what is 0.34 round to the nearest tenth

Answer:  542+(87+41) = 670

Step-by-step explanation:

The standard deviation of the given random sample is approximately 0.351.

To find the standard deviation of a random sample, we need to calculate the standard deviation of the underlying distribution.

In this case, the distribution has a density function:

f(x) = x² + 2/3 (0 ≤ x ≤ 1)

To find the standard deviation, we first need to find the mean (μ) and variance (σ²) of the distribution.

The mean can be calculated as follows:

μ = ∫(x × f(x)) dx

where the integral is taken over the range [0, 1].

μ = ∫(x × (x² + 2/3)) dx

= ∫(x³ + 2/3 × x) dx

= (1/4 × x⁴ + 1/3 × x²) |[0, 1]

= (1/4 × 1⁴ + 1/3 × 1²) - (1/4 × 0⁴ + 1/3 × 0²)

= 1/4 + 1/3

= 7/12

Next, we calculate the variance (σ²):

σ² = ∫((x - μ)² × f(x)) dx

σ² = ∫((x - 7/12)² × (x² + 2/3)) dx

= ∫((x⁴ - 7/6 × x³ + 49/144 × x² - 7/36 × x + 49/432) dx

= (1/5 × x⁵ - 7/24 × x⁴ + 49/432 × x³ - 7/72 × x² + 49/432 × x) |[0, 1]

= 1/5 - 7/24 + 49/432 - 7/72 + 49/432

= 145/432

Now, we can calculate the standard deviation (σ) by taking the square root of the variance:

σ = √(145/432)

≈ 0.351

Therefore, the standard deviation of the given random sample is approximately 0.351.

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Solution:

Given the functions;

Then;

Also;

ANSWERS:

The diver's velocity during the first 2 sec of fall using the modified Euler method with Ar= 0.2 is 62.732 mph.

Given data: Initial velocity, u = 0 ft/sec

Acceleration, a = g = 32.2 ft/sec²

The maximum rate of fall, vmax = 80 mph

Time, t = 2 seconds

Air resistance constant, Ar = 0.2

We are supposed to determine the sky diver's velocity during the first 2 seconds of fall using the modified Euler method.

The governing equation for the velocity of the skydiver is given by the following:

ma = -m * g + k * v²

where, m = mass of the skydive

r, g = acceleration due to gravity, k = air resistance constant, and v = velocity of the skydiver.

The equation can be written as,

v' = -g + (k / m) * v²

Here, v' = dv/dt = acceleration

Hence, the modified Euler's formula for the velocity can be written as

v1 = v0 + h * v'0.5 * (v'0 + v'1)

where, v0 = 0 ft/sec, h = 2 sec, and v'0 = -g + (k / m) * v0² = -g = -32.2 ft/sec²

As the initial velocity of the skydiver is zero, we can write

v1 = 0 + 2 * (-32.2 + (0.2 / 68.956) * 0²)0.5 * (-32.2 + (-32.2 + (0.2 / 68.956) * 0.5² * (-32.2 + (-32.2 + (0.2 / 68.956) * 0²)))

v1 = 62.732 mph

Therefore, the skydiver's velocity during the first 2 seconds of fall using the modified Euler method with Ar= 0.2 is 62.732 mph.

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The rate of the plane in still air is 860 km/h and the rate of the wind is 240 km/h.

To find the rate of the plane in still air and the rate of the wind, we can set up a system of equations using the given information.

Let's denote the rate of the plane in still air as "s" km/h and the rate of the wind as "w" km/h.

When flying against the wind, the effective speed of the plane is reduced by the speed of the wind, so the equation can be written as:

s - w = 2480/4

When flying with the wind, the effective speed of the plane is increased by the speed of the wind, so the equation can be written as:

s + w = 7700/7

We now have a system of equations:

s - w = 620 (Equation 1)

s + w = 1100 (Equation 2)

To solve this system of equations, we can add Equation 1 and Equation 2:

(s - w) + (s + w) = 620 + 1100

2s = 1720

Divide both sides of the equation by 2:

s = 860

Now, substitute the value of s into Equation 2:

860 + w = 1100

Subtract 860 from both sides:

w = 1100 - 860

w = 240

Therefore, the rate of the plane in still air is 860 km/h and the rate of the wind is 240 km/h.

The rate of the plane in still air is 860 km/h and the rate of the wind is 240 km/h.  

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To calculate the cash balance at the end of the period, we need to consider the cash inflows and outflows.

Starting cash balance: $4,520

Cash inflows: $1,654 (receivables collected)

Cash outflows: $1,961 (payments to suppliers) + $500 (cash expenses)

Total cash inflows: $1,654

Total cash outflows: $1,961 + $500 = $2,461

To calculate the cash balance at the end of the period, we subtract the total cash outflows from the starting cash balance and add the total cash inflows:

Cash balance at the end of the period = Starting cash balance + Total cash inflows - Total cash outflows

Cash balance at the end of the period = $4,520 + $1,654 - $2,461

Cash balance at the end of the period = $4,520 - $807

Cash balance at the end of the period = $3,713

Therefore, the cash balance at the end of the period is $3,713.

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Based on the fictitious study of gender and ear piercing in high school students, we can conclude that the sample provides evidence that is too weak to conclude that gender and ear piercing are dependent in the population of high school students. Gender and ear piercing for high school students may be independent.

The study did not provide strong evidence that gender and ear piercing for high school students are dependent. In addition, the differences between observed and expected counts could be attributed to chance variation that occurs in random samples of high school students when gender and ear piercing are independent.

Therefore, the conditions are not met for use of the chi-square test of independence, and we cannot draw a conclusion based on this data.

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This means that when all 8 parts are arranged in a single row, probability there are 28 different conceivable configurations. Finley can have 4 red and 4 black, 5 red and 3 black, 6 red and 2 black, or 7 red and 1 black, depending on the quantity of red and black pieces.

Finley features eight game pieces, each of which is entirely either all red or all black and simply differs in colour. This indicates that there are 28 distinct configurations that may be made using the 8 pieces arranged in a single row. Finley could have 4 red and 4 black, 5 red and 3 black, 6 red and 2 black, or 7 red and 1 black, depending on the quantity of red and black pieces. This is due to the fact that the 8 pieces can be arranged in a variety of ways, and each arrangement will be deemed distinct as long as it contains at least one red and one black piece. For instance, the configuration could be as follows if there are 4 red and 4 black pieces: If there are four red pieces and four black pieces, for instance, the arrangement might be either black-red-black-red-black-red-red or red-black-red-black-red-black. No matter the configuration, there are a total of 28 arrangements.

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Rotating the equation x = √a^2 – y^2 around the y-axis on the interval 0 ≤ y ≤ a/2 creates a torus-shaped solid with a hole in the center.

When we rotate the equation x = √a^2 – y^2 around the y-axis, we create a three-dimensional object called a solid of revolution. The resulting shape will look like a donut or torus.

The interval 0 ≤ y ≤ a/2 indicates that we are only rotating the equation for values of y between 0 and a/2. This means that our resulting solid will have a hole in the center, with a radius of a/2.

To visualize the solid, imagine taking a circle with radius a/2 and rotating it around the y-axis. As it rotates, it traces out the shape of our solid of revolution.

In terms of calculus, we can find the volume of this solid using the formula V = π∫[0,a/2] (x(y))^2 dy, where x(y) is the equation we are rotating around the y-axis (in this case, x = √a^2 – y^2). We integrate with respect to y because our limits of integration are given in terms of y.

Overall, rotating the equation x = √a^2 – y^2 around the y-axis on the interval 0 ≤ y ≤ a/2 creates a torus-shaped solid with a hole in the center.

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Answer:

x = 8

Step-by-step explanation:

If the number 212x5 is a multiple of 3, the sum of the digits needs to be a multiple of 3, so we have:

2 + 1 + 2 + x + 5 = 10 + x

The value of x can be 2, 5 or 8

If the number is a multiple of 11, we have to calculate the first number minus the second, plus the third, minus the fourth... and so on, and the result needs to be a multiple of 11. So we have:

2 - 1 + 2 - x + 5 = 8 - x

x needs to be 8, so we have 8 - 8 = 0, that is a multiple of 11.

So the value of x is 8.

Answer:

Step-by-step explanation:

\(\sqrt {900}=\sqrt {30\times30}=\sqrt {30^2}=|30|=30\)

Answer:

30

Step-by-step explanation:

√900 = 30 Answer

maybe my ans is write ....

Answer:

13212

Step-by-step explanation:

(a) The gradient at (1,1,1) is (e,4,12), (b) direction of fastest increase is \((e/13,4/13,12/13)\), (c) rate of increase in that direction is 17e/13, and (d) the equation of the tangent plane to the ellipsoid \(x^2+2y^2+3z^2=6\) at \((1,1,1) is x+2y+3z=9.\)

(a) Using partial derivatives, we can find the gradient of f:

\(∇f(x,y,z) = ( ∂f/∂x, ∂f/∂y, ∂f/∂z ) = ( e^x, 4y, 12z^3 )\)

Thus, at the point (1,1,1), we have:

\(∇f(1,1,1) = ( e, 4, 12 )\)

(b) The direction of fastest increase of f at (1,1,1) is given by the unit vector in the direction of the gradient:

\(v = ∇f(1,1,1)/||∇f(1,1,1)|| = ( e/13, 4/13, 12/13 )\)

(c) The rate of increase of f in the direction of v is given by the directional derivative:

\(D_v f(1,1,1) = ∇f(1,1,1) · v = (e/13) + (4/13) + (12/13) = (17e/13\))

(d) The equation of the tangent plane to the ellipsoid \(x^2 + 2y^2 + 3z^2 = 6\)at the point (1,1,1) can be found by using the gradient of the left-hand side of the equation:

\(∇(x^2 + 2y^2 + 3z^2) = ( 2x, 4y, 6z )\)

At the point (1,1,1), this is:

\(∇(x^2 + 2y^2 + 3z^2)|_(1,1,1) = ( 2, 4, 6 )\)

The normal vector to the tangent plane is therefore (2,4,6), and the equation of the tangent plane is:

2(x-1) + 4(y-1) + 6(z-1) = 0

Simplifying, we get:

x + 2y + 3z = 9

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A)

The statements that MUST be true based on the given information are:

B) Where the figure above is a square,
BC = 11
AC = 11√2
BD = AC = 11√2
EC = 11/2√2

m∠DAB= 90°
m∠AEB = 90°
m∠CBD = 45°
m∠BAC = 45°

A)
For Quadrilateral C, all four sides are congruent. By definition, this means that all four angles are also congruent since the sum of the interior angles of any quadrilateral is 360 degrees. In an isosceles trapezoid, which is a special case of Quadrilateral C where two sides are parallel and two are congruent, the opposite angles are congruent. Therefore, it can be concluded that the opposite angles of Quadrilateral C are also congruent.

For Quadrilateral L, it is given that the diagonals are congruent and the sides are parallel. This is the definition of a parallelogram, which has the property that opposite angles are congruent. Since the diagonals of Quadrilateral L bisect each other, it can be inferred that the opposite angles are congruent.

The other statements are not necessarily true based on the given information.

B)
Given that ABCD is a square,

BC = AD = AB = 11
AC = BC =√(11² + 11²)
AC = BC = 11√2

EC = 1/2 of AC thus:

EC = 11/2√2

Note that
m∠DAB= m∠ADC = m∠DCB =m∠CBA = 90° - Properties of a square. It's internal angles are 90° and the diagonals intersect each other at 90°

m∠AEB  = m∠AED = m∠DEC = m∠CEB =  90° - Properties of a square. Its internal angles are 90° and the diagonals intersect each other at 90°


m∠CBD = 45°
m∠BAC = 45°

This is because all diagonals are perpendicular to each other and bisect the angles in each vertex.

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Answer: x = 9

Step-by-step explanation:

Answer:

I am on school computer, I cannot see the question. could you please type it?

Step-by-step explanation:

Answer:

this is just a system of equations

x+y=4

2x+3y=12

x=-y+4

plug in

2(-y+4)+3y=12

-2y+8+3y=12

y+8=12

y=4

plug in

x+4=4

x=0

(0,4)

Hope This Helps!!!

Answer:

(0,4)

Step-by-step explanation:

find x by subtracting y from both sides

Given parameters:

  Evaluate;

             \(\sqrt[4]{(16)^{-2} }\)

Now let us solve this;

           \(\sqrt[4]{(16)^{-2} }\);

     the fourth root can be expressed  as the power of    \(\frac{1}{4}\) ;

    \(\sqrt[4]{(16)^{-2} }\)   =     [(16)⁻²]\(^{\frac{1}{4} }\)

                     =  (16)\(^{-2 x \frac{1}{4} }\)

                      = (16)\(^{\frac{-1}{2} }\)

                      =     \(\frac{1}{16^{\frac{1}{2} } }\)

                     =    \(\frac{1}{\sqrt{16} }\)

                     =  \(\frac{1}{4}\)

The solution is \(\frac{1}{4}\)

For the given sample space we have the probabilities as follows: 1. P(sum=11) = 6/64 = 3/32 2. P (sum < 6) = 10/64 3. P ( sum is greater than or equal to 7) = 49/64 4.  P(sum is a multiple of 3 or a multiple of 4) = 33/64.

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has included probability to forecast the likelihood of certain events. The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution.

For the sample space of rolling two 8 sided die we have:

1. P (sum = 11):

The samples that give the sum equal to 11 are:

(3, 8), (4, 7), (5, 6), (6, 5), (7, 4), and (8, 3)

Thus,

P(sum=11) = 6/64 = 3/32

2. P (sum < 6):

(1, 1), (1, 2), (1, 3), (1, 4)

(2, 1), (2, 2), (2, 3)

(3, 1), (3, 2)

(4, 1)

Thus, P (sum < 6) = 10/64

3. P ( sum is greater than or equal to 7):

(1, 6), (1, 7), (1, 8) = 3

(2, 5), (2, 6) (2, 7), (2, 8) = 4

(3, 4), (3, 5) (3, 6) (3, 7) (3, 8) = 5  

(4, 3) (4, 4) (4, 5) (4, 6), (4, 7) (4, 8) = 6

(5, 2) (5, 3) (5, 4) (5, 5) (5, 6) (5, 7) (5, 8) = 7

(6, 1) upto (6, 8) = 8

(7, 1) upto (7, 8) = 8

(8, 1) upto (8, 8) = 8

Total = 3 + 4 + 5 + 6 + 7 + 8 + 8 + 8 = 49

Thus, P ( sum is greater than or equal to 7) = 49/64

4. P (sum is a multiple of 3 or a multiple of 4):

Multiple of 3: 3, 6, 9, 12, ........

(1, 2) (1, 5) (1, 8) (2, 1) (2, 4) (2, 7) (3, 1) (3, 3) (3, 6) (4, 2) (4, 5) (4, 8) (5, 1) (5, 4) (5, 7), (6, 3), (6, 6) (7, 2) (7, 5) (7, 8) (8, 1) (8, 4), (8, 7) = 23

Multiple of 4: 4, 8, 12, 16, .........

(1, 3) (1, 7) (2, 2) (2, 6) (3, 1) (3, 5) (4, 4) (4, 8), (5, 3), (5, 7), (6, 2), (6, 6) (7, 1) (7, 5) (8, 4) (8, 8) = 16

Common terms = 6

Thus, P(sum is a multiple of 3 or a multiple of 4) = 23 + 16 - 6 / 64 = 33/64

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The usual statistical distribution of phenotypes for a quantitative character in a population is a bell-shaped curve known as a normal distribution.

In a population, a quantitative character refers to a trait that can be measured and varies along a continuum, such as height, weight, or blood pressure. The distribution of phenotypes for such characters is often influenced by various factors, including genetic and environmental factors. However, assuming that disruptive selection, which favors extreme phenotypes, is not occurring, the distribution of phenotypes tends to follow a normal distribution.

The normal distribution arises due to the central limit theorem, which states that when a large number of independent random variables contribute to a trait, their combined effect tends to follow a normal distribution. This is applicable to many biological traits where multiple genetic and environmental factors influence the phenotype.

Overall, the assumption of a normal distribution for quantitative traits in a population provides a useful framework for understanding the expected distribution of phenotypes and analyzing statistical patterns in relation to these traits.

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The x value or observed value corresponding to  z-score, z = 1.50 is 130.

According to the question.

For a population with µ = 100 and σ = 20.

Since,  we know that

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

And it is given by

z = (x - μ) / σ

Where,

x is the observed value.

μ is the mean.

and, σ is the standard deviation.

Therefore, the x value or observed value corresponding to z = 1.50 is given by

\(1.50 = \frac{x -100}{20}\)

⇒ 1.50 × 20 = x - 100

⇒ 30 = x - 100

⇒ x = 30 + 100

⇒ x = 130

Hence, the x value or observed value corresponding to  z-score, z = 1.50 is 130.

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Answer:

cylinder 1 has a radius of 8 cm

cylinder 2 has a radius of 2.5 cm

Step-by-step explanation:

cylinder 1:

we know... h = 10cm   \(\pi\) = 3.14   and 2009.6 \(cm^{3}\)

plug these values into the volume formula: 2009.6 = (3.14) (r^2) (10)

multiply 10 and 3.14: 2009.6 = (31.4) r^2

divide both sides by 31.4: 64 = r^2

put both sides under a root square: 8 = r

cylinder 2:

we know... h = 10cm   \(\pi\) = 3.14   and  196.25 \(cm^{3}\)

plug these values into the volume formula: 196.25 = (3.14) (r^2) (10)

multiply 10 and 3.14: 196.25 = (31.4) r^2

divide both sides by 31.4: 6.25 = r^2

put both sides under a root square: 2.5 = r

The interval for which particle moves to the right is D. t ≥ 4

Intervals are the range of values of a function.

Given that a particle moves along the x-axis so that a time t≥0 is given by x(t) = (t-1)³(t-5).

To find the inverval, we differentiate x(t) with respect to t since the velocity is the derivative dx/dt.

So, x(t) = (t - 1)³(t - 5).

dx(t)/dt = d(t - 1)³(t - 5)/dt

= (t - 5)d(t - 1)³/dt + (t - 1)³d(t - 5)/dt

= (t - 5) × 3(t - 1)² + (t - 1)³ × 1

= 3(t - 5)(t - 1)² + (t - 1)³

= (t - 1)²[3(t - 5) + (t - 1)]

= (t - 1)²[3t - 15 + t - 1]

= (t - 1)²(4t - 16)

For the particle to be moving to the right, dx/dt ≥ 0.

So, dx/dt ≥ 0

⇒ (t - 1)²(4t - 16) ≥ 0

⇒ (t - 1)² ≥ 0 or 4t - 16 ≥ 0

⇒ (t - 1) ≥ 0 or 4t ≥ 16

⇒ t ≥ 1 or t ≥ 16/4

⇒ t ≥ 1 or t ≥ 4

⇒ t ≥ 4 (since 4 is greater than 1.)

So, the interval for which particle moves to the right is D. t ≥ 4

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Answer:

5x^2-1x-3

Step-by-step explanation:

First bring the like terms together:

= 3x^2+2x^2+2x-3x-4+1

then solve it

Ans =5x^2-1x-3

I hope its useful

If three electrical utility companies are randomly selected from a group of seven, where two companies are expected to experience nuclear difficulties, the probability of selecting none of the companies with nuclear difficulties is calculated using combinations. The probability of selecting one of the companies with nuclear difficulties is determined by multiplying the probability of selecting one specific company with the probability of not selecting the other company. The probability of selecting both companies with nuclear difficulties is calculated by multiplying the probabilities of selecting each company individually.

To calculate the probability of selecting none of the companies with nuclear difficulties, we need to find the number of ways to select three companies out of the remaining five companies (without nuclear difficulties) divided by the total number of ways to select three companies from the seven available. The calculation is done using combinations, yielding C(5,3)/C(7,3) = 10/35 = 2/7.

To calculate the probability of selecting one of the companies with nuclear difficulties, we multiply the probability of selecting one specific company (2/7) by the probability of not selecting the other company (5/6), as there are two companies with nuclear difficulties but only one slot available. This results in (2/7) * (5/6) = 5/21.

Lastly, to calculate the probability of selecting both companies with nuclear difficulties, we multiply the probability of selecting each company individually. This gives us (2/7) * (1/6) = 1/21.

Therefore, the probability of selecting none of the companies with nuclear difficulties is 2/7, the probability of selecting one of the companies with nuclear difficulties is 5/21, and the probability of selecting both companies with nuclear difficulties is 1/21.

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The predicted number of adults in Oak City whose main source of news is newspapers or the radio is 85

To predict the number of adults in Oak City whose main source of news is newspapers or the radio, we need to add the number of adults who answered "Newspapers" to the number of adults who answered "Radio".

According to the sample data

Number of adults who answered "Newspapers": 64

Number of adults who answered "Radio": 21

Therefore, the predicted number of adults in Oak City whose main source of news is newspapers or the radio we have to use the addition

64 + 21 = 85

Rounding this answer to the nearest whole number, we get

85 ≈ 85

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The given question is incomplete, the complete question is:

There are 44,000 adults living in Oak City. In examining attitudes toward the news, a research group asked a random sample of Oak City adults "What is your main source of news?" The results are shown below. Main Source of News Newspapers Number of Adults 64 Internet 80 Television 126 Radio 21 Other 40 Based on the sample, predict the number of adults in Oak City whose main source of news is newspapers or the radio. Round your answer to the nearest whole number.

Answer:

-4+(-9)=-4-9 because we ignore the minus sign

Step-by-step explanation:

Hope it help you ^_^

sry i was trying to send it but it didnt work so i took screenshot and there you go the answers.