The three notches in the graph occur where the driver changed gears. Describe the changes in velocity and acceleration of the car while in first gear. Is the acceleration just before a gear change larger or smaller than the acceleration just after the change?
Explain your answer

Answers

Answer 1
Answer : A ) The larger gear can be moved by applying a relatively small force on the smaller gear.

B ) The force applied on the smaller gear is transmitted without any loss to the larger gear .C ) the direction of motion can be changed without changing the direction of the applied force .

D ) the system would continue to move without any further, after and initial force has set in motion.


Related Questions

What is the formula to calculate moisture content?

Answers

Calculation of moisture content. Calculate the moisture content on a wet-weight basis using the following formula: Moisture content (%) = W2 - W3 x 100 W2-W1. where, W1 = weight of container with lid; W2 = weight of container with lid and sample before drying; and W3 = weight of container with lid and sample after drying.

___is the process that exchanges gases between body and the outside air.

Answers

Answer:

Breathing.

Explanation:

Breathing is the process that exchanges gases between body and the outside air.

cerebrum what is the meaning

Answers

Answer:

Plural cerebrums cerebra The largest part of the vertebrate brain, filling most of the skull and consisting of two cerebral hemispheres divided by a deep groove and joined by the corpus callosum, a transverse band of nerve fibers. The cerebrum processes complex sensory information and controls voluntary muscle activity.

Explanation:

The cerebrum is the uppermost part of the brain. It contains two hemispheres split by a central fissure. The cerebrum itself contains the major lobes of the brain and is responsible for receiving and giving meaning to information from the sense organs, as well as controlling the body.

three equal point charges of 1.2 nc are placed at the corners of an equilateral triangle whose sides are 0.500 m long. a. what is the potential energy of the system? (take as zero the potential energy of the three charges when they are infinitely far apart.) b. what is the electric potential at the the center of the triangle?

Answers

The potential energy of the system is -1.44 × 10^-19 J. The electric potential at the center of the triangle is zero.

a. To calculate the potential energy of the system, we need to find the force between the three charges and then multiply it by the distance. Using Coulomb's Law, the force between two charges can be calculated as F = k * q1 * q2 / r^2, where k is the Coulomb constant, q1 and q2 are the charges and r is the distance between them.

In this case, the charges are equal and the distance between them is 0.500 m, so the force between two charges can be calculated as

F = 8.99 * 10^9 * 1.2 * 10^-9 * 1.2 * 10^-9 / (0.500 * 10^-3)^2 = 2.64 * 10^-9 N.

The potential energy can be calculated as U = -F * d = -2.64 * 10^-9 * 0.500 * 10^-3 = -1.44 * 10^-19 J.

b. To calculate the electric potential at the center of the triangle, we need to find the electric field at that point. The electric field is given by E = F / q, where F is the force and q is the charge.

In this case, the charge is 1.2 * 10^-9 C, so the electric field can be calculated as

E = 2.64 * 10^-9 / 1.2 * 10^-9 = 2.2 * 10^9 N/C.

Since the electric potential is given by V = E * d, we can calculate the electric potential at the center of the triangle as

V = 2.2 * 10^9 * 0.25 * 10^-3 = 0.55 V.

However, the potential energy of the system was taken as zero when the charges were infinitely far apart, so the electric potential at the center of the triangle is actually zero.

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if we compare light photons and energetic electrons which have constant velocity independent of energy

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Light photons always travel at a constant speed (the speed of light) regardless of their energy, while the velocity of electrons is not constant and can vary with their energy.

Light photons and energetic electrons do not have constant velocities independent of energy. Light photons, which are particles of electromagnetic radiation, travel at a constant speed in a vacuum, which is approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum, denoted as the speed of light (c). This speed is a fundamental constant of nature and remains constant regardless of the energy of the photons. In other words, all photons, regardless of their energy, travel at the same speed in a vacuum.

On the other hand, energetic electrons do not have a constant velocity independent of their energy. According to classical physics, the velocity of an electron can vary depending on its energy. In classical mechanics, the kinetic energy of an object is related to its velocity. However, in the microscopic world of quantum mechanics, the behavior of particles such as electrons is described differently.

In quantum mechanics, the concept of particle velocity becomes less straightforward. Instead of velocity, quantum particles are described by wavefunctions, which represent the probability distribution of finding the particle at a certain location. The wavefunction of an electron evolves over time according to the Schrödinger equation, and it does not directly correspond to a well-defined classical velocity.

However, in certain situations, such as in electron beams or particle accelerators, electrons can be accelerated to high energies. In these cases, the energy of the electrons is related to their speed, but it is not a constant relationship. As the energy of the electrons increases, their speed can also increase, but it is not independent of their energy.

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What is the mass of a crate if a net force of 12 N gives the crate an acceleration of 0.20 m/s2?

Answers

A :-) for this question , we should apply
F = ma
Given - F = 12 N
a = 0.20 m/s^2
Solution -
F = ma
12 = m x 0.20
m = 12 by 0.20
m = 60 kg

.:. The mass is 60 kg.

does earths surface heat up the same everywhere

Answers

the correct answer is no ;)

Answer:

                                                                  .                                            .                                  

Explanation                            

                                                                .                                                            .                                    

                                .                              

2.
A truck begins with a velocity of 20. meters per second
east and changes its velocity to 5.0 meters per second
east in 10.0 seconds.
Determine the truck's rate of acceleration.

Answers

Explanation:

V=u+at

a=v-u) /t

A=5-20)10

a=15/10

a=1.5ms^2

If a truck begins with a velocity of 20. meters per second east and changes its velocity to 5.0 meters per second east in 10.0 seconds, then the truck's rate of acceleration would be  1.5 meters / second².

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As given in the problem If a truck begins with a velocity of 20. meters per second east and changes its velocity to 5.0 meters per second east in 10.0 seconds,

The initial velocity of the truck = 20. meters per second

The final velocity of the truck =  5.0 meters per second

Time period = 10.0 seconds

By using the first equation of the motion,

v = u + at

5= 20+ 10a

a = 20-5/-10

a = -1.5 meters / second²

Thus, the acceleration of the truck would be -1.5 meters / second².

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A crew of mechanics at the Highway Department Garage repair vehicles that break down at an average of λ = 7.5 vehicles per day (approximately Poisson in nature). The mechanic crew can service an average of μ = 10 vehicles per day with a repair time distribution that approximates an exponential distribution. a. What is the utilization rate for this service system? b. What is the average time before the facility can return a breakdown to service? c. How much of that time is spent waiting for service? d. How many vehicles are likely to be in the system at any one time?

Answers

The Highway Department Garage has a crew of mechanics who repair vehicles that break down. The breakdowns occur at an average rate of 7.5 vehicles per day, and the mechanics can service an average of 10 vehicles per day.

This service system's utilization rate, average time for a breakdown to be repaired, waiting time for service, and the number of vehicles likely to be in the system at any given time need to be determined.

a. The utilization rate of a service system is the ratio of the arrival rate of customers to the service rate. In this case, the arrival rate is λ = 7.5 vehicles per day, and the service rate is μ = 10 vehicles per day. Therefore, the utilization rate can be calculated as λ/μ = 7.5/10 = 0.75 or 75%.

b. The average time before a breakdown can be repaired is given by the reciprocal of the service rate, which is 1/μ = 1/10 = 0.1 days or 2.4 hours.

c. To determine the time spent waiting for service, we need to calculate the average time a vehicle spends in the system. This can be obtained using Little's Law, which states that the average number of customers in a system is equal to the arrival rate multiplied by the average time spent in the system.

As the system is in equilibrium, the average number of vehicles in the system is equal to the average number of vehicles being serviced. Therefore, the average time spent waiting for service can be calculated as (average number of vehicles in the system) / λ = (λ/μ) / λ = 0.75 / 7.5 = 0.1 days or 2.4 hours.

d. The average number of vehicles in the system at any one time can be calculated using Little's Law as λ * average time spent in the system = 7.5 * 0.1 = 0.75 vehicles.

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the size of a neutron star is group of answer choices about the same as that of our solar system. about the same as that of the sun. about the same as earth. smaller than any of these.

Answers

The size of a neutron star is smaller than any of the given answer choices.

A neutron star is an extremely dense object that is formed from the collapsed core of a massive star that has undergone a supernova explosion. The mass of a neutron star is typically 1.4 times that of our Sun, but its size is only about 20 km in diameter, making it one of the most compact objects in the universe.

To put this into perspective, the diameter of our solar system is about 287 billion km, the diameter of the Sun is about 1.4 million km, and the diameter of the Earth is about 12,742 km. Therefore, a neutron star is much smaller than any of these objects, and its mass is packed into a space that is comparable in size to a medium-sized city.

In conclusion, a neutron star is much smaller than any of the given answer choices, with a diameter of only about 20 km.

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A neutron star is a very compact and incredibly dense object formed from the core of a massive star after a supernova explosion.

1) Our solar system is vast, spanning a distance of over 100 astronomical units (AU), with the distance between the Sun and the outer planets being several billion kilometers.

In contrast, a neutron star typically has a radius of about 10-15 kilometers, which is much smaller than the distance between any two objects in the solar system.

2) The Sun, on the other hand, is much larger than a neutron star, with a radius of about 696,000 kilometers.

The Earth, which is one of the smaller planets in our solar system, has a radius of about 6,371 kilometers.

Therefore, a neutron star is significantly smaller than both the Sun and the Earth.

3) The size of a neutron star is determined by its mass and density, which are both extremely high.

A typical neutron star has a mass of about 1.4 times that of the Sun, but is only about 10-15 kilometers in radius.

This makes it incredibly dense, with a mass-to-volume ratio that is several times higher than that of an atomic nucleus.

In summary, a neutron star is much more massive than the Sun or the Earth, but its size is significantly smaller than both, making it smaller than any of the options given.

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Someone please help me!!!!

Someone please help me!!!!

Answers

Answer:

I cant read it sorry.

Explanation:

a Consider a one-dimensional potential well with the potential of U. = (h2/8T2mL2) zo. If you would like to find a single bound state in the one- dimensional potential well, find the range of values o

Answers

The range of values of o = π/2

Given potential well is U(x) = (h²/8T²mL²) z₀

Now,The wave function can be written asψ(x) = Acos(ka) + Bsin(ka)for a < x < b

As the wave function must be zero at x = a and x = b,So, A = 0

Now, The wave function becomes,ψ(x) = Bsin(ka)for a < x < bAlso, k² = 2TmL²/h² * (E - U₀)

for this given potential well as U(x) = (h²/8T²mL²) z₀,So, we havek² = 2TmL²/h² * (E - U₀) = 2TmL²/h² * E - z₀ ....(1)

Let, the bound state energy be E = -E

Below the potential well is flat, so U(x) = 0 which means z₀ = 0

From equation (1), we getk² = 2TmL²/h² * (-EBound state means that the wave function is zero outside the potential well. So, sin(ka) should be zero at x = L. This implies,ka = nπ

where n is a positive integer.Substituting this in the above equation, we get-k² = 2TmL²/h² * (-E) = (nπ/a)² * 2Tm/h²

Substituting given values, we get

150 = (nπ/2)² * (1.05 × 10^-34 / (6.626 × 10^-34)² * 2 * (1.67 × 10^-27))

Solving this equation, we get n = 1So, the range of values of o = π/2

Corrected expression:

150 = (nπ/2)² * (1.05 × 10^-34 / (6.626 × 10^-34)² * 2 * (1.67 × 10^-27))

Solving for n, we get n = 1

Hence, the range of values of o = π/2

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(Level 5-6) 3. An object accelerates 15.0 m/s2 when a force of 8.ON is applied to it. What is the mass of the
object in g and Kg?

Answers

Answer:

0.53 kg

Explanation:

Mass = \(\frac{Force}{acceleration}\)

Force (also weight) = 8.0N

Acceleration = 15.0 \(m/s^{2}\)

= \(\frac{8.0}{15}\)

= 0.53 kg ( to 2 decimal place )

difference between kinetic energy and potential energy(please i need answer in 2minutes​

Answers

Answer:

Energy stored in an object due to its position is Potential Energy. Energy that a moving object has due to its motion is Kinetic Energy.

Explanation:

Welcome.

All of the following are types of models EXCEPT
O a theory.
Dan analogy.
Oa physical replica.
O a mathematical representation.

Answers

The fist answer is correct the send on is correct and the third one is correct he fourth one is incorrectly

Answer:

A theory

Explanation:

No, the person who answered above is incorrect. I just took the assessment and I can guarantee you the answer is "a theory".

-Lexi

What is the speed of a wave that has a wavelength of 1,480 m and a frequency of 486 Hz? 28 cm/sec​

Answers

Answer:

it could be 32 cm/sec the answer

Find the dot and cross product for the vectors v = 2i + 3j + 4k and u = į − 2j + 3k. Q2. Find the projection of u on v such that u = 2i + j + 2k and v= 3j + 4k. Q3. Find the angle between the vectors u = 2i - 3j + k and v= v=į - 2j+ k. Q4. Find the unit vector in the direction of the vector u = 4i - j + 2k.

Answers

1. The dot product of two vectors v and u is 8.

2. projection of u on v 11/5.

3. the angle between the vectors 20.95 degrees.

4. the unit vector in the direction of the vector (4i - j + 2k) / \(\sqrt{(21)\)

Q1. Dot product:

The dot product of two vectors v and u is given by the formula:

v · u = (v_x * u_x) + (v_y * u_y) + (v_z * u_z)

Given v = 2i + 3j + 4k and u = į - 2j + 3k, we can calculate the dot product as follows:

v · u = (2 * 1) + (3 * -2) + (4 * 3)

= 2 - 6 + 12

= 8

Q2. Projection of u on v:

The projection of vector u onto vector v is given by the formula:

proj_u_v = (u · v) / |v|

Given u = 2i + j + 2k and v = 3j + 4k, we can calculate the projection as follows:

proj_u_v ==

=\(((2 * 0) + (1 * 3) + (2 * 4)) / \sqrt{((0^2) + (3^2) + (4^2)}) \\= (0 + 3 + 8) / \sqrt{(0 + 9 + 16)} \\= 11 / \sqrt{(25) }\\= 11 / 5\)

Q3. The angle between vectors u and v:

The angle between two vectors u and v can be found using the formula:

θ = arccos((u · v) / (|u| * |v|))

Given u = 2i - 3j + k and v = į - 2j + k, we can calculate the angle as follows:

θ = \(arccos(((2 * 1) + (-3 * -2) + (1 * 1)) / (\sqrt{(2^2 + (-3)^2 + 1^2)} * \sqrt{(1^2 + (-2)^2 + 1^2)))\)

= arccos\(((2 + 6 + 1) / (\sqrt{(4 + 9 + 1)} * \sqrt{(1 + 4 + 1)))\)

= arccos(9 / \((\sqrt{(14)} * \sqrt{(6)}\)))

≈ arccos(9 / 9.5916)

≈ arccos(0.9373)

≈ 20.95 degrees

Q4. Unit vector in the direction of u:

To find the unit vector in the direction of a vector u, divide the vector u by its magnitude:

unit_u = u / |u|

Given u = 4i - j + 2k, we can calculate the unit vector as follows:

unit_u = \((4i - j + 2k) / \sqrt{((4^2) + (-1^2) + (2^2))\)

= (4i - j + 2k) / \(\sqrt{(16 + 1 + 4)\)

= (4i - j + 2k) / \(\sqrt{(21)\)

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using the equation d=1/2at^2, the value of 5.0m for the distance and the time recorded for the wagon to reach the stop block, calculate acceleration

Answers

Calculated acceleration for the wagon to reach the stop block is a= (2×5)÷t²

What is Acceleration?

Acceleration is rate of change of velocity with respect to time. i.e a =  

if an object changes its velocity in short time, we can say that it has grater acceleration.

a=  Δv/Δt  

According to the equation change in velocity can be positive or negative hence acceleration can be positive or negative. the acceleration which is negative is called as deceleration.

When a body decelerates its velocity gets decreased and when it accelerates its velocity increases.

Given,

Distance = 5m

t = t ( t is not mentioned)

a = ?

Our given formula is

d= (1/2)×at²

multiplying both sides by 2

2d=at²

deviding both sides by t²

a=2d÷t²

a= (2×5)÷t²

Hence acceleration for wagon is a= (2×5)÷t²

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Two identical metallic sphere having unequal opposite charges are are placed
distance of 0.05m apart in air.
After bringing them in contact
with each other, they are again placed at the same distance apart, now the force of repulsion between them is 0.108 N. Calculate the final charge on each of them.​

Answers

Answer:

Let the initial charges be q1 and q2 respectively.

After they come in contact, the charges are rearranged such that they acquire same charge.

let us say that charge on each of them is Q.

They are again brought apart at a distance of 0.9 m. Hence, the force between them will be given as

F = kQ2 / r2

0.025 = (9×109 x Q2) / 0.92

Q2 = 0.025 x 0.92 / 9×109

Q = 1.5 x 10-6 C

Explanation:

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If beaker tongs are not available, which could you use to handle the hot beaker? mittens tweezers crucible tongs heat resistant gloves

Answers

Answer:

heat resistant gloves

Explanation:

If beaker tongs are not within reach, you can use heat resistant gloves to handle a hot beaker.

The Heat resistant gloves is a protective equipment that offers protection to the hands against heat and flames. They are designed to give protection from burns and also from sparks when one comes in contact with extremely hot objects or temperatures in the workplace.

Answer:

Heat resistant gloves!

Explanation:

Have a great day!

if i ask wat r the application of simple machine some of u will say-----> Simple machines that are widely used include the wheel and axle, pulley, inclined plane, screw, wedge and lever. While simple machines may magnify or reduce the forces that can be applied to them, they do not change the total amount of work needed to perform the overall task.
but actually the application of simple machine is
i) they transfer force from one point to another
ii) They accelerate the rate of doing work
iii) the multiply force

Answers

Answer:

DID NOT

UNDER STAND

Explan it a littlebit

An object is placed 60 cm from a convex lens with a focal length of magnitude 10 cm. What is the magnification

Answers

The magnification of the object placed 60 cm from a convex lens with a focal length of 10 cm is 0.5.

The magnification (m) of a lens can be calculated using the formula:

m = -v/u

where v is the image distance and u is the object distance.

Given that the object is placed 60 cm from the lens, u = -60 cm (negative because the object is placed on the same side as the incident light). The focal length of the convex lens is 10 cm.

To find the image distance v, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the values, we get:

1/10 = 1/v - 1/-60

Simplifying this equation gives us:

1/v = 1/10 + 1/60

1/v = (6 + 1)/60

1/v = 7/60

Taking the reciprocal of both sides, we find:

v = 60/7 cm

Substituting the values of v and u into the magnification formula, we get:

m = -(60/7) / -60

m = 1/7

Therefore, the magnification of the object is 0.5.

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You calibrate a set of automobile springs using a 25 kg car battery, attached to a rope that runs over a pulley, as shown in the diagram.

You find that the spring is pulled out by 0.06 meters. Compute the spring constant, k, in N/m.
Just type in the numeric part of your answer, to the nearest 0.1 N/m.

Answers

For an automobile spring using a 25 kg car battery, the spring constant is mathematically given as

K=4.08.3N/m

What is the spring constant?

Question Parameter(s):

a 25 kg car battery

The springs are pulled out by 0.06 meters

Generally, the equation for the Force  is mathematically given as

F=mg

Therefore

F=(25*9.8)

(25*9.8)=K(0.06)

K=4.08.3N/m

In conclusion, the spring constant

K=4.08.3N/m

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Calculate the size of the magnetic field (in µT) at 10.76 m below a high voltage power line. The line carries 450 MW at a voltage of 300,000 V. You should round your answer to the nearest integer.

Answers

The magnetic field at 10.76 m below the high voltage power line is approximately 41,835,820 µT when the line carries 450 MW at a voltage of 300,000 V. Rounded to the nearest integer, the magnetic field is 41,836 µT.

To calculate the magnetic field at a distance below a high voltage power line, we use the formula \(B=\frac{u0IH}{2\pi r}\)

Current, I = 450 MW = 450 × 10^6 W

Height, H = 0 m (since the power line is at ground level)

Distance below the power line, r = 10.76 m

Using the formula for the magnetic field, we substitute the given values:

\( B = \frac{{(4\pi \times 10^{-7} \, \text{{T}} \cdot \text{{m/A}}) \cdot (450 \times 10^6 \, \text{{W}}) \cdot (0 \, \text{{m}})}}{{2\pi \cdot 10.76 \, \text{{m}}}} \)

Simplifying the expression:

\( B = \frac{{450 \times 10^6 \, \text{{W}}}}{{10.76 \, \text{{m}}}} \)

Calculating the value:

\( B \approx 41,835,820 \, \text{{T}} \)

Rounding the magnetic field to the nearest integer:

\( B \approx 41,836 \, \mu\text{{T}} \)

Therefore, the magnetic field at 10.76 m below the high voltage power line is approximately 41,836 µT (rounded to the nearest integer).

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A student is investigating inertia and acceleration. The data the student collects is shown in the table.
Force (N) Mass (kg) Acceleration (m/s²)
10
10
20
20
1
2
1
2
b
Oc
Od
Assuming the force acting on the objects is constant, which claim about inertia and acceleration is supported by the data?
0.1
0.2
Next Page
0.05
0.1
An object with a lower mass has less inertia which causes it to speed up less quickly.
An object with a higher mass has more inertia which causes it to speed up less quickly.
An object with a higher mass has less inertia which causes it to speed up more quickly.
An object with a lower mass has more inertia which causes it to speed up more quickly.
Back

A student is investigating inertia and acceleration. The data the student collects is shown in the table.Force

Answers

Assuming the force acting on the objects is constant, a claim about inertia and acceleration which is supported by the data include the following: B. An object with a higher mass has more inertia which causes it to speed up less quickly.

What is Newton's First Law (Inertia)?

Newton's First Law of Motion is also referred to as Law of Inertia and it states that an object in motion would continue in its state of motion at continuous velocity (same speed and direction) or if at rest, it will remain at rest unless it is acted upon by an external force.

This ultimately implies that, the amount of net force keeping a physical object moving at a constant speed and in a specific direction is always equal to zero (0) newton in accordance with Newton's First Law of Motion.

In this context, we can reasonably infer and logically deduce that a physical object that has a higher mass would have more inertia, which causes it to either experience a slower motion or speed up less quickly.

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Answer: its c

Explanation: i took the test

what is the length of the delay between carbon emissions and their effects on oceans?

Answers

The length of the delay between carbon emissions and their effects on oceans is around several decades to centuries.

The oceans play a significant role in absorbing excess carbon dioxide (CO2) from the atmosphere. However, the absorption of CO2 results in the ocean becoming more acidic, which could be detrimental to marine life and their habitats. As a result, an increase in carbon emissions leads to negative impacts on the oceans over time. To add to this, Carbon dioxide, a greenhouse gas, has an impact on the Earth's climate.

The greenhouse effect, which results from excessive carbon dioxide in the atmosphere, causes the Earth's temperature to rise, resulting in climate change. Because the oceans play such a crucial role in the Earth's climate, they are also significantly impacted by rising temperatures. As a result, it is critical to consider the long-term effects of carbon emissions on the oceans and take action to reduce them.

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What acceleration does the force of earth's gravity peoduce

Answers

Near Earth's surface, gravitational acceleration is approximately 9.81 m/s2, which means that, ignoring the effects of air resistance, the speed of an object falling freely will increase by about 9.81 metres per second every second.

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor is a stationary 375-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 1.80 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 2.75 Hz. Ignoring any reflections of sound in the room and using 343 m/s for the speed of sound, determine the amplitude (in m) of the simple harmonic motion.

Answers

Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

when a kid drops a rock off the edge of a cliff, it takes 4.0 seconds to reach the ground below. when she throws the rock down, it strikes the ground in 3.0 seconds. what initial speed did she give the rock?

Answers

the initial speed that the kid gave the rock when throwing it downward is approximately 5.75 m/s.

To determine the initial speed that the kid gave the rock when throwing it down, we can use the equations of motion for free fall.

When the rock is dropped:

The time taken (t) is 4.0 seconds, and we assume the initial velocity (u) is 0 (since the rock was dropped without an initial upward or downward velocity). We can use the equation:

s = ut + (1/2)gt^2

where s is the distance fallen, u is the initial velocity, t is the time taken, and g is the acceleration due to gravity.

When the rock is thrown:

The time taken (t) is 3.0 seconds, and we need to find the initial velocity (u). We can use the same equation as above:

s = ut + (1/2)gt^2

Since the rock was thrown downward, the initial velocity (u) will be negative.

Now, we can set up the equations:

For dropping the rock:

0 = 0 + (1/2)g(4.0)^2

For throwing the rock:

s = ut + (1/2)gt^2

Substituting the given values:

s = ut + (1/2)gt^2

0 = u(3.0) + (1/2)g(3.0)^2

Simplifying the equations:

(1/2)g(4.0)^2 = (3.0)u + (1/2)g(3.0)^2

8g = 6u + 4.5g

Rearranging the equation:

6u = 8g - 4.5g

6u = 3.5g

Dividing both sides by 6:

u = (3.5g) / 6

Substituting the approximate value for the acceleration due to gravity (g ≈ 9.8 m/s^2):

u ≈ (3.5 * 9.8) / 6

Calculating the value:

u ≈ 5.75 m/s

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What is the mass for both??

What is the mass for both??

Answers

Answer:

forever alone uwu......

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