Under What Conditions Will The Behavior Of A Real Gas Best Approximate The Behavior Of An Ideal gas? I High temperature II High pressure
a) I only
b) II only
c) Both I and II
d) Neither I nor II

The radius of the smallest electron orbit in a singly-ionized helium atom is 0.265 Å.

The radius of the smallest electron orbit in a singly-ionized helium atom can be calculated using the Bohr model of the atom.

In the Bohr model, the radius of an electron orbit is given by the formula:

r = (0.529 Å) * n² / Z

Where:

r is the radius of the electron orbit,

Å is the Angstrom unit (1 Å = 10⁻¹⁰ meters),

n is the principal quantum number (for the smallest orbit, n = 1),

Z is the atomic number (number of protons in the nucleus).

For a singly-ionized helium atom, the atomic number (Z) is 2, as helium has two protons in its nucleus.

Plugging in the values into the formula:

r = (0.529 Å) * (1²) / 2

r = 0.529 Å / 2

r = 0.265 Å

Therefore, the radius of the smallest electron orbit in a singly-ionized helium atom is approximately 0.265 Angstroms (Å).

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Answer: I'm not sure but I thinks its  C

Explanation:

The heat produced by the reaction, follow these steps Calculate the total mass of the solution The volume of both solutions combined is 50.0 mL + 50.0 mL = 100.0 Mlo Since the density of the solution is 1.00 g/mL, the mass is 100.0 mL x 1.00 g/mL = 100.0 g.

The Calculate the temperature change the final temperature is 28.9°C, and the initial temperature is 22.0°C. So, the temperature change is 28.9°C - 22.0°C = 6.9°C.  Use the formula for heat (q): q = mcΔT, where m is the mass of the solution, c is the specific heat of the solution (4.18 J/Gac), and ΔT is the temperature change. Plug in the values: q = (100.0 g) x (4.18 J/Gac) x (6.9°C) = 2884.2 J. Convert the heat to kJ: 2884.2 J ÷ 1000 = 2.884 kJ (approximately). The heat produced by the reaction is approximately +2.9 kJ (option a).

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The mass of Cu in 14.0 g of the alloy is 2.76 g.

To find the mass of Cu in 14.0 g of an alloy that is 16.6% Cu, we need to first calculate the total amount of Cu in the alloy.

Assuming we have 100 g of the alloy, the mass of Cu present in it would be:

Mass of Cu = 16.6% * 100 g = 16.6 g

So, the mass of Cu in 14.0 g of the alloy would be:

Mass of Cu = (14.0 g / 100 g) * 16.6 g = 2.76 g

As a result, the mass of Cu in 14.0 g of the alloy is 2.76 g.

The given alloy contains 16.6% Cu, which means that 100 g of the alloy contains 16.6 g of Cu. To find the mass of Cu in 14.0 g of the alloy, we need to calculate the mass of Cu in 100 g of the alloy and then adjust it for the given amount of the alloy (14.0 g).

By using the formula (mass of Cu in given alloy = percentage of Cu in alloy * total mass of alloy) we can calculate the mass of Cu in the given alloy, and then by multiplying it with the ratio of given alloy to total alloy we can calculate the mass of Cu in the given alloy.

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Answer:

A

Explanation:

yellow perch doesn't have a arrow to it from the snail

The solubility of KCl at 90°C is 144 g/L.

To calculate the solubility of KCl at 90°C, we need to determine the amount of KCl that dissolves in 1 dm³ of water at that temperature. The solubility of a compound is typically expressed in terms of the mass of the compound that dissolves in a given volume of solvent.

Given:

Mass of KCl = 144 g

Volume of water = 1 dm³

Step 1: Convert volume to liters

1 dm³ = 1 L

Step 2: Calculate the solubility

Solubility = Mass of solute / Volume of solvent

Solubility = 144 g / 1 L = 144 g/L

It's worth noting that the solubility of KCl can vary with temperature. The given solubility value is specific to the conditions provided (90°C). If the temperature changes, the solubility of KCl may also change. Solubility is often reported as a function of temperature to reflect this relationship.

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Answer:

Explanation:

2 H₂(g) + O₂(g) → 2 H₂O(g

2 moles     1 mole      2 mole

50 g of H₂ = 50 /2 = 25 moles of H₂

100 g of O₂ = 100 / 32 = 3.125 moles of O₂

So oxygen is the limiting reagent .

3.125 moles of O₂ will react with 6.25 moles of H₂ to give 6.25 moles of H₂O .

Hence moles of H₂O produced = 6.25 moles .

Natural formation of lead occurs by radioactive decay of uranium and thorium through radon (222Rn). Four stable isotopes are known, 204Pb, 206Pb, 207Pb and 208Pb, the first three of which are used for estimating the ages of rocks. Lead compounds exist mainly in +2 or +4 oxidation states, the former being more common.

Answer:

2Mg + 4HCl (aq) --> 2 MgCl2 (aq) + H2

Explanation:

balanced...

The growing understanding of how proteins fold allows researchers to make predictions about protein structure based on amino acid sequence data. Considering the amino acid sequence.

a) Bends or turns are most likely to occur at residues 7 and 19 because Pro residues are often (but not always) found at bends in globular folded protiens. A bend may also take place at the Thr residue (residue 4) and, assuming that this is a portion of a larger polypeptide, at the Ile residue (residue 1).

GPFG and QPDG

b) Where might intrachain disulfide cross-lingages be formed between residues 13 and 24 (Cys residues).

c) interior (hydrophobic): ALA, Ile exterior (hydrophillic): Gln, Lys, Asp

THR- intermediate and could found at both.

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The bond and the force present between molecules is called intermolecular force. A hydrogen bond is present between the stearic acid and a water molecule.

Hydrogen bonds are the intermolecular force that forms a dipole-dipole interaction with an electronegative atom in the presence of the lone pair of electrons.

In stearic acid, \(\rm C_{18}H_{36}O_{2}\), hydrogen bonding exists between the oxygen and the hydrogen atom of the molecule.

Therefore, a hydrogen bond is present between stearic acid and the water molecule.

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Answer:

Sb

Explanation:

Sb (antimony) is an metalloid

Explanation:

Wyzant

CHEMISTRY

Zoey C. asked • 06/05/19

Calcium hydroxide reacts with sodium phosphate to produce calcium phosphate and sodium hydroxide. If 100 grams of calcium hydroxide reacts with 100 grams of sodium phosphate,

determine the amount of each chemical present when the reaction is complete

Grams calcium hydroxide =?

Grams of sodium phosphate=?

Grams of calcium phosphate=?

Grams of sodium hydroxide?

Mass reactants=?

Mass after reaction?

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J.R. S. answered • 06/06/19

TUTOR 5.0 (133)

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3Ca(OH)2 + 2Na3PO4 ==> Ca3(PO4)2 + 6NaOH ... balanced equation

First, find the limiting reactant:

moles Ca(OH)2 present = 100 g x 1 mole/74.09 g = 1.35 moles (divided by 3-->0.45)

moles Na3PO4 present = 100 g x 1 mole/163.9 g = 0.610 moles (divided by 2-->0.31)

LIMITING reactant is Na3PO4

There will be zero grams Na3PO4 left after the reaction

For grams Ca(OH)2 left: 0.610 mol NaP x 3 mol Ca(OH)2/2 mol NaP = 0.915 mol Ca(OH)3 used up

Grams left over: 1.35 mol - 0.915 mol = 0.435 mol x 74.09 g/mol = 32 g left over (30 g if use 1 sig. fig.)

For grams of calcium phosphate left: 0.610 mol NaP x 1 mol CaP/2 mol NaP = 0.305 mol CaP formed

Grams at end of rx: 0.305 moles CaP x 310 g/mol = 94 g (90 g if use 1 sig. fig.)

For grams NaOH left: 0.610 mol NaP x 6 mol NaOH/2 mol NaP = 1.83 moles NaOH formed

Grams at end of rx: 1.83 moles NaOH x 40 g/mol = 73 g (70 g if use 1 sig. fig.)

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According to stoichiomtry, 19.99 grams of calcium hydroxide will be needed to completely react with 29.5 grams of sodium phosphate.

Stoichiometry is a process of the determination of proportions of elements or compounds that are present in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is often  used in quantitative analysis for measuring concentrations of substances which are  present in the sample.

As per the stoichiometry of the the given balanced chemical equation,\(222.27\ g\) calcium hydroxide gives \(327.88 \ g\) sodium phosphate, thus,\(29.5 \ g\) sodium phosphate requires,

\(\dfrac{29.5}{327.88}\times{222.27}\\=19.99 \ g\)

Thus, 19.99 grams of calcium hydroxide will be needed to completely react with 29.5 grams of sodium phosphate.

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Answer:

Due to global warming and ocean levels rising, Earth's ocean was made up of more frozen bodies of water. I wouldn't say Earth had more or less water in the past (because where would the water have come from?) but instead the water was less accessible due to it being frozen in glaciers. Comparing the ocean from 66 million years ago to today, I'd say the water levels have definitely risen since many city are below sea level now. You could say the surface area of the ocean has increased over time.

Leather and cloth gloves should not be used in pesticide handling because they can absorb and retain pesticide residues.

Leather and cloth gloves are porous materials that can absorb and retain pesticide residues. Pesticides are chemical substances designed to control pests, and they can be toxic or harmful to human health. When handling pesticides, it is important to use appropriate personal protective equipment (PPE) to minimize exposure. Leather and cloth gloves, although they provide physical protection to the hands, can absorb pesticides through their porous surfaces. This can lead to prolonged contact with the skin and potential absorption of the pesticide into the body.

Instead, impermeable gloves made of materials like nitrile, neoprene, or rubber are recommended for pesticide handling. These types of gloves provide a barrier that prevents the penetration of pesticide residues, reducing the risk of exposure and potential adverse effects.

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Answer:

5.12x10+5 lbs

2.32E+9 g

Explanation:

Density = 732.22 kg/m^3

Volume = 12 gal

Conversion Factor:  0.00378541 gal/m^3 or 264.1721769 m^3/gal

Convert 12 gallons to m^3:  (12 gal)*(264.2 m^3/gal) = 3170 m^3 in 12 gal

Determine total mass from volume:  (3170 m^3/12 gal)(732.2 kg/m^3) = 2321186 kg in 12 gal.

Conversion Factor:  1000 g/kg

Mass of gasoline:  (2321186 kg)*(1000g/kg) = 2.32E+9 g

Conversion Factor:  0.453592 kg/lb or 2.20462442 lb/kg

Yotal wieght = 231186 kg)*(2.205 lb/kg = 511734 lbs (5.12E+5 lbs)

Explanation:

by adding 273.15K to the given value of temperature in Celsius degree.

example:

20℃ to Kelvin

\(T(K)=20℃+273.15K \\

=293.15K \)

Answer:

8.765848 × 10^6

Explanation:

You move the decimal point 6 places to the right because it has to be between 1 and 10. Then, you multiply by 10 to the power of 6 because you moved the decimal point 6 times.

S-32 is probably the isotope of sulphur with the largest isotopic abundance.

The average atomic mass of an element is the weighted average of the masses of all of its isotopes, with the isotopic abundance of each isotope serving as the weighting factor. Given that sulphur has an average atomic mass of 32.06, the isotope with the highest isotopic abundance is probably S-32, which has an atomic mass of 32.066 atomic mass units. This is due to the fact that an element's most prevalent isotope has a significant impact on the average atomic mass of the element. While S-33, S-34, and S-36, other sulphur isotopes, also contribute to the average atomic mass, the largest isotopic abundance will predominate the outcome.

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Answer:

Al2(SO4)3

Explanation:

3Na2SO4 + 2AlCl3 →+ Al2(SO4)3 + 6NaCl

Answer:

A thermochemical equation for the combustion of propane (C3H8)(C3H8) is written as follows:

C3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔH∘rxnC3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔHrxn∘ = -2202.0 kJ/mol

The value given for ΔH∘rxnΔHrxn∘ means that:

a. the reaction of one mole of propane absorbs 2202 kJ of energy from the surroundings.

b. the reaction is endothermic.

c. the enthalpy of formation of propane is 2202 kJ/mol.

d. the reaction of one mole of propane releases 2202 kJ of energy to the surroundings.

e. None of these.

Answer:

The mass density of NaCl is (23 + 35.5)/175.6 g/Å^3 = 0.391 g/cm^3.

(a) In a (100) plane, the Na and Cl atoms form a square lattice with Na atoms at the corners and Cl atoms at the center of each side of the square.

(b) The lattice constant is the distance between adjacent Na or Cl atoms. In a simple cubic lattice, this is equal to the diameter of the sphere (2 x radius) plus the distance between the centers of adjacent spheres. For NaCl, this gives a lattice constant of 5.6 Å.

(c) The volume density of Na atoms is the number of Na atoms per unit volume, which is equal to the inverse of the volume of the unit cell. For NaCl, the unit cell has a volume of (5.6 Å)^3 = 175.6 Å^3, so the volume density of Na atoms is 1/175.6 Å^3 = 0.0057 Å^-3. Similarly, the volume density of Cl atoms is also 0.0057 Å^-3.

(d) The mass density of NaCl is the sum of the masses of the Na and Cl atoms in the unit cell divided by the volume of the unit cell. The mass of an Na atom is 23 g/mol and the mass of a Cl atom is 35.5 g/mol. The number of Na atoms in the unit cell is 1 and the number of Cl atoms is also 1.

Therefore, the mass density of NaCl is (23 + 35.5)/175.6 g/Å^3 = 0.391 g/cm^3.

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The temperature change obtained by Al is accurate

From the question, we were told that the thermometer is faulty, given a reading that is 2.0 °C too high.

Al obtained a temperature change of 11.4 °C.

This value (11.4 °C.) is consider accurate because twhen we subtract 2 from both the initial and final temperature, the change in temperature obtained will still be the same. This is illustrated below:

ΔT = T₂ - T₁

ΔT = 54.7 - 43.3

ΔT = 11.4°C

Thus, we can see that the result obtained is still 11.4°C. Therefore, the temperature change obtained by Al is accurate

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Answer:

10.3

Explanation:

Answer: barium oxide

Explanation: The barium will give some of it's electrons up to the oxygen, and then they will both reach the stability of a noble gas. Then, they will both combinate to barium oxide, so the answer is barium oxide.

Answer:

37

Explanation:

( 98.6 - 32 ) × 5(100c) ÷ 9(180f) = 37

The pH of this solution is approximately 4.74, indicating it is slightly acidic. The presence of sodium acetate, a salt of acetic acid, acts as a buffer and helps maintain the pH of the solution.

The pH of a solution containing\(10^-2\) M acetic acid and 2 x\(10^-2\) M sodium acetate can be determined using a logarithmic concentration diagram.

To determine the pH of the solution, we need to consider the dissociation of acetic acid and the hydrolysis of sodium acetate. Acetic acid (CH3COOH) is a weak acid that partially dissociates in water, releasing hydrogen ions (H+) and acetate ions (CH3COO-).

The dissociation of acetic acid can be represented as follows:

CH3COOH ⇌ H+ + CH3COO-

The equilibrium constant for this dissociation is known as the acid dissociation constant (Ka). The pKa value of acetic acid is approximately 4.74. The pKa is the negative logarithm of the Ka value.

In the given solution, we have both acetic acid and sodium acetate. Sodium acetate (CH3COONa) is a salt that dissociates completely in water, releasing sodium ions (Na+) and acetate ions (CH3COO-). The acetate ions from sodium acetate can react with any additional H+ ions present in the solution through hydrolysis, which helps maintain the pH.

Using a logarithmic concentration diagram, we can determine that the pH of the solution containing \(10^-2\) M acetic acid and 2 x \(10^-2\) M sodium acetate is approximately 4.74, which is slightly acidic.

The presence of sodium acetate acts as a buffer, helping to resist changes in pH by absorbing excess H+ ions or releasing additional H+ ions as needed to maintain the pH within a certain range.

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