two asteroids head straight for earth from the same direction. their speeds relative to earth are 0.82c for asteroid 1 and 0.62c for asteroid 2

Answers

Answer 1

Asteroid 1 is traveling faster relative to Earth, with a speed of 0.82c, while Asteroid 2 is traveling at a speed of 0.62c.

In this scenario, the speeds of the two asteroids relative to Earth are given in terms of "c", which represents the speed of light. A higher value for "c" means a faster speed. Since 0.82c is greater than 0.62c, Asteroid 1 is moving faster toward Earth than Asteroid 2.

Comparing the speeds of the two asteroids, we can conclude that Asteroid 1 is traveling at a faster speed relative to Earth than Asteroid 2.

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Related Questions

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What happens when a wave enters a different material and slows down?
o
A. Refraction
o
B. Transmission
o
C. Reflection
D. AbsorptionWhat happens when a wave enters a different material and slows down?
o
A. Refraction
o
B. Transmission
o
C. Reflection
D. Absorption

Answers

Answer:

A

Explanation:

ap3x

Answer:

A. Refraction

Explanation:

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A boxer hits a punching bag and gives it a change in momentum of 12 kg•m/s
over 7.0 ms.

A boxer hits a punching bag and gives it a change in momentum of 12 kgm/sover 7.0 ms.

Answers

The magnitude of the net force on the punching bag is 1714N

What is momentum?momentum, product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle. See Newton's laws of motion.The change in momentum of an object is the product of mass and the change in velocityThe magnitude of the netforce can be calculated using 12kg/7.0msBut we can convert 7ms to "s" = 7× 10^-3sF= Force = 12/7×10^-3= 1714NHence, the magnitude of the net force on the punching bag is 1714N

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In a game of tug of war, Team A pulls with a force 850N, Team B pulls with force of 975N. Calculate the net force on the rope. Be sure to include which direction.

Answers

I’d need to know which direction team a is pulling in and which direction b is pulling in to determine which direction.

But the net force is 125N in B’s direction (since B’s force is stronger than A’s by 125N)

Why should anybody care about sexual harassment?

Answers

Answer:

Explanation:

People should care about sexual harassment for many reasons. such as, sexual harassment is a very serious and touchy topic. Sexual harassment should not be tolerated and can ruin many peoples mental health.

A sheep is walking at 1.6 m/s. How long will it take to go 3600 m?

Answers

Answer:

2,250 seconds or 37.5 minutes

Explanation:

This chart lists four examples of two objects that are in contact.

A 3-column table with 4 rows. The first column has entries Example 1, Example 2, Example 3, Example 4. The second column labeled Object 1 has entries fire, a metal at 80 degrees Celsius, the cool ocean, a tool with a lot of thermal energy. The third column labeled Object 2 has entries air, a metal at 12 degrees Celsius, the warm air, a material with little thermal energy.

Which statement accurately describes the flow of heat in each example?

Heat will flow from Object 1 to Object 2 in examples 2 and 4, and heat will flow from Object 2 to Object 1 in examples 1 and 3.
Heat will flow from Object 1 to Object 2 in examples 1 and 3, and heat will flow from Object 2 to Object 1 in examples 2 and 4.
Heat will flow from Object 1 to Object 2 in Example 3, and heat will flow from Object 2 to Object 1 in examples 1, 2, and 4.
Heat will flow from Object 1 to Object 2 in examples 1, 2, and 4, and heat will flow from Object 2 to Object 1 in Example 3.

Answers

Answer:

this is the answer........................

This chart lists four examples of two objects that are in contact.A 3-column table with 4 rows. The first

a speeding motorist traveling 120km/hr

Answers

This ain’t even a question so why did you do it

The light beam shown in the figure below makes an angle of? = 15.5° with the normal line NN' in the linseedoil. Determine the angles θ and θ'.(The refractive index for linseed oil is 1.48.)
θ = 1
°
θ' = 2
°

Answers

The angle θ is approximately 0.688°, and the angle θ' is approximately 1.988°.

To determine the angles θ and θ' in the given scenario, we can use Snell's Law, which relates the angles of incidence and refraction to the refractive indices of the media involved. Snell's Law can be stated as follows:

n₁ * sin(θ₁) = n₂ * sin(θ₂)

Where:

n₁ is the refractive index of the medium of incidence (in this case, air with a refractive index close to 1),

θ₁ is the angle of incidence,

n₂ is the refractive index of the medium of refraction (in this case, linseed oil with a refractive index of 1.48), and

θ₂ is the angle of refraction.

Let's solve for the unknown angles θ and θ' using the given information.

Given:

Angle of incidence θ = 1°

Refractive index of linseed oil n₂ = 1.48

We need to find the angle of refraction θ₂.

Using Snell's Law, we have:

n₁ * sin(θ₁) = n₂ * sin(θ₂)

Since the refractive index of air (n₁) is approximately 1, we can simplify the equation to:

sin(θ₁) = n₂ * sin(θ₂)

Plugging in the values:

sin(1°) = 1.48 * sin(θ₂)

We can now solve for θ₂:

θ₂ = arcsin(sin(1°) / 1.48)

Calculating this value, we find:

θ₂ ≈ 0.688°

Now, let's determine the angle θ'.

Given:

Angle of refraction θ₂ = 0.688°

Refractive index of linseed oil n₂ = 1.48

We need to find the angle of incidence θ'.

Using Snell's Law, we have:

n₂ * sin(θ₂) = n₁ * sin(θ')

Since the refractive index of air (n₁) is approximately 1, we can simplify the equation to:

n₂ * sin(θ₂) = sin(θ')

Plugging in the values:

1.48 * sin(0.688°) = sin(θ')

Solving for θ', we find:

θ' = arcsin(1.48 * sin(0.688°))

Calculating this value, we get:

θ' ≈ 1.988°

Therefore, the angle θ is approximately 0.688°, and the angle θ' is approximately 1.988°.

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The light beam shown in the figure below makes an angle of? = 15.5 with the normal line NN' in the linseedoil.

c. at what angle do the equipotentials intersect the edge of the conduction paper?

Answers

The equipotential lines intersect the edge of the conductive paper at a right angle because the electric field lines are perpendicular to the conductive surface, and the electric current flows in the direction of the electric field vector.

The equipotential lines in a conductive paper perpendicular to the edge of the paper will intersect the edge at a right angle, i.e., 90 degrees. This is because the electric field lines are always perpendicular to the conductive surface of the paper.

When the equipotential lines are perpendicular to the electric field lines, they must be parallel to the conductive surface. Therefore, when the equipotential lines reach the edge of the conductive paper, they intersect it perpendicularly.

This behavior can be explained by the fact that the electric current flows in the direction of the electric field vector. In a conductive paper, charges can move freely through the material. When an electric field is applied to the paper, the charges will move in response to the field. This movement of charges will generate an electric current, and the equipotential lines will be perpendicular to the direction of this current flow.

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What form does the signal take while it is broadcast from a transmitting station to your radio or television, regardless of whether it is a digital or analog wave? transverse longitudinal mechanical sound.

Answers

Answer:

transverse

Explanation:

Answer:

Transverse wave is the correct answer, the person above me is correct!

~Hope this helps! :)

Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.

Answers

No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.

This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.

i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.

ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.

The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.

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can anyone help me please​

Answers

Answer:

Gravity.

Rocket ships.

Ball.

Basketball.

Explanation:

Gravity has to do a lot with air. It puts the planets in there area.

Rocket Ship has to do a lot with air. If i'm right, they calculate the area, weather, about the air.

A ball gets throwed in the air, which gravity comes into place.

Basketball is also a similar example to a ball.

Lúc 6 giờ sáng một học sinh đi học từ nhà đến trường mất 10 phút quãng đường từ nhà đến trường là 6 km hỏi học sinh đi với vận tốc là bao nhiêu

Answers

Lúc 6 giờ sáng một học sinh đi học từ nhà đến trường mất 10 phút quãng đường từ nhà đến trường là 6 km hỏi học sinh đi với vận tốc là bao nhiêu

A student is recording how far an ant can crawl over time. He gets so interested in the project that he forgets to enter a few data
points. Based on the data in the table the values for the missing data points are MOST LIKELY
A)
9 minutes and 8 inches
B)
9 minutes and 9 inches
10 minutes and 9 inches
D)
10 minutes and 10 inch
Eliminate

Answers

Answer: 10 minutes and 9 inches

Explanation:

I got it right and they are counting by 2 and 3

The law of conservation of energy states that (1 point) Group of answer choices all energy in the universe comes from the sun and remains in the same form energy is neither created nor destroyed; it is transformed and transferred new energy within a system is converted or transferred and destroyed as it is used energy is created from the sun and is transformed from one type to another

Answers

The law of conservation of energy states that energy is neither created nor destroyed; it is transformed and transferred (option B).

What is the law of conservation of energy?

The law of conservation of energy is a principle stating that energy may not be created or destroyed but can only be transformed i.e. converted from one form to another.

This means that a system always has the same amount of energy, unless it's added from the outside.

The law states that the total energy of an isolated system remains constant; it is said to be conserved over time.

Therefore, according to this question, the law of conservation of energy is described correctly by option B.

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Sodium lamps give off light at
589 nm. When that light passes
through a diffraction grating with
d = 3.88 x 10-6 m, what is the angle of
its second order (m = 2) maximum?

Answers

Answer:

θ = 17.67°

Explanation:

The grating equation can be used here to find the angle. The grating equation is given as follows:

\(m\lambda = dSin\ \theta\)

where,

m = order = 2

d = 3.88 x 10⁻⁶ m

λ = wavelength of light = 589 nm = 5.89 x 10⁻⁷ m

θ = angle = ?

Therefore, using these values in the equation, we get:

\((2)(5.89\ x\ 10^{-7}\ m) = (3.88\ x\ 10^{-6}\ m)Sin\theta \\Sin\theta = \frac{(2)(5.89\ x\ 10^{-7}\ m)}{(3.88\ x\ 10^{-6}\ m)}\\\\\theta = Sin^{-1}(0.3036)\)

θ = 17.67°

Answer:17.67

Explanation:

What's the kinetic energy of the roller coaster at the top and bottom of the hill? Use KE
mu
A kiddie roller coaster car has a mass 100 kilograms. At the top of a hill, it's moving at a speed of 3 meters/second. After reaching the bottom
of the hill, its speed doubles. The car's kinetic energy at the bottom is
v its kinetic energy at the top. The car has
joules of kinetic energy at the bottom of the hill.
Reset
Next

Answers

The kinetic energy of the car is four times greater at the bottom than it is at the top. At the base of the hill, the car's kinetic energy is 1800 joules.

Describe kinetic energy.

The momentum an object has as a result of motion is known as kinetic energy. We must exert force on an object if we desire to accelerate it. To apply a force, we must exert effort. Once the work is finished, the objects will be moving because energy has now been transferred to it.

What elements influence the kinetic energy?

Describe that a travelling internal force and speed are major factors that impact the amount of kinetic energy it will possess. Partially particles can result in the loss of kinetic energy through frictional, sound, and heat.

k = 1 /2 mv²

K = 1 /2 (100 kg) (3 m/s)²

= 450 J

K = 1 /2 (100 kg) (6 m/s)²

k = 1800 J

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please make a research topics for under graduated about lora designs related to electrical engineering environmental

Answers

This research investigates the effectiveness of LoRa technology in environmental monitoring, aiming to develop efficient and scalable systems for sustainable data collection and analysis. Topics include performance evaluation, energy efficiency, IoT integration, network planning, security, challenging conditions analysis, wildlife monitoring, and GIS integration.

Research Topic: "Design and Optimization of LoRa-Based Environmental Monitoring Systems for Sustainable Development"

1. Investigating the Performance of LoRa Technology in Environmental Monitoring: This research aims to evaluate the effectiveness of LoRa (Long Range) technology in collecting and transmitting environmental data, such as air quality, temperature, humidity, and noise levels. The study can explore the range, power consumption, data rate, and reliability of LoRa-based sensors in different environmental conditions.

2. Energy-Efficient LoRa Network Design for Environmental Monitoring: This research focuses on developing energy-efficient LoRa network architectures and protocols for environmental monitoring applications. The study can involve designing low-power LoRa nodes, optimizing transmission schedules, and exploring energy harvesting techniques to prolong the lifetime of the monitoring system.

3. Integration of LoRa with IoT for Smart Environmental Monitoring: This research investigates the integration of LoRa with Internet of Things (IoT) platforms for comprehensive environmental monitoring. It can explore the design and implementation of a scalable and interoperable IoT architecture that combines LoRa-based sensor nodes, data aggregation, cloud computing, and data analytics for real-time environmental monitoring and decision-making.

4. LoRa Network Planning and Deployment for Large-scale Environmental Monitoring: This research focuses on the planning and deployment strategies for large-scale LoRa networks dedicated to environmental monitoring. The study can include optimizing the placement of LoRa gateways, designing efficient routing algorithms, and addressing scalability and coverage challenges to ensure reliable data collection across vast geographical areas.

5. Security and Privacy Considerations in LoRa-based Environmental Monitoring Systems: This research addresses the security and privacy challenges associated with LoRa-based environmental monitoring systems. It can involve investigating encryption techniques, authentication protocols, and data anonymization methods to protect sensitive environmental data from unauthorized access and ensure compliance with privacy regulations.

6. Performance Analysis of LoRa-based Sensor Networks in Challenging Environmental Conditions: This research focuses on analyzing the performance of LoRa-based sensor networks in challenging environmental conditions such as urban environments, remote areas, or harsh climatic conditions. The study can involve evaluating signal propagation, interference effects, and data reliability to understand the limitations and potential enhancements of LoRa technology in such scenarios.

7. LoRa-Based Wildlife Monitoring Systems for Biodiversity Conservation: This research explores the design and implementation of LoRa-based monitoring systems for wildlife tracking and conservation. It can involve developing specialized LoRa sensors and network architectures to collect and transmit data on animal behavior, migration patterns, and habitat conditions, contributing to biodiversity conservation efforts.

8. Integration of LoRa with Geographic Information Systems (GIS) for Environmental Monitoring: This research investigates the integration of LoRa technology with Geographic Information Systems (GIS) for spatial analysis and visualization of environmental data. The study can focus on developing methods to efficiently collect and integrate LoRa-based sensor data with GIS databases, enabling better understanding and management of environmental resources.

Remember to further refine and narrow down the selected research topic based on your specific interests, available resources, and guidance from your academic advisor.

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Describe the main differences in how stars of 20, 1, and 0.2
solar masses evolve.

Answers

Stars of different masses undergo different evolutionary paths. The main differences in the evolution of stars with masses of 20, 1, and 0.2 solar masses lie in their lifetimes, nuclear fusion processes, and ultimate fates.

Stars with a mass of 20 solar masses are considered massive stars. They have shorter lifetimes compared to smaller stars due to their higher luminosities and greater fuel consumption. Massive stars undergo nuclear fusion at a faster rate, leading to more rapid consumption of their hydrogen fuel. They evolve through various stages, including the main sequence, red giant phase, and eventually, they end their lives in a supernova explosion. After the explosion, they can leave behind remnants such as neutron stars or black holes.

Stars with a mass of 1 solar mass, similar to our Sun, have longer lifetimes compared to massive stars. They spend the majority of their lives on the main sequence, where hydrogen is fused into helium in their cores. As they exhaust their hydrogen fuel, they expand into red giants, during which they fuse helium in their cores. Eventually, these stars shed their outer layers and form planetary nebulae, leaving behind a dense core known as a white dwarf. White dwarfs gradually cool and fade over billions of years.

Stars with a mass of 0.2 solar masses, also known as low-mass stars, have the longest lifetimes of all. They follow a similar path to solar-mass stars but at a slower pace. They spend a longer time on the main sequence, undergo less intense nuclear fusion, and evolve into red giants. As they near the end of their lives, low-mass stars shed their outer layers, forming planetary nebulae. The remaining core, composed of a hot, dense stellar remnant called a white dwarf, continues to cool and eventually becomes a cold, dark object known as a black dwarf.

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A wind turbine with a blade diameter of 25 m is to be installed in a location where average wind velocity is 6 m/s. If the overall efficiency of the turbine is 34 percent, determine (a) the average electric power output, (b) the amount of electricity produced from this turbine for an annual operating hours of 8000 h, and (c) the revenue generated if the electricity is sold at a price of $0.09/kWh.Take the density of air to be 1.3 kg/m'.

Answers

The wind turbine with a blade diameter of 25 m and an average wind velocity of 6 m/s has an average electric power output of 172.34 kW. For an annual operating time of 8000 hours, the turbine will produce approximately 1,378,720 kWh of electricity.

If sold at a price of $0.09/kWh, the revenue generated from the electricity produced by the turbine would be approximately $124,086.72. To calculate the average electric power output, we can use the formula:

\(\[P = \frac{1}{2} \times \text{{density of air}} \times A \times v^3 \times \text{{efficiency}}\]\)

Substituting the given values into the formula, we can calculate the average electric power output:

\(\[P = \frac{1}{2} \times 1.3 \, \text{{kg/m}}^3 \times \left(\frac{\pi}{4} \times (25 \, \text{{m}})^2\right) \times (6 \, \text{{m/s}})^3 \times 0.34 \approx 172340 \, \text{{watts}} \approx 172.34 \, \text{{kW}}\]\)

To determine the amount of electricity produced for an annual operating time of 8000 hours, we multiply the average electric power output by the operating time:

\(\[\text{{Electricity produced}} = P \times \text{{operating time}} = 172.34 \, \text{{kW}} \times 8000 \, \text{{h}} = 1,378,720 \, \text{{kWh}}\]\)

Finally, to calculate the revenue generated, we multiply the electricity produced by the selling price per kilowatt-hour:

\(\[\text{{Revenue}} = \text{{Electricity produced}} \times \text{{price per kWh}} = 1,378,720 \, \text{{kWh}} \times \$0.09/\text{{kWh}} \approx \$124,086.72\]\)

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which of the following is a correct statement of the ohm's law? responses a. the resistance of a conductor is always constant. a. the resistance of a conductor is always constant. b. the current in a conductor is always proportional to the potential difference across the conductor. b. the current in a conductor is always proportional to the potential difference across the conductor. c. the resistance of a conductor increases with increasing temperature. c. the resistance of a conductor increases with increasing temperature. d. the resistance of a conductor is constant only if the temperature of the conductor is constant.

Answers

Correct statement of the ohm's law is  the current in a conductor is always proportional to the potential difference across the conductor.

What is Ohm's law's resistance?According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them. As a result, V = RI, where R is the resistance constant. R is influenced by the conductor's material, size, and other factors. Ohm () is its SI unit.In accordance with Ohm's law, as the current increases, the voltage will follow suit. So, the appropriate choice is As resistance rises, current rises. Ohm's Law Declaration: According to Ohm's law, when all other physical parameters, including temperature, are held constant, the voltage across a conductor is directly proportional to the current flowing through it.

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Covalent bonding occurs when:
A. two atoms share electrons in their outer valence shells.
B. positive metallic ions are bonded with delocalized free electrons.
C. the negative side of one molecule bonds with the positive side of
a neighboring molecule.
O D. a negative ion is drawn to a positive ion through electrostatic
attraction.

Answers

Answer:

I guess A option is correct

Due to the distance and vulnerability in supply chains and procurement systems, in order to determine the cost effectiveness of local sourcing, a practical step to do this could be a. Utilize a single

Answers

Employing a single cost comparison model provides a practical approach to evaluating the cost effectiveness of local sourcing in the context of distance and vulnerability in supply chains and procurement systems.

A practical step to determine the cost effectiveness of local sourcing in the given scenario would be to utilize a single cost comparison model.

This model would involve comparing the costs associated with local sourcing against those of distant sourcing, taking into account factors such as transportation costs, lead times, inventory holding costs, quality control measures, and any other relevant expenses.

The cost comparison model would involve gathering data on the various cost components associated with both local and distant sourcing options.

This would include collecting information on the prices of raw materials, transportation costs, import/export duties, storage costs, and any other relevant expenses.

The model would then calculate the total cost for each sourcing option and compare them to determine which one is more cost-effective.

By utilizing a single cost comparison model, organizations can systematically assess the financial implications of local sourcing.

This step allows for an objective evaluation of the costs involved and enables decision-makers to make informed choices based on a comprehensive understanding of the economic factors at play.

Additionally, it helps identify potential cost savings and highlights any potential risks or challenges associated with local sourcing.

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A laser pulse of duration 25 ms has a total energy of 1.4 J. The wavelength of this radiation is
567 nm. How many photons are emitted in one pulse? Let 1 eV = 1.60 x 10-19 J, the mass of
an electron m=9.11 10-31
kg, the speed of light c= 3.00 x 108 m/s, and Planck's constant h
= 4.136 10-15 eV .s.

Answers

Answer:

n = 4 x 10¹⁸ photons

Explanation:

First, we will calculate the energy of one photon in the radiation:

\(E = \frac{hc}{\lambda}\\\\\)

where,

E = Energy of one photon = ?

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m

Therefore,

\(E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}\)

E = 3.505 x 10⁻¹⁹ J

Now, the number of photons to make up the total energy can be calculated as follows:

\(Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\\)

n = 4 x 10¹⁸ photons

I need help ASAP dlelsl

I need help ASAP dlelsl

Answers

Answer:

1) Streak Plate

2) State of Matter

3) Physical Properties

4) Displacement

5) Dull..

so easyyy

A cart of mass m is moving with negligible friction along a track with known speed y, to the right. It


collides with and sticks to a cart of mass 4m moving with known speed y, to the right. Which of the two


principles, conservation of momentum and conservation of mechanical energy, must be applied to determine


the final speed of the carts, and why?

Answers

The principle of conservation of momentum must be applied to determine the final speed of the carts. Conservation of momentum states that the total momentum of a system remains constant if no external forces act on it.

In this scenario, the collision between the two carts is an isolated system, meaning no external forces are involved. Therefore, the initial momentum of the system before the collision should be equal to the final momentum after the collision. Since the carts stick together after the collision, they move as a single combined mass. The initial momentum of the system is given by the sum of the individual momenta of the two carts. After the collision, the combined mass moves with a final velocity, which is the same for both carts since they are now connected.

On the other hand, the principle of conservation of mechanical energy cannot be directly applied in this scenario. Conservation of mechanical energy states that the total mechanical energy of a system remains constant if no external non-conservative forces (such as friction or air resistance) act on it. However, in this case, the collision is not perfectly elastic, and there is a change in the mechanical energy due to the deformation of the carts and the conversion of kinetic energy into other forms of energy, such as heat or sound. Therefore, conservation of mechanical energy cannot be used to determine the final speed of the carts.

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Runner A is initially 5.0 mi west of a flagpole and is running with a constant velocity of 5.0 mi/h due east. Runner B is initially 2.0 mi east of the flagpole and is running with a constant velocity of 4.0 mi/h due west. How far are the runners from the flagpole when they meet?_________ mi

Answers

1.11 miles

Explanation

Step 1

Diagram

so

a)let

for runner A

\(\begin{gathered} distance\text{ traveled by runner A=}x \\ velocity_A=5\frac{mi}{h} \\ time\text{ taken=t}_1 \end{gathered}\)

for runner B

\(\begin{gathered} distance\text{ = y} \\ velocity_B=4\text{ }\frac{mi}{h} \\ time_2=time_1=(\text{ the same time taken when they meet\rparen} \end{gathered}\)

also we know that

\(x+y=7\text{ }\Rightarrow equation\text{ \lparen1\rparen}\)

b) to set the equation, we need to apply the formula

\(time=\text{ }\frac{distance\text{ }}{speed}\)

so

\(\begin{gathered} time_1=time_2 \\ replace \\ \frac{x}{5\frac{m}{s}}=\frac{y}{4\frac{m}{s}} \\ \frac{x}{5}=\frac{y}{4} \\ cross\text{ multiply} \\ 4x=5y \\ divide\text{ both sides by 4} \\ \frac{4x}{4}=\frac{5y}{4} \\ x=\frac{5}{4}y\Rightarrow equation\text{ \lparen2\rparen} \end{gathered}\)

Step 2

solve the equations

\(\begin{gathered} x+y=7\operatorname{\Rightarrow}equat\imaginaryI on\operatorname{\lparen}\text{1}\operatorname{\rparen} \\ x=\frac{5}{4}y\operatorname{\Rightarrow}equat\imaginaryI on\operatorname{\lparen}\text{2}\operatorname{\rparen} \end{gathered}\)

replace the x value from equation (2) into equation(1) and solve for y

\(\begin{gathered} x+y=7\operatorname{\Rightarrow}eq(1) \\ \frac{5}{4}y+y=7 \\ \frac{9}{4}y=7 \\ Multiply\text{ both sides by 4/9} \\ \frac{9}{4}y*\frac{4}{9}=7*\frac{4}{9} \\ y=\frac{28}{9}=3.11 \end{gathered}\)

finally, replace in eq ( 1) to find the x value

\(\begin{gathered} x+y=7\operatorname{\Rightarrow} \\ x+3.11=7 \\ subtract\text{ 3.11 in both sides} \\ x+3.11-3.11=7-3.11 \\ x=3.89 \end{gathered}\)

so, they are

so,they are

1.11 miles far away from the flagpole

Runner A is initially 5.0 mi west of a flagpole and is running with a constant velocity of 5.0 mi/h due
Runner A is initially 5.0 mi west of a flagpole and is running with a constant velocity of 5.0 mi/h due

what is the SI unit of charge and how is this related to the fundamental unit of charge? How is this different for an electron and a proton

Answers

The SI unit of charge is the coulomb (C). It is related to the fundamental unit of charge, which is the charge of an electron or proton. The magnitude of the charge of an electron is equal to -1.602 x 10^-19 C, while the magnitude of the charge of a proton is equal to +1.602 x 10^-19 C.

This means that an electron has a negative charge and a proton has a positive charge. The charge of an object is determined by the number of electrons and protons it has. If an object has an equal number of electrons and protons, it is said to be neutral and has a charge of zero.

The charge of an object can be measured using an instrument called an electrometer. Conductors, such as metals, have a high degree of conductivity and can easily transfer charge. In contrast, insulators have a low degree of conductivity and do not easily transfer charge.

The SI unit of conductance is the siemens (S), which is the reciprocal of resistance (ohms). The conductance of a material is determined by its ability to allow the flow of electric current. The concentration of charged particles in a material can affect its conductivity. For example, increasing the concentration of ions in an electrolyte solution can increase its conductivity.

What happens to the magnet on top of another magnet?

Answers

Similar like magnets, opposites are drawn together. A magnet's north pole will adhere to another magnet's south pole. However, a magnet's north pole will push away from another magnet's north pole.

The basic adage "opposites attract" applies to magnets. Every magnet has a north and a south pole. The drawing together of two poles that are incompatible with one another. If you attempt to align the north and south poles in these directions, they will reject one another.The magnets are surrounded by an invisible magnetic field that is filled with potential energy. When two poles with similar sides are attempted to be pushed together, the built-up energy transforms into motion, or kinetic energy, and pushes the poles apart.

When two diametrically opposed poles combine, the same logic applies. The magnets are compelled to come together because of the intense attraction.

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A ball of mass is attached to a string of length R and negligible mass. The ball moves clockwise in a vertical circle, as shown. When the ball is at point P, the string is horizontal. Point Q is at the bottom of the circle and point Z is at the top.
a) Draw and label all forces on the ball at points P and Q.
b) Derive an expression for , the minimum speed the ball can have at point Z without leaving the circular path.
c) The maximum tension the string can have without breaking is . Derive an expression for , the maximum speed the ball can have at point Q without breaking the string. Answer in terms of M, R, T, and fundamental constants.
d) Suppose that the string breaks when the ball is at point P. Describe the ball’s velocity and acceleration after the string breaks.

Answers

A string of negligible mass and length R is connected to a ball with mass M. The ball moves in a straight circle as depicted, clockwise. the time the ball.

What in physics is negligible?

Negligible refers to something that can be disregarded. Sometimes even in physics, this force is so little that its impact on the overall phenomenon is negligible. For instance, whenever we throw an apple aloft, the apple pulls the earth toward it, but the earth stays put because the force the apple exerts is so little.

Do electrons possess a minuscule mass?

In comparison to protons and neutrons, electrons have a minuscule mass of 9.10938356 1031 kg. A proton's mass is (1.67262191027kg), which is around 1837 times greater than the mass of an electron. the weight of an.

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A string of negligible mass and length R is connected to a ball with mass M. The ball moves in a straight circle as depicted, clockwise. the time the ball.

What in physics is negligible?

Negligible refers to something that can be disregarded. Sometimes even in physics, this force is so little that its impact on the overall phenomenon is negligible. For instance, whenever we throw an apple aloft, the apple pulls the earth toward it, but the earth stays put because the force the apple exerts is so little.

Do electrons possess a minuscule mass?

In comparison to protons and neutrons, electrons have a minuscule mass of 9.10938356 1031 kg. A proton's mass is (1.67262191027kg), which is around 1837 times greater than the mass of an electron. the weight of an.

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