Answer:
The acceleration of the proton is 1.403 x 10⁹ m/s²
Explanation:
Given;
speed of proton, v = 7.7 m/s
magnitude of magnetic field, B = 1.9 T
Magnetic force of moving proton is given by;
F = qvBsinθ
Centripetal force on the moving proton is given by;
\(F = m(\frac{v^2}{r})\\\\F = m(a_c) \\\\a_c \ is \ the \ centripetal \ acceleration\)
\(qvBsin\theta = ma_c\\\\ac = \frac{qvBsin(90)}{m}\)
where;
q is charge of the proton = 1.602 x 10⁻¹⁹ C
m is mass of proton = 1.67 x 10⁻²⁷ kg
\(ac = \frac{(1.602*10^{-19})(7.7)(1.9)sin(90)}{1.67*10^{-27}}\\\\a_c = 1.403*10^{9} \ m/s^2\)
Therefore, the acceleration of the proton is 1.403 x 10⁹ m/s²
Draw a free body diagram showing all forces acting on the air cart, including the extra
force that may be causing a discrepancy between your numbers.
A free body diagram is a visual representation of all the forces acting on an object.
What is a free body diagram?A free body diagram is a visual representation of all the forces acting on an object. It is a tool commonly used in physics to help analyze the motion of an object.
What are the forces acting?In the case of an air cart, the forces acting on the cart might include the force of gravity pulling the cart downward, the normal force of the surface supporting the cart pushing upward, and the force of air resistance acting against the cart as it moves through the air. There may also be other forces at play, depending on the specific situation, such as an applied force from a fan or a motor driving the cart forward.
If there is an extra force causing a discrepancy between your numbers, you would also include this force on the free body diagram, with an arrow representing the magnitude and direction of the force
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Kingda Ka has a maximum speed of 57.2 m/s. Determine the height of the hill on this roller coaster. Explain to get full credit, show work!
This question involves the concepts of the law of conservation of energy, kinetic energy, and potential energy.
The height of the hill is "166.76 m".
LAW OF CONSERVATION OF ENERGY:According to the law of conservation of energy at the highest point of the roller coaster ride, that is, the hill, the whole (maximum) kinetic energy of the roller coaster is converted into its potential energy:
\(Maximum\ Kinetic\ Energy\ Lost = Maximum\ Potential\ Energy\ Gain\\\\ \frac{1}{2}mv_{max}^2=mgh\\\\ h=\frac{v_{max}^2}{2g}\)
where,
h = height of the hill = ?\(v_{max}\) = maximum velocity = 57.2 m/sg = acceleration due to gravity = 9.81 m/s²Therefore,
\(h=\frac{(57.2\ m/s)^2}{2(9.81\ m/s^2)}\\\\ \)
h = 166.76 m
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Specialization can be both limiting and beneficial. How would a plant species benefit from a pollinator that only visits the flowers of that plant species?
less competition for pollinators with other species
Explanation: just took this test and got a 100
Answer:
less competition with other species
Explanation:
just took the test
Simple Pendulum: A 34-kg child on an 18-kg swing set swings back and forth through small angles. If the length of the very light supporting cables for the swing is 4.9 m, how long does it take for each complete back-and-forth swing
Answer:
The correct answer is "4.443 sec".
Explanation:
Given:
Mass of child,
= 34 kg
Mass of swing,
= 18 kg
Length,
= 4.9 m
The time period of pendulum will be:
T = \(2 \pi \sqrt{4g}\)
= \(2 \pi \sqrt{\frac{4.9}{9.8} }\)
= \(4.443 \ sec\)
Answer:
The time taken to back and forth is 4.4 s .
Explanation:
Length, L = 4.9 m
let the time period is T.
Acceleration due to gravity, g = 9.8 m/s^2
Use the formula of time period
\(T = 2 \pi\sqrt{L}{g}\\\\T = 2 \times 3.14\sqrt{4.9}{9.8}\\\\T = 4.4 s\)
Each tire on a car has a radius of 0.330 m and is rotating with an angular speed of 13.9 revolutions/s. Find the linear speed v of the car, assuming that the tires are not slipping against the ground.
Answer:
the linear speed of the car is 28.83 m/s
Explanation:
Given;
radius of the car, r = 0.33 m
angular speed of each tire, ω = 13.9 rev/s = 13.9 x 2π = 87.35 rad/s
The linear speed of the car is calculated as;
V = ωr
V = 87.35 rad/s x 0.33 m
V = 28.83 m/s
Therefore, the linear speed of the car is 28.83 m/s
In an experiment, a student measured the volume of a substance while the mass was changed. The student measured up to five kilograms. The graph of the data is plotted below.
A volume versus mass graph is shown with mass on the vertical axes from 1 to 10 kilograms and volume on the horizontal axis from 1 to 5 milliliters. A line from the origin through all points and beyond.
Which of the following is an error the student made in creating an accurate graph?
The axes and graph are based only on measured values.
The axes are labeled with the incorrect variables.
The plotted points do not show all data collected.
The title has the incorrect order for the variables.
The graph is incorrect because; the title has the incorrect order for the variables. Option D
What is a graph?We know that a graph is made up of two parts. It has two axes and these are what we call the parts of the graph. It is common that we would have the independent variable on the x axis and then we have the dependent variable on the y axis.
With this said, we would now have to look at the graph that has been attached so that we can be able to see what the error in the graph that has been plotted as shown is and how the error that is in the graph can be able to be correct as the student is trying to pass information by the use of a graph system.
The title of the graph can be seen to show that the volume rather than the mass is plotted on the y axis.
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Four identical charges particles of charge 1Uc, 2Uc,
3Uc and 4Uc
are placed at x = lm, x=2m,
x=3m and
x=5m. The electric field intensity
at origin is?
Answer:
17.94 kN/C is the electric field intensity at the origin due to the charges.
Explanation:
From the question, we are told that
The distance of 1 μC from origin = 1 m
The distance of 2 μC from origin = 2 m
The distance of 3 μC from origin = 3 m
The distance of 4 μC from origin = 5 m
Therefore, for us to find the electric field intensity, we'll solve below:
The formula for Electric field intensity = ( k * q ) / ( r * r )
where , r is distance ,
k = 9 * 10^9 ,
and , q is charge .
now ,
electric field intensity at the origin = [ k * 10^(-6) / 1 * 1 ] +[ k * 2 * 10^(-6) / 2 * 2 ] + [ k * 3 * 10^(-6) / 3 * 3 ] + [ k * 4 * 10^(-6) / 5 * 5 ]
=> electric field intensity at the origin = k * 10^(-6) [ 1 + 1/2 + 1/3 + 4/25 ] N/C
=> electric field intensity at the origin = 9 * 10^9 * 10^(-6) * 1.99 N/C
=> electric field intensity at the origin = 17.94 kN/C
Please refer to picture for the question. Stuck on Part A and B. Thanks
The stopping distances are found to be 218.13 m and 149 m, respectively, for
a = -2.6 m/s²
b = -5.5 m/s² with time 0.3 s.
What, in Newton's view, determines motion?Newton's equations of motion link an object's motion to the forces acting on it. According to the first law, an object won't change its motion until a force is applied to it. The second law states that an object's force can be determined by multiplying its mass by its acceleration. The third law states that when two things come into contact, they put equal and opposing pressures on one another.
According to the given information:Initial speed = U = 94Km/hr
=> 26.11m/s
a1 = -2.6m/s²
a2 = -5.5 m/s²
Final velocity = V = 0
t= 0.3sec
A) the stopping distance with a1 = -2.6m/s²:
V² = U² +2as
=> 0 = 26.11² + 2 x -2.6 x s
S=> 131.1 m
the stopping distance
=> 26.11/0.3 + 131.1
=> 218.13m
B) the stopping distance with a2 = -5.5 m/s²:
V² = U² +2as
=> 0 = 26.11² + 2 x -5.5 x s
S=> 61.97 m
the stopping distance
=> 26.11/0.3 + 61.97
=> 149m
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What is the extension force (in lbf) of a 14 inch diameter cylinder with a 10 inch rod and pressure of 700psi?
The given problem can be exemplified in the following diagram:
To determine the extension force we will use the definition of pressure:
\(P=\frac{F}{A}\)Where "F" is the force, and "A" is the area. To determine the area we will use the following equation:
\(A=\frac{\pi D^2}{4}\)Where "D" is the diameter. The force acts over the area of the 10 inches diameter alone, therefore we don't need to have into account the area of the rod. Replacing the value of the diameter we get:
\(A=\frac{\pi(14in)^2}{4}\)Solving the operation:
\(A=153.94in^2\)Replacing in the formula for the pressure we get:
\(P=\frac{F}{153.94in^2}\)Since we are required to determine the force, we will multiply both sides by the area:
\(153.94in^2P=F\)Replacing the given value of the pressure we get:
\((153.94in^2)(700\frac{lbf_{}}{in^2})=F\)Solving the operations we get:
\(107756.62lb_f\)Therefore, the extension force is 107756.62 lbf.
The tiny sparks are at a very high t__________
Explanation:
temperature o temperatura
The diameter of the asteroid Vesta is of the diameter of the planet Mercury. Mercury has a diameter of 5000 km. Calculate the diameter of Vesta. Show your working.
Answer:
5000 km
Explanation:
Sure, to calculate the diameter of Vesta, we can use the fact that Vesta's diameter is equal to the diameter of Mercury, which is 5000 km.
Therefore, the diameter of Vesta is also 5000 km.
We can show the working by using the following formula:
Diameter of Vesta = Diameter of Mercury
Diameter of Vesta = 5000 km
What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?
Answer:
PE = 137.2931 J
Explanation:
PE = 137.2931 J
Name:.
Date:
Homework: Writing an Argument About
Australia's Skin Cancer Rate
G
4
You now have enough evidence to explain why Australia's skin cancer rate is so high. Review your
argument from Chapter 2 and think about how you will convince the AHA that both Claim 2 and
Claim 3 are accurate. You will use your completed Reasoning Tool from Activity 3 to revise and add to
your argument.
Question: Why is the skin cancer rate in Australia so high?
According to the principal of superposition,
Answer:
the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.
Explanation:
imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line
the fact that entropy is always increasing is demonstrated by
The fact that entropy is always increasing is demonstrated by several everyday examples, such as ice melting, clocks running down, dead organisms decaying, and mountains crumbling.
The second law of thermodynamics, which states that the entropy of an isolated system will always increase over time. Entropy is a measure of disorder or randomness in a system, and the second law states that in any natural process, the entropy of a system will always increase or stay the same. This means that energy will always flow from a higher state of organization to a lower state of organization, and that systems will naturally tend towards a state of maximum disorder.
ThIs is demonstrated by many everyday examples, such as the fact that ice melting will not reassemble itself, clocks running down will not get back itself to the previous time, or dead organisms decaying will not assemble itself back in the complete form.
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Which of the following explanations represents why taste aversion breaks the rules of conditioning?
A. Taste aversion requires no cognitive processes in order to develop.
B. Taste aversion is a learned response that does not occur without cognition.
C. Taste aversion can develop after only one pairing of a stimulus and response.
D. Taste aversion cannot be explained by using conditioning processes.
Answer:
C. Taste aversion can develop after only one pairing of a stimulus and response.
Explanation:
Taste aversion is a unique type of learned response where an individual develops a strong aversion or avoidance to a specific taste or food after a single pairing of that taste with a negative reaction, such as nausea or illness. This is in contrast to traditional conditioning, where multiple pairings of a stimulus and response are typically required for learning to occur. Taste aversion demonstrates a unique rapidity and specificity in its development, which deviates from the general principles of conditioning.
Which of these statements is true?
a) Neither (a) nor (b) is true.
b) Both (a) and (b) are true.
c) Electric current is stored in the battery of a circuit.
d) Electric current is the flow of electrons in a circuit.
Answer:
d electric current is the flow of electrons in a circuit
4. Interpret Data The graph below shows the
motion of an elevator. Explain its motion.
Answer:
Below
Explanation:
0-1 sec descends at constant rate from 10 to 6 m
1-2 sec stops at 6m
2-3 sec descends at constant rate to 2 m
3-4 sec stops at 2 m
4-5 sec descends at another constant rate to 0 m
There are four springs stretched by the same mass. Spring A stretches 25 cm. Spring B stretches 10 cm. Spring C stretches 100 cm.
Spring D stretches 1 cm.
Which spring is the weakest?
O B
D C
Answer:
spring D stretches the weakest
Formula:
a= F/m
F= mxa
m=F/a
1. A little boy pushes a wagon with his dog in it. The mass of the dog andwagon together is 50 kg. The wagon accelerates at 0.85 m/s2. What force
is the boy pulling with?
Answer:
42.5 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 50 × 0.85
We have the final answer as
42.5 NHope this helps you
A uniformly charged sphere has a total charge of 300uc and a radius of 8cm . Find the electric field density at a point on the surface of the sphere
Answer:
1.05×108NC−1,1.17×108NC−1, zero
Explanation:
A uniformly charged sphere has a total charge of 300muC and radius of 8 cm. find the electric field (i) at a point 16 cm from the centre of the sphere (ii) at a point on the surface of the sphere (iii) at a point inside the sphere.
CARRY ON LEARNING
Why are theories constructed
A) During the experiment
B) after data is collected from an experiment
C) before the experiment
D) after there is numerous data collected
Answer:
The correct answer is d.
Theories are constructed after there is numerous data collected during the experiment.
Explanation:
hope it helps
Running up the stairs, Emily was able to lift her 80 kg body a total of 5 m in approximately 3.5
seconds. Determine her power.
Answer:
P = W / t work/time
W(ork) = m g h = 80kg * 9.8 m.s^2 * 5 m = 3920 N-m
P = 3920 N-m / 3.5 s = 1120 Watts
15. A pattern of weather and
climate over three months is called a
Answer:
Explanation:
weather pattern
A pattern of weather over three months is called a climate.
What is climate?Climate is the long-term pattern of weather in a particular area. Weather can change from hour-to-hour, day-to-day, month-to-month or even year-to-year. A region's weather patterns, usually tracked for at least 30 years, are considered its climate.
Weather refers to short-term changes in the atmosphere, climate describes what the weather is like over a long period of time in a specific area.
A pattern of weather over three months is called a climate.
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A stone of mass 6.74kg is dropped from rest at a height of 6.02m. What impulse does gravity impart to this stone from the instant is dropped until it hits the ground, assuming negligible air resistance?
The impulse the gravity imparts on the stone from the instant it was dropped until it hits the ground is 72.66 Ns
What is impulse?
This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final moment – Initial momentum
Impulse = force × time
How to determine the timeInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 6.02 mTime (t) =?h = ½gt²
6.02 = ½ × 9.8 × t²
6.02 = 4.9 × t²
Divide both side by 4.9
t² = 6.02 / 4.9
Take the square root of both side
t = √(6.02 / 4.9)
t = 1.1 s
How to determine the impulseTime (t) = 1.1 sMass (m) = 6.74 kgAcceleration due to gravity (g) = 9.8 m/s²Force (F) = mg = 6.74 × 9.8 = 66.052 NImpulse =?Impulse = Force × time
Impulse = 66.052 × 1.1
Impulse = 72.66 Ns
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calculate the density of 1mole of oxygen ata pressure of 4×10^-4Nm^-2 and a temprature of 273.2°K
The density of 1 mole of oxygen at a pressure of 4×10⁻⁴ Nm⁻² and a temprature of 273.2 K is 2.82×10⁻⁶ g/m³
How to determine the density of oxygenWe'll begin by obtaining the volume of the oxygen. This can be obtained as follow:
Number of mole (n) = 1 molePressure (P) = 4×10⁻⁴ Nm⁻²Temperature (T) = 273.2 K Gas constant (R) = 8.314 m³Nm⁻²/KmolVolume = ?PV = nRT
Divide both sides by P
V = nRT / P
V = (1 × 8.314 × 273.2) / 4×10⁻⁴
V = 5678462 m³
Finally, we shall determine the density of the oxygen. This can be obtained as follow:
Mass of 1 mole of oxygen = 16 gVolume of 1 mole of oxygen = 5678462 m³Density of oxygen =?Density = mass / volume
Density of oxygen = 16 / 5678462
Density of oxygen = 2.82×10⁻⁶ g/m³
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a college student produces about 100 kcal of heat per hour on the average what is the rate of energy production and joules
Given:
Amount of heat produced = 100 kcal per hour
Let's find the rate of energy production in joules.
We know that:
1 calorie = 4.184 Joules
1 kcal = 4.184 Joules
To find the rate of energy production in Joules, we have:
\(\begin{gathered} Rate=100\ast4.184 \\ \\ \text{Rate}=418.4\text{ KJ/hour} \end{gathered}\)Therefore, the rate of energy production in joules is 418.4 kJ/h which is equivalent to 418400 Joules
ANSWER:
418.4 kJ/h
Two students push on a box in the same direction, and one student pushes in the opposite direction. What is the net force on the
box if each student pushes with a force of 50 N?
Net force on the box is 50 N if 2 students push it in the same direction with 50 N of force each and one student pushes it in the other direction with 50 N of force.
Define force.An object with mass experiences a pull or push, which changes its velocity. An agent with the ability to change a body's rest or moving condition is known as an external force. It has both magnitude as well as direction.
The force formula according to Newton is what?F = ma, meaning force is equal to the mass times acceleration, is the second of Newton's three laws of motion.
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What is SeaWorld?
What is this
What is that
SeaWorld is a chain of theme parks and oceanariums that showcase marine life through educational exhibits, live shows, and thrilling rides. While it has faced criticism for its treatment of animals, SeaWorld has made changes to prioritize conservation and phased out its orca breeding program.
SeaWorld is a chain of theme parks and oceanariums that primarily focuses on marine life and entertainment. The company operates various parks across the United States, including SeaWorld parks in Orlando, San Diego, and San Antonio, as well as Busch Gardens parks in Tampa and Williamsburg. SeaWorld offers a combination of educational exhibits, live shows, and thrilling rides, with a special emphasis on marine animals such as dolphins, whales, sea lions, penguins, and sharks.
SeaWorld parks provide visitors with opportunities to observe and interact with marine creatures up close, while also offering educational programs that aim to raise awareness about marine conservation and preservation. The parks feature captivating shows featuring trained animals, where they perform impressive behaviors and stunts, showcasing their intelligence and natural abilities.
Over the years, SeaWorld has faced criticism from animal rights activists and environmentalists, who argue that the captivity and use of marine animals for entertainment purposes is unethical and harmful to the animals' well-being. These concerns have led to significant changes in the company's practices, including the phasing out of its orca breeding program and the introduction of more educational and conservation-focused initiatives.
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A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and frictional force between the box and surface is 100 n, calculate the distance covered.
If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.
To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.
Given:
Mass of the box, m = 210 kg
Tension in the string, T = 1300 N
The angle of inclination, θ = 35°
Frictional force, f = 100 N
Initial speed, u = 0 m/s
Final speed, v = 10 m/s
First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:
T_parallel = T * cos(θ)
Next, let's calculate the net force acting on the box along the incline. The net force is given by:
Net force = T_parallel - f
Now, using Newton's second law, we can calculate the acceleration (a) of the box:
Net force = m * a
From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):
v^2 = u^2 + 2as
Rearranging the equation, we get:
s = (v^2 - u^2) / (2a)
Now, let's plug in the given values and calculate the distance covered:
T_parallel = 1300 N * cos(35°) ≈ 1067.35 N
Net force = 1067.35 N - 100 N = 967.35 N
a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2
s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m
Therefore, the distance covered by the box is approximately 10.89 meters.
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