Un móvil sale de una localidad A hacia la localidad B con una velocidad de 80 [km/h], 90 minutos después sale desde el mismo lugar y en su persecución otro móvil a 27,78 [m/s]. Calcular:a. ¿Aqué distancia de la, localidad Alo alcanzará? b. ¿En qué instante lo alcanzará?

Answer:

The velocity of the car of mass 4 kg with respect to ground is 0 m/s

Explanation:

The problem initially stated that the car is at rest. at this stage, the velocity of the car relative to the ground is already = 0 m/s.

When the 10 kg car began to move, the problem did not specify at any point that the 4 kg car began to move also. Hence, the motion of the 10 kg car did not affect the 4 kg car in any way.

As a result, relative to the ground, the velocity of the 4 kg car is still 0 m/s since no motion was recorded by the car.

The ratio of the height attended by the object thrown upward to that thrown at some angle θ with the vertical is 1.  

Note: It is assumed that the mass of the first object is m and the mass of the second object is 2m. Also, the first object is thrown upward and the second object is thrown at some angle θ with the vertical.

Projectile motion: Any object that is thrown in the air is called a projectile and the motion described by it under gravity is called the projectile motion.  

If the air resistance is neglected, then the acceleration due to gravity g is the same for all objects irrespective of their masses. It is given that both objects remain in the air for the same time period. So first calculate the time period for the objects when they are in the air.

Time period of the first object: The first object is thrown in the air upwards so from the second kinematics equation,

h1=u1*t1-(1/2)*gt1^2

where h1 is the height, t1 is the time, and u1 is the initial velocity for the first object.

When the object is not in air h1=0, so

0=u1*t1-(1/2)*gt1^2

After solving the above quadratic equation, the values of t1 obtained are t1=0 which represents the initial time, and t1=2u1/g which represents the time period. So the time period of the first object is,

t1=2u1/g

Time period of the second object: The second object is thrown at some angle θ with the vertical as shown in the diagram. From the diagram, the initial velocity along the vertical direction is,

u2=uocos(θ)

where uo is the initial velocity and u2 is the initial velocity along the vertical direction.

From the second kinematic equation,

h2=u2*t2-(1/2)*gt2^2

where h2 is the height, t2 is the time, and u2 is the initial velocity for the second object along the vertical direction.

When the object is not in air h2=0, so using u2=uocos(θ),

0=uocos(θ)*t2-(1/2)*gt2^2

After solving the above quadratic equation, the values of t2 obtained are t2=0 which represents initial time, and t2=2uocos(θ)/g which represents  the time period. So the time period of the second object is,

t2=2uocos(θ)/g

Given that the time period is the same for both cases,

t1=t2

2u1/g=2uocos(θ)/g

u1=uo cos(θ)

Calculation of the ratio of the height of the object:

The maximum height is attained when the time of the object in the air is half of the total time period. At maximum height, velocity is zero.

From the third equation of motion.

v^2=u^2-2gh

h=u^2/2g

where h is the height and u is the initial velocity of an object.

Using it and u1=uo cos(θ) and u2=uo cos(θ), the ratio of h1 and h2 is,

h1/h2=  u1^2/2g÷u2^2/2g

h1/h2=(uo cos(θ))^2/(uo cos(θ))^2

h1/h2=1

The ratio of their height will be 1.

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Answer:

A.falling time

Explanation:

Because dependent variable is one that changes with respect to the other fixes quantities and here its falling time that changes

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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In general, air-source heat pumps are sized to meet the heating and cooling demands of a building.

Air-source heat pumps are versatile heating and cooling systems that can extract heat from the outdoor air and transfer it into a building for heating purposes or remove heat from the indoor air for cooling. The sizing of an air-source heat pump is crucial to ensure that it can adequately meet the heating and cooling requirements of the space it is installed in.The sizing process takes into account factors such as the size and layout of the building, insulation levels, b, desired indoor temperatures, and the heating and cooling load calculations. Heating load calculations consider factors like the outdoor temperature, desired indoor temperature, insulation, air leakage, and more. Cooling load calculations consider factors like solar heat gain, indoor and outdoor temperature differentials, insulation, and more.By accurately sizing the air-source heat pump, it can operate efficiently, maintain comfortable indoor temperatures, and effectively meet the heating and cooling demands of the building. Improper sizing can lead to inefficient operation, inadequate heating or cooling, and increased energy consumption.

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According to conservation of energy, the energy of interacting bodies in a closed system remains constant. The total energy of an isolated system remains constant; it is said to be conserved over a period of time.

Elastic energy is the mechanical implicit energy stored in the configuration of a material or physical system as it's subjected to elastic distortion by work performed upon it. Elastic energy occurs when objects are impermanently compressed, stretched or generally misshaped in any manner.

The mechanical energy is never lost forever , rather it gets converted to thermal energy because of the friction .

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Answer: When two objects are pressed together with more force: B. Friction increases.

Friction refers to a force that resists or prevent the relative motion of two physical objects when their surfaces comes in contact.

This ultimately implies that, friction prevent the surfaces of two (2) objects from easily sliding over each other or slipping across one another.

Generally, the friction between two (2) objects is highly dependent on the force applied on the objects. Thus, an increase in the force applied on these objects would significantly increase the friction and vice-versa.

In conclusion, friction increases when two objects are pressed together with more force.

Explanation: Hope this helps :)

Answer:

the unit must always be indicated

Explanation:

displacement is alway in metre (m)

Answer:

A: measurement and direction

Explanation:

on edge! hope this helps!!~ (≡^∇^≡)

Answer:

1) Acids have a sour taste , Bases have a bitter taste.

2) Acids turn blue litmus paper into red , Bases turn red litmus paper into blue.

3) Acids react with most metals to form Hydrogen gas but only a few base react with a few metals to form Hydrogen gas

4) Both will conduct electricity. Both acids & bases are good electrolytes. Strong acids & bases conduct more electricity than that of weak acids & bases

Fill in the blanks with the properties of acids and bases as follows:

The properties of acids are as follows:

Therefore, fill in the blanks with the properties of acids and bases are well described above.

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The impulsive force of the car will be 4,333. Kg.m/s.

In physics, the term "impulse" is used to characterize or measure the impact of force operating gradually to alter an object's motion. It is often stated in Newton seconds or kilograms per second and is denoted by the symbol J.

given, A car with a mass of 1200kg, went from 20 km/hr to 7 km/hr.

From the general formula of impulse:

Impulsive force j = mass( initial velocity - final velocity)

In our case,

initial velocity = 20 Km/hr

Final velocity = 7 Km/hr

mass = 1200 Kg

So,

Impulsive force = 1200( 20 - 7)

impulsive force = 15600 Kg. km/hr

Since 1 km/ hr = 5/18 m/s

impulsive force = 15600 * 5 /18 Kg.m/s

impulsive force = 4,333.33  Kg.m/s

Therefore, the impulsive force of the car will be 4,333. Kg.m/s.

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Answer:

Because it has more texture and is solid. Its like glass

Explanation:

Answer:

Why is ice more reflective (has higher albedo) than liquid water? They're both the same substance (water). Is something quantum mechanical involved?

Explanation:

In fact ice is slightly less reflective than water. The reflectivity is related to the refractive index (in a rather complicated way) and the refractive index of ice is 1.31 while the refractive index of water is 1.33. The slightly lower refractive index of ice will cause a slightly lower reflectivity. In both cases the reflectivity is about 0.05 i.e. at an air/water or air/ice surface about 5% of the light is reflected.

Answer:

Friction

Explanation:

Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other.

Answer:

Cross-Species Sequence Comparisons

Explanation:

Cross-Species Sequence Comparisons can help in comparing the nucleotide sequences on DNA

In this comparative study, based on the different evolutionary distances, genomic sequences of species within the evolutionary tree can be determined. The coding and non coding sequences can be determined based on which it can be assessed that which are the unique gene sequences for a given species.

In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.

However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.

It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.

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Answer:

5.76 m/s

Explanation:

Applying,

S = d/t............... Equation 1

Where S = speed, d = distance, t = time.

For circular motion,

d = 2πr............ Equation 2

Where r = radius of the circular track, π = pie

Substitute equation 2 into equation 1

S = 2πr/t.............. Equation 3

From the question,

Given: r = 110 m, t = 2 minutes = (2×60) = 120 s

Constant: π = 3.14

Substitute these values into equation 3

S = (2×3.14×110/120)

S = 690.8/120

S = 5.76 m/s

a. A wave is a disturbance that travels through space and time, transferring energy from one point to another without causing any net movement of matter.

b.i) the length of the air column when the tube is held horizontally is 0 cm.

ii) The length of the air column when the tube is held vertically with the open end underneath is 0.045 cm.

(i) When the tube is held horizontally:

x =  length of the air column

Therefore, the pressure at the open end of the tube is 760 mmHg.

Using Boyle's law,

P1V1 = P2V2,

we can write:

760 × (15 + x) = 760 × 15

15 + x = 15

x = 0 cm

Therefore, the length of the air column when the tube is held horizontally is 0 cm.

(ii) When the tube is held vertically with the open end underneath:

Let the length of the air column be y cm.

The pressure at the open end of the tube is the atmospheric pressure plus the pressure due to the weight of the air column.

The pressure due to the weight of the air column is shown in the formula:

P = hρg,

Since the length of the air column is 20 cm when the tube is vertical and the open end is uppermost, the pressure due to the weight of the air column is:

P = (20/10) × (1.29 × 10^-3) × 9.8

= 0.02508 atm

Therefore, the pressure at the open end of the tube is:

760 + 0.02508 × 760

= 761.9 mmHg

Using Boyle's law as in (i), we can write:

761.9 × (15 + y) = 760 × 15

15 + y = 14.955

y = 0.045 cm

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Answer:

a) α = -65,2 rad/s².

b) t = 2,57 s.

Explanation:

a) La aceleración angular se puede calcular usando la siguiente ecuación:

\( \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta \)

En donde:

\(\omega_{f}\): es la velocidad angular final =  2000 rpm = 209,4 rad/s

\(\omega_{0}\): es la velocidad angular inicial = 3600 rpm = 377,0 rad/s

α: es la aceleración angular=?

θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad

Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.  

Resolviendo la ecuación (1) para α, tenemos:

\(\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}\)  

Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.  

b) El tiempo transcurrido se puede encontrar como sigue:

\( \omega_{f} = \omega_{0} + \alpha t \)

Resolviendo para t, tenemos:

\(t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s\)

Por lo tanto, el tiempo transcurrido fue 2,57 s.

Espero que te sea de utilidad!

The natural frequency of the system is 4.545 Hz and the driving frequency is 5 Hz.

The beat period is the difference between the period of the driving force and the period of the system's natural frequency. Thus, we have:

Beat period = 1/f_beat = 0.2 s

Period of the system = T = 0.02 s

Therefore, we can write:

1/f_driving - 1/f_natural = 1/f_beat

Solving for the natural frequency, we get:

f_natural = f_driving / (1 + f_driving * f_beat)

We know that the system is driven from rest, so the amplitude of the motion will be maximum at the driving frequency. Therefore, the driving frequency is given by:

f_driving = 1 / (2π√(m/k))

where m is the mass of the system and k is the spring constant.

Substituting the given values, we get:

f_driving = 5 Hz

Substituting this value into the equation for the natural frequency, we get:

f_natural = 4.545 Hz

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Option B: The pressure in the neck is equal to the pressure in the knee because of the equal dynamic pressure according to the continuity equation is the answer.

Assuming that the human circulatory system obeys Bernoulli's principle of hydrodynamics, the most accurate comparison of blood pressure in capillaries in the neck and those of equal cross-sectional area in the right knee yields: The neck pressure equals the knee pressure with the same dynamic pressure according to the continuity equation. The Bernoulli equation describes the flow of an incompressible fluid in a pipe and how that flow is affected by changes in pressure. 

In this case, it can be applied to the flow of blood through capillaries in the neck and right knee. The continuity equation, which states that the volume flow rate of fluid through a tube must remain constant, regardless of changes in the tube's cross-sectional area or shape, can also be applied in this case. Because the two capillaries have the same cross-sectional area, the dynamic pressure in both capillaries must be the same because of the continuity equation. This indicates that the pressure in the neck is equal to the pressure in the knee.

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Answer:

Explanation:

And the condition of problem N 6 ???

The angular acceleration of the merry-go-round is 4 rad/s².

To find the angular acceleration of the merry-go-round, follow these steps:

1. Convert the final angular speed from rev/s to rad/s:
Final angular speed = 0.50 rev/s * 2π rad/rev = π rad/s

2. Convert the number of revolutions to radians:
Number of revolutions = 2.0 rev * 2π rad/rev = 4π rad

3. Use the angular displacement equation to find the angular acceleration:
θ = ω₀ * t + 0.5 * α * t^2, where θ is angular displacement, ω₀ is initial angular speed (0 in this case), α is angular acceleration, and t is time.

4. Use the final angular speed equation to find time:
ω = ω₀ + α * t, where ω is final angular speed, ω₀ is initial angular speed (0 in this case), α is angular acceleration, and t is time.

5. Rearrange the final angular speed equation to find time in terms of angular acceleration:
t = (ω - ω₀) / α = π / α

6. Substitute the time expression into the angular displacement equation:
4π = 0.5 * α * (π / α)^2

7. Solve for angular acceleration:
α = 4 rad/s²

Hence, the angular acceleration of the merry-go-round is 4 rad/s².

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A spacecraft has captured and brought material to earth from a comet is True.

A spacecraft has indeed captured and brought material to Earth from a comet. One notable example is the NASA mission called Stardust, which launched in 1999. In 2004, Stardust encountered the comet Wild 2, collected samples of its coma (the cloud of gas and dust surrounding the nucleus), and then returned to Earth in 2006.

The spacecraft captured tiny particles of dust and organic material from the comet, providing valuable insights into the composition and origins of comets. This mission demonstrated the ability of spacecraft to retrieve and deliver extraterrestrial material to Earth for scientific analysis.

Hence, A spacecraft has captured and brought material to earth from a comet is True.

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It will takes approximately 0.165 seconds for the ball to reach the floor after it has been gently pushed off the table top from a height of 1.3 m above the floor.

When an object is dropped from a height, it falls to the ground due to the force of gravity.

When an object is released from a height of 1.3 m above the ground, the time it takes to reach the ground is calculated using the formula:

h = 0.5gt²  where h is the height of the object, g is the acceleration due to gravity and t is the time taken for the object to reach the ground.

Rearranging this formula to solve for t, we have: \(t = \sqrt{(2h/g)}\)

Substituting the values we have: \(h = 1.3 mg = 9.81 m/s^{2} t = \sqrt{(2 \times 1.3 / 9.81)t} = \sqrt{(0.265 / 9.81)t} = \sqrt{0.027t } = 0.165 seconds\)

Therefore, it takes approximately 0.165 seconds for the ball to reach the floor after it has been gently pushed off the table top from a height of 1.3 m above the floor.

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The amount of energy absorbed (eV) by a photon can be calculated using the formula: Energy (eV) = Planck's constant (eV s) × speed of light (m/s) / wavenumber (cm^-1).

Step 1:

To calculate the amount of energy absorbed (eV) by a photon given the wavenumber, you can use the formula: Energy (eV) = Planck's constant (eV s) multiplied by the speed of light (m/s) divided by the wavenumber (cm^-1).

Step 2:

When it comes to calculating the energy absorbed by a photon, the wavenumber is an essential parameter. The wavenumber represents the number of waves per unit distance and is usually measured in reciprocal centimeters (cm^-1). In order to determine the energy absorbed by a photon in electron volts (eV), you can utilize the following formula:

Energy (eV) = (Planck's constant × Speed of light) / Wavenumber

Planck's constant is denoted by the symbol "h" and has a value of approximately 4.1357 × 10^-15 eV s. The speed of light, represented by "c," is approximately 2.998 × 10^8 meters per second. By dividing the product of Planck's constant and the speed of light by the wavenumber, you can obtain the energy absorbed by the photon in electron volts.

In simpler terms, the formula states that the energy of a photon is directly proportional to its frequency. As the wavenumber increases, indicating a higher frequency, the energy absorbed by the photon also increases. Conversely, a decrease in wavenumber corresponds to a lower frequency and a decrease in the energy absorbed.

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With "toward the wall" designated as the positive direction, the average acceleration felt the ball in the 0.0158 s of contact with the wall is

\(a_{\rm ave} = \dfrac{-26.412\frac{\rm m}{\rm s} - 28.4\frac{\rm m}{\rm s}}{0.0158\,\mathrm s} ≈ \boxed{-3470 \dfrac{\rm m}{\mathrm s^2}}\)

There are two forces acting on the woman: the normal force of the floor of the elevator and the weight of the woman.

First, find the weight of the woman by multiplying its mass times the acceleration of gravity:

According to Newton's Second Law of Motion, the net force acting on an object relates to the acceleration of the object according to:

Since the normal force of the floor is exerted upwards and the weight is exerted downwards, then:

Isolate the acceleration from the equation:

Replace the values of the normal force (395N), the weight and the mass of the woman to find the acceleration of the elevator:

Then, the acceleration of the elevator is 2.9 m/s^2 downwards.

Use the definition of acceleration to find the final speed of the elevator 4 seconds after the initial speed of 1.50 m/s downwards:

Therefore, the answers are:

The acceleration of the elevator is 2.9 m/s^2 downwards.

The final speed of the elevator 4 seconds after it had a speed of 1.50 m/s downwards, is 13.3 m/s downwards.

The average power developed by the boy during the climb is approximately 29.4 W.

In physics, the amount of energy transferred or converted per unit time is called power.

total height = number of steps x height of each step

total height = 30 x 0.15 m = 4.5 m

Given, time = 60 s

As power = work done / time

work done = force x distance

force = mass x gravity

mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).

force = 40 kg x 9.81 m/s² = 392.4 N

The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m

work done = force x distance

work done = 392.4 N x 4.5 m = 1765.8 J

power = work done / time

power = 1765.8 J / 60 s

power ≈ 29.4 W

Therefore, the average power developed by the boy during the climb is approximately 29.4 W.

As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.

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