution. It describes how the temperature varies in the radial direction of the tube wall.
Θ(t) represents the time-dependent part of the temperature distribution. It describes how the temperature changes over time.
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give the molecular explanation of of surface tension
Answers
Explanation:
The surface tension of a liquid results from an imbalance of intermolecular attractive forces, the cohesive forces between molecules: A molecule in the bulk liquid experiences cohesive forces with other molecules in all directions. A molecule at the surface of a liquid experiences only net inward cohesive forces.
A 40 kg crate is pulled at a constant velocity. The coefficient of kinetic friction is 0.5 and the crate moves 7 m . How much work is done?
Answers
A 40 kg crate is pulled at a constant velocity. The coefficient of kinetic friction is 0.5 and the crate moves 7 m . The amount of work done is 140 joule.
What is work done?
When an object is moved over a distance by an external force, at least a portion of that force must be applied in the direction of the displacement.
By multiplying the length of the path by the component of the force acting along the path, work can be calculated if the force is constant. The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea.
The work is W = fd cos if the force is applied at an angle of to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as.
Therefore, A 40 kg crate is pulled at a constant velocity. The coefficient of kinetic friction is 0.5 and the crate moves 7 m . The amount of work done is 140 joule.
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how does the relatrinihip between temprature and destiny help to explain why the drop in pressure betweem 2 km and 4km was greater at fairbanks than at key west
Answers
The drop in pressure is greater at Fairbanks than at Key West between 2 km and 4 km. This can be explained by the relationship between temperature and density.
The relationship between temperature and density can be described as follows: as temperature increases, the density of a substance decreases. The same is true in reverse: as temperature decreases, the density of a substance increases. This relationship between temperature and density helps to explain why the drop in pressure between 2 km and 4 km was greater at Fairbanks than at Key West.
This is because Fairbanks is located in a colder climate than Key West. Therefore, the air is colder in Fairbanks than in Key West. Since the air in Fairbanks is colder, it is denser than the air in Key West. As a result, when the air in Fairbanks rises to a higher altitude, it expands and cools, causing it to become even denser. This increase in density results in a greater drop in pressure between 2 km and 4 km at Fairbanks than at Key West.
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Which is not true about the variables in the relationship F = ma?
A. Acceleration is directly proportional to mass.
B. Force is directly proportional to mass.
C. Force is directly proportional to acceleration.
D. Acceleration will double if force is doubled.
Answers
Answer:
A
Explanation:
Because D is definitely true and there is only one false sentence what means if that non of B or C is false because if one is false so other one needs to be too.
A baseball player hits a 0. 15 kg 0. 15kg0, point, 15, start text, k, g, end text baseball that is initially at rest, changing its momentum by 11 kg ⋅ m s 11 s kg⋅m 11, start fraction, start text, k, g, end text, dot, start text, m, end text, divided by, start text, s, end text, end fraction
Answers
The velocity of baseball that was initially at restand changing momentum by 11 kgm/s is 73.3m/s.
How to calculate velocity?We can find the velocity of the player.
Momentum = mass * velocity
Given
Mass = 0.15kg
Momentum = 11kgm/s
Get the velocity
Velocity = Momentum/Mass
Velocity = 11/0.15
Velocity = 73.3m/s
Hence the velocity of the player is 73.3m/s
What is velocity?The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.For more information on momentum kindly visit to
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1.
Convert 450 km/h to m/s.
Answers
Answer:
Do you mean meter per second or Miles per second
Explanation:
If it is meter per second
125 meter per second
If it is miles per second
0.0776714 miles per second
At what point does the ball have the most gravitational potential energy?
Answers
please answer 11-13. say if i'm right for 10 if you can.
Answers
The ratio of the speed of light in a medium to the speed of light in a vacuum
is called its:
A. angle of incidence
B. Snell's Law
C. angle of refraction
D. refractive index
Answers
Answer:D.Refractive Indez
Explanation:
It is usually expressed the other way: the ratio of the speed of light in a vacuum to the speed of light in a medium. In that case, it is called the "index of refraction".
You're going for "refractive index", but you've got the ratio flipped over.
A rock is thrown off a cliff at an angle of 48 degrees above the horizontal. The cliff is 125 m high. The initial speed of the rock is 29 m/s. (Assume the height of the thrower is negligible.) How high above the edge of the cliff does the rock rise (in m)?
Answers
The rock is thrown with an initial speed of 29 m/s at an angle of 48 degrees above the horizontal. We can break down the initial velocity into its horizontal and vertical components. The horizontal component can be calculated as v₀x = v₀ * cos(θ), where v₀ is the initial speed and θ is the angle of projection. Similarly, the vertical component can be calculated as v₀y = v₀ * sin(θ).
Using the given information, we can determine the time it takes for the rock to reach its maximum height. At the highest point of its trajectory, the vertical velocity becomes zero. Using this information, we can find the time using the equation v₀y - gt = 0, where g is the acceleration due to gravity (approximately 9.8 m/s²). Solving for t gives us the time it takes for the rock to reach its maximum height.
Once we have the time, we can calculate the maximum height reached by the rock using the equation h = v₀y * t - (1/2) * g * t². Here, h represents the vertical displacement or the height above the starting point.
To find the height above the edge of the cliff, we subtract the height of the cliff (125 m) from the maximum height calculated earlier.
In summary, the height above the edge of the cliff that the rock rises can be calculated by determining the maximum height reached using the initial velocity components, finding the time to reach that height, and subtracting the height of the cliff from the maximum height.
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Substances that move to the stronger parts of a magnetic field are termed ______ substances; the atomic feature responsible for this property is ______ in atoms.
Answers
Substances that move to the stronger parts of a magnetic field are termed paramagnetic substances; the atomic feature responsible for this property is presence of unpaired electrons in atoms.
What is a paramagnetic substance?A paramagnetic substance is the substance that possess unpaired electrons that are heavily attracted in a magnetic field.
A magnetic field is defined as the field that exists around a magnet that produces a field of force.
Examples of paramagnetic substance include the following:
aluminum, gold, copper.Chromium, andManganese.These substances are known as paramagnetic substances because they possess a high number of unpaired electrons.
Other properties of a paramagnetic substance include the following:
They have a permanent dipole moment or permanent magnetic moment.They are weakly magnetized in the direction of the magnetizing field.They usually have constant relative permeability (μr) slightly greater than 1.Therefore, Substances that move to the stronger parts of a magnetic field are termed paramagnetic substances; the atomic feature responsible for this property is presence of unpaired electrons in atoms.
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) two 0.85-m-long pendulum hang side by side. the masses of the pendulum bobs are 75 g and 95 g. the lighter bob is pulled aside until its string is horizontal and is then released from rest. it swings down and collides elastically with the other bob at the bottom of its arc. to what height does each bob rebound? organize and plan
Answers
The height of each bob rebound is 0.66m.
What is height?Height is the measurement of someone or something.
The velocity with which the 75g bob collides with the 95g bob is u = sqrt(2gl) = 4.12m/s Now th given collsion is headon and elastic therefore the energy and linear momentum of both will be conserves and from the law of conservationists of linear momentum and laws of conservationists of energy we get for lighter (75g) bob
v1 = (m_1 -m_2 \over m_1 +m_2 )u_1 +( 2m_2 \over m_1 +m_2 )u_2
= 0.075-0.095
\over 0.075+ 0.095 ×4.12 + 0
= -0.485 m/s ( -ve sign shows that the bob will move in opp. dir. to its initial dir.)
and v2 = (m_2 -m_1 \over m_1 +m_2 )u_2 +( 2m_1 \over m_1 +m_2 )u_1 = 0 + 2×0.075 \over 0.075+ 0.095 × 4.12 = 3.63 m/s
as at max hieght both the bob will come to rest for a moment then applying v2 - u2 = 2as we get for bob of 95g 0 - 13.21 = -2×10h or h = 13.21/20 = 0.66m for bob height.
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you help your mom move a 401.8n bookcase to a different place in the living room. if you push with a force of 65n and the bookcase accelerates at 0.12 m/s2 , what is the coefficient of friction between the bookcase and the carpet? what is the force of friction?
Answers
The coefficient of friction between the bookcase and the carpet is approximately -0.011. The force of friction is the force that resists the motion of the bookcase. In this case, the force of friction is approximately -44.4 N.
The coefficient of friction is a measure of the resistance to motion between two surfaces in contact. It is defined as the ratio of the force of friction to the normal force, which is the force exerted by one surface on the other perpendicular to the contact surface.
To find the coefficient of friction between the bookcase and the carpet, we can use the following formula:
μ = Ff / Fn
where μ is the coefficient of friction, Ff is the force of friction, and Fn is the normal force.
The force of friction is the force that resists the motion of the bookcase. It is equal to the force you apply to the bookcase minus the acceleration of the bookcase due to that force:
Ff = Fapplied - ma
where Fapplied is the force you apply to the bookcase, m is the mass of the bookcase, and a is the acceleration of the bookcase.
Substituting the given values into this formula, we get:
Ff = 65 N - (401.8 N) × (0.12 m/s2)
Ff = -44.4 N
The normal force is the force exerted by the carpet on the bookcase perpendicular to the contact surface. It is equal to the weight of the bookcase:
Fn = mg
where m is the mass of the bookcase and g is the acceleration due to gravity.
Substituting the given values into this formula, we get:
Fn = (401.8 N) × (9.81 m/s2)
Fn = 3960.6 N
Substituting the values for Ff and Fn into the formula for the coefficient of friction, we get:
μ = (-44.4 N) / (3960.6 N)
μ = -0.011
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