The probability of a woman having breast cancer given she gets a positive test result is 45/10,000 as a fraction.
How we get the result?
Now, let's use Bayes' theorem to calculate the probability that a woman has breast cancer given she gets a positive test result:
P(cancer | 1+) = P(1+ | cancer) × P(cancer) / P(1+)P(cancer | 1+) is the probability of having cancer given a positive test result
P(1+ | cancer) is the sensitivity of the test, or the probability of testing positive given that the person has cancer (in this case, 0.9)
P(cancer) is the prior probability of having cancer, which we don't know, so let's assume it's the prevalence of breast cancer in the population, which is around 0.1% or 0.001
P(1+) is the probability of testing positive, which we can calculate using the sensitivity and specificity of the test:
P(1+) = P(1+ | cancer) × P(cancer) + P(1+ | no cancer) × P(no cancer)= 0.9 × 0.001 + 0.2 × 0.999
= 0.2007
plugging in the values, we get:
P(cancer | 1+) = 0.9 × 0.001 / 0.2007= 0.0045
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The chance that a woman has breast cancer given she gets a positive test result is 0.0827, which can be written as the fraction 827/10000.
When a woman receives a positive test result, the chance that she has breast cancer can be calculated using Bayes' theorem. Here's how:
P (cancer 1 +) = P(cancer) × P(1+ | cancer) / [P(cancer) × P(1+ | cancer) + P(no cancer) × P(1+ | no cancer)]
where:
P(cancer) is the probability of a woman having breast cancer, which is 1% or 0.01 (as given in the problem) P (no cancer) is the probability of a woman not having breast cancer, which is 99% or 0.99 (since there are only two options - having cancer or not having cancer) P (1+ | cancer) is the probability of a positive test result given that a woman has breast cancer, which is 90% or 0.90 (as given in the problem) P (1+ | no cancer) is the probability of a positive test result given that a woman does not have breast cancer, which is 9% or 0.09 (as given in the problem)
Now, let's substitute the given values in the formula: P (cancer 1 +) = 0.01 × 0.90 / [0.01 × 0.90 + 0.99 × 0.09]= 0.0081 / 0.0981= 0.0827.
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what is 0.675 as a percent
Answer:
67.5
Step-by-step explanation:
Answer:67.5
Step-by-step explanation:0.675*100=67.5
When a fixed bridge is created, there must be at least_______of the bridge
Answer: One abutment
Step-by-step explanation: When a fixed bridge is created, there must be at least one abutment of the bridge.
find the value of x²+y² if
x+y=9 xy=14
Step-by-step explanation:
It's a system of equations.
From the first one we isolate x:
x = 9-y
And we substitute in the second one:
(9-y)y = 14
-y^2 + 9y - 14 = 0
y^2 - 9y + 14 = 0
D = 25
y1/2 = (9 +- 5)/2 = 2 or 7
y = 2 => x = 7
y = 7 => x = 2
x^2 + y^2 = 7^2 + 2^2 = 53
I need help please im struggling on this
Answer:
3^2+4^2=7^2
√7^2
7
Answer: c= 5
Given a=4 and b=3,
c = 5
Step-by-step explanation: Given a=4 and b=3,
c = 5
∠α = 53.13° = 53°7'48" = 0.9273 rad
∠β = 36.87° = 36°52'12" = 0.6435 rad
area = 6
perimeter = 12
h =
12
5
= 2.4
Two vertical angles have measures (4x-21)° and (x+6)°. Find the measures of the angles
The measure of the two vertical angles is 15°
The two vertical angles have measures (4x-21)° and (x+6)°
Note that:
The measure of two vertical angles are equal
Therefore, equate (4x-21)° and (x+6)° and solve for x
(4x-21)° = (x+6)°
4x - 21 = x + 6
Collect like terms
4x - x = 6 + 21
3x = 27
x = 27/3
x = 9
Substitute x = 9 into 4x - 21
4x - 21 = 4(9) - 21
4x - 21 = 15°
Substitute x = 9 into x + 6
x + 6 = 9 + 6
x + 6 = 15°
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Autumn buys a bag of cookie that contain 8 chocolate chip cookie 4 peanut butter cookie 9 sugar cookie and 6 oatmeal cookie what is the probability that autumn randomly select a chocolate chip cookie from the back then randomly select a sugar cookie round the solutions of 4 decimal places
This is a simple probability problem to solve, first, we need to know how many cookies we have inside the bag. So we have 8 chocolate chip cookies + 4 peanut butter cookies + 9 sugar cookies + 6 oatmeal cookies = 27 cookies (total). Once we have the total we can see the probability to first randomly select a chocolate chip cookie is P (first chocolate chip cookie) = 8/27 (we just have 8 chances to select a chocolate chip cookie between 27 cookies).
After we select a chocolate chip cookie and eat it, now we just have 26 cookies inside the bag. So our probability to select randomly a sugar cookie is P (sugar cookie second) = 9/26 (we just have 9 chances to select a sugar cookie between 26 cookies). Now we just need to combine those two probabilities, and to do that as a sequence (probability 1 first, next probability 2) we use the product operator *. So P(chocolate chip cookie first and sugar cookie second) = P (first chocolate chip cookie) * P (sugar cookie second) = (8/27) * (9/26) = 72/702.
Finally, our final answer is P(chocolate chip cookie first and sugar cookie second) = 0.1025 (approximately).
fernando competed in an 80 mile bike race. after 0.5 hour, he had ridden 9 miles. after 1 hour of riding, fernando had biked 18 miles. assuming he was traveling at a constant speed, how far will fernando have traveled after 3.5 hours?
Fernando will have traveled 63 miles after 3.5 hours.
To find the distance Fernando will have traveled after 3.5 hours, we can determine his average speed and then calculate the total distance covered.
We are given that after 0.5 hours, Fernando had ridden 9 miles, and after 1 hour, he had ridden 18 miles. By comparing these two data points, we can see that Fernando is traveling at a constant speed of 18 miles per hour.
To calculate the distance traveled after 3.5 hours, we can multiply the speed (18 miles per hour) by the time (3.5 hours):Distance = Speed × Time = 18 miles/hour × 3.5 hours = 63 miles.
Therefore, Fernando will have traveled 63 miles after 3.5 hours.
It is important to note that this calculation assumes a constant speed throughout the entire race. If the speed varied during the race, the result may be different. However, based on the given information of constant speed, we can conclude that Fernando will have traveled 63 miles after 3.5 hours.
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Help , I don’t know how to solve this
Answers in bold:
S9 = 2
i = 20
R = -2
=====================================================
Explanation:
\(S_0 = 20\) is the initial term because your teacher mentioned \(A_0 = I\) as the initial term.
Then R = -2 is the common difference because we subtract 2 from each term to get the next term. In other words, we add -2 to each term to get the next term.
Here is the scratch work for computing terms S1 through S4.
\(\begin{array}{|l|l|}\cline{1-2}S_{n} = S_{n-1} - 2 & S_{n} = S_{n-1} - 2\\S_{1} = S_{1-1} - 2 & S_{2} = S_{2-1} - 2\\S_{1} = S_{0} - 2 & S_{2} = S_{1} - 2\\S_{1} = 20 - 2 & S_{2} = 18 - 2\\S_{1} = 18 & S_{2} = 16\\\cline{1-2}S_{n} = S_{n-1} - 2 & S_{n} = S_{n-1} - 2\\S_{3} = S_{3-1} - 2 & S_{4} = S_{4-1} - 2\\S_{3} = S_{2} - 2 & S_{4} = S_{3} - 2\\S_{3} = 16 - 2 & S_{4} = 14 - 2\\S_{3} = 14 & S_{4} = 12\\\cline{1-2}\end{array}\)
Then here is S5 though S8
\(\begin{array}{|l|l|}\cline{1-2}S_{n} = S_{n-1} - 2 & S_{n} = S_{n-1} - 2\\S_{5} = S_{5-1} - 2 & S_{6} = S_{6-1} - 2\\S_{5} = S_{4} - 2 & S_{6} = S_{5} - 2\\S_{5} = 12 - 2 & S_{6} = 10 - 2\\S_{5} = 10 & S_{6} = 8\\\cline{1-2}S_{n} = S_{n-1} - 2 & S_{n} = S_{n-1} - 2\\S_{7} = S_{7-1} - 2 & S_{8} = S_{8-1} - 2\\S_{7} = S_{6} - 2 & S_{8} = S_{7} - 2\\S_{7} = 8 - 2 & S_{8} = 6 - 2\\S_{7} = 6 & S_{8} = 4\\\cline{1-2}\end{array}\)
And finally we arrive at S9.
\(S_{n} = S_{n-1} - 2\\\\S_{9} = S_{9-1} - 2\\\\S_{9} = S_{8} - 2\\\\S_{9} = 4 - 2\\\\S_{9} = 2\\\\\)
--------------------
Because we have an arithmetic sequence, there is a shortcut.
\(a_n\) represents the nth term
S9 refers to the 10th term because we started at index 0. So we plug n = 10 into the arithmetic sequence formula below.
\(a_n = a_1 + d(n-1)\\\\a_n = 20 + (-2)(n-1)\\\\a_n = 20 - 2(n-1)\\\\a_{10} = 20 - 2(10-1)\\\\a_{10} = 20 - 2(9)\\\\a_{10} = 20 - 18\\\\a_{10} = 2\\\\\)
In other words, we start with 20 and subtract off 9 copies of 2 to arrive at 20-2*9 = 20-18 = 2, which helps see a faster way why \(S_9 = 2\)
Use the Euclidean algorithm to find ged(707, 413), and find integers s, t such that 707s + 413t = gcd (707,413). (b) Are there integers x, y such that 707x +413y = 9? If there are, give an example. If there are no such r, y, then prove it.
a) Using the Euclidean algorithm, we can find gcd (707,413) as follows:707 = 1 · 413 + 294413 = 1 · 294 + 119294 = 2 · 119 + 562119 = 2 · 56 + 71356 = 4 · 71 + 12 71 = 5 · 12 + 11 12 = 1 · 11 + 1
Thus, gcd (707,413) = 1.
We can find the coefficients s and t that solve the equation 707s + 413t
= 1 as follows:1 = 12 - 11 = 12 - (71 - 5 · 12) = 6 · 12 - 71 = 6 · (119 - 2 · 56) - 71
= - 12 · 56 + 6 · 119 - 71
= - 12 · 56 + 6 · (294 - 2 · 119) - 71 = 18 · 119 - 12 · 294 - 71
= 18 · 119 - 12 · (413 - 294) - 71 = 30 · 119 - 12 · 413 - 71
= 30 · (707 - 1 · 413) - 12 · 413 - 71 = 30 · 707 - 42 · 413 - 71
Thus, s = 30, t = -42. So we have found that 707(30) + 413(−42) = 1.
b) Since 707s + 413t = 1 and 9 does not divide 1, the equation 707x + 413y = 9 has no integer solutions. Therefore, we can conclude that there are no such integers x and y.
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Based on data from 2011-2012, the percentage of 6- to 11-year-olds who were obese was about _____ than the percentage of two- to five-year-olds who were obese.
Using the percentage concept, it is found that the percentage of 6- to 11-year-olds who were obese was about 17.76% more than the percentage of two- to five-year-olds who were obese.
What is a percentage?The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:
\(P = \frac{a}{b} \times 100\%\)
Researching on the internet, we find that:
The percentage of two-to-five year old who are obese is of a = 15.2%.The percentage of 6-to-11 year old who are obese is of b = 17.9%.Hence:
\(P = \frac{17.9}{15.2} \times 100\% = 117.76\%\)
117.76% - 100% = 17.76%.
Hence the percentage of 6- to 11-year-olds who were obese was about 17.76% more than the percentage of two- to five-year-olds who were obese.
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At the circus, an acrobat is shot straight upwards out of cannon that is 2 meters from the ground. After 2.6 seconds, the acrobat lands in a safety net that is 1.076 meters from the ground. The formula h=−4.9t2+vt+(initialheight) gives the height h of the acrobat (in meters) at any time t seconds after being shot from the cannon at a velocity of v meters per second from an initial height (in meters.) Identify each known quantity that can be substituted into the equation to find the missing value in this scenario. For the missing value, select "not given."
To solve for missing values, the number of missing values should be equal to the number of equations. The number of missing values that can be present given only one equation is one missing value
From the question, the known quantities are;
h (known) = 1.076 meters
t (known) = 2.6 seconds
(Initialheight) (known) = 2 meters
The missing value is the velocity;
v (not given)
The reason the above elections are correct is as follows:
The known parameters are;
The (initial) height of the cannon from the ground = 2 meters
The time after which the acrobat lands, t = 2.6 seconds
The height of the safety net on which the acrobat lands, h = 1.076 meters
The formula that gives the height, h, to which the acrobat reaches after being shot from the canon is; h = -4.9·t² + v·t + (initialheight)
Where;
h = The height of the acrobat after being shot or launched from the cannon (known)
The height of the acrobat after the given time, h = 1.076 meters
t = The time in seconds after being shot (Known)
The time is given as 2.6 seconds
v = The velocity with which the acrobat was shot out of the cannon (not given)
The velocity with which the acrobat was shot out of the cannon is the missing value
(Initialheight) = The initial height of the acrobat before he was shot from the cannon (known)
The initial height of the was given as the height of the cannon off the ground which is 2 meters
Therefore, the known quantity or quantities that can be substituted into the equation to find the missing value in the scenario are;
h (known) = 1.076 meters
t (known) = 2.6 seconds
(Initialheight) (known) = 2 meters
The missing value is the velocity, v;
v (not given)
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Put the following numbers into the correct box below:
3, 8, 15, 10, 2
Factors of 15:
Factors of 40:
Answer:
15: 15,3
40: 8,10,2
Step-by-step explanation:
Can someone help me with this math (I'll give brainliest)
Answer:
1/y^9= y^-9
1/m^15= m^-15
n^3=n^3
1/m^6=m^-6
n^4
w^12
1/32=2^-5
-6=(-6)^1
1^1
Step-by-step explanation:
Step-by-step explanation:
Use the exponent laws to identify which law to use.
1. y^-4 * y^-5 = y^-9
(add the exponents)
2. (m^-3)^5 = m^-3*5 = m^-15
(multiply the exponents)
3. n^-3 * n^6 = n^3
(add the exponents)
4. m^-12/m^-6 = m^-12-(-6) = m^-6
(subtract exponents)
5. (n^-2)^-2 = n^-2*-2 = n^4
(multiply the exponents)
6. w^5/w^-7 = w^5-(-7) = w^12
(subtract the exponents)
7. 2^-3 * 2^-2 = 2^-5
(add the exponents)
8. (-6)^4 * (-6)^-3 = -6^1
(add the exponents)
9. (4^-6)^0 = 4^-6*0 = 4^0 = 1
(multiply the exponents)
A scatterplot of student height, in inches, versus corresponding arm span length, in inches, is shown below. One of the points in the graph is labeled a.
The variables on the horizontal and vertical axes of a scatter plot are always continuous.Corresponding: When two sets of data are plotted on a scatter plot, each data point in the two sets has a corresponding point in the other set.
When you plot two sets of data on a scatter plot, you should use different colors or symbols for the data points from each set.The horizontal axis represents one variable while the vertical axis represents the other. Each point on the graph represents one set of data that corresponds to both variables, with the x-value and y-value corresponding to the respective data points being plotted.Scatterplot versus: A scatter plot has two axes that correspond to two variables. In a scatter plot, we can determine how one variable changes as the other variable changes. The variables on the horizontal and vertical axes of a scatter plot are always continuous.Corresponding: When two sets of data are plotted on a scatter plot, each data point in the two sets has a corresponding point in the other set. When you plot two sets of data on a scatter plot, you should use different colors or symbols for the data points from each set.
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Find the distance between the points (-8,-9)and (-3,3)
Answer:
13
Step-by-step explanation:
Use the distance formula and plug in both points
Answer:
its either 11 or 13 im not sure
Step-by-step explanation:
If a population has a frequency of q = 0. 25, what is the frequency of p? 0. 05 0. 25 0. 50 0. 75.
Alleles in a population are represented as p and q, with p being the dominant allele and q being the recessive allele. In a population, the frequency of the alleles p and q must equal
1. If q equals 0.25, then p equals 0.75. This is because p + q = 1, so p = 1 - q. In this case, p = 1 - 0.25 = 0.75
.The frequency of p in this population is 0.75.
A resource population is any part of the environment that can be used to meet another organism's needs.
The first population acts as this because the second population is surviving by eating the first.
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is y=3x(x+5) linear or nonlinear?
Answer:
linearStep-by-step explanation:
Solve for x and not to scale
Answer:
x = 90
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are in proportion, that is
\(\frac{BC}{NE}\) = \(\frac{AB}{TN}\) , substitute values
\(\frac{3}{27}\) = \(\frac{10}{x}\) ( cross- multiply )
3x = 270 ( divide both sides by 3 )
x = 90
why is 70.300722 a rational number
Answer:
35150361
________
5000000
What is the domain of this table?
A is the answer
Domain is all x-values and Range is y-values.
Hope this helps!!:)
cos(7π/6)= a. 1/2 b.-1/2 c.√3/2 d.-√3/2 Help please?
Answer:
D. -√3/2
Step-by-step explanation:
Remember your unit circle.
Alternatively, you can plug in cos(7π/6) into your calc (Put it in rad mode) and calculate your answer.
Answer:
D. -√3/2
Step-by-step explanation:
im having trouble with this problem and I was wondering what Y is. here is the question.
(-1.4)= 0.6y - 1.1
Answer: -0.5
Step-by-step explanation: screenshot
Answer:
-0.2
Step-by-step explanation:
So the Equation is -1.4=0.6y-1.1, so to get the variable by itself, you would need to add 1.1 to both sides. Leaving you with -0.3=0.6y. so divide each side by -0.3. Leaving you with -0.2 hope this helps :)
the height of the tide in a small beach town is measured along a seawall. water levels oscillate between 5 feet at low tide and 15 feet at high tide. on a particular day, low tide occurred at 6 am and high tide occurred at noon. approximately every 12 hours, the cycle repeats. find an equation to model the water levels
The height of the tide in a small beach town is measured along a seawall. Water levels oscillate between 5 feet at low tide and 15 feet at high tide. On a particular day, low tide occurred at 6 am and high tide occurred at noon. Approximately every 12 hours, the cycle repeats.
To find an equation to model the water levels, we can use a sinusoidal equation. Let h(t) be the height of the water at time t (in hours). We know that h(6) = 5 and h(12) = 15. Using this information, we can find the equation:
h(t) = 10 sin (πt/6) + 10
To find an equation that models the water levels in a small beach town, given that the height of the tide is measured along a seawall, we need to use the following information:
Water levels oscillate between 5 feet at low tide and 15 feet at high tide. Low tide occurred at 6 am, and high tide occurred at noon. The cycle repeats approximately every 12 hours. Let the water level at low tide be represented by y = 5, and the water level at high tide be represented by y = 15. We can write these points as (0,5) and (12,15), respectively. Since the water levels oscillate every 12 hours, we can create a sine function that models this pattern. We can use the sine function y = a sin(bx + c) + d, where a is the amplitude (half the height of the wave), b is the frequency (number of waves per unit time), c is the phase shift (horizontal displacement of the wave), and d is the vertical displacement of the wave. Using the given information, we can determine the values of a, b, c, and d:a = (15 - 5)/2 = 5, since the amplitude is half the height of the wave. b = 2π/12 = π/6, since the wave repeats every 12 hours (or twice a day), and the period is 2π/b.c = -π/2, since the graph starts at high tide (the maximum point), not at the midpoint between low and high tide (the x-axis).d = (15 + 5)/2 = 10, since the midpoint between low and high tide is the vertical axis of the sine function. Therefore, the equation that models the water levels is: y = 5 sin(π/6 x - π/2) + 10.
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Someone help me out please
Hey there!
150 = 8x + 6y
↠ 150 = 8x + 6(9)
↠ 8x + 6(9) = 150
↠ 8x + 54 = 150
SUBTRACT 54 to BOTH SIDES
8x + 54 - 54 = 150 - 54
CANCEL out: 54 - 54 because that gives you 0
KEEP: 150 - 54 because helps solve for x
↣150 - 54 = 96↢
NEW EQUATION: 8x = 96
DIVIDE 8 to BOTH SIDES
8x/8 = 96/8
CANCEL out: 8/8 because that gives you 1
KEEP: 96/8 because that gives the value of x
96/8 = x
x = 12
Answer: x = 12
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
could anyone help me out on this question?
The value of F when C = 10, is 50°.
Given is an equation, F = 9/5 C + 32
We need to solve for F if C = 10°,
So,
To find the same put C = 10°,
F = 9/5 × 10° + 32
F = 9 × 2 + 32
F = 18 + 32
F = 50°
Hence the value of F when C = 10, is 50°.
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Use the alternative curvature formula k = |a x v|/|v|^3 to find the curvature of the following parameterized curve.
r(t) = ⟨7cost,√2sint,2cost⟩
k = ____
The curvature (k) of the parameterized curve r(t) = ⟨7cost, √2sint, 2cost⟩ is given by the expression involving trigonometric functions and constants.
To find the curvature of the parameterized curve r(t) = ⟨7cos(t), √2sin(t), 2cos(t)⟩, we need to compute the magnitude of the cross product of the acceleration vector (a) and the velocity vector (v), divided by the cube of the magnitude of the velocity vector (|v|^3).
First, we need to find the velocity and acceleration vectors:
Velocity vector v = dr/dt = ⟨-7sin(t), √2cos(t), -2sin(t)⟩
Acceleration vector a = d^2r/dt^2 = ⟨-7cos(t), -√2sin(t), -2cos(t)⟩
Next, we calculate the cross product of a and v:
a x v = ⟨-7cos(t), -√2sin(t), -2cos(t)⟩ x ⟨-7sin(t), √2cos(t), -2sin(t)⟩
Using the properties of the cross product, we can expand this expression:
a x v = ⟨2√2sin(t)cos(t) + 14sin(t)cos(t), -4√2sin^2(t) + 14√2sin(t)cos(t), 2sin^2(t) + 14sin(t)cos(t)⟩
Simplifying further:
a x v = ⟨16√2sin(t)cos(t), -4√2sin^2(t) + 14√2sin(t)co s(t), 2sin^2(t) + 14sin(t)cos(t)⟩
Now, we can calculate the magnitude of the cross product vector:
|a x v| = √[ (16√2sin(t)cos(t))^2 + (-4√2sin^2(t) + 14√2sin(t)cos(t))^2 + (2sin^2(t) + 14sin(t)cos(t))^2 ]
Finally, we divide |a x v| by |v|^3 to obtain the curvature:
k = |a x v| / |v|^3
Substituting the expressions for |a x v| and |v|, we have:
k = √[ (16√2sin(t)cos(t))^2 + (-4√2sin^2(t) + 14√2sin(t)cos(t))^2 + (2sin^2(t) + 14sin(t)cos(t))^2 ] / (49sin^4(t) + 4cos^2(t)sin^2(t))
The expression for k in terms of t represents the curvature of the parameterized curve r(t).
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i need help ASAP please and thank you !!!!!!!
Answer: He would make $1,170 a week.
Step-by-step explanation:
He makes $400 a week.
$55 per appliance sold, he sold 14 appliances.
$55 x 14 = $770
$400 + $770 = $1,170
Hope this helps!:)
Calculate the distance of line segment AB.
1 pm
B
A
24 cm
10 cm
с
14
O 25
O 28
0 26
O 31
Answer:
26 cm
Step-by-step explanation:
\(a^{2} +b^2=c^2\)
\(24^2+10^2=c^2\)
576 + 100 = 676
\(\sqrt{676}\) = 26 cm
can someone help me with this
Answer:
29
Step-by-step explanation:
On the number line below, length
AB = [?]
A
В
16
45
Answer:
29
Step-by-step explanation:
45 - 16 =