Transfer Functions of Electrical Systems (Special assignmen 3) There are 4 possible types of transfer functions for electrical systems. 1) Voltage Gain H_V(s) Vi(s) Electrical System V.(s) 2) Transfer Admittance H_Y(s) Vi(s) + +1 Electrical System I.(s) 3) Current Gain H_I(s) L(S) (1) 4) Transfer Impedance H_Z(s) L(S) (1) Electrical System Electrical System V.(s) I.(s) R = 12.50, L= 4H, C = 0.01F R + Vi(t) L CT Vo(t) 1) Find Vc(s)/Vs(s). 2) Show the pole-zero map. 3) Find the response to Vs(t) = u(t)V. 4) Find the response to Vs(t) = o(t)V.

Answer:

The new charge is +2

Explanation:

Sodium atom has 11 electrons (2, 8, 1)

sodium ion is cation and it will have 10 electrons after losing 1 electron (Na⁺), the charge is +1 because it needs to lose 1 electron to attain octet structure and become stable.

When this sodium ion loses 1 more electron, the new charge will be Na²⁺.

Thus, the new charge will be  +2

Answer:

speed/time

Explanation:

Answer:

a= (Vf - Vi)

         t

To find acceleration (a) you need to subtract the finale velocity (Vf) minus the initial velocity (vi) divided by time (t) as shown in the equation above.

Science is a systematic enterprise that builds and organizes knowledge in the form of testable explanations and predictions about the universe. The earliest roots of science can be traced to Ancient Egypt and Mesopotamia in around 3000 to 1200 BCE.

Answer:

correct

Explanation:

mark me brainlist

Answer:

a c d

Explanation:

yeet

Answer:

a c d

Explanation:

Gauss' law relates the electric field at points on a Gaussian surface to the charge enclosed by that surface. It provides a useful tool for analyzing electric fields and understanding their relationship with charge distributions.

Gauss' law relates the electric field at points on a Gaussian surface to the charge enclosed by that surface. In other words, it connects the distribution of electric charges to the resulting electric field.
When we apply Gauss' law, we consider a closed surface known as a Gaussian surface. This surface can be any shape, but it must enclose the charge or charges we are interested in studying. By using a Gaussian surface, we simplify the calculations involved in determining the electric field.
The law states that the total electric flux through a closed Gaussian surface is equal to the net charge enclosed by that surface divided by the electric constant, also known as the permittivity of free space (ε₀). Mathematically, it can be represented as:
Φ = Q_enclosed / ε₀
Here, Φ represents the electric flux, Q_enclosed is the net charge enclosed by the Gaussian surface, and ε₀ is a constant value.
To find the electric field at a point on the Gaussian surface, we can use Gauss' law by considering the symmetry of the charge distribution. This allows us to simplify the calculation of the electric field, making use of the properties of the Gaussian surface. By determining the electric flux through the Gaussian surface and knowing the charge enclosed, we can then find the electric field at the point of interest.

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Answer:

C

Explanation:

(C) If the distance increases by some factor, the force will increase by the square of that factor.

Answer:

Explanation:

HELP ME WRITE A ONE PAGE ESSAY TO EXPLAIN THE AUTHOR'S PURPOSE IN WRITING HOM SMART ARE ANIMAL

Answer:

Explanation:

In mechanical engineering, a parallel force system is a situation in which two forces of equal magnitude act in the same direction within the same plane, with the counter force in the middle. An example of this is a see saw.

Forces which are parallel and acting a similar way are called like parallel forces. Like Parallel forces are the forces that are parallel to each other and have the same direction. Unlike parallel forces are the forces that parallel yet have directions inverse to each other.

when the parallel force system is a situation in which two forces of equal magnitude act in the same direction within the same plane, Two forces that are parallel can either be in the same direction or in opposite directions.

(hope this helps can i plz have brainlist :D hehe)

Answer:

I need your answer choices to answer this man, you didn't give any.

Explanation:

A table salt crystal with an interionic spacing of 0.280 nm diffracts a beam of neutrons with a de broglie wavelength of 0.250 nm. The speed of the neutrons is approximately 0.15975 km/s.

To find the speed of the neutrons, we can use the de Broglie wavelength equation: λ = h / p

where λ is the wavelength, h is the Planck's constant (approximately 6.626 x \(10^{(-34) J·s)}\), and p is the momentum of the particle.

In this case, we are given the de Broglie wavelength (λ) as 0.250 nm. We need to convert it to meters for the equation to be consistent:

λ = 0.250 nm = 0.250 x\(10^{-9}\) m

Now, we can rearrange the equation to solve for the momentum:

p = h / λ

Substituting the values, we have:

p = (6.626 x\(10^{-34}\) J·s) / (0.250 x\(10^{-9}\)  m)

p = 2.6504 x  \(10^{-25}\)kg·m/s

The momentum (p) of a particle is given by the product of its mass (m) and velocity (v):

p = m × v

Rearranging the equation to solve for velocity:

v = p / m

Since neutrons are neutral particles, we can assume their mass (m) to be approximately 1 atomic mass unit (u) which is equivalent to 1.66 x \(10^{-27}\)) kg)

v = (2.6504 x \(10^{-25}\)kg·m/s / (1.66 x \(10^{-27}\)) kg)

v = 159.75 m/s

To express the speed in kilometers per second, we can convert the units:

v = 159.75 m/s × (1 km / 1000 m) × (1 s / 1000 ms)

v = 0.15975 km/s

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The speed of light is given to be c = 3.0 × 10 8m/s. The time taken by the rocket to acquire a speed of 0.19c, which travels at 3.0×108m/s, can be determined by using the formula t = (v - u) / a where v is the final velocity, u is the initial velocity,

t is the time taken and a is the acceleration.  Therefore, using the formula v = u + at to find the time we get:t = (v - u) / a t = (0.19c - 0) / 9.8m/s 2= (0.19 × 3.0 × 108 m/s) / 9.8m/s 2 = 57.14 × 106s ≈ 57.1 daysTherefore, it will take approximately 57.1 days for the rocket to acquire a speed of 0.19 times that of light.(b) To find the distance travelled by the rocket, we can use the formula s = ut + 1/2 at 2

where s is the distance, u is the initial velocity, t is the time taken, and a is the acceleration.  We can also use v 2 = u 2 + 2as to find the distance. s = ut + 1/2 at 2 s = 0 × (57.14 × 106s) + 1/2 (9.8m/s 2) (57.14 × 106s) 2= 1.74 × 1015m ≈ 1.74 light yearsTherefore, the rocket will travel approximately 1.74 light years to acquire a speed of 0.19 times that of light.Explanation:The main answer is given above which explains how to find the time taken and the distance travelled by the rocket to acquire a speed of 0.19 times that of light.

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true

Explanation:

this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons

A pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. The ratio of their kinetic energies (truck to car) is 0.485

The formulas for the momentum and the kinetic energy are:

p = m . v

Ek = 1/2 . mv²

Where:

p = momentum

m = mass

Ek = kinetic energy

v = speed or velocity

Ek = 1/2 . mv² = 1/2 . mv . v

                      = 1/2 . p . v

Since p or momentum of both vehicles are the same, hence, the ratio of their kinetic energies is

Ek_truck : Ek_car = v_truck : v_car

In the given problem:

m_truck = 2268 kg

m_car = 1100 kg

Both have the same momentum, hence,

m_truck x v_truck = m_car x v_car

v_truck / v_car = m_car / m_truck

                         = 1100 / 2268 = 0.485

Therefore,

Ek_truck / Ek_car = v_truck / v_car = 0.485

Your question is incomplete, but most probably your question was:

A pickup truck (2268 kg) and a compact car (1100 kg) have the same momentum. If the same horizontal net force were exerted on both vehicles, pushing them from rest over the same distance, what is the ratio of their final kinetic energies? (ratio: truck to car)

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Orange, Blue, and Red are the three filters. They are easy to attach and cover the lens and flash on the front of the Polaroid Go camera.

The primary benefit of Polaroid photography is the immediate visual feedback. Sharing Polaroid photos is one of the simplest things you can do with them.

An image of a friend is taken and given to the friend. Being one-to-one rather than one-to-the-world makes it a little different from other forms of sharing. Polaroid started to lose some of its major clients in the real estate, insurance, and photo identi-fication industries as digital cameras proliferated on the market.

As film sales collapsed, Polaroid declared bankruptcy in October 2001. A series of chemicals and dyes are sandwiched between layers to make up a Polaroid;

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Answer:

The initial current is just V / R    because the capacitor will generate not back EMF

Q = V C   for a capacitor - since there is no charge initially on the capacitor the voltage across the capacitor will be zero

Given data:

* The mass of the shuttle is,

* The acceleration of the shuttle is,

Solution:

According to newton's second law, the lifting force of the shuttle is,

Hence, the lifting force of the shuttle is 6000 kN.

It takes the Boeing 777 approximately 35.4 seconds to lift off and become airborne.

To solve this problem, we can use the equation of motion:
d = v_initial * t + 0.5 * a * t^2
Where d is the distance (1600 m), v_initial is the initial velocity (7.5 m/s), a is the acceleration (1.6 m/s^2), and t is the time we want to find.

We can rearrange the equation to solve for t:
t = (-v_initial + sqrt(v_initial^2 + 2 * a * d)) / a
Plugging in the values:
t = (-7.5 + sqrt(7.5^2 + 2 * 1.6 * 1600)) / 1.6 ≈ 35.4 seconds

Summary: With a constant acceleration of 1.6 m/s^2 and an initial velocity of 7.5 m/s, the Boeing 777 takes about 35.4 seconds to travel 1600 meters down the runway and become airborne.

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Contact forces is the answer

Based on Newton's laws of motion, we can make some general observations about the motion of the object and the forces acting on it.

Newton's first law states that an object at rest will remain at rest and an object in motion will remain in motion at a constant velocity unless acted upon by an external net force.

In other words, if the net force acting on an object is zero, its motion will be uniform and unchanging.

Newton's second law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

In other words, the greater the net force acting on an object, the greater its acceleration will be, and the greater its mass, the smaller its acceleration will be for the same net force.

From the motion diagram at point C, we can observe that the object is moving to the right with a constant velocity, as indicated by the equally spaced dots and arrows.

Therefore, the net force acting on the object must be zero, according to Newton's first law.

Based on this information, we can eliminate any situations that involve a non-zero net force acting on the object.

This includes situations where the object is accelerating or experiencing a net force in a different direction than its motion, such as situations involving FG or CF.

Therefore, the situation that corresponds to the motion shown in the motion diagram at point C must involve a zero net force acting on the object and motion in the same direction as the net force.

Additional information or context may be needed to identify which situation corresponds to this motion.

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While spending the day relaxing on the beach, Keisha notices that the Sun appears to move across the sky. The best explanation for this is the Earth's rotation on its axis.

So basically, the earth keeps on rotating about its axis constantly. The change from day to night is due to the phenomenon of Earth's rotation on its axis only. The sun remains fixed, but the earth rotates. So for a person on earth, it seems like the sun rises and moves across the sky and then sets, but in reality, it is the earth that rotates on its axis.

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The applied force for the engine will be 24,450 N.

The applied force produced by the engine for a car weighing 12,500 n starting from rest and accelerating to 83.0 km/h in 5.00 s with a friction force of 1350 n is:

Applied force = (Mass x Acceleration) - Friction force

Applied force = (12,500 N x (83.0 km/h / 5.00 s)) - 1350 N

Applied force = 25,800 - 1350 N

Applied force = 24,450 N

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Answer:

232 N

Explanation:

By Hooke's law, the force applied to a spring is proportional to the stretch of the spring, so

F = kx

Where F is the force, k is the spring constant and x is how much it is stretched.

So, replacing k by 58N/cm and x by 4 cm, we get

F = (58 N/cm)(4 cm)

F = 232 N

Therefore, the force applied is 232 N

Answer:

the answer is false

Explanation:

A wave travels at a constant velocity through a given material.

Answer:

The period (T) of a satellite in a circular orbit can be determined using the formula:

T = 2πr/v

where r is the radius of the orbit and v is the speed of the satellite.

We can rearrange this formula to solve for v:

v = 2πr/T

Substituting the given values, we get:

v = 2π(3.5 × 10^7 m)/(6.3 h × 3600 s/h) ≈ 5,099 m/s

The centripetal force (F) that keeps the satellite in orbit is given by:

F = mv^2/r

where m is the mass of the satellite.

The gravitational force (Fg) between the satellite and Roton is given by:

Fg = GmM/R^2

where G is the gravitational constant, M is the mass of Roton, and R is the radius of Roton.

Since the satellite is in a circular orbit, the centripetal force is equal to the gravitational force:

mv^2/r = GmM/R^2

Simplifying and solving for M, we get:

M = v^2r/GR^2

Substituting the given values, we get:

M = (5,099 m/s)^2 × 3.5 × 10^7 m/(6.674 × 10^-11 m^3/kg s^2) × (1.75 × 10^7 m)^2 ≈ 8.35 × 10^23 kg

The free-fall acceleration (g) on the surface of Roton is given by:

g = GM/R^2

Substituting the calculated value of M and the given value of R, we get:

g = (6.674 × 10^-11 m^3/kg s^2) × (8.35 × 10^23 kg)/(1.75 × 10^7 m)^2 ≈ 8.73 m/s^2

Therefore, the magnitude of the free-fall acceleration on the surface of Roton is approximately 8.73 m/s^2

Explanation:

Acceleration is the rate of change in the speed of an object. If initial and final speed are v₁ and v₂. It changes speed in time t. Its formula is given by :

\(a=\dfrac{v_2-v_1}{t}\)

The problem is "A skater increases her velocity from 2.0 m/s to 10.0 m/s in 3.0 seconds. What is the skater’s acceleration? "

In this problem,

v₁ = 2 , v₂ = 10 m/s and t = 3 s

Acceleration of the object,

\(a=\dfrac{10-2}{3}\\\\a=2.67\ m/s^2\)

So, the acceleration of the skater is \(2.67\ m/s^2\).