Answer:
Who is liang
Explanation:
i need more info if i'm going to help you out
He is most likely trying to figure out how to upload the picture to Brainly.
He knows that his question cannot be answered as long as nobody can see the picture.
Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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the lorenz curve: group of answer choices is located farther from the diagonal when income is defined to include the value of noncash transfers. is located closer to the diagonal today than it was in 1975. plots graphically the distribution of income. plots graphically the poverty rate over time
Lorenz curve is the curve that plots graphically the distribution of income. Therefore, the correct statement is statement 3.
The Lorenz curve depicts the distribution of income (or wealth) within an economy. Max O. Lorenz created it in 1905 to symbolize the distribution of income. The Lorenz curve displays the total percentage of income earned by various demographic groups.
The graph shows cumulative income or wealth on the vertical axis and percentiles of the population according to income or wealth on the horizontal axis. Lorenz curves and the statistics derived from them are frequently utilized to assess inequality within a population.
An empirical measurement of the wealth or income distribution within a population, based on information from tax returns, which detail income for a significant section of the people, is the common starting point for a Lorenz curve.
Therefore, statement 3 is correct.
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Consider the Atwood Machine, assuming a massless pulley. Assume m1 > m2. Using N2, we found the acceleration of the system is: a = g(m1 − m2)/(m1 + m2) and the tension was equal. Now take into account the mass of the pulley:
a) Suppose m1 = 0.7 kg and m2 = 0.4 kg. What would the system acceleration be for the pulley?
b) What is the net torque acting on the pulley in terms of the tensions T1, T2, and the pulley radius R? What is the net force acting on each mass in terms of T and weight?
c) Use Newton's 2nd, Rotational N2, and assume the string doesn’t “slip” (at = αR) to find the acceleration of the system if the mass of the pulley is 5 kg.
The system acceleration for the pulley having masses m1 = 0.7 kg and m2 = 0.4 kg Is 35.93 \(m/s^2\).
What is Newton's Second Law?Newton's second law provides a detailed explanation of how a force can alter a body's motion. It is believed that a body's momentum varies over time at a rate equal to the force acting on it in both direction and amplitude. The combined effects of a body's mass and velocity determine its momentum.
Given:
The mass, m₁ = 0.7 kg,
m₂ = 0.4 kg,
Calculate the system acceleration by the following formula,
a = g(m1 − m2)/(m1 + m2)
Here a is the acceleration.
Substitute the values,
a = 9.8 * (0.7 - 0.4 ) / (0.7 + 0.4)
a = 35.93 \(m/s^2\)
Therefore, the system acceleration for the pulley is 35.93 \(m/s^2\).
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I need help with this question
Explanation:
a boy walks at 2m/s for 30sec and run at 5m/s for 20sec. what is his average speed
Calculate how much gravitational potential energy is lost by an aircraft of mass 80,000 kg if it descends from an altitude of 10,000 m to an altitude of 1000 m. What happens to this energy if the pilot keeps the aircraft's speed constant?
The loss in the gravitataional potential energy is obtained as 7.056 * 10^9 J and this energy is converted to the kinetic energy of the moving aircraft.
What is the change in the gravitational potential energy?The term gravitational potential energy has to do with the energy that is possessed by a body by virtue of its position. Thus it has to do with the height of the object. The greater the height, the more the gravitational potential energy.
Now;
E = mgh
m = mass of the object
g = acceleration due to gravity
h = height of the object
Thus;
The loss in the gravitational potential energy is obtained from;
80,000 * 9.8 (10,000 - 1000)
= 7.056 * 10^9 J
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Consider a car with a mass of 1250 kg moving at a constant speed of (22.0 A) m/s in a circular off ramp with a radius of (65.0 +B) m. What does the coefficient of static friction have to be for the car to just maintain its motion of ramp? Give your answer to 3 significant figures.
A=7
B=2
Answer:
Explanation:
weight of the car mg = m g
frictional force acting on the car = μ mg where μ is coefficient of friction
= m μ g
This force provides centripetal force , hence
m μ g = m v² / R
μ = v² / rg
= 22 x 22 / 65 x 9.8
= .759
How can a body have centripetal acceleration even if the speed is constant?
Please help me understand this it’ll be greatly appreciated!
Answer:
motion of an object—even if the object is maintaining a constant speed—still count as acceleration
Explanation:
A child pulls a string attached to a toy car with a constant force of 7.8 N. The toy car accelerates from
rest to 3 m/s in 1.2 s. What is the mass of the toy car?
A. 3.12 kg
B. 2.6 kg
C. 0.38 kg
D. 0.32 kg
By Newton's second law, the car has mass m so that the net force is
∑ F = ma
Find the acceleration a of the car. Since the force is constant, acceleration is also constant. If the car accelerates from rest to 3 m/s in 1.2 s, then its acceleration is
a = (3 m/s - 0) / (1.2 s) = 2.5 m/s²
Then the mass of the car m is such that
7.8 N = m (2.5 m/s²)
Solve for m :
m = (7.8 N) / (2.5 m/s²) = 3.12 kg
A chemical reaction separates water into hydrogen gas and oxygen gas. Which of the following statements is true about the mass of the water and the combined mass of the two gases
Answer:
The mass of the water is greater than the combined mass of the two gases
Mrs Turner has a scale drawing of her apartment.IN the scale drawing the lenght of her apartment is 6.25 inches and the width is 2.75 onches. If Mrs. Turner used the scale factor 1 inc/18ft, what would the area of the apartment be?
The area of Mrs. Turner's apartment is approximately 0.05304 square feet.
To find the area of Mrs. Turner's apartment, we need to convert the measurements from the scale drawing to the actual measurements in feet, using the given scale factor of 1 inch/18 feet.
Length of apartment in feet = 6.25 inches × (1 foot/18 inches) = 0.34722 feet
Width of apartment in feet = 2.75 inches × (1 foot/18 inches) = 0.15278 feet
Now, we can calculate the area of the apartment in square feet by multiplying the length and width:
Area of apartment in square feet = Length × Width = 0.34722 feet × 0.15278 feet = 0.05304 square feet
Therefore, the area of Mrs. Turner's apartment is approximately 0.05304 square feet.
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You are walking on a moving walkway in the airport. The length of the walkway is 59.1 m. If your velocity relative to the walkway is 2.35 m/s, and the walkway moves with a velocity of 1.85 m/s, how long will it take you to reach the other end of the walkway
Answer:
14.1seconds approx
Explanation:
Given data
Distance= 59.1m
Your velocity= 2.35m/s
Walkway velocity= 1.85m/s
Total velocity= 2.35+1.85= 4.2m/s
We know that
Velocity= distance/time
time= distance/velocity
substitute
time= 59.1/4.2
time= 14.07
time=14.1seconds approx
Hence the time is 14.1seconds approx
1. What is the wavelength
a sound wave in air with a frequency of 50 Hz?
Which object has the most momentum?
A toy car rolling along the floor
A child peddling their bike as fast as possible
&o
A large moving truck stopped at a red light
How might a location's altitude influence it's climate?
Answer:
You will discover that at high altitude, there is cold and the opposite is experienced when you go deep down the sea. However, the reason elevation affects climate and temperature gets colder is this. As you go higher up, the atmosphere experiences less pressure.
Explanation:
A candle is sitting in front of a concave mirror at a distance of 18.0 cm. It is found that an image of the ca
25.0 cm. What is the focal length of the mirror?
03.52 cm
07.50 cm
O 10.4 cm
022.1 cm
Answer:
The focal length of the mirror is 10.4 cm.
Explanation:
The object distance ( d₀ ) ( distance of the candle from the mirror) is -18 cm.The Image distance ( dᵢ ) ( distance of the image from the mirror) is -25.0 cm.The mirror equation is 1/f = 1/d₀ + 1/dᵢ.So substitute the values of object distance and image distance in the mirror equation,
1/f = 1/(-18cm) + 1/(-25.0cm)
1/f = -25cm/(-18cm x -25cm) - 18cm/(-18cm x 25cm)
1/f = ( -25cm - 18cm)/(18cm x 25cm)
1/f = -43.0/450.0
f = -10.4651 cm.
The focal length of the mirror is approximately -10.4 cm.
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What is the biggest agent of erosion?
a tornadoes
b pollution
c gravity
d water
Answer:
D - Water
Explanation:
In your DC experiment, when the capacitor was just beginning to charge the current in the circuit was O maximum between maximum and minimum minimum
Yes ,In my DC experiment, when the capacitor was just began to charge the current in the circuit was O maximum between maximum and minimum.
What is capacitor ?A capacitor is a device which make use of the accumulation of electric charges from two nearby surfaces which are electrically isolated from one another to store electrical energy in an electric field. Capacitor has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect i.e C = Q/U.The unit of electrical capacitance is known to be the farad.DC:DC stands for Direct Current a form of current flow.To know more about capacitor visit
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a)write an equation for the magnitude of this systems acceleration. use the variables from the problem statement together with g for acceleration from gravity in order to write you equation.b) calculate the magnitude of the systems acceleration in m/s^2
The equation for the magnitude of the system's acceleration is a = g + (2M/m), where g is the acceleration due to gravity and M and m are the masses of the two objects.
What is acceleration ?Acceleration is the rate of change of velocity in an object over time. It is the rate of change of the speed of an object, and is defined as the change in velocity divided by the change in time. In other words, it is the rate at which an object's speed changes. Acceleration can be caused by a change in the speed of an object, or by a change in its direction. It is usually measured in meters per second squared (m/s2). Acceleration can be either positive or negative, depending on the direction of the change in velocity.
a = g + (2M/m)
a = 9.81 m/s^2 + (2(8 kg)/(3 kg)) = 13.87 m/s^2
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A stone is thrown horizontally from the top of a cliff. One second after it has left your hand its vertical distance below the top of the cliff is A) 5 m.B) 10 m.C) 15 m.
Answer:
A
Explanation:
d = 1/2 at^2 a = 10
= 1/2 (10)(1^2) = 5 m
An ideal gas absorbs 750 J of heat as it performs 625 J of work. What is the resulting change in temperature if there are 1.3 moles of the gas in the system
Answer:
7.7°K
Explanation:
Using pV = NkT = nRT
U = CvNkT = Cv nRT
where:
Cv is a constant dependent on temperature (e.g. equal to 3/2 for a monatomic gas for moderate temperatures)
U is the internal energy
p is the pressure
V is the volume
n is the amount of gas (moles)
R is the gas constant, 8.314 J·K^−1mol^-1
T is the absolute temperature
N is the number of particles
k is the Boltzmann constant, 1.381×10^−23 J·K^−1
In your first problem, the energy difference between heat absorbed by the gas and the work performed is the energy lost to heat. So
∆E = Cv nR∆T
where ∆T is the temperature change
∆T = ∆E / (Cv nR)
= (750-625) / (3/2)(1.3)(8.314)
= 7.71° K
A piece of wood 350 mm × 350 mm and 15 mm thick conducts heat through its thickness under steady state conditions. The rate of heat flow is measured to be 14.0 watts when the temperature difference is 28 C°. Determine the coefficient of thermal conductivity for this wood
The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:
k = Q / (A * ΔT * L) = Rth * (A * ΔT)
Reorganizing this equation gives:
Rth = k / (A * ΔT)
The given information in the problem is:
Rate of heat flow (Q) = 14.0 watts
Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C
Temperature difference (ΔT) = 28°C
Substituting these values into the equation, we have:
k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK
So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.
As mentioned in the text, the tangent line to a smooth curve r(t) = ƒ(t)i + g(t)j + h(t)k at t = t0 is the line that passes through the point (ƒ(t0), g(t0), h(t0)) parallel to v(t0), the curve’s velocity vector at t0. In Exercises 23–26, find parametric equations for the line that is tangent to the given curve at the given parameter value t = t0.
Answer:
\(x = t\)
\(y = \frac{1}{3}t\)
\(z =t\)
Explanation:
Given
\(r(t) = f(t)i + g(t)j + h(t)k\) at \(t = 0\)
Point: \((f(t0), g(t0), h(t0))\)
\(r(t) = ln\ t_i + \frac{t-1}{t+2}j + t\ ln\ tk\), \(t0 = 1\) -- Missing Information
Required
Determine the parametric equations
\(r(t) = ln\ ti + \frac{t-1}{t+2}j + t\ ln\ tk\)
Differentiate with respect to t
\(r'(t) = \frac{1}{t}i +\frac{3}{(t+2)^2}j + (ln\ t + 1)k\)
Let t = 1 (i.e \(t0 = 1\))
\(r'(1) = \frac{1}{1}i +\frac{3}{(1+2)^2}j + (ln\ 1 + 1)k\)
\(r'(1) = i +\frac{3}{3^2}j + (0 + 1)k\)
\(r'(1) = i +\frac{3}{9}j + (1)k\)
\(r'(1) = i +\frac{1}{3}j + (1)k\)
\(r'(1) = i +\frac{1}{3}j + k\)
To solve for x, y and z, we make use of:
\(r(t) = f(t)i + g(t)j + h(t)k\)
This implies that:
\(r'(1)t = xi + yj + zk\)
So, we have:
\(xi + yj + zk = (i +\frac{1}{3}j + k)t\)
\(xi + yj + zk = it +\frac{1}{3}jt + kt\)
By comparison:
\(xi = it\)
Divide by i
\(x = t\)
\(yj = \frac{1}{3}jt\)
Divide by j
\(y = \frac{1}{3}t\)
\(zk = kt\)
Divide by k
\(z = t\)
Hence, the parametric equations are:
\(x = t\)
\(y = \frac{1}{3}t\)
\(z =t\)
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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How many significant figures are in 0.0067?
Answer:
2
Explanation:
there are 2 significant figures in there
A dog weighing 18 kg runs into a park at a velocity of .63 m/s. What is the momentum of the dog? (1 point)
O.035 kg*m/s
O 17.37 kg*m/s
O 28.5 kg*m/s
O 11.34 kg* m/s
The dog has a momentum of 11.34 kg*m/s.
The correct answer is D.
What exactly is momentum?Product of a particle's mass and velocity. A vector quantity, momentum has both a magnitude and a direction. The force exerted on a particle is equated to the time rate of change of momentum by Isaac Newton's second equation of motion.
How does momentum work?The sum of the units of mass and velocity yields the unit of momentum. The momentum is expressed in kilogram meters per second (kgm/s) in SI units if the mass and velocity are both expressed in kilograms and meters per second, respectively.
Briefing:P = momentum
m = mass
v = velocity
m = 18 kg
v = .63 m/s
P = m × v
P= 18 × .63
p = 11.34 kg*m/s.
The dog has a momentum of 11.34 kg*m/s.
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The complete question is -
A dog weighing 18 kg runs into a park at a velocity of .63 m/s. What is the momentum of the dog? (1 point)
A-035 kg*m/s
B-17.37 kg*m/s
C- 28.5 kg*m/s
D- 11.34 kg* m/s
Answer:
The dog has a momentum of 11.34 kg*m/s.
What is defined as a set of coordinates on a map grid? > ω
A set of coordinates on a map grid are called coordinate grid or grid squares.
The quadrants in which ordered pairings, or coordinates, are established typically have two or more intersecting lines. Coordinates are also used in maps.
Eastings and Northings, two types of grid lines, are what make up the grid squares you see on maps. Both Easting and Northing grid lines are numbered from west to east and from south to north, respectively. The vertical lines that separate the map's west and east halves are known as eastings.
GPS coordinates, which are frequently stated in alphanumeric characters, can be used to uniquely identify a specific geographic place on the planet. In this context, coordinates refer to the points where a grid system intersects. Typically, GPS coordinates are written as a combination of latitude and longitude.
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A 10 kg box initially at a speed of 10 m/s accelerates uniformly to a speed of 20 m/s in 2
seconds. Determine the
A. energy gained by the block
Answer:
What Um Sorry Where's The Answer?....
When attacking fire in stacked and piled materials, _____, then apply water or Class A foam until extinguished.
Select one:
a. advance until you are at least 5 feet (1.5 m) from the fire's edge
b. apply Class B foam or clean agents
c. advance until you are at least 10 feet (3 m) from the fire's edge
d. use hooks or pike poles to break apart material
The correct answer is option D, which specifies that while putting out a fire in stacked and piled materials, use hooks or pike poles to pull the materials apart prior to dousing the area.
Putting out the fire with Class A foam or water until it has fully died down. In physics, a force is a factor that has the potential to change an object's trajectory. In reaction to a force, a mass-containing object can accelerate or modify its velocity by, for instance, moving away from rest. Force can logically be described as pushing or pulling. A force has both magnitude and direction, making it a vector quantity. Using the SI system, it is written as a newton (N). There is material in all things.
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Correct answer:- (d) use hooks or pike poles to break apart material.
When attacking the fire in stacked and piled materials, use hooks or pike poles to break apart material, then apply water or Class A foam until extinguished.
How would you put out a fire containing polar solvent fuels if you were using foam?A mixture of artificial stabilizers, foaming agents, fluorochemicals, and synthetic polymers are used to create alcohol-resistant (AR) foam, which is intended for use with polar solvents. These foams are resistant to being destroyed by polar solvents due to their chemical composition.
What kind of foam is utilized to put out fires caused by flammable and combustible liquids?The very effective foam known as aqueous film-forming foam (AFFF, or alcohol-resistant AR-AFFF) is used to put out high-hazard liquid fires.
What is the main substance applied to put out a Class A fire?Class A: Consists of common combustibles like rubber, paper, wood, and plastic. Pressurized water, foam, or multipurpose dry chemicals are the most often used extinguishing agents.
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The world's demand for fuel is ever increasing. Identify the fuel type predicted to run out within the next hundred years.
Answer: It is clear that the fuels currently used will not be sustainable for the exponential growth of our energy demand. Although it is difficult to accurately predict the fuels that we will use, however it is clear that the powerful combustion of hydrogen is expected to be used especially to propel the aerospace and aeronautical industry. We can also highlight the use of nuclear fusion energy that until now is taking its first steps and finally it is quite likely that solar energy will continue to be used but in a much more powerfull and efficient way.
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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