The partial fractions technique is not applicable because the degree of the numerator (x^3) is not less than the degree of the denominator (x^4 + 73x^2 + 576). For the partial fractions technique to be applicable, the degree of the numerator should be less than the degree of the denominator.
Using the partial fractions technique, the function f(x) = x3 can be written as a sum of partial fractions X4+73x2+576 as shown in equation f(x) = X3 / (X4+73x2+576). The integral of the function f(x) can then be found by using the formula for integrating fractions. The result is:
|F(x) dx = 1/4 (ln|X2+24x| - 3/2 arctan(3x/8) + C)
where C is the constant of integration.
Using the partial fractions technique, the function f(x) = x^3 / (x^4 + 73x^2 + 576) can be written as a sum of partial fractions. To find the integral of the function, we need to first decompose the function into simpler fractions, then integrate each of the simpler fractions.
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the following data set represents the dollar amounts of donations collected at the entrance to a free museum during one hour. donation amount ($) frequency 1 1 5 5 10 3 15 1 600 1 is the median a reasonably good measure of central tendency for this data set? what if the outlier were removed from consideration?
Since, distribution is skewed right even after we remove the outlier (600) from the data set. The median is a good measure regardless of whether the outlier is included.
We have a data set represents the dollar amounts of donations collected at the entrance to a free museum during one hour. The data present in above figure. Now, first we determine the median. As we know, median of a data set is equals to the middle value of data set, so sometimes it is called middle value. It is the value which separates upper and lower halves of data sample or population etc. First we ordered the data values in ascending order. In case odd number of data values, median = middle value and in case of even number of terms, median = mean of two middle terms. Now, here data values in ascending order are 1,5,5,5,5,5,10,10,10,15,600. That is total data values = 11 ( odd) , so median
= 6th value = 5.
So, regardless of whether the outlier is included median is good measure in this situation.
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write the sequence of natural numbers which leaves the remainder 3 on didvidng by 10
The sequence of natural numbers that leaves a remainder of 3 when divided by 10 is:
3, 13, 23, 33, 43, 53, 63, 73, 83, 93, 103, 113, ...
\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)
♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
What is the solution to -4-2x + 6 = -24?
x = 0 or x = -6
O x = 0 or x = 6
O no solution
Answer:
x=13
Step-by-step explanation:
Select the logical expression that is equivalent to:
b. ∃y∀x(¬P(x)∨Q(x,y))
c. ∀y∃x(¬P(x)∨¬Q(x,y))
d. ∃x∀y(¬P(x)∨¬Q(x,y))
e. ∀x∃y(¬P(x)∨¬Q(x,y))
Logical expression that is equivalent to: b. ∃y∀x(¬P(x)∨Q(x,y))
How to find the logical expression equivalent to the given statement?We should analyze each option and compare them to the original statement. The given statement is:
∃y∀x(¬P(x)∨Q(x,y))
Now let's analyze each option:
a. Not provided.
b. ∃y∀x(¬P(x)∨Q(x,y)): This expression is identical to the given statement, so it is equivalent.
c. ∀y∃x(¬P(x)∨¬Q(x,y)): This expression is not equivalent to the given statement because it uses ¬Q(x,y) instead of Q(x,y).
d. ∃x∀y(¬P(x)∨¬Q(x,y)): This expression swaps the order of quantifiers (∃ and ∀) and uses ¬Q(x,y) instead of Q(x,y), so it's not equivalent to the given statement.
e. ∀x∃y(¬P(x)∨¬Q(x,y)): This expression swaps the order of quantifiers (∃ and ∀) but it also has ¬Q(x,y) instead of Q(x,y), so it's not equivalent to the given statement.
After analyzing each option, we can conclude that the logical expression equivalent to the given statement is:
Your answer: b. ∃y∀x(¬P(x)∨Q(x,y))
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The volume of aright circular cone is 12 litres calculate the volume of the two parts into which the cone is divided by a plane parallel to the base a quarter of the way down from the vertex to the base
Answer:
the New Cone Volume is 0.1875 litres & the Volume of frustum is 11.8125 litres.
Step-by-step explanation:
According To Question,
We have Given A Right Circular Cone, Volume = 12 Litres .
Now, Let The Radius Of the base be r & the height be h .
Volume of Cone = 1/3×π×r²×h
thus, 1/3×π×r²×h=12
π×r²×h=36 → Equation. 1
Now, The new Cone is cut from the Plane Parallel to a base a quarter the way down from the vertex of the base. then the cone is cut at 1/4 from the base . So the Height of new Cone is h/r and the radius is r/4 .
Then, Volume Of new Cone=1/3×π×(r²/16)×(h/4) ⇔ (Put Value From Equ. 1)
V= 12/64 ⇔ 0.1875 litres of new cone volume .
Then, the volume of Frustum = 12-0.1875 = 11.8125 litres
In the attachment below I need you to find m∠DBC.
Answer:
m<DBC = 109
Step-by-step explanation:
8x-27=6x+7
8x=6x+34
2x=34
x=17
8(17)-27= 109
Answer: 109
Step-by-step explanation:
i'm not entirely sure of this answer as its been a while since ive done problems like this, however, i think the steps to solve are setting (8x-27) equal to (6x+7). Once you do that, you can solve for x. Substitute x into angle DBC to find the answer.
drag the tiles to the boxes to form correct pairs. match the pairs to equivalent expressions.
A vacation resort offers surfing lessons and parasailing. If a
person takes a surfing lesson and goes parasailing, she will pay
a total of $175. On Friday, the resort collects a total of $3,101 for
activities. How much does each activity cost?
After solving the equations, the cost of parasailing will be 99.75 and the cost of surfing will be equal to 75.25.
What is an Expression?Mathematical actions are called expressions if they have at least two terms that are related by an operator and include either numbers, variables, or both.
Adding, subtraction, multiplying, and division are all reflection coefficient operations. A mathematical operation such as reduction, addition, multiplication, or division is used to integrate terms into an expression.
The given information in the question is,
Assume the cost of parasailing is x and the cost of surfing is y.
x + y = 175
Total number of people in Parasailing = 16 people
Total number of people in Surfing = 20 people
Total collection done by resort = $3,101
16x + 20y = 3,101
So, the equations will be,
16x+20y=3,101 (i)
x + y = 175 (ii)
Now, multiply the equation (ii) by 16 and solve the equation,
16x+20y=3,101
16x+16y= 2,800
4y = 301
Now, find the value of y,
y = 301/4
y = 75.25
Then, the value of x will be equal to,
x + y = 175
x+75.25 =175
Solve for x:
x=175-72.25
x = 99.75
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It seems that your question is not complete, the complete question should be:
A vacation resort offers surfing lessons and parasailing. If a person takes a surfing lesson and goes parasailing, she will pay $175. There are 16 people who go parasailing and 20 people who take surfing lessons. On a Friday, the resort collects a total of $3,101 for activities. How much does each activity cost?
Let RP* be a complexity class defined as follows. A language L is in RP* if and only if there is a polynomial time Turing machine M and a polynomial p such that (i) if we L, then Prųe{0,1 }p(w) [M accepts (w,t)]21-(1/2)lwl and (ii) if w & L, then Prge{0,1}P(w) [M rejects (w,t)] = 1. Thus M comes "exponentially close" to deciding L with certainty. Prove that RP* = RP.
Main answer: RP* = RP.
Supporting answer:
RP* is defined as the set of languages L for which there exists a polynomial-time Turing machine M that, on input w, halts with probability at least 1/2 if w is not in L, and halts with probability at least 1 - 2-l|w| if w is in L. This definition is almost identical to the definition of RP, except that the probability of error is reduced from 1/2 to 2-l|w|. However, RP* and RP are equivalent.
To see that RP* is a subset of RP, note that if a language L is in RP*, then there exists a polynomial-time Turing machine M and a polynomial p such that (i) if we L, then Prųe{0,1 }p(w) [M accepts (w,t)]21-(1/2)lwl and (ii) if w & L, then Prge{0,1}P(w) [M rejects (w,t)] = 1. This means that M can be used as a randomized algorithm for L with error probability at most 1/2. Therefore, L is in RP.
To see that RP is a subset of RP*, note that if a language L is in RP, then there exists a polynomial-time Turing machine M and a constant c such that (i) if we L, then Prųe{0,1}c|w|[M accepts (w,t)] >= 1/2 and (ii) if w & L, then Prge{0,1}P(w) [M rejects (w,t)] < 1/2. By setting p(n) = c * 2n, we obtain a Turing machine M' that satisfies the conditions of RP*. Therefore, L is in RP*.
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Give an example of a series [infinity]
∑
n
=
1
c
n
that diverges even though c
n
<
0.0000001
for all n
and lim
n
→
[infinity]
c
n
=
0.
One example of such a series is the harmonic series with alternating signs:
∑n1(−1)nn= −1/1 + 1/2 − 1/3 + 1/4 − 1/5 + ...
This series alternates between positive and negative terms, with the magnitude of each term decreasing as n increases. Therefore, we can choose c
n
to be the absolute value of each term, which is always less than 0.0000001 for sufficiently large n.
Additionally, we know that the limit of the sequence of terms is zero, since the terms approach zero as n goes to infinity. However, the series still diverges, as shown by the alternating series test. Therefore, this series satisfies the conditions given in the problem.
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Gasoline Many drivers of cars that can run on regular gas actually buy premium in the belief that they will get better gas mileage. To test that belief, we use 10 cars from a company fleet in which all the cars run on regular gas. Each car is filled first with - either regular or premium gasoline, decided by a coin toss, and the mileage for that tankful is recorded. Then the mileage is recorded again for the same cars for a tankful of the other kind of gasoline. We don't let the drivers know about this experiment. Here are the results (miles per gallon): a) Is there evidence that cars get significantly better fuel economy with premium gasoline? b) How big might that difference be? Check a 90% confidence interval. c) Even if the difference is significant, why might the company choose to stick with regular gasoline? d) Suppose you had done a "bad thing." (We're sure you didn't.) Suppose you had mistakenly treated these data as two independent samples instead of matched pairs. What would the significance test have found? Carefully explain why the results are so different.
a) There is not enough evidence to conclude that cars get significantly better fuel economy with premium gasoline.
In order to test the belief that premium gasoline provides better fuel economy, a study was conducted using 10 cars from a company fleet. Each car was randomly assigned either regular or premium gasoline, and the mileage for each tankful was recorded. The data was analyzed to determine if there is a significant difference in fuel economy between the two types of gasoline.
To evaluate this, a paired t-test can be used since the same cars were tested with both types of gasoline. The null hypothesis would be that there is no difference in fuel economy between regular and premium gasoline, while the alternative hypothesis would be that there is a significant difference.
The results of the study would be analyzed using the appropriate statistical test, such as a paired t-test, to determine the p-value. If the p-value is less than the chosen significance level (e.g., 0.05), then there would be evidence to reject the null hypothesis and conclude that there is a significant difference in fuel economy.
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Is (x+1) a factor of f(x) = x^4 - 3x^3 + 2x - 2?
Answer:
\(\text{Yes}\)Explanation:
According to the factor theorem, if we set x+1 to zero, the substitute the x value into the polynomial, if we get a value of zero, then x+1 is a factor of the polynomial, otherwise, it is not
We start by setting x+1 to zero:
\(\begin{gathered} \text{ x+1 = 0} \\ x\text{ = -1} \end{gathered}\)Substitute -1 into the polynomial:
\(\begin{gathered} f(-1)=-1^4-3(-1)^3+2(-1)-2 \\ f(-1)\text{ = 1+3-2-2} \\ f(-1)\text{ = 4-4} \\ f(-1)\text{ = 0} \end{gathered}\)This shows that (x+1) is a factor of the polynomial
11 You are renting a car for a trip. You call two different rental car places about prices. Each
rental place charges a set-up fee for renting a car per day and a price per miles driven.
Find the number of miles when both companies will be the same cost.
Answer:
Step-by-step explanation:
m is number of miles
A: 45+0.21m (45 is the initial cost)
B: 28+0.38m (28 is the initial cost)
To know how in many miles the cost will be equal,
45+0.21m=28+0.38m
0.38m-0.21m=45-28
0.17m=17
m=17/0.17 = 100
So, at 100 miles the cost will be same for company A and B.
Does this graph have a proportional relationship? Explain how you know.
Answer: yes
Step-by-step explanation:
it does have a proportional relationship because as the number of days goes on the number of sales increases. it's a direct relationship
Find the value of x. Round
the nearest tenth.
Answer:
x = 13.5
Step-by-step explanation:
We need to use the law of sines
sin 27 sin 34
------- = --------
11 x
Using cross products
x sin 27 = 11 sin 34
x = 11 sin 34/ sin 27
x=13.54901
To the nearest tenth
x = 13.5
the tiles to the correct boxes to complete the pairs.
Match each power of i to its equivalent expression.
Tiles
1
Pairs
181
¡52
199
¡66
-1
11
-1
Step-by-step explanation:
just keep in mind :
i = sqrt(-1)
that is all we need to know.
from there we know the forever repeating group of 4 "power of i" values :
i¹ = i
i² = sqrt(-1)² = -1
i³ = i²×i = -1×i = -i
i⁴ = i²×i² = -1×-1 = 1
and this repeats now over and over again with the following powers :
i⁵ = i⁴×i = 1×i = i
i⁶ = i⁴×i² = 1×-1 = -1
i⁷ = i⁴×i³ = 1×-i = -i
i⁸ = i⁴×i⁴ = 1×1 = 1
and so on and so on ...
so,
i⁸¹ = i⁸⁰×i = (i⁴)²⁰×i = 1²⁰×i = 1×i = i
i⁵² = (i⁴)¹³ = 1¹³ = 1
i⁹⁹ = i⁹⁶×i³ = (i⁴)²⁴×i³ = 1²⁴×-i = 1×-i = -i
i⁶⁶ = i⁶⁴×i² = (i⁴)¹⁶×i² = 1¹⁶×-1 = 1×-1 = -1
for such questions always look for the modulo (remainder) result when dividing the exponent by 4. and then use the first list or table above.
complete the statement ""a group element x is its own inverse if and only if |x| .""
The completed statement is: A group element x is its own inverse if and only if |x| = 2.
"A group element x is its own inverse if and only if |x| = 2."
Here's a step-by-step explanation:
1. A "group" is a set of elements with a specific binary operation that satisfies certain conditions, like closure, associativity, having an identity element, and every element having an inverse.
2. An "element" is a member of the group, denoted by x in this case.
3. An "inverse" is an element that, when combined with another element using the group operation, results in the identity element of the group.
4. The statement says that x is its own inverse, meaning that when you combine x with itself using the group operation, you get the identity element.
5. |x| represents the order of the element x, which is the smallest positive integer n such that x^n results in the identity element.
6. When x is its own inverse, combining x with itself (x^2) will give the identity element, meaning |x| = 2.
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What are SAS and RHS congruence criterions?
The SAS states that two triangles that have two pairs of corresponding congruent sides and a pair of corresponding included congruent angles are congruent.
The RHS congruence criterion states that two right triangles that have a congruent pair of hypotenuses and a congruent pair of corresponding sides are congruent.
What is the SAS Congruence Criterion?The SAS congruence criterion is a postulate that shows that if two triangles have two pairs of corresponding congruent sides and a pair of corresponding included congruent angles, then both triangles are equal or congruent to each other.
What is the RHS Congruence Criterion?
The RHS stands for "right angle-hypotenuse-side". This congruence criterion states if two right triangles have congruence hypotenuses and a pair of corresponding congruent sides, then the two right triangles congruent to each other.
In summary, SAS congruence criterion proves that two triangles with two pairs of corresponding congruent sides and a pair of corresponding included congruent angles are congruent, while the RHS congruence criterion proves that two right triangles are congruent if they have equal pair of hypotenuses and a congruent pair of corresponding sides.
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In the figure below, m||n. Match the angle pairs with the
correct label for the pairs.
On solving the provided question, by properties of parallel lines we got to know that - 1 - A 2 - C 3 - B 4 - D
what is alternate exterior angles?When two or more lines cross the intersection line, alternate exterior angles result. These angles are created on a number of sides outside the transverse lines. Any two parallel lines that cross one another create two angles with the horizontal line. In the area between the parallel lines, interior angles are formed, while alternate exterior angles are formed in the area outside the parallel lines.
Matches are -
1 - A
2 - C
3 - B
4 - D
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Which situation would be represented by zero? An altitude of 37 feet. An altitude of 7 meters below sea level. An altitude of 8 meters above sea level. An altitude at sea level.
Answer: an altitude at sea level
How to get the answer of 2/5 X -3/7 - 1/14 - 3/7 X 3/5 using distributive property of multiplication?
Answer:
The answer to the given question is - ¹/₂
Step-by-step explanation:
Given;
\(\frac{2}{5} \times -\frac{3}{7} - \frac{1}{14} - \frac{3}{7} \times \frac{3}{5}\)
Before we apply the distributive property, perform the multiplication operation.
\((\frac{2}{5} \times -\frac{3}{7}) - \frac{1}{14} - (\frac{3}{7} \times \frac{3}{5} )\\\\\frac{-6}{35} - \frac{1}{14} - \frac{9}{35}\)
Now, apply the distributive property, to obtain the final answer,
In distributive property, the following rule is applied;
ax + ay = a(x + y)
\(\frac{-6}{35} - \frac{1}{14} - \frac{9}{35} = \frac{-1}{7} (\frac{6}{5} + \frac{1}{2} + \frac{9}{5} )= \frac{-1}{7} (\frac{12 + 5+ 18}{10} )= \frac{-1}{7} (\frac{35}{10} ) = \frac{-35}{70} = \frac{-1}{2}\)
Therefore, the answer to the given question is - ¹/₂
pls give two answers for good measure
Answer:
2nd answer choice.
Step-by-step explanation:
The inequality is x-5 greater/equal to -2 which if you simplify gives you x>= 3 and since the second answer choice has a filled-in dot which means equal to and the arrow goes to the right which means greater than.
Step-by-step explanation: To solve for x in this inequality,
your goal is the same as it would be if you were solving an
equation, to get x by itself on one side.
Since 5 is being subtracted from x, add 5 to both sides of the inequality.
On the left, the -5and +5 cancel out and on the right, -2 + 5 is 3.
So we have x ≥ 3.
When graphing, start with a closed dot at +3 because x is
not just greater than +3, it's equal to it as well.
Then draw an arrow to the right, like I have done below.
Determine whether the statement is true or false. If false, give a counterexample.
Walking on four legs is a sufficient condition for being a dog.
The statement "Walking on four legs is a sufficient condition for being a dog" is false.
Walking on four legs is not a sufficient condition for being a dog because there are other animals that walk on four legs but are not dogs. A counterexample would be a cat, which is a common example of an animal that walks on four legs but is not a dog. There are also various other animals like horses, cows, and elephants that walk on four legs but are not dogs.
Therefore, walking on four legs is not enough to determine if an animal is a dog, as there are multiple species that fit this description.
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if its assumptions are met, the analysis of variance technique is appropriate when ____.
Answer:
comparing the means of three or more groups
Step-by-step explanation:
A square field has an area of 12,100sqm. Find the
perimeter of the field.
a. 110m
b. 220m
C. 330m
d. 440m
Pls show working
Answer:
440m
Step-by-step explanation:
First you would square root the value 12100 to get one of the length of the square.
\(\sqrt{121000}\)=110m
A square has four sides so,
110*4=440m
Answer:
440m
Step-by-step explanation:
Formula of a square's field : a square
So, area is 12,100. Then, let's take this value into the square root.
Now, we found the one edge of this square which is 110m
For finding perimeter, a square has a 4 edge. So, we multiple 110 x 4 = 440m.
Alyssa is drafting an email to Stuart, a financial advisor. He said he could help her create a personalized budget. What information will Stuart need to use to set up a personal budget for Alyssa? Select all that apply.
The information needed through Email from Alyssa to Stuart to create a personalized budget is:
The amount of mortgage paymentThe annual salarySupermarket expenses/ GroceriesWhat is Personalized Budget?
A personal budget, or household budget, simply tracks a household’s money in versus money out. Though a budget can be used to help an individual or family spend less and save more, it is, at its most basic, a planning and tracking tool.
Hello! It was so great catching up with you at the supermarket! You
mentioned that you might be able to help me create a personalized budget.
I am currently employed as a director at a day care center on the corner of 1st and Main Street. My birthday is on June 3. My largest expense is my mortgage payment of $1,200 per month. I picked a house in this neighborhood because it is close to work. Last year, my annual salary was $40 030. Please let me know if you can help!
Thank you,
Alyssa Palmer
Thus, from the above letter, Stuart will need the following;
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Solve the system of equations using substitution.
4x - y = 7
3y – 12x = -21
(3,5)
(6, 17)
no solution
infinite solutions
Answer:
Infinite amount of solutions
Step-by-step explanation:
Step 1: Write systems of equations
4x - y = 7
3y - 12x = -21
Step 2: Rewrite
-y = 7 - 4x
y = 4x - 7
Step 3: Solve for x
Substitute in y into second equation: 3(4x - 7) - 12x = -21Distribute 3: 12x - 21 - 12x = -21Combine like terms: -21 = -21Here we see that we would have infinite amount of solutions.
Answer: infinite solutions. Just took the quiz
Step-by-step explanation:
let a and b be integers. prove that if ab = 4, then (a – b)3 – 9(a – b) = 0.
Let \(\(a\)\) and \(\(b\)\) be integers such that \(\(ab = 4\)\). We want to prove that \(\((a - b)^3 - 9(a - b) = 0\).\)
Starting with the left side of the equation, we have:
\(\((a - b)^3 - 9(a - b)\)\)
Using the identity \(\((x - y)^3 = x^3 - 3x^2y + 3xy^2 - y^3\)\), we can expand the cube of the binomial \((a - b)\):
\(\(a^3 - 3a^2b + 3ab^2 - b^3 - 9(a - b)\)\)
Rearranging the terms, we have:
\(\(a^3 - b^3 - 3a^2b + 3ab^2 - 9a + 9b\)\)
Since \(\(ab = 4\)\), we can substitute \(\(4\)\) for \(\(ab\)\) in the equation:
\(\(a^3 - b^3 - 3a^2(4) + 3a(4^2) - 9a + 9b\)\)
Simplifying further, we get:
\(\(a^3 - b^3 - 12a^2 + 48a - 9a + 9b\)\)
Now, notice that \(\(a^3 - b^3\)\) can be factored as \(\((a - b)(a^2 + ab + b^2)\):\)
\(\((a - b)(a^2 + ab + b^2) - 12a^2 + 48a - 9a + 9b\)\)
Since \(\(ab = 4\)\), we can substitute \(\(4\)\) for \(\(ab\)\) in the equation:
\(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 48a - 9a + 9b\)\)
Simplifying further, we get:
\(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 39a + 9b\)\)
Now, we can observe that \(\(a^2 + 4 + b^2\)\) is always greater than or equal to \(\(0\)\) since it involves the sum of squares, which is non-negative.
Therefore, \(\((a - b)(a^2 + 4 + b^2) - 12a^2 + 39a + 9b\)\) will be equal to \(\(0\)\) if and only if \(\(a - b = 0\)\) since the expression \(\((a - b)(a^2 + 4 + b^2)\)\) will be equal to \(\(0\)\) only when \(\(a - b = 0\).\)
Hence, we have proved that if \(\(ab = 4\)\), then \(\((a - b)^3 - 9(a - b) = 0\).\)
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PLEASE HELP ME ASAP PLEASE.
Answer:
See below
Step-by-step explanation:
g (h(6)) :
h (6) = 3 ( 6^2) + 2 = 110
then g (110) = sqrt (110)
h (g(5))
g(5) = sqrt 5
then h( sqrt5) = 3 ( sqrt5)^2 + 2 = 17
Formalize the following in terms of atomic propositions r, b, and w, first making clear how they correspond to the
English text. (a) Berries are ripe along the path, but rabbits have not been seen in the area.
(b) Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.
(c) If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.
(d) It is not safe to walk along the path, but rabbits have not been seen in the area and the berries along the path are ripe.
e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to
pave been seen in the area.
Walking is not safe on the path whenever rabbits have been seen in the area and berries are ripe along the path.
Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path. This is formalized by using the →(if-then) and ∧(logical and) operators.
Given information and corresponding atomic propositions:
We need to formalize the given statements in terms of atomic propositions r, b, and w, which are defined as follows:
r: Rabbits have been seen in the area.
b: Berries are ripe along the path.
w: Walking on the path is safe.
Now, let us formalize each of the given statements in terms of these atomic propositions:
a) Berries are ripe along the path, but rabbits have not been seen in the area.
b: Rabbits have not been seen in the area, and walking on the path is safe, but berries are ripe along the path.
c: If berries are ripe along the path, then walking is safe if and only if rabbits have not been seen in the area.
d: It is not safe to walk along the path, but rabbits have not been seen in the area, and the berries along the path are ripe.
e) For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.
Walking is not safe on the path whenever rabbits have been seen in the area, and berries are ripe along the path.
The formalizations in terms of atomic propositions are:
a) b ∧ ¬r.b) ¬r ∧ w ∧
b.c) (b → w) ∧ (¬r → w).
d) ¬w ∧ ¬r ∧
b.e) (¬r ∧ ¬b) → w.b ∧
Berries are ripe along the path, but rabbits have not been seen in the area.
This is formalized by using the ∧(logical and) operator.
(¬r ∧ ¬b) → w: It means For walking on the path to be safe, it is necessary but not sufficient that berries not be ripe along the path and for rabbits not to have been seen in the area.
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