the red ball in the diagram is chasing after the blue ball; they have the same mass. the speed of the red ball is 3 m/s the speed of the blue ball is 2 m/s. after the collision the red ball rebounds at 2 m/s and the blue ball speeds away at 3 m/s. what was the change in velocity experienced by the red ball during the collision? what was the change in velocity experienced by the blue ball during the collision? normally, momentum is conserved during a collision. however if a huge external force acts during the collision, it may not be. was momentum conserved during this collision or not?
Answers
The change in velocity experienced by the red ball during the collision is -1 m/s, and the change in velocity experienced by the blue ball is +1 m/s. Momentum was conserved during this collision.
Given that the red ball is initially moving at 3 m/s and the blue ball is initially moving at 2 m/s, we can determine the change in velocity for each ball after the collision.
For the red ball:
Initial velocity = 3 m/s
Final velocity = -2 m/s (since it rebounds at 2 m/s in the opposite direction)
The change in velocity for the red ball is calculated as:
Change in velocity = Final velocity - Initial velocity
Change in velocity = (-2 m/s) - (3 m/s) = -5 m/s
Therefore, the change in velocity experienced by the red ball during the collision is -5 m/s, indicating a decrease in speed by 5 m/s.
For the blue ball:
Initial velocity = 2 m/s
Final velocity = 3 m/s
The change in velocity for the blue ball is calculated as:
Change in velocity = Final velocity - Initial velocity
Change in velocity = (3 m/s) - (2 m/s) = 1 m/s
Therefore, the change in velocity experienced by the blue ball during the collision is +1 m/s, indicating an increase in speed by 1 m/s.
To determine if momentum was conserved during the collision, we need to compare the total momentum before and after the collision. Since the masses of the red and blue balls are the same, we can compare their initial and final momentum.
Before the collision:
Total momentum = (Mass of red ball * Velocity of red ball) + (Mass of blue ball * Velocity of blue ball)
Total momentum = \((m * 3 m/s) + (m * 2 m/s) = 5m\)
After the collision:
Total momentum = (Mass of red ball * Velocity of red ball) + (Mass of blue ball * Velocity of blue ball)
Total momentum = (m * -2 m/s) + (m * 3 m/s) = m
The total momentum before the collision is 5m, and after the collision, it is m. Since 5m is not equal to m, we can conclude that momentum was not conserved during this collision. The presence of a huge external force during the collision caused a change in momentum.
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Related Questions
arrange 3 identical resistors in all the possible combinations and calculate the equivalent resistance. the resistance for each resistor is 200 ohms
Answers
Explanation:
All R's in series: just add them together : 200 + 200 + 200 Ω = 600Ω
One in series with two in parallel :
= 200 Ω + 200*200/(200+200) Ω = 300Ω
All three in parallel :
R = 1 / (1/200 + 1/200 + 1/200) = 66.7 Ω
An average family of four uses roughly 1200 liters of water per day (1L = 1000 Com). A lake that covers 50 km with a uniform depth and
supplies water to a local town with a population of 40,000 people would lose
depth every year due to water consumption form
the locals. Ignore evaporation, rain, creeks and rivers
Answers
Answer:
A family of 4 uses 1200 liters of water per day
1200 liters/day * 365 days/year = 438000 liters per year
If the town has 40,000 people, this equals 10,000 families
Explanation:
So the total town usage in one year = 10000*438000 = 4.38E9 liters = 4.38E12 cm^3 (scientific notation)
The area of the lake in cm^2 is 50 km^2 * (100 cm / m)^2 * (1000 m / km)^2 = 5E11 cm^2
The loss of volume of the lake is 5E11 cm^2 * h, where h is the change in depth
The total volume of water used by the town = the volume lost by the lake.
Therefore 4.38E12/5E11 = h = 8.76 cm
Can someone help me with this
Answers
(a) For graph A the object is moving at a zero constant speed.
(b) For graph B the object is moving at a constant speed greater than zero.
(c) For graph C the object is moving a uniform speed.
What is constant and uniform velocity?Constant velocity refers to a situation in which an object moves at a constant speed in a straight line. This means that the magnitude of the velocity (i.e. the speed) of the object remains the same over time, while its direction may or may not change.
Uniform velocity refers to a situation in which an object moves with a constant speed, but also changes its direction. In other words, the object has a constant magnitude of velocity (i.e. speed), but its direction is constantly changing. An object moving in a circular path at a constant speed is an example of an object with uniform velocity.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
Answers
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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according to past research, why have women engaged in token resistance? group of answer choices they said no but then changed their minds and said yes.
Answers
According to past research, women have engaged in token resistance, which means they said no but then changed their minds and said yes. This occurs because of the cultural expectations that women are supposed to resist sexual advances even if they want to participate.
Because of this, women may feel pressure to refuse initially to maintain their reputation and avoid being seen as promiscuous. However, once the partner persists, they may give in to avoid being seen as too difficult or cold-hearted. Research has indicated that these behaviours are particularly evident in situations where the individual feels vulnerable or feels that they are in a low-power position. Women may also engage in token resistance to test their partner's sincerity and willingness to respect their boundaries. Additionally, it's worth noting that token resistance does not apply only to women, as men may also engage in this behaviour.
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An elevator, mass 4750kg, is designed so that the maximum acceleration is 0.50m/s2. What are themaximum and minimum forces the motor exerts on the cable?
Answers
The free body diagram of the elevator can be shown as,
According to free body diagram, the net force acting on the elevator is,
\(F_n=T_{\max }-mg\)According to Newton's law,
\(F_n=ma\)Plug in the known expression,
\(\begin{gathered} ma=T_{\max }-mg \\ T_{\max }=ma+mg \\ =m(a+g) \end{gathered}\)Substitute the known values,
\(\begin{gathered} T_{\max }=(4750kg)(0.50m/s^2+9.8m/s^2) \\ =(4750\text{ kg)(}10.3m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =48925\text{ N} \end{gathered}\)Thus, the maximum force exerted on the cable is 48925 N.
For minimum, tension the net force can be expressed as,
\(F_n=mg-T_{\min }\)Plug in the known expression,
\(\begin{gathered} ma=mg-T_{\min } \\ T_{\min }=mg-ma \\ =m(g-a) \end{gathered}\)Substitute the known values,
\(\begin{gathered} T_{\min }=(4750kg)(9.8m/s^2-0.5m/s^2) \\ =(4750\text{ kg)(}9.3m/s^2)(\frac{1\text{ N}}{1kgm/s^2}) \\ =44175\text{ N} \end{gathered}\)Thus, the minimum force exerted on the cable is 44175 N.
If the particles that make up an object begin to move quickly, their average kinetic energy _____ and the object's temperature _____. Group of answer choices
Answers
Explanation:
If the particles that make up an object begin to move quickly, their average kinetic energy increases the object's temperature rises. Group of answer choices
A 2018 Tesla Model S has a horsepower of 518. How many watts of power does this car model have?
Answers
Answer:
It depends on the model but these are the watts of each motor
Explanation:
Un motor: 258 HP (262 CV) Dual motor: 154 kW (209 CV) y 197 kW (268 CV). Performance: 154 kW (209 CV) y 225 kW (306 CV).
All waves must travel up and down.
True
False
Answers
Answer:
True all waves that go up must come down
I feel like the follow the rule of gravity:everything that goes up must come d5
A boat can travel 15 m/s when there is no ocean current. If the ocean current has a velocity of 3 m/s that is going directly East, which way should the boat steer to move directly North if the boat is moving at 15 m/s?
Answers
15*15=225(m) boat speed
A 5-uF capacitor is charged to 30 V and is then connected across a 10-mH inductor. What is the maximum current in the circuit
Answers
The circuit's maximum current is \(I_{max}\) = 1.73 A.
The greatest continuous current, measured in amperes, that a conductor can carry while in operation without going above its temperature rating is known as ampacity. The term "current-carrying capacity" is sometimes used. When the motor is running at its maximum speed and there is no load in one direction, the maximum current flow occurs, at which point operation will quickly switch to the opposite direction.
The largest amount of current that an output is capable of providing for brief periods of time is known as the peak current. When an electrical device or power source is turned on for the first time, a large initial current known as the peak current flows into the load, starting at zero and increasing until it reaches a peak value.
We can use the formula for the maximum current in an LC circuit:\(I_{max} = v/\sqrt{L/C} \\I_{max} = 30/\sqrt{10 * 10^{-5}*5 }\)
\(I_{max}\) = 1.73 A
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HELP ME PLZ
Determine this kinetic energy of a 1500-kg roller coaster car that is moving with a speed of 40.0 m/s
Answers
Answer: 1200 000 J = 1.2 MJ
Explanation: Ek = 0.5 mv² = 0.5 · 1500 kg· (40 m/s)²
HELPPPPPPPPPPPPPPPPPPP
Answers
Answer:
directly proportional
Explanation:
Question 12
If an object is moving in a ____
line, the change in velocity equals the final speed minus the initial speed.
Answers
If an object is moving in a straight line, the change in velocity equals the final speed minus the initial speed.
What is the change in velocity?
The change in velocity of an object moving in a straight line is a measure of how much its speed has changed over time. The change in velocity is equal to the final speed minus the initial speed, and it is a vector quantity, meaning it has both magnitude and direction.
For example, if an object is moving at a speed of 10 m/s at time t1 and has a speed of 20 m/s at time t2, then its change in velocity would be;
20 m/s - 10 m/s = 10 m/s.
The direction of the change in velocity would depend on the direction of the speed change, which could be either positive (increasing speed) or negative (decreasing speed).
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Astronomers categorize galaxies into a handful of basic shapes. What can you conclude from this fact?
Answers
From the that astronomers categorize galaxies into a handful of basic shapes, it can be concluded that the all galaxies are made from the same forces.
Astronomers have categorized galaxies into three main categories,
Elliptical Galaxies:
These galaxies have smooth ellipsoidal shape. They are most abundant type. For example- Messier 49
Spiral galaxies:
These galaxies have a spiral shapes with many hand like structures. For example- Milky way.
Irregular Galaxies:
They do not have any specific shape.
Therefore, from the that astronomers categorize galaxies into a handful of basic shapes, it can be concluded that the all galaxies are made from the same forces.
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a cylinder weighs 29.2 grams what is its density? and will it float in water?
Answers
In order to determine the density of a cylinder, we need to know its mass and volume. The mass of the cylinder is given as 29.2 grams, but the volume is not provided. Without the volume, it is impossible to calculate the density of the cylinder.
As for whether or not the cylinder will float in water, that also depends on its density. If the density of the cylinder is less than the density of water (1), then it will float. However, without knowing the density of the cylinder, it is impossible to determine whether or not it will float in water.
1. Draw the following free-body diagrams. Label the forces with their appropriate symbol, and includethe magnitude of each force if it is known.a) A basketball player shoots the ball,and it is flying through the air toward the basket.(Ignore air resistance.)b) A wheeled cart on a track (similar to whatyou used in the lab) weighs 0.5 N. It is pulledto the right with an applied force of 0.25 N, andexperiences rolling friction of 0.03 N. Ignore airresistance.c) A cart is on an air track (a frictionlesssurface similar to an air hocket table). Mrs. Hountonpushes the cart, and then lets go. It is travelingtoward the left. Include air resistance. The free-bodydiagram should be for the situation after Mrs. Hountonlets go of the cart.
Answers
To draw a free-body diagram, identify all the forces acting on an object and draw them including their magnitude and direction. Use a point to represent the object.
a)
While the ball is flying through the air, the only force acting on the ball is its weight (due to gravitational attraction to the Earth).
b)
There are three forces acting on the cart: its weight, the pull to the right and the rolling friction to the left:
c)
There are three forces acting on the cart: The gravitational pull downwards, the push upwards of the air that compensates the weight, and the air resistance to the right (since the cart is traveling toward the left).
A person is trying to drag a box with a mass of 30 kg on a flat floor using a rope attached to it. The static frictional coefficient between the box and floor is 0.50. The angle between the horizontal direction and the rope is 30 degrees. What is the minimum force the person needs to have to move the box along the floor?
Answers
Answer: F = 131.7N
Explanation:
You are given the following parameters.
Mass M = 30 kg
Coefficient of static friction μ = 0.5
Ø = 30 degrees
When the person is trying to drag the box with force F, the static frictional force Fs will be acting in the opposite direction.
From the figure attached, resolve all forces into horizontal component and vertical component.
Horizontal component:
Fs - F cosØ = 0
Fs = F cosØ
F cosØ = μN ...... (1)
Vertical component:
N + F SinØ - mg = 0
N = Mg - F SinØ ..... (2)
Substitutes m, g and Ø into the equation 2
N = (30 × 9.8) - F × sin30
N = 294 - 0.5F
Substitute N and coefficient of friction into the equation (1)
F cos30 = 0.5 (294 - 0.5F)
Open the bracket
0.8660F = 147 - 0.25F
Collect the like terms
1.116025F = 147
F = 147/1.116025
F = 131.7 N
Therefore, the minimum force the person needs to have to move the box along the floor is 131.7 N
For this truss geometry:
|/\|/\|/\|/\|
Select one or more:
a. The bottom chords do not usually need the verticals, since the bottom chords are not subjected to bending loads and the bottom chords only go into compression under severe wind suction that overcomes the dead weight of the structure.
b. This is called a Modified Warren Truss.
c. The vertical webs help brace the top chord against buckling upward and downward.
d. The vertical webs help support parts of the top chord, thereby reducing the span, and associated bending stress, of the top chord under the uniform gravity force of the decking resting on the top chord of the truss.
e. The unbraced length for the bottom chords is twice as long as the unbraced length for the top chords.
Answers
The bottom chords do not usually need the verticals, since the bottom chords are not subjected to bending loads and the bottom chords only go into compression under severe wind suction that overcomes the dead weight of the structure.
Why the bottom chords not usually need verticles?
Truss is a building structure that is usually composed of several triangular units made of straight bars. The triangle shape helps distribute the weight evenly across the structure, making it much stronger than a traditional beam or other type of structure. The Warren truss is a common type of truss used in construction and engineering projects that is used for its strength and durability.
Modified Warren Truss: It is a variation of the Warren truss that includes vertical web members that are added to the structure to help support the top chord and reduce the span of the structure. This reduces the amount of bending stress that is put on the top chord and helps to keep the structure stable and secure.
Vertical webs: The vertical webs are the diagonal members that are added to the Modified Warren Truss. These help to brace the top chord against buckling upward and downward and support parts of the top chord, thereby reducing the span and associated bending stress of the top chord under the uniform gravity force of the decking resting on the top chord of the truss.
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a boy on a bicycle approaches a brick wall as he sounds his horn at a frequency 407.83 hz. the sound he hears reflected back from the wall is at a frequency of 413.81 hz. at what speed is the boy riding his bicycle toward the wall? assume the speed of sound in air is 340m/s.
Answers
The frequency difference between the emitted sound (407.83 Hz) and the reflected sound (413.81 Hz) is caused by the Doppler effect.
This effect occurs when there is relative motion between the source of sound (the boy on the bicycle) and the observer (the wall). The speed of the boy can be determined using the formula for the Doppler effect:
f' = f * (v + vo) / (v + vs)
Where f' is the reflected frequency (413.81 Hz), f is the emitted frequency (407.83 Hz), v is the speed of sound in air (340 m/s), vo is the velocity of the observer (the wall, 0 m/s), and vs is the velocity of the source (the boy, which we need to find).
413.81 = 407.83 * (340 + 0) / (340 + vs)
Solving for vs, we get:
vs = ((413.81 * 340) / 407.83) - 340
vs ≈ 4.91 m/s
Therefore, the boy is riding his bicycle toward the wall at a speed of approximately 4.91 meters per second.
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in certain cyclotron a proton moves in a circle of radius 0.39m. the magnitude of the magentic field is 1.40t. a) what is the oscillator frequency
Answers
The oscillator frequency, according to the statement, is 2.13×10⁷ Hz.
What kinds of fields are there?According on whether the reported weight of an object is a scalar, vector, spinor, or tensor, respectively, a field can be categorized as a numerical solution, vector field, spinor field, or tensor field.
What does a work field mean?Career sectors are means of classifying various career kinds based on shared characteristics. People can use these categories to help them focus their professional options and select a suitable route. Career fields make it simple for people to categorize the many forms of labor for better comprehension.
Briefing:
f=\(\frac{qb}{2\pi m}\)
\($\begin{aligned} f &=\frac{1.6 \times 10^{-19} \times 1.4}{2 \pi \times 1.67 \times 10^{-27}}\\ f &=2.13 \times 10^7 \mathrm{~Hz} \end{aligned}$\)
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An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec2 in the forward direction. What is the net force acting on the automobile?
Answers
\(\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Question \; :- }}}}}}}\)
An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec² in the forward direction. What is the net force acting on the automobile?
_________________________________________
\(\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given\; :- }}}}}}}\)
➢ Mass of the automobile = 1250 kg➢ Acceleration of the body = 4m/sec²_________________________________________
\(\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}\)
Net force acting on the automobile = ?_________________________________________
\(\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Concept \: and \: Formula \: Used \; :- }}}}}}}\)
➯ Force is defined as the product of the mass of the body and its acceleration.
\( \bigstar \: \small{ \fbox {\textsf {\textbf{F = ma}}}}\)
Where :
F = Force m = Mass of the bodya = acceleration due to gravity\(\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Substituting \: the\: Given\: Values :- }}}}}}}\)
\(⇝ \: \: \small \textsf {\textbf{ F = (1250 × 4) N }}\)
\(⇝ \: \: \small \textsf {\textbf{ F = 5000 N }}\)
\(\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Therefore \; :- }}}}}}}\)
❝ The net force acting on the automobile is 5000 N. ❞
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Which of the following technologies is based on the work of Subrahmanyan Chandrasekhar? A. Undersea fiber optic communications cables B. An orbiting observatory to detect X-rays from space objects C.Computer models to predict the effects of climate change D. Radar to detect the movement of storms
Answers
Answer:the answer is B
Explanation:
APE X
The technology that is based on the work of Subrahmanyan Chandrasekhar is an orbiting observatory to detect X-rays from space objects, therefore the correct option is B.
What is Chandrasekhar's limit?Chandrasekhar's limit is a type of maximum limited value that is used to define the maximum mass of a white dwarf star. The generally internationally considered value of the Chandrasekhar limit is about 1.44 times the mass of the sun which is approximately 2.765×10³⁰ kg.
In other words, one can say that Chandrasekhar limit is the maximum value that can attain 1.44 times the solar mass.
In other words, one can say that star with a mass more than 1.44 times that of the Sun does not form a white dwarf but continues to collapse, finally forming a neutron star
An orbiting observatory to detect X-rays from space objects is based on the principle of Chandrasekhar's limit. The correct option is B.
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Two rams run toward each other. One ram has a mass of 49 kg and runs west
with a speed of 7 m/s, while the other has a mass of 52 kg and runs east with
a speed of 9 m/s. What will the momentum of the system made up of the two
rams be after they collide? Assume the total momentum of the system is
conserved
A. 811 kg-m/s west
B. 811 kg-m/s east
C. 125 kg-m/s west
O D. 125 kg-m/s east
S
Answers
Answer: (d)
Explanation:
Given
Mass of the first ram \(m_1=49\ kg\)
The velocity of this ram is \(v_1=-7\ m/s\)
Mass of the second ram \(m_2=52\ kg\)
The velocity of this ram \(v_2=9\ m/s\)
They combined after the collision
Conserving the momentum
\(\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]\)
Momentum after the collision will be
\(\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}\)
Therefore, option (d) is correct
easy one giving brainly if correct
Answers
Answer:
c) Liquid
Explanation:
Liquid takes the shape of its container and has a specific volume. On the other hand, solid and gas don't.
15 points!! pleas help! A rollercoaster cart that has a mass of 4500 kg has 67.5 kJ (kilojoules), or 67,500 J (joules), of gravitational potential
energy. What is its height above the ground?
PT.2
The same 4500 kg rollercoaster cart is moving with 63.0 kJ (kilojoules), or 63,000 J (joules), of kinetic energy at the
bottom of its biggest hill. What is its velocity?
Answers
explanation:
the energy stored in the capacitor is given by
e= 1/2 c v²
e= energy stored
c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f
v= potential difference=36 v
so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²
energy stored= 9.72 x 10⁻⁴j
I not completely sure but I hope this helped you
Each point of a light-emitting object (a) sends one ray. (b) sends two rays. (c) sends an infinite number of rays
Answers
The correct option is C, Each point of a light-emitting object sends an infinite number of rays.
Light-emitting refers to the process by which a material emits light. This can happen through a variety of mechanisms, such as thermal radiation, fluorescence, or phosphorescence. When a material absorbs energy, such as through exposure to light or heat, it can become excited and release this energy in the form of light.
For example, in fluorescence, a material absorbs high-energy light and then emits lower-energy light as it returns to its ground state. This is the process that makes fluorescent materials glow under UV light. In phosphorescence, the material continues to emit light even after the excitation source has been removed, due to a delayed release of energy. Light-emitting is an important phenomenon in many areas of science and technology, such as lighting, displays, and lasers.
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long-term exercisers often report that __________ exercise rewards are their primary motivation.
Answers
Long-term exercisers often report that intrinsic exercise rewards are their primary motivation.
They are often report that the long-term health benefits and feeling of well-being are their primary motivation for continuing to exercise. While short-term rewards such as weight loss and increased energy are also motivating factors, it is the sustained benefits that keep dedicated exercisers committed to their fitness routine.
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URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (60pts)
Answers
Answer:
5
Explanation:
100 newtons pulling a 500 newton object has the mechanical advantage of 5 since it pulled 5x its weight
the expression is simple: 500/100= 5 (5 is the mechanical advantage)
pls mark me brainliest if this is right lol ty
if the amount of work done remains constant but occurs over less time how does this affect the amount of power exerted?
Answers
Answer:
The amount of power will be increased.
Explanation:
If the work remains constant but the time is reduced the power increases. Since power is defined as the relationship between work overtime. By means of the following equation, we can see this relationship.
\(P=W/t\)
where:
P = power [Watts]
W = work [J] (units of joules)
t = time [s]
Let's assume with an example the above written.
If we have an electric motor that exerts a work of 950 [J], and the time used is 5 [s], the power is:
\(P = 950/5\\P = 190 [W]\)
Now if we want to accelerate the work done and use 2 seconds for the time, we will have:
\(P=950/2\\P=475 [W]\)
We want to see how maintaining the work constant but reducing the time in which it occurs affects the power. We will see that the power increases.
We define power as the amount of work done per unit of time.
So we can compute power as the quotient between the work done and the time in which it is done.
So, if we reduce the time in which the work is done, then the denominator is smaller, thus, the power will be larger.
This means that maintaining the work constant, and reducing the time in which it is done, increases the amount of power exerted.
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